#help-0
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Am I being stupid or is there a way to simplify this?
im trying to calculate the derivative of a function using the derivative limit rule, but i keep getting this in the denominator
Doesn't seem like there's any way to simplify it, but maybe you made a mistake in calculating the derivative?
I see
you might want to rationalize the fraction first
$\frac{1}{\sqrt{2x+3}}\cdot \frac{\sqrt{2x+3}}{\sqrt{2x+3}}$
i kinda did that but not in the first step
wait let me take a pic of my work, but its abit untidy
jswatj
i see
okay i think
do the h thing
then rationalize
i think you may have rationalized wrong
Can you do sum rule?
Actually that won’t help
i tried it with different examples, same outcome
so i have to rationalize first then do the limit whenever there is a root in the denominator
Oh you’re doing limits
yeh the teacher asked us to calculate them using the limit way not the fast way lol
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Given 2 integers x,y satisfying : xy -23 ⋮ 24. Prove x^3+y^3⋮72
Are the 3 vertical dots equals
That means divisible
Strange
maybe Vietnamese math uses this notation
oh yes of course
So what’s the problem assuming the vertical dots are /
divisible is not the same as divided by
Now I’m getting confused, three dots mean divisible by or just divide
i'm confusing now bruh
its saying that xy -23 divided by 24 gives an integer
three dots in vietnam means a number can divide another number
like 6/3 = 2
Alright
so Americans write it the other way and use a line like
The result of this division is an integer
so this implies xy is a multiple of 25?
No need to stereotype people
(xy - 23)/24
I'm writing it that way so that Americans reading this chat know what i tmeans
I KNOW EXACLY WHAT IT MEANS
DONT ASSUME AMERICANS ARE DUMB
chill
back to the question…
I wasn't sure what it means, I'm American, and sometimes I'm dumb even if generally I'm not, so relax
Wait you’re one of us
can anyone help me do that problem pls :))
that makes it okay, lmao what
@karmic plume
@karmic plume problem please
no
47
ok non-zero multiple of 25
24 | xy - 23
prove:
72 | x^3 + y^3
I assume those expressions must equate to each other
oh im being silly
its been a long day lol
xy-23=24m ; (x+y)(x^2-xy+y^2)=72n
Ok
right
i found that xy = 6m too
how'd you get that>
Exactly.
ah
there are x = 1(mod3) and y = 2(mod3)
so x + y = 0 (mod3)
oh sorry
not xy
also
xy = 24k + 23 so x and y are odd
=> x + y = 0(mod2)
=> x+y = 0(mod6)
Then, isn't your problem more or less solved?
x^3 + y^3
x^3 + y^3 = (x+y)^3 - 3xy(x+y)
= (x+y)((x+y)^2 - 3xy))
Yes.
e.x 4 can not divide 8
Nope.
10 = 0 mod 2
10 is not 0 mod 8 is it
yeah that's why I said "and" and then ran out of things to say after "and" because I thought we proved more than that
yeah
got ahead of myself sorry
im feeling sleepy now bruh , bye
@karmic plume Has your question been resolved?
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Hi so I need to create a really hard (grade 10) trigonometry question and than solve it. Can someone help me with this. I need to learn the steps
Umm okay let me give you an example
I need something like this.
Brb
Okay im back
I can help you with the steps to this one if you want
Okay
Btw Im looking for the height of the tree
I think so, I'm just bad at it so i need some help
hint: use tangent
it is
this is what I was thinking about, you can see the solution above
u cant just solve with basic trig
u need to know trig function of added angles
like tan(a+b), tan(a-b)
Yeah
So how do I get the angle?
so u have tan(alpha) = 1.75/16
Right
tan^(-1) also
Tan-¹
just notation
RIGHT
yes
yes
it will be useful but later
Okay
Got it
then add height of the man and you're done
Yeah
So wait
For opp is the answer 6.386?
No
I did it wrong
Thats impossible
Unless
opp is 16 * tan(21.76)
Yeah
@desert sage Has your question been resolved?
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i need to find an expression and i have no idea how
@glossy burrow Has your question been resolved?
An expression ? What is the question ?
