help-0

[alpine sable]

oh my bad

$$
x = \frac{0.6m^2}{1.1m} = 0.31355287256600434m
$$

[ocean seal]

weig

[alpine sable]

@white spear

did i make a mistake

[white spear]

All good man thank you so much

[alpine sable]

Awesome

[lone heart]

@white spear Has your question been resolved?

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[lone heart]

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[alpine nexus]

I was told to use inverse gradient to find one of my points on a cartesian plane, and although I think I have plotted the points correctly, I am having difficulty calcultating the difference in y. My teacher told me not use the gradient formula and stick to graphing as it helps you in the 'long run.'

The point to calculate difference in y, starts at 6 on the x axix, and then it goes all the way down to -4 from the y axis.
this is what I did

I went down from 6 to -4, and I found out that the difference will -10, and that was apparently wrong. And then I tried going up from -4 to 6 and I got 10, and that was apparently right. So like is there a specific way you have to do this, because its really confusing to find the difference in y, as it it is different, or am I just doing it wrong, because realisticly shouldnt it just be 10, if go up or down, like could you please help me out here

[rose temple]

aur bunty

[alpine nexus]

sorry?

[rose temple]

u indian?

[alpine nexus]

yes

[rose temple]

konsi state keho bhai

[alpine nexus]

punjab

[rose temple]

mera bhai

me2

[alpine nexus]

yessir

[rose temple]

ab bata sawal kya kehra its asking perpendicular distance from y?

[alpine nexus]

yes bascially

[rose temple]

hmm

[alpine nexus]

just the difference in y

[rose temple]

do u have the printed form of the question?

[unique trout]

are u indian?

[alpine nexus]

ye i do, but its on paper

[rose temple]

send a pic

[rose temple]

yup

[alpine nexus]

alright

[unique trout]

me too

[rose temple]

damn

nice

[alpine nexus]

its question 12

[rose temple]

ahhhh

u want to find slope

[alpine nexus]

yes I did that in this diagram, and after finding the line, I have to find difference in y, how do i do that

[rose temple]

p=15

[alpine nexus]

is it?

apperantly the answer is 25

[rose temple]

as long as there is no printing mistake p=15

[alpine nexus]

ohh

u used the gradient formula

makes sense

we are not allowed to use that, we can only graph

[rose temple]

ohh

well if u wanna do by geometry

than mark point x1y1

and plot y2

[alpine nexus]

yes

[rose temple]

than make 26 degrees

and ntersect

because gradient of 0.5 means 26 degree slope from x axis

[alpine nexus]

ohh alright

thanks!

.close

[lone heart]

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[barren portal]

Is it correct to say gcd of 2x and 4y is 2?

[barren portal]

The confusion arises because for specific x, y values gcd can vary

[vague coral]

gcd(2x,4y) = 2gcd(x,y) if I remember

[barren portal]

Say 2x+4y is a polynomial

[rose temple]

yea its 2

[mellow grail]

yes u take 2 common

[barren portal]

we say 2 is gcd of what?

[mellow grail]

so u can say 2x and 4y have 2 common for all x,y

[barren portal]

2x and 4y?

[mellow grail]

2x and 4y

[rose temple]

until or unless x and y have ratio having multiple of 2

[mellow grail]

he said 2*gcd(x,2y) since he was assuming that u put the values of x and y, ig

[vague coral]

gcd(2x,4y) = 2gcd(x,2y) my bad

[mellow grail]

but when hes factorizing he cant use that he has to use 2 no

hes factorizing 2x+4y

[mellow grail]

yes

[vague coral]

he was asking about gcd so huh

if he wants to factor 2x+4y, the common factor here is 2

so 2(x+2y)

[mellow grail]

yeah but he did that since thats how they teach factorizing. u find gcd(terms) and then take that common

they dont generally teach gcd(2x,4y) = 2*gcd(x,2y)

till like some later class (thats the case in most countries)

[barren portal]

well my question is (2,4)=2 clearly but does that imply (2x,4y)=2 for any x, y

[lone heart]

@barren portal Has your question been resolved?

[mellow grail]

No

it will be atleast 2

[mellow grail]

if thats ur question then @vague coral is right

[rose temple]

Yup it will be 2

Cpuld be more than 2 but that will depend on value of x and y

But given that they are variable its 2

[lone heart]

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[open warren]

Let f:<a, b) -> Y is differentiable on (a, b) and continious in a. Prove that if lim(x->a) f'(x) = c exists then f'(a) = c

[open warren]

I've tried to use theorem

But i don't know how to show that sequence f'n converges uniformly

[lone heart]

@open warren Has your question been resolved?

[open warren]

<@&286206848099549185>

.close

[lone heart]

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[heavy crater]

can someone help me with such a thing ?

<@&286206848099549185>

[rose temple]

Imaginary?

[heavy crater]

what do u mean

my teacher gave me this

and told me to solve the second one

and the first one is how is it solved

but i dont understand this

still

do u know any AI that can help me solve such a thing ?

[rose temple]

Z=2-2i

?

