help-0

[waxen flame]

https://www.geogebra.org/classic/xvsa4q2e

This will help you understand.

[deep grove]

oh

tysm

[waxen flame]

yw

[deep grove]

i actually understand this shit now lmao

thank you so fucking much

.close

[lone heart]

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[quaint jay]

Hi I need some help finding angles if possible

[quaint jay]

Trying to add shelving to the above. From the perspective of that picture im wanting to add shelves top to bottom.

The length isnt really relevant just gotta know what angles to cut the ends so they are flush.

If anyone happens to see this if at all possible send me a msg because im about to give my daughter a bath I would greatly appreciate it.

Im making a dumb coffin shelf for my wifes .... rock crystal waste of money

[lone heart]

@quaint jay Has your question been resolved?

[lone heart]

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[golden bronze]

help me solve this please

step by step

im so lost

[waxen flame]

This should help.

https://www.youtube.com/watch?v=rQ0aWlKyTgA&t=79s

[lone heart]

@golden bronze Has your question been resolved?

[lone heart]

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[alpine sable]

help

[runic trench]

[wary stream]

Order of operations, and simplify the stuff in the radical first

[alpine sable]

what u just said explained nothing to me

can u like at least show step by step until i get it

[wary stream]

It explains everything

[alpine sable]

ok well i dont get it still

[wary stream]

Simplify the stuff in the radical

[alpine sable]

ok and i dont know how?

[wary stream]

Order of operations

[alpine sable]

bruh

[wary stream]

Do you know PEMDAS?

[alpine sable]

Yes?

[wary stream]

Can you simplify the stuff in the radical using order of operations?

[alpine sable]

first u do whatever is in square root

[alpine sable]

if i knew how then I wouldnt be here

💀

[slate jolt]

so lets start

[alpine sable]

ok thank u omg

[gray isle]

first u do whatever is in square root
try that

[slate jolt]

do the power first

[sick shard]

Order of operations refers to the oder in which you must evaluate the given expression. BODMAS, or PEMDAS. Meaning, do the bracekts first (if any present), then exponents, mult, div, addition and at last subtraction.

[wary stream]

What is PEMDAS?

[floral maple]

someone explain this to me?

[alpine sable]

...

bruh this is my chat

[slate jolt]

this is getting chaotic

[wary stream]

#❓how-to-get-help

[alpine sable]

idk how to dopower first

bye

2^2
over
4^2

[slate jolt]

do you know what 2² means?

[alpine sable]

i dohnt know!

[wary stream]

Step one, what is PEDMAS? Do you know what it means?

[alpine sable]

YES!

[slate jolt]

yeah right

whats good about pemdas

is that within each priority

you can do

any

order

[alpine sable]

wait

so do i just do

[slate jolt]

2² first or 4² doesnt matter

[alpine sable]

4 / 16

ugh

I DONT GET IT

[wary stream]

PEMDAS is order of operations, hence the order you should do things first

[slate jolt]

calm down

[alpine sable]

i know what things come first, i just dont know. how. to do it

[slate jolt]

if you do 2² its 4 right and 4² is 16 as you said

[alpine sable]

yes

[slate jolt]

so just replace those by their values

for now

and thats it you dont have no more powers left

[alpine sable]

ok

ignore ijm just bringing the pic back here to front of chat

[slate jolt]

so now what comes next?

[alpine sable]

ok so i have 4 - 6 / 2
over 16

[slate jolt]

yeah right

[alpine sable]

division

6 / 2??

[slate jolt]

yeah

[alpine sable]

4 - 3

over 16

?

[slate jolt]

yeah

whats next?

[alpine sable]

oh

1 / 16

divide again

so whats the final square root

1/4?

[slate jolt]

yeah

[alpine sable]

oh

[wary stream]

Here's a hint: $\sqrt{\frac{a}{b}} = \frac{\sqrt{a}}{\sqrt{b}}$

[ocean seal]

dldh06

[alpine sable]

ok ok wait so

ok

so

[wary stream]

Oh you did that

[alpine sable]

3 + 5 √1/4

[wary stream]

No

[alpine sable]

exatcly what do i do now-

oh

[slate jolt]

is your square root over 1/4

[alpine sable]

no?

[slate jolt]

or just the 1?

