geometry-and-trigonometry

[tulip minnow]

i figured that out lol

so was this right?

[wanton edge]

No

[tulip minnow]

oh

okay lemme do it agian

OH

okok'

is it

v=48m^3

[atomic summit]

I don't think that's the answer either. What formula are you using if I may ask?

[tulip minnow]

v=1/3(1/2)(8)(6)(6)

v=1/3Bh

v=96?

[silent plank]

48m^3 is good

[atomic summit]

wait let me recheck

[atomic summit]

sorry, i think i did something wrong. 48m cubed is correct.

[tulip minnow]

Okok Thank You!

[dry plank]

God I love trig identities

[smoky inlet]

quick question guys ( sin + cos)^2 ? i remeber you do like sin power or 2 then multiply both sin and cos I forgot ? xd

[weary drift]

$(x+y)^2=x^2+2xy+y^2$ for any numbers $x,y$

[somber coyote]

RokabeJintaro

[pliant roost]

it's like

simple

the lines you draw are middle perpendiculars

and their property is that any point of such a perpendicular is equally distanced from the ends of the line segment

and intersections of such perpendiculars is equally spaced from each vertex of the triangle

and you are done! that point is obviously the circumcenter

works for acute triangles too

[pliant roost]

this is pretty easy to prove

and why do they intersect in one point? it's because the intersection of some two sides is already equally spaced from all the triangle vertices, so the last middle perpendicular must pass through that point

[pliant roost]

you could really define middle perpendicular this way

[upper karma]

i don’t get this at all

can someone help me?

[upper karma]

<@&286206848099549185> ☹️

[zealous dove]

A slice of a pizza is shaped like a sector. The arc length of a sector with radius $r$ and central angle $\theta^\circ$ is $\dfrac{\theta}{360} \cdot 2\pi r$, and its area is $\dfrac{\theta}{360} \pi r^2$. You can use these formulae to calculate the arc length and area. Then, the one who ate the most pizza is the one who has a pizza of the greater area, and the one who ate the most crust is the one who has a pizza of the greater arc length.

[somber coyote]

pi over four

[upper karma]

i’m so lost i have no idea how to do it at all

[zealous dove]

I will do the one on the left as an example.

$$\text{Pizza area} = \dfrac{45}{360} \cdot \pi \cdot (10\text{ in.})^2 = 12.5 \text{ sq. in.} $$
$$\text{Length of crust} = \dfrac{45}{360} \cdot 2\pi \cdot (10 \text{ in.}) = 2.5 \text{ in.}$$

Can you try to imitate what I did to complete the one on the right?

[somber coyote]

pi over four

[upper karma]

,rotate 90

[zealous dove]

Considering the interior angle sum of the triangle in the middle gives $B = 100^\circ$.
Using Law of Sines in the triangle in the middle yields $\dfrac{92\text{ m}}{\sin 52^\circ} = \dfrac{d}{\sin 100^\circ}$. Solving gives $d \approx 114.97\text{ m}$.
Using Law of Sines in the triangle on the right yields $\dfrac{d}{\sin 76^\circ} = \dfrac{63\text{ m}}{\sin A}$, which means $A \approx 32.11^\circ$.

The rest can be done likewise.

[somber coyote]

pi over four

[zealous dove]

Yes, you can find the central angle using the radius and arc length, and then find the area. You have the right approach.

[upper karma]

is this correct

[zealous dove]

I am confused, what do "s" and "sc" mean in your solution?

[upper karma]

sector

[zealous dove]

Sorry, I still don't understand it. Would you mind to explain your thought process in words?

[prisma saddle]

how do i also get the C..?

[upper karma]

wait i’m slow

i rewrote it

i didn’t even know what i wrote myself sc was supposed to be X

[zealous dove]

Since we already know what A is, we can consider the interior angle sum of the triangle on the right to get $76^\circ + A + C = 180^\circ$, which means $C = 104^\circ - A$. You can substitute the value of A to calculate C this way.

[somber coyote]

pi over four

[upper karma]

@zealous dove

[zealous dove]

Yeah this is correct

[upper karma]

what about this one

sending

[zealous dove]

x should be 10.5625 pi

[prisma saddle]

is my solution correct..?

or my brain's just farting

[zealous dove]

Yes

[upper karma]

can you help me with the other side now pi over four🥺

[zealous dove]

Suppose that $x$ sq. in. is the area of the sector. Then $$\dfrac{x}{42.25\pi} = \dfrac{90}{360}$$
$$x = \dfrac14 \cdot 42.25\pi = 10.5625\pi$$

[somber coyote]

pi over four

[zealous dove]

Then it is just the same as the one on the left, but with the numbers changed.

[finite quail]

Pls help no understanding

[zealous dove]

If the triangle is right-angled, then using Pythagorean theorem,

$$(x - 4)^2 + (x - 5)^2 = (x + 4)^2$$

If you solve the equation, you should get exactly one root with $x \in \mathbb N$ (i.e., $x$ is a natural number).

[somber coyote]

pi over four

[zealous dove]

To solve this equation, you can expand all parentheses, and move all terms to the left-hand side. This will result in a quadratic equation, hopefully you will be able to factor the left-hand side.

[prisma saddle]

@zealous dove what law do i use for sides a and c?

[zealous dove]

At this point, both Law of Sines and Law of Cosines work.

[prisma saddle]

oh okay okay thank you

[coarse saddle]

chill dude

[dark sparrow]

texit is a bot. there is literally never any point in pinging a bot.

[coarse saddle]

[dark sparrow]

also you shouldn't ping helpers until it's been 15 minutes without a reaction to your question

and third, is this an exam or other timed assessment?

cause i think it is.

[coarse saddle]

you also shouldn't advertise your question in multiple channels

[dark sparrow]

is this a timed, graded assessment? YES or NO @upper karma

[tardy skiff]

dont you have some sort of formula book ? there is a formula for slope between two points

[dark sparrow]

so you do not know how to compute the slope between two points?

it is literally defined by a formula: $m = \frac{y_2 - y_1}{x_2 - x_1}$

[somber coyote]

Ann

[dark sparrow]

and as far as i can tell you have never seen it before, somehow

[tardy skiff]

you might of been taught like rise/run which is the same thing essentially

its like this

not sure how you were taught this so throwing formulas at you might be bad but there is a formula for this , its basically pythagoras if you know that one

[thin sable]

how this expression is evaluated?

[river tundra]

Ggs Microsoft having a stroke

[real wyvern]

https://mathsolver.microsoft.com/en/solve-problem/`frac{ `sin ( `theta ) }{ `cos ( `theta ) - `cos ( 2 `theta ) }

thats your solution

[real wyvern]

look at above message

[thin sable]

yes but i am unable to understand the steps

how to do

[thin sable]

means?