[heavy crater]

yeah

z=2-2i

z3

[rose temple]

And what u want to find

[heavy crater]

exactly

she got me confused

[rose temple]

U want z³

[heavy crater]

yesss

z3

[rose temple]

Cube ir

It

[heavy crater]

is there any ai

that will help me do this ?

anything for free

[torn elk]

Do you know how to do z^2?

[heavy crater]

no idont im so sorry im new at this

[torn elk]

Do you know what z^2 means?

[heavy crater]

no

[torn elk]

z^2 means z * z

[heavy crater]

ahhh

and z3 means

z z z

[torn elk]

so z^3 means z * z * z

[heavy crater]

ahhh

[rose temple]

2-2i×2-2i=z²=4 +4i² -4i

I²=-1 so z²=4-4-8i=-8i

Now z³=z²x 2-2i

Z³=-16i+16i²=-16-16i

[heavy crater]

wow

[rose temple]

👍

[heavy crater]

can u help me again but after some mins ?

[rose temple]

Umm ok

[torn elk]

That's wrong

[heavy crater]

guys , i can pay around 50 dollars if u guide me on my knowledge

cause i lack on mathematics

[rose temple]

How

[torn elk]

just re-check it

[rose temple]

Oki

Ah yess

2ab

[heavy crater]

can u fix the result ?

perhaps u did something wrong ?

[rose temple]

Now its correct

Ya i forgot to multiply by 2

[heavy crater]

ahh thankuuu

[rose temple]

Welcome

[heavy crater]

do u study by urself ?

or u go to college for this

[rose temple]

There are tons of good ques in imaginary especially the geometry ones

[heavy crater]

which kind of math is also applied on geometry ?

algebra ?>

[rose temple]

I learnt this when i was in school

[heavy crater]

and u didnt forget it ?

ure just talented bro

[rose temple]

Algebra is applied in geometry calculus is even imagenary numbers

[heavy crater]

ahhh

i wanna learn code

so which types of maths

benefits me on coding

[rose temple]

Haha yes

[heavy crater]

thanks god bro

lol

[rose temple]

Thnks

[heavy crater]

are u plannin

to code in the future ?

or be an architect

[rose temple]

Logical reasoning basic algebra matrices and determinants

[rose temple]

Geometry

[heavy crater]

yeah , ive tried all of these by myself

yeah i was really good at it

[rose temple]

Calculus?

[heavy crater]

i only lacked about that kind of math

no geometry

like i can visualise a lot even numbers

but not really like

[rose temple]

Calculus is used in geometry of complex shaoes to find area slope angle radius

[heavy crater]

know things in definitions and in concepts

[rose temple]

Ahhh

[heavy crater]

i had a terrible

highschool

and my teacher was shit

so i have to go all over and over again

and study by myself

[rose temple]

U can do one thing go through your school books

And then pick difficult ones

[heavy crater]

yeah

i should do something

[rose temple]

For calculus go for single variable book

[heavy crater]

do u know any site where i can learn all of maths

from a to z

[heavy crater]

so calculus will help with code ?

[rose temple]

Download books from telegram thats what i do

[heavy crater]

calculus , shows the motion of real physics ?

[rose temple]

Not with code but with architec

[heavy crater]

ah

[rose temple]

Hmm

[heavy crater]

ah really ?

[rose temple]

For coding learn matrices determinant probability stats

Basic algebra

[heavy crater]

i should keep this in mind

[rose temple]

Yes

You dont need to be a math wiz to code tbh

[heavy crater]

im going to work this whole month

[clever vale]

What are you guys talking about

[heavy crater]

he helped me solve a math problem

[rose temple]

Most of coding is just memorizing syntaxes and arguments

[heavy crater]

but now were just having a general conversation

about maths in general

[clever vale]

Ohh

[rose temple]

Got any more ques?

[clever vale]

Something about complex numbers

[heavy crater]

well how do u get the books in telegram

cause i know telegram is such a dark place

lots of scams happen in there lol

[heavy crater]

u saw the pic

2-2i×2-2i=z²=4 +4i² -4i

I²=-1 so z²=4-4-8i=-8i

Now z³=z²x 2-2i

Z³=-16i+16i²=-16-16i

this is the result

[rose temple]

Hmm

At top its 8i

Change 4 to 8

[heavy crater]

u can edit that

[heavy crater]

how

do u know any link

i need to grab some resources before its super late

for me lol

[rose temple]

Download telegram

And search jeebot

[heavy crater]

ah okay

[rose temple]

Jee is an indian enterance exam

Its very tough

[heavy crater]

oh

jee chemistry physicss handbooks and formula booklets

and a lot of things omg

[rose temple]

For example the question u asked is like the easiest question one can imagine in that exam

Its 2nd most difficult exam in wrld

Tahts why i know this stuff

[heavy crater]

ahhh

im like ahhh

cause i have to process what u saying

lol

do u have a keyboard

specially for mathematics ?

[rose temple]

No

[heavy crater]

how did u do the z3

the small 3

[rose temple]

Long press 3 on phone keypad

[heavy crater]

ahhhhhhhh

lol

[rose temple]

Android*

[heavy crater]

u on the phone

lmfao

im on my pc

so i cant do that

[rose temple]

Yea

At dentist rn

Otherwise i wouldve written on paper and sent answer

[lone heart]

@heavy crater Has your question been resolved?