[alpine sable]

yes

[gray isle]

what's the radical covering, why's it still there after taking the root

[slate jolt]

then how did you go from √1/16 to √1/4?

[alpine sable]

what is radical covering...

[slate jolt]

radical is the way we call this √ symbol

[alpine sable]

oh

oops

ok so what do i replace it with

3+5 x 1/4??

[slate jolt]

use this

[gray isle]

you already took the sqrt of 1/16 which is 1/4
the radical symbol is gone now

[alpine sable]

is it multiplication

or

add

[alpine sable]

ya but i have to replace the radical w something

like adidtion or substraction or multiplication

3 + 5 (1/4)

?

[slate jolt]

yeah but do you understand why?

[gray isle]

yeh

[slate jolt]

or did you guess?

[alpine sable]

well yes i guess i get it

cause the square root of 1/16 is

[slate jolt]

break it down then

[alpine sable]

1/4

so

[slate jolt]

yeah

[alpine sable]

u just write 1/4 in brakcets

ok

3 + 5 (1/4)

so

[gray isle]

multiplication was implied between 5 and sqrt(1/16)
after simplifying, you should still have something representing 5 multiplied by whatever sqrt(1/16) is

[alpine sable]

yes

[slate jolt]

what i meant by breaking down was this

[alpine sable]

yes

[slate jolt]

ok good then

as ramonov said

[alpine sable]

ok so

3 + 5 (1/4)

[slate jolt]

when theres no symbol

it means multiplication

[alpine sable]

5/1 x 1/4 = 5 / 4??

3 + 5/4

[slate jolt]

yes

[alpine sable]

bye

oh

how do i add a numerator to a fraction 💀

bye

[slate jolt]

multiply 3 by 4/4

[alpine sable]

3 5/4

[gray isle]

get common denominator

[slate jolt]

since 4/4 is equal to 1

it doesnt change

[alpine sable]

wait

so

ok

[alpine sable]

so 12

[slate jolt]

12/4*

[alpine sable]

3/1 = 12 /4

yeah thats what i meant

[slate jolt]

yeah

right

[alpine sable]

rightOH

[slate jolt]

so now that its the same denominator

[alpine sable]

oh i get iti think wait

ya

ok ya

easy

wait

12/4 + 5/4 = 17/4

[slate jolt]

can you simplify further?

[alpine sable]

yes

it

will be

4 1/4

[slate jolt]

why?

[alpine sable]

because 4 goes into 17 4 times

[slate jolt]

oh

[alpine sable]

but then theres an extra 1

[slate jolt]

this way

[alpine sable]

yes

LOL

[slate jolt]

you forgot the + then

it looked like multiplication

[alpine sable]

whattt

[slate jolt]

this

it looks like 4 * 1/4

[alpine sable]

how thats how we write it here LOL

we just write the whole number and fraction

[slate jolt]

oh ok

[alpine sable]

ya but ok thanks

[slate jolt]

w/e

i would have kept it 17/4

as a fraction

[alpine sable]

ya

ya

id keep it too

[slate jolt]

so do you understand

[alpine sable]

ok thank u

yes

[slate jolt]

how i chosed

[alpine sable]

yesss

[slate jolt]

by what to multiply 3?

[alpine sable]

yep

i will probably come back later on to ask more math questions but thanks!!!!

.close

[lone heart]

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[slate jolt]

bye

[lone heart]

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[lethal parcel]

Anyone able to help me get started with this calc problem?

[slate jolt]

yeah

what is a derivative of a function to you?

[lethal parcel]

The slope at a certain point

[slate jolt]

right

[lethal parcel]

So would P'=slopeF/slopeG

[slate jolt]

so thats good

[lethal parcel]

or *

[slate jolt]

P is the product

[lethal parcel]

oops

[slate jolt]

but thats not it

whats the formula for

the derivative of a product of functions

given the derivatives of the said functions

which is what P is after all

[lethal parcel]

F[x]G(x)+F(x)G[x]

correct? or at least similiar

[slate jolt]

[] means derivativ?

[lethal parcel]

yeah

[slate jolt]

usually most people write f'

for the derivative of f

but yeah

so you can calculate

the derivative of P at 2

then

using this formula

you just have to substitute

[lethal parcel]

slope at 2 for F would be 0 correct?

