#help-0
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-ζ(-1/2, n + 1) - ζ(3/2)/(4 π)
That's Riemann's function rigth?
and?
just cuz you're in 10th grade doesn't mean you shouldn't know advanced stuff
I know, just wanted to note I don't
There's no easy way to do this that I'm aware of, I'm afraid
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anything u tried?
xy^3 = ky^2 but I'm not sure whether this approach is correct or what to do next lol
yes it correct why do u think that's wrong?
u need to be a biit careful and use the fact that $ky \neq 0$
∆y/∆x=sin(x) + cos(y)
indeed yes
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any hints or pointers on how i could approach this question?
What is 94^2?
hint: the square root of 8881 is <95
hmm
what do you know regarding the properties of primes? There are ways to determine this by just checking all primes for divisibility by brute force, but that doesn't seem very elegant
im still a bit stuck, so there being a bound on the square root of the number would mean that if u list out pairs of factors it would be less than 95?
i honestly dont know much about primes except the standard definition
a particular fact about the prime factorization of a composite number is that it is guaranteed to have at least one factor less than its square root
it's a bit simpler i think
yea id have never gotten that
it probably is, since that's the brute force method
it says prove by contradiction, the alternative would mean that all factors are 97+
is it one 97+? no it's not prime!
is it two 97+? no that's already more
proved it
i assume the solution is a bit simpler since this was a problem given after the first 10 pages or so of an "intro" to pure mathematics
it's the multiplicative equivalent to the fact that every number can be written as the sum of two numbers of the form A+-x where A is the average and x is some distance away, and they always come in these pairs
you also have to check if it's prime itself, as it would then have a prime factorization above 89
what do you mean
oh, given that it's composite
nvm
the text of the question contains the scope of the question
hmm i think maybe it is enough to say that the next greatest prime is 97 and if there are no prime factors less than 89, then the least number u can get with primes above 97 is 97*97.
the factors "revolve" around the sqrt of the number
any factor > sqrt has the other factor be < sqrt
any factor = sqrt has the other factor be = sqrt
in either case, there must exist a factor that is <= sqrt
that's too hard
and since you're looking for primes, that factor is at most 89
d < sqrt(n) => n/d > sqrt(n)
8881 =
easier expressed symbolically
we can try to find some squares whose difference is 8881
why?
to find the factors
Great idea. I think this works
the question doesn't ask to find the factors
you're not supposed to find the factors
got a feeling it might be a little overkill
Ah wait in fact it doesn't, nvm
the idea is you're not supposed to compute much, if anything
just argue the existence
oh sorry
every number has a factor not above its own square root
every composite number has a prime factor not above its own square root
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can anyone help me prove this?
This involves binomial theorem
hmm the start point is the binomial theorem?
the left side tells us how many options there are how to select p elements from n+m elements
can you tell me what (n choose k)*(m choose p-k) tells me?
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can I do this ?
i calculated the possible limits of a_n+1 = a_n
and came out there is only one, for a = 2
so now I need to show that its really the limit right ?
If you have done a and b
You have a theorem that says limit exist
So no need to do anything else
kennen Sie der Satz von der monotonen Konvergenz?
haben Sie schon (a) gelöst?
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feeling kind of braindead today, can't seem to visualise the bottom angle being 2theta
Im braindead too
any quick explanation is appreciated
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im ngl im very confused idek what im doing i was just doing random math
Do you know derivatives?
Otherwise you just gotta find the vertex if it ends up being a quadratic
$$2L + W = 68$$
$$A = LW$$
Umbraleviathan
How would he find A then tho
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ohh woops i did 2 w by accident
so 2l + 4
w
= 68
aight
But the stuff I did, was it right?
Like the way i solved for area
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bruh
2L+W=68
68-2L=W
A=LW
A=L(68-2L)
A=68L-2L^2
dA/dL=68-4L
dA/dL=0
4L=68
L=68/4
2(68/4)+W=68
@rose blade
Not necessarily
Not without using limits which you probably don't know
to get the max i think my teacher wants me to find the vertex by converting the equatioon into vertex form
I learned what differentiation is
lol
i get where the 4 came from now
Damn okay then
I mean I was gonna write like
u can still write it
cus im still confused
just curious if any of u guys actually solved it is the area 578?