[lone heart]

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[elder hinge]

ok so i have been dreading this question for days now since our exams and i still cant get why the answer is 1340

[elder hinge]

You are walking along a straight level path toward a mountain. At one point, the angle of elevation of the top of the mountain is 40°. As you walk 250 m closer, the angles of elevation are 45°?

I'm so confused on what to do

the opp is somehow 1340?

[lone heart]

What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above

[rustic coral]

Diagram?

[elder hinge]

drawing looks scuffed sorry

[rustic coral]

Since we want to find the opposite side, let's label that with a variable, say x

We can thus find ||the bottom side of the smaller triangle in terms of x||

Then say that ||tan(40)=x/(250+the bottom side of the other triangle)||

I gtg soon so here's a solution sketch

[elder hinge]

okok thx I'll try to solve

yeah i cant find the adj of the 45

like the bottom side of it

[lone heart]

@elder hinge Has your question been resolved?

[lone heart]

@elder hinge Has your question been resolved?

[elder hinge]

yaya

wat

wait

the angle of elev before u move is 40 then it turned into 45 si theres like 3 given stuff and idk what to do with it other than look for the side that is missing which is the 45 degree one and add it with the 40 degree one which is 250 so i can do tangent and just calculate it

i know the answer but idk how to get the answer

i dont have the solution

just the answer 😢

1340

opp

height of the mountain

yep

x is 1340

the base is what i use to get 1340

so i can like use tangent properly

yaya

yep either that or our teacher fucked up big time

Cuz this has kept me awake ever since her exam

i blame our teacher

yaya no worries thx for ur insight have a great day

[lone heart]

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[silent flint]

guys

[silent flint]

i have a whole worksheet of questions abt ceircle theorms

can someoen check someone of my answes

if so dm

ight

its the whole worksheet

ill ask spesific questions

https://piacademy.co.uk/gcse-maths-topic/geometry-and-measures/circle-theorems/

for q19

how do i do

y

i got x

x=66

wb y

u dont

only for answes u do

let me send ss

idk the answer

yea

whats y

19 firstly

then ill ask othes

its arranfged wierdly but q19 is after q16

ye same

wb y

thx bro

how?

oh

yea then its easier

how did yk alternatie interior angle

yea then i get it

ye

[lone heart]

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✅

[silent flint]

ye

my b

another one is

https://piacademy.co.uk/gcse-maths-topic/geometry-and-measures/volume-and-surface-area/

23

[lone heart]

@silent flint Has your question been resolved?

[tardy stag]

this one is just dimensional analysis

[silent flint]

what

[tardy stag]

can you figure out the area of the prism? like the area of that hexagon touching the ground?

for a prism (any prism!) volume = area * height

[lone heart]

@silent flint Has your question been resolved?

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[noble onyx]

For f(x) = x/(x^2 + 1) for all real numbers x
Is this function one-to-one?

[mossy laurel]

To find it out I would rather compute its variations

[noble onyx]

For the one-to-one proof i have completed this work so far. I want to make sure if this is the correct approach on how to continue in the proof

[wind cloak]

It would just be faster to show $f'(x) \leq 0$

[ocean seal]

neonperseus

[wind cloak]

But yes you're doing alright so far

Continue by bringing all the terms to one side and factorizing it

[noble onyx]

how would I do that?

[wind cloak]

Differentiate the function

[noble onyx]

-1/x^2 ?

this would always be less than 0 not including 0?

in the function -1/ x^2

[noble onyx]

if x is -1 or 1 in the differentiated function it would give the same output which makes it not one-to-one?

[wind cloak]

no no

If the derivative is always positive or always negative in the domain of the function it means that it will fail the horizontal line test

simply put

[noble onyx]

Got it thanks

Can I also simply provide a counterexample to it

[lone heart]

@noble onyx Has your question been resolved?

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[vapid shuttle]

don't troll

.close

[lone heart]

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[vapid shuttle]

this channel is occupied and closing soon, see #❓how-to-get-help on how to open your own help channel @high mason

[high mason]

oh sorry

[lone heart]

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[cobalt grotto]

.close

[lone heart]

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[night lodge]

how do i turn a fraction square root into -1/2 exponent?

[quartz parrot]

bruh

you posted in 2 channels

??

[proven leaf]

Consider two properties $a^{-n}=\frac{1}{a^n}$ and $a^{\frac{n}{m}}=\sqrt[m]{a^n}$

[ocean seal]

XxMrFancyu2xX

[proven leaf]

then as to how $\frac{1}{\sqrt{5}}=5^{-\frac{1}{2}}$ should be trivial! :))

[ocean seal]

XxMrFancyu2xX

[night lodge]

OH okay

i forgot the root over raise thing

ty

.close

[lone heart]

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[dreamy sun]

Can someone explain to why the definite integral went from -2 to 1, to -3 to 3? It is in Italian, and part of a bigger problem, so if anything is missing or it needs to be translated just ask

[plain flame]

you have to recalculate the bounds when you do a u sub

[dreamy sun]

how?

