So you can definitely susitute that into your equation
#geometry-and-trigonometry
low scaffold
Yea, I subbed into the powered x
Instead of keeping the gradient the same and x separate
low scaffold
So c= e^4a -4ae^4a?
pure cape
You did it again.....
Wheres the a in the coefficient?
e^(4a) = 4ae^(4a) - c
How could that turn into - 3e^(4a)
low scaffold
ok, so I got a as 1/4 now
low scaffold
I mean for part b
dense marten
hey can i get some help with CPCTC and triangles ? its a worksheet ive been having trouble on for awhile
pure cape
try solving for c
low scaffold
I got e^4a - 4ae^4a = c
low scaffold
Ok so the equation is y= (4e^4a) x + (e^4a - 4ae^4a)
pure cape
Yep
low scaffold
Aye
pure cape
Its pretty easy for part b now that yoy got the equation
pure cape
Wait what? Whats part b about
low scaffold
It asks for a when the tangent passes through the origin
low scaffold
Am I right to sub x,y for 0,0 and solve for a?
pure cape
Yep
astral bluff
Ayo I'm not tryna bother yall but does anyone know the answer to this
placid bone
can you prove that's the case?
astral bluff
Assignment
spring jolt
YOOO
astral bluff
Lol kk
placid bone
not sure what to do if it's a dubious case
slate blade
F bro
green tree
@west basin yes
west basin
basically just draw bisectors of S R and T
and whereever they all meet is the incenter
west basin
its not showing any picture
west basin
thats roughly it yeah
ashen brook
Let sin A = − 8/17 with 270° ≤ A ≤ 360° and cos B = − 3/5 with 90° ≤ B ≤ 180° and find the following. sin(A+B)
how would i answer this
glacial dawn
upper karma
somber coyoteBOT
Doodaide
slate blade
given that $$f(x) = a\sin{(bx-c)}+d $$
somber coyoteBOT
Doodaide
ashen brook
tan 𝜃 − 2 cos 𝜃 tan 𝜃 = 0 for this problem i got 60,180,300 but it says it is still wrong even tho it checks out
did i do something wrong
silent plank
show work (also what interval did they ask you to solve for)
clever zodiac
can anyone help me w my problem lol
ashen brook
show work (also what interval did they ask you to solve for)
this was the question: Find all solutions in the interval 0° ≤ 𝜃 < 360°. If rounding is necessary, round to the nearest tenth of a degree.
silent plank
you missed 0
ashen brook
ahh ok that makes sense thank you man
upper karma
Hey hey hey
I need help urgent yelp
I'm sitting in tye class right now
And I need this to be solved pls help me
Pls solve this
Plssssss
ashen brook
8 cis 3𝜋/4 how would i right this in standard form
versed river
by definition, 8cis(3pi/4)=8(cos(3pi/4)+isin(3pi/4))
versed river
idk wym by that
ashen brook
i put in that answer before but it says it was wrong
versed river
you put 8(cos(3pi/4)+isin(3pi/4))?
ashen brook
yeah
versed river
well you've still got a step to do after that lol
you have to find the exact values of cos(3pi/4) and sin(3pi/4)
rather than just writing it in terms of sin and cos
ashen brook
ohh ok that makes more sense thank you
earnest echo
Have you tried something?
halcyon cipher
Can some help me with this or give me a formula to solve it
solemn axle
Personally, and I might be doing this weird, I would use tangent to find the angle across from x and then use tangent again with the bigger side to find x
Wait
I’m stupid
The easy way is to find the ratio from 16.8/6.4 and then multiply it by 2 to get x
@halcyon cipher
halcyon cipher
Personally, and I might be doing this weird, I would use tangent to find the ang...
