#help-0

1 messages · Page 5 of 1

lone heartBOT
#

@tall current Has your question been resolved?

lone heartBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Please take a minute to participate in [our survey](#changelog message) if you haven't already!

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

misty notch
#

Am I being stupid or is there a way to simplify this?

misty notch
#

im trying to calculate the derivative of a function using the derivative limit rule, but i keep getting this in the denominator

alpine sable
#

Doesn't seem like there's any way to simplify it, but maybe you made a mistake in calculating the derivative?

misty notch
#

this is what i got towards the end

alpine sable
#

I see

#

you might want to rationalize the fraction first

#

$\frac{1}{\sqrt{2x+3}}\cdot \frac{\sqrt{2x+3}}{\sqrt{2x+3}}$

misty notch
#

i kinda did that but not in the first step

#

wait let me take a pic of my work, but its abit untidy

ocean sealBOT
#

jswatj

alpine sable
#

okay i think

#

do the h thing

#

then rationalize

#

i think you may have rationalized wrong

vernal thunder
#

Actually that won’t help

misty notch
#

so i have to rationalize first then do the limit whenever there is a root in the denominator

vernal thunder
#

Oh you’re doing limits

misty notch
#

yeh the teacher asked us to calculate them using the limit way not the fast way lol

vernal thunder
#

Hmmm

#

Ok

#

It be much easier if we have 1 variable

misty notch
#

.close

lone heartBOT
#
Channel closed

Closed by @misty notch

Use .reopen if this was a mistake.

Please take a minute to participate in [our survey](#changelog message) if you haven't already!

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

karmic plume
#

Given 2 integers x,y satisfying : xy -23 ⋮ 24. Prove x^3+y^3⋮72

vernal thunder
karmic plume
vernal thunder
#

Strange

karmic plume
#

example 6 ⋮ 3

#

and also

#

6 ⋮ 2

vernal thunder
#

Never saw that notation

#

So it’s xy- (23/24)

#

In this context

karmic plume
karmic plume
#

how does it say

vernal thunder
#

I don’t know Vietnamese notations for math

#

We use / as divide

karmic plume
#

oh yes of course

grizzled mauve
#

and Americans write it the other way

#

3 | 6 , or 3 \ 6

vernal thunder
#

So what’s the problem assuming the vertical dots are /

frigid hatch
#

divisible is not the same as divided by

vernal thunder
#

Now I’m getting confused, three dots mean divisible by or just divide

karmic plume
#

i'm confusing now bruh

uncut torrent
#

its saying that xy -23 divided by 24 gives an integer

karmic plume
#

like 6/3 = 2

vernal thunder
#

Alright

grizzled mauve
#

so Americans write it the other way and use a line like

karmic plume
#

The result of this division is an integer

uncut torrent
grizzled mauve
#

24 \ xy-23

#

or
24 | xy-23

vernal thunder
karmic plume
grizzled mauve
#

I'm writing it that way so that Americans reading this chat know what i tmeans

vernal thunder
#

DONT ASSUME AMERICANS ARE DUMB

uncut torrent
#

chill

frigid hatch
#

why you writing in caps

#

you mad for what?

uncut torrent
#

back to the question…

grizzled mauve
#

I wasn't sure what it means, I'm American, and sometimes I'm dumb even if generally I'm not, so relax

karmic plume
#

can anyone help me do that problem pls :))

vernal thunder
#

Oops

#

Alright back to the problem

frigid hatch
uncut torrent
vernal thunder
#

@karmic plume problem please

karmic plume
slender gull
#

47

uncut torrent
#

ok non-zero multiple of 25

karmic plume
#

also 23

grizzled mauve
#

24 | xy - 23
prove:
72 | x^3 + y^3

vernal thunder
#

I assume those expressions must equate to each other

uncut torrent
#

oh im being silly
its been a long day lol

grizzled mauve
#

xy-23=24m ; (x+y)(x^2-xy+y^2)=72n

karmic plume
vernal thunder
#

Ok

karmic plume
grizzled mauve
#

hmm

#

I tried taking both equations mod 23 and that didnt help thunk

karmic plume
#

i found that xy = 6m too

grizzled mauve
#

how'd you get that>

karmic plume
#

using mod 24 seems more feasible

#

xy = -1 (mod24)

slender gull
karmic plume
#

xy + 1 = 24m

#

=> xy + 1 = 3m

#

=> xy = 2 (mod 3)

grizzled mauve
#

ah

karmic plume
#

so x + y = 0 (mod3)

#

oh sorry

#

not xy

#

also

#

xy = 24k + 23 so x and y are odd

#

=> x + y = 0(mod2)

#

=> x+y = 0(mod6)

slender gull
#

Then, isn't your problem more or less solved?

karmic plume
#

cause

slender gull
#

x^3 + y^3

karmic plume
#

x^3 + y^3 = (x+y)^3 - 3xy(x+y)

slender gull
#

= (x+y)((x+y)^2 - 3xy))

karmic plume
#

(x+y)^3 = 0 (mod 6^3)

#

so (x+y)^3 = 0 (mod 72)

slender gull
#

Yes.

karmic plume
#

then

#

3(x+y) = 0 (mod 18)

#

so we need to prove that x+y = 0 (mod8)

grizzled mauve
#

which it is, because x + y = 0 (mod 2)

#

and

karmic plume
slender gull
grizzled mauve
#

yeah that's why I said "and" and then ran out of things to say after "and" because I thought we proved more than that

karmic plume
grizzled mauve
#

got ahead of myself sorry

karmic plume
#

im feeling sleepy now bruh , bye

slender gull
#

Same.

