help-0

[alpine sable]

the center comes out to be 2,3/2

then

what do i consider the other two either points

so that i can apply midpoint

[slow sentinel]

One moment

[torn elk]

Use the rotation points.

The vertices of the square will be at a 90-degree rotation from the given vertices about the center of the square.

[slow sentinel]

$y=\frac{2x}{5}-\frac{7}{10}$
You can now assume 2 points on this line such as (x, 2x/5-7/10) and put them in the distance formula from centre and you'll get 2 values of x and subsititute the value of x in the equation of line to get your y coordinates

[ocean seal]

MeDumb

[slow sentinel]

Does this make sense?

[alpine sable]

umm

alr i assumed one point to be x,2x/5 -7/10

the other one ?

[slow sentinel]

Try solving just one

When you solve using this

[alpine sable]

ah i see

i got it

ah shit

[slow sentinel]

You'll get 2 values of x

[alpine sable]

i am so stoopid

i was almost there

got it bud

thanks a lot

[slow sentinel]

No problemo

👌

[alpine sable]

can you please elaborate more

i wanna hear his idea too

[torn elk]

https://en.wikipedia.org/wiki/Rotation_matrix#In_two_dimensions

Midpoint (h,k) = (3,3/2)

x' = h + (y - k)
y' = k - (x - h)

[alpine sable]

just like shifting of origin ?

[torn elk]

Apply for the point (3,4) and the for the point (1, -1)

[alpine sable]

similar to it

[torn elk]

we "rotate the image"

[alpine sable]

just rotating the system

oh i see

got it

i will try it

thanks

how do i close it now ?

[torn elk]

.close

[alpine sable]

.close

[lone heart]

Channel closed

Closed by @tawny acorn

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[junior gazelle]

Under these assumptions:

Is this true?

[junior gazelle]

,

gpt said its ok but idk

[surreal crystal]

gpt is bad at math, and has misled me many times

[lone heart]

@junior gazelle Has your question been resolved?

[lone heart]

@junior gazelle Has your question been resolved?

[junior gazelle]

😦

[ashen vault]

hi

hello gays

[junior gazelle]

no

[lone heart]

@junior gazelle Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[patent swallow]

Guys I know how to draw x = -3 and y = 5x but idk how to draw the other function

I need to find the area between those 3 funcs

[dire trail]

whitch area do you mention ?

[patent swallow]

not y = -4

[dire trail]

ah my bad

good ?

[patent swallow]

yes

but

idk how to draw hx

in the exam

so using geogebra isnt valid to solve this excercise

[dire trail]

well in order to find the area between multiple functions in a specific field you need to integrate their difference

like here we want to find the area in : -4 < x < 0

just go ahead and integrate those two functions

since x = -4 don't take any area you're just left with those two

if you get a negative value, use the apsulute value since the area can't be negative

[patent swallow]

I need to find $5x=\frac{x}{\sqrt{x^2+9}}$ right?

[ocean seal]

Chuti | Argentina

[patent swallow]

But I get to this $5\sqrt{x^2+9}-x=0$

[ocean seal]

Chuti | Argentina

[patent swallow]

I'm prolly doing something wrong here

[slender gull]

You already have made a mistake, yes.

[patent swallow]

| -42 | the area

assuming x is 0

but maybe I'm losing solutions

literally got the result at the same time u sent the message lmao

[slender gull]

I must say, I didn't read any prior messages.
But I only commented on your work in solving the equation. You lost x = 0

[patent swallow]

yes, forget about the previous messgaes

I'm struggling with $5x=\frac{x}{\sqrt{x^2+9}}$

[ocean seal]

Chuti | Argentina

[patent swallow]

tbh I still dont understand how I passed high school

🤣

[trim sorrel]

Haha

How would you start to do this?

[patent swallow]

😭

[trim sorrel]

You missed sometihng

As before, the other guy pointed out you missed the solution x = 0

[trim sorrel]

Plugging in x = 0 here will make it clear that that's a solution

[patent swallow]

correct

but what if there are more?

[trim sorrel]

Right

[patent swallow]

I mean idk

[trim sorrel]

So now let's try to find a nonzero solution

[patent swallow]

wolfram might know, I dont 🤣

[trim sorrel]

If x is nonzero, we can divide it from both sides, right?

Bc we're trying to find a nonzero solution

[patent swallow]

divide it, what's it?

[trim sorrel]

Divide x

From both sides

[patent swallow]

like 5x/x ?

u mean

[trim sorrel]

Yes

From both sides

Cancelling the x

[patent swallow]

correct

[trim sorrel]

Since we are assumign its nonzero

[patent swallow]

yes

yes

absurd

[trim sorrel]

If we simplify a bit, we get $5 \sqrt{x^2 + 9} = 1 \Rightarrow \sqrt{x^2 + 9} = 1/5 \Rightarrow x^2 + 9 = 1/25 \Rightarrow x^2 = 1/25 - 9 < 0$

[patent swallow]

5 = 1/ something

[ocean seal]

wakebloom

[patent swallow]

is this enough?

[trim sorrel]

Hm?

