#help-0

1 messages · Page 173 of 1

vapid shuttle
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Me and you are standing on the sidewalk. You start walking north at 5 mph, and I stay in the same spot. Question 1. How fast are you moving away from me?

daring ferry
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5

vapid shuttle
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ok

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if I start, moving away aswell, if I start walking south, will we be moving apart faster or slower?

daring ferry
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faster

vapid shuttle
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okay

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So me and you are on the sidewalk. You start walking north at 5mph, and I walk south at 1mph. This will make us move away faster than before (which was 5mph). So how fast are we going apart now?

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hint: the only difference is that I started moving away, this adds to the speed we are moving apart

daring ferry
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7? im not sure this is my understanding

vapid shuttle
#

could you tell me why you think 7?

daring ferry
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i dont know too but i think its 4 or 3

vapid shuttle
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so, is your guess going to be 7, or 4, or 3

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pick one and tell me why

daring ferry
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4

vapid shuttle
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stop for a second

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you said earlier, we would be going faster

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right

daring ferry
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ohno ok

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Yes

vapid shuttle
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4mph is not faster than 5mph

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so it wouldn't be 4 then

daring ferry
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so its higher than 5

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OK

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fine i pick 7

vapid shuttle
#

atleast that's faster this time! but 7 is not correct, and the reason is because you just randomly chose 7,

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the answer here is not random

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try to look back at the question 1 more time

daring ferry
#

Okay

vapid shuttle
#

also read the hint I provided aswell

daring ferry
#

we move 10 mph away from eachother

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this is my last answer

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if this iswrong

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please explain it to me

vapid shuttle
#

well, it is wrong because you randomly guessed again

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the reasoning is

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if you go 5mph away

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and I go 1mph away

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the speed we are traveling apart

daring ferry
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6

vapid shuttle
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adds

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yes!

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so in total we are going apart 6mph

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because instead of it only being the speed you go away, I add to the speed by going away aswell

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Two passenger trains left the station at the same time and traveled in opposite directions. One traveled at the rate of 50 km/h and the other at 45 km/h. After few many hours are the trains 315 km apart?

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so for this,

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one train is traveling 50km/h away

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and the other is traveling 45km/h away in the opposite direction

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so the total speed they are traveling apart from eachother is?

daring ferry
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95 km

vapid shuttle
#

good!

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okay so now we know

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the trains travel apart 95 km , every hour

daring ferry
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thank you

vapid shuttle
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how long until they are 315 km apart?

daring ferry
daring ferry
vapid shuttle
#

yeah, what do you think we should divide

daring ferry
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315 and 95

vapid shuttle
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yes XD

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but divide which by what

daring ferry
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what which by what ?

ocean sealBOT
#

AustinU

daring ferry
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95/315

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wait im gonna solve

vapid shuttle
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no

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if they go apart at 95 km every hour

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then in 2 hours they are apart 190km

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in 3 hours they are apart 285 km

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and so on

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so the answer will clearly be above 3

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95/315 is not above 3

daring ferry
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yes

vapid shuttle
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315/95 is the proper next step

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it answers: how many times do we have to go 95 km to get to 315 km

daring ferry
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3

vapid shuttle
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not exactly 3

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but around that

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the answer is exactly 315/95....

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good luck with the rest of this, goodnight!

daring ferry
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WDYM angerysad

vapid shuttle
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if you can't recognize that 315/95 is just a number about the size of 3, I'm not sure how I can help

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the trains move apart 95 km every hour

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how many hours will it take for them to move apart 315 km?

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that is answered by 315/95

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so the answer is

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315/95 hours

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that is how long it will take

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however many times 95 goes into 315

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if it asked, how long will it take for them to go 95 km apart

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you would see that it is 1 hour

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because they go 95 km apart every hour

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if it was 190 km

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then it would be 2 hours

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because 190/95 = 2

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so for 315 km

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the answer is 315/95 hours

daring ferry
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thanks austin

vapid shuttle
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np

daring ferry
#

i understand now

vapid shuttle
#

great!

daring ferry
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this gave me a little headache ☠️ but yes tbh ur great at teaching

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can i not close this

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for future purposes

vapid shuttle
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well thank you! You can take screenshots and leave it open for now, but sadly it will close eventually on its own

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but feel free to take pictures or something to save it if you need

daring ferry
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thanks

lone heartBOT
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@daring ferry Has your question been resolved?

lone heartBOT
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alpine sable
#

I'm trying to understand the integration of these $$\int^{\frac{2\pi}{\omega}}{0} e^{2i\omega t}\omega L dt = \frac{e^{4i\pi}-1}{2i}L$$ $$\int^{\frac{2\pi}{\omega}}{0} e^{2i\omega t} (\omega C)^{-1} dt = ?$$

ocean sealBOT
whole shell
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whats wrong

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@alpine sable

alpine sable
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I don't understand how the first integration has ended with that result.

whole shell
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also is that for fourier transform just curious

alpine sable
#

hmm ah no. it's electric engineering

whole shell
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well since we are integrating everything with respect to t, you are integrating be^(ax) normally

