help-0

[lone heart]

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[urban mural]

Anyone free?

[urban mural]

My question is, John and Mary are walking a circular pathway of 1.2km. John's walking at a constant pace of 4km/h and mary was walking at a constant pace of 5km/h. If they walk in the opposite direction. Find the time it takes for them to pass each other if they start at the same point...

lemme know how to approach it

[fringe sleet]

its the same as if one of them was walking 9 km/h and the other was stationary

[prime badge]

without knowing the length of the track you can point at the point where they meet

like they walk for the same amount of time, so mary will walk 5/4 of the distance John will walk

[urban mural]

ok

given me an idea

thanks

[plain flame]

thats not really how this server works

[lone heart]

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[sterile shuttle]

i get this but how can i apply it

[errant raft]

Hello, is anyone willing to help me with this, this is the first the time I've seen this type of problem

[sterile shuttle]

wrong channel

[errant raft]

Ohhh sorry

[sterile shuttle]

because from my understanding, for values of g(-1/2) then we get g(-1/2) = integral from -1/2 to 1 f(t) dt. since I dont know f(t) then what do i do

[last ether]

,tex \ftctwo

[ocean seal]

Umbraleviathan

[sterile shuttle]

wait

so f(1(-1/2)*1'(-1/2) - f(-1/2)a'(-1/2))

what would be 1'(-1/2)?

i've never seen the FTC be written like that

or am i misunderstanding it

[last ether]

First of all, if b(x) = 1 then b'(x) = 0

And if a(x) = x, then a'(x) = 1

[sterile shuttle]

oh

so with the values you've given, then you get f(-x) no?

because b'(x)=0 then you get f(0-x)=f(-x)

[lone heart]

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[sterile shuttle]

.close

[lone heart]

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[alpine sable]

Help

[alpine sable]

I have been absent for the past 2 days and my teacher sucks and won't help me so I don't understand

[sterile shuttle]

for the first question, when you have an exponent to the power of another exponent, that is the same as multiplying them

[alpine sable]

Ok

So t-¹²

[sterile shuttle]

yea

[alpine sable]

So that would be uh

Idk

[sterile shuttle]

well its just t^-12, thats the final answer

[alpine sable]

How

[sterile shuttle]

T is an unknown number

we cant calculate it further

[alpine sable]

Ok what about 2

Question 2

From left to right

[sterile shuttle]

(3d)^-3

[alpine sable]

Yes

[sterile shuttle]

is the same as (3^-3)*(d^-3) =??

[alpine sable]

What

So u just multiply all things by -3

[sterile shuttle]

no

[alpine sable]

Or ^

[sterile shuttle]

yea

what is 3 to the power of -3

[alpine sable]

So 27

-27

[sterile shuttle]

not exactly

[alpine sable]

3x3x3

Tho

[sterile shuttle]

with negative integers, you have to flip them

so it would be 1/27

[alpine sable]

Ohhh

The invisible 1

[sterile shuttle]

when you have a^-2, that is the same as 1/a^2

[alpine sable]

I see

And d is unknown

[sterile shuttle]

yup

but remember, d^-3 is the same as 1/d^3

so the final answer would be?

[alpine sable]

Uh

1/27 1/d^3

[sterile shuttle]

close, but remember, they are being multiplied

[alpine sable]

1/27 x 1/d^3

[sterile shuttle]

make them under the same fraction

[alpine sable]

Idk what you mean

[sterile shuttle]

well, 1/3 multiplied by 1/2 is what?

[alpine sable]

1/6

2/6

[sterile shuttle]

yea so 1/27 multiplied by 1/d^3

1/6 is right

[alpine sable]

Ok

This is tough

Fractions I suck at

[sterile shuttle]

it always is

[alpine sable]

And this stuff is hard

[sterile shuttle]

no worries, often times the difficulty comes in the fact that your seeing this the first time

you are experiencing and understanding something completely new to you

that will always be difficult

[alpine sable]

Yes

Ok I'm done thanks for your help

.close

[lone heart]

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[tiny marten]

Am i doing it right?

[alpine sable]

no

[tiny marten]

Darn i've been stuck on this for hours

[alpine sable]

expand the brackets if you wanted to see if it is equal or not

[sterile shuttle]

try factoring out x^4 first

factor our whats common to the function

[tiny marten]

Sounds hard

[sterile shuttle]

how so, what do you get after factoring x^4 out

[tiny marten]

Uh 8

[sterile shuttle]

well, when you take out x^4, whats left? when you take x^4 out of x^6, what do you have

[tiny marten]

idk

aw man this is harder than the other ones

aw snap

[tiny marten]

😭

idk

fuck this

this is stressful

.close

[lone heart]

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[bitter sage]

Hi, im completely stuck on this question and im not sure how to get about finding this limit.

[buoyant kayak]

use dominant terms

[slow hound]

what class, calculus or analysis?

