#help-0

1 messages · Page 1 of 1 (latest)

scarlet shore
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Hello, I have been searching on the internet but couldn't find anything relevant, is there any formula for sum of n square roots?

scarlet shore
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I mean this

mortal trellis
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,w sum_{n=1}^k sqrt(n)

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doesn't seem like it

karmic rapids
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-ζ(-1/2, n + 1) - ζ(3/2)/(4 π)

scarlet shore
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That's Riemann's function rigth?

karmic rapids
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yes

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zeta function

scarlet shore
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Im in grade 10 lol

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Thanks anyway

karmic rapids
scarlet shore
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I mean thats kinda advanced

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Most advanced thing I know is partial derivatives

karmic rapids
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just cuz you're in 10th grade doesn't mean you shouldn't know advanced stuff

scarlet shore
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I know, just wanted to note I don't

lean depot
lone heartBOT
#

@scarlet shore Has your question been resolved?

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normal bridge
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alpine sable
normal bridge
alpine sable
#

u need to be a biit careful and use the fact that $ky \neq 0$

ocean sealBOT
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∆y/∆x=sin(x) + cos(y)

alpine sable
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tho

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if that's what u were confused of

normal bridge
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is xy correct?

alpine sable
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indeed yes

normal bridge
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WOOOOO ty

#

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normal jasper
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any hints or pointers on how i could approach this question?

hollow shale
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What is 94^2?

alpine sable
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hint: the square root of 8881 is <95

normal jasper
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hmm

keen bear
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what do you know regarding the properties of primes? There are ways to determine this by just checking all primes for divisibility by brute force, but that doesn't seem very elegant

normal jasper
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im still a bit stuck, so there being a bound on the square root of the number would mean that if u list out pairs of factors it would be less than 95?

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i honestly dont know much about primes except the standard definition

keen bear
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a particular fact about the prime factorization of a composite number is that it is guaranteed to have at least one factor less than its square root

prime badge
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it's a bit simpler i think

normal jasper
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yea id have never gotten that

keen bear
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it probably is, since that's the brute force method

prime badge
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it says prove by contradiction, the alternative would mean that all factors are 97+
is it one 97+? no it's not prime!
is it two 97+? no that's already more
proved it

normal jasper
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i assume the solution is a bit simpler since this was a problem given after the first 10 pages or so of an "intro" to pure mathematics

keen bear
# normal jasper yea id have never gotten that

it's the multiplicative equivalent to the fact that every number can be written as the sum of two numbers of the form A+-x where A is the average and x is some distance away, and they always come in these pairs

keen bear
prime badge
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what do you mean

keen bear
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oh, given that it's composite

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nvm

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the text of the question contains the scope of the question

normal jasper
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hmm i think maybe it is enough to say that the next greatest prime is 97 and if there are no prime factors less than 89, then the least number u can get with primes above 97 is 97*97.

hollow shale
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the factors "revolve" around the sqrt of the number

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any factor > sqrt has the other factor be < sqrt
any factor = sqrt has the other factor be = sqrt

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in either case, there must exist a factor that is <= sqrt

prime badge
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that's too hard

hollow shale
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and since you're looking for primes, that factor is at most 89

vale wigeon
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d < sqrt(n) => n/d > sqrt(n)

north perch
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8881 =

vale wigeon
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easier expressed symbolically

north perch
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we can try to find some squares whose difference is 8881

real gazelle
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why?

north perch
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to find the factors

lean depot
real gazelle
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the question doesn't ask to find the factors

hollow shale
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you're not supposed to find the factors

vale wigeon
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got a feeling it might be a little overkill

lean depot
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Ah wait in fact it doesn't, nvm

vale wigeon
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the idea is you're not supposed to compute much, if anything

hollow shale
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just argue the existence

north perch
vale wigeon
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every number has a factor not above its own square root

real gazelle
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every composite number has a prime factor not above its own square root

vale wigeon
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right

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also note the next prime up from 89 is 97

normal jasper
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thank u

#

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alpine sable
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alpine sable
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can anyone help me prove this?

mystic dew
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This involves binomial theorem

alpine sable
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hmm the start point is the binomial theorem?

mortal trellis
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the left side tells us how many options there are how to select p elements from n+m elements

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can you tell me what (n choose k)*(m choose p-k) tells me?

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keen python
#

can I do this ?

lone heartBOT
keen python
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i calculated the possible limits of a_n+1 = a_n
and came out there is only one, for a = 2

so now I need to show that its really the limit right ?

noble sinew
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If you have done a and b

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You have a theorem that says limit exist

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So no need to do anything else

real gazelle
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kennen Sie der Satz von der monotonen Konvergenz?

keen python
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I will first show that its limited by induction

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should be bounded to 0 <= a_n < 2

real gazelle
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haben Sie schon (a) gelöst?

lone heartBOT
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@keen python Has your question been resolved?

keen python
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@real gazelle

real gazelle
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right and then how do you prove it is positive

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er nonnegative

keen python
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I think that would be correct ?