[plain flame]

so you have 2x + 1 as your substitution

so your new bounds would be 2 * (-2) + 1 and 2 * (1) + 1

[dreamy sun]

oh yeah u're right that was easy

not sleeping enough before finals can be dangerous

thx

[plain flame]

hahaha yeah been there

gl

[dreamy sun]

ty

.close

[lone heart]

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[mellow skiff]

x − 4| < 2

[limpid spade]

|x-4|<2?

[knotty elk]

can u help me in this problem

[vale wigeon]

!help

[lone heart]

Please read #❓how-to-get-help

[vale wigeon]

open your own channel

[ebon sparrow]

!status

[lone heart]

What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above

[proven leaf]

!status

[lone heart]

What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above

[proven leaf]

sorry Akira didn't see ur msg lol

[mellow skiff]

Sry

[ebon sparrow]

wdym sry?

[proven leaf]

idk tbh

[mellow skiff]

I was busy a bit

[knotty elk]

i don't understand how do make ur own chanel

[ebon sparrow]

oh

[proven leaf]

just type in an empty one like #help-23

[mellow skiff]

Okay so |x − 4| < 2

[ebon sparrow]

just send your question in any channel

in help channels

[proven leaf]

for absolute value consider two cases, either positive or negative

[mellow skiff]

Wait let me say How i think first

[proven leaf]

kk

[mellow skiff]

Because this is absolute value of x it can mean to be negative or positive

[proven leaf]

kind of, but keep going

[mellow skiff]

And we know it is less than <2

Because it is a magnitude

Its corresponding is -2

Which means the range of the values are between -2 and 2

-2<x-4<2
That means we can write it as Such and solve the solution.

[proven leaf]

[mellow skiff]

Here we can add the 4 on both sides because it represents the lenght that 4 is less than 2

I think

2<x<6

[proven leaf]

you are entirely correct 🎉

[mellow skiff]

Ok thx!

.close

[lone heart]

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• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[scenic wing]

im lost

[naive valley]

on which part?

[scenic wing]

g

[naive valley]

x intercept means what?

[scenic wing]

where the graph crosses x

[naive valley]

which means the function value equals..?

[scenic wing]

x

[naive valley]

which means the function value equals what number?

[scenic wing]

pi/2

[naive valley]

if a function crosses the x axis at some point, what is the function's value at that point?

[scenic wing]

idk

[naive valley]

what y value does the x axis correspond to?

[scenic wing]

0

[naive valley]

right

[scenic wing]

90 or 270 degrees

plus 180

[naive valley]

so if a function crosses the x axis, its value is 0 there

[scenic wing]

for y

[naive valley]

so where does cos x = 0?

[scenic wing]

pi/2

3pi/2

[naive valley]

yes, any others?

[scenic wing]

all the following points 180 degrees after 3pi/2

[naive valley]

i.e. pi radians after 3pi/2

[scenic wing]

3pi/2 +180, +180
or +pi +pi

[naive valley]

(not good to mix degrees and radians)

yeah so what's the pattern

pi/2, 3pi/2, 5pi/2, 7pi/2 etc

[scenic wing]

x times pi

for however many x intercepts infinite

[naive valley]

so which of the multiple choice answers does this correspond to?

[scenic wing]

C

[naive valley]

no

c says "k pi"

[scenic wing]

i tried d and it said no

[naive valley]

try plugging in some values for k

if i plug in k=0 to kpi, i get 0

is cos 0 = 0?

[scenic wing]

its A

[naive valley]

no

what do you get if you plug in k=1 into A

[scenic wing]

(2(1)-1)180/2= 90

ok ok ok

[naive valley]

i don't know what that calculation is

[scenic wing]

$\frac{(2(2)-1)180}{2}= 270$

[ocean seal]

putridplanet

[naive valley]

which answer is this for

[scenic wing]

NOW YUOOOOO SEEEEE

B

[naive valley]

so B is the answer?

[scenic wing]

https://tenor.com/view/correct-plankton-gif-14118231

[lone heart]

@scenic wing Has your question been resolved?

Channel closed

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• Show your work, and if possible, explain where you are stuck.
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[viral marsh]

For question 5 how do I break each force into x and y components to solve

[sand pawn]

imagine one of the vectors here as the base or along the 'x' axis

[viral marsh]

ok so how do I do it?

[sand pawn]

Let's think the 30N force as the 'x' axis

and the other 20N to have a 28 degrees top of the 30N

and draw another arbitrary force vector 'r'

So, Fx= FcosO

so, Fx = F1x + F2x

then you can compute for the 'y' components

then just find the components, the inverse of the components or negative value of the component's is your answer towards the resultant vector

[viral marsh]

shat would the angle be ?

