#help-0
1 messages · Page 173 of 1
5
ok
if I start, moving away aswell, if I start walking south, will we be moving apart faster or slower?
faster
okay
So me and you are on the sidewalk. You start walking north at 5mph, and I walk south at 1mph. This will make us move away faster than before (which was 5mph). So how fast are we going apart now?
hint: the only difference is that I started moving away, this adds to the speed we are moving apart
7? im not sure this is my understanding
could you tell me why you think 7?
i dont know too but i think its 4 or 3
4
atleast that's faster this time! but 7 is not correct, and the reason is because you just randomly chose 7,
the answer here is not random
try to look back at the question 1 more time
Okay
we move 10 mph away from eachother
this is my last answer
if this iswrong
please explain it to me
well, it is wrong because you randomly guessed again
the reasoning is
if you go 5mph away
and I go 1mph away
the speed we are traveling apart
6
adds
yes!
so in total we are going apart 6mph
because instead of it only being the speed you go away, I add to the speed by going away aswell
Two passenger trains left the station at the same time and traveled in opposite directions. One traveled at the rate of 50 km/h and the other at 45 km/h. After few many hours are the trains 315 km apart?
so for this,
one train is traveling 50km/h away
and the other is traveling 45km/h away in the opposite direction
so the total speed they are traveling apart from eachother is?
95 km
thank you
how long until they are 315 km apart?
yes
are we gonna divide?
yeah, what do you think we should divide
315 and 95
what which by what ?
AustinU
no
if they go apart at 95 km every hour
then in 2 hours they are apart 190km
in 3 hours they are apart 285 km
and so on
so the answer will clearly be above 3
95/315 is not above 3
yes
315/95 is the proper next step
it answers: how many times do we have to go 95 km to get to 315 km
3
not exactly 3
but around that
the answer is exactly 315/95....
good luck with the rest of this, goodnight!
if you can't recognize that 315/95 is just a number about the size of 3, I'm not sure how I can help
the trains move apart 95 km every hour
how many hours will it take for them to move apart 315 km?
that is answered by 315/95
so the answer is
315/95 hours
that is how long it will take
however many times 95 goes into 315
if it asked, how long will it take for them to go 95 km apart
you would see that it is 1 hour
because they go 95 km apart every hour
if it was 190 km
then it would be 2 hours
because 190/95 = 2
so for 315 km
the answer is 315/95 hours
thanks austin
np
i understand now
great!
this gave me a little headache ☠️ but yes tbh ur great at teaching
can i not close this
for future purposes
well thank you! You can take screenshots and leave it open for now, but sadly it will close eventually on its own
but feel free to take pictures or something to save it if you need
thanks
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I'm trying to understand the integration of these $$\int^{\frac{2\pi}{\omega}}{0} e^{2i\omega t}\omega L dt = \frac{e^{4i\pi}-1}{2i}L$$ $$\int^{\frac{2\pi}{\omega}}{0} e^{2i\omega t} (\omega C)^{-1} dt = ?$$
Hin
I don't understand how the first integration has ended with that result.
also is that for fourier transform just curious
hmm ah no. it's electric engineering
well since we are integrating everything with respect to t, you are integrating be^(ax) normally
theres nothing special going on
ah so
I thought like the omega in the interval 2pi/omega affects anything in the integrating process
no
you just sub it in
its just a normal number to sub in
since we are integrating with respect to t
anything that isnt t
means nothing
its well b^-1?
isn't the both of integrating in the form abe^(acx) ? or something like that because of the omega being exponential
$\omega L e^{2i\omega t}$
Hin
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need a lil help with this integral
Suro
which is equal to $\int \frac{1}{4((\frac{x-3}{2})^2 + 1)}$
Suro
which is equal to $\int \frac{1}{4} \times \frac{1}{(\frac{x-3}{2})^2 + 1}$
Suro
Suro
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How do I convert this to Cartesian?

@limber crow Has your question been resolved?