#

bye

lone heartBOT
#

@karmic plume Has your question been resolved?

lone heartBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Please take a minute to participate in [our survey](#changelog message) if you haven't already!

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

desert sage
#

Hi so I need to create a really hard (grade 10) trigonometry question and than solve it. Can someone help me with this. I need to learn the steps

old horizon
#

ok

#

like

#

which type of question you want to create

#

proving ones?

desert sage
#

Umm okay let me give you an example

#

I need something like this.

#

Brb

#

Okay im back

minor needle
desert sage
#

Okay great, here this is what I came up with

minor needle
#

ok so

#

I'd start from finding that angle

desert sage
#

Okay

minor needle
desert sage
#

Btw Im looking for the height of the tree

minor needle
#

Can you find it?

#

using trig

desert sage
#

I think so, I'm just bad at it so i need some help

minor needle
#

hint: use tangent

desert sage
#

Like SOH CAH TOA?

#

But it isnt 90⁰

minor needle
#

it is

vernal crag
#

is this ok?

minor needle
desert sage
#

OHH

#

Right

#

Thanks

minor needle
#

this is what I was thinking about, you can see the solution above

vernal crag
#

u cant just solve with basic trig

#

u need to know trig function of added angles

#

like tan(a+b), tan(a-b)

desert sage
#

Yeah

desert sage
minor needle
desert sage
#

Right

minor needle
#

use arctan

#

calculator required

desert sage
#

Arctan?

#

So

minor needle
#

tan^(-1) also

desert sage
#

Tan-¹

minor needle
#

just notation

desert sage
#

RIGHT

minor needle
#

yes

desert sage
#

Okay okay so

#

Here

#

I got 6.24

minor needle
#

yes

desert sage
#

Okayama

#

Okay

minor needle
#

now notice that

#

angle alpha is also here

desert sage
#

Sure

#

Wait

#

Where do I put the 6.24

#

In general

minor needle
#

it will be useful but later

desert sage
#

Okay

minor needle
#

now what can you say about that angle

desert sage
#

Beb

#

Brb

#

Okay Im starting to understand it hold on

#

Okay Im at tan 21.76 = opp/16

minor needle
#

great

#

solve for opp

desert sage
#

Got it

minor needle
#

then add height of the man and you're done

desert sage
#

Yeah

#

So wait

#

For opp is the answer 6.386?

#

No

#

I did it wrong

#

Thats impossible

#

Unless

minor needle
#

opp is 16 * tan(21.76)

desert sage
#

Yeah

minor needle
#

but 21.76 is in degrees

#

ah

#

yes

#

6.386

desert sage
#

So

#

Okay SWEET

#

Ight now ill add em up

#

Thanks a million

#

8.136

#

M

lone heartBOT
#

@desert sage Has your question been resolved?

lone heartBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Please take a minute to participate in [our survey](#changelog message) if you haven't already!

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

glossy burrow
#

i need to find an expression and i have no idea how

lone heartBOT
#

@glossy burrow Has your question been resolved?

tidal lantern
#

An expression ? What is the question ?

lone heartBOT
#
Channel closed

Closed by @glossy burrow

Use .reopen if this was a mistake.

Please take a minute to participate in [our survey](#changelog message) if you haven't already!

glossy burrow
tidal lantern
#

No problem x)

lone heartBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

lime tartan
#

Collatz Conjecture 3x+1 problem

lone heartBOT
lime tartan
#

Why can't zero be an x?

#

That way we can solve Collatz Conjecture

worn fox
#

?

alpine sable
#

Collatz conjecture is based on positive integers

lone heartBOT
#

@lime tartan Has your question been resolved?

keen pasture
#

Also there are discussions if 0 is even

abstract fractal
weary wyvern
tacit arch
#

can someone just close this and put me out of my misery

lone heartBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Please take a minute to participate in [our survey](#changelog message) if you haven't already!

lone heartBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

rapid crest
#

How do you solve this? cos(x) + 2sec(x) = -3
I converted sec to tan^2x +1
but figured that wouldn't help
should I change to 1/cosx
and then add left side?

rapid crest
#

I tried doing it with that method and ended up getting no solution

abstract fractal
#

Sec isn't tan²x + 1

rapid crest
#

I think I did wrong

rapid crest
abstract fractal
#

sec²x is, but you don't have sec²x

rapid crest
#

I wrote wrong

#

oh

abstract fractal
#

It's better to turn sec into 1/cos

rapid crest
#

yeah I did that

#

and multiplied by 2

abstract fractal
#

Why multiply by 2

rapid crest
#

but ended up getting cos^2x = -5

rapid crest
abstract fractal
#

Yeah, but that's not being divided

rapid crest
#

multiplied?

abstract fractal
#

2secx = 2/cosx

rapid crest
#

yeah

#

I got that

abstract fractal
#

I don't see how multiplying by 2 simplifies anything

rapid crest
#

what do you with the 2

abstract fractal
#

Nothing. Just leave it there. The more pressing matter is the cos in the denominator

rapid crest
#

I ended up getting cosx + 2/cosx = -3

#

then multiplied by lcm

#

both sides

#

which is cosx

#

and got cos^2x + 2 = -3cosx

#

actually idek anymore

#

I'll send the problem over

abstract fractal
rapid crest
#

my teacher did this

abstract fractal
#

I'd rather know what you did than what your teacher did

rapid crest
#

I did the same thing up to a certain step

#

but didn't get same answer

abstract fractal
#

Be more specific

rapid crest
#

I looked at the answer rn

#

I multiplied by cos(x) on both sides

#

from this cos(x) + 2/cos(x) = -3

#

to cancel out the denominator

abstract fractal
#

Then what?