Thank you but I asked my teacher and she said I didn’t have to do it
chrome kelp
Just use triangle congruence and it becomes ez
humble pulsar
@uncut rock draw a triangle with angle B and sides sqrt6 amd 5
chrome kelp
tan alfa = sin alfa / cos alfa
humble pulsar
tan alfa = sin alfa / cos alfa
you'd still need to find cos in that idea
uncut rock
I don’t understand
humble pulsar
what's tan a ratio of?
humble pulsar
Opposite/Adjacent in a triangle
wasnt asking you
versed inlet
O_O was trying to help him he seems confused lol
uncut rock
Thank you I am 😂
humble pulsar
Thank you I am 😂
Draw a right triangle where opposite side is sqrt6 and adjacent is 5
humble pulsar
solve for x?
placid bone
4+(x-2)^2=x^2
placid bone
what is the definition of bisection?
placid bone
what dos it mean if the line ab bisects cad
ivory fractal
its the vertex
placid bone
what does it mean about the angles cab and bad
ivory fractal
i have no idea
ivory fractal
I think it means that Im an idiot and didnt pay attention in class
placid bone
no
divide (a line, angle, or shape) into two exactly equal parts.
this is the google definition
so what would that mean for 4x+1 and 33?
ivory fractal
you want me to divide 33 and (4x+1)?
ivory fractal
okay..
ivory fractal
8.5
placid bone
how...
pastel gulch
Quick brain check, if you have supplementary angles, if one is larger than the other, the larger one must be obtuse right?
upper karma
Quick brain check, if you have supplementary angles, if one is larger than the o...
yes
pastel gulch
Alright thanks. Writing a somewhat long proof based on that lemma, and wanted to just make sure I wasn't messing up a really basic thing lol
upper karma
how do I solve this?
this is what I did but it's wrong, can anyone guide me in the right direction?
night basin
how do u find vector with same direction but dif magnitude
like
direction of [5 12] (magnitude 13) but magnitude 26 ???
humble pulsar
@night basin [5c,12c], find c such that |[5c,12c]| = 26
placid bone
find unit vector then multiply by 26
main lintel
@upper karma seems to me that you have to find the closest point on the ladder to the base of the wall
upper karma
upper karma
90
west basin
thats not true
upper karma
there a square
west basin
the square denotes its a 90 degree angle
yes
but the sum of all the angles within the triangle is 180
so add all three angles set it equal to 180 and solve
west basin
thats wrong
fresh topaz
i did 2x -2 + x + 5 = 180
silent plank
the 90° right angle is an angle within that right angled triangle
west basin
yes you forgot to include the 90
west basin
the square you were speaking of is 90 degrees
silent plank
there are 3 angles within a triangle.
2 of them are 2x-2 and x+5
the 3rd is the 90° right angle denoted by that "square"
the sum of these 3 angles will be 180°
fresh topaz
ooo
fresh topaz
jaunty marsh
Use vertical angles and then sum of angles in a triangle
fresh topaz
still confuse
jaunty marsh
Can you find angle BAC?
fresh topaz
180?
jaunty marsh
The measure of angle BAC, using vertical angles
fresh topaz
uhh
jaunty marsh
Does this help?
fresh topaz
no but do i have to do 13x + 6 + 70 = 8 + 3x
jaunty marsh
No, measure of angle BAC=13x+6 and measure of angle BCA is 70
That’s why I highlighted them, to show that they’re equal
So, using sum of angles in a triangle, 13x+6+70+8+3x=180
jaunty marsh
👍
strange stag
Hello is there anyone that can help me?
strange stag
Yeah, I was typing it ;-;
I need help with this, I tried doing it the same way my teacher had shown by drawing the triangle and putting 96° but then I just got so confused and lost
dark sparrow
longer sides lie opposite to larger angles.
silent plank
because there isn't enough info
nocturne thicket
@silent plank 2 sides + Angle = SAS ?
silent plank
not quite
note the position of the A in SAS, the angle needs to be between the 2 sides
silent plank
otherwise you just have ASS which as the acronym implies gets you nothing
nocturne thicket
lmao
but what does "between the 2 sides" mean?
Which two sides am I looking at?
ohhh
side 1 and side 2
silent plank
the corresponding congruent sides
buoyant oracle
cosmic pebbleBOT
upper karma
Don't ask to ask, just post it.
radiant halo
can i get help with this please
ive done tan x = sinx/cosx
then tanx = sinx/sin(x+30)
and i used the trig identity
but i dont know where to go from there
dark sparrow
do you know the angle sum identity for sin
dark sparrow
i think you mightve gone down a difficult route
why not start with sin(x+30°) = cos(x) and expand here
dark jacinth
A rectangular box is 2 by 3 by h, and two of its internal diagonals are perpendicular.
Find possible values for h.
