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1 messages · Page 128 of 1

cold zenith
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Un is the nth term

vale wigeon
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yeah, sure, but calling this "The Formula For All Sequences Ever™️" is... very sketchy

cold zenith
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yeah i understand i just called it the formula for sequences cos its the only formula i was given for arithmetic sequences

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i got 9 using that formula

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i agree the question is badly worded it threw me off

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patent night
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how do i find the length of PR?

lone heartBOT
patent night
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what is the process of it?\

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like process of finding it

delicate jacinth
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Pr = 2tu?

patent night
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so PR = tu 2 times?

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so PR would be 20?

delicate jacinth
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Yes, look at the image

patent night
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okay thank you

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that helps aton

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jaunty pollen
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How do I answer question e and f?

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If you like I can send what I done for question a to diii

hollow sparrow
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and send also the questions

jaunty pollen
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but I'll give you the answers

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as well

wind cloak
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Uh is this a test

jaunty pollen
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nono just a set of questions in answering

wind cloak
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Fair, no test paper would have a credit on it

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Huge question devastation

jaunty pollen
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so here's A

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hold on could I get the others later because I done them on my personal computer

alpine sable
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hi all i need help for assiments anyone can help ?

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maiden sphinx
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maiden sphinx
#

<@&286206848099549185>

alpine sable
#

!15m

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empty juniper
# maiden sphinx Q16

U probably should send a clearer pic of the diagram itself, can’t see a small portion of it

lone heartBOT
#

@maiden sphinx Has your question been resolved?

empty juniper
#

Ok so b4 we do anything we establish this,
Both triangles are isosceles
ADB = 90 = BDC and B bisects a 90 degree angle in half = 45 degrees for each triangle thus both are a 90-45-45 triangle since all angles of a triangle must add up to 180 degrees
Triangle ABC is EQUAL (similar in angles and also magnitude) to triangle BDC because of angle-side-angle similarity
BD is same for both triangles
angles ADB = BDC
angles ABD = DBC (B bisects the angle in equal halves)
Now since we have ASA similarity, both triangles are established to be same in dimensions and angles
Now we solve the problems

  1. Let us also assume that the side BD is some constant k since it is unnamed
    x^2 = pz is simplified as
    X^2 = p^2 + pq ( since z = p + q)
    Here, p= q since both triangles are similar in size and p = k since it is an isosceles triangle
    Therefore x^2 = p^2 + k^2 is proven by Pythagorean theorem and so the given equation is proved
  2. by Pythagorean theorem
    Y^2 = k^2 + q^2
    Or Y = zq in the same way that we proved the last question, we just go in reverse
  3. x^2 + y^2 = pz + qz
    We get x^2 + y^2 = z(p+q)
    Where p + q is geometrically equal to z so x^2 + y^2 = z^2 and Pythagorean theorem is proven
#

@maiden sphinx sorry for the late response it took a second to type it out lol

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maiden sphinx
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vale tiger
#

Can someone help me answer these, I'm being skeptical but I think the first one is -2.

graceful sparrow
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so what u do here

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is u multiply -5 with the equation in the LHS

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and -2 with the equation in the RHS

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after that, u separate the variables and the constants

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u take the variables to the left and the constants to the right

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and if the variable has a coefficient, u divide both sides

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this is how u do the first problem

gray isle
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Can someone help me answer these, I'm being skeptical but I think the first one is -2.
show your work that lead to that answer

graceful sparrow
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i assume once u get the hang of it, u can do the rest

vale tiger
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.close

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earnest laurel
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.open

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g(x+h)=(x-7)/(x+2), doesnt state a value for h

gray isle
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post the original question

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that feels butchered

earnest laurel
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it changed since i tried infinity and that was wrong

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but same idea

worn fox
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Everytime you see x, replace it with x+h

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south maple
#

<@&286206848099549185>

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last ether
#

!15m

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Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

ocean sealBOT
#

Royal_love

spare plaza
south maple
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Not sure

spare plaza
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Yup

south maple
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Do you know how to do it?

south maple
spare plaza
south maple
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Even I don't get it 😭

lone heartBOT
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@south maple Has your question been resolved?

nimble fern
south maple
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Yes please

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@nimble fern

nimble fern
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okay

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so to have closure w.r.t. to reflexive property means, add more items to the relation R so that it becomes reflexive

south maple
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Wrt?

nimble fern
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do you recall the reflexive prop. for relations?

nimble fern
south maple
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Soo the answer is?

nimble fern
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no answer giving.

south maple
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2,2 and 3,3

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Okay

nimble fern
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good

nimble fern
south maple
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Alright thanks 🙏

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If I need help can I dm u??

nimble fern
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nope

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just post it in this server lol

south maple
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Alright

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Thx

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@south maple Has your question been resolved?