rapid crest
#

nvm I get it now. Sorry for wasting your time

#

Do you mind me asking more questions in case I get stuck?

abstract fractal
#

That's the point of the help channels, after all

rapid crest
#

sometimes I get confused interpreting my teachers work

#

For a problem like this would you use double angle formulas and try to simplify everything into one value

#

like for example in terms of sin or cosine

abstract fractal
#

You could use double angle formulas, yeah. You would also want to get everything in terms of sines and cosines, generally, because it makes simplification easier

rapid crest
#

I used it and got (cos^2x - sin^2x + cosx +1)/ (2sinx)(cosx) + sinx

#

but don't know what to do afterwards

abstract fractal
#

Notice that cotx = cosx/sinx

rapid crest
#

I could factor sinx on bottom

rapid crest
#

how about left side

abstract fractal
rapid crest
#

would you do sinx

#

to cancel denominator?

abstract fractal
#

Yep

rapid crest
#

There is no need for double angle?

abstract fractal
#

And then almost everything is in terms of cos. Only exception is the sin²x, but you can easily make that cos

rapid crest
#

you use pythagorean identities right

abstract fractal
rapid crest
#

so cos^2x - 1

abstract fractal
rapid crest
#

and then thought of factoring out

rapid crest
abstract fractal
#

Since everything is in terms of cos, all that's left is to solve for cosx

rapid crest
#

alright ima try the problem out and see if I can solve

#

alright I got this

#

(sinx)(cos^2(x) + sin(x)cos(x) + 1 / (sinx) = cosx

abstract fractal
#

Why do you still have a bunch of sines

rapid crest
#

and then if I simplify do I get cos^2(x) + cos(x) + 1 = cos(x)

rapid crest
abstract fractal
#

I don't know what it simplifies to. I don't have any paper nearby and I'm too tired to grab some

rapid crest
#

hmm

#

oh wait that was prove the identity problem

#

should have specified

#

:/

#

just realized rn

abstract fractal
#

Oh

#

Now that changes things

rapid crest
#

yeah

#

we can't mulitply on both sides right

abstract fractal
#

Right

rapid crest
#

just simplify left and right side

#

I think then the double angles would work right

abstract fractal
#

I'm too tired to work this one out. I'm afraid I can't help too much on this one

rapid crest
#

No problem, thanks for the help!

#

I'll ask on another channel and close this one

#

.close

lone heartBOT
#
Channel closed

Closed by @rapid crest

Use .reopen if this was a mistake.

Please take a minute to participate in [our survey](#changelog message) if you haven't already!

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

wind bloom
#

idk how to do 38

lone heartBOT
tacit arch
#

add 360 until you get a positive number

wind bloom
#

but how would i sketch it

tacit arch
wind bloom
#

so 205?

tacit arch
#

,calc -515 + 720

ocean sealBOT
#

Result:

205
tacit arch
#

ya

wind bloom
#

mk thx

#

.close

lone heartBOT
#
Channel closed

Closed by @wind bloom

Use .reopen if this was a mistake.

Please take a minute to participate in [our survey](#changelog message) if you haven't already!

lone heartBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

tight gulch
#

what does exp stand for in this context?

lone heartBOT
tight gulch
fluid basin
#

the exponential function

tight gulch
#

7^(3x)?

fluid basin
#

$exp(x) = e^x$

ocean sealBOT
#

romeofoxtrot

tight gulch
#

oh

#

prof put e for letter a so thats why i got confused

#

thanks

fluid basin
#

where e is euler's number, 2.7818.....

tight gulch
#

oh shit

#

totally forgot

#

haven't done calculus in a minute

#

ty

#

.close

lone heartBOT
#
Channel closed

Closed by @tight gulch

Use .reopen if this was a mistake.

Please take a minute to participate in [our survey](#changelog message) if you haven't already!

fluid basin
#

no problem

lone heartBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

sharp moth
#

How does he know it's increasing or decreasing?

sharp moth
golden bronze
#

are you gr 10

carmine harbor
#

Positive derivative

#

Positive slope

golden bronze
#

do you know trig?

#

does anyone know trig

#

i need help

carmine harbor
#

@golden bronze open your own channel

golden bronze
#

how

tight gulch
sharp moth
#

fprime

#

2x-4 is positive?

carmine harbor
#

It can be positive and negative based on x

#

That’s what helps us find an infection point

#

We set it equal to 0

#

And solve for x

sharp moth
#

Critical point

carmine harbor
#

Oh yes sorry it’s critical point

#

Inflection point is 2nd derivative and curvature

#

We then look the behaviour

#

To the “left” of x when x sets the function to 0 and the “right”

#

And that tells us if it’s a max or a min

carmine harbor
#

If the slope of the tangent line is always positive

#

The function is always increasing

sharp moth
#

If you were to graph it, it would be a tangent line

carmine harbor
#

Yes the derivative of a point

#

Is the slope of the tangent line at that point

#

If the derivative is 0

#

What does that mean about the function ?

