#geometry-and-trigonometry | Mathematics | Page 332

tender prawn Dec 9, 2020, 8:53 PM

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this is a joke right

silk patio Dec 9, 2020, 8:53 PM

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Stop harassing me

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I will report you

upper karma Dec 9, 2020, 8:53 PM

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If I draw a square and put the diagonal between the center of each circle, then the radius is not applicable, right? I'm still not sure how this will work

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<@&268886789983436800> help please

tender prawn Dec 9, 2020, 8:54 PM

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upper karma If I draw a square and put the diagonal between the center of each circle, then ...

ok one sec

buoyant tapir Dec 9, 2020, 8:54 PM

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Need help w this

📎 image0.jpg

silk patio Dec 9, 2020, 8:54 PM

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@upper karma you join the centres up

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To make a right triangle

upper karma Dec 9, 2020, 8:54 PM

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ah I see

umbral snow Dec 9, 2020, 8:54 PM

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This channel is doing real well

silk patio Dec 9, 2020, 8:54 PM

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The length of the hypot is R+r

green tree Dec 9, 2020, 8:55 PM

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📎 unknown.png

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yo guys im struggling

buoyant tapir Dec 9, 2020, 8:55 PM

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I rly need help on that one

tender prawn Dec 9, 2020, 8:56 PM

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green tree

have you tried anything so far

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oh bruh im so dumb

green tree Dec 9, 2020, 8:57 PM

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yes

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i tried everything

tender prawn Dec 9, 2020, 8:57 PM

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ok what have you tried

green tree Dec 9, 2020, 8:58 PM

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i found TC couldn't figure the rest out

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TC = AT

tender prawn Dec 9, 2020, 8:59 PM

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what do you know about the relationship between ft and at

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wait nvm

upper karma Dec 9, 2020, 9:00 PM

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Euler, how do I account for the small space at the bottom?

📎 circle.jpg

green tree Dec 9, 2020, 9:00 PM

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@tender prawn so /

tender prawn Dec 9, 2020, 9:00 PM

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wat

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draw the lines from f to a b c

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what is fb congruent to

upper karma Dec 9, 2020, 9:02 PM

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chicken602, do you know what I should do?

tender prawn Dec 9, 2020, 9:02 PM

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uh lemme take a look

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a not so elegant way would be using geometric sequence

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hold on

green tree Dec 9, 2020, 9:03 PM

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yo guys i need h elp again

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https://i.imgur.com/ag6jshC.png

Imgur

main meadow Dec 9, 2020, 9:03 PM

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Im so confused

tender prawn Dec 9, 2020, 9:03 PM

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bruh at least think about it before asking

main meadow Dec 9, 2020, 9:03 PM

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📎 image0.jpg

green tree Dec 9, 2020, 9:03 PM

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bro

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ive been thinking for 50 minutes

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i cant understand this anymore

tender prawn Dec 9, 2020, 9:04 PM

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main meadow

shaded region over whole region?

main meadow Dec 9, 2020, 9:04 PM

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Shaded

tender prawn Dec 9, 2020, 9:04 PM

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area of shaded region isn't 9 pi btw

main meadow Dec 9, 2020, 9:04 PM

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Oh

tender prawn Dec 9, 2020, 9:04 PM

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area of shaded is whole circle - white circle (4pi)

main meadow Dec 9, 2020, 9:04 PM

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Its 5

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Yeah

tender prawn Dec 9, 2020, 9:04 PM

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yeah

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wait what're the answer choices

main meadow Dec 9, 2020, 9:04 PM

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📎 image0.jpg

tender prawn Dec 9, 2020, 9:05 PM

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upper karma Euler, how do I account for the small space at the bottom?

try 2((R-r)^2) = (R+r)^2

main meadow Dec 9, 2020, 9:05 PM

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What is it

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@tender prawn

upper karma Dec 9, 2020, 9:06 PM

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is big R for the big circle or small?

main meadow Dec 9, 2020, 9:06 PM

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V

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B

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Big

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Circle

tender prawn Dec 9, 2020, 9:07 PM

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upper karma is big R for the big circle or small?

R for big, r for small

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oh im dumb lol

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what's the total region

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like u have shaded/total

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what's the total

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u know shaded is 5pi

main meadow Dec 9, 2020, 9:09 PM

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Its5/9

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Cuz the total is 9pi

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And its asking for the shaded

tender prawn Dec 9, 2020, 9:09 PM

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mhm

main meadow Dec 9, 2020, 9:09 PM

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So 9-4=5

tender prawn Dec 9, 2020, 9:09 PM

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5/9 should be the correct answer

main meadow Dec 9, 2020, 9:09 PM

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5/9

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Yeah

main meadow Dec 9, 2020, 9:27 PM

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📎 image0.jpg

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@tender prawn

tender prawn Dec 9, 2020, 9:27 PM

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label the sides and do some pythagorean theorem

main meadow Dec 9, 2020, 9:28 PM

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Can u help me

tender prawn Dec 9, 2020, 9:28 PM

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im not gonna tell u the answer

main meadow Dec 9, 2020, 9:28 PM

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No but help me

tender prawn Dec 9, 2020, 9:28 PM

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label the sides you currently have

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and what tool do you have relating to right triangles

main meadow Dec 9, 2020, 9:29 PM

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So

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📎 image0.jpg

tender prawn Dec 9, 2020, 9:29 PM

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um

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are you sure

main meadow Dec 9, 2020, 9:29 PM

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Idk

tender prawn Dec 9, 2020, 9:29 PM

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write down the side lengths you currently have on the diagram

main meadow Dec 9, 2020, 9:30 PM

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📎 image0.jpg

tender prawn Dec 9, 2020, 9:30 PM

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mhm

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so using the pythagorean theorem

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which length can you find next?

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currently there are two unknown side lengths

main meadow Dec 9, 2020, 9:31 PM

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Idk

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Yes

tender prawn Dec 9, 2020, 9:31 PM

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AC and AD

main meadow Dec 9, 2020, 9:31 PM

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AD

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C-D is 2

tender prawn Dec 9, 2020, 9:31 PM

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well to find AD you would need AC

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so how do you find AC

main meadow Dec 9, 2020, 9:31 PM

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Ok

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So 2^2+1^2=c2

tender prawn Dec 9, 2020, 9:32 PM

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mhm

main meadow Dec 9, 2020, 9:32 PM

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So

tender prawn Dec 9, 2020, 9:32 PM

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what is c

main meadow Dec 9, 2020, 9:32 PM

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2+rad(1)=c

tender prawn Dec 9, 2020, 9:33 PM

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wat

main meadow Dec 9, 2020, 9:33 PM

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C is 2

tender prawn Dec 9, 2020, 9:33 PM

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no u have 4 + 1 = (AC)^2

main meadow Dec 9, 2020, 9:33 PM

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Oh

tender prawn Dec 9, 2020, 9:33 PM

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so what can u do now

main meadow Dec 9, 2020, 9:33 PM

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Sq root

tender prawn Dec 9, 2020, 9:34 PM

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📎 unknown.png

main meadow Dec 9, 2020, 9:34 PM

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Ok

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Then you do same?

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Answer is 3?

tender prawn Dec 9, 2020, 9:35 PM

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should be

main meadow Dec 9, 2020, 9:35 PM

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Ok

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Im not good with traiangles

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I mena

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Not like that

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I just didnt understand

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Im preping for the shsat

golden girder Dec 9, 2020, 9:36 PM

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main meadow Answer is 3?

if u ask DA line yes it is 3

main meadow Dec 9, 2020, 9:36 PM

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Whats da

tender prawn Dec 9, 2020, 9:38 PM

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idk how proper of a solution u need but u can like

main meadow Dec 9, 2020, 9:38 PM

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What

golden girder Dec 9, 2020, 9:38 PM

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can anyone 104.I

main meadow Dec 9, 2020, 9:38 PM

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Is fhat

tender prawn Dec 9, 2020, 9:38 PM

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look at the case where it's a square because it deosn't specify what parallelogram it is

golden girder Dec 9, 2020, 9:38 PM

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help*

main meadow Dec 9, 2020, 9:38 PM

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Make fullscreeb pls

golden girder Dec 9, 2020, 9:39 PM

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it is maximum size

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all text are seen

golden girder Dec 9, 2020, 9:39 PM

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tender prawn look at the case where it's a square because it deosn't specify what parallelogr...

okay i will try

upper karma Dec 9, 2020, 9:41 PM

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Looks tough

main meadow Dec 9, 2020, 9:41 PM

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Is nick lord ur prof

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@golden girder

upper karma Dec 9, 2020, 9:41 PM

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You should hide that part lol

main meadow Dec 9, 2020, 9:42 PM

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Lol

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Its his prof

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https://encrypted-tbn0.gstatic.com/images?q=tbn:ANd9GcStmChk643hloHWBj1dg2AoXYn3t0hmift2sF0OdTfC_Q&s

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Maybe?