[trim sorrel]

5 = 1/sqrt(x^2 + 9)

[trim sorrel]

Then continue on here

[patent swallow]

correct

[trim sorrel]

Just algebra

[patent swallow]

this will never be true

[trim sorrel]

Correct

In the real numbers yes

So there are no real solutions for x when x is nonzero

[trim sorrel]

Therefore, this is only true when x = 0

In the reals

[trim sorrel]

You can see that on the graph here

[patent swallow]

yes in R

[trim sorrel]

Ya

So thats the solution

To that equation

[patent swallow]

good

😎

[trim sorrel]

[patent swallow]

again, idk how I passed high s

[trim sorrel]

Lolll

[patent swallow]

thanks for the help

[trim sorrel]

You did and thats what matters

o7

[patent swallow]

haha

now I need to pass calc 1

😭

[trim sorrel]

You got this

[patent swallow]

first time in my life I study

never studied before fr haha

already got used to studying a lot by now but this is hella difficult 🤣 anyways, thanks again, I'll close the channel

.close

[lone heart]

Channel closed

Closed by @patent swallow

Use .reopen if this was a mistake.

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

Channel closed

Closed due to the original message being deleted

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lone heart]

Channel closed

Closed due to the original message being deleted

[junior warren]

.reopen

pain

[echo socket]

Open a new one

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[boreal sluice]

Hello can someone verify my answers for me please

[boreal sluice]

I’m not so sure about q1, hence I didn’t complete it

[pallid scarab]

Q5) is good !

[boreal sluice]

ok thanks

[pallid scarab]

Q4 is good too

And Q3

In Q2) is D those 2 quadrants next to the question ? Because I would have expected the result to be 0

Let me double check

[boreal sluice]

i guess so, the graph was given and those two quadrants are the shaded ones

[pallid scarab]

Oh I think you're supposed to integrate from pi/2 to 3pi/2, not from -pi/2 to pi/2

[boreal sluice]

3pi/2 is -pi/2

oh do u mean that they arent in the correct order?

[pallid scarab]

I think that's a first thing to correct

But I suggest trying to write it as :
int[x = -2 to x = 0] int[y = -sqrt(4-x²) to y = sqrt(4-x²)] x⁴y dy dx

Then bringing out the x⁴ term from the inner integral

int[x = -2 to x = 0] x⁴ * (int[y = -sqrt(4-x²) to y = sqrt(4-x²)] y dy) dx

But then you'll find this inner integral is null

So you're integrating 0, which gives 0

I don’t know what went wrong with your approach, I'm trying to wrap my head around it

Maybe it's when you calculate the new boundaries, you should find the same boundary twice

[boreal sluice]

oh okay tysm, i'll try to figure it out

[pallid scarab]

Yeah it's cos(pi/2) = cos(-pi/2) = 0 that are the boundaries

[boreal sluice]

are the boundaries for q3 correct?

[pallid scarab]

Technically they should be -pi/2 and 0

But it has no impact on the result

[boreal sluice]

oh right

[pallid scarab]

Also for question 1, it might help writing f(x,y) = (x+2)² + (y-1)² - 3

Just so you get confirmation that the absolute minimum is at x = -2 and y = 1

[boreal sluice]

i think its wrong from the start then

[pallid scarab]

Yeah i think you need to find where Gradient(f) = 0

And otherwise, find an expression for f(x,y) at the border x² + y² = 20

(x = rcos(theta) and y = rsin(theta))

And you can now find the min and max in terms of theta

[boreal sluice]

ok tysm

[lone heart]

@boreal sluice Has your question been resolved?

[boreal sluice]

I re-did it

[lone heart]

@boreal sluice Has your question been resolved?

[pallid scarab]

I'm sorry for not understanding the method behind this for finding max/min, I might have not seen it before

[boreal sluice]

its okay

.close

[lone heart]

Channel closed

Closed by @boreal sluice

Use .reopen if this was a mistake.

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

Channel closed

Closed due to the original message being deleted

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lapis nacelle]

the set {(x, x+y, y, x-y) | x, y real} is the set R^4 ?

[lapis nacelle]

I think so, but I'm not sure

how can I verify that

[mortal trellis]

can you write every vector in R^4 in that form?

eg (1,1,1,1) ?

[lapis nacelle]

not that one

[mortal trellis]

why not?

[lapis nacelle]

(1,1,1,1) means x=1 and y=1

then, (1,2,1,0)

[mortal trellis]

yes

[lapis nacelle]

But in general how can I see all the lists that are in the set?

[mortal trellis]

well they all have that form

what exactly would you want as an answer here?

this form is pretty explicit

[naive valley]

you might try expressing (x, x+y, y, x-y) in the form xu + yv, where u and v are two specific fixed vectors

[lapis nacelle]

I need a base of {(x, x+y, y, x-y) | x, y real}

[naive valley]

^ @lapis nacelle that's what this suggestion will do for you

(x, x+y, y, x-y) = x(1, 1, 0, 1) + y(?,?,?,?) <-- what's the second vector here?

[lapis nacelle]

(0,1,1,-1)

oooh ok

I I'm just a little confused

so, I can say the dimension of that space is 2, right?

because (1,1,0,1) and (0,1,1,-1) form every (x, x+y, y, x-y) with a pair of constants

[tardy stag]

if you can span it with two vectors and not with one, then yes it's two dimensional

[lapis nacelle]

Ok, thanks!

.close

[lone heart]

Channel closed

Closed by @lapis nacelle

Use .reopen if this was a mistake.

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lapis nacelle]

if this is the base:

[lapis nacelle]

to verify this

just ask: is 1+x+5x^2 = 1+x^2?

right?

[vale crag]

is that a question or a statement ?

[lapis nacelle]

is a question

a true false statement

[vale crag]

yea that's what they're asking then

[lapis nacelle]

thanks

.close

[lone heart]

Channel closed

Closed by @lapis nacelle

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[alpine sable]

If |2x+3| - |x-1| = 6, then the sum of possible values of x will be___.