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timber sparrow
lone heartBOT
timber sparrow
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feeling kind of braindead today, can't seem to visualise the bottom angle being 2theta

clear stump
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Im braindead too

timber sparrow
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any quick explanation is appreciated

lone heartBOT
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@timber sparrow Has your question been resolved?

timber sparrow
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nvm I figured it out. brain just stopped working

#

.close

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lone heartBOT
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solemn basin
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solemn basin
#

nvm i kinda understand it

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.close

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rose blade
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im ngl im very confused idek what im doing i was just doing random math

rose blade
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can some1 help

last ether
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Do you know derivatives?

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Otherwise you just gotta find the vertex if it ends up being a quadratic

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$$2L + W = 68$$
$$A = LW$$

ocean sealBOT
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Umbraleviathan

last ether
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Just express A in terms of L

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@rose blade

vale junco
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How would he find A then tho

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@rose blade Has your question been resolved?

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rose blade
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ohh woops i did 2 w by accident

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so 2l + 4

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w

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= 68

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aight

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But the stuff I did, was it right?

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Like the way i solved for area

lone heartBOT
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rose blade
#

bruh

lone heartBOT
rose blade
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so it wouild be L= 34 - w/2

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or L=34 - 0.5 w

rose blade
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would u be able to explain

keen socket
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2L+W=68

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68-2L=W

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A=LW

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A=L(68-2L)

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A=68L-2L^2

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dA/dL=68-4L

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dA/dL=0

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4L=68

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L=68/4

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2(68/4)+W=68

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@rose blade

rose blade
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whats da/dl and where did the 4 come from

keen socket
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i differentiated

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to get max area

last ether
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Not without using limits which you probably don't know

rose blade
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to get the max i think my teacher wants me to find the vertex by converting the equatioon into vertex form

last ether
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Here lemme write it down

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Write how to solve this without differentiation

rose blade
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I learned what differentiation is

keen socket
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lol

rose blade
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i get where the 4 came from now

last ether
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Damn okay then

rose blade
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Oh

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sorry

last ether
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I mean I was gonna write like

rose blade
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u can still write it

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cus im still confused

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just curious if any of u guys actually solved it is the area 578?

last ether
#

First, construct a set of equations based off given information:

$$2L + W = 68$$
$$A = LW$$

We can rearrange the first equation so that $W = 68-2L$. Then we get:

$$
\begin{align*}
\begin{split}
A &=L(68-2L) \
& = -2L^2 + 68L
\end{split}
\end{align*}
$$

You need to find the vertex. If $(h, k)$ is the vertex of quadratic polynomial ${\color{lime}{a}}x^2 + {\color{cyan}{b}}x+{\color{orange}{c}}$, then $h = -\frac{{\color{cyan}{b}}}{2{\color{lime}{a}}}$. We can rewrite A:

$$A = {\color{lime}{-2}}L^2 + {\color{cyan}{68}}L + {\color{orange}{0}}$$

You can now find the vertex which will give you maximum area and the dimensions.

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Bruh

rose blade
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what are the dollar signs

last ether
#

Except it's breaking

rose blade
#

oh ok

ocean sealBOT
#

Umbraleviathan
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

last ether
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There

rose blade
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yeah thats what i thought

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but u guys had me confused

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everyone is so high level in this server

rose blade
last ether
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Yeah

rose blade
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bruh

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thats all i neeeded

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Thank you anyways tho

keen socket
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completing the square is boring

rose blade
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i have to do

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tho*

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cus thats the unit where doing rn

keen socket
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oh gl

rose blade
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thanks

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is the vertex (5.83,17) and if not can someone please check to see where i went wrong

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sorry

keen socket
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is it not (17,578)

rose blade
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i thoight the area was 578

keen socket
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but our equation was A=-2L^2+68L

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so if we were graphing we would plot L on the x axis and A on the y axis

rose blade
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im so confused now because the ewquation i used previously worked to find the area but the vertex is wrong

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yeah

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ok nvm imma jus re do this

rose blade
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but

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ok so i get 17 for x or the length, then if u pluf that back into 2l-68 u get -34 which doesnt make sense

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oh no

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no

keen socket
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-2L^2+68L

rose blade
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tes tyes

vague cedar
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isn't it (68-34)/2 which gives the width which is 17?

rose blade
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yep i alr got 17

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then i got 34

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so the area is 578

vague cedar
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good job

rose blade
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tyty

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it was all them tho

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.close

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#
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tired osprey
#

Julia launched a rocket vertically upward from the top of a cliff. The height of the rocket above the base of the cliff is approximated by the model h=-5t^2+30t+20, where "h" is the height in meters, and "t" is the time in seconds

A) how high is the cliff?

B) After how many seconds does the rocket hit the ground?

C) When does the maximum height occur?

D) What is the maximum height?

E) When is the rocket at 45m from the ground I'm not sure how to do this i've tried for like 30 mins and i can't figure it out and its due in 45 mins

alpine sable
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so what have u tried?