[somber coyote]

Jagteshwar(JPS838898)

[river tundra]

The algorithm

[thin sable]

what i am unable to understand?

[river tundra]

How can I know

Lol

[thin sable]

ohh

[pastel swift]

so confused on how to do this

anyone?

[opaque gull]

sin(75) is the opposite side over the hypotenuse.
cos(75) is the adjacent side over the hypotenuse.
tan(75) is the opposite side over the adjacent.

Which one of these apply?

@pastel swift As in, which trigonometric ratio can we use to solve for length x? What information do we have?

[pastel swift]

the first one applies in this situation

SOH is the ratio

@opaque gull

[opaque gull]

Are you sure?

Do you have the hypotenuse?

[pastel swift]

The hypotense im pretty sure is the longest side but there isnt any measurement iu cn use

im new to thjis topic and i have no idea how to work this out

[opaque gull]

Don't worry

Correct, the hypotenuse is the longest side, we'll call it y.

Now, you can't use sin

Because if you use the sin ratio it would give us sin(75)=x/y

They are asking you to find out what x is

sin(75)=x/y
cos(75)=10/y
tan(75)=x/10

does that help you? which one can be used to find x?

ignore the csc, sec, and cot

[pastel swift]

sin? because we need to use the hypotenuse and the opposite to get x

[opaque gull]

not quite, because let me show you

if we use sin

you want x by itself

so you will have to multiply both sides by y

but

you get nowhere

y*sin(75)=x

we don't know what y is and we don't know what x is so it will never work

[pastel swift]

So how would I go and figure out how to get x?

[opaque gull]

sin(75)=x/y
cos(75)=10/y
tan(75)=x/10

We eliminate sin, now let's try and use cos.

in cos(75)=10/y do you see any way we can get x?

[pastel swift]

no

[opaque gull]

exactly, so we eliminate that

what do we have left?

[pastel swift]

tan

[opaque gull]

correct

now do you know how to solve for x?

tan(75)=x/10

given this

what do you need to do to get x by itself?

[pastel swift]

not sure

i have no idea what i am supposed to be doing

im a newbie

[opaque gull]

does it make it easier if i write it like this?

[pastel swift]

so tan 75 is equal to x divided by 10?

[opaque gull]

yes, how can you get x alone?

can we somehow get rid of that 10?

[pastel swift]

X by 10?

[opaque gull]

do you mean multiply both sides by 10?

[pastel swift]

yes

[opaque gull]

yes correct

because

multiplying x/10 with 10 will cancel out the 10's

leaving you with x on the right hand side

and tan(75)*10 on the left hand side

which you will use a calculator for

[pastel swift]

which is 37.3

[opaque gull]

after multiplying by 10 you get this equation

yes, good job

[pastel swift]

omg thank you

you explained it so well

[opaque gull]

you're welcome 😃

i'm glad i could help

[pastel swift]

😃

[opaque gull]

https://www.youtube.com/watch?v=g8VCHoSk5_o

this guy is a life saver too

subscribe to him and watch that video

[pastel swift]

will do

[gleaming nova]

why are you sending this everywhere

[prisma saddle]

how do i find angles E and D

[prisma saddle]

so i minus the 42 to 180 then divide by 2?

[dark sparrow]

no, unless you somehow know that c = 50m

which, even if it is, doesn't seem obvious to me - you'd need to apply the law of sines to the middle triangle to find c first

[grave pond]

My calculator says c=52.3, so it's not isosceles.

[errant flare]

What is so interesting about geometry?

[dark sparrow]

is that question intended to be taken in the most general sense possible?

[errant flare]

Yes.

I got hooked because of Euclid elements

[dark sparrow]

and by "interesting", what exactly do you mean?

[errant flare]

Makes you go into library pick some books and follow the questions as they arise

[dark sparrow]

then i don't know.

[errant flare]

I got repulsed yesterday - got old ussr book. Bunch of formalisms and trivialities.

But I feel there is something more in it.

[dark sparrow]

did you get stuck at chapter 1 or something

it may be of use to look a bit further ahead

[errant flare]

its just boring

but yeah thanks for the advice

[upper karma]

https://media.discordapp.net/attachments/975622187618824273/978169721650311209/unknown.png

[deep lake]

heres a rather easy question, how do i calculate the value for arctan if i don't have a calculator?

i know what the value for tan is but i don't know how to find the values for arctan

[deep lake]

i figured it out 🙂

[proven dome]

Question 22

[opaque gull]

draw

[proven dome]

Wym

I don’t know how to lay it out

[opaque gull]

Draw a diagram with the information that you have

[proven dome]

But I can’t get it layed down

Bcs I don’t understand it

The maximum angle of climb is 9 degrees

So that would be at the top

[opaque gull]

Yeah but tbh its confusing for me too

The words I dont get it

[proven dome]

It’s inverted

[opaque gull]

,rotate

[proven dome]

He said it’s angle of depression

[dull solstice]

need to show my work but dont get it

[upper karma]

2:cos\left(1/2x\right)cos\left(x\right):-:2:sin\left(1/2x\right)sin\left(x\right):=:1

2 cos(1/2x)cosx - 2 sin(1/2x)sinx = 1

[tropic glen]

Please help

Can someone help with this, I already Translated 9 to the left. I don’t know how to reflect across y= -2

[desert shore]

Having trouble picturing this question

[desert shore]

<@&286206848099549185>

No longer need help with question above but need help with this

[tardy skiff]

did u finish it yet? i tried it but kinda confused m yself

[blissful haven]

How does this get simplified?

[grave pond]

You can start by dividing out the common sec factor in the numerator and denominator.

Then note that sec²(x)-tan²(x) = 1.

[pliant roost]

then note remember secant and tangent definitions, use the Pythagorean trig identity and you're done

you've proved this

[blissful haven]

OH! Thank you

[boreal wind]

so can someone please explain me what X over this symbol with a number means because I don't understand it

like, I know it means square root of three, but what does 4.5 square root of three even mean in the first place I don't get it, it's just confusing to me

[runic beacon]

it means times

4.5 times sqrt(3)

[boreal wind]

so four times the square root of three?

but why not just put the real number?

instead of an equation

they're littered all over my assignments as answers and side lengths

[runic beacon]

wdym?

@boreal wind

[boreal wind]

Well in my geometry curriculum for multiple choice questions they'll put something like this as an answer

@runic beacon

[runic beacon]

so?