[alpine sable]

I’ve made some progress

I made 3 cases

Wait I think I found my mistake

One sec

Actually I don’t

I’ll write my solution down nearly and post it in a sec

Ugggh I was solving the for the wrong question 😑

.close

[lone heart]

Channel closed

Closed by @vivid walrus

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[next osprey]

ok so im trying g(2)

im at 2/3 ln10

how would i solve that

[fallen verge]

You dont

find f(2/3×ln10)

[next osprey]

so i plug that into 5e^3x then?

[fallen verge]

Yes

[next osprey]

im also not allowed a calculator

so 5e^3((2/3)ln(10))

[fallen verge]

Yes

[next osprey]

how do i solve that

[tacit arch]

you were given log rules

look at it again

[fallen verge]

Start with 3×(2/3)

[next osprey]

am i distributing?

[next osprey]

so 2

[fallen verge]

Yes

So now you have 5e^(2ln(10))

[next osprey]

yes

[fallen verge]

Recall $a \ln b = \ln b^a$

[ocean seal]

garlicbredfries

[next osprey]

so 5e^ln(10)^2

[fallen verge]

$ \ln (b^a)$

$\ln (b^a)$

[ocean seal]

garlicbredfries

[next osprey]

...

lost

[tacit arch]

$e^{\ln(a)} = a$

[ocean seal]

rie.mann

[next osprey]

so 10^2 *5?

that rule is so

thank you very much

.close

[lone heart]

Channel closed

Closed by @next osprey

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tulip musk]

I just need help solving

[vapid shuttle]

start by filling out the tables

[lone heart]

@tulip musk Has your question been resolved?

[tulip musk]

I just need the answers

[vapid shuttle]

have you tried filling out the table yet

we don't give answers

[tulip musk]

Alr give me a second

idk anything

Like how to fill

[vapid shuttle]

take a specific x-value

find the y-value of the line at that x-value

and then put them in the table together

[tulip musk]

So like -3, -1, 1, 3

[vapid shuttle]

those could be choices of x

[tulip musk]

Could?

So it varies

[vapid shuttle]

well you can just pick whichever values for x that you want

to fill out the table

picking easy ones makes it easier

this is an example of one point you could do

pick x=2

[tulip musk]

okay

[vapid shuttle]

the y-value at that point, is y=2

so on our table, we put 2, 2

now you can pick some more x-values

whatever you want them to be

and keep filling out the table

[tulip musk]

So like x = 0

[vapid shuttle]

and y would then be?

[tulip musk]

1

[vapid shuttle]

mhm

just like that

[tulip musk]

Idk how to write equation

[vapid shuttle]

Do you know how to find the slope of the line?

Do you also know how to find the y-intercept of the line?

[tulip musk]

Pythagoras?

[vapid shuttle]

the slope is the change in y / change in x

rise / run

[tulip musk]

sorry I thought it was rise x run

[vapid shuttle]

it is rise/run

[tulip musk]

5/8.5

=5.88235….

[vapid shuttle]

no

choose two x-values from your table

the difference between them is the run

the difference between the y-values that go with them is the rise

then do rise/run

[tulip musk]

0.5?

[vapid shuttle]

mhm

[tulip musk]

Alr lemme try the other one

does the next one = -3?

[lone heart]

@tulip musk Has your question been resolved?

Channel closed

Closed by @tulip musk

Use .reopen if this was a mistake.

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[humble tiger]

uh yeah honestly

confused about where to start

im assuming u need to

find some kind of closed form expression

instead of recursive

maybe u can use like finite differences somehow

idk im jsut stuckk ugh

[weary wyvern]

Maybe write a few terms and find a pattern

Or let b_n = a_n/a_n-1 and rearrange for b_n

Which seems to be possible

[humble tiger]

hm lemme try

whats the rationale

[weary wyvern]

Just that it seems possible

[humble tiger]

oh shoot nvm tis easy

clear pattern

thanks

LOL

.end

whats the thign

.stop

.close

[lone heart]

Channel closed

Closed by @humble tiger

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vapid basin]

help

[proven leaf]

!status

[lone heart]

What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above

[vapid basin]

2

[proven leaf]

where are you stuck? :)

[vapid basin]

well getting the two possible k values i can find the gradient of the two lines using negative reciprocals and stuff

but i just dont get how u can get two k values in the first place

do u use simulatneous to find? im just stuck there

[proven leaf]

well "two" possibile values of k is kind of a gives away that we're dealing with a quadratic

[vapid basin]

riight

[proven leaf]

so can you show any work that you've done so far?

[vapid basin]

mm not rly

sorry

[vapid basin]

quadratic from lines?

[proven leaf]

alright so do you know the midpoint formula?

[vapid basin]

yeah

[proven leaf]

so what is the midpoint of A and B?

[vapid basin]

(3, -3+k/2)

[proven leaf]

ok good! :) but make sure you use parantheses

[vapid basin]

ya sry its just hard on keyboard

[proven leaf]

so now we need the line for A and B, do you know how to get a line using only two points?

[vapid basin]

the gradient?

wdym by line?

[proven leaf]

like the line that passes through these two points

[vapid basin]

the equation of the line or just the line 😂

[proven leaf]

well the equation would be more helpful lmao

[vapid basin]

oh haha

uh yeah

so well ive worked ou the gradient as (k+5)/-4

[proven leaf]

alright! now we just need the y-intercept

[vapid basin]

oh so what method are u using to find the equation of the line

[proven leaf]

well we know the equation of a line is y=mx+b, right?