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let's start with letter A, ok?

tired osprey
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i tried to solve the quadratic and figure out the height of the cliff.

alpine sable
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ok, but u don't need to solve it

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just try to think

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at what time the object is on top of the cliff?

tired osprey
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30 seconds

alpine sable
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wait isn't it thrown from the top?

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so at t=0 the rocket is on the top

tired osprey
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i'm not sure it just says this

alpine sable
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well the answer is 20

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but I mean, u just need to substitute the values of t in the equation

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at t=0 the rocket is on top, and then is starts going down

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so if u substitute t=0 into the equation, u'll get h=20

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for the second point, if the rockets hits the ground, what's its height?

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oh sorry, upwards. so it goes up and then down

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well but the answer is the same

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at t=0 the rocket is on the cliff, so h=20

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are u following?

tired osprey
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yeah

alpine sable
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ok

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so let's go to letter b

tired osprey
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ok

alpine sable
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if the rocket hits the ground it means that h=0

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so if h=0 it means that the equation is equal to 0

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so then u just solve the equation 0=-5t^2+30t+20

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u can devide by so 0-t^2+6t+4

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and then u just solve it

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it should give u two solutions, one must be negative and the other is positive

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the answer should be around 6.6

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seconds

tired osprey
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wait so for this you just make h = 0 and solve the rest?

alpine sable
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yep

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bc it hits the ground

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can u follow?

tired osprey
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yes

alpine sable
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perfect

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do u wanna go on?

tired osprey
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yeah

alpine sable
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so

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the equation that u have is the equation of a parabola

tired osprey
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yes

alpine sable
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u can think that t=x and h=y

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so the highest point

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is actually the turning point

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bc the parabole is like a sad face, so it reaches a maximum and then it goes down again

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are u able to follow this?

tired osprey
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yes

alpine sable
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so do u wanna how to calculate the turning point of a parabola?

tired osprey
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yes please

alpine sable
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so u can calculate in a lot of different ways

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the easiest one is t=-b/2a

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where a is the coefficient of t^2 and b of t

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so the t of the maximum high is t=-30/(-5)

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so t=6

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now that u have the time u can calculate the height

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u just need to put t back into the equation

tired osprey
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i see

alpine sable
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so h should be 220

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20*

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meters

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and this is letter c and d

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do u wanna go on?

tired osprey
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yes

alpine sable
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so for the last question

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u know that h=45

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so just substitute into the equation and solve for t

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45=-5t^2+30t+20

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devide by 5

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9=-t^2+6t+4

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rearrange and sum

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t^2-6t+5=0

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and it has twho solutions

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t=5 or t=1

tired osprey
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thank you

alpine sable
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i haven't done any calculations with the calculator

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so check everything

tired osprey
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ok will do

#

thanks for the help tho u really helped me understand this better

#

.close

lone heartBOT
#
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sullen vapor
lone heartBOT
sullen vapor
#

I need to learn how to do proofs with angle congruence

#

<@&286206848099549185>

pearl pagoda
#

∠DHF= ∠DHE+ ∠EHF

∠EHG= ∠EHF+ ∠FHG
but ∠DHF=∠EHG, then…

∠DHE+∠EHF=∠EHF+∠FHG
then ∠DHE= ∠FHG

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∠DHE= ∠2
∠FHG= ∠3
=> ∠2=∠3

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“m” can be reduce.

lone heartBOT
#

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sullen vapor
#

.close

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dusk thorn
lone heartBOT
keen socket
#

,rotate

ocean sealBOT
dusk thorn
#

How do i get to (a+b)(a²+3ab+b²) from here?

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I was able to do it this way

fresh parcel
dusk thorn
#

How???

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Somebody

desert moon
#

that looks like the right method

dusk thorn
#

I wanna know if its possible in this method...if so...how?

desert moon
#

just as you did

#

or do you mean you don't know what you did?

lone heartBOT
#

@dusk thorn Has your question been resolved?

lone heartBOT
#
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azure trout
lone heartBOT
azure trout
#

how would I even do this 😭

echo socket
#

Law of cosines could help

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Although the problem does not mention which sides b and c are but I'd assume c is the one opposite to the angle C and b is the one opposite to the angle B

azure trout
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well thats why it said possible solutions

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so i have to do two triangles

azure trout
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wait

echo socket
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Well applying the law of cosines here yields that c^2 = a^2 + b^2 - 2abcos(C)

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Assuming what I said about the position of b and c is correct*

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So from here you can solve for a

azure trout
#

would I have to do 2 triangles? for all "possible solutions"

echo socket
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Eh yeah, pretty much

azure trout
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but how?

echo socket
#

You mean what cases to consider?

azure trout
#

yes

echo socket
#

I think those are when a is opposite to C, b is opposite to C and when none of them are opposite of C (meaning they're both adjacent to it)

azure trout
#

so theres only one possible solution?

echo socket
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There are 3 cases as I mentioned those

azure trout
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im so confused

echo socket
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Just consider each case separately and those will lead you to the possible answers

azure trout
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how do i even consider those lol

echo socket
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But again I think the author meant that c is the side opposite to angle C

echo socket
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Oh

azure trout
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so its only one triangle?

echo socket
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Then you don't need to consider several cases

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Ye

azure trout
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okay perfect thank you!