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hollow lark
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hi can anyone help with this?

lone heartBOT
royal plank
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alas, I assume you have the formula for the geometric bodies

hollow lark
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I have the formula A=2πrh+2πr^2

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and I tried to set 2πrh = 1000/r

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but got lost

pseudo ice
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Well first off, note that they give you a statement about the volume

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,w millilitre volume

pseudo ice
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Find an expression for the volume and then set that equal to what they tell you it is

hollow lark
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thank you thats what i was forgetting about

pseudo ice
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That'll allow you to get the height h in terms of r

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Thought so, I can't seem to remember the volumes myself tbh KEK

hollow lark
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I always forget lol

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thank you

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brazen berry
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Can anyone verify my answer/work?

lone heartBOT
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Please don't occupy multiple help channels.

brazen berry
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im trying to get rid of my other one pain_peko

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ok done

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if anyone is able to verify, i'd appreciate it

merry depot
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cos(pi*b) does not go to infinity

brazen berry
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heck

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what does it go to? D:

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pi *infinity

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just infinity

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is cos infinity something else?

merry depot
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nothing. cos(x) is bounded between -1 and 1 and is periodic between those two values

brazen berry
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oh

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trig was my worst unit in precalc

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so what would i even answer that with

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since cos infinity doesnt exist

gritty talon
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@brazen berry You could use a sequence

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2 actually

brazen berry
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how so?

gritty talon
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If the integral were convergent, that means the limit of whatever sequence you take of that integral converges to the same number

brazen berry
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this one is divergent, no?

gritty talon
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Yes

brazen berry
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since cos infinity doesnt exist

gritty talon
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No

brazen berry
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oh

gritty talon
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You can't really tell like that AFAIK

brazen berry
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I havent learned about sequences in this context, i dont think

gritty talon
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There is a sequential characterization of limits

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lim when x->a of f(x)=l means that for all sequences xn such that xn goes to a when n goes to infinity, f(xn) goes to l when n goes to infinity

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Sorry still haven't learned Late

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Latex*

brazen berry
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np np

gritty talon
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Choose xn= n

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And make the integral go from 0 to xn

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and take the limit

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You get (-1)^2 -1

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which is already divergent

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well, it comes back to the same thing I guess

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(-1)^n I meant

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You can then choose another sequence xn= n+ 1/2, and you get 0if I'm not mistaken

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That clearly shows that it diverges

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I hope I didn't complicate matters even more 😅

brazen berry
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i uhhhh

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😅

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you might have, but only because I havent seen that stuff before

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Idk if im allowed to use that in my solution

gritty talon
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I think what you found is actually enough

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Yeah it's basically the same

brazen berry
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ok ok ty

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.close

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cursive nebula
lone heartBOT
cursive nebula
#

all of them except the last are the same right

cursive nebula
#

alright sweet

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old mica
lone heartBOT
frigid stream
#

@old mica Hello, what did you try?

old mica
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I assumed that the means are both zero but cannot think of a proof, For the Vars I got the following:

frigid stream
old mica
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Yes

frigid stream
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For the mean of X, you know that epsilon_1 and epsilon_2 are independent, so what can you do with E(X) ?

old mica
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Hmm

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I am completely new to this stuff sorry

frigid stream
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What is the expectation of the product of two independent random variables?

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No problem

old mica
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The means multiplied?

frigid stream
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Yes

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This is your proof for E(X) = 1

old mica
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0 no?

frigid stream
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Sorry, yes

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E(X) = 0

old mica
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Gotcha

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I guess I find the idea of expectation confusing

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Like for the means I thought of it as multiplying two distributions by eachother then calculating the mean again

frigid stream
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Multiplying two distributions does not really make sense here

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You aren't given any distribution here anyway

old mica
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Understood

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So E(XY)=E(X)*E(Y)

frigid stream
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No, watch out, do not confuse X,Y and epsilon_1, epsilon_2

old mica
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Oh yes, i just meant as in the formula sorry

frigid stream
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If X and Y are independent, yes

old mica
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Is my answer for variance correct?

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answers*

frigid stream
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yes

old mica
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Do you know how to get the covariance?

frigid stream
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You have Cov(X,Y) = E(XY) - E(X)E(Y)

old mica
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Yes

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From this?

frigid stream
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Yes

old mica
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Could you explain what the top line means?

frigid stream
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There is nothing to explain as it is the definition of the covariance

old mica
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I understand the formula as this

frigid stream
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This is for a given sample

old mica
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I see

frigid stream
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A positive covariance tells you for example that if X tends to get bigger, then Y should tend to get bigger too
The opposite for a negative covariance

old mica
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Understood

frigid stream
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Back to the problem you already know what are E(X) and E(Y), so you only have to compute E(XY) in order to have the covariance

old mica
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I see, is that again just E(X) and E(Y) multiplied?

