#help-0
ocean sealBOT
pseudo ice
That's how to plot things here btw
vapid shuttle
nice
xsinx does converge from 0 to inf though doesn't it
its gonna converge to 0
which is what that equation gives you aswell
you get gamma(2) is 1* sin(pi) = 0
pseudo ice
,w int x*sin(x), x from 0 to inf
ocean sealBOT
pseudo ice
Think its sin(x)/x that may be the one you were thinking of?
vapid shuttle
sinx-xcosx
and then do limit as t goes to inf
replace with t's and 0s
I get that it converge to 0
quasi vector
,w graph sin(x)/x
ocean sealBOT
ocean sealBOT
vapid shuttle
well that one uses a different function lol
quasi vector
quasi vector
yeah
vapid shuttle
instead of gamma function
quasi vector
but
vapid shuttle
Si(x)
quasi vector
I think im rushing into things without understanding
thanks for your help thou
im gonna go learn stuff properly
vapid shuttle
Yeah sorry if it wasn't the most helpful
quasi vector
.close
lone heartBOT
vapid shuttle
good luck!
lone heartBOT
Available help channel!
alpine sable
,w calculus
lone heartBOT
,w calculus
ocean sealBOT
Requested by Loues#4445
alpine sable
IBP / tabular ?
sullen meteor
,w calculus
Integrate it by parts
sullen meteor
yeah but i don't know how
First step set the u, and dv
harsh swallow
@alpine sable Another good source for integration by parts is blackpenredpen
he is a proponent of the DI method and i am 100% standing behind him on that
it is the easiest method making integration by parts easy
lone heartBOT
@alpine sable Has your question been resolved?
cedar cloak
Hi does anyone know how to solve this?
timid igloo
lone heartBOT
timid igloo
3rd times the charm
I’ll just wait here for someone to come
Whoever shows up, please ping me
lone heartBOT
@timid igloo Has your question been resolved?
timid igloo
<@&286206848099549185>
timid igloo
<@&286206848099549185>
rustic coral
Honestly this is straight calclator work - either check your calculator model or google it for your specific calculator.
timid igloo
Honestly this is straight calclator work - either check your calculator model or...
Dawg I don’t know how to do it haha
timid igloo
Yes yes
violet surge
lone heartBOT
violet surge
can someone solve this for me req
rq
i got sqrt(3)/3 as my answer
$\frac{\sqrt{3}}_{3}$
ocean sealBOT
NotOrz
Compile Error! Click the 
reaction for more information.
(You may edit your message to recompile.)
violet surge
there no answer book to this problem as i just found this textbook as a pdf and i just wanna make sure my ans is correct
gray isle
show your work
violet surge
show your work
here
gray isle
seems alright, don't forget this is just the x-coord of the point
they want the full coordinates
young solar
My question is how to find the greatest common factors of big numbers. The question I am stuck on is "What is the greatest common factor of 10^9 and 25!"
ocean sealBOT
The following error occured while calculating:
Error: Undefined symbol u
ocean sealBOT
The following error occured while calculating:
Error: Undefined symbol u
raven haven
If you want to help just help
worn fox
@young solar starting by prime factoring 10^9 would be a good start
young solar
yea so I got 2^9 and 5^9
worn fox
yea so I got 2^9 and 5^9
right so then just find as many factors of 2 and 5 as you can in 25!
young solar
I'm not sure how to do that. Can you explain how?
normal gull
Can someone help me with question 1.b please.
violet surge
write 25 as 25 x 24 x ... 1
lone heartBOT
Can someone help me with question 1.b please.
Please read #❓how-to-get-help
violet surge
bro use a dif channel
normal gull
!help
lone heartBOT
Please read #❓how-to-get-help
last ether
normal gull
it said come to help-0
gray isle
it said come to help-0
not really. it says to use one of the channels under available
young solar
and see which ones contain 2s and 5s
wait so when you said contain 2s and 5s is that just 2^1 and 5^1 or can it be 2 to any power and 5 to any power?
violet surge
like 5 10 15, 20, 25
and any even number
actually wait no then they dont go into 10^9
hold up dont listen to me
violet surge
wait so when you said contain 2s and 5s is that just 2^1 and 5^1 or can it be 2 ...
yeah this
young solar
ok so I counted 16 instances of 2s and 5s in all the factors from 25 -> 1
gray isle
how are you getting 16
young solar
(5^2) (2^3 x 3) (23) (2x11) (3x7) (2^2x5) (19) (2x3^2) (17) (2^4) (3x5) (2x7) (13) (2^2x3) (11) (2x5) (3^2) (2^3) (7) (2x3) (5) (2^2) (3) (2) (1)
I just counted how many 5s and 2s were in these
violet surge
(5^2) (2^3 x 3) (23) (2x11) (3x7) (2^2x5) (19) (2x3^2) (17) (2^4) (3x5...