[vapid basin]

yes

[proven leaf]

so we mave m

and we have (x,y) because that's just one of our points!

so we can solve for b

[vapid basin]

sry i was using this form

[proven leaf]

oh ok actually that works fine too

[vapid basin]

yeah so i think what i got was

y= (k+5)/-4 (x-5)+3

using the points

of A

(5,-3)

[proven leaf]

I don't agree with that answer

[vapid basin]

mm okay

[proven leaf]

so we have $y-(-3)=-\frac{k+5}{4}(x-5)$

[ocean seal]

XxMrFancyu2xX

[vapid basin]

WOW

U CAN DO THAT

[proven leaf]

if we plug in directly

[vapid basin]

LOOKS SO COOL

[proven leaf]

just $\LaTeX$ :)

[ocean seal]

XxMrFancyu2xX

[vapid basin]

sorry getting distracted

ohhhhhh

so is it -3 at the end

whoooops

but i was close right

i thought i did it all wrong

[proven leaf]

ok now we have our line, so what's our slope?

[vapid basin]

(k+5)/-4

[proven leaf]

now if we want the perpendicular line

what would be the slope?

[vapid basin]

u swap

so

4/(k+5)

[proven leaf]

yep :) so we want the perpenicular bisector

so we use the slope-point formula

with our midpoint and new slope

[vapid basin]

oh okay

gimmie a sec

okay so

i got

y = 4/(k+5) (x-3) - (3+k)/2

[proven leaf]

ok so now, we use our final piece of information

this line crosses through the x-axis at -2

so what would be that coordinate point? :)

[vapid basin]

DO U SUBSTITUDE -2 FOR X AND 0 FOR Y

OR AM I BEING DUMB

wait...

WAIT DO U

omg omg

[proven leaf]

that's what crosses the x-axis means, no? :)

[vapid basin]

waiiittt

[proven leaf]

now, you will get a quadratic for k

and get two solutions just as wanted

[vapid basin]

quadratic for k... hmm wait gimmie a sec

OHH BECAUSE DENOMENATOR

u need to do cross multiplication right

[proven leaf]

what method ur teacher taught you there are multiple ways to approach this, but only two right solutions :)

[vapid basin]

wait so if i substitute -2,0 for x and y

it gives me 0 = -4/(k+5)-(3+k)/2

since they are both negative i can just multiply both by -1 to make it easier to work with right

so they become positive?

[proven leaf]

$0\cdot-1=0$ :)

[ocean seal]

XxMrFancyu2xX

[vapid basin]

whew okay thanks 😂

is the numerator 8 + (k+5) (3+k) ??

[proven leaf]

sounds about right

[vapid basin]

well ig the denominator will just dissapear if u times by 0

[proven leaf]

but we'll come back to that dw so don't forget abt that denominator

[vapid basin]

wait ok

so

k^2 + 8k + 23 = 0

then i use quad formula find the two answers?

would that be correct?

[proven leaf]

not factorable so gotta use formula

[vapid basin]

hmm?

ohy yeah yhea

hmm

no real roots

did i do something wrong

maybe the last part

[proven leaf]

how did you get this line?

[vapid basin]

using the slope point formula

but lemme double check

hmm i dont see anything wrong with it

could u help me out

[proven leaf]

that's what im tryna do ;-;

[vapid basin]

sorryy

[proven leaf]

ah i think i may have it

we have $y = \frac{4}{k+5}(x-3) - \frac{k+3}{2}$ at $(-2,0)$, right?

[ocean seal]

XxMrFancyu2xX

[vapid basin]

yes

[proven leaf]

so this lends us $0 = \frac{4}{k+5}(-5) - \frac{k+3}{2}$

[ocean seal]

XxMrFancyu2xX

[vapid basin]

OHHH

[proven leaf]

you just straight up got rid of the 5 in your original calculation

but idk what difference that would make it's kinda late tbh

[vapid basin]

NO BECAUSE HAHA I DID -2 - 3 AS -1

im so dumb

im so sorry for wasting ur time man

[proven leaf]

bro I chose to help you for a reason :)

if you were wasting my time I'd leave, I'm still here

[vapid basin]

so -5

[proven leaf]

yep then maybe try to do the algebra

see if it generates a better answer

ah damnit

still getting complex roots

[vapid basin]

YEAH

i think

hmm

actually idk what im talking abt 😭

[proven leaf]

ur slope is wrong I think

[vapid basin]

do u think the question could be faulty

oh nvm

[proven leaf]

like the one at the very beginning ;-;

[vapid basin]

oh lemme check

omg

UR RIGHT AGAIN

k+3

not k+5

[proven leaf]

there that might get us a better answer :)

[vapid basin]

bro my handwriting actually screws things everytime man

[proven leaf]

better write neat on the test 😭

[vapid basin]

ok what is wrong this time

😭

still no real roots

[proven leaf]

uh oh

[vapid basin]

do u think its the question

because i thought if it was gonna be yk giving actual roots

[proven leaf]

4/(k+3) is the slope of the bisector

plug in the midpoint (3, -3+k/2)

check the line again hang on

$y=\frac{4}{k+3}x+b$

[ocean seal]

XxMrFancyu2xX

[proven leaf]

$\frac{k-3}{2}=\frac{4}{k+3}(3)+b$

[ocean seal]

XxMrFancyu2xX

[proven leaf]

$b=\frac{k-3}{6}-\frac{4}{k+3}$

[ocean seal]

XxMrFancyu2xX

[proven leaf]

$=$\fbox{$\frac{(k-3)(k+3)-24}{6(k+3)}$}

[ocean seal]

XxMrFancyu2xX

[proven leaf]

there that's b

that's the issue

[vapid basin]

so b is y-int so do u chuck that whole thing into

[proven leaf]

^ this eq. was wrong

$y=\frac{4}{k+3}x+\frac{(k-3)(k+3)-24}{6(k+3)}$ at $(-2,0)$

[ocean seal]

XxMrFancyu2xX

[proven leaf]

[vapid basin]

woww

okay

[proven leaf]

this is algebra bootcamp right here

love it

[vapid basin]

thanks man, saving my brain right now

wait wouldnt that mean k would become k^3

[proven leaf]

where k^3 come form?

we have $0=\frac{-8}{k+3}+\frac{(k-3)(k+3)-24}{6(k+3)}$, right?