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SORRY NVM ITS FINE
No problem x)
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Collatz Conjecture 3x+1 problem
?
Collatz conjecture is based on positive integers
@lime tartan Has your question been resolved?
Also there are discussions if 0 is even
Elaborate
Give this man a fields medal
can someone just close this and put me out of my misery
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How do you solve this? cos(x) + 2sec(x) = -3
I converted sec to tan^2x +1
but figured that wouldn't help
should I change to 1/cosx
and then add left side?
I tried doing it with that method and ended up getting no solution
Sec isn't tan²x + 1
I think I did wrong
yeah
sec²x is, but you don't have sec²x
It's better to turn sec into 1/cos
Why multiply by 2
but ended up getting cos^2x = -5
the 2 infront of the secx
Yeah, but that's not being divided
multiplied?
2secx = 2/cosx
I don't see how multiplying by 2 simplifies anything
what do you with the 2
Nothing. Just leave it there. The more pressing matter is the cos in the denominator
I ended up getting cosx + 2/cosx = -3
then multiplied by lcm
both sides
which is cosx
and got cos^2x + 2 = -3cosx
actually idek anymore
I'll send the problem over
So after getting this, what then?
I'd rather know what you did than what your teacher did
Be more specific
I looked at the answer rn
I multiplied by cos(x) on both sides
from this cos(x) + 2/cos(x) = -3
to cancel out the denominator
nvm I get it now. Sorry for wasting your time
Do you mind me asking more questions in case I get stuck?
That's the point of the help channels, after all
sometimes I get confused interpreting my teachers work
For a problem like this would you use double angle formulas and try to simplify everything into one value
like for example in terms of sin or cosine
You could use double angle formulas, yeah. You would also want to get everything in terms of sines and cosines, generally, because it makes simplification easier
I used it and got (cos^2x - sin^2x + cosx +1)/ (2sinx)(cosx) + sinx
but don't know what to do afterwards
Notice that cotx = cosx/sinx
I could factor sinx on bottom
After doing this, you can multiplying by something to simplify a bit
Yep
There is no need for double angle?
And then almost everything is in terms of cos. Only exception is the sin²x, but you can easily make that cos
oh I see
you use pythagorean identities right
Wdym? You used the double angle formulas to get it to that large fraction
so cos^2x - 1
Yeah
Not cos²x - 1
and then thought of factoring out
yes my bad
Since everything is in terms of cos, all that's left is to solve for cosx
alright ima try the problem out and see if I can solve
alright I got this
(sinx)(cos^2(x) + sin(x)cos(x) + 1 / (sinx) = cosx
Why do you still have a bunch of sines
and then if I simplify do I get cos^2(x) + cos(x) + 1 = cos(x)
just realized lol
I don't know what it simplifies to. I don't have any paper nearby and I'm too tired to grab some
hmm
oh wait that was prove the identity problem
should have specified
:/
just realized rn
Right
I'm too tired to work this one out. I'm afraid I can't help too much on this one
No problem, thanks for the help!
I'll ask on another channel and close this one
.close
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idk how to do 38
add 360 until you get a positive number
but how would i sketch it
by sketching the result from this
so 205?
,calc -515 + 720
Result:
205
ya
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what does exp stand for in this context?
the exponential function
7^(3x)?
$exp(x) = e^x$
romeofoxtrot
where e is euler's number, 2.7818.....
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no problem
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How does he know it's increasing or decreasing?
@golden bronze open your own channel
how
@golden bronze #❓how-to-get-help
What's that referring to
fprime
2x-4 is positive?
It can be positive and negative based on x
That’s what helps us find an infection point
We set it equal to 0
And solve for x
Critical point
Oh yes sorry it’s critical point
Inflection point is 2nd derivative and curvature
We then look the behaviour
To the “left” of x when x sets the function to 0 and the “right”
And that tells us if it’s a max or a min
Do you understand that a derivative is the slope of the tangent line
If the slope of the tangent line is always positive
The function is always increasing
If you were to graph it, it would be a tangent line
Yes the derivative of a point
Is the slope of the tangent line at that point
If the derivative is 0
What does that mean about the function ?