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Im not tryna be stalky

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I am just curios

golden girder Dec 9, 2020, 9:43 PM

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actually it is not my question

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i do it for my friend

tender prawn Dec 9, 2020, 9:43 PM

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kekw

golden girder Dec 9, 2020, 9:43 PM

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maybe nick lord is his prof

golden girder Dec 9, 2020, 9:44 PM

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upper karma You should hide that part lol

actually as i said it is not my question and i just help my friend at this question

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there is not anything illegal 🙂

tender prawn Dec 9, 2020, 9:45 PM

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its just for your own safety

upper karma Dec 9, 2020, 9:47 PM

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Those problems are hard holy

golden girder Dec 9, 2020, 9:48 PM

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i was trying for 2hours

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i am a bit confused i think maybe there is some easy way i dont know

upper karma Dec 9, 2020, 9:48 PM

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Anyway the ratio between areas most certainly is invariant so just let the parallelogram be a square

tender prawn Dec 9, 2020, 9:48 PM

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^

upper karma Dec 9, 2020, 9:49 PM

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It will probably get you the answer

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But it's not a solid proof

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Unfortunately

golden girder Dec 9, 2020, 9:49 PM

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upper karma Anyway the ratio between areas most certainly is invariant so just let the paral...

can we call all parallelogram square?

tender prawn Dec 9, 2020, 9:49 PM

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no

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its just asking for a solution

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it doesn't specify what type of parallelogram so you can solve it for the case where it's a square and get the answer

golden girder Dec 9, 2020, 9:50 PM

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okay

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i retry

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thanks in advance

upper karma Dec 9, 2020, 9:52 PM

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The intended method involves sum and difference of triangles whose areas are fractions of the parallelogram's

tender prawn Dec 9, 2020, 9:55 PM

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📎 PXL_20201209_215522806.jpg

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sorry its messy

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basically i have A+B+C=pi

upper karma Dec 9, 2020, 9:56 PM

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What is your goal?

tender prawn Dec 9, 2020, 9:56 PM

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and the second line

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im supposed to prove the second line

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ok elmme send the problem

upper karma Dec 9, 2020, 9:56 PM

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I see

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Sum to product identities

tender prawn Dec 9, 2020, 9:56 PM

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📎 unknown.png

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oh

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ok ill take a look at that

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did i mess up my work i feel like i did

silk patio Dec 9, 2020, 9:59 PM

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You know you can do it with a single picture

tender prawn Dec 9, 2020, 9:59 PM

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like on a unit circle

silk patio Dec 9, 2020, 9:59 PM

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Yeah, consider a triangle with those angles

tender prawn Dec 9, 2020, 10:00 PM

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oh

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bruh

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a right triangle

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or any triangle

silk patio Dec 9, 2020, 10:00 PM

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It has to have those angles

tender prawn Dec 9, 2020, 10:00 PM

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o yea

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ok thx

silk patio Dec 9, 2020, 10:00 PM

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Are you practicing for an Olympiad?

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So the area can be found in 2 ways

tender prawn Dec 9, 2020, 10:01 PM

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not in particular no

silk patio Dec 9, 2020, 10:01 PM

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R^2[sin(2a)+sin(2b)+sin(2c)]

tender prawn Dec 9, 2020, 10:01 PM

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1/2 ab sinC and 2R^2 sinA sinB sinC?

silk patio Dec 9, 2020, 10:01 PM

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Yeah with a half

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Let me draw it tho

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Cause that’s not quite careful enough

tender prawn Dec 9, 2020, 10:03 PM

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ok

silk patio Dec 9, 2020, 10:03 PM

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📎 image0.png

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Look at the three centre triangles

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Area (1/2)R^2sin(2a)

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Or you can do the whole triangle in one go using the extended sine rule

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(1/2)xysin(a) where x=2Rsin(b) and y=2Rsin(c)

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So if you equate you get the formula

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There is always an easy way to do things

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Think smart not hard

tender prawn Dec 9, 2020, 10:05 PM

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ahh okay

upper karma Dec 9, 2020, 10:16 PM

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📎 unknown.png

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y=50 and x=80?

jagged basalt Dec 9, 2020, 10:16 PM

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yep

upper karma Dec 9, 2020, 10:16 PM

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kk

jagged basalt Dec 9, 2020, 10:17 PM

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is this a olympics question?

upper karma Dec 9, 2020, 10:17 PM

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hm?

jagged basalt Dec 9, 2020, 10:18 PM

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📎 20201210_011824.jpg

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can you solve this ?

upper karma Dec 9, 2020, 10:18 PM

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i cant understand anything

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i dont know what language that is

jagged basalt Dec 9, 2020, 10:20 PM

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you do not need to understand anything. it is writing values cd cember

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there is half circle

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you can understand br: cm

surreal sleet Dec 9, 2020, 10:40 PM

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📎 unknown.png

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can someone help me

buoyant karma Dec 9, 2020, 10:52 PM

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<@&286206848099549185>

valid osprey Dec 9, 2020, 10:59 PM

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surreal sleet

ive seen this question 99^10x9999 times in the past 2 days

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what does this mean

📎 unknown.png

surreal sleet Dec 9, 2020, 11:01 PM

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congruent

valid osprey Dec 9, 2020, 11:01 PM

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so they;'ve said

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these two sides are equal

📎 unknown.png

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twice?

surreal sleet Dec 9, 2020, 11:01 PM

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if they are conqruent

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they are equal

valid osprey Dec 9, 2020, 11:02 PM

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thats a weird ass question

upper karma Dec 9, 2020, 11:03 PM

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Think this is a trig question. How do I solve for x in

📎 unknown.png

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I've tried everything I know of, so I am restorting to here

tender prawn Dec 9, 2020, 11:07 PM

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x in what

upper karma Dec 9, 2020, 11:07 PM

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I sent an image, do you see it?

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sin^2(t) = (x+3)^2 / 2

tender prawn Dec 9, 2020, 11:08 PM

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yeah

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whats the question

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oh

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solve for x

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https://www.wolframalpha.com/input/?i=sin^2(t)%3D((x%2B3)^2%2F2)

sin^2(t)=((x+3)^2/2) - Wolfram|Alpha

Wolfram|Alpha brings expert-level knowledge and capabilities to the broadest possible range of people—spanning all professions and education levels.

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oh

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multiply by two and take sqrt of both sides probably

upper karma Dec 9, 2020, 11:12 PM

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I would do that, but that doesn't give me the answer I'm looking for.

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Which channel would I post this in

📎 unknown.png

unique marten Dec 9, 2020, 11:18 PM

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📎 unknown.png

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heeeeeeelepp

tender prawn Dec 9, 2020, 11:26 PM

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unique marten

just plug in values?

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or u can do the whole shift thing

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its probably d

upper karma Dec 10, 2020, 12:06 AM

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It is D

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X > 1 and Y > 4

arctic mirage Dec 10, 2020, 12:20 AM

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hey can someone help

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📎 unknown.png

mortal mason Dec 10, 2020, 12:30 AM

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is the way I drew the angles for this triangle true?

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📎 e916234909a472a8e015c8386dd8e938.png

upper karma Dec 10, 2020, 12:34 AM

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📎 image0.jpg

fathom root Dec 10, 2020, 12:51 AM

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https://gyazo.com/2183119033e657c6c7724635f32eb865

Gyazo

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help pls

tawdry ruin Dec 10, 2020, 1:03 AM

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Anyone

📎 image0.jpg

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@knotty merlin

jaunty marsh Dec 10, 2020, 1:03 AM

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$x(36+x)=60^2$

somber coyoteBOT Dec 10, 2020, 1:03 AM

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AV8312

📎 688511860500201522.png

jaunty marsh Dec 10, 2020, 1:05 AM

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By the power of a point theorem

opal forge Dec 10, 2020, 1:10 AM

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Anyone here god tier at trig?