[boreal wind]

why? I don't understand

is it an alternative form of measurement

sorry if these are stupid questions math is not my forte

is it to avoid decimals?

[runic beacon]

yes

to avoid

approximations

it gives neater answer

[boreal wind]

ahh, okay, thank you for your time

[summer canopy]

..... tf

i guessed this right

can anyway explain me here why is the ratio 2:7 pls?

[grave pond]

It is the ratio of AB to AC.

These are the lengths that you multiply the common height of the two shapes by to find their area.

[fallen sleet]

measure of an arc is an angle or length?

when written as m before an arc

[dark sparrow]

angle

[somber coyote]

Kawai

[fleet palm]

use identity sin(x+y)= sinxcosy+cosxsiny

[solar peak]

What if we were to do it geometrically?

[fleet palm]

draw a right angled triangle, consider one of the 2 remaining sides as x and the other as 180-(90+x) find the sine of one angle and cosine of the other

[north heart]

why would you ever want to do that tho

[solar peak]

Because the book from which I'm learning from hasn't taught me unit circle or identities other than the 3 basic one

He has proven it geometrically but I don't understand it

[north heart]

honestly pick a better book then

[solar peak]

Yeah but there should be a way to do it geometrically

I wanna learn that too

[solar peak]

Okay I'll try

[lime pond]

help pls

[silent plank]

what have you tried?

[unique ore]

pls helpp, idk what to do

[dark sparrow]

you are asked for the SA:V ratio

so find the surface area and find the volume...

[unique ore]

ohh, i did that and i thought there was more too it

wait, but i have to find the ratio of [ans]:R

[dark sparrow]

and what did you get for the SA and V?

your SA should be something*R^2 and your V should be something*R^3

[unique ore]

2(r^2π) + r(2rπ) : r(r^2π)

i think it is that??

not very good with these kinds of stuff sry 🥲

[dark sparrow]

so you didn't simplify either one

was that a conscious choice or did it just not occur to you

[unique ore]

not occur to me

[dark sparrow]

well then simplify the SA and tell me what you get, then simplify the volume and tell me what you get

also it's R not r

[unique ore]

dude

[dark sparrow]

math is case-sensitive

also please don't call me dude

[unique ore]

ok

is it 4πr^2: r^3π ???

with r capslock

nvm ik what to do now

ty

[obtuse cypress]

Just to double check, the correct answer is 1280 right?

[dark sparrow]

yes

[dull whale]

can someone help me solve this?

[dark sparrow]

what is a generator in this context?

@dull whale

[hardy bay]

It could maybe be a meridian of the paraboloid since it generates it as a revolution surface.

[dull whale]

@dark sparrow

[tiny birch]

Hey can anyone help me with any of these questions I need help with a c and d

[north heart]

this a test?

or a quiz?

[tiny birch]

No it’s a past paper

[forest bridge]

It's multivariable calculus lmao

[tiny birch]

But it has more geometry

Differential geometry

[forest bridge]

You're not wrong

[north heart]

this channel is not for diff geo

it's for like

reg geo

[forest bridge]

Pre uni

[north heart]

think "hurr durr the angles in this triangle add up to 180"

[tiny birch]

Oh LOL MAN im not good at discord 😂

[north heart]

diff geo belongs in #diff-geo-diff-top

[tiny birch]

Thank you

[north heart]

which might actually be a better place to go than #❓how-to-get-help (although check that out too) bc idt many ppl will know diff geo in the help channels

[tiny birch]

It doesn’t let me type in most channels so idk what to do 😂

[forest bridge]

This belongs in multivariable calc tho

[north heart]

then tell 'em to put it there ¯_(ツ)_/¯

s'not like i know the difference between differential geometry and some crank's scribbles lmao

[spice stirrup]

How should I graph, y=3/2 Cos t/2

[placid parrot]

How do i solve this>

?

[spice stirrup]

Actually I have another question, how do I solve for pi? For example 2π\6

[dark sparrow]

@dull whale ok so you posted this while i was asleep. do you still need help with that problem?

[dark sparrow]

by definition of sin^-1

[dire pollen]

first make sure the domain and range are appropriate. after that, they are complementary formulas.

if sin-1 x = y, then sin y = x

[dull whale]

yes

[dark sparrow]

alright

so you need to find a straight line which (a) is parallel to the plane x-z+1 = 0 and (b) is contained in the paraboloid 25x^2 - y^2 - 6z = 0

do you understand that this is your goal?

@dull whale

it's going to be impossible to help you at all if you keep taking hours upon hours to respond to every message

[dull whale]

sorry
I'm here

[dull whale]

yes

[dark sparrow]

so you might want to write down the parametric equation of a line

ie in terms of a point on it and the direction vector

and then require that the vector be perpendicular to the normal of the plane (which is <1, 0, -1>) and also require that the point described by the parametric equation be contained in P for all values of t (which will require some coefficient-matching)

this may be somewhat unclear as im deliberately avoiding the assignment of any variable names to leave it entirely up to you

so if anything needs clarifying just tell me

[dull whale]

ok then, I will try something and ask again if i can't get an answer, thx

[unkempt belfry]

Hi, I'm having some trouble understanding some problems with trig identities, can anyone help?? Thnx in advance

[dusk lion]

help

[boreal wind]

how does this work?

I am rather confused I must admit

and what is P

does that mean perimeter?

and do I just assume that the pentagon is regular?

[floral shale]

The later area is gonna be the perimeter times height

If you think about it

If you stack perimeters you get lateral area

[upper karma]

I think this should belong here?

[vague turret]

(translation) ABCD is a square with an area of 16 cm². Been M the middle point of CD, N the middle point of AM and P the middle point of NC. What's the area of ANPB?

[knotty yoke]

How do I enter this expression into a calculator? It's for Trig, Complex numbers.
I'm using a Texas Instruments scientific calculator.

[storm portal]

@knotty yoke Already answered your question 👍

[harsh violet]

cos θ + sin θ > tan θ . how can i show this statement is true

[fleet fog]

Hi, I do not understand why the reflexive property works here. Please help

[fleet fog]

Using a property

[harsh violet]

wdym

idk what that is

[fleet fog]

Oh wait

this is an inequality

[trim breach]

What do you need to prove?

[azure crown]

it's the same angle

[fleet fog]

Is that because it shares the vertex 'A' and the rays are corresponding.

[rare sierra]

They both share the same angle making them congruent to one another.