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theres nothing special going on

alpine sable
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ah so

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I thought like the omega in the interval 2pi/omega affects anything in the integrating process

whole shell
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no

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you just sub it in

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its just a normal number to sub in

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since we are integrating with respect to t

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anything that isnt t

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means nothing

alpine sable
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I see

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thank you

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how about integrating b^-1 e^(ax)?

whole shell
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b^-1 is just a constant

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so nothing changes

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besides, its well b^-1

alpine sable
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its well b^-1?

whole shell
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as in

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instead of the integral being

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a^-1 be^(ax)

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itll be

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a^-1 b^-1 e^(ax)

alpine sable
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ah I see

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one last question

alpine sable
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$\omega L e^{2i\omega t}$

ocean sealBOT
whole shell
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it doesnt really matter

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you can make

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omega L = b

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and 2iomega = a

alpine sable
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ah I see. thank you

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I didn't integrate Euler's form before

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.close

lone heartBOT
#
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fresh perch
#

need a lil help with this integral

lone heartBOT
fresh perch
#

so that is equal to $\int \frac{1}{(x-3)^2 + 4}$

ocean sealBOT
fresh perch
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which is equal to $\int \frac{1}{4((\frac{x-3}{2})^2 + 1)}$

ocean sealBOT
fresh perch
#

which is equal to $\int \frac{1}{4} \times \frac{1}{(\frac{x-3}{2})^2 + 1}$

ocean sealBOT
fresh perch
#

so why isn't this equal to $\frac{1}{4} \int \frac{1}{(\frac{x-3}{2})^2 + 1}$

#

?

ocean sealBOT
fresh perch
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oh no nvm

#

all of this is right

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my mistake was later lol

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.close

lone heartBOT
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limber crow
lone heartBOT
limber crow
#

How do I convert this to Cartesian?

vale wigeon
lone heartBOT
#

@limber crow Has your question been resolved?

limber crow
#

<@&286206848099549185>

alpine sable
lone heartBOT
#

@limber crow Has your question been resolved?

carmine crow
#

could someone help me with question 8c and 8d? please

lone heartBOT
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craggy token
lone heartBOT
craggy token
#

I let f(x) = ax^2 + bx + c. From f(2) + f(3) = f(5), I got:
4a + 2b + c + 9a + 3b + c = 25a + 5b + c
13a + 2c = 25a + c
c = 12a

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Then, from f(2)f(3) = f(6), i substituted c = 12a to get
(4a + 2b + 12a)(9a + 3b + 12a) = 36a + 6b +12a
(16a + 2b)(21a + 3b) = 48a + 6b
2(8a + b)3(7a + b) = 6(8a + b)
7a + b = 1 ... (1)

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From f(1) = 1, i got a + b + c = 13a + b = 1 ... (2)
so, subtracting (1) from (2), i got 6a = 0 <=> a = 0, which means c = 0

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however, f is a second-degree polynomial, which means a can't be 0

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in which part did i do it wrongly?

gray isle
#

q = 1 isn't the only solution to
pq = p

craggy token
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what's the other solution?

gray isle
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have a think about it

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rearranging the equation to general form
and factorisation would be helpful

craggy token
#

oh right

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there's p = 0

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alright thanks

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.close

lone heartBOT
#
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fickle oyster
lone heartBOT
fickle oyster
#

is what im doing correct?

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i forgot to add lim_h->0

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|0| = 0

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which exists

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then the function is differentiable at 0?

fickle oyster
pseudo ice
#

You should have |h|/h

fickle oyster
pseudo ice
#

Actually no no I’m blind

fickle oyster
#

not just |x|

pseudo ice
#

Never mind me thonkHang

fickle oyster
pseudo ice
#

Yea you’re fine then!

fickle oyster
#

.cclose

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.close

lone heartBOT
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shut musk
lone heartBOT
shut musk
#

can someone explain why the integration of ln(1-x) turns into a negative?

vale wigeon
#

do you mean to ask why it is subtracted and not added

shut musk
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No i mean why is the integration of ln(1-x) = -1/1-x and not +1/1-x

whole shell
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chain rule

last ether
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the primitive of ln(1+x) is not 1/(1+x) as far as I'm concerned

whole shell
#

also, since when is the integral of ln(1+x) 1/(1+x), isnt it (1+x)(ln(x+1) -1)

last ether
#

,w Integrate ln(1+x)

alpine sable
#

I can understand why $\int\left(\frac{1}{1+x}+\frac{1}{1-x}\right)\mathrm{d}x = \ln\frac{1+x}{1-x} + C$ but why the other way around?

ocean sealBOT
#

Landau08

last ether
#

Yeah the model solution's just wrong

whole shell
last ether
#

Someone whose keyboard is being a bitch

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Antiderivative

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There happy

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I had to dodge autocorrect

whole shell
#

what is integral correcting as

last ether
#

,w simplify integrate ln((1+x)/(1-x))

ocean sealBOT
last ether
#

Yeah the answer key is just wrong

alpine sable
lone heartBOT
#

@shut musk Has your question been resolved?

lone heartBOT
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amber niche
#

find the parametric equation of the intersection of these two cylinders :
x^2 + y^2 = 25
y^2 + z^2 = 20

amber niche
#

if it was something like z + y = 20, then I would simply do
x = 5cos(t)
y = 5sin(t)
z = 20 - 5sin(t)

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but since they are squared I do not know what to do

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and if I take the root for z, I end up with a +-, which I don't want

whole shell
#

hmm

lone heartBOT
#

@amber niche Has your question been resolved?

amber niche
#

@crisp iron

lone heartBOT
#

@amber niche Has your question been resolved?

amber niche
#

okay, so after looking carefully, it seems that there is no choice but to split it into the positive root and the negative root

#

i'm not sure but it looks that way...

lone heartBOT
#

@amber niche Has your question been resolved?