2^3 x 3 doesnt work
gray isle
doesn't tell me where 16 is coming from
gray isle
doesn't matter
violet surge
so no way can 24 be a divisor of 10^9
bro what???
its asking for greatest common factor
gray isle
it has factors of 2, that's all you care about
violet surge
no
My question is how to find the greatest common factors of big numbers. The question I am stuck on is "What is the greatest common factor of 10^9 and 25!"
the greatest common factor must divide both the numbers
so how can 24 be a factor of 10^9
gray isle
who said it was?
violet surge
krillix
violet surge
(5^2) (2^3 x 3) (23) (2x11) (3x7) (2^2x5) (19) (2x3^2) (17) (2^4) (3x5...
here
gray isle
no they didn't
young solar
I was just listing the factored form of the numbers from 25 -> 1
violet surge
I was just listing the factored form of the numbers from 25 -> 1
yeah just realized
nvm mb
gray isle
doesn't tell me how you're getting 16
violet surge
I just counted how many 5s and 2s were in these
so there are 9 numbers in this list that have only 2s and/or 5s
in their prime factors
violet surge
doesn't tell me how you're getting 16
i think hes counting the ones that have at least one 2 or 5 in them, but hes forgetting to exlude the ones with other prime factors
young solar
oh ok I was also including ones with other numbers
gray isle
still doesn't tell me how you're getting 16
young solar
Idk lets just forget about that
violet surge
ok just multiply all of the numbers that only have 2s and 5s in them
gray isle
consider the total factors of 2 and 5 separately
violet surge
and make sure the final answer does not have more than 9 2s and 9 5s
or else it wouldnt divide 10^9
young solar
ok so 2^9 and 5^6
gray isle
is that your final answer for the gcd?
young solar
would it be 10^6 x 2^3?
gray isle
doesn't really answer my question
young solar
would it be 10^6 x 2^3?
this would be my final answer
gray isle
that would be acceptable
young solar
alright thanks for the help
rotund grove
I can’t seem to get the integration by parts part right… anyone know what I did wrong
lone heartBOT
I can’t seem to get the integration by parts part right… anyone know what I did ...
@rotund grove Has your question been resolved?
cursive badger
integration by parts looks right to me
I think it's your substitution that's wrong
lemme work it out just a sec
yup @rotund grove your integration by parts is correct
it makes sense too, since there is no way your substitution answer can differentiate to be correct
peak mist
hello
lone heartBOT
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
@peak mist Has your question been resolved?
past gull
Got a bit of confusion from this
lone heartBOT
Got a bit of confusion from this
vapid shuttle
which parts?
the amplitude of the function is the vertical distance the function ranges from, you can think of it as the magnitude of the 1/2 the range of the function
basically how high does it go, from top to bottom, of a half period
past gull
Amplitude is 7 right?
past gull
The period is what I'm honestly struggling to find
vapid shuttle
the period is how often the function repeats itself
so how far do you need to go in x, for the y-value to be the same as when it started?
x=0, y=0
so how far do you need to get y=0 again? but another caveat is that the function has to be behaving in the same way
the first time it is y=0 again, it hasn't been a full period because the function isnt really repeating yet
so the second time y=0, that is when the function has been through an entire period
because it will start behaving in the same way again after that
,w plot sin(x)
ocean sealBOT
vapid shuttle
see in this graph how on the negative side of the x-axis it is the exact same as the positive side?
so the function completely repeats itself every 2pi
from -2pi to 0 is the same as from 0 to 2pi
so the period for sin(x) would be 2pi
what is it for your graph then?
past gull
So 3pi?
vapid shuttle
if you took from 0 to 3pi
and then shifted it over
to repeat at 3pi to 6pi
would it look the exact same as what is currently graphed?
because if 3pi was the period it should
past gull
Oh 6pi
That makes more sense
So it'd be 7sin(6pi)
9r something
I'm forgett8ng how to make it into the curve form lmao
Mind reminding me?