[slate jolt]

yeah

[lethal parcel]

(02)+(31/2)

(0 * 2)+(3 * 1/2)

0+1.5

1.5

And then just quotient for the next?

[slate jolt]

yeah

thats it

[lethal parcel]

😄

Thanks ill tell you if I get it

I dont think ive done it right

Oh. I did Q'(6)

.close

[lone heart]

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[final badge]

how to solve number 25?

actually nvm

.close

[lone heart]

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[ornate condor]

hiii guys n gals +. can ive an eg of how i would use residue theorem to calculate an integral

[half silo]

hello people, i need to find a vector, but i cant see how

[ornate condor]

#❓how-to-get-help

https://math.stackexchange.com/questions/2069992/compute-the-following-real-integral-using-the-residue-theorem

so for ref i saw this

but how did they go from bound -inf to inf to circles?

[wanton tusk]

QUEEN

[ornate condor]

QUEENNNNNNN

HELPPPP

idk how to

[wanton tusk]

AHAJIDKSNEO

[ornate condor]

do integrals

[wanton tusk]

finished my bio exam

❤️

[ornate condor]

❤️

good

[wanton tusk]

i love Spain without the S

[ornate condor]

now u can

help me with math

[wanton tusk]

okie let’s go

[ornate condor]

❤️

[wanton tusk]

what do I help with

[ornate condor]

so i was wondering

how do i conpute

an int

with residue theorem

[wanton tusk]

ya

[ornate condor]

i was looking at this

[wanton tusk]

[ornate condor]

idk how they translated

[wanton tusk]

what is..residue theorem

[ornate condor]

-inf to inf as the bounds

to a contour

using jordans lemme

TnT

[ornate condor]

its

finding residues at poles

HAHAHAH

[wanton tusk]

i am so not that advanced

HAHAHA

[ornate condor]

im so

[wanton tusk]

where’s snow

[ornate condor]

doomed

prob

helping others

[wanton tusk]

where’s kitty kat

[ornate condor]

TnT

no idea

ben help mee

[wanton tusk]

wait someone’s typing

[ornate condor]

my knight is shining armor!!

[wanton tusk]

maybe they know

[ornate condor]

in

[slate jolt]

i can try but i did only a tiny bit

of complex analysis

[ornate condor]

allg

[slate jolt]

so i'm not very sure

[ornate condor]

i dont understand anything

[slate jolt]

so whats your integral?

[ornate condor]

idk im just tryna understand the concept first

[slate jolt]

oh ok

[ornate condor]

so i went online

n got this

https://math.stackexchange.com/questions/2069992/compute-the-following-real-integral-using-the-residue-theorem

but idk how they went from -inf to inf to contours

prob the first part at jordans lemma

i barely get how to apply that

[slate jolt]

i guess they use jordans lemma to go from the fact that the function is dominated by 1/z

to the contour

integral converging

as the radius goes to infinity aswell

[ornate condor]

sry wait no

so

what exactly did jordans lemma do

what even is jordans lemma

ive to review stuff

[slate jolt]

jordans lemma is

if |zf(z)| goes to zero

when |z| goes to inf

then the integral over a circle of radius r

of f(z)

goes to zero

as the radius goes to inf

but theres also a version for half circles

i think

[ornate condor]

oh no

[slate jolt]

which is the one they use here

it seems

[ornate condor]

i realised

i completely

do not get jordans lemma

so sad

thinking back

i dont get kronig rouches theorem as well

i just thought they sounded cool but i wouldnt need em

[slate jolt]

its hard

are you doing this on your own?

[ornate condor]

im

doing some course

but

idk

they havent released the nornal worksheets

so idh practice stuff to reference

TnT

well

i

try to understand that first

jordan

[slate jolt]

i think jordan

makes intuitive sense

i cant say that about residue

[ornate condor]

both dont

[slate jolt]

i can try and give you my pov on jordan theorem

let me draw a bit

[ornate condor]

OH REALLY THANKSS

https://en.m.wikipedia.org/wiki/Jordan's_lemma#:~:text=In complex analysis%2C Jordan's lemma,the French mathematician Camille Jordan.

oh from this

from what i understand

nvm i dont

they.. probably used the fact that the max is on the boundary

but idk how g is related

[slate jolt]

@ornate condor

[lone heart]

@ornate condor Has your question been resolved?