[ocean seal]

XxMrFancyu2xX

[vapid basin]

yeah

oh do u

cancell

the two k+3

[proven leaf]

helps to write it out don't it :) and you can multiply everything by 6

now we just have a quadratic my friend!

[vapid basin]

thanksss

omg thats been a long one

[proven leaf]

get real roots finally?

[vapid basin]

hold on lemmme solve it

and expand rq

[proven leaf]

I actually enjoyed that, shaved off the rust of my algebra skills which needed a good derusting tbh

[vapid basin]

wait quick question

when u cancell the two k+3

and ur left with the numerator as (k-3)-24

[proven leaf]

wait hold on

[vapid basin]

is it just k-27

[proven leaf]

I think we have to different interpretations of "cancel k+3's"

$0=\frac{-8}{k+3}+\frac{(k-3)(k+3)-24}{6(k+3)}$\
$0=\frac{-48}{6(k+3)}+\frac{(k-3)(k+3)-24}{6(k+3)}$\
$0=\frac{-48}{\cancel{6(k+3)}}+\frac{(k-3)(k+3)-24}{\cancel{6(k+3)}}$\
\fbox{$0=-48+(k-3)(k+3)-24$}

[ocean seal]

XxMrFancyu2xX

[vapid basin]

oh okay i see

wait so u can just multiply by 6

just like that

[proven leaf]

only because I did it to top and bottom

[vapid basin]

i think my algebra skills arent too sharp lol

riight but u dont have to for the other one

[proven leaf]

I think abt it like this $\frac{a}{b}\cdot1=\frac{a}{b}\cdot\frac{a}{a}=\frac{a^2}{ab}$\
$\implies\frac{a}{b}=\frac{a^2}{ab}$

[ocean seal]

XxMrFancyu2xX

[proven leaf]

so as long as we multiply to top and bottom

we can multiply whatever we like

and the fraction does not change :))

as long as we do multiplication the same doesn't hold for addition

[vapid basin]

but because the other side is a 0 it doesnt matter because 0 times 6 is always 0

okayy i see

[proven leaf]

that's not the reason

the reason is im multiplying by 6/6

which is 1

and mutliplication by one just keeps it the same

$a\cdot1=a$

[ocean seal]

XxMrFancyu2xX

[vapid basin]

are u multiplying it by 6/6?

i thought

oh wait u areee

sry took a while for me to see that\

[proven leaf]

nah ur good :)

math is learning experience

[vapid basin]

IS THE ANSWER

PLUS OR MINUS 9

K = +- 9

[proven leaf]

could be lemme check desmos rq

seems right but if you can check with your teacher or another person cause im tired :))

[vapid basin]

THANK U SO MUCH

have a good rest of ur day or perhaps goodnight

[proven leaf]

im going to bed! 😂 so i am sorry in advance if anything is wrong :)

[vapid basin]

haha no worriess

[proven leaf]

I try not to give people bad advice to the best of my ability

hope you continue to learn math it's pretty fun if you give it a shot! enjoy!

[vapid basin]

thanksss

ur such a big help

[lone heart]

@vapid basin Has your question been resolved?

[vapid basin]

oh before i go i just redid the question and there was just a slight error with ur working but its fineee u were tired and i had so many errors aswell

[lone heart]

Channel closed

Closed by @vapid basin

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[weak field]

Is it correct

[lone heart]

@weak field Has your question been resolved?

[weak field]

<@&286206848099549185>

[alpine sable]

Thats me. How can I help?

[weak field]

@alpine sable can u confirm if it's correct or not

[alpine sable]

If you are asking then it is probably not, but yes, I will check. Give me background on the subject.

[weak field]

Umm
Sorry
But I don't get wdym 😅

Can u elaborate

[upbeat hornet]

this looks correct, for acute angles x and y

[weak field]

Ohk
Ty

.close

[lone heart]

Channel closed

Closed by @weak field

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[cinder sundial]

Is that true

Is it always happens? The expression wrote in blue ink

[vale wigeon]

Does it always happen? The expression written in blue ink

[cinder sundial]

Thank you

[vale wigeon]

no, it only happens if p and r/q are either both positive or both negative.

[cinder sundial]

Is there any rule that explains this phenomenon

[vale wigeon]

a > b > 0 implies 1/a < 1/b

it is not hard to prove yourself with basic inequality properties

[cinder sundial]

It’s not that intuitive in my opinion, like ppl might often forget to change the “direction” of inequality

[cinder sundial]

In conclusion, when ab>0 and a >b then (a)^-1 < (b)^-1

[vale wigeon]

the parentheses are redundant here

[vale wigeon]

it takes some time to get used to

[cinder sundial]

That is, the inequality has to changed when we reciprocal those

[cinder sundial]

For sure, thank you Ann!

[lone heart]

@cinder sundial Has your question been resolved?

Channel closed

Closed by @cinder sundial

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[balmy ridge]

what is 1+1

[long axle]

Don’t troll bruh

[balmy ridge]

bro

I ned help

Someone said 3

and someone said 11

I aint trollin

[long axle]

Use your judgement

.close

[lone heart]

Channel closed

Closed by @long axle

Use .reopen if this was a mistake.