#

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echo socket
#

Good luck

lone heartBOT
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sharp moth
#

When do I know how to do the product rule?

sharp moth
#

In this equation, I just multiply the two values together

#

But how do I know the difference between doing that and applying the product rule

#

Is it going to specifically say to use the product rule?

#

Or is it indicated by putting the prime symbol, with yprimex?

crisp grail
#

but its good to use the product rule to practice it i guess

sharp moth
#

Okay sweet thank you.

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stable gazelle
#

Hello

lone heartBOT
stable gazelle
#

I need help please

#

But it’s more for physic than mathematics 😅

dry ridge
stable gazelle
#

I tried to apply the coulomb formula between a helium core and an electron, but I come to a confusion:

#

The strange thing about the coulomb force is that the force exerted by the electron on the nucleus is the same force exerted by the nucleus on the electron. Yet we could say that the force of generated by the electron is 2 times smaller than that generated by the 2 protons of the helium nucleus

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#

@stable gazelle Has your question been resolved?

stable gazelle
#

No but it doesn’t matter no problem

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reef field
#

Small question

lone heartBOT
reef field
#

r^2 = (s/pi/r)^2 - (h^2)
rv^2 = (2s/pi/rv)^2 - (hv^2)
(2 * pi *r) + (2 * pi * rv) = 100
Solve for r, rv, h, and hv
My brain is dead
Pi is pi

iron mulch
#

Schizo this chat is taken

zealous ruin
#

Oh, my bad

#

lol

reef field
#

I just don’t know where to approach this

#

.

#

<@&286206848099549185>

#

If anyone is available

tacit arch
#

4 unknowns but only 3 equations?

#

Maybe you have more information than presented

reef field
#

Doesn’t look like it unless I messed up

tacit arch
#

Show the original question and all your work

reef field
#

Nvm figured it out

#

.close

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reef field
#

I’m an idiot

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fresh parcel
#

im having trouble with this matrix multiplication\

fresh parcel
#

im getting the exact same thing except with a 2 instead of a 10 on the bottom left corner

tacit arch
#

2 is correct

fresh parcel
#

wait why does my book say 10

#

bruh

tacit arch
#

Assuming E32 is the first matrix, E31 is the second matrix, and E21 is the third matrix

fresh parcel
#

yeah

#

how were you able to verify that it was 2 so quickly

tacit arch
#

The first column in E31 is only nonzero in the first entry

#

So you just need to dot the last row of the first matrix with the first column of the second matrix

fresh parcel
#

i see

#

thanks for the help

#

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shell urchin
lone heartBOT
shell urchin
#

I don’t know what to do

tacit arch
#

Use a z score

lone heartBOT
#

@shell urchin Has your question been resolved?

shell urchin
tacit arch
shell urchin
#

I was only guessing

alpine sable
# shell urchin

Well, you know he's below average so his percentile rank is below 50%, so we throw out option 3. But it can't be something absurd like 0.19 or 0.5 given his value is within 1 standard deviation of the mean, so we throw out option 2 and option 4. What are you left with?

#

That's a "multiple choice thinking" way of solving it.

shell urchin
#

Thank you

tacit arch
shell urchin
#

It’s a practice problem because I’m studying so it doesn’t actually count. So I was hoping to learn the process of it since I forgot, but I learn really slow

shell urchin
#

When using the z score formula

tacit arch
#

Show your work

shell urchin
tacit arch
shell urchin
#

Okay

shell urchin
tacit arch
#

Show your z table

shell urchin
#

It doesn’t give me one

shell urchin
#

I tried looking for one

#

But not a good one

tacit arch
shell urchin
shell urchin
#

I know the left is -0.5

tacit arch
#

the top is the number after 5

#

so in your case it's 00 because -0.5 = -0.500

shell urchin
#

Okay

#

I don’t really understand that but okay 😭

#

.3085?

tacit arch
#

then you scan right until you get 0.cd

shell urchin
#

I’m trying to understand 😐 I don’t learn fast

tacit arch
#

oh sorry i was wrong

#

you add 0.cd to a.b

#

0.cd is 0.05 in this case. i guess it's always 0.0d

#

and a.b is 0.2

#

so for the z score of 0.25, you look in the first column for 0.2, then scan that row until you get 0.05 because 0.2 + 0.05 = 0.25

shell urchin
#

Okay

#

I will look at this

#

Ty

shell urchin
tacit arch
shell urchin
#

I understand now

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lucid apex
chrome plank
#

,rotate

ocean sealBOT
#

Retrieving the previous image failed.

chrome plank
#

f

lone heartBOT
#

@lucid apex Has your question been resolved?

chrome plank
#

I made a nice sketch

#

If you zoom in at the sphere's surface and make a very small triangular shape (Something like going outside and drawing a triangle on the ground), the sum of the interior angles will be super close to 180°, and can be approximated very well by a 2D plane

#

But if you make such a big triangle on a sphere, do you expect it's interior angles to be bigger or smaller than 180°?

lucid apex
#

Bigger I think

chrome plank
#

Yes

#

You can choose between 85°, 95°, 175° and 185°

lucid apex
#

Is it 185?

chrome plank
#

Yes, I think so

lucid apex
#

Alr

#

Thanks for explaining this to me I’ve been struggling with this for a while lol. Have a great day!