[fleet fog]

Oh

Thanks

[rare sierra]

ye

[muted quest]

Need noob level handouts for projective geometry

Pls help

[robust jackal]

help pls

[upper karma]

If it's topology, #point-set-topology would be the best place as advanced users in topology can help you out

[molten delta]

Hello, I have a question about rotations

Suppose we are rotating a figure about a point, let’s say 90 degrees

Do we assume it rotates counter clockwise or clockwise?

[upper karma]

You may need more information about it, but according to my experience, we usually consider counterclockwise rotations and measure the angle (again counterclockwise) from the x-axis

[molten delta]

I see, thanks for the info

[cursive snow]

help ?

i've tried to simplify it and the best thing i've got is :
tan(α) tan(β)+sin(α+β) +1

[spice stirrup]

There's no options

[royal cedar]

write tan a = sin a/cos a and similar for tan b. then expand and make everything a single fraction and then simplify the numerator using cosine difference and sine sum formulas and then use product to sum on the denominator and things cancel

[lime pond]

help pls

[static jolt]

6. is BD

7. is CA and BA

8. is GE

1. is i(lower case)

2. is DCG

whats coplanar?

4. is B

i guess 3. is D

i guess 5. is B

[spiral abyss]

I can do this right?

[dark sparrow]

cos(r/2)/sin(r/2) is cot(r/2)

[spiral abyss]

Oh ty

[hybrid frigate]

in a right angled triangle like this one, how do you calculate the sin, cos, tan.. for the angle S, which is the right angle. Do you use the same formulas that you would use for calculating these values for R and U? I mean tan R would be opposite/adjacent which is 5/10. but how about tan for S?

[storm bobcat]

angle S is 90? thats the right angle

you dont need trig to work that out

[hybrid frigate]

yeah i think i just found that sin, cos, tan.. etc are static values for the 90 deg angle, so i guess you just need to memorize them

[dark sparrow]

those lengths are very

but also tan(90°) is either undefined, or unsigned infinity

[hybrid frigate]

they're great

[dark sparrow]

well you could have a triangle like that in spherical geometry i think

with the right radius...

[iron rain]

hello, I'm tasked to show that arccos(x) + arcsin(x) is a constant value and I'm supposed to find this value. Could somebody give me a hint? I have no idea where to start

[grave pond]

Start by plugging in some numbers for x, and see if it seems to hold. That will also tell you what the constant value is, so you have one more handle on the problem now.

Next, perhaps graph the two functions and see if that gives you any ideas.

[iron rain]

p sure the constant value is pi/2

the slopes look like they're (-) the other one

oh yeah thats true cos the derivatives are 1/sqrt(1-x^2) and -1/sqrt(1-x^2)

So their derivatives added together are zero

not sure if thats helpful..

OH if the derivative is zero then the function must be a constant

yepyepyep

got it

[grave pond]

You can also say arccos(x) = pi/2 - arcsin(x) because sin(t) = cos(pi/2 - t).

[iron rain]

Thats clever

isnt it awesome when you prove something in 2 different ways

[silent plank]

consider the definition/properties of diameter

[lime pond]

helpp pls

[jade hornet]

In this solution

why we just didn't wrote
answer as
$\vect {r}• (7j+4k)= 0$

[somber coyote]

Ned Stark
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[jade hornet]

this was the question

the book method was confusing

and complicated

[storm bobcat]

what type of equation is it asking for? cartesian or vector form?

[tulip minnow]

I have been using the formula Volume+Density=Mass

Will that formula always work?

[crystal kelp]

For the length of AB, you can use the Pythagorean theorem since the diagonals of a rhombus bisect each other at right angles.

For angle BAD, you can use the law of sines to find angle BAO and double it. (If you didn’t learn law of sines yet then I’m not sure what to do)

Area formula for a rhombus is (1/2)d1d2
(The 1 and 2 are subscripts) The formula is A = half of the product of the diagonals. In this case, you know the diagonals of a rhombus bisect each other, so the diagonals are 4.8 times 2 and 3 times 2 which is 9.6 and 6.

I hope I’m not too late

[crystal kelp]

I think the formula should be Volume times Density = Mass

Yes, the formula would always work

[tulip minnow]

Thank You!

[oak prawn]

this solution is in Cartesian form

[oak prawn]

you've said same thing yours is vector form

[lime pond]

help pls

[upper karma]

Hey there, I'd just like to understand, does the problem lie in understanding how you would prove what you need to, or are you struggling with putting what you need where you need (to fill the blanks basically).

Oh and one last thing, I'm kinda new here some I'm not accustomed to the rules or anything, but I feel like you might be better asking this at the help channels.

[errant flare]

What does it mean that there are many geometries?

I am reading a book where geometry is described as a structure < G, I > where g is a set of geometrical objects and i is a set of relations.

[dark sparrow]

it means that there are many things that get called "geometries" by mathematicians but which are not the same as the euclidean geometry to which you are accustomed.

[round snow]

Hi

I need help I’ve been pinging for over 2 hours

Im in server 23

My questions are there

[lunar rune]

hii

can we use tan/sin/cos formulas outside of rectangle triangle??

[real wyvern]

wdym?

[lunar rune]

like tan alpha= opposite side/adjacent side

[real wyvern]

oh not everytwhere

[lunar rune]

i knew it

[real wyvern]

there is rules of these

like law of sines law of cosines and law of tangents

[lunar rune]

ye

[real wyvern]

those can be used any triangle

[lunar rune]

ty for the help

[real wyvern]

yep

heres links for those

https://www.google.com/search?q=law+of+sines&rlz=1CATAVM_enUS991&oq=law+of+sine&aqs=chrome.0.0i131i433i512j69i57j0i512l8.3345j0j7&sourceid=chrome&ie=UTF-8&safe=active&ssui=on sines

https://www.google.com/search?q=law+of+cosies&newwindow=1&rlz=1CATAVM_enUS991&sxsrf=ALiCzsbN-jQFQSlf8rNtG96ouabuY8tm9A%3A1654104992014&ei=oKOXYoI9_8PQ8Q_97J3wDg&ved=0ahUKEwiCjeGj5Yz4AhX_ITQIHX12B-4Q4dUDCA4&uact=5&oq=law+of+cosies&gs_lcp=Cgdnd3Mtd2l6EAMyCggAELEDEIMBEEMyBAgAEAoyBAgAEAoyBAgAEAoyBAgAEAoyBAgAEAoyBAgAEAoyBAgAEAoyBAgAEAoyBAgAEAo6BwgAEEcQsAM6BwgAELADEEM6BAgjECc6CggAEIAEEIcCEBQ6BQgAEJECOgUIABCABDoICAAQgAQQsQM6CwgAEIAEELEDEIMBOgQIABBDSgQIQRgASgQIRhgAUIoDWPQZYIMbaAFwAXgAgAFbiAH_BZIBAjExmAEAoAEByAEKwAEB&sclient=gws-wiz&safe=active&ssui=on cosines