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Same as epsilon for X

frigid stream
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Are X and Y independent?

old mica
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Oh, no I assume, as they both use epsilon2

frigid stream
#

You have a good intuition, X and Y are probably not independent

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Sometimes, random variables can depend of the same one (here, epsilon_2), but are still going to be independent, surprisingly

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But the key point here is you can never assume independence if you aren't being told

old mica
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Understood

frigid stream
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So unfortunately you cannot write E(XY) = E(X)E(Y), so we have to find another way

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Your best shot is to replace X and Y by their given definition

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Then maybe you can use independence 😉

old mica
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I anticipated that haha

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Gotcha

frigid stream
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Good, so give it a try

old mica
#

Below that message*

frigid stream
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Yes

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90% of the time the best way to compute a covariance is using the formula Cov(X,Y) = E(XY) - E(X)E(Y)

old mica
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working out now

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Is it just the epsilons subbed in, so zero?

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E(ep1ep2^2)-E(ep1ep2)E(ep2)

frigid stream
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E(ep1ep2) and E(ep2) are known as you already calculated the expectation of X and Y

old mica
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And the two eps can be split given they are independent

old mica
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so E(ep1ep2^2)-0*0

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E(ep1)E(ep2)^2-00

frigid stream
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Wait

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$E(\epsilon_1 \epsilon_2^2) \neq E(\epsilon_1) (E(\epsilon_2))^2$

ocean sealBOT
#

Fέliχ

old mica
#

Hmm

frigid stream
#

You rather have \
$E(\epsilon_1 \epsilon_2^2) = E(\epsilon_1)E(\epsilon_2^2)$

ocean sealBOT
#

Fέliχ

frigid stream
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By independence

old mica
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Is the expectation of the distribution squared different to the squared expectation of the distribution then?

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or random variable

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rather than distribution

frigid stream
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It is different

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E(X^2) is the mean of the random value X^2

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(E(X))^2 is the mean of the random value X, but squared

old mica
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Oh I understand

frigid stream
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So it remains to compute $E(\epsilon_2^2)$

ocean sealBOT
#

Fέliχ

old mica
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so E(ep1)E(ep2^2)-0*0

frigid stream
#

But hold on. E(epsilon_1) is 0

old mica
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so we know it is 0 whatever

frigid stream
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So you actually do not care about E(epsilon_2^2)

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Yes

old mica
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but can we find epsilon 2^2 anyway?

frigid stream
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Yes, we could

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Using the formula $E(X^2) = \mathrm{Var}(X) + (E(X))^2$

ocean sealBOT
#

Fέliχ

old mica
#

Could you explain this formula?

frigid stream
#

It is just the variance formula written differently:

Var(X) = E(X^2) - (E(X))^2

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You used it above in your first screenshot

old mica
#

I see

old mica
frigid stream
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Yes

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You used it twice

old mica
#

I see, so the answer is zero

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then for the correlation u just use the formula

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0/(1^0.5*1^0.5)

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=0

frigid stream
#

Yes

old mica
#

Then as covariance=0

frigid stream
#

Exactly

old mica
#

They are in fact independent

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So the result of the question is 'despite X and Y involving epsilon2, due to the means being zero they remain independent'

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?

frigid stream
#

⚠️

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If Cov(X,Y) =/= 0, then X and Y are not independent

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But if Cov(X,Y) = 0, you cannot conclude anything

old mica
#

So how do i conclude whether they are independent or not?

frigid stream
#

you cannot

#

You do not have sufficient information to tell anything about it here

old mica
#

Understood, what information would i need to conclude that?

#

Would I need to conclude that epsilon2 has no effect essentially?

#

I can review this later maybe

#

Could I do one further question?

lone heartBOT
#

@old mica Has your question been resolved?

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tribal monolith
lone heartBOT
tribal monolith
#

i'm a little confused on how to find f(x)?

near garden
#

riemann sum is basically taking chunks of the integral and evaluating the integral as parts to estimate it

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and the parts have the pattern of sqrt(8+(6n/n))*(6/n)

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so the function would just be this

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but be careful that its the RIGHT riemann sum

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so the f(5) was taken as 6/n in the sqrt

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and the 6n/n, which in this case is upper n = 1 was from the f(6) since we're taking the floor of the integral part

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so itd be like sqrt(8+(6(n-5)/n))*(6/n)

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im not sure about the usage of the n's in the summation formula tho

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@tribal monolith

tribal monolith
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i thought n is the number of partitions of the riemann sum

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?

near garden
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probably

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oh wait its x-5 mb

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or just n-5

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inside

tribal monolith
#

inside? what do you mean

near garden
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just sqrt(8+(6(n-5)/n))*(6/n)

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dw about that

tribal monolith
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wait but it's a function of x why is it just n

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wait

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ohhhh

near garden
#

or just replace all the n's with x's

ocean sealBOT
#

Mehdi_Moulati

tribal monolith
hollow sparrow
#

,align
\sqrt{8 + \frac{6}{n}} * \frac{6}{n} + \cdots + \sqrt{8 + \frac{6n}{n}} *\frac{6}{n}
&= \sum_{k=1}^n \frac{6}{n} * \sqrt{8 + \frac{6k}{n}}\
&= \sum_{k=1}^n \frac{11-5}{n} * \sqrt{3 + 5 + \frac{(11 - 5)k}{n}}\
&= \sum_{k=1}^n \frac{11-5}{n} * \sqrt{3 + \qty(5 + \frac{(11 - 5)k}{n})}

ocean sealBOT
#

Mehdi_Moulati

#

Mehdi_Moulati

tribal monolith
#

ohhhhhhhhhh

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i get it now

#

wow ok

#

thank you

hollow sparrow
lone heartBOT
#

@tribal monolith Has your question been resolved?