First, construct a set of equations based off given information:
$$2L + W = 68$$
$$A = LW$$
We can rearrange the first equation so that $W = 68-2L$. Then we get:
$$
\begin{align*}
\begin{split}
A &=L(68-2L) \
& = -2L^2 + 68L
\end{split}
\end{align*}
$$
You need to find the vertex. If $(h, k)$ is the vertex of quadratic polynomial ${\color{lime}{a}}x^2 + {\color{cyan}{b}}x+{\color{orange}{c}}$, then $h = -\frac{{\color{cyan}{b}}}{2{\color{lime}{a}}}$. We can rewrite A:
$$A = {\color{lime}{-2}}L^2 + {\color{cyan}{68}}L + {\color{orange}{0}}$$
You can now find the vertex which will give you maximum area and the dimensions.
Bruh
what are the dollar signs
oh ok
Umbraleviathan
Compile Error! Click the
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(You may edit your message to recompile.)
There
yeah thats what i thought
but u guys had me confused
everyone is so high level in this server
oh so that meabns the way i did it was right
Yeah
completing the square is boring
oh gl
thanks
is the vertex (5.83,17) and if not can someone please check to see where i went wrong
sorry
is it not (17,578)
i thoight the area was 578
but our equation was A=-2L^2+68L
so if we were graphing we would plot L on the x axis and A on the y axis
im so confused now because the ewquation i used previously worked to find the area but the vertex is wrong
yeah
ok nvm imma jus re do this
use this
right
but
ok so i get 17 for x or the length, then if u pluf that back into 2l-68 u get -34 which doesnt make sense
oh no
no
-2L^2+68L
tes tyes
isn't it (68-34)/2 which gives the width which is 17?
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Julia launched a rocket vertically upward from the top of a cliff. The height of the rocket above the base of the cliff is approximated by the model h=-5t^2+30t+20, where "h" is the height in meters, and "t" is the time in seconds
A) how high is the cliff?
B) After how many seconds does the rocket hit the ground?
C) When does the maximum height occur?
D) What is the maximum height?
E) When is the rocket at 45m from the ground I'm not sure how to do this i've tried for like 30 mins and i can't figure it out and its due in 45 mins
i tried to solve the quadratic and figure out the height of the cliff.
ok, but u don't need to solve it
just try to think
at what time the object is on top of the cliff?
30 seconds
well the answer is 20
but I mean, u just need to substitute the values of t in the equation
at t=0 the rocket is on top, and then is starts going down
so if u substitute t=0 into the equation, u'll get h=20
for the second point, if the rockets hits the ground, what's its height?
oh sorry, upwards. so it goes up and then down
well but the answer is the same
at t=0 the rocket is on the cliff, so h=20
are u following?
yeah
ok
if the rocket hits the ground it means that h=0
so if h=0 it means that the equation is equal to 0
so then u just solve the equation 0=-5t^2+30t+20
u can devide by so 0-t^2+6t+4
and then u just solve it
it should give u two solutions, one must be negative and the other is positive
the answer should be around 6.6
seconds
wait so for this you just make h = 0 and solve the rest?
yes
yeah
yes
u can think that t=x and h=y
so the highest point
is actually the turning point
bc the parabole is like a sad face, so it reaches a maximum and then it goes down again
are u able to follow this?
yes
so do u wanna how to calculate the turning point of a parabola?
yes please
so u can calculate in a lot of different ways
the easiest one is t=-b/2a
where a is the coefficient of t^2 and b of t
so the t of the maximum high is t=-30/(-5)
so t=6
now that u have the time u can calculate the height
u just need to put t back into the equation
i see
yes
so for the last question
u know that h=45
so just substitute into the equation and solve for t
45=-5t^2+30t+20
devide by 5
9=-t^2+6t+4
rearrange and sum
t^2-6t+5=0
and it has twho solutions
t=5 or t=1
thank you
ok will do
thanks for the help tho u really helped me understand this better
.close
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∠DHF= ∠DHE+ ∠EHF
∠EHG= ∠EHF+ ∠FHG
but ∠DHF=∠EHG, then…
∠DHE+∠EHF=∠EHF+∠FHG
then ∠DHE= ∠FHG
∠DHE= ∠2
∠FHG= ∠3
=> ∠2=∠3
“m” can be reduce.
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,rotate
you factor out the (a+b)????
so you did it, what do you want to know?
that looks like the right method
I wanna know if its possible in this method...if so...how?