[bitter sage]

sorry for late response, this is for calculus

i understand that quotient law means i can find lim of numerator and lim of denominator and than divide

im unsure for indeterminate form inf/inf if its allowed to be -inf/inf

[buoyant kayak]

dominant terms

[bitter sage]

what that mean

[buoyant kayak]

bigger powers grow faster

[bitter sage]

so -x^3 in dominator and 10x in numerator?

[buoyant kayak]

sqrt(-x^3)

[bitter sage]

ya i meant that

but than what would i do knowing those numbers

divide by sqrt(-x^3)?

[buoyant kayak]

take the limit of the dominant terms

$\lim_{x\to -\infty}\frac{10x}{\sqrt{x^3}}$

[ocean seal]

a disappointing son

[bitter sage]

that limit doesnt exist correct?

[buoyant kayak]

it does

[bitter sage]

it exists at lim x->-inf ?

i dont understand, the graph of that function never goes to -inf

[buoyant kayak]

indeed it does

[bitter sage]

r u saying the limit doesnt exist or does exist im confused

[buoyant kayak]

it exists

this should be a standard limit

convert to a power if it makes it easier for you

[bitter sage]

so how would i find this limit

[buoyant kayak]

do you know standard limit rules

[bitter sage]

like quotient law>

[buoyant kayak]

can you tell me $\lim_{x\to\pm\infty}{\frac{x^a}{x^b}}$ for $b > a$

[ocean seal]

a disappointing son

[bitter sage]

ok no i didnt learn this

i dont think

[buoyant kayak]

if you haven't learned that then you definitely should not be working on the problem you sent

[bitter sage]

well this is my assigned homework idk what to say

[ornate seal]

The above answer is the generalized version of the problem you posted. If you understand this, you not only will be able to answer your question, but all others like it.

What does your intuition tell you so far?

[bitter sage]

that it either doesnt exist or is = to 0

[buoyant kayak]

why do you say equal to 0

[ornate seal]

it's one or the other

[bitter sage]

for the x^a/x^b where b > a

lim x -> -inf is equal to = 0

[buoyant kayak]

why didn't you say that when i originally asked

[bitter sage]

cuz i figured that out know

i wasnt taught that

[buoyant kayak]

apply it to your problem then

[bitter sage]

but when i use examples in desmos the equations go to -inf

at 0

so it makes sense to me

but 10x/sqrtx^3 doesnt

[buoyant kayak]

looks like you typed it on wrong

[bitter sage]

i dont think i did

[buoyant kayak]

x^3 should be -x^3

[ornate seal]

let's break it down a little

[bitter sage]

oh okay

now it makes more sense

[ornate seal]

x^3, if you take the square root of that, what are you left with?

[bitter sage]

xsqrtx?

[ornate seal]

you have three x's

[bitter sage]

or isnt it x^3/2

[ornate seal]

square root of x^2 is x, not sqrt(x)

[bitter sage]

ya

[ornate seal]

so what's your denominator after taking that square root of x^3?

[bitter sage]

x^3/2 no?

[ornate seal]

think simple, we're trying to get rid of unnecessary notation here

yes, technically, but there's a more obvious way to write that number

[bitter sage]

x times sqrt x

[ornate seal]

in other words, what's x times sqrt(x^2)

[bitter sage]

uh

x^2

[ornate seal]

yep

look at what you have left, 10x?x^2

sorry 10x/x^2

[buoyant kayak]

none of that makes any sense

[bitter sage]

what

[buoyant kayak]

you're correct with this and your intuition that the limit i sent earlier = 0

stick with that

i have no idea what this guy is saying

[bitter sage]

ok

[lone heart]

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[alpine sable]

someone please show me how to do this

Let u, v be vectors in R2 and let’s assume they are linearly independent (e.g. det([u, v]) ̸= 0). Prove that the two vectors u + v and u − v are also linearly independent.

[alpine sable]

Let u, v be vectors in R2 and let’s assume they are linearly independent (e.g. det([u, v]) ̸= 0). Prove that the two vectors u + v and u − v are also linearly independent.

[crimson jetty]

Proof by contradiction, what would happen if u+v and u-v are linearly dependent?

[lone heart]

@alpine sable Has your question been resolved?

[lone heart]

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[rotund cairn]

How would i setup this problem to solve?

[gray isle]

apply interior angle sum of a triangle twice
once for the small triangle
and then again for the big triangle

[rotund cairn]

so for the small triangle it would be 4x+y=180?

[gray isle]

yes

[rotund cairn]

I got 45 as value of x

So what would be the value of y?

[lone heart]

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[sand oriole]

Why would this be true (combinatorially)?

I don't really get what the LHS is counting...

The number of ways to divide n objects into three sets and arrange them in a sequence such that the first set of objects appears first, the second set appears next, and the third set appears last, maybe?