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zealous oxide
#

I need help with 5 and 6.

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Please don't occupy multiple help channels.

tacit arch
#

.close

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cloud kiln
#

Im trying to disprove that the seq 1/n converges to 1
so anyways I did

cloud kiln
#

|1/n - 1| < eps

#

then

#

|1/n| - |1| < eps

#

but since both terms are positive

#

1/n - 1 < eps

#

1/n < eps + 1

#

1/(eps + 1) < n
but here I got a stage for n

tacit arch
#

wrong approach

cloud kiln
#

hm

#

Im just applying the definition of sequence

cloud kiln
tacit arch
#

figure out the correct contrapositive first

cloud kiln
tacit arch
#

Yea that's not correct

#

negate this:

#

$a_n \to a$ if $\forall \eps > 0, \exists N \in \N s.t. |a_n - a| < \eps, \forall n > N$

ocean sealBOT
#

riemann

cloud kiln
tacit arch
#

oof

cloud kiln
#

😭

tacit arch
#

the very first part of the negation after saying a_n does not converge to a is

#

$\exists \eps > 0$

ocean sealBOT
#

riemann

cloud kiln
#

yes

#

so an would not converge if there does not exist an eps > 0 such that.... right?

tacit arch
cloud kiln
tacit arch
#

for all N, yes

#

alternatively, you can just show 1/n converges to 0 and probably quote some theorem about uniqueness of limits and say that 0 is not equal to 1 and you're done

cloud kiln
#

hm alright

#

but I did the mathematical part correct right? Why did that guy sully triangular inequality part

tacit arch
#

1 < 2 and 1 < 3 does not imply 3 < 2

cloud kiln
#

oh u are correct

tacit arch
cloud kiln
#

yes I used |x-y| >= |x| - |y|

tacit arch
#

you sully the best reverse inequality

cloud kiln
#

whats going on over here???

tacit arch
#
cloud kiln
#

|1/n| - |1| <= |1/n - 1| < eps
therefore
|1/n| - |1| < eps

tacit arch
#

oh no i deserve the sully now

cloud kiln
#

sully the guy who sullied triangular inequality

#

how do I close this thread

#

btw thx

tacit arch
#

.close

lone heartBOT
#
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meager pagoda
lone heartBOT
#

Please don't occupy multiple help channels.

meager pagoda
#

How do I set up 7

tacit arch
#

,rotate

ocean sealBOT
lone heartBOT
#

@meager pagoda Has your question been resolved?

merry depot
#

basically the same way you set up 6, but with a1 and a6 (or a12)

lone heartBOT
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brisk ore
#

i need help with geometry

lone heartBOT
brisk ore
#

i have a few questions to ask. 1. A triangle has side lengths of 12, 35, and 36. What kind of triangle is it. how would i solve this?

slim spire
brisk ore
#

okay, theres another one that im going to send a picture of that im going to need help understanding

#

how would i solve for x and w?

gray isle
#

right triangle trig

#

would be sufficient

#

(specifically the use of tan)

brisk ore
#

okay, could you walk me through it? im so confused on wtf im supposed to be doin in this clss💀

gray isle
#

how much trig have you learned?
have you started right triangle trig yet?

brisk ore
#

im in geometry not trig so idk why im doing this but this is what my teacher assigned

gray isle
#

if you haven't been taught any trig

#

(short for trigonometry)

brisk ore
#

im in geometry b right now

gray isle
#

go back to your teacher and go wtf

brisk ore
#

ik im so confused

gray isle
#

so you have no idea what sine,cos,tan are?

brisk ore
#

but it was due last week so if i dont finish the test today its considered an "absence"

#

i kinda do

#

ive been watching some videos on what they are and shi but i havent gotten too far into it

#

but this gotta be done tn so im trying to get as much help as possible

gray isle
#

an image of sohcahtoa
should be sufficient
assuming you're capable of basic algebra

brisk ore
#

let me look that up real quick

#

okay so with the image i posted up there^ would i use cosine?

#

for both or just for w or x?