[sand pawn]

the third child should impose an opposite force equivalent to the resultant of the 20N and 30N force

use this sentence

@viral marsh

[viral marsh]

so can I show you what i’m doing

you tell me if it’s correct

[sand pawn]

k

[viral marsh]

kk

id this correct

[sand pawn]

yeah, this is good

[sand pawn]

now, do this

@viral marsh

[viral marsh]

wait I got the angle wrong I put 30

it’s 28

let me just fix it

I did it

thanks

.close

[lone heart]

Channel closed

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[wanton turtle]

I dont really understand why all the angles of a star pentagon are equal to 180 degreee

[wanton turtle]

Let α, β and γ be the interior angles in the triangle AFG. ∠CGE=180°-α or ∠BFD=180°-β then applies to their secondary angles (external angle theorem for triangle AFG). In the triangle GCE, the two red-colored interior angles of the star pentagon together are as large as α+β (sum of angles). Likewise, the two blue-colored interior angles in the triangle FBD together are as large as β. Overall, the sum of the interior angles of the star pentagon is α+β+γ, so it corresponds to the sum of the angles of a triangle.

Im wondering why the two red angles are equal to a+ß

[limpid turret]

Which two red angles?

oh nvm

[wanton turtle]

E and C

I dont really understand why they are supposed to be a+ß

[limpid turret]

They're not..

I'm not sure how you're getting that

[wanton turtle]

The solution says so

[limpid turret]

show

[wanton turtle]

I tried out different things and it was never a+ß

[wanton turtle]

I literally sent the solution

"the two red-colored interior angles of the star pentagon together are as large as α+β (sum of angles)"

How do we know that?

[limpid turret]

This is false

[wanton turtle]

U sure?

[limpid turret]

Angles E and C alone sum to just α

[wanton turtle]

This is weird

[limpid turret]

Then B and D sum to β

So A E B C and D E, C, B and D all sum to α+β

Consider triangle EGC

[wanton turtle]

Wait, so if Id have to prove this having 180 degree

[limpid turret]

<EGC=180-α, so what does that tell you about <E and <C

[wanton turtle]

How would I do that? (Pg Im not that good at geometry)

[limpid turret]

Interior angles of a triangle always sum to 180

[wanton turtle]

Yes

[limpid turret]

So what part do you not know?

[wanton turtle]

Why are E and C equal to Alpha?

[limpid turret]

E+C=α

Not E and C are equal to α

It's important to distinguish that

[wanton turtle]

I get it, but how do we know that

[limpid turret]

Use this property on triangle EGC

[wanton turtle]

Well, we have C, E and 180-Alpha

C+E+(180-Alpha)=180

C+E = Alpha

Omg, I think I just understood

So the solution was wrong?

[limpid turret]

yes

Looks like it typod and meant just α where it wrote α+β

[wanton turtle]

Would it be fine if I try to prove the rest?

[limpid turret]

go ahead

[wanton turtle]

Like okay, now we know that E+C=a

What do we do now?

Or whats the next step

[limpid turret]

Figure out D and B

(I am a typo machine today)

[wanton turtle]

It makes sense

Thats what I thought

We use the same logic here

(180-ß)+B+D = 180

B+D = ß

Now we know the angels E, C, D and B

G and F as well

What now?

We still have Y missing

[limpid turret]

You want to prove A+B+C+D+E=180, right?

[wanton turtle]

Yes

[wanton turtle]

Hmm

[limpid turret]

You have gamma in triangle AFG

[wanton turtle]

Yes

[limpid turret]

so what does that tell you about alpha, beta, and gamma?

[wanton turtle]

Their sum is equal to 180

And we have a and ß already

That means we could implement them in an equation?

B + D + E + C + Gamma = 180

But its still not a prove, we do not have values. Right? (Probably wrong)

[limpid turret]

What is the measure of angle A?

[wanton turtle]

180 - (Alpha + Beta)?

[limpid turret]

yes

So, what is A+B+C+D+E?

[wanton turtle]

And this is basically the prove?

[limpid turret]

yes

[wanton turtle]

180? I suppose

Omg, you dont know how u rescued me

I have an exam soon and I was never good at geometry

Thanks

[limpid turret]

glad to help

[wanton turtle]

One little question before I go

Isnt direclty about math. Is it noticable that Im not an english person?

[limpid turret]

Yes

[wanton turtle]

Language etc.

Bc Im working on my english

[limpid turret]

You say "prove" in some areas where you mean "proof"

I respect anyone working on their language skills

So good luck to you

[wanton turtle]

Yes... Idk wheter its fine. Can I maybe send u a friend request or u wont accept?

[limpid turret]

I won't accept. Sorry

But thank you for asking first

[wanton turtle]

I appreciate your opinion so its fine

Thanks

Im gonna close the help channel now

.close

[lone heart]

Channel closed

Closed by @wanton turtle

Use .reopen if this was a mistake.

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Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
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• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[alpine sable]

How do I simplify 12/tan(30) into radical form?

[proven leaf]

I'm going to assume that's 30degrees and not radians

first, what is tangent in terms of sin and cos?

[alpine sable]

opp/adj

@proven leaf

this was my work so far

but i want to know how to put it into radical form/simplified form, rather than decimal form

[proven leaf]

the way we do that is by beginning with turned tan into sin and cos

[alpine sable]

look

[proven leaf]

yes...

[alpine sable]

so what would you do?

[proven leaf]

^

[alpine sable]

how?

[proven leaf]

oh, have you not done the unit circle yet?