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solar glade
#

if f(x+2) = x^4-4x^3+3x^2+x-6. find f(1), then find 2f(3)+4. im confused on how to do it

quasi vector
#

notice f(1) = f(-1+2)

solar glade
#

yea

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oh wait

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could i just

quasi vector
#

you have an expression for f(x+2)

solar glade
#

substitute x for -1

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?

quasi vector
#

yes

solar glade
#

ohhhhhh

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ok

#

ty

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could u also help me on another question

quasi vector
#

sure

solar glade
#

if the middle term of (2b^2n-4+6b^3-n)^6 has no variable. what is the value of n

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actually like 2 more questions i need help on after this lol

quasi vector
solar glade
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uh

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idk either

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thats what the question gives

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wait

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how about

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this other question

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what is the cofeeiient of the x^2 term in the expansion of (ax+2/a)^5?

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@quasi vector

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/close

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.close

lone heartBOT
#
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gusty iron
#

hey ima kinda lost

lone heartBOT
gusty iron
#

so i to find the derivative of f(0) in the equation 2^3x

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how do u derive 2^3x

tacit arch
#

differentiate is the verb form of derivative

tacit arch
ocean sealBOT
#

riemann

gusty iron
#

first

tacit arch
#

either chain rule or use exponent laws

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,tex .exp rules

gusty iron
#

do i use

ocean sealBOT
#

riemann

gusty iron
#

AB prime + BA prime

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oh i see

vapid shuttle
#

no, that is for taking the derivative of a product

gusty iron
#

ohh

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which one do i use above

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im confused

ocean sealBOT
#

AustinU

vapid shuttle
#

first use some of the rules to simplify it

gusty iron
#

oh

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is the one i use above power of power?

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a^xy looks closest to what i have

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ya?

vapid shuttle
#

use the reverse of the product rule

gusty iron
#

oh ok

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(2^3) (2^x)

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ya?

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so from here

vapid shuttle
#

and 2^3 is?

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and then once it is simplified you will use these derivative facts: derivative of $C * f(x)=C * f'(x)$ and derivative of $a^{x}=ln(a) * a^x$

ocean sealBOT
#

AustinU

vapid shuttle
#

where C is a constant

worn fox
gusty iron
#

im lost

gusty iron
worn fox
gusty iron
#

reverse product rule

ocean sealBOT
#

AustinU

gusty iron
#

ohh i see

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should i use power of power reverse

vapid shuttle
#

yes

gusty iron
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so (a^3)^x

vapid shuttle
#

and a being?

gusty iron
#

x my bad

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(x^3)^x

vapid shuttle
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hmmm

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idk about that

gusty iron
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uhh

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oh noo

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(2^3)^x

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brain glitch

vapid shuttle
#

yes

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there we go

gusty iron
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so from here

vapid shuttle
#

and then the 2^3 is?

gusty iron
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8 and then its 8^0 ya?

vapid shuttle
#

8^x

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yes

gusty iron
#

that is 1 ya

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woo

vapid shuttle
#

?

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slow down

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you had (2^3)^x

gusty iron
#

yeah

vapid shuttle
#

that is 8^x

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not 8^0

gusty iron
#

yes

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oh

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but its f(0) so dont we plug in 0 at the end

vapid shuttle
#

you haven't find the derivative yet

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you just simplified 2^(3x)

gusty iron
#

oh

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wait

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uhh

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ok

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so we have 8^x

vapid shuttle
gusty iron
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8 * 8^x

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?

vapid shuttle
#

not quite

gusty iron
#

hm

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oh wait

ocean sealBOT
#

AustinU

gusty iron
#

oh mb

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ln(8) * 8^x

vapid shuttle
#

yes

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so that is the derivative

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and then you can evaluate at x=0

gusty iron
#

so thats ln(8) * 8^0

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ln(8) * 1

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ln(8)

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i think we went wrong somehwere

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if that is the final answer

vapid shuttle
#

can you send the original question

gusty iron
#

Let f(x) = 2^3x. Find fprime(0)

vapid shuttle
#

seems to me like ln(8) works out

gusty iron
#

on the practice sheet thats not an answer tho they give u 5 possibilities

vapid shuttle
#

what are the possibilities?

gusty iron
#

3, 3ln(2), 1, ln(2), 0

ocean sealBOT
#

AustinU

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AustinU

vapid shuttle
#

does that help you see the correct answer?

gusty iron
#

not really

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im not sure why the answer key isnt on this

ocean sealBOT
#

AustinU

gusty iron
#

oh

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ohhhhhhhh we did it right

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i didnt know ln(8) could be 3ln(2) my bad