<@&286206848099549185>
Mine wasn’t ether
@limber crow Has your question been resolved?
could someone help me with question 8c and 8d? please
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I let f(x) = ax^2 + bx + c. From f(2) + f(3) = f(5), I got:
4a + 2b + c + 9a + 3b + c = 25a + 5b + c
13a + 2c = 25a + c
c = 12a
Then, from f(2)f(3) = f(6), i substituted c = 12a to get
(4a + 2b + 12a)(9a + 3b + 12a) = 36a + 6b +12a
(16a + 2b)(21a + 3b) = 48a + 6b
2(8a + b)3(7a + b) = 6(8a + b)
7a + b = 1 ... (1)
From f(1) = 1, i got a + b + c = 13a + b = 1 ... (2)
so, subtracting (1) from (2), i got 6a = 0 <=> a = 0, which means c = 0
however, f is a second-degree polynomial, which means a can't be 0
in which part did i do it wrongly?
q = 1 isn't the only solution to
pq = p
what's the other solution?
have a think about it
rearranging the equation to general form
and factorisation would be helpful
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is what im doing correct?
i forgot to add lim_h->0
|0| = 0
which exists
then the function is differentiable at 0?
how?
You should have |h|/h
but the function is x|x|
Actually no no I’m blind
not just |x|
Never mind me 
lol its okay
Yea you’re fine then!
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can someone explain why the integration of ln(1-x) turns into a negative?
do you mean to ask why it is subtracted and not added
No i mean why is the integration of ln(1-x) = -1/1-x and not +1/1-x
chain rule
the primitive of ln(1+x) is not 1/(1+x) as far as I'm concerned
also, since when is the integral of ln(1+x) 1/(1+x), isnt it (1+x)(ln(x+1) -1)
,w Integrate ln(1+x)
I can understand why $\int\left(\frac{1}{1+x}+\frac{1}{1-x}\right)\mathrm{d}x = \ln\frac{1+x}{1-x} + C$ but why the other way around?
Yeah the model solution's just wrong
also who the ffuck says primitive
Someone whose keyboard is being a bitch
Antiderivative
There happy
I had to dodge autocorrect
what is integral correcting as
,w simplify integrate ln((1+x)/(1-x))
Yeah the answer key is just wrong
I think so, too.
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find the parametric equation of the intersection of these two cylinders :
x^2 + y^2 = 25
y^2 + z^2 = 20
if it was something like z + y = 20, then I would simply do
x = 5cos(t)
y = 5sin(t)
z = 20 - 5sin(t)
but since they are squared I do not know what to do
and if I take the root for z, I end up with a +-, which I don't want
hmm
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@crisp iron
@amber niche Has your question been resolved?
okay, so after looking carefully, it seems that there is no choice but to split it into the positive root and the negative root
i'm not sure but it looks that way...
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if f(x+2) = x^4-4x^3+3x^2+x-6. find f(1), then find 2f(3)+4. im confused on how to do it
notice f(1) = f(-1+2)
you have an expression for f(x+2)
yes
sure
if the middle term of (2b^2n-4+6b^3-n)^6 has no variable. what is the value of n
actually like 2 more questions i need help on after this lol
what does the "middle term" mean
uh
idk either
thats what the question gives
wait
how about
this other question
what is the cofeeiient of the x^2 term in the expansion of (ax+2/a)^5?
@quasi vector
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hey ima kinda lost
differentiate is the verb form of derivative
is it $f(x)=2^{3x}$ or $f(x) = 2^3 x$ ?
riemann
first
do i use
riemann
no, that is for taking the derivative of a product
AustinU
first use some of the rules to simplify it
use the reverse of the product rule
and 2^3 is?
and then once it is simplified you will use these derivative facts: derivative of $C * f(x)=C * f'(x)$ and derivative of $a^{x}=ln(a) * a^x$
AustinU
where C is a constant
Are you saying this is 2^(3x)?
im lost
confused by ur question
What did you write this for
reverse product rule
AustinU
yes
so (a^3)^x
and a being?
so from here
and then the 2^3 is?
8 and then its 8^0 ya?
yeah
use the second tip in this text here to take the derivative of 8^x
not quite
AustinU
so thats ln(8) * 8^0
ln(8) * 1
ln(8)
i think we went wrong somehwere
if that is the final answer
can you send the original question
Let f(x) = 2^3x. Find fprime(0)
seems to me like ln(8) works out
on the practice sheet thats not an answer tho they give u 5 possibilities
what are the possibilities?