@vapid shuttle
vapid steppe
So it'd be 7sin(6pi)
that’s just a constant
vapid steppe
I'm forgett8ng how to make it into the curve form lmao
i’m pretty sure you mean 7sin(6πx)
surreal meadow
y=sin(x/b) has period b
2pib
so if you want your period to be 6pi
what must your b be?
past gull
1?
surreal meadow
the function sin(x/b) has period 2pi*b
or if you want
sin(xb) has period 2pi/b
we want to find a b so that the period is 6pi
that is, we want to solve 6pi = 2pi/b for b
surreal meadow
do you remember how to solve equations?
past gull
dude I'm gonna be honest
I barely remember what was before pre Calc since I had a yesr of no math
Alongside my teacher sucks at teaching
viscid relic
How can you determine the type of solution to a system of linear equations WITHOUT graphing, using substitution, or elimination?
surreal meadow
are you being asked to do this?
viscid relic
yes
ruby current
compute the determinant?
heady pollen
Either that or notice symmetries
viscid relic
heres the entire thing. Algebra 2 btw
(1) What are some of the reasons you might choose substitution over elimination to solve a system of linear equations? What should you look for?
(2) What is the least accurate method of solving systems of equations and why?
(3) How can you determine the type of solution to a system of linear equations WITHOUT graphing, using substitution, or elimination?
I dont know that 3rd one
<@&286206848099549185>
gusty gorge
not sure if any of those questions have decent mathematical answers
in practice, systems of linear equations are solved by eliminating so they're triangular, and then using back-substitution
as tushar said, you can compute the determinant of the coefficients matrix (if the coefficients matrix is not a square shape and m > n, then yikes)
lone heartBOT
@viscid relic Has your question been resolved?
lone heartBOT
@viscid relic Has your question been resolved?
wheat isle
How would I do this?
lone heartBOT
How would I do this?
median dirge
What does the question want you to do with it?
median dirge
So after applying the exponent law I get w^-0.5/16v^1/8
The denominator is wrong
The 1/4 would be the power of 16 too
wheat isle
You talking about 2 as in 2^1/8?
lone heartBOT
@wheat isle Has your question been resolved?
lone heartBOT
lone heartBOT
Available help channel!
zealous juniper
Hi, for this one, is the mass of the crate = 1000-700x?
lone heartBOT
Hi, for this one, is the mass of the crate = 1000-700x?
zealous juniper
I think I should do work of crate+ work of cable
for the cable I did Work = 100 lbs*50ft is it correct ?
lone heartBOT
@zealous juniper Has your question been resolved?
lone heartBOT
@zealous juniper Has your question been resolved?
zealous juniper
<@&286206848099549185>
ruby current
not sure if any of those questions have decent mathematical answers
not without some algebraic geometry 😄
lone heartBOT
@zealous juniper Has your question been resolved?
zealous juniper
.close
lone heartBOT
lone heartBOT
Available help channel!
alpine sable
how do i do reverse percentages
lone heartBOT
how do i do reverse percentages
vale wigeon
wdym by "reverse percentages"?
alpine sable
one second
how do i solve these types of questions
im not getting answers on youtube
and the marking scheme for this question is confusing
vale wigeon
15% of the pen's normal price is £1.20
what is the pen's normal price?
that's what this question can be rephrased to
or in other words, "15% of ___ is 1.20"
alpine sable
okay
vale wigeon
does that make it clearer for you how to proceed?
vale wigeon
okay... how familiar are you with algebra?
alpine sable
i just dont know how to continue
alpine sable
okay... how familiar are you with algebra?
pretty bad at it
alpine sable
can you show me both
vale wigeon
so first, can you tell me what 1% of the normal price would be?
alpine sable
how would i find that out
alpine sable
so divide both sides by 15?