https://www.google.com/search?q=law+of+tangents&newwindow=1&rlz=1CATAVM_enUS991&sxsrf=ALiCzsbPGVPcG7PI2g_oQHy2pqbDXmuxEg%3A1654105001349&ei=qaOXYv_4FJKC0PEP1ZKEwAo&ved=0ahUKEwi_8Zqo5Yz4AhUSATQIHVUJAagQ4dUDCA4&uact=5&oq=law+of+tangents&gs_lcp=Cgdnd3Mtd2l6EAMyCwgAEIAEELEDEIMBMgUIABCABDIFCAAQgAQyBQgAEIAEMgUIABCABDIFCAAQgAQyBQgAEIAEMgUIABCABDIFCAAQgAQyBQgAEIAEOgcIABBHELADOgoIABCxAxCDARAKOgQIABAKOgoIABCxAxCDARANOgQIABANSgQIQRgASgQIRhgAUMwIWMgjYKglaARwAXgBgAG4BogBxQuSAQc4LjEuNi0xmAEAoAEByAEIwAEB&sclient=gws-wiz&safe=active&ssui=on tangents

@lunar rune

[lunar rune]

ty

[snow bane]

can anyone help me with 5 questions rq

[twin crane]

need help with finding good geoemtrical pictures! :(

i found some but the printer couldnt print them out cuz the resolution was 1200x something :/

[wet pond]

just use the prism volume formula

and area of a circle

area of base = pi * (3)^2

volume of cylinder = 10* pi * (3^2)

= 282.74333

=283 (to nearest whole)

[lapis moon]

i appreciate your effort for helping but i think we shld leave a chance for OP to do the calc him/herself, so that (s)he can learn by doing

we can give hints/explain concepts instead of spoonfeeding them the ans/soln

[upper karma]

i need a lot of help understanding 30 60 90 triangles, 45 45 90 triangles, sohcahtoa, and angle of elevation/depression my final is tomorrow but i have a notecard I can write all formulas and how to do it

but i dont know how to do it

[true hull]

starting off,

do you know this?

soh (sin = opposite/hypotenuse)

cah (cos = adjacent/hypotenuse)

toa (tan = opposite/adjacent)

[upper karma]

yes

[wet pond]

Ok, will do next time

[placid parrot]

Did I do this correctly??

[lapis moon]

,rccw

[nimble ingot]

how do i find the sides of an equilateral triangle using its area and hernons formula, is it possible? sry for sounding dumb

[lime pond]

help pls

[nimble ingot]

pls help me, youre better than me. my teacher said i should do this, but idk how to 😭

[wet pond]

which one

[lime pond]

all 😭

[lime pond]

what grade are you?

[nimble ingot]

ik hernons formula is for finding the area, if given the side lengths. but my teacher says i should findthe side lengths using the formula and area

[nimble ingot]

im 13

😦

[lime pond]

Dont trust me Im dumb😭 😭 sorry

[nimble ingot]

its ok im dumb too 🥲

[wet pond]

well for the first question, do you know about SAS, SSS, ASA and AAS?

[lime pond]

sas means side include angle side

asa means angle inculde side angle

sss - side, side, side

aas means angle angle non included side\

[wet pond]

yeah, cool

do you know how to use it to prove congruency?

[lime pond]

noo😭

our teacher only discuss whats the meaning and she gave us the assignment

[wet pond]

np

[lime pond]

and I dont know how to do it

[wet pond]

well, lets look at the rule SSS for now, as its the simplest

if 2 triangles are congruent, they are the same size and shape, just maybe rotated and moved around a bit

one rule for finding if they are congruent is SSS - if 2 different triangles both have the same side lengths, they are congruent

got that?

[upper karma]

is this a trapezoid?

[wet pond]

yes

[upper karma]

why doesn't the area of a trapezoid work on it lol?

[lime pond]

so if the shape has or had 3 size then there should be 3 sides? right?

[upper karma]

oh wait, nm

i miscalculated

fack

[wet pond]

I'm not sure what you mean by that

[lime pond]

yess

[wet pond]

ok

well, the other rules work similarly

SAS for example

if 2 triangles both have 2 sides that are the same length, and the angle between those sides is the same, then the 2 triangles are the same/congruent

[upper karma]

Is there anything special or weird about circles and spheres whose radius is pi?

[dark sparrow]

no

[real wyvern]

ok so if you know the hieght then if you divide it by $ sqrt(3)$ ou get half the sidelength and then multiply it by two to get sidelength

like this

$ 2 * /frac(h(sqrt(3))) $

hmm

[somber coyote]

A brief description and guide on how to use me was sent to your DMs!
Please use ,list to see a list of all my commands, and ,help cmd to get detailed help on a command!

[real wyvern]

then you could use herons formula

[somber coyote]

Jagteshwar(JPS838898)

[real wyvern]

nvm did mistake

$\sqrt{ (S-A) * (S-B) * (S-C) * S }$ where S = $\frac{3* \frac{2h}{\sqrt{3}}}{2}$

thats right

i believe

[somber coyote]

Jagteshwar(JPS838898)

[real wyvern]

@nimble ingot
see above

[teal kayak]

if you have a right triangle like this with hypotenuse of one what are the lengths of the adjacent and the opposite? how does a^2+b^2=1??

google has not provided satisfactory answers

[nocturne remnant]

What exactly are you confused by

[teal kayak]

how does a^2+b^2=1

[dark sparrow]

what are a and b?

are a and b meant to be the legs of this triangle?

[teal kayak]

ye

[dark sparrow]

okay then it's just pythagorean theorem

does this answer your question?

[rocky musk]

well you only know C don't you? it wouldn't be possible to know A or B

[dark sparrow]

yeah, it is impossible to know either of the legs from the hypotenuse alone

[teal kayak]

well in the case of the right triangle i showed these are the side lengths

[dark sparrow]

great, and?

we could not tell.

[rocky musk]

yea that would work

[steel breach]

i took my trig identities quiz and did great on it yay

[rocky musk]

0.86603^2+0.5^2=1

[dark sparrow]

this is not the only possible set of measurements

[teal kayak]

but it doesnt equal one

this is the problem

[rocky musk]

aha

rounding

[dark sparrow]

0.86603 is an approximate value

[teal kayak]

is the 0.86603 irrational

that would be cool

[dark sparrow]

the exact value, assuming the other side is exactly 0.5, is sqrt(3)/2

[teal kayak]

ah

cool

[rocky musk]

0.86603 is closer to 0.86602540378

[dark sparrow]

that is not exact either, daanhun.