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how would I even do this 😭
Law of cosines could help
Although the problem does not mention which sides b and c are but I'd assume c is the one opposite to the angle C and b is the one opposite to the angle B
Well applying the law of cosines here yields that c^2 = a^2 + b^2 - 2abcos(C)
Assuming what I said about the position of b and c is correct*
So from here you can solve for a
would I have to do 2 triangles? for all "possible solutions"
Eh yeah, pretty much
but how?
You mean what cases to consider?
yes
I think those are when a is opposite to C, b is opposite to C and when none of them are opposite of C (meaning they're both adjacent to it)
so theres only one possible solution?
There are 3 cases as I mentioned those
im so confused
Just consider each case separately and those will lead you to the possible answers
how do i even consider those lol
But again I think the author meant that c is the side opposite to angle C
yes they did
Oh
so its only one triangle?
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Just start with this then
Good luck
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When do I know how to do the product rule?
In this equation, I just multiply the two values together
But how do I know the difference between doing that and applying the product rule
Is it going to specifically say to use the product rule?
Or is it indicated by putting the prime symbol, with yprimex?
the answers will be the same no matter which method you use
but its good to use the product rule to practice it i guess
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Hello

I tried to apply the coulomb formula between a helium core and an electron, but I come to a confusion:
The strange thing about the coulomb force is that the force exerted by the electron on the nucleus is the same force exerted by the nucleus on the electron. Yet we could say that the force of generated by the electron is 2 times smaller than that generated by the 2 protons of the helium nucleus
@stable gazelle Has your question been resolved?
No but it doesn’t matter no problem
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Small question
r^2 = (s/pi/r)^2 - (h^2)
rv^2 = (2s/pi/rv)^2 - (hv^2)
(2 * pi *r) + (2 * pi * rv) = 100
Solve for r, rv, h, and hv
My brain is dead
Pi is pi
Schizo this chat is taken
I just don’t know where to approach this
.
<@&286206848099549185>
If anyone is available
Doesn’t look like it unless I messed up
Show the original question and all your work
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I’m an idiot
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im having trouble with this matrix multiplication\
im getting the exact same thing except with a 2 instead of a 10 on the bottom left corner
2 is correct
Assuming E32 is the first matrix, E31 is the second matrix, and E21 is the third matrix
The first column in E31 is only nonzero in the first entry
So you just need to dot the last row of the first matrix with the first column of the second matrix
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I don’t know what to do
Use a z score
@shell urchin Has your question been resolved?
-0.50?
Show how you got that
Well, you know he's below average so his percentile rank is below 50%, so we throw out option 3. But it can't be something absurd like 0.19 or 0.5 given his value is within 1 standard deviation of the mean, so we throw out option 2 and option 4. What are you left with?
That's a "multiple choice thinking" way of solving it.
Thank you
Using a formula is not guessing. Use the z score formula
It’s a practice problem because I’m studying so it doesn’t actually count. So I was hoping to learn the process of it since I forgot, but I learn really slow
Okay
I got -0.5
When using the z score formula
Show your work
Looks good. Just plug it into a table for percentile
Okay
Um:/ idk what else I’m supposed to look for on the z table. I know -0.5 but idk the other one
Show your z table
It doesn’t give me one
It just gave the question
I tried looking for one
But not a good one
Ty
What number am I looking for at the top and why?
I know the left is -0.5
say you have a positive z value of a.bcd then you look for the row under the z column with a.b
then you scan right until you get 0.cd
I’m trying to understand 😐 I don’t learn fast
oh sorry i was wrong
you add 0.cd to a.b
0.cd is 0.05 in this case. i guess it's always 0.0d
and a.b is 0.2
so for the z score of 0.25, you look in the first column for 0.2, then scan that row until you get 0.05 because 0.2 + 0.05 = 0.25
another SAT example
https://towardsdatascience.com/how-to-use-and-create-a-z-table-standard-normal-table-240e21f36e53
Because it has 0.25
You look for the two and then the 5?

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https://cdn.discordapp.com/attachments/326138757474680852/1000168308559061113/IMG_0040.jpg
So basically I have been trying to understand this question but I dont know how to find triangle angle sums in spherical geometry. Can someone explain triangle angle sums in spherical geometry to me?
,rotate
Retrieving the previous image failed.
f
@lucid apex Has your question been resolved?
I made a nice sketch
If you zoom in at the sphere's surface and make a very small triangular shape (Something like going outside and drawing a triangle on the ground), the sum of the interior angles will be super close to 180°, and can be approximated very well by a 2D plane
But if you make such a big triangle on a sphere, do you expect it's interior angles to be bigger or smaller than 180°?