[gleaming ridge]

1+1 is actually 10

[sour dove]

if you're going to troll, at least do it well

[balmy ridge]

ok sir

[vale wigeon]

and do it in #chill

[balmy ridge]

guys

hep me

someone pls help meeeeeeeeeeee

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[balmy ridge]

can you guys help me solve
I actually got an problem with it like
it looks easy but actually hard lol
I forgot how to solve those things.

[44×{(33+21)+(50-15)}]=[{40+(36-28)}÷2] × [99× 22]

[balmy ridge]

pls

[echo socket]

Use a calculator

[balmy ridge]

...

I dont have it

[vale wigeon]

this is an arithmetic problem

[balmy ridge]

I lost it

[echo socket]

You have internet

[vale wigeon]

do you know how to add, subtract, multiply and divide?

[balmy ridge]

ye but

I mess all of those

up

yk

[vale wigeon]

then do it slowly and one thing at a time

do you have paper?

[balmy ridge]

ye

yes

[vale wigeon]

ok

then work it out on paper slowly

[balmy ridge]

I think I should do it slowly

[vale wigeon]

one step at a time

[balmy ridge]

ok

[vale wigeon]

ensuring that each arithmetic operation is done correctly before moving on to the next

[balmy ridge]

ok sir

thx for the help

[vale wigeon]

please don't call me sir.

but you're welcome

[balmy ridge]

aw ok i didnt know im sorry

[balmy ridge]

ok!

[lone heart]

@balmy ridge Has your question been resolved?

Channel closed

Closed by @balmy ridge

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[clear jungle]

I trying to find how many numbers have 6 or 8 but not 6 and 8 in an inclusive range of l, n. I plan on using the inclusion-exclusion method (as seen here: https://math.stackexchange.com/questions/19682/how-many-eight-digit-numbers-are-there-that-contain-both-a-5-and-a-6/19685#19685) but I don't know how. I am really bad at math.

[lone heart]

@clear jungle Has your question been resolved?

[lone heart]

@clear jungle Has your question been resolved?

[tacit arch]

If you're still stuck, you can try #probability-statistics

[lone heart]

@clear jungle Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[safe tartan]

I have a question on dot products

[cedar hatch]

Hello

[safe tartan]

in the formula a . b =|a|^2+|b|^2-|a-b|^2,

[cedar hatch]

🙂

[safe tartan]

and a is lets say u+v

can you expand the brackets so |u+v|^2 can you expand?

[cedar hatch]

Hard Problem

[echo socket]

|u + v|^2 = (u + v)^2, so yeah, you can expand that

So it becomes |u|^2 + 2u*v + |v|^2

[safe tartan]

oh

i didnt know you could multiply vectors

i c

could i then ask for help on this question?

[echo socket]

What question

[safe tartan]

for question b, i found the dot products of op or and pr oq

and equated them, which left me with a final expression of

and then i have no clue what to do lmao

[charred violet]

Just want to point out that from a.b = |a|^2+|b|^2-|a-b|^2 we can re arrange to find

|a-b|^2 = |a|^2+|b|^2-a.b

[safe tartan]

is this applicable here or jsut something to note

[echo socket]

If OPQR is a square, wouldn't you need to just say OP*OR = 0 and |OP| = |OR|?

[brisk bay]

This is a parallelogram

[echo socket]

So OR is 2a - 3b, right?

[safe tartan]

yep

[echo socket]

So (a + b)(2a - 3b) = 0
And 2|a|^2 - a.b - 3|b|^2 = 0

Hm, it seems like we need to prove that a.b = |b|^2

[safe tartan]

wait how did u get the second line again

[echo socket]

(a + b)(2a - 3b) = 2a.a - 3b.a + 2a.b - 3b.b = 2a^2 - 3a.b + 2a.b - 3b^2 = 2|a|^2 - a.b - 3|b|^2

[alpine sable]

if we could prove that a.b=b-a , it';ll be solved

[rigid smelt]

you forgot to use the second information, which is |OP|=|QR|

[echo socket]

And the other condition is that |a + b| = |2a - 3b|

Yeah I was about to mention its implications

[rigid smelt]

which just implies that |OP|^2=|QR|^2, and use dot product to find ab

[echo socket]

So here we can square

And get |a|^2 + 2a.b + |b|^2 = 4|a|^2 - 12a.b + 9|b|^2 or 3|a|^2 - 14a.b + 8|b|^2 = 0

We obtain a system of equations
2|a|^2 - a.b - 3|b|^2 = 0
3|a|^2 - 14a.b + 8|b|^2 = 0

a.b could be get rid of by multiplying the first equation by -14 and adding the equations up

Let's see

So it's
-25|a|^2 + 50|b|^2 = 0

Hence |a| = 2|b|^2

[safe tartan]

thats

wow

[safe tartan]

the expression after or, where is that from?

[echo socket]

Just collect similar terms together in the first equation of that message

[safe tartan]

ah shit mb

ok yep i understood it

thanks lonely bean

.cloes

.cloes

.close

[lone heart]

Channel closed

Closed by @safe tartan

Use .reopen if this was a mistake.

[feral shale]

wow hankukin

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[silk terrace]

anyone that can help me interpret this ACF plot for a hmm?

[noble sinew]

Normally (for time series at least) you would plot +2- * sqrt(n) (+- 2 standard error) and then approx 95% of the sample ACFs should be within these limits.

[lone heart]

@silk terrace Has your question been resolved?