#

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chrome plank
#

catthumbsup You too!

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forest orchid
#

does anyone know if for the final form of this equation is it possible for n to equal 4

chrome plank
#

What do you mean

#

$\sqrt[4]{x}$?

ocean sealBOT
forest orchid
#

yes

chrome plank
#

Yes of course

forest orchid
#

oh I didnt know for sure because I knew 3 meant it was cubed and 2 it was squared so i wasnt 100% sure if you could use 4 in it

vernal thunder
chrome plank
#

not 0 I think

#

because you have x^(m/n) and n can't be 0

forest orchid
#

0 is pretty much undefined right?

chrome plank
#

0 is defined, the division by 0 is undefined

forest orchid
#

oh yeah right

#

thank you for answering my question

vernal thunder
chrome plank
vernal thunder
#

My mistake

chrome plank
#

thonk m and n can be negative

vernal thunder
chrome plank
#

well I don't think it's super useful, but

#

$x^{-\frac m n }$

ocean sealBOT
chrome plank
#

You would just bring the - to the m instead of the m

#

$x^{\frac {-m} n }$

ocean sealBOT
chrome plank
#

and it becomes\
$\sqrt[n]{x^{-m}}$

vernal thunder
#

Ok so a negative root works

ocean sealBOT
vernal thunder
#

Not m

chrome plank
#

Yes, but because of the definition as x^(m/n)

#

$\sqrt[n]{x^{-m}} = \sqrt[-n]{x^{m}}$

ocean sealBOT
chrome plank
#

because
$x^{\frac {-m} {n}} = x^{\frac{m}{-n}}$

ocean sealBOT
chrome plank
#

Does it make sense?

vernal thunder
#

Alright enough

#

I got it

#

Just used a calculator

chrome plank
#

Nice

#

@forest orchid If you have more questions feel free to ask, otherwise .close the channel

forest orchid
#

.close

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chrome plank
lone heartBOT
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fluid raven
#

help

lone heartBOT
abstract fractal
#

What have you tried

fluid raven
#

Nvm i solved it

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quasi rover
#

Working on a larger problem, I got this as a part of an equation. Wasn't sure how to approach, so plugged numbers in. Got the Bernoulli Triangle sums [(1), 1, 3, 8, 20, 48].

I worked out that the sum permutation on the left -- if isolated -- form the fibonacci numbers, and the isolated sum of the permutation on the right give triangular/tetrahedral/etc. numbers.

Anyways, would like to prove whether or not the summation will give the n-1th Bernoulli number.

quasi rover
#

<@&286206848099549185> I will pay 3 boiled eggs

#

I have tried marking values in Pascal's triangle, but I don't think it works.

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#

@quasi rover Has your question been resolved?

quasi rover
#

<@&286206848099549185>

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#

@quasi rover Has your question been resolved?

fluid raven
#

help

lone heartBOT
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reef lantern
#

are these false?

lone heartBOT
reef lantern
#

hello?

abstract fractal
#

Can you explain why for each?

reef lantern
#

for 1 f'(x) = 0 could just be the graph platueing but it can still carry on in any direction, it doesnt necessarily mean there WILL be a local minimum and max

#

I think

fallen verge
#

could you perhaps draw out what you mean

reef lantern
#

some thing like this

fallen verge
#

yup

reef lantern
#

so 1 is false then

fallen verge
#

yup

#

what about #2? this one is a bit harder

reef lantern
#

ok im confused on 3 now then

#

i said 2 is false for example x^4

fallen verge
#

good example

reef lantern
#

f''(x) is 12x^2

fallen verge
#

that would work yup

reef lantern
#

but 3 i have no idea

fallen verge
#

consider the graph of f'

reef lantern
#

i tried this

#

but would that count as a local minimum

fallen verge
#

#3 is true

#

its a little hard to prove in what i would assume is calc 1?

#

i could be wrong

reef lantern
#

yes this is calc 1

alpine sable
#

In the first case the only case where it's false is when f(x)= constant right

#

?

fallen verge
#

oh true

#

but a cubic also works

alpine sable
#

Oh yes it can be an inflection

reef lantern
#

a cubic for #3

#

?

fallen verge
#

no it would still be a minimum

reef lantern
#

its supposed to be minimum? do u mean absolte?

#

absolute*

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#

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lone heartBOT
#
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dawn ridge
lone heartBOT
dawn ridge
#

,RCCW

ocean sealBOT
dawn ridge
#

what does this question mean and how do i check?

lone heartBOT
#

@dawn ridge Has your question been resolved?

tacit arch
#

Plug in the formula for a_n and a_{n-1} into the recurrence relation

dawn ridge
#

mean?

#

can you tell me little concept first?

#

@tacit arch

tacit arch
#

Do you know how to evaluate a_n for 1,2,3,4?