[alpine sable]

my geo teacher skipped that

[proven leaf]

that's kinda important

[alpine sable]

now i need it for ap physics work

[proven leaf]

unit circle is so important ur teacher is garbage

[vale storm]

omg john quinones

[alpine sable]

how would you go at understanding it?

[vale storm]

(for someone who doesnt know it at all)

[alpine sable]

do you have a good video, or good explanation?

[proven leaf]

organic chem tutor is always good :)

https://www.youtube.com/watch?v=V5ArB_GFGYQ&ab_channel=TheOrganicChemistryTutor

otherwise Khan Academy never fails but I prefer Organic Chem Tutor tbh

[vale storm]

i hate that guy

apparently he said the n word

and called black people racist stuff

[alpine sable]

Yoo

So I have to watch an hour video

to fully understand it

also wondering,

is the unit circle on the SAT or used in physics?

[proven leaf]

it's kinda used, well, everywhere...

but you don't have to watch the entire for a bsic understanding

[vale storm]

how hard is the unit circle to learn?

like out of 10

[proven leaf]

there's nothign to compare it to though...

but for me like a 2/10

[vale storm]

for a 8th grader

[proven leaf]

6-7/10

it can be unintuitive

[vale storm]

what would be considered like 9 for a 8th grader

what topic

[proven leaf]

deriving the quadratic formula

[vale storm]

ok

[alpine sable]

@proven leaf what did u get on the SAT?

[proven leaf]

we don't talk abt that

[balmy solstice]

idk about u but we just memorised the values of trig functions

tan(30) = 1/sqrt3

[proven leaf]

our teacher gave the intuition behind it and I think it helped a TON

[vale storm]

what does derive mean

[proven leaf]

I could just visualize it in my head

[alpine sable]

whats the intuiton behind it?

[vale storm]

wait

[proven leaf]

$$ax^2+bx+c=0$$
\begin{center}
To complete the square, we must first make sure our $a$ term is equal to $1$.
\end{center}
$$x^2+\frac{b}{a}x+\frac{c}{a}=0$$
$$x^2+\frac{b}{a}x=-\frac{c}{a}$$
\begin{center}
Completing the square requires taking half of the b term and squaring to satisfy the equation: $(a+b)^{2}=a^2+2ab+b^2$ then adding it both sides of the equation to keep the equality.
\end{center}
$$x^2+\frac{b}{a}x+\frac{b^2}{4a^2}=\frac{b^2}{4a^2}-\frac{c}{a}$$
\begin{center}
Simplifying both sides. On the left, using the perfect trinomial equation: $(a+b)^2=a^2+2ab+b^2$ and on the right, just adding the fractions.
\end{center}
$$\left(x+\frac{b}{2a}\right)^{2}=\frac{b^2-4ac}{4a^2}$$
\begin{center}
Square rooting both sides.
\end{center}
$$x+\frac{b}{2a}=\frac{\pm\sqrt{b^2-4ac}}{2a}$$
\begin{center}
By subtracting on both sides of the equation, we get the revered:
\end{center}
\centerline{\fbox{$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$}}

[ocean seal]

XxMrFancyu2xX

[vale storm]

wait

i thought the quadratic formula was a^2 plus b^2 = c ^2

[alpine sable]

its ax^2+bx+c=0

[proven leaf]

that's the Pythagorean Theorem

[alpine sable]

a^2+b^2=c^2 is the formula for triangles

[vale storm]

oh

[alpine sable]

?

[vale storm]

bro i never learned this in my geometry class

[alpine sable]

@proven leaf

[proven leaf]

you learn that in algebra class

[vale storm]

wtf my algebra teacher was ass

[alpine sable]

bluds algebra and geometry teacher failed him 💀

[vale storm]

we are from the same school

[vale storm]

we have the same classes

[alpine sable]

whats the intuition behind the unit circle

[vale storm]

dont start

[proven leaf]

watch the video lmao

[alpine sable]

how long

[vale storm]

1hour

[alpine sable]

bruhhhhhhhhhhhhhhhhhhhhhhhhhh

[proven leaf]

nah u dont have to all of it lmao

just up until you get to sin,cos,tan :)

[vale storm]

oh...

[alpine sable]

oh...

[proven leaf]

once u know what they mean you might be able to figure out the rest

[vale storm]

ok...

[alpine sable]

thank you :)

[proven leaf]

instead of memorizing terms, you'll know ah, on the unit circle sin is the y-component and on a 45-45-90 triangle that is 1/sqrt(2) so sin(45)=1/sqrt(2)

[alpine sable]

do you have any study playlists or anything to get a 1600 on the SAT... i heard the math section was pretty free...

[vale storm]

woah there

sqrt

woah

[proven leaf]

honestly Khan Academy has a great practice SAT part of their website

[trim sorrel]

I will forever be an ACT proponent

[alpine sable]

whats the diff

[trim sorrel]

btwn SAT and ACT?