0.08
now would we times that by 100 to get the answer
0.08 x 100 = 8
vale wigeon
yes, to get 100% of the normal price, you would multiply 1% of it by 100.
lone heartBOT
lone heartBOT
Available help channel!
placid swallow
lone heartBOT
placid swallow
The exercise gives these two sets described as so
the goal is proving the last statement
placid swallow
,rotate
ocean sealBOT
placid swallow
Is this enough or am I supposed to do more?
I've just given an example following the constraints given by the exercise to prove that inequality is true
lone heartBOT
@placid swallow Has your question been resolved?
lone heartBOT
@placid swallow Has your question been resolved?
lone heartBOT
@placid swallow Has your question been resolved?
alpine sable
I've just given an example following the constraints given by the exercise to pr...
Inequality?
alpine sable
Ah I see
Okay so, use the advantage that A1, A2 and B1, B2 are disjoint sets
i.e., they have no common elements between them respectively
alpine sable
the one with ≠
By the way, you may call it an inequation/inequality
alpine sable
Well it seems you have proved the inequality holds for that particular example only
You have to show that the inequality holds for any kind of set A and B
Also, are the sets finite?
placid swallow
the exercise just say Let A and B be two not-empty sets
no mention of their cardinality
alpine sable
I see
I was thinking of using the size of the sets in the proof, but if infinite sets are also allowed, I would also be not sure how to prove the inequality for that case
placid swallow
the idea was proving the that the product of A and B is the union of the subproducts of A1 and B1 and A2 and B2, finding an example where this isn't true (which I did), and then going back to the initial hp.
alpine sable
Say I define a Real function f(x) = √x and claim this holds for all real numbers, by showing an example by taking x=4. Surely this proof would conclude my statement is true, which is in fact, false
But I can take a contradictory example (like take x=-1) and show my statement is false. That is allowed
placid swallow
But I can take a contradictory example (like take x=-1) and show my statement is...
this was the idea
rather than proving that the inequality is true, let's prove that the equality is false
alpine sable
The flaw in the logic is that you are providing only one example for showing the equality does not actually hold. There could exist other sets that could satisfy the equation (as the proof didn't include that). What you could do is proof by contradiction, by claiming the equality holds for any set A and B, and in the end proving that no such sets A and B exist by contradiction
lone heartBOT
@placid swallow Has your question been resolved?
sturdy yacht
Lets say u have a trapezoid and the ratio between a:c is 5:2 the diagonal of the trapezoid cuts the sharp angle in half and the diameter of the trapezoid is 33cm how do i calculate the height of the trapezoid here
sturdy yacht
The legs of the trapezoid (b) are equal
I started with like 33cm=7t +2b but not much from here im assuming there must be somthing with the diagonal by idk what
lone heartBOT
@sturdy yacht Has your question been resolved?
lone heartBOT
<#490557019623915520>
halcyon monolith
image 1
image 2
Is the last line of image 1 exactly equal to the last line of image 2?
wild trail
!help
lone heartBOT
Please read #❓how-to-get-help
alpine sable
ok
lone heartBOT
@halcyon monolith Has your question been resolved?
halcyon monolith
<@&286206848099549185>
lone heartBOT
@halcyon monolith Has your question been resolved?
sturdy yacht
If any triangle has the ratio a:b is 2:3 are the height(a) and height(b) in the same ratio 2:3/3:2
hard patio
bad google translation
sturdy yacht
Bahahahah
Aight leme try to explain
Draw any triangle that has a:b=3:2 this ratio
Are the heights of a and b in the same ratio ?
sturdy yacht
No
Any triangle u can think of
Sides
a,b,c
a:b=3:2
now is height(a):height(b)=3:2 ?
sturdy yacht
yes
hard patio
now a:b = 2:3
sturdy yacht
Yes
sturdy yacht
Tf has area to do with here
Not really bro
U can have sides long 10km
The ratio is 2:3
So like if a = 2x b will be 3x
hard patio
at least give me a minute here
sturdy yacht
Kk
sturdy yacht
Wdym
hard patio
Okay here
sturdy yacht
sturdy yacht
Yea
hard patio
So the area of this triangle remains constant
hard patio
a=2t and b=3t
sturdy yacht
Correct
hard patio
so whats the area of this triamgle
sturdy yacht
Ur one ?