#

It is neither increasing or decreasing at that point

#

This is a critical point because it often means that the function is switching from increasing to decreasing or vice versa

sharp moth
carmine harbor
#

Okay so he finds the critical point first

sharp moth
#

This part has me confused

carmine harbor
#

Than he looks to the left of the critical point

#

X=2

#

So he finds an x that is less than 2

#

Let’s say 1

#

Plug 1 into the function

sharp moth
#

and just graphs it

carmine harbor
#

And the the answer is negative

sharp moth
#

and from that he determines if it is increasing or decreasing.

carmine harbor
#

So we know it’s decreasing

carmine harbor
#

You look at local behaviour of critical point

sharp moth
carmine harbor
#

We put in a value lower than x=2

#

So say our critical point is 2

#

Which it is in this case

#

We would see what happens to x=1 and x=3

#

So we first try x=1

sharp moth
carmine harbor
#

Yeah it looks easier that way we are just conditioned left to right

sharp moth
carmine harbor
#

So our equation for the first derivative is 2x-4

#

Plug in x=1

#

2-4=-2

#

So the function is decreasing

#

Plug in x=3

#

6-4=2

#

Function is increasing

#

Does that make sense?

#

You really need to understand what a derivative is

sharp moth
#

slope of a tangent line at a particular point

#

so when you plug in x what are you doing to that original derivative equation?

carmine harbor
#

You are evaluating the derivative at a particular point

#

Of x

#

You are finding the slope of the tangent line at a point x

#

When our derivative is positive our function is increasing

#

When it’s negative it’s decreasing

#

Does this make sense to you

#

When our function is decreasing the derivative is negative when it’s increasing the derivative is positive

sharp moth
#

Yes, I do understand

sharp moth
#

.close

lone heartBOT
#
Channel closed

Closed by @sharp moth

Use .reopen if this was a mistake.

Please take a minute to participate in [our survey](#changelog message) if you haven't already!

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

sharp moth
#

Is this question asking me to find 8 critical points?

abstract fractal
#

I don't think there's necessarily 8, but yeah, find all the critical points

lone heartBOT
#

@sharp moth Has your question been resolved?

#
Channel closed

Closed by @sharp moth

Use .reopen if this was a mistake.

Please take a minute to participate in [our survey](#changelog message) if you haven't already!

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

slim fern
lone heartBOT
slim fern
#

I've gotten so far as to find that there are 13! ways to arrange all the chairs around the tables.

#

I also know that there are 14*13 ways to find a pair of chairs (including opposites)

#

But I'm not sure where to go from there

copper stone
placid zinc
#

There's 14 ways to choose the first chair, and 12 ways to choose the second. Since order doesn't matter, I am double counting. So, I divide by 2 to fix

#

14×12/2

slim fern
#

OH OMG

#

I COMPLICATED IT SO MUCH

#

YEAH I THINK THATS THE ANSWER

#

tysm guys!

copper stone
#

yeah both make 84

#

no problem

slim fern
#

😂 👍

#

.close

lone heartBOT
#
Channel closed

Closed by @slim fern

Use .reopen if this was a mistake.

Please take a minute to participate in [our survey](#changelog message) if you haven't already!

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

real gazelle
#

I have a sequence $$s_1 = \sqrt2$$ and $$s_{n+1} = \sqrt{2 + \sqrt{s_n}}.$$
Does anyone have any bloody idea how to prove that $$s_{n+1} > s_n?$$
Only hints necessary, you don't have to give the answer.

real gazelle
#

I've noticed just by graphing it that $$\sqrt{2 + \sqrt{s}} > s$$ is true for all positive $s$ less than the fixed point

copper stone
real gazelle
#

How does induction help here

#

oh wait it's supposed to be s_n my bad

ocean sealBOT
#

Eric Tao (he/him)

real gazelle
#

fixed the typo

copper stone
#

induction makes it trivial

#

try it, you will see that the result comes directly @real gazelle

#

if not i will help

real gazelle
#

do you mean you want me to show that s2 > s1 and that if s_n+1 > s_n then s_n+2 > s_n+1

copper stone
#

yep

real gazelle
#

aight

ocean sealBOT
#

Eric Tao (he/him)

real gazelle
#

ohh okay

#

figured it out thanks!

#

.close

lone heartBOT
#
Channel closed

Closed by @real gazelle

Use .reopen if this was a mistake.

Please take a minute to participate in [our survey](#changelog message) if you haven't already!

real gazelle
#

that's really neat

lone heartBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

lapis juniper
#

i must be dumb or smth but I can't prove this

lapis juniper
#

sorry it's in french but it says "Prove that, if n ∈ N, there exists an odd integer λ_n such that :"

#

I tried an induction (idk if it's the right word ?) but I cant pass the heredity part

#

$$5^{2^{0}} = 5$$ and $$1+\lambda_0 2^{0+2} =5$$ with $$\lambda_0=1$$ so P(0) is true

ocean sealBOT
#

Elayos

lapis juniper
#

then let's fix an n such that P(n) is true

#

$$5^{2^{n}} = 1+ \lambda_n 2^{n+2} $$

ocean sealBOT
#

Elayos

lapis juniper
#

$$\iff 25\times5^{2^{n}} = 25 + \frac{25}{2}\lambda_n2^{n+3}$$

ocean sealBOT
#

Elayos

lapis juniper
#

$$\iff 5^{2^{n+1}} = 1 + 24 + \frac{25}{2}\lambda_n2^{n+3}$$

ocean sealBOT
#

Elayos

lapis juniper
#

but i cant go further

#

<@&286206848099549185>

#

well I guess nobody likes my exercise 🥲 its ok

lone heartBOT
#

@lapis juniper Has your question been resolved?

novel night
#

In the inductive case, are you saying $5^{2^{n+1}} = 25\times 5^{2^n}$? Because it should be $\left(5^{2^n}\right)^2$.

ocean sealBOT
#

daveamayombo

novel night
#

I think I'd also rephrase the problem as showing $5^{2^n} - 1$ is divisible by $2^{n+2}$.

ocean sealBOT
#

daveamayombo

lapis juniper
#

oooooh yeah I forgot about the brackets my bad

#

thanks for pointing out the hole

#

okay I succeeded thanks !

novel night
#

👍

lapis juniper
#

.close

lone heartBOT
#
Channel closed

Closed by @lapis juniper

Use .reopen if this was a mistake.