3, 3ln(2), 1, ln(2), 0
does that help you see the correct answer?
AustinU
oh
ohhhhhhhh we did it right
i didnt know ln(8) could be 3ln(2) my bad
thank you austin
no problem
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Is this correct?
Can x be 1?
what happens when you plug 1 into f(x) ?
1?
nope
Try plugging it into the original function. You should notice a problem
what happens when you plug x=1 here
0
Result:
Infinity
,wolf 1/sqrt(1-1)
have you heard of divide by zero error?
yeah
then x can't be 1
I was solving this and the answer given is x=0 and 1
I got 0
But not sure how can I get x =1
solving what
what's the original question asking for
locations where the derivative is undefined but the original function is, are critical locations
Substituting 1 is making the function undefined, so that's why it is considered?
@dim matrix Has your question been resolved?
@dim matrix Has your question been resolved?
@dim matrix do u still need help
yeah, I'm not clear if I need to consider 1 or not as a critical point.
The solution is stating that though 1 and 0 are critical points, we can't consider 1.
yeah we actually just did this unit and it tripped me up too, what is the difference between 0 and 1 in this case
like how did you get 0 vs 1
key word is point, not number
there's a spider on my computer one minute lmao
this
yes your critical numbers are 0 and 1
the 0 makes your derivative = 0 and the 1 makes your derivative = undefined
yeah
The solution is stating that 1 can't be considered.
what did you do next
I need to understand why I can't consider 1 here, for which reason.
the question wants you to do the 2nd derivative test
so get the 2nd derivative 🙂
I rushed but I got 1/2(1-x)^3/2
so just please tell me you got the same thing lmao
just do it you will see why
with 1 ?
okay
lmk when you have it done
maybe wrong
Can't figure
I rushed and this is on old scrap paper that I have already used as scrap paper
you're right lmao
rewrite it so it's -1/ everything though
just to make this extra clear
that it is in a denominator
check with wolfram
okay
So here, now if I use x=1, it will be 0
2nd derivative
But we need to substitute critical points into the 2nd derivative.
yes we do
I'm trying to show you why the 1 doesn't work
plug the 1 in, you get -1/(0)
which equals what
idk abt infinity this was where I was going
yeah, same thing.
that implies that there is no second derivative at that point right?
yeah, or at least we can't get the answer with the second derivative.
wasn't that what you were asking?
the point is, how without going through the second derivative they abandon 1
abandon?
I mean they didn't consider
who is they
the explanation
could you send a screenshot of the explanation
yeah sure
I think all you need to see is that because the 2nd derivative doesn't exist it cannot be applied at that point
doesn't exist at x=1 (and the original function and 1st derivative too lol)
this
OH
ok sorry, they abandoned it when they saw that 1 is outside of the domain of f'(x)
that's their way of saying how they know the 2nd derivative at that point doesn't exist
what does 'outside of the domain' mean?
helloooooooooooo
um
an x value "outside of the domain" is an x value in an area where the function doesn't exist
I'll send a picture
what is 2+2??
so any x value that is less than 0 is "outside of the domain" of the function
because as you can see from the graph there is no line when x is less than 0
It's actually hard to figure 2+2
GUYS WHAT IS 2+2??
sirius u good now
I'm trying to understand.
Is it bcz they mentioned in the problem?
these are both ways of showing how the test does not apply at that point because there is no 2nd derivative at that point
watch a video on the domain of functions if you really want to understand the explanation, but as long as you can tell that there is no second derivative there I think you are good
Okay, I will. Thank you so much @merry spire 🙂
I feel like I didn't actually do anything lmao good luck!!
No, it helped me a lot. I need to go through an explanation on domains.
Thanks again!
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need help with c i
Yh Yh Ik Unrelated but, Can Anyone Decode this Binary? 00010111 11010001 11000110 00100110 00100011 00100010 00001111 01001011, Pls Just idk into what maybe Pls Ya Can try everything and then see what makes the Most Sense or smthn pls, Pls Help me out here 
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close one of your channels
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!help
Please read #❓how-to-get-help
Yh thx
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@frozen charm
yes
do this or i'll do it for you
y tho theyre two different questions
doesn't matter. read the bot message
[and ideally don't blank replies either
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For your other question, I said this:
#help-2 message
As to how you could have done it 
oh sorry i didnt see your msg but was able to do it thanks tho
As long as you got it in the end 
@pseudo ice any tips for c i ?