hard patio
1/2 * (base)(height)
sturdy yacht
Yea
sturdy yacht
Correct
hard patio
and if you use base a?
sturdy yacht
1/2 * a *height of a
sturdy yacht
Yea
hard patio
1/2 * b * h(b) = 1/2 * a * h(a)
sturdy yacht
Ur the god
Ur acctualyy the best
Holy moly
Marry me
Tysm again holyyy
Have a good one boss
hard patio
Have a good one boss
you too:)
sturdy yacht
.close
silk notch
how can i not forget things that i learn?
lone heartBOT
how can i not forget things that i learn?
hard patio
can you more specific?
limpid spade
Ask a math question
hard patio
also that might not be a question for the help channels, but rather for the general section
hard patio
Ask a math question
cant force em
silk notch
I studied math before, but can't solve most of the math algebraic problems now?
silk notch
Ask a math question
sorry sir
lone heartBOT
@silk notch Has your question been resolved?
junior warren
lone heartBOT
junior warren
could someone help me with this, absolutely despise these drag and drop proofs
i know it has to end in; therefore a is a subset of b
so that narrows it to 4 more
and i assume before that would be "we have shown x element of a so x element of b
north hemlock
well u need to talk about the stuff in A cross B so the first one is ur start
junior warren
ah ok
north hemlock
and i assume before that would be "we have shown x element of a so x element of ...
u can just sps x in A cross B
junior warren
sps?
north hemlock
suppose*
junior warren
ah
right
so from there
would i go to the "for any b"
actually that doesnt relate to x
does this look right?
junior warren
well
north hemlock
oh sorry, ur first statement should be x in A then later show x in B
junior warren
is that not just the assumption?
north hemlock
is that not just the assumption?
That's true
bc currently we have x in A cross B implies x in B
junior warren
oh right
north hemlock
mbm
north hemlock
x in AxB implies that x is in A right?
no bc x can be from B but still be in A cross B
so we should have started with x in A
junior warren
is that true?
if x is ONLY in b
i dont think its in this AxB
since its x,b
unless im thinking about this wrong
but anyways yeah we can start with x in a
from there would i say for any b?
north hemlock
I'm trying to say that like if we start with x in A x B then it may be possible that x was originally from B so the following statement "we hvae shwon x in A" this part, it's not true
junior warren
right
north hemlock
from there would i say for any b?
the rest is fine
north hemlock
we just have to make sure that we say x is from A and not A cross B
north hemlock
yeah, that's mb tho, bc I said that originally overlooking the fact that x in AxB can be x from either A or B
north hemlock
otherwise x can be from B
exactly
junior warren
ok so now
a worse one
one second
the same statement just
opposite?
would this not be
the exact same proof?
oh it is
okay thank you
north hemlock
yes sae
north hemlock
cartesian product new concept so this made it much clearer
it's like "combining" the domains kinda lol if that helps at all
north hemlock
junior warren
just the proofs behind it are new
junior warren
since im not sure how all the things interact
north hemlock
I see
spring spruce
So its supposed to be -9k I guess. What am I doing wrong exactly.
outer lark
positive k coefficent
only j is negative
+i (somin) - j (somin) + k (somin)
you have super neat hand writing btw
very nice
lone heartBOT
outer lark
it may of taken a (-1) out as a factor
but then you swap the order of the inside determinant of the 2x2
its commonly done to turn -j into +j
spring spruce
well it had it in the form i -j -k. think it was just a mistake with the lecture.
outer lark
👍
lone heartBOT
Available help channel!
raven field
lone heartBOT
raven field
what information tells me that the angle would be in quadrant 1?
since sin is positive in quad two and 1
but like what information specifically lets me know that sin is in quad 1 and not quad 2
tacit arch
what information tells me that the angle would be in quadrant 1?
domain and range of arcsine
lone heartBOT
@raven field Has your question been resolved?
raven field
wait so what would have to change for it to be in quadrant two?
tacit arch
what is "it"
raven field
what would be an example of a value of arcsin that would be in quad 2?
tacit arch
what would be an example of a value of arcsin that would be in quad 2?