#

what about this image

#

what type of sin should i use to solve this and how would i solve it?

lone heartBOT
#

@brisk ore Has your question been resolved?

brisk ore
#

no

lone heartBOT
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hybrid stirrup
#

The host of a party wants to order 3 salads, 4 hot dishes, and 2 desserts from a catering company. The company offers 7 different salads, 6 hot dishes, and 5 desserts. How many ways can the host of the party select which items to order?

hybrid stirrup
#

Should the answer be 7C3 * 6C4 * 5C2 ?

lone heartBOT
#

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hybrid stirrup
#

Let A and B be sets in U which satisfy n(A ∪ B) = 17, n(A) = 12, n(B) = 8, and
n(A′ ∪ B′) = 21. Calculate the size of the universe.

viral pagoda
#

Draw venn diag

#

Or use formula

wary stream
hybrid stirrup
#

.close

lone heartBOT
#
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lunar lintel
lone heartBOT
lunar lintel
#

could someone explain

#

hiow they got i-1/2

waxen flame
#

$(i - \frac{1}{2})\cdot \Delta x = i\Delta x - \frac{1}{2} \Delta x$

ocean sealBOT
#

Kookiemon

waxen flame
#

This gives you the midpoints.

lunar lintel
#

where did they get that

#

from

#

i was asking

#

it wasint in equation

waxen flame
#

Did you ever learn about sequences in Algebra?

#

That's just the formula for the sequence of the midpoints.

lunar lintel
waxen flame
#

Well, it's the sequence for the midpoints.

lunar lintel
#

for midpoint

#

left sum was

#

Xk-1

#

right sum = Xk

waxen flame
#

$x_{k-1} + x_{k} = x_{k-1} + \Delta x$

ocean sealBOT
#

Kookiemon

waxen flame
#

The former is used when the intervals are not all the same. The latter can be used when the intervals are equal.

#

eg.

#

Former -> {1,2, 5, 6, 7.5, 11, 12, 13}
Latter -> {1,2,3,4,5,6,7,8,9,10,11,12,13}

lunar lintel
#

used for when intervals are not same?

#

and i+1/2 is used for when they are same?

waxen flame
#

You can use the former regardless if the partitions are equal or not. The latter can only be used when the partitions are equal.

lunar lintel
# lunar lintel

so this would also be correct if they put this instead of i-1/2

waxen flame
#

Yes.

lone heartBOT
#

@lunar lintel Has your question been resolved?

lone heartBOT
#

@lunar lintel Has your question been resolved?

lone heartBOT
#
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wide oxide
lone heartBOT
wide oxide
#

I’m currently doing matices and I’m wondering how to do these type of questions.

#

Where I have to find values of said variable which satisfy the question for which values of the varaibale does this matrix have a inverse?

#

If you want you can help me through question 12

lone heartBOT
#

@wide oxide Has your question been resolved?

wide oxide
#

<@&286206848099549185>

#

<@&286206848099549185>

#

Ok I solved Q.12 can someone help me with 14 and 15

#

I absolutely have no clue where to start

#

<@&286206848099549185>

lone heartBOT
#

@wide oxide Has your question been resolved?

lone heartBOT
#

@wide oxide Has your question been resolved?

alpine sable
#

Think about the formula for A^-1

alpine sable
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alpine sable
lone heartBOT
alpine sable
#

its pretty simple geometry, but im really bad in it and just want to make sure

#

i missed school today and my teacher sent this

#

ill get to the point

#

how do i prove the top triangle =~ to the bottom one

#

i got 2 angles

#

idk why she didnt mark the middle

#

?

#

what

#

can you elaborate ?

hard patio
alpine sable
#

ASA no?

alpine sable
#

such as A , B , C, D , E

hard patio
alpine sable
#

yes

hard patio
#

I thought similar

alpine sable
#

oh, no

hard patio
alpine sable
#

can you say in words

#

i dont learn math in english

#

so i dont know angle something angle ?

alpine sable
#

or DS

hard patio
alpine sable
#

oh its called side

#

alright

#

so i get the two angles

#

lets add a letter for me to be more clear

#

how do i say DF = DB

hard patio
#

The diagonals of a parallelogram bisect each other

alpine sable
#

i need to know that F is the center of the square

#

?

hard patio
alpine sable
#

but you still dont know its a parallelogram

#

you only know that when you prove

hard patio
#

But I’m guessing that was a typo?

alpine sable
#

she just marked AB=DS because she proved its congruent

alpine sable
hard patio
#

Where’s S?

alpine sable
#

i feel like im missing something

alpine sable
hard patio
#

That’s isn’t C?

alpine sable
#

haha

#

no

#

Oh wait it is

#

my bad

#

i opened the book,

#

its given that DF=FB

#

that makes it more clear

hard patio
#

Yes

alpine sable
#

so you just do congruence and then you know its a

#

parallelogram

#

complicated names man

#

well

#

thanks for the help

hard patio
alpine sable
#

yes

#

in hebrew its a lot more simple

hard patio
hard patio
hard patio
alpine sable
alpine sable
#

rectangle is מלבן

#

a lot shorter

hard patio
#

Quadrilateral lol

alpine sable
#

tf

#

how people learn in this language

#

id never remember all these names

hard patio
alpine sable
#

lmao

#

in hebrew its just a five letter word, מרובע

hard patio
#

That’s cool 😎

alpine sable
#

yeah

#

who thought of making 10 letter words shapes

hard patio
alpine sable
#

thats so stupid honestly

hard patio
alpine sable
alpine sable
hard patio
#

No, you haven’t prov n that AD is parallel to BC

#

So it could be a parallelogram

alpine sable
#

well you could

#

and then you say its a parallelogram

#

Why not,

#

corresponding sides in congruent triangles

#

so AB=DC

#

Why not ?