<@&286206848099549185>

[mint goblet]

i aint readin allat

[near saffron]

Do you just need to prove it or do you have to do some reason with combinatorics

[sand oriole]

I need to prove it combinatorially, so I have to say why the LHS counts the same thing as the RHS basically

3^(n-2) is how to select 3 elements, with repetition, out of n-2 elements...

n * (n-1) is choosing for the first element, and second element, respectively, right..

oh!

okay wait

so would this be

choose your first element in n ways, choose your second element in (n-1) ways. what does the 3^(n-2) contribute though

youre choosing 3 elements, with repetition, from the remaining n-2 elements? so would this be counting # of sets like (n, (n-1)th, {a, b, c}) or something? idk...

[near saffron]

I have an idea

Note that I haven't learned combinatorics so I might not be able to describe it well

So the left side is like you had n boxes, you chose two of them and moved them out, and then you assigned the rest a number 1, 2, or 3

The combinations of that

I think the 'k' in the right is like the number of numbers you didn't assign 3

[lone heart]

@sand oriole Has your question been resolved?

[sand oriole]

Oh

wait

that might work!

let me think

[near saffron]

Wait I think k-2 is your number of 3's

So if you go from k=2 to k=n you go from 0 3's to n-2 3's

[sand oriole]

@near saffron so im a bit confused about something

why is it counting the number of 3's exactly?

[lone heart]

@sand oriole Has your question been resolved?

[near saffron]

Because the rest are 1 or 2, which makes sense because of the 2 to the power

Note by counting the number of 3’s, 3 is just a symbol. We could instead of doing 1,2,3 do square, triangle, circle and count the circles

[lone heart]

@sand oriole Has your question been resolved?

[sand oriole]

Oh, that's interesting

okay let me think about that a little more lol

sorry for taking so long!

[sand oriole]

.close

[lone heart]

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[viscid iron]

Hi, I don't really know where to begin for this question. Thanks

[vale wigeon]

plug the given value of x into the expression 1 + 1/x, simplify, then verify that you get the same thing as x

[viscid iron]

Got it thanks

.close

[lone heart]

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[pliant ermine]

I know this is incorrect. What did I do wrong here

[full frost]

the error is in b^2

[pliant ermine]

Her is the answer for reference

Can you elaborate on this

I'm not fallowing

[lone heart]

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[steel olive]

are there any 2 points equidistant from (1/3,1/5) where the coordinates of the 2 points are integers

[full frost]

what do you think

[steel olive]

no

should be the answer

i think

[full frost]

what’s the reasoning

[steel olive]

thats what i want

[lone heart]

@steel olive Has your question been resolved?

[lone heart]

@steel olive Has your question been resolved?

[lone heart]

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[covert sonnet]

is 12a^3 + a = 20 a linear equation in one variable?

[alpine sable]

is a the single variable?

[covert sonnet]

yes

im confused bcz theres cubed on the 1st term

[vale wigeon]

no this is not a linear equation

[covert sonnet]

why so?

[vale wigeon]

because of the a^3

[covert sonnet]

ahhh alr ty

wb 7y = 19 - 2x

rlly confsued ab this

[alpine sable]

a variable is linear when the power on all instances is one

[covert sonnet]

but its asking for in one variable

[alpine sable]

a function is single variable when there is one variable (ex: x, y, a, b, etc.) appearing in function

so 2a^3 + a = 20 is single variable, but not linear

[covert sonnet]

ahhh ty

[alpine sable]

where as 2y + 5x = 0 is multi-variable and linear

in both the variables x and y

[alpine sable]

np

[covert sonnet]

so its not a linear equation in one var?

its linear but not in one var

[covert sonnet]

so its a no here right?

[alpine sable]

2a^3 + a = 20 , this expression is non-linear AND single variable

[covert sonnet]

but what about this?

[alpine sable]

what do you think?

or rather, how similar would you say the equation 7y = 19 - 2x is to 2y + 5x = 0 ?

[covert sonnet]

im so confused abt this lesson sorry i dont know 😭

help

@alpine sable i think its similar since adding a variable or something wont change the equality

[covert sonnet]

<@&286206848099549185> is this a linear equation in one variable?

why

[lone heart]

@covert sonnet Has your question been resolved?

[hushed wolf]

you have to variables

x and y

x's power is 1 and y's power is 1 as well

so its a linear equation

but not one variable bcs you have two variables which are x and y

[hushed wolf]

here

[covert sonnet]

ah so the answer is no?

ah alr tyy

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[lone heart]

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[red zealot]

Permutation: how many different arrangements can be done from the letters in word love?

[pliant cedar]

you have four spaces _ _ _ _, and the four letters l, o, v, e to choose from

how many choices of letters do u have to put in the first space

[red zealot]

4

[pliant cedar]

okay

now say u put the letter l in the first space, how many choices do u now have for the second space?

[red zealot]

3

[pliant cedar]

yes

so with l in the first space, u have 3 choices for the second space

1. lo
2. le
3. lv

how abt when u have o in the first space

then how many choices do u have for the second space

[red zealot]

3?

[pliant cedar]

yes 3 again

so

1. with l in the fist space - 3
2. with o in the first space - 3
   ...

hw many choices is that altogether?