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thank you austin

vapid shuttle
#

no problem

gusty iron
#

.close

lone heartBOT
#
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dim matrix
#

Is this correct?

lone heartBOT
dim matrix
#

Can x be 1?

tacit arch
dim matrix
#

1?

tacit arch
hard inlet
#

Try plugging it into the original function. You should notice a problem

tacit arch
#

what happens when you plug x=1 here

dim matrix
#

0

tacit arch
#

,calc 1/sqrt(1-1)

ocean sealBOT
#

Result:

Infinity
tacit arch
#

,wolf 1/sqrt(1-1)

tacit arch
dim matrix
#

yeah

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then x can't be 1

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I was solving this and the answer given is x=0 and 1

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I got 0

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But not sure how can I get x =1

tacit arch
gray isle
#

what's the original question asking for

dim matrix
#

the second one

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I am trying to get critical points

gray isle
#

locations where the derivative is undefined but the original function is, are critical locations

dim matrix
lone heartBOT
#

@dim matrix Has your question been resolved?

lone heartBOT
#

@dim matrix Has your question been resolved?

merry spire
#

@dim matrix do u still need help

dim matrix
#

The solution is stating that though 1 and 0 are critical points, we can't consider 1.

merry spire
#

yeah we actually just did this unit and it tripped me up too, what is the difference between 0 and 1 in this case

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like how did you get 0 vs 1

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key word is point, not number

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there's a spider on my computer one minute lmao

dim matrix
merry spire
#

yes your critical numbers are 0 and 1

#

the 0 makes your derivative = 0 and the 1 makes your derivative = undefined

dim matrix
#

yeah

merry spire
#

so they both are critical numbers you are right

#

was that your question?

dim matrix
#

The solution is stating that 1 can't be considered.

merry spire
#

what did you do next

dim matrix
#

I need to understand why I can't consider 1 here, for which reason.

merry spire
#

the question wants you to do the 2nd derivative test

#

so get the 2nd derivative 🙂

#

I rushed but I got 1/2(1-x)^3/2

#

so just please tell me you got the same thing lmao

dim matrix
#

I didn't solve it

#

as I was not clear about critical points

merry spire
#

just do it you will see why

dim matrix
#

with 1 ?

merry spire
#

nono just

#

solve for the 2nd derivative

#

keep the x's in there

dim matrix
#

okay

merry spire
#

lmk when you have it done

dim matrix
merry spire
#

I think it's positive

#

nope you are right

dim matrix
#

Can't figure

merry spire
#

I rushed and this is on old scrap paper that I have already used as scrap paper

#

you're right lmao

#

rewrite it so it's -1/ everything though

#

just to make this extra clear

#

that it is in a denominator

dim matrix
#

check with wolfram

merry spire
#

I checked on desmos

#

the graphs lined up

#

ur right

dim matrix
#

okay

merry spire
dim matrix
#

So here, now if I use x=1, it will be 0

merry spire
#

wait what will be 0

#

the derivative or the denominator

dim matrix
#

2nd derivative

merry spire
#

nope

#

what is 1/0

dim matrix
#

But we need to substitute critical points into the 2nd derivative.

merry spire
#

yes we do

#

I'm trying to show you why the 1 doesn't work

#

plug the 1 in, you get -1/(0)

#

which equals what

dim matrix
#

yeah

#

inf

merry spire
#

idk abt infinity this was where I was going

dim matrix
#

yeah, same thing.

merry spire
#

that implies that there is no second derivative at that point right?

dim matrix
#

yeah, or at least we can't get the answer with the second derivative.

merry spire
#

wasn't that what you were asking?

dim matrix
#

the point is, how without going through the second derivative they abandon 1

merry spire
#

abandon?

dim matrix
#

I mean they didn't consider

merry spire
#

who is they

dim matrix
#

the explanation

merry spire
#

could you send a screenshot of the explanation

dim matrix
#

yeah sure

merry spire
#

I think all you need to see is that because the 2nd derivative doesn't exist it cannot be applied at that point

#

doesn't exist at x=1 (and the original function and 1st derivative too lol)

dim matrix
merry spire
#

OH

#

ok sorry, they abandoned it when they saw that 1 is outside of the domain of f'(x)

#

that's their way of saying how they know the 2nd derivative at that point doesn't exist

dim matrix
#

what does 'outside of the domain' mean?

alpine sable
#

helloooooooooooo

merry spire
#

um

#

an x value "outside of the domain" is an x value in an area where the function doesn't exist

#

I'll send a picture

alpine sable
#

what is 2+2??

merry spire
dim matrix
merry spire
#

so any x value that is less than 0 is "outside of the domain" of the function

#

because as you can see from the graph there is no line when x is less than 0

dim matrix
#

It's actually hard to figure 2+2

alpine sable
#

GUYS WHAT IS 2+2??

merry spire
#

sirius u good now

dim matrix
#

Is it bcz they mentioned in the problem?

merry spire
#

these are both ways of showing how the test does not apply at that point because there is no 2nd derivative at that point

#

watch a video on the domain of functions if you really want to understand the explanation, but as long as you can tell that there is no second derivative there I think you are good

dim matrix
merry spire
#

I feel like I didn't actually do anything lmao good luck!!

dim matrix
#

Thanks again!