[ornate condor]

oh

i went

away

oops

ye um

is zf -> a cond?

ok anw

no but

my issue was

the original Q

how did we go from

bound -inf, inf

to a contour

was that substituition, i feel it is

[slate jolt]

oh

he goes

integral of the circle =

semicircle*

=

integral on the line + integral on the rest

and takes the limit

thanks to jordan

the whole integral is 0

so essentially integral on the line at the limit

is -inf to +inf

ok i'm messing things up look at the drawing

[ornate condor]

ive

[ornate condor]

just been lookin

hahaha

[slate jolt]

thx to jordan

integral of the GammaR

path

goes to 0

when R goes to +Inf

integral of omegaR

[ornate condor]

wait

is this like

cauchys theorem

[slate jolt]

goes to -inf,+inf

[ornate condor]

contour=0

yay?

[slate jolt]

well no because there's a singularity

in the middle

[ornate condor]

nuu

[slate jolt]

the red cross

[ornate condor]

but

its a simple pole

so int of zf=0?

n when thrs multiple

we compute em with residue themrem separately

yay?

[slate jolt]

well int of (z-z0)f = 0

[ornate condor]

oh ye that

[slate jolt]

if z0 is the singularity

[ornate condor]

at z0 i guess oops

[slate jolt]

its not what we have then

[ornate condor]

w8w8w888

we dont hv this??

wait

im but

bit

confused then

[slate jolt]

like its =0 right

but its not helpful for our purpose

since we evaluate zf(z)

and not (z-z0)f(z)

no?

[ornate condor]

oh

yea

[slate jolt]

and you cant split and do anything you want

[ornate condor]

we arent even integrating it

we just using ml bound

oops

[ornate condor]

w8 so this

is completely unrelated to cauchys theorem?

[slate jolt]

it is because residue theorem

is a generalization

of cauchys

for when there are singularities

[ornate condor]

ok but the

[slate jolt]

but the same apply

[ornate condor]

zf goes to 0

whats that mean

like

whats it say abt f

wait sry im

feelin dizzy rn

[slate jolt]

it means that f goes to 0 faster than 1/z

[ornate condor]

sry ill

b back ltr

[slate jolt]

gotta sleep personally

but gl

[ornate condor]

oki

thankssss

[lone heart]

@ornate condor Has your question been resolved?

[ornate condor]

ill

figure dis out

TnT

.close

[lone heart]

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[alpine sable]

what have you tried so far? @shut garnet

[zinc dagger]

I suggest lots of sin law as diagnosis

[alpine sable]

can i see what you did?

but it looks like sine might not help us here

can i see what you did please?

okay there's a huge algebra mistake there

the first one implies x=tan(13'5)*1020 but nonetheless this isn't correct

so we want to make 2 equations to solve the system of equations okay?

since we have two variables, the height they called v and the distance between B and Mr Lofty

which is shown as "unknown"

we'll label that "unknown" as x

and now think about it as 2 triangles, the smaller one with the angle of 19'9°, an opposite side of v and an adjacent side of x

do you agree with that first triangle?

now what about the second one

ie the big one

that has an angle of 13'5°

yes

what's the opposite side of that triangle?

same as the other one

yeas

and now what is the adjacent side of that triangle?

take some seconds to think about it

great

now are you able to form 2 different equations using the tan(angle)=opp side/adj side?

[ocean seal]

Al3dium

[alpine sable]

this might help

missing the side but whatever

can i see your attempt for the smaller triangle first?

[alpine sable]

remember this

yes don't worry

we are making a system of 2 equations

with 2 variables

great

wait no

yeah 19'9

now try with the bigger one

v/(1020+x) but yes

now we have a system of 2 equations with 2 variables

do you know know to solve them?

okay i would help but i have class rn

you can either watch any youtube video or wait for another

[lone heart]

@shut garnet Has your question been resolved?

[lone heart]

@shut garnet Has your question been resolved?

[lone heart]

@shut garnet Has your question been resolved?

[viscid pawn]

Still here or ?

[lone heart]

@shut garnet Has your question been resolved?