Please take a minute to participate in [our survey](#changelog message) if you haven't already!

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

copper heron
#

what is x if

lone heartBOT
copper heron
#

sin 40degrees = 60/x

#

.close

lone heartBOT
#
Channel closed

Closed by @copper heron

Use .reopen if this was a mistake.

Please take a minute to participate in [our survey](#changelog message) if you haven't already!

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

frosty venture
lone heartBOT
frosty venture
#

does this graph work given those limits and points?

#

ignore the lines in the top left

lone heartBOT
#

@frosty venture Has your question been resolved?

tribal oxide
#

Then this graph fails the vertical line test

#

So not a function

frosty venture
#

oh rip

#

one sec ill fix it

frosty venture
#

because with the infinities doesnt it not pass it automatically?

tribal oxide
#

Look at the graph of y=1/x to check how they work

frosty venture
#

like this

tribal oxide
frosty venture
#

gotcha one sec

frosty venture
# tribal oxide

im confused on how to do it with 4,-3 with it going to positive infinity from the right side

frosty venture
#

wait

#

is this correct?

tribal oxide
#

U should mark points on the x axis

#

Y as well

frosty venture
#

👌

tribal oxide
#

No it doesnt seem correct 🤔

frosty venture
#

oh rip

tribal oxide
#

Where is the lim x-->-4-?

#

Also f(-4)=1

tribal oxide
frosty venture
#

lol ight

frosty venture
#

wait nvm

tribal oxide
frosty venture
#

ya

tribal oxide
#

No its the opposite

frosty venture
#

-4,1

#

ya lol

tribal oxide
#

Also im not sure what the point discontinuity at (4,-3) is doing, but its not a problem as it wont make the question wrong

frosty venture
#

ty

#

one sec ima try graphing this thing again

#

this is what i got before graphing the lines

#

woudl the infinities be switched around?

tribal oxide
#

Why do you think they wud be switched around tho

frosty venture
#

the negative means theyre coming in from the left or going to the left?

tribal oxide
#

Which negative

frosty venture
#

x-->5^-

tribal oxide
#

5- means we are approaching 5 from the left side

frosty venture
#

so that looks good then?

tribal oxide
#

Yes

frosty venture
tribal oxide
#

Yes

frosty venture
#

how would i connect these two on the left?

#

without failing vertical line

tribal oxide
#

They arent meant to be connected

frosty venture
#

gotcha

#

final product look good?

tribal oxide
#

For continuity at a point a,we need lim x-->a f(x) =f(x). Here lim doesnt exist

tribal oxide
frosty venture
#

have a good one

frosty venture
#

is there even a way b/c for the upcoming quiz we get a similar problem and we have to prove it

#

is there a way to plug it into desmos?

#

@tribal oxide

frosty venture
#

.close

lone heartBOT
#
Channel closed

Closed by @frosty venture

Use .reopen if this was a mistake.

Please take a minute to participate in [our survey](#changelog message) if you haven't already!

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

neat sierra
lone heartBOT
neat sierra
#

does does gker phi = hker phi => h{-1}g in ker phi?

#

its probably sth really basic, i just dont remember

merry depot
#

multiply by the left inverse of h

neat sierra
#

$h^{-1}g \ker \phi = \ker \phi$

merry depot
#

then h^(-1)gker(phi) is a coset of ker(phi) that is equal to ker(phi)

ocean sealBOT
merry depot
#

so h^(-1)g must be in ker(phi)

neat sierra
#

since ker phi is a group?

merry depot
#

subgroup of G

#

yeah

neat sierra
#

yeah ok that makes sense

#

thanks

#

.close

lone heartBOT
#
Channel closed

Closed by @neat sierra

Use .reopen if this was a mistake.

Please take a minute to participate in [our survey](#changelog message) if you haven't already!

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

obtuse quarry
#

how do i do 1.c) ?

lone heartBOT
median oar
#

im just gonna assume we're talking projectile motion in highschool

#

so it's a parabola

#

we can pin a unique parabola with 3 distinct points

#

we wanna construct a function here that's h(t)

#

height as a function of time

obtuse quarry
median oar
#

the 3 points we know are,
on start t=0, h = 25
when t =2, h = 45
and t=5, h=0

#

with this information we can make our parabola

obtuse quarry
#

ur awesome thanks

#

.close

lone heartBOT
#
Channel closed

Closed by @obtuse quarry

Use .reopen if this was a mistake.

Please take a minute to participate in [our survey](#changelog message) if you haven't already!

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

neat sierra
#

why is xnx^{-1} in H?

lone heartBOT
neat sierra
#

x is an element in G right, not neccecerily in H. So how do we know xnx^{-1} is in H for sure

#

ok nvm

#

.close

lone heartBOT
#
Channel closed

Closed by @neat sierra

Use .reopen if this was a mistake.