It is neither increasing or decreasing at that point
This is a critical point because it often means that the function is switching from increasing to decreasing or vice versa
Okay so how does that explain whether he knows it's decreasing and increasing or vice versa?
Okay so he finds the critical point first
This part has me confused
Than he looks to the left of the critical point
X=2
So he finds an x that is less than 2
Let’s say 1
Plug 1 into the function
and just graphs it
And the the answer is negative
and from that he determines if it is increasing or decreasing.
So we know it’s decreasing
You don’t need to graph it
You look at local behaviour of critical point
What determines if the answer is negative?
We put in a value lower than x=2
So say our critical point is 2
Which it is in this case
We would see what happens to x=1 and x=3
So we first try x=1
Okay because you read the graph from the left?
Yeah it looks easier that way we are just conditioned left to right
and because it's one less then two, the answer is negative?
So our equation for the first derivative is 2x-4
Plug in x=1
2-4=-2
So the function is decreasing
Plug in x=3
6-4=2
Function is increasing
Does that make sense?
You really need to understand what a derivative is
slope of a tangent line at a particular point
so when you plug in x what are you doing to that original derivative equation?
You are evaluating the derivative at a particular point
Of x
You are finding the slope of the tangent line at a point x
When our derivative is positive our function is increasing
When it’s negative it’s decreasing
Does this make sense to you
When our function is decreasing the derivative is negative when it’s increasing the derivative is positive
Yes, I do understand
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Is this question asking me to find 8 critical points?
I don't think there's necessarily 8, but yeah, find all the critical points
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I've gotten so far as to find that there are 13! ways to arrange all the chairs around the tables.
I also know that there are 14*13 ways to find a pair of chairs (including opposites)
But I'm not sure where to go from there
There's 14 ways to choose the first chair, and 12 ways to choose the second. Since order doesn't matter, I am double counting. So, I divide by 2 to fix
14×12/2
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I have a sequence $$s_1 = \sqrt2$$ and $$s_{n+1} = \sqrt{2 + \sqrt{s_n}}.$$
Does anyone have any bloody idea how to prove that $$s_{n+1} > s_n?$$
Only hints necessary, you don't have to give the answer.
I've noticed just by graphing it that $$\sqrt{2 + \sqrt{s}} > s$$ is true for all positive $s$ less than the fixed point
did u try proof by induction?
Eric Tao (he/him)
fixed the typo
induction makes it trivial
try it, you will see that the result comes directly @real gazelle
if not i will help
do you mean you want me to show that s2 > s1 and that if s_n+1 > s_n then s_n+2 > s_n+1
yep
aight
Eric Tao (he/him)
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that's really neat
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i must be dumb or smth but I can't prove this
sorry it's in french but it says "Prove that, if n ∈ N, there exists an odd integer λ_n such that :"
I tried an induction (idk if it's the right word ?) but I cant pass the heredity part
$$5^{2^{0}} = 5$$ and $$1+\lambda_0 2^{0+2} =5$$ with $$\lambda_0=1$$ so P(0) is true
Elayos
Elayos
$$\iff 25\times5^{2^{n}} = 25 + \frac{25}{2}\lambda_n2^{n+3}$$
Elayos
$$\iff 5^{2^{n+1}} = 1 + 24 + \frac{25}{2}\lambda_n2^{n+3}$$
Elayos
but i cant go further
<@&286206848099549185>
well I guess nobody likes my exercise 🥲 its ok
@lapis juniper Has your question been resolved?
In the inductive case, are you saying $5^{2^{n+1}} = 25\times 5^{2^n}$? Because it should be $\left(5^{2^n}\right)^2$.
daveamayombo
I think I'd also rephrase the problem as showing $5^{2^n} - 1$ is divisible by $2^{n+2}$.
daveamayombo
oooooh yeah I forgot about the brackets my bad
thanks for pointing out the hole
okay I succeeded thanks !
👍
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what is x if
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does this graph work given those limits and points?
ignore the lines in the top left
@frosty venture Has your question been resolved?
f(x) is a function?
Then this graph fails the vertical line test
So not a function
hmm how do i fix it to pass vertical line test
because with the infinities doesnt it not pass it automatically?