[rocky musk]

yea its irrational but its closer :) mb

[dark sparrow]

grumble grumble

[rocky musk]

lol

[upper karma]

How does that fit in with geometry/trig

[hollow plume]

It’s literally a triangle

When you’re studying triangles you’re studying shapes

When you’re studying shapes, that’s geometry

[upper karma]

Deleted message

Smth about fractals

[hollow plume]

Ok 😂👌🏻

[slender mist]

Hey y'all

i got a big test tmrw

can someone help me with this ?

[upper karma]

Just plug in values for x

[hollow plume]

You got it right

0.1^3 will turn out to be a smaller number than 0.1

0.1^3 is 0.001

[night hedge]

counter example is basically just reverse of the sign to <= in this case i suppose

then 0.1^3 <= 0.1 is true

[sleek mirage]

how do i find out the values of the variables this is the only problem that is confusing me

[hollow plume]

Set all three angles to 180 degrees because those three angles form a triangle. Find y (or z) first then substitute the answer for y (or z) then find the other variable

[night hedge]

i don't think you can find the values of y and z if you only have one equation: 180 = 50 + 3y + 4z

[hollow plume]

There is substitution

Solving right now…

[night hedge]

nah you will end up in two same numbers equaling each other

130 = 3y + 4z, y = (130-4z)/3, 130 = 3*(130-4z)/3 +4z 130-4z + 4z = 130, 130=130

[hollow plume]

That means all real numbers

[night hedge]

so you can't solve for two variables using one equation

hm

[hollow plume]

Wait

Y is 130/3, z is 0

[night hedge]

you cant have z as 0, or else the angle would be 0 degrees which is not true

[hollow plume]

Forgot about that…

The circle has a reason

A possible solution would be y=10 and z=25

[night hedge]

z = 9.5 and y = 95/3

the line i drew in the through the middle is the same as the middle of the circle to Q and to N

therefore the angles on the point P would be the same as the angles on point Q and N

so z = 9.5 and y = 95/3 @sleek mirage

hopefully u understand me because im asian and i suck at explaining

[sleek mirage]

i did it a different way and i got y = 30 and z = 10

[night hedge]

how did u do it

[sleek mirage]

because NQ is a diameter and is a central angle arc NQ = 180

so then i found the measure of angle P since it is inscirbed

3y = 90

y = 30

thats not what im saying

P would be 180/2

[night hedge]

nvm ff

[sleek mirage]

and then u just subtract all of the angles from 180 and ddivide by 4

[upper karma]

If someone could help in #help-7｜zen1thxyz I would love them forever

[night hedge]

i dont think that equals to 90 degrees

tbh

because PQ is not perpendicular to NP

[sleek mirage]

lets check the answer key

[night hedge]

ight

[night hedge]

yes you are correct

hm

i dont think i did anything wrong also

this is weird

[upper karma]

Nice about me

[silent plank]

PQ is perp to PN by Thales theorem

i dont think i did anything wrong also
subbing an equation back into itself achieves nothing. the question could be completed using the construction you described however it was unclear what calculations you did to reach your final values

[weak marlin]

Does anyone know polar coordinates graphing and word problems cause this is hardddd

[onyx hollow]

yes

that angle is 90 degrees

because 3y is 90 degrees

and therefore y = 30

and therefore 4z = 40 and therefore z = 10

the fact that 3y is 90 degrees is shown by this:

[runic kayak]

hi how is this computed in the calculator like with log sin 33 the answer that shows up for me isnt 9.7361

[dark sparrow]

,calc sin(33*pi/180)

[somber coyote]

Result:

0.54463903501503

[runic kayak]

like the result is different i dont get it 😦

[dark sparrow]

is there by any chance an instruction manual at the beginning of the book for how to use these tables

[vagrant carbon]

<@&286206848099549185>

[runic kayak]

no : ( heres the link! https://jscholarship.library.jhu.edu/bitstream/handle/1774.2/34271/31151014623072.pdf?sequence=35&isAllowed=y

[dark sparrow]

@vagrant carbon this is a probability problem. what is this doing in the geometry channel?

[vagrant carbon]

because i am in geometry and they give me this

i thought that was in geometry

i am sorry

Where is the channel of probability?

[dark sparrow]

#probability-statistics, shockingly enough.

[vagrant carbon]

thank u

i am sorry

[dark sparrow]

,calc 0.544639035^(1/9.736108765)

[somber coyote]

Result:

0.9394974712856

[dark sparrow]

huh

well that doesn't seem to be very informative

[vagrant carbon]

thats the answer ?

[dark sparrow]

no, that was my attempt at figuring out what's going on

i.e. whether the "log sine" was in fact the logarithm of the sine to some base

[vagrant carbon]

oh

[dark sparrow]

ah.

i think i figured this out

i looked up another log sine table

it seems that the entry in the log sine column is log(sin(x)) + 10

let's check this

,calc 10^(9.736108765 - 10)

[somber coyote]

Result:

0.5446390355275

[dark sparrow]

yup there we go

[dark sparrow]

the reason for this, so says the book i've turned up by googling, is to avoid the inconvenience of dealing with negative numbers in tables.

@vagrant carbon

[vagrant carbon]

yes

[dark sparrow]

wait sorry

wrong person

fuck

my bad

@runic kayak youre the one who asked about the trig table things

i pinged the wrong person im so sorry

[candid seal]

yo

sure

<@&286206848099549185>

[runic kayak]

oh my god thank you so much

[runic kayak]

THANK YOUUU !!!

[autumn trout]

How do you determine angle A?

[wise pawn]

are you familiar with the inscribed angle theorem and also the sum of angles in a polygon?

[autumn trout]

Yeah, Inscribed Angle Theorem states that the inscribed angle is 1/2 of the center angel and the arc, and that all angles in a triangle add up to 180°

[onyx hollow]

A = x/2

x = x/2 + 35 + 35

x = 140

just use this

[wise pawn]

I meant in general, sum of angles is 180*(n-2) with n being the number of sides. In particular for this quadrilateral is what I had in mind:

[autumn trout]

How do find angle A? @onyx hollow

[onyx hollow]

half of x

[autumn trout]

You need to find it before you can find x

[onyx hollow]

not really

the value of "A" relies on the value of "x"

[onyx hollow]

.

[autumn trout]

A = b + d + c
A = b + 35(2)

[onyx hollow]

Q = A + C + B

[autumn trout]

That'd be equal to x° I think

[onyx hollow]

as A is an inscribed angle that is "looking" to the arc BC, and x is the central angle that is "looking" to the arc BC, A is half of x

[autumn trout]

Ok so you can find x without finding A

How do you do that?