Please take a minute to participate in [our survey](#changelog message) if you haven't already!

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

chrome olive
#

Looking into compound interest and I'm a bit stumped:

Trying to figure out how to increase Deposits/Withdrawals by a %/(or flat numerical increase) every year & tie that into figuring out what will the total be after x years

lone heartBOT
#

@chrome olive Has your question been resolved?

lone heartBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Please take a minute to participate in [our survey](#changelog message) if you haven't already!

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

#
Channel closed

Closed due to the original message being deleted

Please take a minute to participate in [our survey](#changelog message) if you haven't already!

covert juniper
#

I’m looking at the proof of this theorem, I understand everything expect why we can conclude that the n element a^0,…,a^{n-1} are unique? Thanks

novel night
#

a has order m, so a^m is the first power of a that equals 1. And n is less than or equal to m.

lone heartBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

covert juniper
novel night
#

Correct. That's true for any a, in any group, where m is the order of a.

covert juniper
novel night
#

Because the group is generated by x, which has order n... so there are n elements total in the group. If you list n distinct elements like a^0, ... a^(n-1), you must have listed every element in the group.

covert juniper
#

Thanks!

#

.close

lone heartBOT
#
Channel closed

Closed by @covert juniper

Use .reopen if this was a mistake.

Please take a minute to participate in [our survey](#changelog message) if you haven't already!

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

tropic oasis
#

how do i solve this?

lone heartBOT
tropic oasis
#

lim is pi/4 to pi/2

#

i’m stuck

vale wigeon
#

a substitution almost suggests itself

tropic oasis
#

cosx?

vale wigeon
#

u := sin(x) is what i would've gone with.

tropic oasis
#

it's sin^2(x)

#

oh wait

#

that's equivalent to

#

(sin(x))^2?

#

so i can use chain rule on that?

vale wigeon
#

sin^2(x) is (sin(x))^2 yes

#

are you familiar with substitutions in general

tropic oasis
#

i did two problems previous

#

i just

#

dont really like

#

understand them when they get complex

vale wigeon
#

ok so substitute u := sin(x) as i suggested

#

du = cos(x) dx

#

so you will have $\int_{\sin(\pi/4)}^{\sin(\pi/2)} \frac{1}{u^2} \dd{u}$

ocean sealBOT
tropic oasis
#

how did we move the sin into the limits?

#

i'm at

#

du/cosx = dx

#

oh wait

#

i’m here

vale wigeon
#

do not forget to recalculate your bounds

tropic oasis
#

i cant seem to figure out how

#

the sin moves to the limits

vale wigeon
#

in a definite integral when you substitute u := g(x) the bounds go from [a, b] to [g(a), g(b)]

tropic oasis
#

oohhh

#

okay

#

so whatever i set for u

#

is the function that i apply onto the limits?

vale wigeon
#

yes thats what i said

#

look up "substitution in definite integrals"

tropic oasis
#

ohh okayy

tropic oasis
#

and i guess now i solve the limits

#

and subtract one from the other?

vale wigeon
#

bad wording

tropic oasis
#

i plug in b and a into my du

#

and subtract b plugged in from a plugged in?

vale wigeon
#

...

#

still bad wording

#

there exists a charitable interpretation that makes what you said correct but it is kind of a stretch

#

you have your integral

#

$\int_{1/\sqrt{2}}^{1} \frac{\dd{u}}{u^2}$, now calculate it

ocean sealBOT
tropic oasis
#

isnt sin(pi/4) = sqrt(2)/2

tacit arch
#

,calc sqrt(2/2)

ocean sealBOT
#

Result:

1
lone heartBOT
#

@tropic oasis Has your question been resolved?

lone heartBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Please take a minute to participate in [our survey](#changelog message) if you haven't already!

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

fervent marsh
#

can somebody help me please

lone heartBOT
fervent marsh
#

.close

lone heartBOT
#
Channel closed

Closed by @fervent marsh

Use .reopen if this was a mistake.

Please take a minute to participate in [our survey](#changelog message) if you haven't already!

fervent marsh
#

nvm

#

i don’t need it

lone heartBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

sterile stone
lone heartBOT
sterile stone
#

is there a difference between radians and degree

#

when answering this

#

actually im not sure how to answer this

#

sin would be 10sqrt3/20 right

woeful pulsar
#

sin of R? opposite over hypotenuse

gray isle
#

sin would be 10sqrt3/20 right
no

#

recall your sohcahtoa

sterile stone
#

opposite over hypotenuse

#

I thought the opposite would be 10sqrt3

gray isle
#

10sqrt(3) isn't opposite of R

sterile stone
#

oh

#

so 10/20

#

so just 1/2

gray isle
#

where did your confusion of the opposite side come from

lone heartBOT
#
Channel closed

Closed by @sterile stone

Use .reopen if this was a mistake.

Please take a minute to participate in [our survey](#changelog message) if you haven't already!

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

sterile stone
lone heartBOT
sterile stone
#

just want to know if i did this right

lethal tendon
#

seems that you read your 16 as 10

sterile stone
#

alright

sterile stone
#

is it right

lethal tendon
#

looks good to me

sterile stone
#

alright thanks

#

.close

lone heartBOT
#
Channel closed

Closed by @sterile stone

Use .reopen if this was a mistake.

Please take a minute to participate in [our survey](#changelog message) if you haven't already!