No there should be ways to do it
Look at the graph of y=1/x to check how they work
right but dont we have it going possitive and negative on both sides in this?
like this
Ur question just says -inf for tend to 5 from the left side and inf, for tend to 5 from the right side
gotcha one sec
im confused on how to do it with 4,-3 with it going to positive infinity from the right side
Wdym?
No it doesnt seem correct 🤔
oh rip
I dont write out every number bte just the important ones💀
lol ight
U mean the point (1,-4)?
ya
No its the opposite
Also im not sure what the point discontinuity at (4,-3) is doing, but its not a problem as it wont make the question wrong
ahhh i didnt see the negative in front of the 4
ty
one sec ima try graphing this thing again
this is what i got before graphing the lines
woudl the infinities be switched around?
Why do you think they wud be switched around tho
the negative means theyre coming in from the left or going to the left?
Which negative
x-->5^-
5- means we are approaching 5 from the left side
so that looks good then?
Yes
everything here before i connect them looks good?#help-0 message
Yes
how would i connect these two on the left?
without failing vertical line
U wont
They arent meant to be connected
For continuity at a point a,we need lim x-->a f(x) =f(x). Here lim doesnt exist
Yes
whats the best way to "prove" the solution is correct?
is there even a way b/c for the upcoming quiz we get a similar problem and we have to prove it
is there a way to plug it into desmos?
@tribal oxide
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does does gker phi = hker phi => h{-1}g in ker phi?
its probably sth really basic, i just dont remember
multiply by the left inverse of h
$h^{-1}g \ker \phi = \ker \phi$
then h^(-1)gker(phi) is a coset of ker(phi) that is equal to ker(phi)
KN
so h^(-1)g must be in ker(phi)
since ker phi is a group?
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how do i do 1.c) ?
im just gonna assume we're talking projectile motion in highschool
so it's a parabola
we can pin a unique parabola with 3 distinct points
we wanna construct a function here that's h(t)
height as a function of time
this is what i needed tysm!
the 3 points we know are,
on start t=0, h = 25
when t =2, h = 45
and t=5, h=0
with this information we can make our parabola
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why is xnx^{-1} in H?
x is an element in G right, not neccecerily in H. So how do we know xnx^{-1} is in H for sure
ok nvm
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Looking into compound interest and I'm a bit stumped:
Trying to figure out how to increase Deposits/Withdrawals by a %/(or flat numerical increase) every year & tie that into figuring out what will the total be after x years
@chrome olive Has your question been resolved?
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I’m looking at the proof of this theorem, I understand everything expect why we can conclude that the n element a^0,…,a^{n-1} are unique? Thanks
a has order m, so a^m is the first power of a that equals 1. And n is less than or equal to m.
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Ah ok, thanks. Not that’s it’s relevant to the proof, but a^0,…,a^{m-1} are also distinct right?
Correct. That's true for any a, in any group, where m is the order of a.
Great, thank you. One last thing, because the a^0,…,a^{n-1} are unique, how can we conclude that <a>=G?
Because the group is generated by x, which has order n... so there are n elements total in the group. If you list n distinct elements like a^0, ... a^(n-1), you must have listed every element in the group.
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a substitution almost suggests itself
u := sin(x) is what i would've gone with.
it's sin^2(x)
oh wait
that's equivalent to
(sin(x))^2?
so i can use chain rule on that?
sort of yes
i did two problems previous
i just
dont really like
understand them when they get complex
ok so substitute u := sin(x) as i suggested
du = cos(x) dx
so you will have $\int_{\sin(\pi/4)}^{\sin(\pi/2)} \frac{1}{u^2} \dd{u}$
Ann
how did we move the sin into the limits?
i'm at
du/cosx = dx
oh wait
i’m here
do not forget to recalculate your bounds
in a definite integral when you substitute u := g(x) the bounds go from [a, b] to [g(a), g(b)]
oohhh
okay
so whatever i set for u
is the function that i apply onto the limits?
ohh okayy
ill watch a video after
and i guess now i solve the limits
and subtract one from the other?
bad wording
...
still bad wording
there exists a charitable interpretation that makes what you said correct but it is kind of a stretch
you have your integral
$\int_{1/\sqrt{2}}^{1} \frac{\dd{u}}{u^2}$, now calculate it
Ann
isnt sin(pi/4) = sqrt(2)/2
,calc sqrt(2/2)
Result:
1
@tropic oasis Has your question been resolved?