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So, I kinda need a lil help, at least some guidance I guess, I'm trying to generate equations for motion in what is basically a linkage mechanism of N links, in any configuration (but I'm trying to do it in a continuous configuration first), however I'm kind of lost
This of course using differential equations and such
Any help or guidance would be appreciated
Some extra context, I made this software that simulates a 4 bar linkage mechanism, however I just derivate the positions, velocity and acceleration vectors using trigonometry, I'm trying to simulate this, and any other mechanism of greater number of linkages (in any configuration)
I was reading a paper regarding pendulums that kind of help me but... a series of n segment pendulums is not that similar to what I'm looking for
hmm, okay so the assumptions are typically that that the input is not overdetermined and everything is rigid
Is a mechanism, so it moves, but each linkage is rigid, yes
also, velocity and acceleration can probably be first ignored
so focusing rigidness + position is probably the way to go
yeah, my initial attempt with a n linkage mechanism was using unity physics system but... it simply freaked out and it didn't really work, so I'm trying to code myself the physics simulation
hmm I don't think a full physics simulation is required
I mean, I won't code any kind of collision, is not necessary for what I'm looking for
though there must be an assumption that the positions pretty much define finitely many configurations
I only really care about position, velocity and acceleration, and technically I can derive velocity and acceleration out of the position
yeah this kind of a problem... if you don't mind let me give draw you a diagram of what I'm looking for
yeah drawing would help
formalise all the parameters you have and what you want to calculate
because to do it in generality would be hard but doing small examples is not too hard
This is a simple 4 bar mechanism linkage, all I'm given at the start is the positions A and B (and by extension the vector AB), the lengths, r1, r2, r3, and the masses of r1,r2,r3
Being that is a mechanism the rotational movement on r1 with respect to A will move r2 and subsequently will move r3
Assuming only those parameters I'm trying to find
- a general movement equation for the joint points
- the same as 1, but given a rotational force in r1
This is the simplest setup, my goal is to extend it up to r_n and in different configurations
forgor to ping
you can calculate the endpoint E between r1 and r2, then you have the distance EB, then you can use trigonometry to find the configuration of r2, r3
of course the next question is because r2, r3 don't have a uniquely determined solution (there's two configurations), so one would probably need to estimate the velocity of each of the nodes to figure out which configuration is more appropriate
Yeah, that's kind of the thing, I do have the trigonometric formulas for this case, the four bar linkage, and I have solved the problem of multiple configurations, however this doesn't take into account the mass of the bodies to determine their motion, nor what happens with an applied force to each linkage
idk if I'm being clear on that, sorry
I think you are looking at a different problem than just finding the configuration, we need to refine that
mass generally isn't too much of an issue, unless you are doing something which involves checking the strain at each joint
Like I said, this is linkage mechanism, is expected to move, it freely moves
well "freely" there is some level of constraint of course
perhaps an example of how these applied forces can occur can help
let me show you a vid of the app I made, give me a sec
https://www.youtube.com/watch?v=9GzszKnLJTg
This is an old video of what I'm trying to illustrate, each link is rigid, but is connected with a rotating joint, I'm taking in consideration the mass because I want to determine its movement if I simply let it rest, as well if I apply a force to the input linkage
And here is my original simulator if you're interested, is the interactive version of what the video shows (and more)
https://vakogp.itch.io/simuladorbarras
so you only care about forces on the input linkage, not other parts
yeah
yeah it's quite close to a physics simulation, so we need a better model than "just rigid bars"
wdym?
we can't ignore the forces on each joint since we need to consider forces
yeah, it would need to propagate
Right now what I was doing was basically generating solid shapes based on n vertex, then generating a centroid from it and then having each point (including the centroid) have a list or an array of the acceleration and velocity
okay we can model each linkage as a mass at the center and write down the equations for torques and force to find their linear and angular velocity, and we need to model the 2d contact forces at each joint
plus the length conditions
but i'm not sure how to solve that entire system
maybe throw numerical methods at it
yeah.... this shit sucks
my initial idea was basically kind of a propagation method, basically give the input priority, each frame I'd update the input first, and then based on the calculations of the first link update each subsequent link, you know?
and then at the end, check if the output (last link) breaks, if so then simply return to the previous state
Anyway, this is good enough for me, thank you tho!