[lone heart]

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[chrome plank]

[lone heart]

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[burnt escarp]

Can anyone help me solve this question

[burnt escarp]

9 A shipping company charges to ship packages based on the mass of the package. For packages weighing up to and including 3 kg, the cost is $7.65. For packages weighing greater than 3 kg to 8 kg, the cost is 14.95 to ship. For packages greater than 8 kg to 18 kg, the cost is $32.55. For packages grater than 18 kg to 30 kg, the cost is $70.85 to ship. And for packages greater than 30 kg to 45 kg, it costs $149.95 to ship.
a) Graph the situation on a coordinate grid.

[lone heart]

@burnt escarp Has your question been resolved?

[carmine reef]

Probably you want x axis to be mass and y axis to be the cost

Since cost depends on mass, not the other way around

[lone heart]

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[alpine sable]

how to find KEN angle

[alpine sable]

K is in the mid of AA1

N is mid of AB

E is mid of AD

[manic wind]

default cube

[alpine sable]

yea found that blender is the best way to show

[alpine sable]

tip: look at the triangle that the angle is in

does it tell you anything ?

60

ffs

yes

that triangle is echilateral

.close

[lone heart]

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[alpine sable]

ty

[lone heart]

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[alpine sable]

i got no idea how to go about doing this please help

[gray isle]

poly long division

[alpine sable]

so like box method

i'd prefer using synthetic division

so like this?

the ax^2 +bx+c kinda got me super confused

you can also compare coefficients through expansion but that'll take a while

[alpine sable]

i dont think im at that level

do you know how to multiply polynomials?

smt like that

but i got it wrong

[alpine sable]

box method thats all ik

[alpine sable]

ye that was 100% wrong

ye

i figured it out

idk whats up with the ax squared

but the divison is like 2x^2 -7x +4

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[alpine sable]

.close

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[sterile shuttle]

can i get help with 273

[ocean seal]

Toby

[alpine sable]

try using the power rule first to get rid of the sqrt. then the product rule

note also that log_5(125)=3 (because 5^3=125)

[sterile shuttle]

how would the power rule apply in this scenario though? wouldnt that just bring down the (1/2) sqrt down to the front

then would we use the product rule for log_5(125) + log_5(x)+ log_5(y^3)

[alpine sable]

yes, that is correct

[sterile shuttle]

so 1/2+ log_5(125) + log_5(x)+ log_5(y^3)?

or wait
1/2log_5(125) + 1/2log_5(x)+ 1/2log_5(y^3)

[alpine sable]

this second one

[sterile shuttle]

ah yea that makes sense, thanks alot in guiding me

[alpine sable]

you can also pull the 3 out (if thats what the question wants)

[sterile shuttle]

yea, and that got me the final answer. was just a lil confused about rewriting (125xy^3)^1/2 since i forgot i can change it to the power of 1/2

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[junior condor]

Is there a fast way to work out if a finite set of generators and relations generates an infinite group without just cranking out some calculations?

[junior condor]

For example, this presentation gives an infinite group but wasn't immediately obvious

[alpine sable]

bump, I would also like to know :p

I normally just whip out gap or smth

found this https://math.stackexchange.com/questions/476854/the-order-of-a-group-presentation

[heavy osprey]

Can someone help me with my pre-cal??

[lone heart]

@junior condor Has your question been resolved?

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@junior condor Has your question been resolved?

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[tranquil barn]

How did he get the 2

[gray isle]

direct sub

[tranquil barn]

Thanks

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[topaz narwhal]

Ahmed are u Arabic?

I have a question

[prime sluice]

Mayhaps

[tranquil barn]

Yes

[topaz narwhal]

شوف السؤال الرابع الف

مجموعة التعريف بتكون

لساتني فالثنوايه سو بتكون سهلة ليك

بت استاذتنا

[prime sluice]

The question in Arabic but answer in English? 🤔

[topaz narwhal]

تقول اخر مجال حق ال3 يكون مغلق

[tranquil barn]

اول مرة اسمع فالمتراجحات😂

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[tranquil barn]

بس ثانية بحاول

[topaz narwhal]

لانو مماسي للصفر ، بت هو اصلا اصغر تماما اصلا ما نقدر

[topaz narwhal]

اه 😭

[topaz narwhal]

حسنا

[prime sluice]

مش واخد السالب تلاته و الواحد معاك ليه

[topaz narwhal]

ها؟

[prime sluice]