#

.close

lone heartBOT
#
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frozen charm
#

need help with c i

lone heartBOT
#

Please don't occupy multiple help channels.

elder wyvern
#

Yh Yh Ik Unrelated but, Can Anyone Decode this Binary? 00010111 11010001 11000110 00100110 00100011 00100010 00001111 01001011, Pls Just idk into what maybe Pls Ya Can try everything and then see what makes the Most Sense or smthn pls, Pls Help me out here nameitpls

lone heartBOT
#

@frozen charm Has your question been resolved?

tacit arch
elder wyvern
#

.question

#

/question

tacit arch
lone heartBOT
elder wyvern
#

!help

lone heartBOT
elder wyvern
#

Yh thx

lone heartBOT
#

@frozen charm Has your question been resolved?

tacit arch
frozen charm
#

yes

tacit arch
frozen charm
#

y tho theyre two different questions

tacit arch
pseudo ice
#

[and ideally don't blank replies either sadcat]

frozen charm
#

wdym

#

@pseudo ice

pseudo ice
frozen charm
#

oh sorry i didnt see your msg but was able to do it thanks tho

pseudo ice
frozen charm
#

@pseudo ice any tips for c i ?

lone heartBOT
#

@frozen charm Has your question been resolved?

frozen charm
#

Never

lone heartBOT
#

@frozen charm Has your question been resolved?

frozen charm
#

.close

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waxen dove
#

So, I kinda need a lil help, at least some guidance I guess, I'm trying to generate equations for motion in what is basically a linkage mechanism of N links, in any configuration (but I'm trying to do it in a continuous configuration first), however I'm kind of lost
This of course using differential equations and such
Any help or guidance would be appreciated

woeful pulsar
#

seems quite vague at the moment

#

maybe share what the aim is to find?

waxen dove
# woeful pulsar maybe share what the aim is to find?

Some extra context, I made this software that simulates a 4 bar linkage mechanism, however I just derivate the positions, velocity and acceleration vectors using trigonometry, I'm trying to simulate this, and any other mechanism of greater number of linkages (in any configuration)

#

I was reading a paper regarding pendulums that kind of help me but... a series of n segment pendulums is not that similar to what I'm looking for

woeful pulsar
#

hmm, okay so the assumptions are typically that that the input is not overdetermined and everything is rigid

waxen dove
#

Is a mechanism, so it moves, but each linkage is rigid, yes

woeful pulsar
#

also, velocity and acceleration can probably be first ignored

#

so focusing rigidness + position is probably the way to go

waxen dove
#

yeah, my initial attempt with a n linkage mechanism was using unity physics system but... it simply freaked out and it didn't really work, so I'm trying to code myself the physics simulation

woeful pulsar
#

hmm I don't think a full physics simulation is required

waxen dove
#

I mean, I won't code any kind of collision, is not necessary for what I'm looking for

woeful pulsar
#

though there must be an assumption that the positions pretty much define finitely many configurations

waxen dove
#

I only really care about position, velocity and acceleration, and technically I can derive velocity and acceleration out of the position

waxen dove
woeful pulsar
#

yeah drawing would help

#

formalise all the parameters you have and what you want to calculate

#

because to do it in generality would be hard but doing small examples is not too hard

waxen dove
#

This is a simple 4 bar mechanism linkage, all I'm given at the start is the positions A and B (and by extension the vector AB), the lengths, r1, r2, r3, and the masses of r1,r2,r3
Being that is a mechanism the rotational movement on r1 with respect to A will move r2 and subsequently will move r3
Assuming only those parameters I'm trying to find

  1. a general movement equation for the joint points
  2. the same as 1, but given a rotational force in r1
#

This is the simplest setup, my goal is to extend it up to r_n and in different configurations

woeful pulsar
#

of course the next question is because r2, r3 don't have a uniquely determined solution (there's two configurations), so one would probably need to estimate the velocity of each of the nodes to figure out which configuration is more appropriate

waxen dove
#

idk if I'm being clear on that, sorry

woeful pulsar
#

I think you are looking at a different problem than just finding the configuration, we need to refine that

#

mass generally isn't too much of an issue, unless you are doing something which involves checking the strain at each joint

waxen dove
#

Like I said, this is linkage mechanism, is expected to move, it freely moves

#

well "freely" there is some level of constraint of course

woeful pulsar
#

perhaps an example of how these applied forces can occur can help

waxen dove
#

let me show you a vid of the app I made, give me a sec

waxen dove
woeful pulsar
#

so you only care about forces on the input linkage, not other parts

waxen dove
#

yeah

woeful pulsar
#

yeah it's quite close to a physics simulation, so we need a better model than "just rigid bars"

waxen dove
#

wdym?

woeful pulsar
#

we can't ignore the forces on each joint since we need to consider forces

waxen dove
#

yeah, it would need to propagate

#

Right now what I was doing was basically generating solid shapes based on n vertex, then generating a centroid from it and then having each point (including the centroid) have a list or an array of the acceleration and velocity

woeful pulsar
#

okay we can model each linkage as a mass at the center and write down the equations for torques and force to find their linear and angular velocity, and we need to model the 2d contact forces at each joint

plus the length conditions

but i'm not sure how to solve that entire system

#

maybe throw numerical methods at it

waxen dove
#

yeah.... this shit sucks
my initial idea was basically kind of a propagation method, basically give the input priority, each frame I'd update the input first, and then based on the calculations of the first link update each subsequent link, you know?