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I have several doubts regarding this problem.
red dot line: Why was y^y made 0? I mean, that would have been true if y wasn't a function of x. But it's given that x = y = z
yellow line: I don't know how they found out the f12
I mean, did they multiply it?
interesting question
they're definitely assuming x, y, z are all independent of each other
they're asking you to prove x=y=z so i can understand why you think it contradicts y is not a function of x
but y can be anything to start
i think they're going for z being a function of independent variables x and y
they were perhaps trying to. is this a good question btw, or is it just that I can't under this
well given that there is ambiguity in how to interpret the question, its probably not a great question
also, we are asked to prove partial diff of (z) with respect to y and then x is equal to something.
if z = x = y, it just would be freaking zero, wouldn't it be?
take x, partially differentiate wrt x
and then you get 1
now partially differentiate again with rt x
0?
why are you partially differentiating x wrt x
ok that makes sense.
infact, thats what they do in the solution you posted
we have to assume that z is a function of x and also y until we apply x = y = z
yeah its implied here that z = f(x,y)
but we are assuming z is a function of x and y only because we are asked to partially differentiate it with respect to x and y
yes.... you are right
a bad question nonetheless
agreed, but with nothing else to go on, this is what you should assume
its the "standard" ig
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are u dumb?
i was using that channel. i decided to stop learning because u were interfering with it
<@&268886789983436800> ?
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What are youre guys thoughts on this? I think the proof is flawless, however, the way the question is framed it seems like it shouldnt be. Any help would be appreciated
there is a problem with the proof
in fact the claim is wrong
(draw a venn diagram to check)
@radiant pecan
wtf]
im clearly an idiot
ill ahve another look at it that way
thank you
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Hi peeps! Just wondering if I've got the right idea for this question. Thanks XD
Closed due to the original message being deleted
Hi peeps! Just wondering if I've got the right idea for this question. Thanks XD
Kind of stuck on this question, not sure if I used a correct method
what about proviingusing contrapositive
your approach was good, but n^3 + 11 does not equal n?
if n is odd then n^3 + 11 is even
I will try that, ty bro
its much simpler imo
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well you can solve a linear system
or you can use part a to find two more points it passes through
@high palm Has your question been resolved?
put the values then solve the linear equation
like the coordinaties?
is a = -26 and b = 20
,w (2^3) -26(2^2) + 20
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Help pls
I'm stuck in here
Problem is find H(x)?
h(-2)
Trying to understand that notiation by H circle F circle g, do yuu mean H(f(g)) or H(x) x F(x) x G(x)
h(f(g))
H(x) = x^4 ?
H(sqrt(x+4)) = (x+4)^2
f(g) = (x+4)^(1/2)
h(x) = x^4
H(-2) = 16?
Ohh I see
solved?
Yea, thx btw 🙂
allg
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It is known that the function $$f(x)=\frac{x^2+ax+b}{x^2+2x+3}$$ for real number $x$ has a minimum value of $-5$ and maximum value of $4$. If $a$ and $b$ are integers, find all the possible values of $|a+b|$.
$nichoals$
How do I go through this problem?
there are different ways of going about this
you could rewrite the equation y=f(x) as a quadratic in x parameterized by y, then require that its discriminant be positive precisely for y between -5 and 4
i see
i'll try first
discriminant be positive precisely for y between -5 and 4
what do you mean by this?
i got D = -8y^2 + (12 + 4b - 4a)y + (a^2 - 4b)
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Omg
💀
That's true hahaha
DEB
What's SEB?
DEB*
angle
DBE= 180-(y+x) thats why DEB = x ,
A = Y
B = 180-Y-X
X = 180- (180-Y-X) - Y
You describe the angle by starting at D, going to E and ending at B
So that you avoid mistaking it with other angles
Like E can be the angle inside and can be the angle outside
isn't DBE and DEB the same thing?
nah
Nope
dbe is b angle
SO THE MIDDLE letter is the angle?
yes
and the ends of the formula is the sides?