Bigger I think
Is it 185?
Yes, I think so
Alr
Thanks for explaining this to me I’ve been struggling with this for a while lol. Have a great day!
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You too!
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does anyone know if for the final form of this equation is it possible for n to equal 4
Nonna
yes
Yes of course
oh I didnt know for sure because I knew 3 meant it was cubed and 2 it was squared so i wasnt 100% sure if you could use 4 in it
Works for any positive integer (rational number?) as far as I know
0 is pretty much undefined right?
0 is defined, the division by 0 is undefined
I did say positive integer
you mentioned rationals too, it's to not bring confusion
I forgot to say positive in front
My mistake
m and n can be negative
Is it possible to have a negative root
Nonna
Nonna
and it becomes\
$\sqrt[n]{x^{-m}}$
Ok so a negative root works
Nonna
Yes, but because of the definition as x^(m/n)
$\sqrt[n]{x^{-m}} = \sqrt[-n]{x^{m}}$
Nonna
because
$x^{\frac {-m} {n}} = x^{\frac{m}{-n}}$
Nonna
Does it make sense?
Nice
@forest orchid If you have more questions feel free to ask, otherwise .close the channel
Im good now, thank you for the help
.close
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help
What have you tried
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Working on a larger problem, I got this as a part of an equation. Wasn't sure how to approach, so plugged numbers in. Got the Bernoulli Triangle sums [(1), 1, 3, 8, 20, 48].
I worked out that the sum permutation on the left -- if isolated -- form the fibonacci numbers, and the isolated sum of the permutation on the right give triangular/tetrahedral/etc. numbers.
Anyways, would like to prove whether or not the summation will give the n-1th Bernoulli number.
<@&286206848099549185> I will pay 3 boiled eggs
I have tried marking values in Pascal's triangle, but I don't think it works.
For reference: http://oeis.org/wiki/Bernoulli's_triangle
I have plugged it into desmos too, though different variable names. https://www.desmos.com/calculator/akc1qbgvye
@quasi rover Has your question been resolved?
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@quasi rover Has your question been resolved?
help
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are these false?
hello?
Can you explain why for each?
for 1 f'(x) = 0 could just be the graph platueing but it can still carry on in any direction, it doesnt necessarily mean there WILL be a local minimum and max
I think
could you perhaps draw out what you mean
some thing like this
yup
so 1 is false then
good example
f''(x) is 12x^2
that would work yup
but 3 i have no idea
consider the graph of f'
#3 is true
its a little hard to prove in what i would assume is calc 1?
i could be wrong
yes this is calc 1
Oh yes it can be an inflection
no it would still be a minimum
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what does this question mean and how do i check?
@dawn ridge Has your question been resolved?
Plug in the formula for a_n and a_{n-1} into the recurrence relation
yes. it comes from o-th term to 3th term
There is no 0 index
a1,a2 like that
What's a2
3
Nope
2
Use the given formula and stop guessing
what is mean by one expression is olution recurence of another
i just started yesterday so i know some basic term only
Did you have a lecture on it?
little bit videos
Just means you plug in your given formula into the recurrence relation
But you need to understand the formula a_n
an=dan -1
You know what $2^n + 1$ means?
so i should each expression by n-1
riemann
No. The one given in your problem
its a rec reln?
Do this
Also, no
just replace n in 2n + 1 by 1,2,3,&4?
yes
so how do i check one reln is recursive reln of another,,..I have solved basic number related problem yet
What's your answer for this
I already told you
5,9,17,33
Plug a2 and a1 into the recurrence relation to see if it holds
a2 = 2 * a1 - 1
Repeat for a3 and a2
Once you're done with a few values, plug it in for general n and n-1
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imagine a chess board and imagine there is only one bishop piece, given the current coordinate of the piece is (4,6) and the coordinate that the piece wants to go to is (3,7) determine whether the piece is moving diagonally
chess math
hold on
@main zephyr Has your question been resolved?
"determine whether the piece is moving diagonally"?
what's there to determine?
bishops always move diagonally by definition, do they not?
@main zephyr can you clarify your question
ikr, maybe it's a gradient type question?
can you show the problem EXACTLY as it was stated
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it's probably to define through gradient and coords whether in this case, if the bishop does a legal move to said square
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this is right?