#

and then at the end, check if the output (last link) breaks, if so then simply return to the previous state

#

Anyway, this is good enough for me, thank you tho!

#

.close

lone heartBOT
#
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halcyon monolith
lone heartBOT
halcyon monolith
#

red dot line: Why was y^y made 0? I mean, that would have been true if y wasn't a function of x. But it's given that x = y = z

#

yellow line: I don't know how they found out the f12

I mean, did they multiply it?

tacit arch
#

they're definitely assuming x, y, z are all independent of each other

#

they're asking you to prove x=y=z so i can understand why you think it contradicts y is not a function of x

#

but y can be anything to start

worn fox
#

i think they're going for z being a function of independent variables x and y

halcyon monolith
worn fox
#

well given that there is ambiguity in how to interpret the question, its probably not a great question

halcyon monolith
#

also, we are asked to prove partial diff of (z) with respect to y and then x is equal to something.

if z = x = y, it just would be freaking zero, wouldn't it be?

worn fox
#

why would it be zero

#

you calculate the partial diff and then you sub in x=y=z

halcyon monolith
#

take x, partially differentiate wrt x

and then you get 1

now partially differentiate again with rt x

#

0?

worn fox
#

why are you partially differentiating x wrt x

halcyon monolith
worn fox
#

infact, thats what they do in the solution you posted

halcyon monolith
#

we have to assume that z is a function of x and also y until we apply x = y = z

worn fox
#

yeah its implied here that z = f(x,y)

halcyon monolith
#

but we are assuming z is a function of x and y only because we are asked to partially differentiate it with respect to x and y

#

yes.... you are right

#

a bad question nonetheless

worn fox
#

its the "standard" ig

halcyon monolith
#

thank you1

#

.closed

#

.close

lone heartBOT
#
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vestal imp
#

are u dumb?

#

i was using that channel. i decided to stop learning because u were interfering with it

serene junco
#

<@&268886789983436800> ?

sly mantle
#

.close

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radiant pecan
#

What are youre guys thoughts on this? I think the proof is flawless, however, the way the question is framed it seems like it shouldnt be. Any help would be appreciated

woeful pulsar
#

there is a problem with the proof

#

in fact the claim is wrong

#

(draw a venn diagram to check)

#

@radiant pecan

radiant pecan
#

wtf]

#

im clearly an idiot

#

ill ahve another look at it that way

#

thank you

#

.close

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vestal imp
#

Hi peeps! Just wondering if I've got the right idea for this question. Thanks XD

lone heartBOT
#
Channel closed

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vestal imp
#

Hi peeps! Just wondering if I've got the right idea for this question. Thanks XD

#

Kind of stuck on this question, not sure if I used a correct method

gilded vessel
#

what about proviingusing contrapositive

gleaming granite
#

your approach was good, but n^3 + 11 does not equal n?

gilded vessel
#

if n is odd then n^3 + 11 is even

vestal imp
gilded vessel
#

its much simpler imo

lone heartBOT
#
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high palm
lone heartBOT
high palm
#

Having trouble with 14. B)

#

I don't know what to do

#

I've done 14 a) and it's 2w^3

woeful pulsar
#

well you can solve a linear system

#

or you can use part a to find two more points it passes through

lone heartBOT
#

@high palm Has your question been resolved?

high palm
#

<@&286206848099549185>

viral solstice
#

put the values then solve the linear equation

high palm
alpine sable
#

(1,3)

#

3 = (1^3) + a(1)^2 + b

#

4 = (2)^3 +a(2)^2 + b

high palm
#

is a = -26 and b = 20

alpine sable
#

Did you solve?

#

You plug in and see

#

if it's equivalent

#

,w 1 - 26 + 20

ocean sealBOT
alpine sable
#

,w (2^3) -26(2^2) + 20

ocean sealBOT
high palm
#

bruh

#

how about a = -2, b = 4

#

@alpine sable

alpine sable
#

?

#

Let's see

#

,w 1 - 2 + 4

ocean sealBOT
alpine sable
#

@high palm Oo nice

#

,w (2^3) -2(2^2) + 4

ocean sealBOT
alpine sable
#

That works

#

how did you solve it?

#

system of equations?

high palm
#

ty

#

no i used

#

elimination method

lone heartBOT
#

@high palm Has your question been resolved?

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clear vault
#

Help pls

lone heartBOT
clear vault
clear vault
exotic river
#

Problem is find H(x)?

clear vault
#

h(-2)

exotic river
#

Trying to understand that notiation by H circle F circle g, do yuu mean H(f(g)) or H(x) x F(x) x G(x)

clear vault
#

h(f(g))

exotic river
#

H(x) = x^4 ?