Any ideas for this?
granite lintel
this is example https://gyazo.com/881f0e6cd352bc560323a8977137189f
https://gyazo.com/115cd11d4e6435234a4f317e4d82f6df and this is task
i dont understand which line to connect etc
humble pulsar
@granite lintel no info on what the question is
solemn axle
I don’t understand how to do this question. I don’t remember how to get a+bi from this
upper karma
You could start by multiplying by the conjugate num and den
main lintel
You need to get rid of the i in the denominator
obtuse tapir
(2+3i)(9+7i)
——————
9^2-(7i)^2
solemn axle
I got -3/130 + 41/130i
granite lintel
<@!145304030531420161> no info on what the question is
Construct a polyhedral section plane idk if its correctly translaated
im so confused what i need to do
i drew a triangle just connecting those 3 dots 😂
main lintel
@granite lintel Oh, I see. That is likey not enough
A polyhedral is not its internals (the volume), but only the sides
The three dots define a plane (always 3 dots define one plane).
This plane cuts the polyhedral somehow
You need to visualize where will each side be cut.
main lintel
If you connect the dots you will get some visualisation of that plane.
But that will not be enough
granite lintel
btw im using geogebra website where i draw everything sooo myb u could help me out
i sent her 6 tasks and all of them were incorrect
upper karma
Hello, i am really bad at geometry proving and i seek tips to improve my skills
main lintel
Practice. @upper karma
For example this problem of Shades, try to solve it.
@granite lintel When you connect the bottom two points you will get a line. This line is belonging to the cutting plane, right?
granite lintel
i assume like this
granite lintel
ye ig so
main lintel
This line is also passing directly through the side of the polyhedron also, right?
granite lintel
yas
main lintel
So the cutting plane is cutting polyhedron exactly on that line
It cuts this segment IJ
It cuts the side CDEH of the polyhedron exactly on this IJ segment
granite lintel
so? i think i understand cutting part but i dont see the visual in my brain of it where i need to place next line if i have given 3 dots and i gotta add extra dots
main lintel
OK, we did just the first step, but you need to understand it.
granite lintel
mkay
main lintel
The line cuts the polyhedron across several of its sides.
Side CDEH is cut, and is cut on the segment IJ
Now if you connect I and the remaining third dot what you get?
granite lintel
main lintel
OK, does this pass line pass through the ployhedron's side?
granite lintel
🤔 yes
coarse crag
Is there a proof that all triangles can be decomposed into 30-60-90 triangles if we assume an infinite level of subdivision is possible?
main lintel
@granite lintel I mean, it passes though side CDEH but only at one point, I
which is also a point on the CDBA side
And it passes through side ABFG at point G, which is also a point on the HEFG side and CHGA side.
granite lintel
mkay 🤔
main lintel
Now I dont know how to proceed further 😄
granite lintel
😂
main lintel
But at least we have something 😄
OK, let's thing at this point
Can you connect the remaining line also
granite lintel
i cant literally think if i dont get any visual in my brain but i assume
main lintel
GJ
granite lintel
it will make triangle
main lintel
SHow it please
main lintel
I guess what you can do is to take a midpoint of GI
granite lintel
wdym
main lintel
And then make a line J and this midpoint
Midpoint of IG is at the half of the height of the cube (is this a cube?), half of the depth of the qube.
granite lintel
idk
main lintel
@granite lintel What is this task, should you solve that in geogebra?
main lintel
Are these tasks given as geogrebra tasks?
But how can you copy on your paper if you dont know if that is a cube
and if I is the midpoint of CD?
granite lintel
^Construct a polyhedral section plane idk if its correctly translaated
main lintel
OK, I think it is assumed that that is a cube
and that I and J are midpoints of their edges
granite lintel
i guess so
like idk tbh what she wants neither i have been teached about it
neither i have done this before
main lintel
Can you define where the midpoint of IG is?
granite lintel
upper karma
Practice. <@456226577798135808>
is 1 hour / day of practice enough
granite lintel
as long as u practice
upper karma
@granite lintel what grade are you in
upper karma
9$
main lintel
OK, but can you describe where is its position in the cube?