#

You're given the first value

dawn ridge
#

yes. it comes from o-th term to 3th term

tacit arch
#

There is no 0 index

dawn ridge
#

a1,a2 like that

tacit arch
#

What's a2

dawn ridge
#

3

tacit arch
#

Nope

dawn ridge
#

2

tacit arch
#

Use the given formula and stop guessing

dawn ridge
#

what is mean by one expression is olution recurence of another

#

i just started yesterday so i know some basic term only

tacit arch
#

Did you have a lecture on it?

dawn ridge
#

little bit videos

tacit arch
#

Just means you plug in your given formula into the recurrence relation

#

But you need to understand the formula a_n

dawn ridge
#

an=dan -1

tacit arch
#

You know what $2^n + 1$ means?

dawn ridge
#

so i should each expression by n-1

ocean sealBOT
#

riemann

tacit arch
dawn ridge
#

its a rec reln?

tacit arch
tacit arch
dawn ridge
#

just replace n in 2n + 1 by 1,2,3,&4?

tacit arch
#

yes

dawn ridge
#

so how do i check one reln is recursive reln of another,,..I have solved basic number related problem yet

tacit arch
dawn ridge
#

5,9,17,33

tacit arch
#

Plug a2 and a1 into the recurrence relation to see if it holds

#

a2 = 2 * a1 - 1

#

Repeat for a3 and a2

#

Once you're done with a few values, plug it in for general n and n-1

dawn ridge
#

well ..i will try it , i think i neeed to understand more theoritical concept

#

.close

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main zephyr
#

imagine a chess board and imagine there is only one bishop piece, given the current coordinate of the piece is (4,6) and the coordinate that the piece wants to go to is (3,7) determine whether the piece is moving diagonally

lone heartBOT
#

@main zephyr Has your question been resolved?

vale wigeon
#

"determine whether the piece is moving diagonally"?

#

what's there to determine?

#

bishops always move diagonally by definition, do they not?

#

@main zephyr can you clarify your question

icy latch
vale wigeon
#

can you show the problem EXACTLY as it was stated

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icy latch
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abstract skiff
lone heartBOT
abstract skiff
#

this is right?

vale wigeon
#

why not check yourself?

#

,calc -5*2 + 6

ocean sealBOT
#

Result:

-4
vale wigeon
#

,calc 3*2 - 2

ocean sealBOT
#

Result:

4
vale wigeon
#

looks like your answer is incorrect

abstract skiff
#

oh alright

#

how do I solve this

#

?

#

nvm

vale wigeon
#

how did you arrive at x=2, y=4?

abstract skiff
#

wait ill check

vale wigeon
#

show your work here so that we can look for your error(s)

abstract skiff
#

y = 8?

#

alright

#

so basically

#

-5x + 6

#

3x - 2

#

I made the 3x into 15x

vale wigeon
#

...?

abstract skiff
#

So basically

vale wigeon
#

do you have your work written out on a piece of paper?

vale wigeon
#

ok so all you did was write out a bunch of expressions with no rhyme or reason behind them

#

not a single equals sign in your work

abstract skiff
#

Just put y =

vale wigeon
#

are you allergic to equals signs?

abstract skiff
#

in front the euqations

#

equations*

vale wigeon
#

you want to put y= at the start of every line?

abstract skiff
#

yes

#

I need to

vale wigeon
#

but then that won't make any sense

abstract skiff
#

why not?

vale wigeon
#

surely, if you want to multiply both sides by 3 in the equation y = -5x + 6, the equation ought to become 3y = -15x + 18?

abstract skiff
#

oh true

#

Didnt consider that

vale wigeon
#

that, and also there's a somewhat simpler way to do this

#

and you have no instructions forbidding you from doing so

#

just solve the equation -5x + 6 = 3x - 2

abstract skiff
#

alright

#

-5x + 6 = 3x - 2

-5x + 5x + 6 = 3x + 5x - 2

6 = 8x - 2

8 = 8x

X = 1

#

Y = -5 + 6

y = 1

knotty spire
#

,w solve -5x + 6 = 3x - 2

knotty spire
#

congratulations

abstract skiff
#

alright

#

nice

vale wigeon
#

be mindful of capitalization

#

also, while we're at it

#

with sufficient correction, your way could've solved the system too: you would have the equations 3y = -15x + 18 and 5y = 15x - 10 which you could then add to get 8y = 8 whence y = 1

lone heartBOT
#

@abstract skiff Has your question been resolved?