[alpine sable]

yea

[proven leaf]

format pretty much

[trim sorrel]

ACT has easier questions, bigger time crunch, and more lenient grading if you want a perfect score

if u get like more than 1 wrong on the SAT ur not getting a 1600

if u get a few wrong on ACT u can still get 36

[proven leaf]

also SAT is more preferred on east and ACT on west I think

[vale storm]

do colleges rank sat the same level as act?

[trim sorrel]

oh interesting i didnt know that

[trim sorrel]

p much

They really dont care a whole lot about test scores anymore

[vale storm]

like will colleges care more about one

[alpine sable]

might aswell take both?

[trim sorrel]

No

No😭

[vale storm]

ok

[trim sorrel]

Dont do that to urself

Choose 1 and take it

[vale storm]

if we take both

are we required to show both scores

or can we just show the easier one

[trim sorrel]

Ur not required to show anything

[vale storm]

the better one i mean

[proven leaf]

some schools are test optional

[vale storm]

OH

[alpine sable]

you can chose whatever you want to show

lol

[long axle]

I’m p sure SAT has less subjects than ACT

[trim sorrel]

Yes

ACT has an extra science section that's basically just fast reading comprehension tho

[proven leaf]

ACT has science

[vale storm]

wait if i take math act do i HAVE to take english act?

[proven leaf]

its on the SAT too

[trim sorrel]

I think so its all one test

[vale storm]

ok

[proven leaf]

my SAT was like 5 hours

[alpine sable]

how do yall practice reading/writing? or should i go to .gg/literature lol

[vale storm]

WTF

[vale storm]

is that normal

[proven leaf]

8am-1pm

nah our proctor was slow as hell

others got out at like 12pm

[vale storm]

damn

good for u

[trim sorrel]

Writing should be fine, for reading theres always a logical way to go about it since their grading cannot be subjective

Find the thing that's wrong in each answer choice bc there WILL be something

[long axle]

I just did khanacademy to study for sat

[trim sorrel]

Also just learn the patterns for each question

[alpine sable]

so just guessing strat

you get hints from each question

[trim sorrel]

Bros named yeat

[vale storm]

💀

[proven leaf]

if you're running out of time, yes guess

[trim sorrel]

Dont guess theres like a singular right answer

[alpine sable]

yes twizzy 💯

[trim sorrel]

my money be twerkin my money do dances

[proven leaf]

but ONLY if ur running out of time

a filled in answer is better than none

[alpine sable]

No like, get hints from other answers to verify/check your answer

[trim sorrel]

Sure u can do that

[proven leaf]

that most likely wont happen but yes

ur not allowed to go back to a prevous section tho

[alpine sable]

no answers

like the multiple choice ones

[vale storm]

listen to my ultimate guessing strategy

[alpine sable]

on the same question

[trim sorrel]

Sometimes u can use previous answers to infer next ones

in reading

[vale storm]

if there are 4 multiple choice questions

[alpine sable]

No like the choices on the questions

[vale storm]

there will be one that is completly wrong

dont choose that one

then there will be 2 that are similar

its one of them

[trim sorrel]

The other 2 will be subtly wrong

[vale storm]

then

[proven leaf]

it's the SAT they're always trying to trick you btw

[vale storm]

from the 3rd question

[trim sorrel]

Are yall high schoolers

[proven leaf]

READ QUESTIONS CAREFULLY

[vale storm]

the 3rd question gives you a hint

[alpine sable]

yes

[trim sorrel]

Good luck

[vale storm]

and you use that for the 2 quiestion

s

[alpine sable]

we

[trim sorrel]

Rising senior?

[alpine sable]

no

[vale storm]

yeat is entering hs

[trim sorrel]

Oh shit😭

[alpine sable]

we r both enter

[vale storm]

waht

[trim sorrel]

Yall are like what 15?

[proven leaf]

I messed up a math question that said how many solutions in the equation 3x+5=4x+4 and I said 1, but that's also the answer to the equation 😭

[vale storm]

we have to do ap phisics

[vale storm]

14

[trim sorrel]

Ay i took that freshman year hs too

[vale storm]

WW

[trim sorrel]

It's a great class

[vale storm]

im scared of it tho

[trim sorrel]

If u have a good teacher

U should be

[vale storm]

i feel like its gonna be impossible

[vale storm]

😭

[trim sorrel]

Mechanics only or E&M as well?

[proven leaf]

APs aren't too bad

[vale storm]

really?

[trim sorrel]

AP physics is hard

Im ngl

[proven leaf]

you have to get used to them

[trim sorrel]

True

[proven leaf]

i think he means AP Physcis 1, AP Physics C is hard 😭

[trim sorrel]

Ohhh LMFAOO

I did C

[vale storm]

whats the difference

[trim sorrel]

C is calculus based with mechanics and E&M

[proven leaf]

(electricity and magnetism)

[trim sorrel]

Right i should have explained that 😭

[vale storm]

me and yeat have to do ap physics cause we r in engineering magnet

i hate how it requires ap physics

[trim sorrel]

Damn

I mean

u kinda need it for eng

[vale storm]

WTF YEAT

YEAT IS SAYING SO MANY THINGS

IN VC

CHILL @alpine sable

[alpine sable]

kid

[proven leaf]

bro this started with a simple question about tan(30) 😭

[alpine sable]

;loool

[trim sorrel]

15 year old calling someone kid...I must laugh...