Result:
-4
,calc 3*2 - 2
Result:
4
looks like your answer is incorrect
how did you arrive at x=2, y=4?
wait ill check
show your work here so that we can look for your error(s)
...?
So basically
do you have your work written out on a piece of paper?
ok so all you did was write out a bunch of expressions with no rhyme or reason behind them
not a single equals sign in your work
Just put y =
are you allergic to equals signs?
you want to put y= at the start of every line?
but then that won't make any sense
why not?
surely, if you want to multiply both sides by 3 in the equation y = -5x + 6, the equation ought to become 3y = -15x + 18?
that, and also there's a somewhat simpler way to do this
and you have no instructions forbidding you from doing so
just solve the equation -5x + 6 = 3x - 2
alright
-5x + 6 = 3x - 2
-5x + 5x + 6 = 3x + 5x - 2
6 = 8x - 2
8 = 8x
X = 1
Y = -5 + 6
y = 1
,w solve -5x + 6 = 3x - 2
congratulations
be mindful of capitalization
also, while we're at it
with sufficient correction, your way could've solved the system too: you would have the equations 3y = -15x + 18 and 5y = 15x - 10 which you could then add to get 8y = 8 whence y = 1
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in my situation, im making a game similar to chess but all pieces can only move diagonally, the board's layout is the same as the chess board. Lets say that the piece that sits at (4,6) wants to move to (5,7). I want to know if the piece if moving diagonally before updating the piece's position
i don't understand still
"all pieces can only move diagonally"
"i want to know if the piece is moving diagonally"
well im programming the game
you just said all pieces in your game are moving diagonally
isnt that just checkers
thats the rule ye so i wanna implement it into my code
check if gradient is 1 or -1?
its called checkers? oh
"i want to know if the piece is moving diagonally" implies the answer could be yes or no depending on some circumstances
but in your case the answer seems to always be yes
oh
so i fail to see the point
why would it always be yes?
all pieces can only move diagonally
that is the rule im going with
ok let me try this again
what part of the code is this check supposed to be in, and what is it responsible for?
i cant just write "all pieces can only move diagonally" into my program, i need to know the math to return a value of "true" or "false"
validating whether the move is diagonally
its like a function that i provide 2 coordinates with
ah
so you have a function that takes in a start point and end point that you need to return true if and only if the move thus described is a valid diagonal move
yes
then yeah, check if the gradient is equal to ±1
oo
btw can u explain, in simple terms, what is a gradient
my teacher teached me its formula but never really explained what its used for
the gradient, or slope as i've seen it called more often, is the measure of how steep or shallow a line is on the plane
she did say that parallel lines have the same gradient so i assume its the direction of a line?
ah
kind of.
i would not call it the direction per se
but it is a function of the direction
Just make the absolute value of slope = 1
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hi
so i have a pde
ut + H(Du) = 0
where u is a function of x, a n dimensional vector
the book says u write the 2(n+1) +1 = 2n+3 odes for the characteristic system
i dont get where the 2n+3 comes from???
also it says that u can decouple the system of characteristics into two systems
dxi/dt = dho(H)/dho(pi)
and dpi/dt = -dho(H)/dho xi
where pi = dhou / dho xi
and xi are the components of the vector x
how do u decouple the system-??
could you upload an image please for visualizing your problem? @alpine sable
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I've used the midpoint formula and found that P is (2,0) by doing (midpoint of RS = ((-2+6)/2), ((4-4)/2)) = (2,0))
if I used the mid point formula, it must mean that P is collinear with R and S, yet part (ii) requires me to explain why they are not collinear, which means my answer must be wrong
Please help!
"its x coordinate is twice its y coordinate" that's not true for the point you found
Also, the midpoint between two points is not the only point that is equdistant
does that mean that P(2,0) fulfills the being equidistant part but does not fulfil the "x-coordinate is twice its y-coordinate)?
So I will have to find another point using another way that fulfills both conditions
yes
Okay, I will try again and update you, thank you

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does anyone how to make any of the following? pareto chart, histogram , frequency graph, sector graph, stastical display if so dm me please
what's the context of "make"
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I'm confused on how to find the opposite of cosine. I tried using the fact that cosine is an even function to ignore the negative.