[silk terrace]

in the time series there is about 24k data points. all of the data points with a lag of up to 300 are not within the CI bands

[noble sinew]

I would suggest taking a step back. Why do you want to plot ACF?

[silk terrace]

So I was told that the hidden process induces auto correlation in the data and that this acf plot shows that our model does not account for all of it (sorry i am trying to think about the answer). I am actually not sure on why that matters.

I was told stuff like introducing more covariates (feedback mechanisms to account for history) or states could solve that

[silk terrace]

but from my understanding i dont actually see the 'harm' when autocorrelation is the correlation between two observations at different points in a the time series

<@&286206848099549185>

[noble sinew]

While the ACF plot itself may not directly inform the structure of an HMM, it can help in model selection, parameter estimation, and diagnosing potential issues.

[silk terrace]

Yes I have actually used AIC and state dependent distribution fits to check for model fit and selection. However, I just can not interpret the acf plot above. From my understanding, we want the lags to be insignificant white noise, however that is not the case here (i am not sure why that is wanted though).

I can only find one ressource with a similar acf graph and it says that a trend is present but doesn't explain further than that

[noble sinew]

You should look at ACF of residuals if you aren't

[silk terrace]

This is basically what I am using in the package:

[noble sinew]

Sure looks fine from description

[silk terrace]

So it is actually the acf of the pseudo residuals. I did not even notice that

so the plot above is actually acf of the residuals. I am now even more confused on how to interpret it haha.

but this is the thing I am not seeing it is relatively new for me. If the residuals is showing a trend: i.e "shorter lags typically have large positive correlations because observations closer in time tend to have similar values. The correlations taper off slowly as the lags increase." Why is that necessarily bad

in other words: why is a trend in the ACF plot a indication that my model does a relative poor job of explaning the data

[noble sinew]

Wait can I see the ACF plot of the observed data

[silk terrace]

I can only grab this one from the package unfortunately. I am using: https://cran.r-project.org/web/packages/momentuHMM/momentuHMM.pdf. I did not know the newer version hmmTMB came out before i started

[noble sinew]

What does that have to do with anything. Its just ur data (which is stored in some vector or whatever)

Nothing about your HMM

[silk terrace]

let me see give me a moment

[noble sinew]

So as long as your residual ACF looks similar to the ACF of the observed data it should be fine

[silk terrace]

the decrease is much more steep in the residual ACF but what would be 'too different'/similar and what do we mean by fine in this case

as in the model fits alright if they are similar?

[noble sinew]

Its the only thing that makes sense to do if looking at ACF as far as I can see. Though I have no idea why one would ever do this over just splitting data up into training and test data.

[noble sinew]

yes whatever that means

[silk terrace]

You are the one that said it, though lol. Training data would make sense if patterns in both cases were similar. I think we aren't getting any further so I am closing. Ty

.close

[lone heart]

Channel closed

Closed by @silk terrace

Use .reopen if this was a mistake.

[noble sinew]

What? Its very common to split data in machine learning, time series data is no exception.

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[noble sinew]

You were the one who wanted to interpret ACF? I said the only thing that makes sense as far as I can see is compare the two ACF plots and visually compare. No idea what you mean with 'Training data would make sense if patterns in both cases were similar.'

[noble sinew]

.close

[lone heart]

Channel closed

Closed by @noble sinew

Use .reopen if this was a mistake.

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[alpine sable]

So the problem says:
Find the roots of z^3 - (8+i)z^2 + (24 + 4i)z - (24 - 6i) = 0. Knowing that the product of 2 of them is 15 + 9i.
How would u approach this?

[lone heart]

Please don't occupy multiple help channels.

@alpine sable Has your question been resolved?

[rustic coral]

Using Vieta's formulas, the product of the 3 roots is (24-6i), use thst to find the third root

Also, the sum of the three roots is 8+i

See if you can do it from here

[alpine sable]

why?

[alpine sable]

and if i didnt know this formula?

[rustic coral]

Let the roots be $\alpha, \beta, \gamma$ and consider the expansion of $$(z-\alpha)(z-\beta)(z-\gamma)$$

[ocean seal]

civil_service_pigeon

[alpine sable]

yeah, that should be my polinomio, right?

[rustic coral]

Yeah

[alpine sable]

and i know 2 of the are 15+9i

how do i find the third?

[rustic coral]

Did you expand it?

It's how you derive Vieta's

It's essentially ||comparing coefficients after you expand||

[alpine sable]

ah

+close

[rustic coral]

The command is .close

[alpine sable]

.close

[lone heart]

Channel closed

Closed by @lilac skiff

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[copper temple]

I think I understand what this problem is asking me but I’m not sure because the diagram is showing a weird right angle triangle?

[rustic coral]

I think that's just supposed to represent that B is above A

[copper temple]

Okay, ill give it a try

.close

[lone heart]

Channel closed

Closed by @copper temple

Use .reopen if this was a mistake.

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[foggy mica]

I dont understand how to solve this. The solution doesn't make sense to me. Why can't (1/7)*(1/6) work?

[analog gate]

Please solve this <@&286206848099549185>

3D Geometry question

[foggy mica]

This channel is occupied, bro. Can you use one of the available ones? they're the channels that are above these ones.

right now, they're #help-6 #help-17 and #help-18

[analog gate]

Ok

[foggy mica]

<@&286206848099549185>

[torn elk]

First of all, what is the total number of ways to assign 7 students to 7 chairs?

[foggy mica]

is it 7!?

[torn elk]

Yes, now how many ways to assign Sam and Chris to the 2 special chairs? (which is the events we are interested in).