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Like elite lol

zenith garnet Dec 10, 2020, 1:37 AM

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📎 Screen_Shot_2020-12-09_at_5.36.57_PM.png

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how do i solve this?

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i feel like I'm missing something but idk

silent plank Dec 10, 2020, 1:40 AM

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what's the actual question

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i see a statement,
two triangles with markings and a blue pip
what's there to solve?

eager ocean Dec 10, 2020, 3:18 AM

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how do I do this

📎 unknown.png

upper karma Dec 10, 2020, 9:40 AM

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📎 image0.png

upper karma Dec 10, 2020, 1:33 PM

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📎 unknown.png

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Im confused with all of these

silent plank Dec 10, 2020, 1:39 PM

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what's the source

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of your confusion

upper karma Dec 10, 2020, 1:43 PM

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Like im sure what im meant to put for them

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Or how to know which to put

silent plank Dec 10, 2020, 1:44 PM

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the justification for congruence if it exists

upper karma Dec 10, 2020, 1:47 PM

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📎 congruent-triangles.png

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are these all of them?

silent plank Dec 10, 2020, 1:52 PM

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yes

upper karma Dec 10, 2020, 1:53 PM

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so for #2 it would be none?

silent plank Dec 10, 2020, 1:55 PM

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yes

upper karma Dec 10, 2020, 1:56 PM

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then MNP would be congruent to

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QRP?

silent plank Dec 10, 2020, 1:56 PM

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if the answer to the first part is NONE

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there would be no congruence

upper karma Dec 10, 2020, 1:56 PM

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ohh

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makes sense

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for #3

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MNP congru to MQP/

sleek dove Dec 10, 2020, 2:46 PM

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I need help

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📎 20201210_094651.jpg

alpine niche Dec 10, 2020, 2:56 PM

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Hi, how can I know the direction of the following normalised vector? [0.7 -0.7]

sleek dove Dec 10, 2020, 2:58 PM

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Wait t/c?

thorny lintel Dec 10, 2020, 4:05 PM

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how would i do this question?

📎 image0.jpg

silent plank Dec 10, 2020, 4:08 PM

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know properties of the sine function and/or unit circle

thorny lintel Dec 10, 2020, 4:11 PM

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how would i start the question

upper karma Dec 10, 2020, 4:14 PM

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if you're familiar with the unit circle you'd know that sin(x) = 0 when x is a multiple of 180. Find all multiples of 180 that are less or equal to* than 720 degrees*

green osprey Dec 10, 2020, 4:23 PM

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hey

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i have a math question

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In parallelogram QRST if TU=18 find TR.

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📎 unknown.png

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can someone pls help

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<@&286206848099549185>

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anyone pls

upper karma Dec 10, 2020, 4:33 PM

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ok so if TU = 18, then that must mean that RU also equals 18, yes?

green osprey Dec 10, 2020, 4:34 PM

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yeah

upper karma Dec 10, 2020, 4:34 PM

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so find tr from there

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segment addition

green osprey Dec 10, 2020, 4:34 PM

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oh

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36?

upper karma Dec 10, 2020, 4:34 PM

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👍

green osprey Dec 10, 2020, 4:36 PM

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ty

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📎 unknown.png

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i got 13,-11

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am i right

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this hw is kinda hard

stuck dragon Dec 10, 2020, 4:42 PM

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what type of quadrilateral is that

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parallelogram?

green osprey Dec 10, 2020, 4:42 PM

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parallelogram

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ye

stuck dragon Dec 10, 2020, 4:42 PM

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ah

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i'll check

green osprey Dec 10, 2020, 4:42 PM

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wouldnt 15=2x+y

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and 17=3x+2y

stuck dragon Dec 10, 2020, 4:45 PM

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yeah

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yeah i got x=13 y=-11

thorny lintel Dec 10, 2020, 4:46 PM

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how would i start this question?

📎 image0.jpg

upper karma Dec 10, 2020, 4:46 PM

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,rotate

somber coyoteBOT Dec 10, 2020, 4:46 PM

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📎 706357388072189983.png

upper karma Dec 10, 2020, 4:48 PM

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@thorny lintel do you know in which quadrants tan(x) is negative?

thorny lintel Dec 10, 2020, 4:49 PM

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@upper karma quadrant IV and II

upper karma Dec 10, 2020, 4:49 PM

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right, and are you allowed to use a calculator to solve this problem?

thorny lintel Dec 10, 2020, 4:50 PM

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yes

upper karma Dec 10, 2020, 4:51 PM

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okay, so you'd do arctan(-1.428) and you should get about -55* for that

thorny lintel Dec 10, 2020, 4:51 PM

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what’s arctan?

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would -55 be the only answer?

upper karma Dec 10, 2020, 4:51 PM

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the inverse function of tan

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also known as $\tan^{-1}

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$\tan^{-1}

thorny lintel Dec 10, 2020, 4:52 PM

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so -55 would be the only value?

upper karma Dec 10, 2020, 4:52 PM

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no

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remember that you need all values within the domain of [90, 270]

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and for tan to be negative, it needs to be in the second and fourth quadrants. So you need to find the reference angles in quadrants II and IV

thorny lintel Dec 10, 2020, 4:54 PM

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oh so -55 is just an angle

upper karma Dec 10, 2020, 4:54 PM

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yes, put you can't use -55 because it's not in the domain [90, 270]

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Do you know how to find the reference angle?

thorny lintel Dec 10, 2020, 4:55 PM

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i have some knowledge of it but not in depth

upper karma Dec 10, 2020, 4:56 PM

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can you find the reference angle of 55 in the second quadrant?

thorny lintel Dec 10, 2020, 4:56 PM

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would it just be 55?

upper karma Dec 10, 2020, 4:57 PM

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no

thorny lintel Dec 10, 2020, 4:57 PM

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oh i’m not sure then

upper karma Dec 10, 2020, 4:58 PM

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so the value of the angle MUST be in quadrant 2 or quadrant 3. because
Quad 1: 0-90
Quad 2: 90-180
Quad 3: 180-270
Quad 4: 270-360
and your sheet says to find an angle between 90 and 270. Do you now understand why 55 wouldn't work?

thorny lintel Dec 10, 2020, 4:59 PM

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yes

green osprey Dec 10, 2020, 5:00 PM

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after you guys are done can i get a bit of help

arctic cobalt Dec 10, 2020, 5:00 PM

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Anyone know how I would solve this tan6= 30000/x

📎 image0.jpg

green osprey Dec 10, 2020, 5:01 PM

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📎 unknown.png

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i know im stupid but does this work

thorny lintel Dec 10, 2020, 5:01 PM

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@upper karma wait so how would arctan help?

upper karma Dec 10, 2020, 5:01 PM

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since tan is positive in quadrant 3, that restricts the value of the angle to quadrant 2 (where tan is negative). To find the reference angle in quadrant 2, we just do 180 - 55 = 125. We can check our work by doing tan(125) and seeing that our answer is indeed -1.42 @thorny lintel

arctic cobalt Dec 10, 2020, 5:01 PM

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How did you write that in the calculator

green osprey Dec 10, 2020, 5:02 PM

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mathway.com

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now can someone pls help

arctic cobalt Dec 10, 2020, 5:02 PM

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Yeah that’s actually right thx

upper karma Dec 10, 2020, 5:02 PM

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arctan will give us the angle

green osprey Dec 10, 2020, 5:02 PM

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📎 unknown.png

upper karma Dec 10, 2020, 5:02 PM

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the value of x

green osprey Dec 10, 2020, 5:02 PM

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The diagonals are perpendicular.
The diagonals bisect each other.
One diagonal bisects the opposite angles.
One pair of opposite angles are congruent.