I also tried to just move theta to the negative x value and then moving it by the xpi factor but that doesn't work either
use that cosine is the projection on the x-axis
I will give an example on paper one second
the upper one is one of the solutions
and cuz its an even function the other solution is $\cos(-\right(\frac{\pi}{2}-\theta\left))$
VincentBH
Ok my confusion comes when I do pi-t and pi+t
Technically it's the same thing but then that's 3 solutions 💀
It can't be 2pi-t because it leaves it in the same quadrant, quadrant 1
And that's positive so it can't be opposite
Are you still here? 😫
Who can help me? I'm confused
.close
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.reopen
✅
opposite here just means negative right?
Yes, I believe so.
It's weird terminology right, no one else uses it.
just making sure i'm not overthinking it
Very frustrating when someone wants to suddenly reinvent the wheel lol
lots of opposites in math lol
for this i like to look at the angle and then move the theta from there
Yeah so I'm confused because 2pi-t can't be it because obviously that leaves it in the same place it was before in quadrant 1 so it's not opposite
Then pi-t and pi+t are both potential solutions since it leaves you with a negative cosine
But the guy here says pi/2-t is one solution
So they can't be both the solution
so cos(pi/2 - t) will always be sin(t)
that's an identity
and sin with SOHCAHTOA is the opposite, so that's why i was checking earlier lol
for these i like to start with the angle then move by theta
so cos(t) is starting at angle 0 (x-axis)
and cos(pi/2 +- t) is starting at angle pi/2 (x-axis other side)
and hopefully you see they go up/down theta either way, but the projection is still the same, just on the negative side of the x-axis
we can see the 2pi like you said it's the same as 0
yeah you can visualize it like that
I thought I started with theta and then moved with the pi factor.
both work, i like to do the constant first and then kind of wiggle the variable in my head
whatever works for you
But either way if I don't then I'm confused because pi+t and pi-t obviously start in quadrant 3 it's the same thing
correc
well not quite Q3
the negative x-axis
one will go up to Q2, the other will go to Q3
careful
yes
but
cos(a - t) = cos(-(-a + t)) = cos(-a + t)
can't just grab any theta in the argument and switch the sign
i.e. cos(a - t) /= cos(a + t) in general
I'm sorry I just don't understand.
nw
you're correct that cos is even
if a function f is even then f(-x) = f(x)
that's the def
but notice we have to be careful once the arg of the function is more complicated (including other terms)
f(a - x) is not necessarily f(a + x)
quick example x^2 is even but (a - x)^2 = a^2 - 2ax + x^2 and (a + x)^2 = a^2 + 2ax + x^2
not the same
not sure if i'm addressing which part you're confused about exactly
Not really honestly this seems quite advanced
not trying to attack you with old algebra stuff :p but just a quick example, the gist is that you can't just reach in and pick and choose what is positive or negative
Hmm
the entire input of the function can be negated without any effect
all or nothing
SO anyway that's all just to say that cos(a - t) and cos(a + t) are usually distinct; and they are for our case a = pi
Ok and I have to use the former formulae to find that out?
how do you mean?
which formula?
definition of even?
for now i wouldn't worry about it. it's prob best to get comfy with your unit circle instead of proving all this algebraically
The one you said earlier with x^2 etc.
sure that was a counterexample to being able to switch signs wherever you want (you can use the same to show that the negative of the whole thing is good to go tho)
i made a little visual for the cosine prob
play with the a and t sliders
couldn't make the triangles nice, so you'll have to imagine them lol
I tried using desmos app on my phone; I'm at work rn
It is not very good it seems
It just shows a line when I put like x = cos(pi-t) for example.
not missing much; it just plots cos(t) and compares to cos(pi - t) and cos(pi + t)
oh yeah when you type that it's a line equation so it'll give a line
if you wan't to plot points on a unit circle you have to give it a point like i did (cos(a - t), sin(a - t))
then it'll give the (x, y) coord for that
no those will be two lines
in the same field put a coord in (something for x, something for y)
i'd recommend taking a look at mine to start
Oh ok
brb
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what have you tried?
I honestly have no idea what is going on
im integrating
here
No
why not
expansion si the easiest way forward
you get three terms
which you can integrate within seconds
yeah ik
but i want to know why can i not do reverse chain rule
why cant i do wht i just did
What you did isn't reverse chain rule
Reverse chain rule is just another name for u substitution
AFAIK, anyway
well it definitely wasn't u-sub either
In this case, well, I don't think it would help
but you are welcome to try
this is why integration is generally difficult; not every way works
Can you explain your thought process for what you did here
what you did is a u-sub in disguise
so?