#
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main zephyr
# vale wigeon <@625305547629133825> can you clarify your question

in my situation, im making a game similar to chess but all pieces can only move diagonally, the board's layout is the same as the chess board. Lets say that the piece that sits at (4,6) wants to move to (5,7). I want to know if the piece if moving diagonally before updating the piece's position

vale wigeon
#

i don't understand still

#

"all pieces can only move diagonally"

#

"i want to know if the piece is moving diagonally"

main zephyr
#

well im programming the game

vale wigeon
#

you just said all pieces in your game are moving diagonally

clear stump
#

isnt that just checkers

main zephyr
icy latch
#

check if gradient is 1 or -1?

main zephyr
vale wigeon
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"i want to know if the piece is moving diagonally" implies the answer could be yes or no depending on some circumstances

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but in your case the answer seems to always be yes

main zephyr
vale wigeon
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so i fail to see the point

main zephyr
vale wigeon
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all pieces can only move diagonally

main zephyr
#

that is the rule im going with

vale wigeon
#

ok let me try this again

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what part of the code is this check supposed to be in, and what is it responsible for?

main zephyr
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i cant just write "all pieces can only move diagonally" into my program, i need to know the math to return a value of "true" or "false"

main zephyr
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its like a function that i provide 2 coordinates with

vale wigeon
#

ah

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so you have a function that takes in a start point and end point that you need to return true if and only if the move thus described is a valid diagonal move

main zephyr
#

yes

vale wigeon
#

then yeah, check if the gradient is equal to ±1

main zephyr
#

oo

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btw can u explain, in simple terms, what is a gradient

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my teacher teached me its formula but never really explained what its used for

vale wigeon
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the gradient, or slope as i've seen it called more often, is the measure of how steep or shallow a line is on the plane

main zephyr
#

she did say that parallel lines have the same gradient so i assume its the direction of a line?

vale wigeon
#

kind of.

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i would not call it the direction per se

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but it is a function of the direction

earnest tiger
#

Just make the absolute value of slope = 1

main zephyr
#

i think i understand now

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thank you for your time

lone heartBOT
#

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hollow pasture
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I need some assistance on how to get started with this question

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alpine sable
#

hi

lone heartBOT
alpine sable
#

so i have a pde

#

ut + H(Du) = 0

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where u is a function of x, a n dimensional vector

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the book says u write the 2(n+1) +1 = 2n+3 odes for the characteristic system

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i dont get where the 2n+3 comes from???

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also it says that u can decouple the system of characteristics into two systems

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dxi/dt = dho(H)/dho(pi)

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and dpi/dt = -dho(H)/dho xi

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where pi = dhou / dho xi

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and xi are the components of the vector x

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how do u decouple the system-??

sand pawn
#

could you upload an image please for visualizing your problem? @alpine sable

alpine sable
#

huh gimme a minute

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@alpine sable Has your question been resolved?

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slender mantle
lone heartBOT
slender mantle
#

I've used the midpoint formula and found that P is (2,0) by doing (midpoint of RS = ((-2+6)/2), ((4-4)/2)) = (2,0))

#

if I used the mid point formula, it must mean that P is collinear with R and S, yet part (ii) requires me to explain why they are not collinear, which means my answer must be wrong

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Please help!

chrome plank
#

"its x coordinate is twice its y coordinate" that's not true for the point you found

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Also, the midpoint between two points is not the only point that is equdistant

slender mantle
#

does that mean that P(2,0) fulfills the being equidistant part but does not fulfil the "x-coordinate is twice its y-coordinate)?

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So I will have to find another point using another way that fulfills both conditions

chrome plank
#

yes

slender mantle
#

Okay, I will try again and update you, thank you

chrome plank
slender mantle
#

I got the answer, thank you so much! @chrome plank

#

.close

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lone heartBOT
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fierce plaza
#

does anyone how to make any of the following? pareto chart, histogram , frequency graph, sector graph, stastical display if so dm me please

alpine sable
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potent rain
lone heartBOT
potent rain
#

I'm confused on how to find the opposite of cosine. I tried using the fact that cosine is an even function to ignore the negative.

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I also tried to just move theta to the negative x value and then moving it by the xpi factor but that doesn't work either

crisp grail
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use that cosine is the projection on the x-axis

potent rain
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I will give an example on paper one second

potent rain
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Cosine is an even function right so negative theta is positive theta?

crisp grail
#

the upper one is one of the solutions

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and cuz its an even function the other solution is $\cos(-\right(\frac{\pi}{2}-\theta\left))$

ocean sealBOT
#

VincentBH

potent rain
#

Technically it's the same thing but then that's 3 solutions 💀

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It can't be 2pi-t because it leaves it in the same quadrant, quadrant 1

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And that's positive so it can't be opposite

potent rain
#

Who can help me? I'm confused

#

.close

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potent rain
#

.reopen

lone heartBOT
#

potent rain
#

Hi lol

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💀

urban pine
#

opposite here just means negative right?

potent rain
#

It's weird terminology right, no one else uses it.

urban pine
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just making sure i'm not overthinking it

potent rain
#

Very frustrating when someone wants to suddenly reinvent the wheel lol

urban pine
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lots of opposites in math lol

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for this i like to look at the angle and then move the theta from there

potent rain
#

Yeah so I'm confused because 2pi-t can't be it because obviously that leaves it in the same place it was before in quadrant 1 so it's not opposite

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Then pi-t and pi+t are both potential solutions since it leaves you with a negative cosine

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But the guy here says pi/2-t is one solution

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So they can't be both the solution

urban pine
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so cos(pi/2 - t) will always be sin(t)

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that's an identity

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and sin with SOHCAHTOA is the opposite, so that's why i was checking earlier lol

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for these i like to start with the angle then move by theta
so cos(t) is starting at angle 0 (x-axis)
and cos(pi/2 +- t) is starting at angle pi/2 (x-axis other side)

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and hopefully you see they go up/down theta either way, but the projection is still the same, just on the negative side of the x-axis

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we can see the 2pi like you said it's the same as 0

potent rain
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Pi/2 starts at angle pi/2?