احم انا حمار ثانيه

[topaz narwhal]

هي قعدت تكتبلنا ااثلاثة هيك

[prime sluice]

طيب ليه أغلقت علي ال -4 و ال3 لا

[topaz narwhal]

بت لو كانت او تساوي تنغلق فال3

هي اصغر تماما

[tranquil barn]

الثلاثة نقطة مغلقة يعني قوس مغلق اتوقع

[topaz narwhal]

هي ال4 اصغر من محور الفواصل

هي تحتها اصغر تماما فمغلق

[prime sluice]

🤔 فعلا مش عارف اجابتك غلط ليه

[topaz narwhal]

بت ال3 مماسية لل0

سو بيكون مجال مفتوح ، غير اذا كان اصغر او تساوي بيكون مغلوق

[prime sluice]

اتأكد من المدرس، ممكن يغلط عادي

[topaz narwhal]

مدري ، قاعدة تقولنا انو بيكون مغلق لنو مماسي لل0 بت ذا يعني انو يساويه وهي تقول لا

فمش عارفه وين الصح ووين الغلط

[topaz narwhal]

اكس

ي

[tranquil barn]

جربتي تسئلي الهيلبرز هنا؟

[topaz narwhal]

مفهمت

مين

مساعدين؟

لا اظن ، سالت هنا فقط

[tranquil barn]

<@&286206848099549185> the question (4) says solve the inequalities when f(x) is smaller than 0

[tranquil barn]

Is this correct?

[alpine sable]

Uhh idk any Arabic

Idk how to help u ngl

[tranquil barn]

Here is the translation

[tranquil barn]

.

[alpine sable]

Yeah but

Where's q4 lmao

[alpine sable]

This?

[tranquil barn]

Its has a blue square thing on the right here

[alpine sable]

Well you can see the plot of f(x)

And the values at which it can be seen to be below zero are
\
$-4\geq x\geq -3$ or $1 \geq x \geq 3$

[tranquil barn]

So

[tranquil barn]

Is that correct?

[alpine sable]

Yes it's correct

It's just given in set notation

[tranquil barn]

The teacher said the last line thingy on the right should be closed maybe she is mistaken

[alpine sable]

Also I didn't realise

That the graph ends at x=-4

[tranquil barn]

Yes ok thank you

[ocean seal]

idecanymore

[alpine sable]

So it should be this

[alpine sable]

Np

[tranquil barn]

Shouldnt x be smaller than 3 here?

[tranquil barn]

.

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[twilit cypress]

can someone help me understand how both of these end up being the same as -infinity?

[tawny condor]

A limit of the form 1/0+ will give you infinity, and a limit of the form 1/0- will give you -infinity.

As x approaches -2 from the left side, what does x + 2 approach?

[twilit cypress]

-infinity?

[twilit cypress]

should this be read as 1/0(from the right) and 1/0(from the left)

(I read it as positive 0 and negative 0, but that cant be right lol)

[tawny condor]

Yes

$\frac{1}{0^{+}}$

[ocean seal]

RedstonePlayz09

[tawny condor]

So the denominator is approaching 0, from the positive side

[twilit cypress]

oh ok, I think that makes sense. So does it just hold that if its coming from the left, then -infinity and if coming from the right +infinity?

[tawny condor]

Yes.

Think about it intuitively.

1/(a very small positive number)

is going to approach infinity.

[twilit cypress]

ah ok, that makes sense. Thank you @tawny condor, I really appreciate your help

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[tawny condor]

No problem! you should revise limit arithmetic

[twilit cypress]

what do you mean?

I think that might be what I am learning currently (although with different terminology)

[tawny condor]

Surely you have this rule somewhere in your textbook.

Yeah, different terminology I guess

revise the material

[twilit cypress]

Yeah in the lecture, they did not go into much details for this, but I might have to go dig in the textbook and see what else they say in there

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[violet idol]

$\frac{1}{x^8-4x^6+6x^4-4x^2+1}$

[ocean seal]

Raid

[violet idol]

The following fraction is defined for
A x != +-2
B x != +-4
C x != +-1
D x != +-0
E x != +-1

How can I solve this?

I would put the denominator != 0

but then?

[tawny condor]

Just plug in the different x values

and see where you get division by 0.