[vale storm]

im older then you son

[alpine sable]

no your not

[vale storm]

14 both of us

[vale storm]

stfu

[trim sorrel]

Sheesh

Get off discord

Trust me

[alpine sable]

only use it to call

[vale storm]

what

[alpine sable]

insta is weird

[trim sorrel]

Ts tanked my mental health soph year

[alpine sable]

to clal on PC

call

[vale storm]

nah yeat uses it for other things

[alpine sable]

bro lying on my name

[trim sorrel]

bro probably e dates

[alpine sable]

💀

[vale storm]

nawh something else

if you know what i mea

n

[alpine sable]

dude droolg has a black pfp bc his ekitten left him

[proven leaf]

yes dw we know what u mean

[vale storm]

what

[alpine sable]

this kid is so weird

[vale storm]

no

stop lying

[alpine sable]

hes in this egirl server bro

[vale storm]

i clown people with ekittens

YO

STOP LYING

[proven leaf]

alright please go play with each other somewhere else

[trim sorrel]

damn i forgot what it was like to be 14

yall have fun

[vale storm]

DONT MAKE ME SEND THE SCREENSHOT OF U IN THAT CORN SERVER

[proven leaf]

.close

[lone heart]

Channel closed

Closed by @proven leaf

Use .reopen if this was a mistake.

[alpine sable]

?????

[vale storm]

yeaaa

thats what it hought

[alpine sable]

ok shut up

this is a form,al server

[proven leaf]

please go fight in DMs 😭

[alpine sable]

.

^

[vale storm]

alright i wont share ur secrets mb

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tacit arch]

Exp and log are inverses

exp(log(z)) = log(exp(z)) = z for all positive z

[cobalt ermine]

oh sorry thats just how wolfram produced my input its e^(6ln|x|)

oh so would the (e^(6ln|x|))^(1/6) turn into e^ln|x| ?

[lone heart]

@cobalt ermine Has your question been resolved?

[tacit arch]

exponent rules

,tex .exp rules

[ocean seal]

rie.mann

[tacit arch]

a = e, x = 6ln|x|, y = 1/6

[cobalt ermine]

ok give me a minute

[worn fox]

their answer is wrong fwiw

[cobalt ermine]

???? @worn fox

how so?

[tacit arch]

,w solve dy/dx = (1+y^6)/(xy^5)

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by rie.mann#0

[trim sorrel]

I believe discontinuity at 0

[worn fox]

they just left out the ^6

[tacit arch]

omcheezus i'm blind

[worn fox]

all your working is fine and you have the right answer. after you simplify the e^log you'll get this (for positive x)

[cobalt ermine]

k thanks!

.stop

.close

[lone heart]

Channel closed

Closed by @cobalt ermine

Use .reopen if this was a mistake.

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Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[chrome depot]

Right triangle is given.

Radius of excircle is 15. Radius of incircle is 6. Find lengths of sides.

[chrome depot]

Please follow my logic and tell me where I am wrong

1. In right triangle, excircle lies on midpoint of hypotenuse (c). Therefore, R = c / 2. From this, it follows that c = 2 * R = 30.

2. We know that median, coming from right angle vertex, is half of the length of hypotenuse. Therefore, that median has length of 15.

3. We now have a triangle whose sides are half of hypotenuse (c/2), lower side (a) and that median line (whose length is 15).
   Therefore, length of side a is equal to (c/2)^2 + (c/2)^2 --> a = 15 * sqrt(2)

Where am I wrong?

[worn fox]

how does the excircle lie on the midpoint of the hypotenuse?

[chrome depot]

Center of excircle does

As far as I know, that's a well known fact in a right triangle?

[worn fox]

an excircle lies outside of a triangle no?

[chrome depot]

As far as I know, in this case no

It's exactly on the midpoint of hypotenuse

[balmy solstice]

the centre is inside

[chrome depot]

I have used wrong word!

I am sorry

How do you call a circle that touches all 3 vertices?

[balmy solstice]

circumcircle?

[chrome depot]

May be, I don't know the word in English for it

[worn fox]

that makes a lot more sense

[chrome depot]

That's what I am talking about

[chrome depot]

That one!

[balmy solstice]

sry i thought thats what u meant as well lol

[worn fox]

so you have this kind of set up

[chrome depot]

But where is my logic wrong then?

[worn fox]

i think your triangle in part 3 is not necessarily right angled

[chrome depot]

Median line goes towards the middle of hypotenuse. Middle of hypotenuse should be at 45 degrees, or at the half of right angle ?

[worn fox]

you might be assuming that your original triangle is also isosceles

[chrome depot]

That may be true

Ah sadness

Can you tell me, while you are still here

Does radius of incircle, in isosceles triangle, have the length of 1/3 of height?

[worn fox]

i dont think so

[chrome depot]

Alright

I will be asking more soon I suppose

Thank you for the help!

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[lone heart]

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[shadow sparrow]

Can someone help me solve the second derivative? I've already found the first derivative:

[shadow sparrow]

$t^3(1+4lnt)$