#

H(sqrt(x+4)) = (x+4)^2

#

f(g) = (x+4)^(1/2)

#

h(x) = x^4

#

H(-2) = 16?

clear vault
#

Ohh I see

exotic river
#

solved?

clear vault
#

Yea, thx btw 🙂

exotic river
#

allg

lone heartBOT
#

@clear vault Has your question been resolved?

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craggy token
#

It is known that the function $$f(x)=\frac{x^2+ax+b}{x^2+2x+3}$$ for real number $x$ has a minimum value of $-5$ and maximum value of $4$. If $a$ and $b$ are integers, find all the possible values of $|a+b|$.

ocean sealBOT
#

$nichoals$

craggy token
#

How do I go through this problem?

vale wigeon
#

there are different ways of going about this

#

you could rewrite the equation y=f(x) as a quadratic in x parameterized by y, then require that its discriminant be positive precisely for y between -5 and 4

craggy token
#

i see

#

i'll try first

#

discriminant be positive precisely for y between -5 and 4
what do you mean by this?

#

i got D = -8y^2 + (12 + 4b - 4a)y + (a^2 - 4b)

lone heartBOT
#

@craggy token Has your question been resolved?

lone heartBOT
#

@craggy token Has your question been resolved?

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gray oxide
lone heartBOT
gray oxide
#

What is X equal to?

#

This is what I've gotten so far

#

A = Y
E= 180-Y

severe ruin
#

E is also x

#

i think

gray oxide
#

Omg

severe ruin
#

💀

gray oxide
#

That's true hahaha

rocky grove
#

DEB

gray oxide
#

What's SEB?

gray oxide
severe ruin
#

angle

gray oxide
#

right

#

so DEB = 180deg

#

D=Y
E =X

#

B = 180-y-x

#

right?

#

then

rocky grove
#

DEB is an angle

#

One full angle

#

So like

severe ruin
#

DBE= 180-(y+x) thats why DEB = x ,

gray oxide
#

A = Y
B = 180-Y-X
X = 180- (180-Y-X) - Y

rocky grove
#

You describe the angle by starting at D, going to E and ending at B

#

So that you avoid mistaking it with other angles

#

Like E can be the angle inside and can be the angle outside

gray oxide
#

isn't DBE and DEB the same thing?

severe ruin
#

nah

rocky grove
#

Nope

severe ruin
#

dbe is b angle

gray oxide
#

SO THE MIDDLE letter is the angle?

severe ruin
#

yes

gray oxide
#

and the ends of the formula is the sides?

rocky grove
#

Yeah

severe ruin
#

ye

gray oxide
#

ah ok i understand now makes much more sense

rocky grove
#

But the left and right letters are needed or else your angle description will stay incomplete

gray oxide
#

But then

severe ruin
#

so you wont mistaken it with other e angle

gray oxide
#

DEB and BED would be the same no?

severe ruin
#

no

#

yea

#

they are

gray oxide
#

but the middle is them same and the sdies

severe ruin
#

yes yes

#

sorry

gray oxide
#

oh ok

#

sorry

#

I didn't read it

#

alright so how do I solve this what am I supposed to be thinking?

#

how do I get X?

#

or ACB

severe ruin
#

lemme try on paper

gray oxide
#

ok

#

if what I've written is true

#

does that mean that x = 180-y

#

meaning that C would be the correct answer

#

x= 90-Y/2

rocky grove
#

Hmm

severe ruin
#

DEC = 180-x in my opinion

rocky grove
#

It's true

#

DEC = 180 - x

severe ruin
#

so

rocky grove
#

And similarly ADE = 180 - y

severe ruin
#

yea

gray oxide
#

So then x = 180-y

severe ruin
#

i dont think thats true

gray oxide
#

hmmm

#

so how do we get X?

rocky grove
#

Let's call angle B as B

gray oxide
#

sure

rocky grove
#

So 180 = B + x + y

gray oxide
#

yep

rocky grove
#

So that means B = 180 - (x+y)

gray oxide
#

oohh yeyeye

severe ruin
#

its D

gray oxide
#

the correct answer is C

#

x = 180 - y

severe ruin
#

u sure ?

gray oxide
#

ye I have the cheat sheet

#

but idk how to get there

#

that's the problem

severe ruin
#

1min

gray oxide
#

ok

severe ruin
#

so look

gray oxide
#

I'm looking

severe ruin
#

b=180-x-y
CED =180-x
ADE=180-y
now put random numbers that would work for example x=50
y=40
in that case DBE=90 and if you check answers 180-80=100 100/2=50

gray oxide
#

sure I follow so far

severe ruin
#

so i think its D idk

gray oxide
#

can I give my theory and can you correct it if it's wrong?

severe ruin
#

sure

gray oxide
#

is this correct?

is Dec = y
and is ADE = x
?

severe ruin
#

why do you think 180-x=y?