The depth, the height and the offset from the right side.
granite lintel
i dont think i can check on this app
granite lintel
no 😂
main lintel
Well it is in the middle of I and G
I is at the very bottom of the cube, G at the very top, so K is at half height
Same as for depth
granite lintel
i dont think i need heck depth/height for this
main lintel
And as for the left-right offset, I is in the middle, G on the very left, so K is at 3/4 from right to left
granite lintel
i think this isnt that hard xD
main lintel
You need.
main lintel
This is not hard, this is trivial.
coarse crag
You want to know where K is?
main lintel
He wants to know where does the plane cut the cube
I tell him to find K to solve that.
coarse crag
Would there be a better channel for me to ask my previous question?
main lintel
Perhaps. I don't understand the question.
Perhaps competition-math
When you say infinite, I guess you mean finite, but as many as needed?
coarse crag
yes
Given any triangle, can it be decomposed into a collection of smaller 30-60-90 right triangles
My assumption, and logic says that it can
but I need to prove this
So im wondering if there are any given proofs of this
main lintel
It seems as a hard problem, write it on competition-math channel
I will post it on math olympiad channel
coarse crag
Ok, thank you, i will give that a go
main lintel
My intuition tells me nothing here 😄
coarse crag
Well think of it like this, if its a triangle, it has area, and if we assume you can subdivied area, then there should be a point of subdivision where we can comprise the entire area out of nothing but 30-60-90 triangles
coarse crag
Well exactly
main lintel
And I dont think a circle can be subdivided into triangles
coarse crag
That is what im actually getting to, is that you can form a circle completely out of 30-60-90 triangles
It can, thought we do not think of it like that
Here is the crus of everything, resolution
We assume a circle because the resolution in which we percieve the object is not enough to detect the finest of details
coarse crag
If you want to make a true circle, yes infinite
but we never measure infinitely, we measure to a degree of accuracy
main lintel
No, in mathematics we measure infinitely
coarse crag
so this you only need enough equilaterals to satisfy the resulution of the measurement
main lintel
To the finest perfect rpecision
coarse crag
Well we think that is what we do, but it actually wrongh
When you surpass measurable resolution, what you are doing is including "all possiblities"
but the problem is all possibilities are not actually possible
I know, it doesnt make a lot of sense
main lintel
You cannot make these arbitrary statements, either you can prove it with the mathemaical rigour and precision, or you dont make such statements.
coarse crag
and goes against convential math
main lintel
This is not engineering.
coarse crag
Well i can prove the sstatements, that is what im working on
or rather, i will be able to prove the statements
Think of this. In order to distinguish something, what is the single most important facet about that thing?
Space, as without the space around it, it would be indistinguishable from nothing, or anything else, it would not be its own thing
Soo while a circle may appear to be a complete "thing" from a given perspective, zooming in you will either find it is made of smaler line segments, or that the composition of the line mking the circle does not actually complete a circle, there will be gaps between the points
and if it is disconnected arcs, if you zoom in on an arc you will again find it is either comprised of line segments, or again more disconnected arcs, meaninnig the previous arc you saw was not a single arc, but a composite of disconnected arcs
etc etc to infinity
You can see the pink shapes, they appear almost to be a circle at this zoom
But they are this
upper karma
neon hamlet
You could say SAS
Since vertical angles
And your 2 given sides
Can Skew Lines be coplanner?
main lintel
What are skew lines? @neon hamlet
Is that a new question, or related to something prveious?
void wind
Posted in the wrong channel and im too lazy to re-write. I hope its ok
or is it pi/180 that gives radians? 
main lintel
1 PI radians = 180°
From that you get all the values.
For example 2PI radians = 360°
Or 1/2 PI radians = 90°
Or 1/4 PI radians = 45°
...