Yeah
ye
ah ok i understand now makes much more sense
But the left and right letters are needed or else your angle description will stay incomplete
But then
so you wont mistaken it with other e angle
DEB and BED would be the same no?
but the middle is them same and the sdies
oh ok
sorry
I didn't read it
alright so how do I solve this what am I supposed to be thinking?
how do I get X?
or ACB
lemme try on paper
ok
if what I've written is true
does that mean that x = 180-y
meaning that C would be the correct answer
x= 90-Y/2
Hmm
DEC = 180-x in my opinion
so
And similarly ADE = 180 - y
yea
So then x = 180-y
i dont think thats true
Let's call angle B as B
sure
So 180 = B + x + y
yep
So that means B = 180 - (x+y)
oohh yeyeye
its D
u sure ?
1min
ok
so look
I'm looking
b=180-x-y
CED =180-x
ADE=180-y
now put random numbers that would work for example x=50
y=40
in that case DBE=90 and if you check answers 180-80=100 100/2=50
sure I follow so far
so i think its D idk
can I give my theory and can you correct it if it's wrong?
sure
is this correct?
is Dec = y
and is ADE = x
?
waity
consists of x+ y
i still believe my theory was correct 💀 idk how to solve but answer is D
just putting numbers
here's the thing I thought it was correct because ADEC create a rectangle so there fore it would end up 360deg and if x+y = 180 then it would be correct because
A = y
D=x
E=y
C=x
which equals 360
but DBE fucks that up
it would be correct if it was Parallelogram its trapezium
in Parallelogram diagonal angles are equal but not in trapezium
it does sum to 360 in total, but that's not enough information to determine the angles
x, y, 90, 90, also sums to 360
yea
but also yeah x+y is not 180
i think its D
so how do we get X = 180-Y or x = 90-y/2?
Why not?
just did basics and put numbers
so what's DBE
So this drawing is wrong?
180-x-y
yep
Ok then I'm back to square one fuuuuck
bro you sure answer is 100% C cuz i thinks its D
this is a national test
that has the correct answers next to it
the chances of it being wrong is very low
but never 0 I guess
oh
ok wait hang on
there isn't enough information
what exactly does the question say?
.
it says more than that
I forgot to say
define x with y
?
ABC Is a triangle
DE is paraell with AC
DE=BD
That is the info
lmao sorry about this I made a huge mmistake
💀
oh
so DBE is isosceles
yea
What's isosceles ?
2 side equal triangle
same
i FOUND
so B = X?
???
Wait does that mean that B = x?
which is this?
DBE triangle
I think I understand
DEC is not x
but DEB is
yea sorry DEB lol
@lament forge can you confirm that ?
to be sure
ye so finally lmao we got it LET'S GO BOISSSSSSSSSSSSSS
yep that looks right
you guys are sick thank you so much for helping me out this took too long because I did not give enough info so sorry about that again thx guys good luck on helping the rest of the channels that are open
<3
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How is the integral symbol used? (∫)
do you mean how to write it in latex?
No, I've never learned what it does.
Hm?
if you really want to learn integration, I would suggest watching 3Blue1Brown's series on the essence of calculus
it will give you a sense of calculus beyond what school curriculum's will
What might it feel like to invent calculus?
Help fund future projects: https://www.patreon.com/3blue1brown
An equally valuable form of support is to simply share some of the videos.
Special thanks to these supporters: http://3b1b.co/lessons/essence-of-calculus#thanks
In this first video of the series, we see how unraveling the nuances of a simp...
All right. Thanks.
have you learnt of the summation symbol
$\Sigma$
doctor99268
I know a little about it.
the integration symbol
is basically
its brother
@craggy nebula do you know what discrete vs continous are
Like capital pi is? (∏)
i get what you are thinking, but in a different way
I've stumbled across it when developing games, but never really understood what they mean, so no.
Yeah.
this would be continuos
Oh, so interpolation?
you use interpolation for discrete values
because you dont have information
on whats between
while continous
you have the information for everything
Linear interpolation?
linear interpolation is one form of interpolation