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can somebody help me please
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is there a difference between radians and degree
when answering this
actually im not sure how to answer this
sin would be 10sqrt3/20 right
sin of R? opposite over hypotenuse
10sqrt(3) isn't opposite of R
where did your confusion of the opposite side come from
we dont talk about it
but I get it now
thanks
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careful with the handwriting for q10
seems that you read your 16 as 10
alright
looks good to me
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Why is 0.9 repeting equal to 1?
are you familiar with geometric series?
and with infinite series in general, which is the means by which infinite decimals (repeating or otherwise) are given meaning?
yes
as in an arithmetic series with a common ratio?
i don't know what you mean by "arithmetic series with a common ratio"
but anyway
0.9999... is the sum of the geometric series 0.9 + 0.09 + 0.009 + 0.0009 + ...
the first term is 0.9 and the common ratio is 0.1
Yes but that series does not end
So to say there is a sum is moot
It has a limit
Proof: Assign each term of the series to the smallest known particle in the universe. Then; there exists no size particle such that the number of terms in the series is exhausted. Thus, the existence of infinite series is disproven.
well if you're gonna be the kind of person to deny the existence of infinite series and go full crank mode to shout "infinite series dont real!!!" then we have little if anything else to talk about
So you are saying limits are mathematically invalid?
That is "crank" to me
man's trying to sound like einstein from that nat geo show
Let me describe more concretely what I mean
the sum of an infinite series is defined to be the limit of its partial sums, if said limit exists.
it is not "moot" to say that an infinite series has a sum.
But there exists no number, not even grahams number, amount of terms that can satisfy the limit sum
so what
If I ask you what pi plus e is, can you give me an answer?
exactly
if you want it to however many decimal places, tell me how many
?
sorry, let me restate what i said.
if you want it to some number of decimal places, tell me how many decimal places you want.
that's got to be a natural number, for obvious reasons, but if you're going to give me something other than that i'll round to the nearest integer anyway.
I want the number of decimal places it takes such that if it were on the left side of the equation, it would equal pi plus e on the right
Professor of mathematics Norman Wildberger expounds on the nature of the infinite and the real numbers. Sponsors: https://brilliant.org/TOE for 20% off. For Algo's podcast https://www.youtube.com/channel/UC9IfRw1QaTglRoX0sN11AQQ and website https://www.algo.com/.
Patreon: https://patreon.com/curtjaimungal
Crypto: https://tinyurl.com/cryptoTOE
...
This is not "crank", here this mathematician explains it
proofs have constructive content, and what you get out of these constructions isn't much more than you put in.
A(0)∧(∀x.A(x/2)⇒A(x))⇒∀x.A(x)
Then any proof of a forall-exists statement has to be realized by a polynomial time computable function.
Explain this then
your google search results vary depending on your search history
If this is too complex a question I apologize, I am a grad student
its not too complex a question
but your objection, as wildberger's, is not mathematical
this is purely a philosophical objection
wildberger rejects certain axioms and constructions purely on philosophical opinion
which he is, as you are, allowed to do
however if you ask a question on this server, everyone will assume that you do the "standard" mathematics, that everyone else (save wildberger and a few other people) are doing
So? Math is made foundational off of set theory which is based off of the peano axioms
Its not too far a stretch to ask foundational mathematical questions, no?
so what is your question?