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

native blaze
#

Why is 0.9 repeting equal to 1?

lone heartBOT
vale wigeon
#

are you familiar with geometric series?

#

and with infinite series in general, which is the means by which infinite decimals (repeating or otherwise) are given meaning?

native blaze
#

as in an arithmetic series with a common ratio?

vale wigeon
#

i don't know what you mean by "arithmetic series with a common ratio"

#

but anyway

#

0.9999... is the sum of the geometric series 0.9 + 0.09 + 0.009 + 0.0009 + ...

#

the first term is 0.9 and the common ratio is 0.1

native blaze
#

Yes but that series does not end

#

So to say there is a sum is moot

#

It has a limit

#

Proof: Assign each term of the series to the smallest known particle in the universe. Then; there exists no size particle such that the number of terms in the series is exhausted. Thus, the existence of infinite series is disproven.

vale wigeon
#

.........

#

what

keen socket
vale wigeon
native blaze
#

That is "crank" to me

weary wyvern
#

man's trying to sound like einstein from that nat geo show

vale wigeon
#

no, i never said that

#

don't put words in my mouth

native blaze
#

Let me describe more concretely what I mean

vale wigeon
#

the sum of an infinite series is defined to be the limit of its partial sums, if said limit exists.

#

it is not "moot" to say that an infinite series has a sum.

native blaze
#

But there exists no number, not even grahams number, amount of terms that can satisfy the limit sum

vale wigeon
#

so what

native blaze
#

If I ask you what pi plus e is, can you give me an answer?

vale wigeon
#

sure

#

π+e

native blaze
#

exactly

vale wigeon
#

if you want it to however many decimal places, tell me how many

native blaze
#

however many = pi plus e

#

see

vale wigeon
#

?

#

sorry, let me restate what i said.

#

if you want it to some number of decimal places, tell me how many decimal places you want.

#

that's got to be a natural number, for obvious reasons, but if you're going to give me something other than that i'll round to the nearest integer anyway.

native blaze
#

I want the number of decimal places it takes such that if it were on the left side of the equation, it would equal pi plus e on the right

#
#

This is not "crank", here this mathematician explains it

#

proofs have constructive content, and what you get out of these constructions isn't much more than you put in.

mortal trellis
native blaze
#

A(0)∧(∀x.A(x/2)⇒A(x))⇒∀x.A(x)

Then any proof of a forall-exists statement has to be realized by a polynomial time computable function.

#

Explain this then

native blaze
#

If this is too complex a question I apologize, I am a grad student

sleek gyro
#

its not too complex a question

#

but your objection, as wildberger's, is not mathematical

#

this is purely a philosophical objection

#

wildberger rejects certain axioms and constructions purely on philosophical opinion

#

which he is, as you are, allowed to do

#

however if you ask a question on this server, everyone will assume that you do the "standard" mathematics, that everyone else (save wildberger and a few other people) are doing

native blaze
#

So? Math is made foundational off of set theory which is based off of the peano axioms

#

Its not too far a stretch to ask foundational mathematical questions, no?

sleek gyro
#

so what is your question?

native blaze
#

a reasonable objection to ultrafinitism

#

I am not aware of any and would like an explanation

sleek gyro
#

this is not a mathematical question

#

the answer is "I dont want to do this kind of mathematics, i like what i am doing currently"

native blaze
#

Ok then, in the future I will note to not ask foundational questions and limit the remit of my queries

#

.close

lone heartBOT
#
Channel closed

Closed by @native blaze

Use .reopen if this was a mistake.

Please take a minute to participate in [our survey](#changelog message) if you haven't already!

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

main ether
lone heartBOT
main ether
#

i understand that im supposed to find all the numbers that dont have a 5 or 7

#

and then subtract that from the total outcomes

main ether
frigid rune
#

like normally each digit could be 0, 1, 2, 3, 4, 5, 6, 7, 8, 9 ( except the first digit which cant be 0 )

#

which gives you 9 * 10 * 10 * 10 = 9000 total 4 digit numbers

main ether
#

ahhhh yes that makes sense, i will try it now

#

give me a moment

#

ok so i tried this

first digit: cannot be 0, 5 or 7 therefore 7 choices
second: cant have 5 or 7 therefore 8 choices
third: cant have 5 or 7 therefore 8 choices
fourth: cant have 5 or 7 therefore 8 choices

so 7 * 8 * 8 * 8 = 3584

frigid rune
#

yep

main ether
#

9000-3584=5416

frigid rune
#

correct

main ether
#

my dude thank you so much

frigid rune
#

np

main ether
#

this is the first time ive asked for help in the server lol

#

i really appreciate it, you made it really clear to understand

#

.close

lone heartBOT
#
Channel closed

Closed by @main ether

Use .reopen if this was a mistake.

Please take a minute to participate in [our survey](#changelog message) if you haven't already!

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

native cloud
#

Why isn't this online platform accepting my answer?

frigid rune
native cloud
#

Ohhh

#

It worked

#

Thanks

#

.close

lone heartBOT
#
Channel closed

Closed by @native cloud

Use .reopen if this was a mistake.

Please take a minute to participate in [our survey](#changelog message) if you haven't already!