#

pls help

thorny lintel Dec 10, 2020, 5:03 PM

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ooh ok thank you @upper karma

upper karma Dec 10, 2020, 5:04 PM

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np

green osprey Dec 10, 2020, 5:04 PM

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;-;

upper karma Dec 10, 2020, 5:04 PM

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we know that they bisect each other, right?

green osprey Dec 10, 2020, 5:04 PM

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they do

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yeah i guess

upper karma Dec 10, 2020, 5:04 PM

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of course they do, we can see it. so that leaves only 3 other answers

green osprey Dec 10, 2020, 5:04 PM

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oh

#

ok

#

b and d are congruent

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so two

#

i have a hunch on b

upper karma Dec 10, 2020, 5:05 PM

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we also know that the diagonals are perpendicular

green osprey Dec 10, 2020, 5:06 PM

#

yeah

#

so is it b?

#

its not a c or d

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holup

#

how is b crossed out

#

ac bisecs db?

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wait

#

probably

#

eni meeni mini moe catch a tiger by its toe if it hollers let it go eeni meeni minne moe

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oh lol

upper karma Dec 10, 2020, 5:09 PM

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I mean this one: The diagonals bisect each other.

green osprey Dec 10, 2020, 5:09 PM

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oh ok

#

thats what i thought lol

#

wait

#

are the diagnols perpendicular in rectangles

#

📎 unknown.png

#

no right

upper karma Dec 10, 2020, 5:12 PM

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Remember that a square is a rectangle, so all rectangles except squares do not have perpendicular diagonals.

zenith garnet Dec 10, 2020, 5:22 PM

#

https://cdn.discordapp.com/attachments/326138757474680852/786406243395960832/Screen_Shot_2020-12-09_at_5.36.57_PM.png

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how can i prove this?

silent plank Dec 10, 2020, 5:24 PM

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what's the actual question

#

there is no proper question posted

valid osprey Dec 10, 2020, 5:28 PM

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lmaqoo

silent plank Dec 10, 2020, 5:30 PM

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@zenith garnet

#

👻

valid osprey Dec 10, 2020, 5:37 PM

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LMAO tf is that

#

👻

upper karma Dec 10, 2020, 5:45 PM

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To do what

#

What's the question

upper karma Dec 10, 2020, 6:00 PM

#

num = 1 + e^(ia)

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denominator is quite similar

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@upper karma

upper karma Dec 10, 2020, 6:06 PM

#

upper karma num = 1 + e^(ia)

just do this then multiply by conjugate then back to trig form

jagged magnet Dec 10, 2020, 6:09 PM

#

Yo

#

For number 42

#

📎 image0.jpg

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Would it be

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16 or 24

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Since

#

AY is 8

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Y to z

#

Should be 16 or 24

upper karma Dec 10, 2020, 6:29 PM

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ping me if you respond. Please help me with this.

#

📎 ffaed8cc-7acc-4052-8dde-4912245ddb0a.png

lilac stag Dec 10, 2020, 6:43 PM

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help my friend needs help and idk how to do it

mint verge Dec 10, 2020, 6:49 PM

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can you guys help me with this?

#

📎 20201211_022655.jpg

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i dont know what to do sadcat sadcat sadcat

lofty inlet Dec 10, 2020, 7:37 PM

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hey can someone help me with this geometry word problem?

#

Daniel installed his own 38- foot fladpole. He added a wire with one end attached to the top of the pole and the other end attached to the ground 12 feet from the base of the pole. How long was this wire?

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@here

upper karma Dec 10, 2020, 7:47 PM

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📎 unknown.png

valid osprey Dec 10, 2020, 7:48 PM

#

u could do pythagoras for each side

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or count the squares ig

upper karma Dec 10, 2020, 7:49 PM

#

maybe proving AB is parallel to DC and perpendicular to AD and BC (so quadrilateral becomes a rectangle), then pythagoras to show AB = BC (from a rectangle to square)

valid osprey Dec 10, 2020, 7:50 PM

#

📎 unknown.png

upper karma Dec 10, 2020, 7:50 PM

#

I got y=x-1 for the first but the rest I am confused

📎 image0.jpg

valid osprey Dec 10, 2020, 7:51 PM

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how did u get x-1

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for the first one?

upper karma Dec 10, 2020, 7:51 PM

#

valid osprey

this is not enough, you will end up with a rhombus

valid osprey Dec 10, 2020, 7:51 PM

#

yeah im saying do that for every side

#

ohhhhhhhhhhhhhhhhhhhhhhh

#

ahhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhh

upper karma Dec 10, 2020, 7:52 PM

#

still not enough

valid osprey Dec 10, 2020, 7:52 PM

#

ahhhhhhhhhhhhhhhhhhhhhhhh

upper karma Dec 10, 2020, 7:53 PM

#

I’m very confused about this but it could also be y=x-2. I just need help with these three

valid osprey Dec 10, 2020, 7:53 PM

#

so for the first one

#

if its being enlarged by a scale factor of 1/3

#

y = x - 3

#

enlarged by 1/3

#

what do u think we have to do

umbral snow Dec 10, 2020, 7:55 PM

#

@upper karma
Instead, check every angle is 90°

valid osprey Dec 10, 2020, 7:55 PM

#

😮

#

nva thoughta dax

#

actually

upper karma Dec 10, 2020, 7:56 PM

#

alr

valid osprey Dec 10, 2020, 7:56 PM

#

its says centred at the originx

#

how do we factor that into our calcs if we dont know the original position of the shape

upper karma Dec 10, 2020, 7:56 PM

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Bro can you tell me how to do it. If you can’t it’s fine I’m just confused and need someone to help.

umbral snow Dec 10, 2020, 7:59 PM

#

@upper karma
Or wait, my suggestion is stupid. Every side has the same length, and opposite sides are parallel is easier

valid osprey Dec 10, 2020, 7:59 PM

#

https://cdn.discordapp.com/attachments/326138757474680852/786681251779838003/image0.jpg

#

these questions are quite odd

#

or i might be doing them wrong

#

to englarge them i did multiply them

#

but then

#

📎 unknown.png

upper karma Dec 10, 2020, 8:00 PM

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That’s what I got for the first one mate

valid osprey Dec 10, 2020, 8:00 PM

#

yeah

upper karma Dec 10, 2020, 8:00 PM

#

It’s one question but the rest is what you apply for each graph

valid osprey Dec 10, 2020, 8:00 PM

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wait hold on

valid osprey Dec 10, 2020, 8:01 PM

#

upper karma It’s one question but the rest is what you apply for each graph

wdym?

upper karma Dec 10, 2020, 8:01 PM

#

yeah I got an error on that

#

thanks

#

Like y=x-3 is the equation that is dilated by and is used for questions 1,2,3

valid osprey Dec 10, 2020, 8:03 PM

#

yes

upper karma Dec 10, 2020, 8:03 PM

#

So I’m confused on what to do in 2 and 3 since the equation y=x-3 had multiple coordination

#

Coordinates*

valid osprey Dec 10, 2020, 8:06 PM

#

a coordinate is one point

#

a line has many points

#

they are saying that u need to enlarge the whole line by that scale factor

upper karma Dec 10, 2020, 8:07 PM

#

So question 2. Has a scale factor of 2 and centered at the origin

#

Man anyone? This is due in 15 mins

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It’s okay if you can’t just say it I’ll just do what I can

valid osprey Dec 10, 2020, 8:09 PM

#

just multiply by 2

#

like u did at with number 1

#

but they said the scale factor is 1/3

upper karma Dec 10, 2020, 8:10 PM

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I didn’t multiply for the first I cut it down by 1/3 since it’s dilated

valid osprey Dec 10, 2020, 8:10 PM

#

cut it down

#

dilated basically mean to enlarge

#

the scale factor is 1/3

#

so u multiplied the equation of the line (x - 3) by 1/3

#

so for the second one

#

just multiply it by 2

#

have u guys not studied enlargements

upper karma Dec 10, 2020, 8:13 PM

#

What? So multiply (x-3)*2 and no just got these three pwctice wiestikns today

#

Practice questions*

valid osprey Dec 10, 2020, 8:14 PM

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yes multiply it by 2

upper karma Dec 10, 2020, 8:14 PM

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Got 2x-6..........

valid osprey Dec 10, 2020, 8:14 PM

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yeah

#

is that not the answer?

upper karma Dec 10, 2020, 8:14 PM

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Tf idk you probably know this better than me

valid osprey Dec 10, 2020, 8:15 PM

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yeah 2x-6 is the answer

📎 unknown.png

#

i was just asking bc i thought u also had the answers

#

do u understand why we multiplied by 2

#

its the same as Q1

#

u multiplied by 1/3

#

bc that was the scale factor

#

does that make sense?

upper karma Dec 10, 2020, 8:17 PM

#

Yeah scale factor is dilated so for 3 it would be the centered coordinate and scale factor also multiplied by 2?