#

oh\

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i understand

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now

gray oxide
#

something about a rule of parrelel lines I think

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but I'm not sure

severe ruin
#

yes yes wait

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180-x=y so x+y=180

gray oxide
#

yes

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so the D angle

severe ruin
#

waity

gray oxide
#

consists of x+ y

severe ruin
#

that would be correct if there was not triangle

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if x+y=180

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DBE should be 0

gray oxide
#

oh true

#

B would be 0

#

shiiiit

severe ruin
#

+thats not Parallelogram

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thats trapezium i guess

gray oxide
#

no idea what that is :/

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but either way wtf then how does one solve this ????

severe ruin
#

i still believe my theory was correct 💀 idk how to solve but answer is D

#

just putting numbers

gray oxide
#

here's the thing I thought it was correct because ADEC create a rectangle so there fore it would end up 360deg and if x+y = 180 then it would be correct because

A = y
D=x
E=y
C=x
which equals 360

#

but DBE fucks that up

severe ruin
#

it would be correct if it was Parallelogram its trapezium

gray oxide
#

what's the difference?

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isn't it 360deg

severe ruin
#

in Parallelogram diagonal angles are equal but not in trapezium

lament forge
#

it does sum to 360 in total, but that's not enough information to determine the angles

#

x, y, 90, 90, also sums to 360

severe ruin
#

yea

lament forge
#

but also yeah x+y is not 180

severe ruin
#

i think its D

gray oxide
#

so how do we get X = 180-Y or x = 90-y/2?

gray oxide
severe ruin
#

just did basics and put numbers

gray oxide
lament forge
#

so what's DBE

gray oxide
severe ruin
#

180-x-y

lament forge
gray oxide
#

Ok then I'm back to square one fuuuuck

severe ruin
#

bro you sure answer is 100% C cuz i thinks its D

gray oxide
#

this is a national test

#

that has the correct answers next to it

#

the chances of it being wrong is very low

#

but never 0 I guess

severe ruin
#

oh

lament forge
#

ok wait hang on

#

there isn't enough information

#

what exactly does the question say?

severe ruin
gray oxide
#

oh

#

shit

#

sorry

lament forge
#

it says more than that

gray oxide
#

I forgot to say

severe ruin
#

define x with y

severe ruin
gray oxide
#

ABC Is a triangle
DE is paraell with AC
DE=BD

#

That is the info

#

lmao sorry about this I made a huge mmistake

severe ruin
#

💀

lament forge
#

oh
so DBE is isosceles

severe ruin
#

yea

gray oxide
#

What's isosceles ?

severe ruin
#

2 side equal triangle

gray oxide
#

I dont study in English so I don't know the terms

#

aha ok

severe ruin
#

same

gray oxide
#

So if DB and ED is the same

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then DEC and DBE would be the same no?

severe ruin
#

i FOUND

gray oxide
#

so B = X?

gray oxide
severe ruin
#

180-x-y=x

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2x=180-y

#

x=90-(y/2)

gray oxide
#

Wait does that mean that B = x?

severe ruin
#

b is 180-x-y

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DEB is x

gray oxide
severe ruin
#

DBE triangle

gray oxide
#

I think I understand

severe ruin
#

EDB is y

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DBE is x

gray oxide
#

can we for sure say DEC = x?

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if so then it's simple

lament forge
#

DEC is not x
but DEB is

severe ruin
#

180-x-y=x
2x=180-y
x=90-(y/2)

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i think thats the answer

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C

gray oxide
#

yea sorry DEB lol

severe ruin
#

@lament forge can you confirm that ?

severe ruin
gray oxide
#

ye so finally lmao we got it LET'S GO BOISSSSSSSSSSSSSS

lament forge
#

yep that looks right

severe ruin
#

lolll

#

finally

gray oxide
#

you guys are sick thank you so much for helping me out this took too long because I did not give enough info so sorry about that again thx guys good luck on helping the rest of the channels that are open

severe ruin
#

<3

gray oxide
#

.close

lone heartBOT
#
Channel closed

Closed by @gray oxide

Use .reopen if this was a mistake.

#
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craggy nebula
#

How is the integral symbol used? (∫)

lone heartBOT
quasi vector
#

do you mean how to write it in latex?

craggy nebula
#

No, I've never learned what it does.

quasi vector
#

well

#

it basically represents the area under a curve

craggy nebula
#

Hm?

quasi vector
#

if you really want to learn integration, I would suggest watching 3Blue1Brown's series on the essence of calculus

#

it will give you a sense of calculus beyond what school curriculum's will

craggy nebula
#

All right. Thanks.

whole shell
#

$\Sigma$

ocean sealBOT
#

doctor99268

craggy nebula
#

I know a little about it.

whole shell
#

the integration symbol

#

is basically

#

its brother

#

@craggy nebula do you know what discrete vs continous are

craggy nebula
#

Like capital pi is? (∏)

whole shell
craggy nebula
#

I've stumbled across it when developing games, but never really understood what they mean, so no.

whole shell
#

discrete just means that

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it is split into seperate blocks

#

this would be discrete

craggy nebula
#

Yeah.

whole shell
#

this would be continuos

craggy nebula
#

Oh, so interpolation?

whole shell
#

you use interpolation for discrete values

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because you dont have information

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on whats between

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while continous

#

you have the information for everything

craggy nebula
#

Linear interpolation?

whole shell
#

linear interpolation is one form of interpolation