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So does cos pi-t start at pi then

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I'm confused

urban pine
#

yeah you can visualize it like that

potent rain
#

I thought I started with theta and then moved with the pi factor.

urban pine
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both work, i like to do the constant first and then kind of wiggle the variable in my head

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whatever works for you

potent rain
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But either way if I don't then I'm confused because pi+t and pi-t obviously start in quadrant 3 it's the same thing

urban pine
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correc

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well not quite Q3

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the negative x-axis

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one will go up to Q2, the other will go to Q3

potent rain
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Why?

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I thought cosine was an even function

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So -t = t I thought.

urban pine
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careful

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yes

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but

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cos(a - t) = cos(-(-a + t)) = cos(-a + t)

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can't just grab any theta in the argument and switch the sign

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i.e. cos(a - t) /= cos(a + t) in general

potent rain
#

I'm sorry I just don't understand.

urban pine
#

nw

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you're correct that cos is even

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if a function f is even then f(-x) = f(x)

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that's the def

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but notice we have to be careful once the arg of the function is more complicated (including other terms)

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f(a - x) is not necessarily f(a + x)

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quick example x^2 is even but (a - x)^2 = a^2 - 2ax + x^2 and (a + x)^2 = a^2 + 2ax + x^2

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not the same

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not sure if i'm addressing which part you're confused about exactly

potent rain
#

Not really honestly this seems quite advanced

urban pine
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not trying to attack you with old algebra stuff :p but just a quick example, the gist is that you can't just reach in and pick and choose what is positive or negative

potent rain
#

Hmm

urban pine
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the entire input of the function can be negated without any effect

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all or nothing

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SO anyway that's all just to say that cos(a - t) and cos(a + t) are usually distinct; and they are for our case a = pi

potent rain
#

Ok and I have to use the former formulae to find that out?

urban pine
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how do you mean?

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which formula?

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definition of even?

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for now i wouldn't worry about it. it's prob best to get comfy with your unit circle instead of proving all this algebraically

potent rain
#

The one you said earlier with x^2 etc.

urban pine
#

sure that was a counterexample to being able to switch signs wherever you want (you can use the same to show that the negative of the whole thing is good to go tho)

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i made a little visual for the cosine prob

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play with the a and t sliders

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couldn't make the triangles nice, so you'll have to imagine them lol

potent rain
#

I tried using desmos app on my phone; I'm at work rn

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It is not very good it seems

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It just shows a line when I put like x = cos(pi-t) for example.

urban pine
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not missing much; it just plots cos(t) and compares to cos(pi - t) and cos(pi + t)

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oh yeah when you type that it's a line equation so it'll give a line

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if you wan't to plot points on a unit circle you have to give it a point like i did (cos(a - t), sin(a - t))

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then it'll give the (x, y) coord for that

potent rain
#

Ok let me try then

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Like this?

urban pine
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no those will be two lines

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in the same field put a coord in (something for x, something for y)
i'd recommend taking a look at mine to start

potent rain
#

Oh ok

urban pine
#

brb

lone heartBOT
#

@potent rain Has your question been resolved?

potent rain
#

.close

lone heartBOT
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tidal zealot
lone heartBOT
knotty spire
#

what have you tried?

tidal zealot
#

am i stupid or does reverse chain rule not work

tidal zealot
#

zzz

knotty spire
#

I honestly have no idea what is going on

tidal zealot
#

im integrating

knotty spire
real gazelle
#

yeah

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try expanding out instead

tidal zealot
#

why

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cant i do reverse chain rule?

real gazelle
#

No

tidal zealot
#

why not

real gazelle
#

well you can try it

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but if it doesn't work then it doesn't work

knotty spire
#

expansion si the easiest way forward

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you get three terms

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which you can integrate within seconds

tidal zealot
#

but i want to know why can i not do reverse chain rule

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why cant i do wht i just did

abstract fractal
#

What you did isn't reverse chain rule

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Reverse chain rule is just another name for u substitution

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AFAIK, anyway

knotty spire
#

well it definitely wasn't u-sub either

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In this case, well, I don't think it would help

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but you are welcome to try

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this is why integration is generally difficult; not every way works

tidal zealot
real gazelle
# tidal zealot

Can you explain your thought process for what you did here

tidal zealot
#

why does this work

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i dont get how this works and the other one dosent

real gazelle
#

Oh I see what you did

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Because of the x^2

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The x^2 has derivative 2x

knotty spire
#

what you did is a u-sub in disguise

tidal zealot
knotty spire
#

dx = 1/3 * d3x

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then you integrate