#

But (-1,-2) is the center now but it would still be the same the same again?

#

Due in 5 mins now. I’ll try dis Man. Thanks for trying to help me

valid osprey Dec 10, 2020, 8:21 PM

#

the centre of the shape changed

#

or the line

upper karma Dec 10, 2020, 8:22 PM

#

Yeah to (1,-2) for question 3

valid osprey Dec 10, 2020, 8:22 PM

#

yeah

upper karma Dec 10, 2020, 8:22 PM

#

So the same step?

valid osprey Dec 10, 2020, 8:22 PM

#

yeah

#

if they havent toild u to draw the graph, then the centre does not matter much

upper karma Dec 10, 2020, 8:22 PM

#

Which is literally the same equation.

valid osprey Dec 10, 2020, 8:22 PM

#

yeah

upper karma Dec 10, 2020, 8:23 PM

#

It’s y=2x-2 again?

valid osprey Dec 10, 2020, 8:23 PM

#

they are throwing extra info at u to confuse u

#

nope

#

y = 2(x - 3)

#

cant br y = 2x - 2

upper karma Dec 10, 2020, 8:24 PM

#

Alright I’ll just ask my teacher about this tomorrow. Like we didn’t even start of by learning just practicing

valid osprey Dec 10, 2020, 8:24 PM

#

aight

upper karma Dec 10, 2020, 8:24 PM

#

But thanks mate

valid osprey Dec 10, 2020, 8:24 PM

#

yw

upper karma Dec 10, 2020, 8:27 PM

#

Alright it’s correct. But how you get y=2(x-3) when you said it’s the same equation if the center is Changed?

valid osprey Dec 10, 2020, 8:29 PM

#

lemme send a vid in a bit

upper karma Dec 10, 2020, 8:30 PM

#

Vid? Ok

#

📎 unknown.png

valid osprey Dec 10, 2020, 8:34 PM

#

srry channelk takenb

upper karma Dec 10, 2020, 8:34 PM

#

What video you sending?

umbral snow Dec 10, 2020, 8:35 PM

#

Same as before @upper karma
Make sure the sides are equal length, and opposite sides are parallel

valid osprey Dec 10, 2020, 8:40 PM

#

nvm about the video

#

but u dont need to care about the origin

#

if it says enlarge

#

and they've given u an equation

#

ur probably gonna study enlargements soon

#

and it will all make sense

upper karma Dec 10, 2020, 8:45 PM

#

📎 unknown.png

main meadow Dec 10, 2020, 8:51 PM

#

Hi

#

<@&286206848099549185>

oak citrus Dec 10, 2020, 9:14 PM

#

what is the formula for area of circle?

next jackal Dec 10, 2020, 9:15 PM

#

@oak citrus literally same thing asked in #prealg-and-algebra

oak citrus Dec 10, 2020, 9:15 PM

#

ah

#

great minds think alike

next jackal Dec 10, 2020, 9:15 PM

#

clown to clown

main meadow Dec 10, 2020, 9:19 PM

#

📎 image0.jpg

glacial dawn Dec 10, 2020, 9:19 PM

#

use pythagoras and solve

main meadow Dec 10, 2020, 9:20 PM

#

Yes

#

📎 image0.jpg

oak citrus Dec 10, 2020, 9:20 PM

#

pythagoream theorem is a^2+b^2 = c^2

#

so basically

main meadow Dec 10, 2020, 9:21 PM

#

Opps forgot to add the ^2

oak citrus Dec 10, 2020, 9:21 PM

#

the bigger issue is

#

that it should be

next jackal Dec 10, 2020, 9:21 PM

#

@main meadow can you point out what the hypotenuse of that triangle is?

main meadow Dec 10, 2020, 9:22 PM

#

Longest sode

oak citrus Dec 10, 2020, 9:22 PM

#

what is the longest side in this case?

main meadow Dec 10, 2020, 9:22 PM

#

5a

oak citrus Dec 10, 2020, 9:23 PM

#

and if c in this equation is the hypotenuse, would you agree that whatever a and b are they equals a^2+b^2=5a^2

main meadow Dec 10, 2020, 9:23 PM

#

Teah

oak citrus Dec 10, 2020, 9:24 PM

#

ok

#

and what are the a & b values in this case?

main meadow Dec 10, 2020, 9:24 PM

#

3a for a abd 12 for b

oak citrus Dec 10, 2020, 9:25 PM

#

ok so with this knowledge can you setup the equation again?

main meadow Dec 10, 2020, 9:25 PM

#

Yeah

oak citrus Dec 10, 2020, 9:25 PM

#

ok do that and send

next jackal Dec 10, 2020, 9:27 PM

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@oak citrus is a man of patience, commitment and s h e e r f o c k i n g w i l l

main meadow Dec 10, 2020, 9:27 PM

#

Oh is 9

oak citrus Dec 10, 2020, 9:27 PM

#

?

main meadow Dec 10, 2020, 9:27 PM

#

A=9

oak citrus Dec 10, 2020, 9:27 PM

#

did you finish problem

main meadow Dec 10, 2020, 9:27 PM

#

Yes

oak citrus Dec 10, 2020, 9:27 PM

#

i havent done the problem but send work

main meadow Dec 10, 2020, 9:28 PM

#

6Rad2

next jackal Dec 10, 2020, 9:28 PM

#

No it's wrong

main meadow Dec 10, 2020, 9:28 PM

#

6|—
|2

#

Oh

oak citrus Dec 10, 2020, 9:29 PM

#

send pic of your work

next jackal Dec 10, 2020, 9:29 PM

#

what's rad doing in this?

main meadow Dec 10, 2020, 9:30 PM

#

Mb

humble pulsar Dec 10, 2020, 9:30 PM

#

main meadow 6|— |2

pandaThink

main meadow Dec 10, 2020, 9:30 PM

#

Its

#

3

#

Since rad9 is 3

#

So 3

humble pulsar Dec 10, 2020, 9:30 PM

#

yes

main meadow Dec 10, 2020, 9:30 PM

#

Oops i forgot to rad

oak citrus Dec 10, 2020, 9:31 PM

#

rad as in sqrt?

main meadow Dec 10, 2020, 9:32 PM

#

Yeah

#

Rad 9 is 3

next jackal Dec 10, 2020, 9:32 PM

#

I'd suggest you call it square root instead of radical

oak citrus Dec 10, 2020, 9:33 PM

#

yeah

#

agreed

#

because later on in math rad stands for radians

late breach Dec 10, 2020, 9:34 PM

#

📎 unknown.png

#

📎 8Dl2miKx1mJp0AAAAASUVORK5CYII.png

#

how would I know when to add the 180

humble pulsar Dec 10, 2020, 9:35 PM

#

depends on what quadrant you need

#

tanx < 0 will always give an angle in quad 4

#

if the angle is in quad 2, you add pi / 180

late breach Dec 10, 2020, 9:36 PM

#

ok thank you

upper karma Dec 10, 2020, 9:41 PM

#

pick a postulate and then apply it

zenith garnet Dec 10, 2020, 9:41 PM

#

https://cdn.discordapp.com/attachments/326138757474680852/786406243395960832/Screen_Shot_2020-12-09_at_5.36.57_PM.png

#

how can i prove if this is true or false

upper karma Dec 10, 2020, 9:42 PM

#

see if you can use one of the triangle theorems

#

SAS, AA

📎 congruence-theorem.png

zenith garnet Dec 10, 2020, 9:44 PM

#

well i only know the congruence of one angle

#

and one side

#

so i cant prove anything

upper karma Dec 10, 2020, 9:48 PM

#

@zenith garnet you have to prove one of the other sides or angles is congruent first

zenith garnet Dec 10, 2020, 9:54 PM

#

ya thats why im confused about

#

i dont know how to do that

main meadow Dec 10, 2020, 10:19 PM

#

📎 image0.jpg

tender prawn Dec 10, 2020, 10:23 PM

#

📎 unknown.png

#

ok im pretty sure ik how to do this

tender prawn Dec 10, 2020, 10:23 PM

#

main meadow

A = 1/2 bh

#

like sin^3 A = 8R^3 by extended law of sines

#

so i did that, top and bottom cancelled out, 8R^3=7

main meadow Dec 10, 2020, 10:24 PM

#

Yes

tender prawn Dec 10, 2020, 10:24 PM

#

is that correct?

main meadow Dec 10, 2020, 10:24 PM

#

But no

#

The answer choices r there

tender prawn Dec 10, 2020, 10:24 PM

#

whats the base whats teh height

main meadow Dec 10, 2020, 10:25 PM

#

Idk

#

I got this from someone

tender prawn Dec 10, 2020, 10:25 PM

#

...