[pliant cedar]

in (1) u have the choices lo, le, lv
in (2) u have ol, oe, ov
etc
how many choices is that altogther then

[pliant cedar]

please read #❓how-to-get-help

[solemn cosmos]

no one helped me. ive been waiting for over 5 months

i keep getting removed

now help me

[red zealot]

24?

[pliant cedar]

you must post ur problem in a new channel

[pliant cedar]

how are u saying this

[red zealot]

in our lesson, we use factorial, so i multiply 4x3x2x1

[pliant cedar]

okay so you already know the answer

[pliant cedar]

4! is how many arrangments there are

[red zealot]

then what formula should i use

[pliant cedar]

what do u mean, 4! is the "formula" u wud use

[alpine sable]

Imagine if you have 4 places for each letters
Now the 1st place will have 4 possibilities among (l,0,v,e)
The 2nd place will have 3 possibilities since one of them is already taken away from (l,o,v,e)
and so on
So multiplying all we get 4 * 3 * 2 * 1 = 24

[red zealot]

oh sorry, i got confused, thanks i alr get it

[red zealot]

thanku

[lone heart]

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[wanton cosmos]

https://cdn.discordapp.com/attachments/1059353595465715823/1072843254711713842/image.png

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@wanton cosmos Has your question been resolved?

[wanton cosmos]

.close

[lone heart]

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[molten orchid]

i need to find ab, how to do by solving using trigonometry?

[wind cloak]

If it's a regular hexagon you don't need to

Since hexagons are the bestagons, you can divide it internally in 6 equilateral triangles

[molten orchid]

i dont understand

how to do trig on equalateral triangle?

[wind cloak]

No trig

Join each of the vertices to the midpoint of AB and you'll get 6 equilateral triangles

AB will become twice the side length

[molten orchid]

how to find side length

[wind cloak]

It's given to you right

5 cm

At the bottom

[molten orchid]

ohh ok

im stupid ahah

thanks for helping

.close

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[rich quiver]

I didn't understand why he took Δx=0

[rich quiver]

In next step to find dy/dx

[wind cloak]

It isn't equal to 0

It's approaching 0

[rich quiver]

So why he took Δx=0 in next step?

[wind cloak]

Where

[rich quiver]

dy/dx = 2x+dx?

[wind cloak]

It's probably an approximation thing

[rich quiver]

When Δx --> 0 he removed the Δx term

[rich quiver]

Ok

.close

[lone heart]

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[proven peak]

If x changes from x=1 to x=2 along the curve y=x^2, which of the following is equal to Δ(xy)?

[proven peak]

7
6
19
8```

<@&286206848099549185>

[raven haven]

!15m

[lone heart]

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

[raven haven]

what on earth is delta xy

[proven peak]

no idea

i got it wrong on a test though

[raven haven]

,tex \factoid original

[proven peak]

its not 6

[proven peak]

it's solveable - it was on a calculus test

[near temple]

Yeah, this is why I didn't even make an attempt. I feel like a definition is important here

[proven peak]

I showed you the answers they provided

it was multiple choice

[raven haven]

yeah unfortunately if you can't provide the definitions

nobody can help

[proven peak]

what the hell do you mean by definition

this is the entire problem

[near temple]

Well, what is Δ(xy)

[proven peak]

there's no more information to give

[near temple]

Like how are you even defining Δ(xy)

[proven peak]

that's the question

[raven haven]

then there's nothing to help

[proven peak]

that's the question

[proven peak]

there is, and it's the reason I'm on this server

[alpine sable]

changed of x and y

[raven haven]

there's no way they will just leave that undefined

[alpine sable]

You just multiplied the change of x and y

[proven peak]

there we go

[pliant cedar]

can u send a picture?

[proven peak]

i did that and it was wrong

[pliant cedar]

of the original problem

[proven peak]

wrong

[near temple]

Well that's like me saying "what's η(xy)". You can't tell me because you don't know what η is

[alpine sable]

:/

[raven haven]

watch this

[proven peak]

no, because for the third time I've provided all of the information

[raven haven]

,tex \factoid amazingNotation

[raven haven]

do you know what's going on here?

no

because the notation is not defined

[wind cloak]

UPEPCPC

[proven peak]

it's one of these 4 - #help-0 message

[wind cloak]

[raven haven]

and we have no idea of knowing which one

[proven peak]

7
6
19
8```

[raven haven]

It could be ANY of them

seriously

delta could be a function

[near temple]

I'm not sure how I can more clearly explain how the question literally cannot be answered without a definition

[proven peak]

okay

it's just one question

[raven haven]

okay how about this

uh

once you get your test back

come back here

[proven peak]

fuck whoever made this exam

[alpine sable]

exam?