,w range of arcsine
ocean sealBOT
tacit arch
do you understand what range of a function is?
tacit arch
ya its what values y can be
what's the range of arcsine?
raven field
[-pi/2, pi/2]
raven field
im not sure lmao im having a brainfart right now
if we look at it through a unit circle cant the 2nd quad share the same y values as the 1st quad
tacit arch
raven field
it has to be positive in the top right so i guess only 0 to pi/2 would be found in both quad 1 and 2
tacit arch
,tex .unit circle
ocean sealBOT
riemann
surreal oracle
lone heartBOT
ocean sealBOT
yomiko
ocean sealBOT
Result:
1.7071067811865
,calc (2+sqrt(2))/4
ocean sealBOT
Result:
0.85355339059327
the denominator should remain 2 and not magically change to 4
humble scroll
Hello
humble scroll
Could someone help me with this
I thought the answer would be a plus b but it wasn’t correct
slow hound
probably probability
alpine sable
oh
alpine sable
I thought the answer would be a plus b but it wasn’t correct
if u draw a venn diagram it can help visualize it
the intersect is 0.1, so how much is just in A and just in B
and from there whats the total
and then complement it
tacit arch
"You look nice today, probability"
worn fox
"You look nice today, probability"
might unironically be the funniest thing you've said
lone heartBOT
@humble scroll Has your question been resolved?
grizzled marsh
raven fog
how do I get the derivative of sqrt(3x-1)?
lone heartBOT
how do I get the derivative of sqrt(3x-1)?
plain flame
power rule, chain rule
raven fog
what is the chain rule? we've only learned the power rule
lone heartBOT
@raven fog Has your question been resolved?
stone dove
is this valid, i feel like i translated to the implication incorrectly in the first step
plain flame
lone heartBOT
@stone dove Has your question been resolved?
empty canopy
hey
empty canopy
i have a calc question
If f(c)>0, then f(X) is concave up at X=C.
can someone please tell me if thats right
empty canopy
why is it false tho
tacit arch
why is it false tho
do you know the definition of concave up?
tacit arch
why is it false tho
empty canopy
.close
fair musk
can anyone catch my mistake?
lone heartBOT
can anyone catch my mistake?
fair musk
alpine sable
you went from theta to x
and you didnt change dx to dtheta
you need your theta bounds as well
unless you are subbing back in x at the end
fair musk
you went from theta to x
should i restart the whole thing or can I change a small portion?
alpine sable
id probably restart
lone heartBOT
@fair musk Has your question been resolved?
fair musk
.close
worldly kindle
im super confused
lone heartBOT
im super confused
worldly kindle
did he js typo or smth
static minnow
ok
hearty valve
For R^2 explained variance, is it higher the better or lower the better 0-1
outer lark
You want it to be as close to 1 as possible
hearty valve
Ok ty
lone heartBOT
@hearty valve Has your question been resolved?
spring harbor
I don’t understand E or F
wheat crystal
.close
broken locust
lone heartBOT
broken locust
How do you do B, C
lone heartBOT
@broken locust Has your question been resolved?
north hemlock
How do you do B, C
think about derivatives and what that might mean here
(assuming u can't just use the graph as ur justification btw)
if u can use the graph as justification then just legit point out that "hey, u see it going down? that's decreasing!"
broken locust
nvm i got the justification and asnwer
for that one
i just need help on this one
north hemlock
which part
north hemlock
u can use FTC2 for that iirc
broken locust
? for whihc one
north hemlock
sorry FTC1, to deal with that integral
since ur gonna need that derivative for the questions, FTC1 applies
north hemlock
Get what?
oh sorry, I'm not doing the problem, just giving u hints to go thru it lol
I can solve it real quick tho, gimme a sec
broken locust
oh sorry, I'm not doing the problem, just giving u hints to go thru it lol
like ik that local max is when it changes from positive sign to negative sign
for the h'(x) function
adn so u put in 2x-2 into f(t) so its d/dx(f(2x-2)
so its like 2f(2x-2)
idk wht to do after
north hemlock
wait, no the derivative of that is just f(2x-2)
broken locust
isnt it chain rule?
north hemlock
ftc1 is $$\frac{d}{dx} (\int_a^{g(x)}f(t)dt) = g'(x)f(g(x))$$
ocean sealBOT
Jukelyn
north hemlock
isnt it chain rule?