[onyx hollow]

A = x/2

[autumn trout]

Ok but how do you find the x?

[silent plank]

consider angle sums

[onyx hollow]

finding an equation solvable for x

[onyx hollow]

as i did here

[silent plank]

set up an equation and soolve

[autumn trout]

Ok that way works, x = 140, but wouldn't there be another way of using isosceles triangles?

[onyx hollow]

c = d is just a particular case of this

nothing changes, the rule a = b + c + d remais the same

[wise pawn]

for my picture the angle sum would be 360 = x/2 + 35+ 35 + (360-x) since those are the 4 angles inside the quadrilateral

[autumn trout]

Ok, thanks, the center angle/arc's degree is equal to all the angles of the triangle combined. In this case we're given an inscribed angle which is x1/2 and two other angles c & b which together add up to x, (x = a + b + c), so we've x = x1/2 + b + c

[lime pond]

hi help pls

[silent plank]

what's your issue with these?

[raw shore]

can help

[grave pond]

One more than this:

[static jolt]

1.) SSS

2.) SSA

4.) AAS

2.) SAS not SSA

5.) ASA

6.) SAS

3.) ASA

[tulip minnow]

what is ssss and like the other letters? i see them in my math class

but idk what they are

[static jolt]

s = side

a = angle

[tulip minnow]

ohhhh

okay

thanks you

[upper karma]

Yay

Jsjdsjjddkkfjjfughtjngflmrif id ix dud eiwbwkbciskoKkk((8 no ekieki)39388_&!8_!(!!jjrjzk8#(*!(izjdusukIs

[dark sparrow]

wrong server?

[fathom shell]

Anybody good at finance math and equations, and geometric series?

[humble bolt]

Geometric series? I'm alright at them

It's just like difference equations right

And you have the formula $S_n = \frac{a(1-r^{n})}{1-r}$

a is the first term
r is the ratio between the terms
So if it goes 2, 4, 8, 16
Divide the second term by the second term to get r (2)
And 2 is the first term

n is the nth term

[somber coyote]

Scott 🌙

[humble bolt]

Is there any specific part you struggle with? Solving a difference equation?

@fathom shell

[fathom shell]

Hey @humble bolt Thanks for asking. I could show you the problem I’m struggling with

It’s a word problem that I’m confused about. It might be asking for a geometric series, or something close. I learned about infinite and finite geometric series this week

[high trench]

Can anyone help me find the x in a polygon and find the sides of a polygon I don't know how to do it

[onyx hollow]

what is "x" in a polygon?

[high trench]

the unknown angle

[onyx hollow]

too vague

[humble bolt]

Yeah if you want just dm me so the others can discuss this other problem

[onyx hollow]

now i can solve something

[fathom shell]

Okay thanks

[humble bolt]

Do all those angles add to 360°? It kinda looks like that

[onyx hollow]

this polygon is a quadrilateral

[high trench]

yeah

[onyx hollow]

the sum of the inside angles is 360

that is
$[180-(4x+1)] + [180-(7x+4)] + [180-(5x+4)] + [180-(4x+9)] + [180-(9x-6)] = 360$

[somber coyote]

Fernando Coelho

[high trench]

Alright

[onyx hollow]

simplifying:
$5\cdot 180 - (4x+1) - (7x+4) - (5x+4) - (4x+9) - (9x - 6)= 3\cdot 180$

[high trench]

Okay thanks a lot

[onyx hollow]

wait

[onyx hollow]

thats not a quadrilateral

[high trench]

it has 5 sides

[onyx hollow]

its a pentagon

the sum of the inside angles is 540

[high trench]

yes

yep

[somber coyote]

Fernando Coelho

[onyx hollow]

$2\cdot 180 = 4x + 1 + 7x + 4 + 5x + 4 + 4x + 9 + 9x - 6$

[somber coyote]

Fernando Coelho

[high trench]

Okay that looks good now

Thanks again

[upper karma]

Would someone be able to see whether or not my working out is accurate?

[dark sparrow]

well you'll have to post it here for anyone to see it

[upper karma]

I figured, I was just making sure it was allowed

@dark sparrow

[dark sparrow]

it is not only allowed but basically required

lmao

but anyway ok lets see here

[upper karma]

Thanks for letting me know

[dark sparrow]

what's your goal here

[upper karma]

Just to make sure my working out is correct

[dark sparrow]

no, what's the goal of your working

what are you trying to achieve with it

[upper karma]

To determine the total area of a regular decagon

[dark sparrow]

ok

any regular decagon, or just a regular decagon with side length 8?

[upper karma]

Here is the question

@dark sparrow

[dark sparrow]

,rccw

[dark sparrow]

right...

in the future, post the problem ALONG WITH your work

[upper karma]

No worries

[dark sparrow]

anyway, i would double-check your rounding just to make sure you did not over-round anything

but other than that your work is okay

[upper karma]

Awesome! Thanks for checking it out

[somber frigate]

guys, how do i turn this into 2cos(2alpha)

[silent plank]

double angle identity

pythagorean trig identity

you do need to be careful with signs at the end
the end result isn't quite 2cos(2a)
unless you were given some restrictions on alpha

[floral shale]

How did you even read that

[silent plank]

with the experience of reading handwriting on this server

and context

[floral shale]

I can't tel if that's a 7-4sin or a 1-4sin or a 7-9 or a 1-9

[silent plank]

context was important

[tulip marten]

yeah, alpha is between 0 and pi/4

[rigid otter]

Can this be a valid proof?

[onyx hollow]

AP being always equal to BP seems false

[hazy thunder]

hi, I just want to ask whats the formula to get angle C in law of cosine?

[dark sparrow]

are you asking how to get the value of $C$ in $c^2 = a^2 + b^2 - 2ab \cos(C)$?

[somber coyote]

Ann

[wheat dove]

In △ABC, D, E, and F are points on BC, CA, and AB, respectively, such that AD, BE, and CF are concurrent lines. Points P, Q, and R respectively on EF, FD, and DE are such that DP, EQ, and FR are concurrent. Prove that AP, BQ, and CR are also concurrent.

How do i start?

[steel breach]

Why wouldn't this question be equal to 5pi/3 ? asap please

[silent plank]

5pi/3 isn't in the range of the arcsin function

[wild bluff]

A circle of radius 1, from origin O
Two points on the circle P,Q where ∠POQ = 90°
And the midpoint of PQ = M
And a circle from origin M, and radius MP

The area of the second circle outside the first circle is 0.5.