#

figure it out from diagram

main meadow Dec 10, 2020, 10:25 PM

#

Idk how to do it so i come out here to ask

tender prawn Dec 10, 2020, 10:28 PM

#

well

#

how would you find the base

alpine niche Dec 10, 2020, 10:32 PM

#

Hi does anyone know how to solve this? I can't even start it :/

📎 Screenshot_3.png

main meadow Dec 10, 2020, 10:41 PM

#

@tender prawn

📎 image0.jpg

tender prawn Dec 10, 2020, 10:42 PM

#

extend AB and draw a line from C straight down to hit line ab

upper karma Dec 10, 2020, 10:56 PM

#

or u could use heron's formula

#

Or do you have to do it a certain way

humble pulsar Dec 10, 2020, 10:57 PM

#

why would you use heron's formula when you know the base and height...

upper karma Dec 10, 2020, 10:58 PM

#

I did not look at the picture lmao I just looked at find area

#

If you know base and height then you're good

tender prawn Dec 10, 2020, 11:17 PM

#

📎 unknown.png

#

teacher explained in class but i wasnt paying attention :/

#

pretty sure its something to do w half angle formula

#

and maybe herons formula

#

📎 PXL_20201210_231821269.jpg

#

kinda looks like law of cosines

#

hmm

#

i like multiplied both sides by s(s-a) and did herons formula and then used a=1/2bc*sinA to get

#

sinA = s(s-a)(1-cosA)

#

probably wrong direction tbh

hasty bone Dec 10, 2020, 11:53 PM

#

hey can anyone help me

upper karma Dec 11, 2020, 12:15 AM

#

can someone explain this to me rq?

📎 unknown.png

silk patio Dec 11, 2020, 12:27 AM

#

Similar triangles

upper karma Dec 11, 2020, 12:34 AM

#

x= similar triangles?

tender prawn Dec 11, 2020, 12:37 AM

#

the top triangle is similar to the whole triangle

#

and then use side lengths of similar triangles

#

ok my teacher explained like part of this

📎 unknown.png

#

i proved the second part using area of triangle = sr

#

and i think im supposed to somehow relate it to the first but idk how :/

#

kinda avoiding the half angle formula but it might be that

#

oh im dumb i turned cot into cos/sin instead of 1/tan and using tan half angle formula

tender prawn Dec 11, 2020, 1:03 AM

#

ahh i finally got it lol

#

i was supposed to use the sum/difference of cot and tan

#

man trig is hard

upper karma Dec 11, 2020, 1:05 AM

#

📎 unknown.png

#

help

#

I know like 10 different ways to do this

#

but I don't know how to take up every slot

#

my teacher when she teaches it usually uses every slot

#

never has one wasted

#

but all the ways I solved it

#

didn't use them all

silent plank Dec 11, 2020, 1:08 AM

#

show what you're doing

upper karma Dec 11, 2020, 1:10 AM

#

ok

#

wait

#

I deleted it let me retype it

silent plank Dec 11, 2020, 1:10 AM

#

wait, statement 2 doesn't even make sense

upper karma Dec 11, 2020, 1:11 AM

#

📎 unknown.png

#

that's what I mean

#

@silent plank

silent plank Dec 11, 2020, 1:12 AM

#

statement 2 doesn't make sense

upper karma Dec 11, 2020, 1:12 AM

#

how

#

the traversal

#

makes it true no matter what

#

wait

#

that's only if it's parallel

#

👀

silent plank Dec 11, 2020, 1:12 AM

#

you can't assume that lines c and d are parallel at that stage

upper karma Dec 11, 2020, 1:12 AM

#

yea

#

I just realized

silent plank Dec 11, 2020, 1:13 AM

#

that statement is something you could aim to reach

upper karma Dec 11, 2020, 1:13 AM

#

this guy told me that's how I should start it

silent plank Dec 11, 2020, 1:13 AM

#

and then use the converse to justify that the lines are parallel

upper karma Dec 11, 2020, 1:13 AM

#

so how do I start it?

#

angle 7 congruent to angle 3

#

?

#

angle 7 congruent to angle 1

#

vertical

silent plank Dec 11, 2020, 1:14 AM

#

there are multiply routes you can take

#

do some angle chasing and apply a converse related to parallel lines

upper karma Dec 11, 2020, 1:15 AM

#

okay

late breach Dec 11, 2020, 2:11 AM

#

📎 unknown.png

#

Can someone explain how I would know to divide these degrees by 2?

silent plank Dec 11, 2020, 2:17 AM

#

DeMoirvre's

limpid gust Dec 11, 2020, 2:41 AM

#

can someone tell me what equation I would need to solve?

📎 unknown.png

west basin Dec 11, 2020, 3:52 AM

#

well you have (6x-7) do you know what angles on a line add up to

limpid gust Dec 11, 2020, 3:55 AM

#

I solved that

#

i was being dumb

untold crow Dec 11, 2020, 3:55 AM

#

i need help. i have 9-13 questions on a study guide. my test from this study guide is tomorrow. please someone help.

limpid gust Dec 11, 2020, 3:55 AM

#

But i do need help on this

📎 aaaaaaaa.PNG

#

because of x and 6

#

y*

prime drum Dec 11, 2020, 4:37 AM

#

yo ill pay someone if they help me with a couple problems

#

dm me!

west basin Dec 11, 2020, 4:38 AM

#

its against the rules to pay for help

prime drum Dec 11, 2020, 4:38 AM

#

oh nvm then

west basin Dec 11, 2020, 4:38 AM

#

just post your problems and someone will help you

prime drum Dec 11, 2020, 4:40 AM

#

📎 unknown.png

#

could someone help me with this please!

west basin Dec 11, 2020, 4:41 AM

#

sure can

#

break $sin 2\theta$ down into $2cos \theta sin \theta$

#

will that help you at all?

somber coyoteBOT Dec 11, 2020, 4:42 AM

#

Star_

📎 251264406493593601.png

prime drum Dec 11, 2020, 4:43 AM

#

nah

#

i need answers g

west basin Dec 11, 2020, 4:43 AM

#

we dont give answers lol

#

just use symbolab or something if you want that

zenith garnet Dec 11, 2020, 5:18 AM

#

https://cdn.discordapp.com/attachments/326138757474680852/786406243395960832/Screen_Shot_2020-12-09_at_5.36.57_PM.png

#

is it possible to prove this is congruent with the info given

#

im not sure how to decide if its true or false

tepid finch Dec 11, 2020, 5:38 AM

#

if its congruent every side must be equal

#

can you think of a situation where AC/BC don't necessarily equal EG/GF

slate blade Dec 11, 2020, 5:51 AM

#

Congruence needs one of the following requirements:

SSS (Side, Side, Side)
Basically if you know all 3 sides are equal in magnitude, they are congruent
-SAS (Side, Angle, Side)
If two pairs of sides are equal in length, and the included angles are equal, then the triangles are congruent, But this one needs the sides to sandwich the angle
-ASA (Angle, Side, Angle) There's another variation of this called AAS
Basically your two given pairs of angles are the same, and the sides are the same
-RHS (Right angle, Hypotenuse, Side)
For right angle triangles only

#

In your case @zenith garnet you only have 2 pieces of information in your triangles, therefore you cannot reach that conclusion that they are congruent unless I am stoopid

#

SSA is another variation (but sometimes you cannot prove congruence with it because of the ambiguous case)

#

and AAA is the only one that you legit cannot use, because that identity only demonstrates similarity, not congruence

#

hope this helps

near tendon Dec 11, 2020, 7:20 AM

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📎 Trig_Review.png

#

Can someone give me the steps in order to prove this trig identity? Not the greatest at Trig functions & identities