a reasonable objection to ultrafinitism
I am not aware of any and would like an explanation
this is not a mathematical question
the answer is "I dont want to do this kind of mathematics, i like what i am doing currently"
Ok then, in the future I will note to not ask foundational questions and limit the remit of my queries
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i understand that im supposed to find all the numbers that dont have a 5 or 7
and then subtract that from the total outcomes
but i have no clue how to find this
since you are looking at only 4 digit numbers, think about what each digit can be and then use that to find the number of integers with no 5s or 7s
like normally each digit could be 0, 1, 2, 3, 4, 5, 6, 7, 8, 9 ( except the first digit which cant be 0 )
which gives you 9 * 10 * 10 * 10 = 9000 total 4 digit numbers
ahhhh yes that makes sense, i will try it now
give me a moment
ok so i tried this
first digit: cannot be 0, 5 or 7 therefore 7 choices
second: cant have 5 or 7 therefore 8 choices
third: cant have 5 or 7 therefore 8 choices
fourth: cant have 5 or 7 therefore 8 choices
so 7 * 8 * 8 * 8 = 3584
yep
9000-3584=5416
correct
my dude thank you so much
np
this is the first time ive asked for help in the server lol
i really appreciate it, you made it really clear to understand
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Why isn't this online platform accepting my answer?
try without the i
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hello how can i find the image of this matrix
Im(T) is the span of [1;0;1;0], [1;1;1;1] and [2;1;2;1]
wait thats it ?
$\Lambda$ and $\Phi$ are bases
Element118
the base thing is whats confusing me
okay lets say i found Im(T)
and i wanna find Ker(T)
it's all vectors in the domain that go to 0
so in order to find it i gotta put the matrix i have equal to a zero's matrix
and i gotta find its rank or something ?
@viscid moat Has your question been resolved?
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if i quantify x over a set, what is the term of the set in relation to x?
would the set be the domain of x?
Elucidate please
ok
if x is quantified over the real numbers, can I say x is in the domain of R
or that the domain of x is R
@native cloud
if i quantify x over a set
what does that even mean
I don't understand either
As in if I want to prove a property of x, I need to quantify it first
like saying for all x is an element of the reals, x + 1 > x
Have you never encountered the words "For All" or "There exists" in math?
That is quantifying a variable
yeah probably
ah that's what you mean
to quantify something, you need a statement involving x like P(x)
Ok, thank you. I find it funny how @native cloud and @weary wyvern , two helpers with the tag "advanced", have never come across set quantification which I am learning as a freshman
i haven't heard the term "quantification" much
but ofc i know what for all and there exist means
it can be as simple as let x be an element of R, right? I don't need an assertion
i assumed by "quantifying" x you meant saying "for all x in a set" or "there exists an x in a set" such that ...
yea
? so you need a P(x)
or just stating x is an element of a set
that is quantifying too
but doesn't specify a P(x)
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gigaclaim
for formal languages/grammar/regular expressions
for this regular language:
what does the + change? is it the same as just L(((01111)*(00)*)*)
like for this previous question:
i can tell it has to start with 0, then can have none or infinite '11's afterwards, then none or infinite of both of those together
but with the first thing i posted i feel like im missing something
omg nevermind the + means OR
@mortal latch Has your question been resolved?
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Hi whats the fourth root of the cube root of the square root of 2^24?
I put 2 on the test (the test is over im not cheating)
also looking how to solve it not just an answer which i could get from google
$\sqrt[4]{\sqrt[3]{2^{24}}}={\sqrt[3]{2^{24}}}^{\frac{1}{4}}={{{2^{24}}^{\frac{1}{3}}}^{\frac{1}{4}}={{2^{24}}}^{\frac{1}{12}}=2^2$
Toby
Compile Error! Click the
reaction for more information.
(You may edit your message to recompile.)
thank you
forgot the squareroot
yeah
(2 is correct)
yw :)
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missing parentheses here
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Right, so I've tried the obvious thing of considering every combination of 3 points being on the grid of 4x4, which is 16C3
...And from there I suppose I must eliminate triangles which can't be formed. But I'm not sure how to go about doing that
well you need to make sure the vertices are not colinear
Okay, so that will eliminate 3 points lying on the same row/column, right?
Oh wait, so I do 4C3 to figure out how many ways that can happen for each row
yeah, and diagonal
the harder ones to count are the diagonals
Yep, and and multiply by...
10, 4 for the row, 4 for the column, 2 for the 4 pointed diagonals
And then the uhhhh 3 pointed diagonals
Which are in 4 rotations
Oh that makes so much sense
Thank you
so 16C3 - 10(4C3) - 4
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how do u solve for x and y for this?