[raven haven]

if they seriously left it undefined

[proven peak]

they're the reason I'm cheating(not)

[raven haven]

that's awful

[wind cloak]

Wild guess here but perhaps something like $\dd{xy} = y\dd{x} + x\dd{y}$

[ocean seal]

NEONPerseus

[raven haven]

if you're asking us after the exam ended

[alpine sable]

What class are you in

[raven haven]

then that's fine

[alpine sable]

math class

[proven peak]

yes

[wind cloak]

did I abuse product rule

[raven haven]

prove it

[proven peak]

I said 6 and it was wrong

[proven peak]

calculus

[proven peak]

👀

[proven peak]

solve for xydeltacontact exam provider for further details

[old loom]

i think delta xy is the change of x.y, so its 7, because at x=1 its 1, and x=2 its 8

[near temple]

That's just the Δ(y) though surely?

[alpine sable]

I got 3

[proven peak]

wait so how did you get the blue and green line

show equations (all of them)

[near temple]

This seems like the most reasonable answer

[proven peak]

nvm

[near temple]

Green and blue lines are just the functions x=1 and x=2

[proven peak]

okay

[proven peak]

so how did you get 8 then

they're closer than 8 units

[old loom]

Well at x=2, y is equal to 4 and x is equal to 2. xy implies x times y. at x=1 xy is 1.

[proven peak]

but at x=2 y is equal to 4, not 2

[old loom]

Slight oversight sorry

Still the same answer

[proven peak]

whhhyyy

[old loom]

The answer is 7

[proven peak]

whhhyyyyyy

amongus

[old loom]

y=x^2
if x is 1, x^2 is 1. y is equal to 1
if x is 2, x^2 is 4. y is equal to 4.
xy is x times y. x times y when its x=1 is 1.1 meaning 1. at x=2 its 4.2 meaning 8.
Δ(xy) means the change of state of xy in state 1 to 2. it changes from 1 to 8 meaning the change is +7.
I dont think i can explain anymore clearly

[proven peak]

so you just got that through graphing and process of elimination?

[old loom]

yes? And if you understand the question you can just solve it without using your pen.

i guess it was unclear since you didint know what they meant by delta

[proven peak]

we're not even supposed to use graphing calculators during test

supposed to

2^2 - 1^2 = 3 !=7

what

okay

this question

[old loom]

ok i'll edit

[proven peak]

does not matter

.close

[lone heart]

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[native temple]

(Not cheating today I have a review before my exam) Here are some elastic collisions formula how was this derived?

[wind cloak]

Probably conservation of momentum and the coefficient of elasticity equation

[lone heart]

@native temple Has your question been resolved?

[lone heart]

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[native temple]

What is that coefficient of elasticity equation?

[wind cloak]

$e = |\frac{v'_2 - v'_1}{v_2 - v_1}|$

[ocean seal]

NEONPerseus

[wind cloak]

For elastic collisions, the coefficient of elasticity (e) is 1

[native temple]

Huh

[wind cloak]

v' is the final velocity and v is the initial velocity

Often crisped down to "velocity of seperation over the velocity of approach"

[native temple]

What is the elasticity equation?

[wind cloak]

Well this is that equation

[native temple]

Oh

Hmm physics must take studying all day

Making equations sounds hard!

[wind cloak]

:P depends on you really

[wind cloak]

Well yeah I tend to think it's better that you learn where such equations come from and derive them yourself, a lot better than mindlessly remembering bogus that doesn't seem to have any intuition

[lone heart]

@native temple Has your question been resolved?

[lone heart]

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[modern lichen]

Hi help me with these 3 problems

[night zodiac]

!status

[lone heart]

What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above

[modern lichen]

1. I don't know where to begin

[night zodiac]

oh these are some pretty funny questions~

it might help you to draw these out first

for number 1 draw out a square

then a pentagon

then a hexagon etc etc

until you get to an infinite amount of sides

what will it look like?

number 2 is pretty simple just calculate the steps one by one

1/2+1/4
1/2+1/4+1/8
(see where the limit of that takes you)

number 3 is just a basic geometry thing

[modern lichen]

I didn't understood that one

[night zodiac]

if you keep adding more and more sides to a shape

what will it end up looking like

[modern lichen]

Cause it's said this...

but what is this

[night zodiac]

don worry about it

[modern lichen]

or what is in relation with the adding of sqaure lmao

[night zodiac]

apothem is the distance from the center of the shape to the side

[modern lichen]

oh

[night zodiac]

you can just google define apothem to figure it out

same goes for any mathy term

[modern lichen]

third one how do I calcultate it by step

[night zodiac]

heres what i mean by the way

[modern lichen]

first exercise?

[night zodiac]

yeah

since its just adding more and more sides to a shape

what will the end result of the final shape look like?

[modern lichen]

ohhhhh

kind of what I understood

[night zodiac]

right

exercise 3 is just a half circle attached to a triangle

the proof is trivial and like trying drawing on it it helps

[modern lichen]

so I drew like the sequence of the first one but but you said that it give a figure

[night zodiac]

yeah

at the end of the sequence

when you have a shape with infinite sides, what does it look like?