[violet idol]

If I put 1 its 0

[tawny condor]

the fraction isn't defined when there is division by 0

okay so it's not defined for x = 1

[violet idol]

but if the question is

for which values the fraction is defined

is defined

[tawny condor]

Oh

[violet idol]

doesn't mean its != 0?

[tawny condor]

basically

let's take the first one

[violet idol]

then why my book says that its +-1

[tawny condor]

x != +-2

plug in both 2 and -2

[violet idol]

If I put 1 its = 0

[hollow shale]

x is not equal to ± 1

[tawny condor]

and if both give you 0, then it's defined for all x != +- 2

!= means does not equal

[violet idol]

yes

[tall hearth]

yes not defined for all values for which it is 0, that's your answer

[violet idol]

but it asks when its defined

I can't be defined for x = +-1

[hollow shale]

yes

[violet idol]

because I would have the denum as 0

[hollow shale]

so it's defined for x ≠ ±1

[violet idol]

?????????????

[hollow shale]

it works for all x

apart from 1, -1

[violet idol]

defined doesn't mean that the denum is != 0?

oh

Im dumb

[hollow shale]

undefined is denominator = 0

[tall hearth]

it means exactly that

[violet idol]

yes yes

ye ye

im dumb

xD

so in exercises like this

I would just swap the numbers

and try

ty guys

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[wanton hearth]

I don't understand why is it equal to cos/cos

[pallid scarab]

hello, recall euler's formula for cosine

cos(x) = 1/2*(e^ix + e^-ix)

[wanton hearth]

so 2cos(x) = e^ix + e^-ix

ok i got it thx

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[formal wind]

No

[lone heart]

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[alpine sable]

.reopen

[lilac nest]

You'll have to open a new channel

[alpine sable]

damn

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[left totem]

How would u do 7

[minor needle]

do you know distance formula?

[left totem]

Yh

[minor needle]

d = sqrt(34), P = (x, y) = (x, 4 - 3x)

[left totem]

Should do

Actually I don’t

[minor needle]

mb, it's about distance between two points

ok, so O = (0,0) and P = (x, 4 - 3x)

|OP| = d, find 'x'

you'll get a quadratic equation

[minor needle]

yes, but root on whole LHS

[left totem]

Well I got that

But it seems wrong

<@&286206848099549185>

[minor needle]

= 34, not 0

you forgot about RHS

[left totem]

Y

What rhs

[minor needle]

right hand side

just right side of an equation

[left totem]

Is that correct

[minor needle]

yes

(= 0)

[left totem]

How did u get thou

(X,4-3x)

<@&286206848099549185>

[languid verge]

hi

how can i help you

[left totem]

The question above what u type plz sir

How do u get (x,4-3x)

??

Help plz

<@&286206848099549185>

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@left totem Has your question been resolved?

[lone heart]

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[lone heart]

Please don't occupy multiple help channels.

[wicked marten]

.close

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[south elm]

The sum of two numbers is 92.their difference is 20. Find the numbers.

[mellow tusk]

x+y=92, x-y=20, add both

2x=112

[south elm]

How did you get 62?

[fringe sleet]

should be x+y=92

[mellow tusk]

yh mb i misread

[south elm]

Oh, got it!

[mellow tusk]

u get the point

[south elm]

I got 112 when I added

[mellow tusk]

good

2x=112, x=?

[south elm]

56?

[mellow tusk]

yh

x+y=92

x=56, y=92-56=?

[south elm]

36!

[mellow tusk]

nice

[south elm]

56+36=92

Holy cow

Thank you so much

My teacher made it seem awful

Thank you so much again!

[mellow tusk]

np

[surreal mason]

fyi: its generally a good idea to write down all the information in the form of a system of equations to solve in world problems

[south elm]

Thank you

My question was answered

How do I close this

[surreal mason]

.close

[cedar tide]

Did u get this in the end?

I could help

[lone heart]

@south elm Has your question been resolved?

[lone heart]

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[alpine sable]

Can someone help me🥲 so get the value of O_D

[zinc dagger]

,rotate

[zinc dagger]

So I’m seeing variables a b c and d, right?