#

Please and thank you👍

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sin(2x)/1-cos(2x)= 2/sin(2x)sec^2(x)

earnest echo Dec 11, 2020, 7:23 AM

#

Start from RHS
And use half angle identities on both numerator and denominator

#

Once you simplify it a bit
Use double angle to get your desired result

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Not RHS, use LHS

near tendon Dec 11, 2020, 7:24 AM

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Start off with the Left Side instead?

earnest echo Dec 11, 2020, 7:25 AM

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Yeah

near tendon Dec 11, 2020, 7:31 AM

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errrr

slate blade Dec 11, 2020, 7:31 AM

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u get anywhere?

near tendon Dec 11, 2020, 7:31 AM

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Nah not really

slate blade Dec 11, 2020, 7:32 AM

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would u like a step through?

near tendon Dec 11, 2020, 7:32 AM

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yes please

slate blade Dec 11, 2020, 7:32 AM

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aight give me a moment let me actually solve it myself

near tendon Dec 11, 2020, 7:32 AM

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Okay thank you

#

I've only been able to change sin(2x) into 2sin(x)cos(x) -- Double Angle

earnest echo Dec 11, 2020, 7:33 AM

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Do the same for 1-cos(2x)

near tendon Dec 11, 2020, 7:33 AM

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Okay

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so 1-2sin^2(x)

earnest echo Dec 11, 2020, 7:34 AM

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That's wrong

slate blade Dec 11, 2020, 7:34 AM

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remember there are 3 options for cos(2x)

near tendon Dec 11, 2020, 7:35 AM

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Okay yeah thats true

earnest echo Dec 11, 2020, 7:36 AM

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1- cos(2x)= 2 sin²(x)

near tendon Dec 11, 2020, 7:36 AM

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Ok got it

#

thank you

slate blade Dec 11, 2020, 7:37 AM

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epic good job

winged vine Dec 11, 2020, 12:21 PM

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hey

limpid phoenix Dec 11, 2020, 2:21 PM

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um can someone help me with this?

📎 unknown.png

raven heart Dec 11, 2020, 2:41 PM

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https://cdn.discordapp.com/attachments/746690106877804565/786961214227218442/unknown.png

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hey can1 help me with this

pure cape Dec 11, 2020, 2:45 PM

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@raven heart can you find the obtuse angle inside?

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and you should use the property that all angles in a triangle adds up to 180 deg

raven heart Dec 11, 2020, 2:47 PM

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well how??

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can u show me

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@pure cape

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hey any1....i need immediate help

pure cape Dec 11, 2020, 2:49 PM

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lets start with an example first

📎 unknown.png

#

given angle ABC

silent plank Dec 11, 2020, 2:50 PM

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need immediate help

pure cape Dec 11, 2020, 2:50 PM

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can you find the reflex angle

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just give me the answer to the reflex angle

raven heart Dec 11, 2020, 2:51 PM

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yeah...its 310

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but i dont know any angle inside

pure cape Dec 11, 2020, 2:51 PM

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or how you would go about finding it

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yep

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so can you do that in reverse for your exercise

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you just have to find all of the angles in your triangle

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and add them up

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you also know that by adding up all 3 angles, it will give you 180

hybrid solstice Dec 11, 2020, 2:52 PM

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📎 Screenshot_1.png

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can someone help me with that

pure cape Dec 11, 2020, 2:55 PM

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which one do you think it is?

hybrid solstice Dec 11, 2020, 2:55 PM

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i think its the second

pure cape Dec 11, 2020, 2:56 PM

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and why is that?

hybrid solstice Dec 11, 2020, 2:56 PM

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only reason why i think that is B and F will the right angles

pure cape Dec 11, 2020, 2:57 PM

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well you're almost right

#

if the statement is correct, it means that angle C and angle E are equal, and the same for B and F, A and D

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which is true from what we see here

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if you say its correct because B and F are equal then its wrong, because there isnt enough evidence

hybrid solstice Dec 11, 2020, 2:58 PM

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oh ok

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ohhh

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so then

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the third one?

pure cape Dec 11, 2020, 3:00 PM

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no, the second is right

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im just saying that your reasoning is wrong

hybrid solstice Dec 11, 2020, 3:02 PM

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ohh ok

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📎 Screenshot_2.png

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this was pretty hard too

pure cape Dec 11, 2020, 3:04 PM

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remember the rules of congruence

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what rule is the first one

hybrid solstice Dec 11, 2020, 3:05 PM

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SSS

pure cape Dec 11, 2020, 3:05 PM

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are you sure?

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because as i see it, the first one only talks about a pair of sides

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and two pairs of angles

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rather than 3 pairs of sides

hybrid solstice Dec 11, 2020, 3:06 PM

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aas?

pure cape Dec 11, 2020, 3:06 PM

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close

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asa

hybrid solstice Dec 11, 2020, 3:06 PM

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oh

pure cape Dec 11, 2020, 3:07 PM

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what about the second one

hybrid solstice Dec 11, 2020, 3:07 PM

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i ahve to prive wihich is wrong

pure cape Dec 11, 2020, 3:07 PM

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yes

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so lets find which one is correct first

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and then we shall know which one is wrong

hybrid solstice Dec 11, 2020, 3:08 PM

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ok

pure cape Dec 11, 2020, 3:08 PM

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i see 2 pairs of sides, and a pair of angles

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is that sas?

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pay close attention to the positioning

hybrid solstice Dec 11, 2020, 3:09 PM

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that would have to be sas

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aas wouldnt work

pure cape Dec 11, 2020, 3:10 PM

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but is it really sas

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i dont know.....i mean the angle isnt in the middle of the two sides

hybrid solstice Dec 11, 2020, 3:11 PM

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youre talking about the first one correct?

pure cape Dec 11, 2020, 3:12 PM

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nah

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im talking about the second one

hybrid solstice Dec 11, 2020, 3:13 PM

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the angle is between AC and BC

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well angle C is

pure cape Dec 11, 2020, 3:13 PM

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yes

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so for the second one

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to prove that the triangles are congruent,

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we have to use angle C

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so that means the second one is wrong

hybrid solstice Dec 11, 2020, 3:14 PM

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ohh ok

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bec we would need more info correct

pure cape Dec 11, 2020, 3:14 PM

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yeah

hybrid solstice Dec 11, 2020, 3:14 PM

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and that info is C

pure cape Dec 11, 2020, 3:14 PM

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or AB

hybrid solstice Dec 11, 2020, 3:14 PM

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oh ok

#

thank you

slim saddle Dec 11, 2020, 3:18 PM

#

📎 unknown.png

#

Any idea of how to solve this?

#

please ping me

#

also I was struggling on this question

📎 unknown.png

humble pulsar Dec 11, 2020, 3:22 PM

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@slim saddle if DEF ~ JKL, then m<D = m<J

slim saddle Dec 11, 2020, 3:22 PM

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ok

#

so 7x-12+9x-20+52=180?

humble pulsar Dec 11, 2020, 3:23 PM

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yes

slim saddle Dec 11, 2020, 3:23 PM

#

thanks!

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any clue of how to find the second one?

humble pulsar Dec 11, 2020, 3:24 PM

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which one has 2 sides and 1 angle?

slim saddle Dec 11, 2020, 3:25 PM

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2nd one?

humble pulsar Dec 11, 2020, 3:26 PM

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yes

slim saddle Dec 11, 2020, 3:26 PM

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thanks

#

📎 unknown.png

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it isn't the 2nd one

upper karma Dec 11, 2020, 4:26 PM

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(tan27 x tan53)/sin30

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How to solve this ^^

silent plank Dec 11, 2020, 4:29 PM

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apply properties of the tan function

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as well as trig functions evaluated at special angles

green osprey Dec 11, 2020, 4:38 PM

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wait

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how am i one minute earlier

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than you

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wait fk im just sht at math

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29m is less than 38m

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anyways

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do squares have legs like trapazoids

silent plank Dec 11, 2020, 4:40 PM

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wdym by like trapazoids?

green osprey Dec 11, 2020, 4:43 PM

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never mind

silent plank Dec 11, 2020, 4:44 PM

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squares are special trapezoids

green osprey Dec 11, 2020, 4:50 PM

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oh

thorny maple Dec 11, 2020, 4:55 PM

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is this right?