[modern lichen]

So could you give me the answer

or mods can't give the answer

[night zodiac]

eeeh basically

it goes against the spirit of math

besides even if i did give you the answer you'd get like 1/4 points

since it would just look like

1. True
2. False
3. A number

and this doesnt look like a multiple choice

also also you wont be able to do the questions in the future so itd be pointless eitherway

[modern lichen]

why the true is true

it thought it was true

[night zodiac]

why do you think its true

[modern lichen]

don't know

If I calculate the triangle first the what should i do after

on question 3

[night zodiac]

wel youre finding the outer lengths, so you nd need to find the height and the base length so you could use the pythagorean theorem on it

then after tha tyou just calculate the perimeter of a half circle

[modern lichen]

yeah it gave me 325

the hipotenuse

[modern lichen]

then what I should do or what equation should i use

[night zodiac]

the perimeter of a half circle is

half of the perimeter of a full circle

[modern lichen]

ok and what's the value?

or the number

what should I divide 325/?

Can I call you or mods can't answer calls?

[night zodiac]

honestly

im not sure where you got 325 as the hypothenuse from

well i thinkj i do

did you 15^2+10^2

[modern lichen]

yeah

[night zodiac]

im not a mod and even if you did call me i would reject it sksksks

[modern lichen]

oh ok ok

[modern lichen]

So I made that sum

[night zodiac]

if you use 10 and 15 directly youd be caclulacting the hypothenuse of this triangle

[modern lichen]

yeah that's what I basically do

but I asked you on which step do I start

and if what I did it's right

[night zodiac]

alright so basically what were gonna start with is

i need you to find the length of the two blue lines

keep in mind that 10 u is exactly the diameter of the half circle

[modern lichen]

ok

so then what should I calculate?

[night zodiac]

the length of the blue lines

tell me what they are and we can continue

[modern lichen]

the lenght

but what's the lenght value?

I would say 10 by eye

[night zodiac]

that iiis what im asking you

all the information is in the question

[modern lichen]

Ok so one of my classmates sent me this pic

that should be the process but not sure tho

where tf does the perimeter formula does come from

I mean it's obviously 2 times pi times radius

[night zodiac]

well your classmate is compltely right

[modern lichen]

but where tf does that perimeter answer comes from LMAO

[modern lichen]

yeah I know it already told me

[night zodiac]

theres only half of a circle

therefore the perimeter is just half of a normal circle's perimeter

[modern lichen]

where does the 5u comes from?

[night zodiac]

the radius of the half circle

[night zodiac]

see your friend also drew in the helping lines

[modern lichen]

so the radius it's from the diameter right?

the diameter it's 10?

[night zodiac]

yes

correct

and the radius is?

[modern lichen]

well 5

Now could you explain me why P = 5u * (pi + 2)

[night zodiac]

well to my awareness it should only be 5u*pi

since there snothing tha should add the pi with anything there

[modern lichen]

yeah

[night zodiac]

more or less

(my bad for sounding certain her ei didnt review his whole paper)

[modern lichen]

so the +2 is not necessary?

[modern lichen]

ok

[night zodiac]

yes

[modern lichen]

Now the solution is the most accurate for you?

or how would you have solved the whole process?

oh and if in question 1 could you give like a little synthesis which provides its true

[night zodiac]

as far as im skimming this part is fine

so you just add them together

[modern lichen]

huh?

so the other part is kinda of rare?

[night zodiac]

the perimeter of the tringle and the preimeter of the half circle

[night zodiac]

the perimeter of the half circle is not 25

its 5*pi

[modern lichen]

but it's wrong?

or it could be as that

in which part are you saying especifically

oh nvm

so could you give me the synthesis of question 1

pls

@night zodiac

[night zodiac]

truth be told i don tknow what a synthesis is

so ill just tell you that a side with infinite sides is a circle

[modern lichen]

a brief explanation or outline why its true the answer

[modern lichen]

ok for what question?

[night zodiac]

^oh then this is the synthesis sksksksk

of

number 1?

[modern lichen]

yay

[night zodiac]

its the only one that deals with shapes

[modern lichen]

so this is the synthesis or what could you add?

[night zodiac]

i mean

its basically all you need to udnerstand it right

when you keep adding more and more sides to a shape

[modern lichen]

so that's the answer

[night zodiac]

its going to look more and more like a circle

[modern lichen]

So it would be like "true, because it's a side with infinite sides is a circle"

and that's it?

cause that wouldn't prove anything for the teacher

just saying

[night zodiac]

it wouldnt

im not gonna spit out the whole answer but thats the essence of the conclusion

[modern lichen]

ok...

[night zodiac]

when you add more sides to a shape, you add more points to which the distance from said point to the center is n

[modern lichen]

oh ok ok

[modern lichen]

so that would basically a simple outline for that right?

[night zodiac]

its

one of the ways you could prove it

[modern lichen]

ok ok

I understood

[night zodiac]

i think newton has a proof of it to when he was reducing shapes of n sides to find pi

[modern lichen]

yeah I heard it when I was in elementary or something like that

So for me it has been already resolved

Can I add you as a friend?