#

Oh

#

its given

#

forgot to say that

#

i thought you meant equal

#

until i checked what parallel means in translator

hard patio
#

Also one more thing

alpine sable
#

yes?

hard patio
#

You assumed it was a parallelogram to prove that it is?

alpine sable
#

No

#

why do you think so?

hard patio
#

Cause we used the fact that the diagonals of a parallelogram bisect each other?

#

Unless that was already given

alpine sable
#

Oh no

#

we dont need that

hard patio
#

And you forget to mention

alpine sable
#

since the question gives you given stuff

#

AB parallel DC, DF=FB

hard patio
#

You didn’t even give us that:((

alpine sable
#

dude

#

i knowww

#

i opened the booko

#

and saw that

hard patio
#

XD

alpine sable
#

idk why my teacher didnt write that on the board

#

i felt like we were missing something

#

and we did

hard patio
alpine sable
#

so yes we can prove its a parallelogram

#

also another question, when a question gives you info, how do you call it in english?

#

why not ?

hard patio
#

Okay, It is a parallelogram

#

Cause the parallel sides are equal

#

@alpine sable

#

Do you get it?

lone heartBOT
#

@alpine sable Has your question been resolved?

lone heartBOT
#
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flint iron
#

@mental coyote

lone heartBOT
echo socket
#

Don't ping random people?

#

And what's your question

lone heartBOT
#

@flint iron Has your question been resolved?

flint iron
#

can i get help with geomitry

jaunty acorn
#

l.In a right triangle ABC with hypotenuse BC, the difference between the hypotenuse and the cathetus AB is equal to 9 cm. Knowing that the projection of AB onto the hypotenuse is 3.77 cm long, what's the area?

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#

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acoustic mirage
#

Can someone pls explain the first step ?

acoustic mirage
#

PS: i already know the tan(a+b) property

#

I still couldn't get this thing as the book says

gray isle
#

1 = (x+1) - x

#

tan(1) = tan( (x+1) - x )

acoustic mirage
gray isle
#

if you're referencing tan(a-b),
yeh

acoustic mirage
#

Thanks a lot

#

.close

lone heartBOT
#
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inner path
#

Hello, I have just started the matrices and I would like to know if you know of any books or links to understand and practise because I still don't really understand what it is

lone heartBOT
#

@inner path Has your question been resolved?

worn fox
#

3blue1brown youtube series "essence of linear algebra"

inner path
#

thanks i wiil look at that 🙂

#

.close

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tepid prism
#

can someone explain me the 1st step

lone heartBOT
sharp peak
#

identities.

tepid prism
#

Specially what happeened in the numerator

tribal oxide
sharp peak
#

both in the numerator and denominator

tepid prism
sharp peak
#

btw instead of asking people you can always go have a look at an integral calc on the internet

tepid prism
#

that seems to be a helpful tool

sharp peak
#

DONT OVER USE IT

lone heartBOT
#

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acoustic mirage
#

How did pi/6 come ?

lone heartBOT
acoustic mirage
#

Shouldn't pi/3 come instead ?

rich quiver
#

Cengage 🌚

acoustic mirage
kindred anchor
acoustic mirage
#

I am way too dumb for it tho 💀

acoustic mirage
rich quiver
acoustic mirage
#

12th

kindred anchor
#

,, \sin(A+B)=\sin(A)\cos(B)+\cos(A)\sin(B)

ocean sealBOT
acoustic mirage
#

Yes but shouldn't pi/3 come ?

kindred anchor
#

How much is pi/3 in degrees?

acoustic mirage
#

Sin pi/3 = root(3)/2

pulsar parcel
#

Please help with this problem for my 2D game development, pls, pls pls :)))

acoustic mirage
#

But it can be either cos or sin ?

acoustic mirage
#

So it can also fit in the formula of cos(a+b) ?

acoustic mirage
#

.close

lone heartBOT
#
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kindred anchor
#

What?

#

Did you even understand?

rich quiver
acoustic mirage
acoustic mirage
#

I am sleep deprived

#

2 continuous board practicals

#

Which grade are u in ??

lone heartBOT
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rocky cloak
#

If I use superscript squared on a vector variable is it clear I mean the elementwise product with itself?

remote tulip
#

How do I solve this. Also how do I backwards in the other two pictures. My teacher only gave us formulas and nothing else. So I am super confused.

Specially I’m really confused about what to do when the variable is in the denominator

Currently in AP Calculus in highschool

rocky cloak
#

I've claimed this channel please read the rules

remote tulip
#

Oh wait I see how you do the channel thing now

#

Sorry about that

pseudo ice
lone heartBOT
#

@rocky cloak Has your question been resolved?

rocky cloak
#

Just to post again

#

FargothUrIsOnline — Today at 2:59 PM
If I use superscript squared on a vector variable is it clear I mean the elementwise product with itself?

lone heartBOT
#

@rocky cloak Has your question been resolved?