Or 3/4 PI radians = 135°
void wind
From that you get all the values.
thx
how about the values for the angles? for instance cos 1/2?
how do you get that?
im asuming that you have to memorize the exact values for 30, 45 and 60 degeres
and just put minus if they are in the negative area, right?
main lintel
Yes.
void wind
Cool, thank you very much 😄 
void wind
yup, i learned that pattern thingy so i remeber some stuff from it
void wind
I think i know which one you talking about, that one was very hard to understand
main lintel
you better memorize
main lintel
The derivations are related to observing the particular triangles
void wind
i learned this the last time but i didnt understand cos and sin before but now i have a better understanding for it. I hope im good without it ^^
main lintel
yes, if you memorize these 5 for sin 30, cos 30, sin/cos 45, sin 60 cos 60 you are good
void wind
Great, thanks for the help ^^
umbral snow
Mind you, if you are switching to radians, start to memorize in radians as well. It's a better and easier measure
Converting all the time is pain
void wind
Yea, my trick is i draw the unit circle before the test starts so i have it infront of me. I just wanted to be sure so i don't mess up the values. But you are right , im going to try to memorize them 🙂
main lintel
I convert all the time 🙂
Hate memorization
Its error prone 🙂
I derive as much as I can, and memorize the concepts
void wind
Havent gotten to derivative yet, does it help?
I just know that derivate for sin is cos
lyric light
Does anybody know theorem 5-5
humble pulsar
Does anybody know theorem 5-5
Theorem 5-5 sounds like it's from a textbook.. so no, unless i magically have the text
main lintel
Havent gotten to derivative yet, does it help?
not that kind of derivate. Derivation as derive one value by proving from some other things
When you derive some formula from some other notions, the common english word derive.
main lintel
Theorem 5-5 sounds like it's from a textbook.. so no, unless i magically have th...
hehe, i think his image didnt copy
You see this small [obj]
void wind
whoops, i think ill stick to this one instead :p
umbral snow
@void wind
Though it's cool you want to know. The derivative of a function f is a new function f' that describes the slope of the first.
When you're using radians, the derivative of sin is cos, and the derivative of cos is -sin
late breach
why for cos(2x) can I go for the other angles, but for csc(x) I can only keep the bottom two?
technically the top one would be between 0<x<2pi anyway?
humble pulsar
what do you mean exactly?
csc(x) < 0 means sin(x) < 0, which means x is in quadrants 3 and 4
late breach
the top one I only list 7pi/6 and 11pi/6 but not 5pi/6 and pi/6
humble pulsar
what's csc(pi/6) ?
humble pulsar
yeah, sin is negative in quadrants 3 and 4, so you need angles in those quadrants
cos(2x) < 0, so you need the quadrants where cosine is negative, namely 2 and 3
humble pulsar
cos(2 * 5pi/3) ?
humble pulsar
@upper karma #❓how-to-get-help rule 1
upper karma
You could have just said no
Or not responded at all
Can someone please help me with my geometry
placid bone
it's not a no
it's just an unnecessary question, because this server was literally made for help
so the answer will always be yes
upper karma
Well I just would like some help
placid bone
there will always be someone that can help you
upper karma
@placid bone can you help me
placid bone
just make sure that channel's not being used
depends
i haven't done geometry in a few years
so
but i can try
upper karma
This makes no sense
west basin
why doesnt it make sense
the midpoint theorem tells you the NQ is double the length of RS
placid bone
how does it not make sense lmao
void wind
This makes no sense
Don't pm for help. Just ask, if someone can help they will help.
upper karma
Would you be okay if pm you
main lintel
I'm not answering pms
upper karma
Why
main lintel
If i speak with you there, you might ping me later
upper karma
I won't
main lintel
for further explainations, or new quesitons
upper karma
Which I won't
main lintel
just write here.
placid bone
just
write the question here
there's no judgement
plus having to answer dms is really ceebs
upper karma
Lofi
Is it okay to ping you here
@placid bone
Nobody cared to help me bruh
I've tried on my own
void wind
You can literally ask and somebody will help you
void wind
Then comes the boring part, which is the waiting. If someone can help they will
pure cape
That seems right
humble pulsar
what's the slope of 2x+4y=-5 @upper karma
scenic gust
Can anyone help me with this one i'm clueless
valid lagoon
jaunty marsh
Initial height is found by plugging in t=0
Maximum time for a quadratic ax^2+bx+c is given by -b/2a
Plug that value back into the equation for t to get max height
jaunty marsh
Np
oak citrus
sick junco
Yea I just need help finding the area for all the shapes
urban knoll
Well ummm
It kinda tells u right there
The numbers
I could be wrong tho
Do you have to create an equation?