[night zodiac]

i mean

sure i guess

[modern lichen]

ok

[lone heart]

@modern lichen Has your question been resolved?

[lone heart]

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[green notch]

@night sail

[lone heart]

Please don't occupy multiple help channels.

[green notch]

here you go

[night sail]

AHHH THANKS MAN

[green notch]

.closed

[night sail]

APPRICIATE IT

[green notch]

.close

[lone heart]

Channel closed

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[green notch]

you type your question here

[night sail]

how do i solve physics/maths without memorizing fourmulas (is there as way to do so?)

P.S Im in last year of high school

.reopen

.reopen

.close

[night zodiac]

understand the coremechanics that make the formulas work

[lone heart]

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[alpine sable]

Can anyone uelp me with this question

I dont get how the answer is 16

[long axle]

100*frequency = 16

Look

[lone heart]

@alpine sable Has your question been resolved?

[alpine sable]

Oh thx , I misunderstood I thought we each bar was like 0.025, anyways thanks for answering!

.close

[lone heart]

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[jaunty sedge]

Hi, can someone pls explain why $\frac{1+\sqrt{5}}{-2}$ is the answer and not $\frac{4\sqrt{5}}{-4}$ which would equal to $\sqrt{5}$

[ocean seal]

Lushes

[fallen verge]

2 and 2$\sqrt5$ are like apples and oranges, they cannot combine together

[ocean seal]

GarlicBredFries

[modern sedge]

It would be $\frac{4\sqrt{5}}{-4}$ if it was $\frac{2\cdot2\sqrt{5}}{-4}$

I gotta learn latex

[ocean seal]

MathIsAlwaysRight

[jaunty sedge]

I see my error in understanding. Thank you @fallen verge & @modern sedge

.close

[lone heart]

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[modern sedge]

$\frac{2+2\sqrt{5}}{-4}=-\frac{2\left(1+\sqrt{5}\right)}{2\cdot2}=-\frac{1+\sqrt{5}}{2}$

[ocean seal]

MathIsAlwaysRight

[modern sedge]

whoops sorry, didnt notice it's closed

[lone heart]

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[quaint crown]

Help me please

[random token]

what have you tried

and where are you stuck

[quaint crown]

I tried a lot aff

But i dont find the result

[random token]

well, show your reasoning

show some work that you did

[random token]

,rotate

[random token]

what for did you this separation?

[quaint crown]

Please can you write the result in the paper and send me

[random token]

No, I can't. We are not giving results. We can give some help.

[quaint crown]

Give me the help

[random token]

?

[quaint crown]

Now you don't give me the help you give me just a lot of question

[random token]

and are you sure that the limit actually exists?

[quaint crown]

No

[random token]

Do you have any intuition on that limit?

like informal reasoning whether it exists or not

[cursive cypress]

Yo can someone help me with my piss easy maths hw 🙏🙏

[quaint crown]

I dont now

But yes

[random token]

This channel is busy. Go to other channel.

[random token]

yes, that is, it exists?

[quaint crown]

So ?

[random token]

,w plot x+1 and (ln(x+1))^2

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Commander Vimes#4407

[random token]

bad scale

nvm then

ok, so look

the point you should use is that x+1 grows much faster than ln(x+1)

and in fact you should also notice that it grows much faster than (ln(x+1))^2

[quaint crown]

How

[random token]

you can notice it from the graph

[quaint crown]

I can't

[random token]

well, take desmos and plot them

[quaint crown]

It s ln(x+1)^2

Not log

[random token]

I know that.

[random token]

this is exactly what i wrote here

alright

so once you get graphical intuition, i will do step back

do you know definition of limit?

[quaint crown]

You knowa what i dont need your help

.close

[lone heart]

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[tired fox]

I am in the process of deriving the Fourier transform. The lecturer states that this integral 'integrates xi out', leaving a function of just omega. I don't get the concept of this: is the integral not going to yield a function g(omega,xi)?

[tacit arch]

$\xi$ is "integrated out"

[ocean seal]

riemann

[tacit arch]

just like $\int_0^1 x^2 dx = \frac{1}{3}$ the $x$ is integrated out

[ocean seal]

riemann

[tacit arch]

in any definite integral, $\int_a^b f(x) dx, x$ is called a "dummy variable" because it would be the same for any variable name $y, z, w, \xi, \alpha$ if you replaced $x$ with any of those

[ocean seal]

riemann

[tired fox]

Right, I'm with you. So the integral is still definite even with the bounds of infinity

[tacit arch]

it's still true for improper integrals, but yea you get the idea

[tired fox]

cool, thank you

[lone heart]

@tired fox Has your question been resolved?