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alpine sable
#

20+8(x-7)=100 Can someone explain?

lone heartBOT
quasi scarab
#

simplify the left side

alpine sable
long axle
#

Show ur simplification of the left side

lone heartBOT
#

@alpine sable Has your question been resolved?

quasi scarab
#

a* (b+c)= a* b +a* c

quasi scarab
alpine sable
quasi scarab
#

put the numbers on the right side

lone heartBOT
#

@alpine sable Has your question been resolved?

alpine sable
quasi scarab
lone heartBOT
#

@alpine sable Has your question been resolved?

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rocky night
#

"Students sit at their desks in three rows of eight. Felix, the class pet, must be passed to each student exactly once, starting with Alex in one corner and finishing with Bryn in the opposite corner. Each student can pass only to the immediate neighbour left, right, in front or behind. How many different paths can Felix take from Alex to Bryn?" from AMC 2022 Intermediate Q30

I've been struggling with this problem for quite a while. Unfortunately, I haven't been able to find an answer. I have tried a few common techniques such as back-tracking, starting with simple cases and looking for any recurrences but I've had no luck. I would appreciate if someone could provide an explanation for how one would solve the general case of an N by M grid under the same restrictions, thanks.

royal plank
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if you need more hints just ask, this is quite the annoying problem

rocky night
prime badge
royal plank
prime badge
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there's no solution, literally no reason to click, but it's the same question so that's neat

prime badge
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i counted the cases then

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for each way the top row looks like

lone heartBOT
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delicate yacht
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some help solving this equation?
i noted 2 ^ x = a and 3 ^ x = b
I got to an quadratic equation with these 2 values, from there im stuck

delicate yacht
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<@&286206848099549185>

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delicate jacinth
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wait 15 mins before you ping

delicate yacht
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Ok

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didnt know xd

delicate yacht
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actually a = 3 ^ x and b = 2^×

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got this by just bringing the left and right members to a common denominator and multiplicate diagonally

delicate jacinth
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$a^2(b+1)(b-1)-ba+b^2+1=0$?

ocean sealBOT
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sopinha

delicate yacht
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its -4ab

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-4ba*

delicate jacinth
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$a^2(b+1)(b-1)-4ba+b^2+1=0$

ocean sealBOT
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sopinha

delicate jacinth
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hm

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what is the context of this

delicate yacht
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idk, ive got delta = someting*something + 4, i ve broke down these somethings into 4's divisors, but it got me to ugly solutions which are not the right ones

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considering that the equation has solutions (delta >= 0)

lone heartBOT
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@delicate yacht Has your question been resolved?

alpine sable
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@lone heart

lone heartBOT
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@delicate yacht Has your question been resolved?

dawn sand
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Hi, I have a question regarding this
what i do not understand is why is the mans velocity (u_m) in the other direction
i know it says with respect to the boat (relative velocity)
im just asking someone to explain to me why the velocity vector of the man is in the other direction
the question states the man is walking 2km/hr in a direction to the right and perpendicular, so its vector is 2(cos45ax + sin45ay)... but relative to the boat it is 2(-cos45ax -sin45ay)
why is its vector like that relative to the boat

lone heartBOT
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uncut berry
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Which of the options shows the bisector of angle XYZ?

keen mason
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in what picture is the angle cut in half

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so both of the angles on either side are equal

uncut berry
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uuh b??

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my english isn't too good, i'm sorry

keen mason
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yea

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b is correct

uncut berry
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thank you

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brazen berry
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How is it getting (3t+1) i calculated it and got (3t-1)

brazen berry
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for the simplification

last ether
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A common factor is e^(-3t)

brazen berry
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yes

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but look

last ether
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I don't see anything wrong

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The left side fraction has to be multiplied by 3/3

brazen berry
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pulling out e^-3t would give e^3t(3t-1)

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OOOH

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gotta multiply right side by -1/1

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since its subtraction, not a negative

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.close

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ivory briar
lone heartBOT
ivory briar
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need help with 4 and 6

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i did synthetic division for the first two problems and got no remainder

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i did it for 4, 6 and i got a remainder

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what am i meant to do after

lone heartBOT
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@ivory briar Has your question been resolved?

ivory briar
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no one has even said anything

alpine sable
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if you got a remainder

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that means what ever you are dividing by is not a factor

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hallow moth
lone heartBOT
hallow moth
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Shouldn't the shaded area be 605/12?