yea
broken locust
yea
so then its 2f(2x-2)
right
wait so how do u use tht to solve for local max/min
north hemlock
oh sorry, I didn't type it here but yeah
I had it written on my paper but didn't type it, that's mb
broken locust
oh its okay
broken locust
I had it written on my paper but didn't type it, that's mb
so wht do u do after?
north hemlock
so wht do u do after?
so for extrema we want h' to be 0 but that doesn't hapenn on the interval (-1, 5)
so there are none
since h' = 0 is when f(t) is 0 and that happens at -1, 5, and 8
but -1, and 5 aren't included in the interval. so we can't use those
north hemlock
oH shit, I mixed x and t
okay so for t= -1, -5, and 8 are critical points
and t = 2x-2 so the x are x=-4, x=3.5, and x=5
so x= 3.5 is indeed a critical point
sorry abuot that
lone heartBOT
@broken locust Has your question been resolved?
broken locust
sorry abuot that
oh okok thanks
dark spade
I have a simple work question
lone heartBOT
I have a simple work question
dark spade
for part A they use mgd, so they include gravity
for part b they do not
why is that
surreal meadow
they used distance there
30 * 4 feet
oh
you’re asking about gravity sorry
30lbs is a force
it’s the weight of the object
this is different from mass
5kg referred to the mass of the object
to find the weight you’d do mg
but 30lbs is already mg
wheat isle
Please help I’ve been stuck on this question for days
lone heartBOT
Please help I’ve been stuck on this question for days
wheat isle
I know that w^-0.5 and the denominator is 16^1/4(v^1/8)
I don’t know what comes after
gusty gorge
what are you asked to do
wheat isle
Simplify
flint pecan
You can simplify 16^1/4 first
wheat isle
You can simplify 16^1/4 first
So that’s just 4 then?
wheat isle
Oh it’s 2
flint pecan
Yup
You can either bring w^(-1/2) to the denominator or bring v^(1/8) to the numerator
wheat isle
Is that it’s most simplified form? By flipping the sides
flint pecan
Wdym by "flipping the sides"
flint pecan
Why did you flip it 😭
wheat isle
You can either bring w^(-1/2) to the denominator or bring v^(1/8) to the numerat...
I thought that’s what you meant by this
flint pecan
This is what I meant
wheat isle
This is what I meant
Oh
Is that the most simplified it can get I’m assuming
Thanks
.close
steady timber
lone heartBOT
tawny condor
$\ln(y) + \ln(x) = \ln(xy)$
ocean sealBOT
RedstonePlayz09
steady timber
i dont get it
tawny condor
log sum formula
but you don't even need this
just raise e to both sides
$e^{\ln x + \ln(x+2)} = e^{\ln(x+6)}$
ocean sealBOT
RedstonePlayz09
narrow oar
Just confused why I’m getting two different answers for the simplified version of the formula
narrow oar
i get 0.1833712082 for the standard deviation when using the unsimplified formula but get 0.18234582528 when using the simplified formula
just barely different but i don't get why theyre different whatsoever
slate monolith
i get 0.1833712082 for the standard deviation when using the unsimplified formul...
maybe its the difference of population and sample sd
or maybe your calculator just rounded somwhere
narrow oar
i mean its 11 digits so it cant be a rounding difference
and the numbers being multiplied to simplify arent so big that they were ever rounded
its the same formula and same input, but for some reason different answers
slate monolith
i mean its 11 digits so it cant be a rounding difference
fromn previous steps
narrow oar
ya the numbers being mulitpied to simplyify arent big enough to be rounded
slate monolith
maybe your algebra messed up
gusty gorge
what do you mean by simplified vs simplified formula
slate monolith
just do it again but slowly
narrow oar
i did it three times, look over it does any of it look wrong?
narrow oar
what do you mean by simplified vs simplified formula
unsimplified formula is the first equation set equal to sd of p, simplified is second equation
i just multiplied it out to get it in simpler terms
gusty gorge
give more context
I actually don't know what you're doing on that paper
ugh it's the stupid portfolio theory stuff again
narrow oar
filling out the table for b, double checked my answer from the simplified formula with the unsimplified and for no apparent reason they are slightly different
but im p sure my algebras not wrong
gusty gorge
standard deviation of the portfolio is given by sqrt(X_D^2 sigma(R_D)^2 + (1-X_D)^2 sigma(R_I)^2) correct?