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[lone heart]

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[next wagon]

i need some help

[next wagon]

passing the 1 to the left, it gives x-4 / x+1 =< 0

the answer is (-1, 4]

why is the -1 open?

if it is =<, it has to be closed

[modern sedge]

Because if x=-1, the expression would be something/0

division by 0 is forbidden

[echo socket]

Because x + 1 = 0 when x = -1

[next wagon]

ohh sure

i didn't see it

thank you

.close

[lone heart]

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[rose sable]

Which step am I doing wrong?

It is meant to be x^2-16x+52 but I keep getting x^2-4x+52

solved it

.close

[lone heart]

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[wind thistle]

I'm a bit new to Combinatorial Proofs and I'm not sure how to start this question.

I only need to be able to answer part a.

[lone heart]

@wind thistle Has your question been resolved?

[alpine sable]

I think the answer of a) is simpler than you expect. Can you work out the answer for a simple case, say you have x=2 fezzes and y=3 ties by drawing a tree?

[wind thistle]

It should be 6, right?

[alpine sable]

right

and in the general case?

[wind thistle]

For each fez, there are 3 tie choices?

Yes

In general then, it would be xy?

[alpine sable]

Correct

[wind thistle]

That is simple

Well thank you!

[alpine sable]

The surprising bit is that the more complicated formula in b yields the same result

By the way: exercise c tells you that x * y is correct.

[wind thistle]

Yeah :/

Just realized that

I just couldn't wrap my head around why 💀

Alright, I'm gonna close this, thank you for your help

.close

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[solemn barn]

Whats the easiest way I can tell which one of these graphs is larger, im sure its simple i just dont understand when g(x) is bouncing below and above f(x)

[solemn barn]

I am told f(x) converges and by the comparison theorem I assume that g(x) will converge because I believe its smaller but jsut want to confirm

[jagged cobalt]

wdym specifically by 'larger'

[solemn barn]

I dont have the actual f(x) and g(x) functions

If I did I could tell that 1/x^2 is smaller than 1/x because the denominator is growing faster

therefore I would know I could use comparison theorem

If that answers your question

So I guess my question is how can I confirm just by looking at the two graphs is how I can create an inequality between the two functions

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@solemn barn Has your question been resolved?

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[white swallow]

hi

[white swallow]

how do you solve this

[vapid shuttle]

what are you trying to solve?

[white swallow]

5 (1) + 2 (3) = 11
and
9 (1) - 2 (3) = 3

im trying to understand how to get 11 and 3

😭

[vapid shuttle]

okay well lets do 1 at a time

5(1)+2(3)

that is 5 times 1

plus 2 times 3

do you see how that is equal to 11?

[white swallow]

Ah

Ohhhh

[vapid shuttle]

and same thing for the other one

[white swallow]

5 + 6

Yeah yeah

[vapid shuttle]

it is giving you an equation involving x's and y's, and then giving you a point (x,y)

and basically what you do with the point

is plug in whatever x is

into the x's

and plug in whatever y is

into the y's

so the point was (1,3)

x=1

y=3

and you plug them into the x and the y

[white swallow]

can you give me

one example

I need to practice rq

😭

[vapid shuttle]

sure

[white swallow]

Okie

[vapid shuttle]

2x+7y=81

(9, 9)

try that

[white swallow]

2x+7y=81 (9,9)

2 (9) + 7 (9) = 81

81 = 81

[vapid shuttle]

yes

the thing is, you aren't really solving for anything with these questions

they are giving you an equation of a line

and a point on the line

so of course when you put the point into the line

you will find out

it is indeed on the lne

[white swallow]

Oh but why is there

[vapid shuttle]

what is 2 times 3?

[white swallow]

6

[vapid shuttle]

okay

what is 9-6

[white swallow]

3

sorry my internet disappeared

[vapid shuttle]

so then 3=3

[white swallow]

Nvm

I got in the part where theres lines

😭

how do you do this?

🥲🥲

[sly orchid]

2x + 3y =24 ?

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[pseudo ice]

Shouldn't the bottom one be sin(2theta)?

[wise ember]

oh, yeah

[pseudo ice]

,w int 1/(t^3 sqrt(t^2 - 1)), t from sqrt(2) to 2

[ocean seal]

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[wise ember]

yeah, sorry, it lacked the -1/4 in the answer

[pseudo ice]

Should be pi/4 as well no?

[wise ember]

oh, yeah

[pseudo ice]

Think that should be it from there?

[wise ember]

yeah, it was a little mistake

thank you 😄

.close

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[blissful silo]

not sure if this is a math related question, but kind of stuck on this matlab code

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[limber oasis]

I am in advance math because I am In 7th grade and have a test tomorrow was wondering if i can get help on it

[lofty heart]

Think you’re meant to start your own ticket

[limber oasis]

huh

[lofty heart]

#❓how-to-get-help

[lone heart]

@bleak lily Has your question been resolved?

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@bleak lily Has your question been resolved?

[bleak lily]

.close

[lone heart]

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[elfin depot]

is (3, 2) and <3, 2> equivalent representations of a vector?

[raven haven]

sure

[elfin depot]

Why is that?