📎 ytu.png

silent plank Dec 11, 2020, 4:58 PM

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yes

thorny maple Dec 11, 2020, 5:00 PM

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how owuld you do this?

📎 xqfv.png

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4:5?

solemn axle Dec 11, 2020, 8:18 PM

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That’s what I got

sleek dove Dec 11, 2020, 8:54 PM

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📎 20201211_155426.jpg

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I need help

west basin Dec 11, 2020, 9:38 PM

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its a 45-45-90

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that means the hypotenuse will be the product of leg*sqrt(2)

arctic cobalt Dec 11, 2020, 9:44 PM

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Your given the length of one of the legs which is 9 the and both of the legs are the same length the hypotenuse which is opposite to the right angle sign is equal to 9x2

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How would I solve this using law of cosines

📎 image0.jpg

umbral snow Dec 11, 2020, 9:47 PM

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Do you know the statement of the law of cosines? Have you gotten any progress in it?

arctic cobalt Dec 11, 2020, 9:47 PM

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You mean the formula

unreal vine Dec 11, 2020, 9:48 PM

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how do i find a diff restraint?

umbral snow Dec 11, 2020, 9:48 PM

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The formula, and what everything in it means

arctic cobalt Dec 11, 2020, 9:48 PM

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Yeah I get it

#

But I got 35.95 for c^2 which I’m pretty sure is wrong

umbral snow Dec 11, 2020, 9:49 PM

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x² = 13² + 24² - 2(13)(24)cos(87°)

somber coyoteBOT Dec 11, 2020, 9:50 PM

#

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

arctic cobalt Dec 11, 2020, 9:50 PM

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Is that what c is equal to?

umbral snow Dec 11, 2020, 9:50 PM

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What's c?

#

I see an x on your page

arctic cobalt Dec 11, 2020, 9:51 PM

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Yeah I mean x

umbral snow Dec 11, 2020, 9:51 PM

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That's what x² is equal to anyway

arctic cobalt Dec 11, 2020, 9:51 PM

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What did you do to get that

umbral snow Dec 11, 2020, 9:51 PM

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x² = 13² + 24² - 2(13)(24)cos(87°)

arctic cobalt Dec 11, 2020, 9:52 PM

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Cause I did 169 plus 576 equals 745

umbral snow Dec 11, 2020, 9:52 PM

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Which should be the law of cosines, applied to that triangle. Let me know of course if I made any mistake haha

arctic cobalt Dec 11, 2020, 9:53 PM

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The second part is confusing me what do I do with the cos 87

umbral snow Dec 11, 2020, 9:53 PM

#

,w cos(87°)

somber coyoteBOT Dec 11, 2020, 9:53 PM

#

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

arctic cobalt Dec 11, 2020, 9:54 PM

#

Did you distribute -2 by 14 and 24

umbral snow Dec 11, 2020, 9:54 PM

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cos(87) is just a number, approximately 0.05234...

arctic cobalt Dec 11, 2020, 9:54 PM

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13 not 14

umbral snow Dec 11, 2020, 9:54 PM

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Everything is being multiplied, there's nothing to distribute

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So you have the right idea, do every term separately then add them all up in the end

arctic cobalt Dec 11, 2020, 9:55 PM

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So what do I do with the negative 2 the 13 and the 34 left over

umbral snow Dec 11, 2020, 9:56 PM

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The last term is just
2(13)(24)(0.0523359...)

arctic cobalt Dec 11, 2020, 9:56 PM

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So -26 times 24 time 0.05

umbral snow Dec 11, 2020, 9:56 PM

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Approximately

arctic cobalt Dec 11, 2020, 9:57 PM

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I got it now thank you

humble pulsar Dec 11, 2020, 10:19 PM

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@molten bronze cant help w/o the question

humble pulsar Dec 11, 2020, 10:35 PM

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Can't help w/o the question

glacial dawn Dec 11, 2020, 10:37 PM

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Well the first is a given right?

upper karma Dec 11, 2020, 10:53 PM

#

📎 unknown.png

molten bronze Dec 11, 2020, 11:33 PM

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I need help pls help ;-; #geometry-and-trigonometry

west basin Dec 11, 2020, 11:34 PM

#

post your question

molten bronze Dec 11, 2020, 11:36 PM

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Ohh thank you so much

#

📎 image0.jpg

#

What are the blanks @west basin

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given 2) bd=bd 3) ???

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Sas or hl

#

Hello:? #geometry-and-trigonometry

west basin Dec 11, 2020, 11:40 PM

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should be sas

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since they share an angle between two shared sides

molten bronze Dec 11, 2020, 11:40 PM

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Yea I just realized

#

The angle doesn’t show 90 degrees to

#

Can I ask one more ?

#

What are the blank for this one

📎 image0.jpg

#

pa =ya 3) segment bisector or reflective property?

#

Idk which

west basin Dec 11, 2020, 11:43 PM

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reflexive

#

its better to use that than bisector

molten bronze Dec 11, 2020, 11:44 PM

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It’s a multiple choice and they have both tbh

west basin Dec 11, 2020, 11:44 PM

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well youd also need to prove its a bisector if you were doing that

molten bronze Dec 11, 2020, 11:45 PM

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Ohhh I guess midpoint isn’t bisecting py

#

It’s a point

#

Just a point I presume

#

So then it has to be reflexive property

#

What would 4 be in that case? Sss still right

west basin Dec 11, 2020, 11:45 PM

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actually you could use bisector i think

#

because it gives you the midpoint

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i didnt read that

molten bronze Dec 11, 2020, 11:46 PM

#

Ahhh so confused

#

Uhh

#

I think it’s reflexive still

#

Cause I feel like with midpoint it can’t bisect

west basin Dec 11, 2020, 11:46 PM

#

yeah because they both share LA

#

just go with reflexive

molten bronze Dec 11, 2020, 11:47 PM

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Okay, I have one more

#

This is my last concern

#

📎 image0.jpg

#

What are the blanks for this one :?

#

Just wanna make sure I did it right

west basin Dec 11, 2020, 11:48 PM

#

what did you put?

molten bronze Dec 11, 2020, 11:48 PM

#

definition of midpoint

#

Statement 3) angle aix = angle oim

#

Reason 3 vertical angles

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Sas

west basin Dec 11, 2020, 11:49 PM

#

looks good to me

molten bronze Dec 11, 2020, 11:50 PM

#

Thanks 🙂

upper karma Dec 12, 2020, 12:54 AM

#

is this correct

📎 unknown.png

upper karma Dec 12, 2020, 3:06 AM

#

📎 unknown.png

#

help

#

#geometry-and-trigonometry

upper karma Dec 12, 2020, 3:43 AM

#

bruh

tender prawn Dec 12, 2020, 5:42 AM

#

just use a bunch of supp and corresponding angles

steep dawn Dec 12, 2020, 9:47 AM

#

what's a linear pair

#

for 2 if you're using that as proof you need a few more lines

#

@upper karma

upper karma Dec 13, 2020, 12:34 AM

#

uh

upper karma Dec 13, 2020, 3:06 AM

#

📎 2922d3360558b394538a7bae6378199f.png

plain wyvern Dec 13, 2020, 4:00 AM

#

well read this https://brilliant.org/wiki/polynomial-division/#:~:text=Division with polynomials (done with,a factor of the dividend).

Polynomial Division | Brilliant Math & Science Wiki

Division with polynomials (done with either long division or synthetic division) is analogous to long division in arithmetic: we take a dividend divided by a divisor to get a quotient and a remainder (which will be zero if the divisor is a factor of the dividend). More formally, given a dividend ...

#

@upper karma

#

also this is the wrong channel for this question

elder creek Dec 13, 2020, 4:48 AM

#

📎 Screenshot_2020-12-10_153109.png

#

i need help lol

polar summit Dec 13, 2020, 6:02 AM

#

put problems 1 by 1

placid bone Dec 13, 2020, 10:24 AM

#

lmao theres no question there????

upper karma Dec 13, 2020, 10:56 AM

#

if everytime you try to make a circle with a compass it makes a spiral is that user error or a bad compass?

earnest echo Dec 13, 2020, 10:58 AM

#

Probably user error

#

Or the screw could be lose