And variable O_d

[alpine sable]

Thats right

[zinc dagger]

Sorry idk, it’s too hard for me too lol

[alpine sable]

😂💀🔫

[zinc dagger]

Hey don’t do that, there’s bound to be someone who can help or some YouTube video tutorial that gives the answer, so don’t worry

At least one thing I noticed is that there are two fractions with the number 110 and 95 in them

Maybe isolate 110 for the two fractions and equate the two?

I also noticed that if f(x) = (95-ax)/(a+x), then d = f(c) and c = f(d). same thing with the two equations with 110 in them

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@alpine sable Has your question been resolved?

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@alpine sable Has your question been resolved?

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@alpine sable Has your question been resolved?

[carmine reef]

Whats the x equation?

31-dc?

[fluid spade]

can someone help me with math

[charred flint]

post your question in #help-42

[trim wagon]

oh my, what an algebraic disaster it looks like

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[tacit dirge]

hello

[tiny mango]

how do i isolate two of the same variables in an equation?

d = vi(t) + 1/2(at^2)

i want to solve for t

[tacit dirge]

.close

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[tiny mango]

oh

[lofty magnet]

That’s a quadratic equation, if you’re doing physics generally there’s a longer way around which avoids one. If you do want to solve the quadratic, the easiest way is to use the quadratic formula. Google is your friend

I’d recommend learning how the quadratic formula actually works and the process for solving them, but that takes significantly more time

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[tiny mango]

would u be able to tell me what that way or the name of it is? I am doing physics.

[tiny mango]

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[lofty magnet]

If the question is related to throwing an object, for example, you can find the time until it reaches its peak (vf = 0) then find the time until it goes some distance from there, now that vi is zero. It depends, get creative

[tiny mango]

the question is to find time taken to reach maximum height, I am given a vf of 0, acceleration which is -9.81, vi of 3.5m/s, and a height of 15. a ball is thrown up.

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[stuck schooner]

could you guys help me, I'm stuck

[sand jetty]

the bound should not be infinity

there is a double use of the variable n

use k for the sigma index

[stuck schooner]

upsi

ye

mb

[sand jetty]

you'll get a telescope series in the end that will instantly solve it.

tag me if needed.

[sand jetty]

telescope series

[stuck schooner]

could you help me I do not remember that 😦
mb

[sand jetty]

do exactly what you did the last screenshot

open the brackets

you get a sum of x^(n+1) - x^n

and this telescopes

(x^(n+1) - x^n) + (x^n - x^(n-1)) + ... + (x - 1) = x^(n+1) - 1

[stuck schooner]

oooh

expanding the summation and what else?

[sand jetty]

and saying that this is corrent by telescoping

can you see that all the objects besides x^(n+1) - 1 are cancelling out?

[sand jetty]

Yes!

for completeness cancel also these x^4 and x^n bcs they cancel with thins in the "..."

and you remain with what neede to be proved

[sand jetty]

Fantastic

[stuck schooner]

It's funny because 2 hours ago I was doing the same thing but it was giving me 1=0 hahaha and it was not correct because I was not canceling the x^n correctly.

Thanks

[sand jetty]

👍 np

[stuck schooner]

have a nice evening or a nice day, thank you 😄

.close

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[fair glade]

Oh, sorry it got cropped.

[prisma elbow]

what happened to the rest of the radical

ah there

[fair glade]

My katex previewer is bit buggy, nothing else 🙂

[remote heron]

the est of the adical

hrm what have u tried

[fair glade]

Tried to refactor the expression, no luck though

Also I can't see any way to use substitution method.

[lone heart]

@fair glade Has your question been resolved?

[fair glade]

Thanks, seems like the book has the incorrect answer printed here

[lone heart]

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[zenith compass]

$$\textbf{Problem:}$$

Find the volume of the solid that is bounded on the front and back by the planes $x=2$ and $x=1$, on the sides by the cylinders $y=\pm \frac{1}{x}$, and above and below by the planes $z=x+1$ and $z=0$.

$$\textbf{My Question:}$$

According to my textbook, I can directly use the triple integral to solve the problem:

$$V=\int_1^2\int_{-\frac{1}{x}}^{\frac{1}{x}}\int_0^{x+1}dzdydx$$

But is there any constraint to do like this? Like do I need to check the continuity and integrable thing etc.?

[ocean seal]

Trenton

[lone heart]

@zenith compass Has your question been resolved?

[lone heart]

@zenith compass Has your question been resolved?