urban knoll
I’m not sure
scenic fulcrum
can someone tell me if i started this right
desert wharf
tan^2x-5tanx+6
is this factorable? i can't tell
<@&286206848099549185>
jaunty marsh
@desert wharf $(\tan(x)-2)(\tan(x)-3)$
somber coyoteBOT
AV8312
upper karma
@jaunty marsh what does that bot do
desert wharf
thank you !
placid bone
<@688511860500201522> what does that bot do
it basically 'prints' out what you want to say
so for example, instead of saying x^2 for x squared
you just
somber coyoteBOT
lofi hip hop radio
placid bone
and it returns with how you would actually write it
and like fractions too
so instead of (x-1)/(x+1), you could
somber coyoteBOT
lofi hip hop radio
placid bone
do that^
earnest fjord
The point P lies on the line joining A(-2,3), and B(10,19) such that AP:PB = 1:3
- show that the x-coordinate of P is 1 and find the y-coordinate of P
desert wharf
does anyone know how ot solve this? i dont know how ot go about it
earnest fjord
@desert wharf replace q and p with their definitions first
desert wharf
what are their definitions :/
desert wharf
ohhh in the equation?
desert wharf
ok
I DID IT
I LOVE YOU MATE
@earnest fjord I HOPE YOU KNOW THAT YOU AR ENOW MY NEW FAVOURITE HUMAN
earnest fjord
i got that one nvm
bronze forge
How would I go about solving this?
upper karma
In the diagram below of triangle CDECDE, FF is a midpoint of \overline{CD}
CD
and GG is a midpoint of \overline{DE}
DE
. If FG=57-9xFG=57−9x, and CE=29-xCE=29−x, what is the measure of CECE?
bronze forge
Im in a car rn let me attempt it on my tablet
upper karma
Guys can anybody help me out with this question?
dark sparrow
do you know what a line of symmetry is?
steep temple
Encountered this problem earlier today and I feel like I was within grasp of solving it but I didn’t have a clue how to finish
the points a, b, and b prime lie on the line with equation y = -2x + 11
I tried substituting that into the circle equation and solving but that gave me an imaginary solution and I am looking for a real solution (obviously)
the dotted circle and the circle equation on the paper is the approach I came up with to try and solve the problem. the problem itself only stated my previous message about the points being trilinear and the coordinates of point a
steep temple
well what is the equation
main lintel
@steep temple you should show the question, and a clear image. Like this it is impossible. Maybe sketch the image in paint or geogebra or something.
obtuse tapir
-3/4 and 7 are the solutions
steep temple
<@!180738241824030720> you should show the question, and a clear image. Like thi...
I thought so give me a moment
slim saddle
@obtuse tapir how?
slim saddle
it is?
slim saddle
ok
steep temple
Do your calculations properly
this is shitty advice
@slim saddle how many triangles are in the picture?
slim saddle
Do your calculations properly
actually this is good advice
because i did dumb mistake
arithmetic mistake haha
upper karma
Can someone help me with this please? im very confused as to where to start
steep temple
the reason you didnt get the answer was not because of an arithmetic mistake
slim saddle
i did algebra wrong
obtuse tapir
Yes
slim saddle
haha thanks
main lintel
What's stated, and what is the question?
steep temple
what is drawn by desmos, except the circle, is what is stated
what i have drawn is my attempt at a solution
$$
(x-3)^2 + (y-5)^2 = (6\sqrt5)^2
(x-3)^2 + (-2x+11-5)^2 = (6\sqrt5)^2
(x-3)^2 + (-2x+6)^2 = (6\sqrt5)^2
x^2-6x+9+4x^2-24x+36=180
5x^2-30x+225=0
x^2 - 6x + 45 = 0 \Rightarrow x_1 = 3-6i, x_2 = 3+6i
$$
somber coyoteBOT
dlp
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steep temple
the points a(3,5), b, and b prime lie on the line with equation y = -2x + 11
solve for the coordinates of b and b prime
upper karma
dlp mind helping me with some geometry
steep temple
what geometry
upper karma
Midsegments
steep temple
post q
upper karma
In the diagram below of triangle CDECDE, FF is a midpoint of \overline{CD}
CD
and GG is a midpoint of \overline{DE}
DE
. If FG=57-9xFG=57−9x, and CE=29-xCE=29−x, what is the measure of CECE?
steep temple
post diagram
upper karma
there isn't a diagram
steep temple
there isnt a diagram?