[foggy mica]

2!?

[torn elk]

2, so

what are th total number of ways to assign the remainin 5 students to the remaining 5 chairs?

[foggy mica]

5!

[torn elk]

What is the favorable outcomes then?

[foggy mica]

uhh what does that mean?

[torn elk]

the number of favorable outcomes for the event we're interested in, which is Sam and Chris being assigned to the special chairs.

[foggy mica]

oh is it 2 and 5!?

[torn elk]

and is not a valid operator in this context

[foggy mica]

oh

so what do i use instead of and?

[torn elk]

times

2 * 5!

[foggy mica]

but im only used to multiplying probablities, how is 2 and 5! a probability?

[torn elk]

2 comes from 2!

[foggy mica]

yeah

[torn elk]

so you're gonna use outcomes now

the probability of an event is the number of favorable outcomes divided by the total number of outcomes

[foggy mica]

ohhh ok so I multiply the favorable outcomes when there is an and in between them

[foggy mica]

ok thanks a lot

[torn elk]

np

[foggy mica]

.close

[lone heart]

Channel closed

Closed by @foggy mica

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[white crater]

quick question, w the rule where if a^m = a^n then m = n, cant i set a = 1 and 'prove' that any number is equal to another number? like 1^2 = 1^3 therefore 2 = 3

im new w understanding logs so u might have to dumb it down for me 😓

[proven leaf]

Think about it like this. Let's take the logarithm of both sides: $3\ln(1)=2\ln(1)$. Now your idea if we divide both sides by $\ln(1)$ we get $3=2$.\~\

This is not correct, and the reason this funny busines happens is because we are dividing by $\ln(1)=0$ and division by zero is undefined and we get some funny results. :)

[ocean seal]

XxMrFancyu2xX

[proven leaf]

What really happens is we get: $1^3=1^2\implies3\ln(1)=2\ln(2)\implies3\cdot0=2\cdot0\implies$\fbox{$0=0$}

[ocean seal]

XxMrFancyu2xX

[proven leaf]

nvm I did it right lol

thought I did something wrong

[mortal trellis]

you dont have to argue with logarithms here. from the start, the property that a^m=a^n implies m=n is just not true for a=1

[proven leaf]

but there were asking about logarithms anyways so I thought I'd just show them why we can't cancel logarithms of 1 :)

[white crater]

ahhh okay yeah both points make sense thanks from both :)

.close

[lone heart]

Channel closed

Closed by @white crater

Use .reopen if this was a mistake.

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[orchid perch]

$\forall x P(x)$equals just $P(x)$ right

[ocean seal]

metnal

[orchid perch]

hmmm i guess i'd have to state that x arbitrary from the universe of disourse

.close

[lone heart]

Channel closed

Closed by @orchid perch

Use .reopen if this was a mistake.

[rose sigil]

P(x) on its own has no truth value

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[desert olive]

i need help

[desert olive]

I got that answer but I don't know why it is wrong

[worn fox]

leave your answer in terms of pi
for a start

[desert olive]

i did

[worn fox]

5760?

[desert olive]

yeah

[worn fox]

thats not in terms of pi

[desert olive]

it is

I just changed it but it is still wrong

[gray isle]

what did you change it to

[desert olive]

the same ans pi

[gray isle]

show your work

[desert olive]

i di

did

[gray isle]

where

how are you getting 5760 or 5760pi

[desert olive]

it is not clear

[gray isle]

do you have a clearer pic

[desert olive]

nope

[gray isle]

even looking closer, i don't see the full work

[desert olive]

i did 5428.67-3619.114737

[gray isle]

and doesn't show where you're getting
5760

[desert olive]

but it was terms in pi

[gray isle]

in terms of pi means that you actually have the symbol pi in it

i.e. you shouldn't have used a calculator to multiply pi(6^2)48
but just multiplied just the (6^2)48 to get
1728pi

same idea for the volume of the spheres

regardless that doesn't get you anything close to 5760

[lone heart]

@desert olive Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[cyan nexus]

dumb question but this is true right

[gleaming ridge]

Yes :P

[cyan nexus]

thanks a lot 🌑 🌙 🌝

.close

[lone heart]

Channel closed

Closed by @cyan nexus

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lone heart]

Please don't occupy multiple help channels.

[fresh arch]

But this would lead to triangle EXF congurent to triangle CXB which is stupid

So where is my mistake

And there is some bug with the sever because of which my previous channel is not visible to me

[tacit arch]

#help-4

[vale wigeon]

.close

[lone heart]

Channel closed

Closed by @vale wigeon

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[junior gazelle]

Is this a convex function? (|x|)

[alpine sable]

you can use the definition directly

(alternatively use the second derivative test)

[lone heart]

@junior gazelle Has your question been resolved?

Channel closed

Closed by @junior gazelle

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[nocturne vapor]

what does this question mean by "corresponding coordinates"?

[nocturne vapor]

nevermind i understand

.close

[lone heart]

Channel closed

Closed by @nocturne vapor

Use .reopen if this was a mistake.

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[errant shuttle]

i need help

[errant shuttle]

i need help in math i have a end of year test this friday

[tacit arch]

[wind cloak]

It's June but alright

[errant shuttle]

wdym

[wind cloak]

nevermind

Just ask your question

[errant shuttle]

i got to learn all 16 chapters in a math book

i need help with algebra and surds

and direct propertion and ration and y=mx-c

[tacit arch]

Help channels are for specific problems, do them

[errant shuttle]

ok ratio of 15243:7823

[wind cloak]

,w reduce 15243/7823

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by neonperseus#0

[wind cloak]

Coprime numbers