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

viscid moat
#

hello how can i find the image of this matrix

viscid moat
#

ImT

vale wigeon
#

Im(T) is the span of [1;0;1;0], [1;1;1;1] and [2;1;2;1]

viscid moat
#

wait thats it ?

woeful pulsar
#

$\Lambda$ and $\Phi$ are bases

ocean sealBOT
#

Element118

viscid moat
#

the base thing is whats confusing me

#

okay lets say i found Im(T)

#

and i wanna find Ker(T)

woeful pulsar
#

it's all vectors in the domain that go to 0

viscid moat
#

so in order to find it i gotta put the matrix i have equal to a zero's matrix

#

and i gotta find its rank or something ?

lone heartBOT
#

@viscid moat Has your question been resolved?

mortal trellis
#

solve the system Tx=0

#

with row reduction

lone heartBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Please take a minute to participate in [our survey](#changelog message) if you haven't already!

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

native blaze
#

if i quantify x over a set, what is the term of the set in relation to x?

native blaze
#

would the set be the domain of x?

native cloud
#

Elucidate please

native blaze
#

ok

#

if x is quantified over the real numbers, can I say x is in the domain of R

#

or that the domain of x is R

#

@native cloud

weary wyvern
#

if i quantify x over a set
what does that even mean

native cloud
#

I don't understand either

native blaze
#

As in if I want to prove a property of x, I need to quantify it first

#

like saying for all x is an element of the reals, x + 1 > x

#

Have you never encountered the words "For All" or "There exists" in math?

#

That is quantifying a variable

alpine sable
weary wyvern
#

to quantify something, you need a statement involving x like P(x)

native blaze
# alpine sable yeah probably

Ok, thank you. I find it funny how @native cloud and @weary wyvern , two helpers with the tag "advanced", have never come across set quantification which I am learning as a freshman

weary wyvern
#

i haven't heard the term "quantification" much

#

but ofc i know what for all and there exist means

native blaze
weary wyvern
#

i assumed by "quantifying" x you meant saying "for all x in a set" or "there exists an x in a set" such that ...

native blaze
#

yea

weary wyvern
#

? so you need a P(x)

native blaze
#

or just stating x is an element of a set

#

that is quantifying too

#

but doesn't specify a P(x)

weary wyvern
#

alright sure

#

x is an element of some set

#

what's ur question

native blaze
#

if that is possible

#

which seems like you said yes to

#

.close

lone heartBOT
#
Channel closed

Closed by @native blaze

Use .reopen if this was a mistake.

Please take a minute to participate in [our survey](#changelog message) if you haven't already!

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

mortal latch
#

gigaclaim

lone heartBOT
mortal latch
#

for formal languages/grammar/regular expressions

#

for this regular language:

#

what does the + change? is it the same as just L(((01111)*(00)*)*)

#

like for this previous question:

#

i can tell it has to start with 0, then can have none or infinite '11's afterwards, then none or infinite of both of those together

#

but with the first thing i posted i feel like im missing something

#

omg nevermind the + means OR

lone heartBOT
#

@mortal latch Has your question been resolved?

#
Channel closed

Closed by @mortal latch

Use .reopen if this was a mistake.

Please take a minute to participate in [our survey](#changelog message) if you haven't already!

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

verbal elbow
#

Hi whats the fourth root of the cube root of the square root of 2^24?

verbal elbow
#

I put 2 on the test (the test is over im not cheating)

#

also looking how to solve it not just an answer which i could get from google

alpine sable
#

$\sqrt[4]{\sqrt[3]{2^{24}}}={\sqrt[3]{2^{24}}}^{\frac{1}{4}}={{{2^{24}}^{\frac{1}{3}}}^{\frac{1}{4}}={{2^{24}}}^{\frac{1}{12}}=2^2$

ocean sealBOT
#

Toby
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

verbal elbow
#

thank you

alpine sable
#

forgot the squareroot

verbal elbow
#

yeah

alpine sable
#

(2 is correct)

verbal elbow
#

but i get the idea

#

thanks

alpine sable
#

yw :)

verbal elbow
#

.close

lone heartBOT
#
Channel closed

Closed by @verbal elbow

Use .reopen if this was a mistake.

Please take a minute to participate in [our survey](#changelog message) if you haven't already!

lone heartBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

alpine sable
lone heartBOT
alpine sable
#

How I can derivate it again
Specially to 3/(3X+3y)??

worn fox
#

chain rule

#

its 3(3x+3y)^-1

alpine sable
#

Oh okay!!

#

Thnko

#

.close

lone heartBOT
#
Channel closed

Closed by @topaz moth

Use .reopen if this was a mistake.

Please take a minute to participate in [our survey](#changelog message) if you haven't already!

lone heartBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

alpine sable
lone heartBOT
alpine sable
#

Right, so I've tried the obvious thing of considering every combination of 3 points being on the grid of 4x4, which is 16C3

#

...And from there I suppose I must eliminate triangles which can't be formed. But I'm not sure how to go about doing that

#

well you need to make sure the vertices are not colinear

#

Okay, so that will eliminate 3 points lying on the same row/column, right?

#

Oh wait, so I do 4C3 to figure out how many ways that can happen for each row

#

yeah, and diagonal

#

the harder ones to count are the diagonals

#

Yep, and and multiply by...

#

10, 4 for the row, 4 for the column, 2 for the 4 pointed diagonals

#

And then the uhhhh 3 pointed diagonals

#

Which are in 4 rotations

#

Oh that makes so much sense

#

Thank you

#

so 16C3 - 10(4C3) - 4

#

.close

lone heartBOT
#
Channel closed

Closed by @lethal root

Use .reopen if this was a mistake.

Please take a minute to participate in [our survey](#changelog message) if you haven't already!

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

pliant oxide
lone heartBOT
pliant oxide
#

how do u solve for x and y for this?