or perhaps I'll write it in LaTeX
$\sqrt{X_D^2 \sigma_D^2 + (1-X_D)^2 \sigma_I^2 - 2\rho_{D, I} (1-X_D)X_D\sigma_D\sigma_I}$
whoops forgot the correlation term
narrow oar
narrow oar
lol idk man thats the formula tho
ocean sealBOT
Saccharine
gusty gorge
it's just the formula Var(X+Y) = Var(X) + Var(Y) - 2Cov(X, Y) but with fancier symbols in it because investment science professors love to do that
narrow oar
i mean i can just use the unsimplified one and move on because i dont think i have to take the extra few steps i took, im just genuinely curious why my simplified formula doesnt give the same answer
cause im almost 100% my algebra and calculations were right
gusty gorge
I still don't know what you mean by unsimplified or simplified
what's there to simplify here
narrow oar
the (1-X)^2 and the X(1-X)
gusty gorge
how would you simplify that?
narrow oar
like i did on the apper, X^2-2X+1 and X-X^2
gusty gorge
that doesn't simplify anything lol
narrow oar
makes it a simpler formula is what i mean
gusty gorge
you must've made a rounding mistake or something if you got slightly different answers
narrow oar
but i didnt lol, the only multiplication to be done was .0225 times 2, which is just 0.045
theres no room for rounding error because no rounding was done
and i used the full terms for each number when solving
gusty gorge
you said you got a value of 0.18 for something?
narrow oar
i get 0.1833712082 for the standard deviation when using the unsimplified formula but get 0.18234582528 when using the simplified formula
"simplified"
gusty gorge
I get the same thing for both of them
which is 0.18337121
so this is definitely a rounding mistake on your part or some other entry mistake
narrow oar
oh wtf i just plugged em in again and got that too
im just dumb
using phone calculator is so garbage my graphic calculators broken
i was going crazy over nothing lmao ty
.close
twin drum
how do i separate 2 sin waves?
lone heartBOT
how do i separate 2 sin waves?
twin drum
Fourier series?
grim basin
lone heartBOT
grim basin
i have a few questons
we're using u-sub to get the answer
and i dont understand where i u-sub and why
<@&286206848099549185>
sudden igloo
in this i think F would be right then it will simply become differentiation of sec u
sudden igloo
differentiate 33w so it would 33
grim basin
yes, but how would we incorperate that back into the original equation
pseudo ice
Notice that after changing variables, you’re integrating something you know is the differential of something
sudden igloo
replace dw by du/33 and rest inplace of 33w you can write u
grim basin
Notice that after changing variables, you’re integrating something you know is t...
im a bit confused by this
grim basin
replace dw by du/33 and rest inplace of 33w you can write u
so like 1/33(du) = dw
?
but why exactly do we do that?
pseudo ice
It makes life easier once you change the variables (though imo the variable change isn’t really needed as much)
grim basin
ah okay, i think my problem is i dont understand it enough, so i wouldnt do this on my own (like without help)
pseudo ice
Ahh, it’s mostly practice I think really ☺️
But like sometimes I find variable changes not really needed (though that’s mostly cause I learned to do some integrals “by recognition”) 
grim basin
well i dont struggle with most other equations
grim basin
But like sometimes I find variable changes not really needed (though that’s most...
ah okay, that makes sense
sudden igloo
yes substitution is not really required
sudden igloo
once there is linear replacment of x its not really needed
sudden igloo
practice is something that can only help
pseudo ice
To be fair, many of the “by recognition” ones are basically u sub in disguise, in a way
grim basin
well not if i dont quite understand how to do a problem :')
sudden igloo
try some solved examples
grim basin
i already did like 14 on my own :<
just the more difficult ones im stuck on
i understand u-sub
just some more difficult ones stump me
hence me doing 13/16 problems on my own :')
pseudo ice
Ah, like which ones did you find easier and which ones were harder?
Just so I have an idea of like how much they differ
pseudo ice
well the 3 problems i have im stumpt
The ones up in this thread yea?
grim basin
yes maam
these are ones i’ve done before (with the exception of 9 and 10)
and these
pseudo ice
Ahhh I see, fair fair!