[wild bluff]

It's actually pretty easy lol

[silent plank]

that doesn't sound true

[wild bluff]

Yea it's pretty cool

[silent plank]

the area isn't 0.5

[wild bluff]

Area of the blue part is 0.5

[silent plank]

1 sec might've miscalculated

ok yeh, it is

[wild bluff]

Yea it's a famous result, kinda surprising

And gave the Greeks false hope for squaring the cube

https://en.wikipedia.org/wiki/Lune_of_Hippocrates

[spiral abyss]

Can anyone teach me how to make graph of this function @here

[red coyote]

Can anyone show me the completed figure for Euclid's elements book two proposition twelve

[supple dune]

well ima assuming u know teh graph of sin x over [-2pi, 2pi]

if u don't u can just google a picure of it

the problem is assuming that u know this

then -sin x is just flippingt he graph of sin x over the x-axis

and just do that over the range [-2pi, 2pi] and u are done

generally with these types of trig graphing questions its just applying the right transformations to get the graph

so if u want more practice on these questions i would recommend reading smth related to transformations on grpahs

[daring bramble]

So I have this problem where I need to prove that the angle inscribed in a semicircle is a right angle, and the hint was to use the slopes to find that the lines forming the angle are perpendicular,can anyone over any help

[supple dune]

there's a much easier way to do this which is just to use inscribed angel thm

but if the book insists on doing it this way

then here ya go

from the fact that (b,c) is on the circle we get c = \sqrt{a^2-b^2}

then u just have to check that the slopes of lines AC and BC hae a product of -1

which is easy to check

[modest saddle]

Hiiii

Does anyone here knows the answer?

[green osprey]

So first you gotta find the radius

The great circles circumference is is 20pi

20pi = 2pi r

10 = r

The formula for the surface area is 4×pi×r² irrc

So 4×pi×10²

Giving you 400pi Sq units

[green osprey]

I'm pretty sure I'm right but maybe look over what I said incase I made a stupid error

[modest saddle]

Thank you

[onyx hollow]

bad approach to the problem

it is always a bad idea to use coordinate geometry if you did not try all you could on euclidean

[onyx hollow]

in this case by drawing the segment OC you can easily find that the angles CAB and ABC add to 90

[supple dune]

i mean the problem itself said in the hint to use coord so i did it that way

but obviously coord in general is not the best way

its one of those ways thats

like

"guaranteed" to be right

to a certain degree

but then again its very mindless and takes a lot of time

and is also easy to make mistakes

so i def would not recommend it as your first aporach

@daring bramble

[onyx hollow]

coordinate geometry is usually 99% about euclidean and 1% about algebra

[wise pawn]

I've never thought about doing it with slopes like this, that's kinda neat even though it's not ideal, it's not that bad

[spiral abyss]

Thankyou

[stuck chasm]

Hello I’m new here I don’t know how this works but I need help with maths , we have to do this

[stuck chasm]

IV and V we have to find the equations of the functions

[runic beacon]

what issues do you have with this?

and what is the question?

[upper karma]

Need help on first one, and the second one I’m not sure if my answer is correct which was 173.2 for the hypotenuse

I did tan(78) multiplied by 36

Which was 169.4 which I think is the length of the bottom part of the triangle and then multiplied that by itself then multiplied 36 by 36 then added the both answers together and squared it

N the final answer I got was 173.2 for the length of the hypotenuse but I’m not sure I did it right

[silent plank]

you mean square rooted it?

try not to round too early

that method works but it's making it more complicated than needed

tan isn't the only trig function

[fleet fog]

For postulate 1-4: (Through any 3 non collinear points there is exactly one plane) does that mean that all the points have to be non collinear or just they all can't be on the same line but 2 of the points can be?

[silent plank]

there is no straight line that passes through all 3 points

[fleet fog]

So it a line can pass through 2 of the points but not at 3 right?

[echo blaze]

can someone help me with this plsss

[real wyvern]

Yes

[slow spruce]

Do you remember how many degrees angle OPR must be?

[distant marsh]

We consider a Parallelogram ABCD in which AB = 2BC. If K is the Middle of AB Prove that CK is vertical to DK

I have no idea how I am supposed to solve this, any help?

[rigid oar]

Why do that subtract 59.4 from 180? I got 59.4 as my answer using the sine rule so why do they subtract 180 from it

oh

[dark sparrow]

the angle x is obtuse

[rigid oar]

yeah, I just didn't realise that I had to account for it being obtuse

[latent silo]

Given are two circles with centers M1=(0;0),M2=(xM=0;yM=−253)
and radii r1=203,r2=5
.
Calculate coordinates of intersection points S1,S2
. Report all results as whole numbers or as fractions.

S1: x,y
S2:x,y

[eager bolt]

a drawing would help

[upper karma]

https://cdn.discordapp.com/attachments/818589757440917534/984130553848672266/unknown.png

just gonna put this here as it's a nice visual definition of trig functions

[quaint raven]

Yea

For the triangle cbd

Find BC then do cosin to find x

Yea

Look first you should count bc

We now that c is 45 and a is 90 which mean b should be 45

So cos30=BC/16

Which mean BC=16cos30

Oh

Which only Pythagoras theorem ?

I'll have dinner and help you ok

See another guy

[summer canopy]

can someone explain it better how they go to the answer?

[summer canopy]

.

[upper karma]

someone help me out?

finding domain and range

and then the equation that models the equation

[slow spruce]

Domain are the x values you can put in

Range is the y values you can get out

So look at the x that are possible, from left to right

And the y that you get out, from bottom to top

[upper karma]

-5 < x < 2 ?

oh there are whole channels for math help

I'll just have an ask over there

[slow spruce]

It's ok to ask here too, but you can ping people in a help channel after 15 minutes

[slow spruce]

I can see why you say that. It might not look like it because it gets super steep, but this function will eventually be over top every positive x value

[north heart]

*it's okay to ask here on the premise that no active discussion is happening

like if two ppl are talking abt a problem don't interrupt

in this case ur chilling but keep it in mind

[upper karma]

Can someone help me with this?

I need to find the variables

[quaint raven]

All the sides ar equal ?

[quaint raven]

Are these sides all equal so it's a regular square or you have other info ?

[deep hatch]

not possible bc 4x = 2y and 4y = 2x

[quaint raven]

Yea

Y cannot equal to 2x and 1/2 X in the same time

No solution

[west cedar]

Hello!

can someone help me with

Geography

[dark sparrow]

this is not geography

this is not geometry either

this is a multiplication problem

do you know how to multiply numbers?