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Integrating from 0 to 11 where my integrand is x - ((x^2)/44)

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Since y=11 is my upper limit and y=x is the "top" line

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integrating gives me ((x)^2/2) - (1/3)((x^3)/44)

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which simplifies to ((x)^2/2)-((x)^3/132)

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and when evaluated over 11 to 0, I get 605/12

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what am I doing wrong here?

modern crown
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Don't integrate from 0 to 11, integrate from 0 to 22, since the red curve starts at 0 and ends at 22.

hallow moth
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until x = 22?

modern crown
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This gives you the area below the red curve. Then, the area of the shaded region is (area of rectangle + triangle) - (area under red curve).

hallow moth
modern crown
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It's still $x^2/44$

ocean sealBOT
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DavidL1450

hallow moth
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I guess what I meant was, when I am setting up my integration, is it still S x - x^2/44

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which then becomes x^2/2 - x^3/132

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evaluated from 0 to 22?

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<@&286206848099549185>

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Should I consider integrating from 0 to 11 and then adding the results to integrating from 11 to 22 of 11x-x^3/132?

modern crown
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There is a way to do that, but it would require two integrations : $\int_0^{11} (x - x^2/44) dx + \int_{11}^{22} (11 - x^2/44) dx$.

ocean sealBOT
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DavidL1450

There is a way to do that, but it would require two integrations : $\int_0^{11} (x - x^2/44) dx  + \int_{11}^{22} (11 - x^2/44) dx$.
hallow moth
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What am I missing here? I originally got 605/12 but when I failed the question on MLM it told me the answer was 605/6

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not really seeing what im doing wrong

modern crown
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Right. what does that integral evaluate to? I get 605/6 as well.

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I see now. You only did the first part, where you integrated from 0 to 11. There is also a second part from 11 to 22.

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$\int_0^{11} (x - x^2/44) dx = 605/12$

hallow moth
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So I do need to integrate from 0 to 11, and then again from 11 to 22

ocean sealBOT
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DavidL1450

modern crown
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yes, do two integrations and add them.

hallow moth
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finally - thank you.

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appreciate it!

#

.close

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fair musk
lone heartBOT
fair musk
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If we take integral of the top (red) and bottom (blue), why do we subtract them, not add?

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To find the area that is within all 3*

waxen flame
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Because you want the length from the upper bound to the lower bound.

fair musk
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wont adding add it up

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or is it because the blue is negative

waxen flame
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No, because the lower bound is negative.

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eg. 5 - (-2) = 7

fair musk
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OHHH

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knotty veldt
lone heartBOT
sullen vector
knotty veldt
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Yo

sullen vector
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I need help on this

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I'm so confused

knotty veldt
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Stol my channel lmao

sullen vector
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Oh my bad

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I'm new to this

knotty veldt
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Its fine

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Help each other 🤝

lone heartBOT
knotty veldt
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Idk wtf ur question is tho

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Ok for my question: reviewing dif eq, solution was simple seperstion of variables, but i tried to work it out this way…v, is that a dead end? Also is there any intuition behind separation of variables besides it just makes the “integrals solvable”

waxen flame
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,rotate

ocean sealBOT
knotty veldt
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sry bout that

sullen vector
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Hey

lone heartBOT
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@knotty veldt Has your question been resolved?

lone heartBOT
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@knotty veldt Has your question been resolved?

lone heartBOT
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@knotty veldt Has your question been resolved?

knotty veldt
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.close

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timber basin
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Hi, could somebody please explain me why -80+10=-70 and not -90
I know it's probably really simple, I've no idea how I graduated and don't wanna be stupid

raven haven
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um

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-80+10 = -70

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not 90

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let's write it this way

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-80 + 10 = 10 - 80

timber basin
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Yeah my bad

raven haven
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-80 - 10 is -90

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because -80 - 10 is really just (-80) + (-10)

timber basin
raven haven
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well

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I'm showing you a different example

timber basin
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Please

raven haven
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80 + 10 = 90

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-80 - 10 = -90

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but -80 + 10 = -70

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the negative sign is attached to the number

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one way to think of it is whenever you see a negative

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say n - m

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you think of it as n + (-m)

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if I have negative 80 and I add 10, I should get negative 70

timber basin
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Ohh

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I get it now

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Thank you

#

.close

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trail cairn
#

At the football stadium, 35 000 people
attend a football match each week. What
is the order of magnitude of the number
of people who attend 8 weeks of games?

raven haven
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firstly, how many people attend 8 weeks of games?

trail cairn
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35,000

limpid turret
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That's how many people attend a game in one week

trail cairn
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do i times it

kindred anchor
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Yes

trail cairn
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so like 245000

kindred anchor
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Do you understand why?

trail cairn
kindred anchor
trail cairn
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i think i got the answer

kindred anchor
trail cairn
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is it 4

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??

zealous moat
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hey im new how am i suppose to get help from someonne

limpid turret
pseudo ice
zealous moat
#

can you just help me lol

kindred anchor
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Sure, just open your own channel

trail cairn
limpid turret
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You do?

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Might want to check that scientific notation calculation

trail cairn
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i check or you?

limpid turret
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you

trail cairn
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i did

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i changed it

limpid turret
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Ah you edited your answer

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Yes

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That looks good

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And your reasoning is perfect

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full marks

trail cairn
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can you help me with this please