upper karma
i was not specific
steep temple
then this is algebra
main lintel
@steep temple You should state the actual question
So given are three points with their coordinates? and asked is what?
upper karma
steep temple
you are given a and the line y = -2x+11
oh and the distance from a to b and from a to b' is 6sqrt5
main lintel
So given is this line, a point A on it, with xA = 3. And 2 other points on the line B and B', which are 6sqrt(5) distant from A?
upper karma
can anybody help me out with this question please ive been stuck on it
steep temple
a is (3,5)
obtuse tapir
@upper karma 2FG=CE
main lintel
@steep temple A is given uniquely by just its x coordinate, as it is on the line?
steep temple
a is (3,5)
where its x coordinate is 3 and its y coordinate is 5
it is on the line y=-2x+11 yes
main lintel
And B and B' are on the same line distant 6sqrt(5) from A?
steep temple
yes
main lintel
And what is the question?????
steep temple
the question is to find b and b prime's coordinates
main lintel
You correctly noted that they are on the circle. That is one way of solving it.
main lintel
Where is the square on the second summand on the first line?
main lintel
If you move 180 to the left it is -180
steep temple
You correctly noted that they are on the circle. That is one way of solving it.
is there other ways to solve it?
main lintel
It boils down to the similar path.
If you dont take the circle, but you write it according to pytagorean theorem.
steep temple
so what i was doing?
i couldnt figure out how to solve it that way
can you show me?
main lintel
d = 6sqrt(5) 36*5 = xd^2 + yd^2
xd is the distance from A to B in x direction, and yd is the distance from A to B in y direction.
So xb= 3 + xd yb = 5 - yd
main lintel
And you also have that B is on the line so yb = -2xb + 11
You can inset xd and yd into first equation.
And you have 2 equations with 2 unknowns "xb" and "yb".
steep temple
but i dont have xd and yd?
main lintel
You have them below the image, as expressions. #geometry-and-trigonometry message
limpid gust
can somebody help me, I don't know what to do here
jagged sapphire
deft blaze
soh cah toa
jagged sapphire
?
slim saddle
nevermind
jagged sapphire
i need help on my homework
jagged sapphire
na
deft blaze
that's literally the beginning of everything
what do you know about right angled triangles?
jagged sapphire
Ion know shit lol
jagged sapphire
i've always been bad at math
i have good grades in all my classes exept math.
deft blaze
but right angled triangles are special cades
cases
because one angle is 90°
do you know the angle which is 90° in your question?
deft blaze
good
jagged sapphire
deft blaze
you know the opposite side, hypotenuse and adjacent?
jagged sapphire
no
deft blaze
ok
the opposite side is the side directly opposite to your angle (line KH)
hypotenuse is the longest side
jagged sapphire
gk
deft blaze
adjacent is the last one
slim saddle
adjacent is the side that is touching the angle, but isn't the hypotenuse
jagged sapphire
KH is adjacent
deft blaze
yes
jagged sapphire
so then
deft blaze
I usually just try to recognize my hypotenuse and opposite then I automatically know my adjacent
slim saddle
Hypotenuse is also the side opposite of the right angle
deft blaze
so you can use sohcahtoa to find the length of a side when given any of the angle and a side
jagged sapphire
what do i do after finding the oppiste and adjacent
slim saddle
soh is the sine function or the sin() on your calculator
slim saddle
tan(theta)=opposite/adjacent
slim saddle
haha theta is the angle
deft blaze
yes the sohcahtoa is an abbreviation
jagged sapphire
brain
deft blaze
sine opposite hypotenuse
slim saddle
would you like an example of how to solve one of these problems?
jagged sapphire
Sine vs oppisite right
deft blaze
lol
jagged sapphire
@slim saddle yes thank you?
deft blaze
you really should know all these things
jagged sapphire
i'm a retard at math lmafo
deft blaze
before being given that kind of question
slim saddle
@jagged sapphire your teacher isn't very good
deft blaze
true
slim saddle
beam could you join the mathematics channel please?
next jackal
@upper karma Do you understand trigonometric identities?
upper karma
nothing
at all in trig
idk what the word even means
pls help its my final
@next jackal
yea i am gonna commit
next jackal
@upper karma What do you see that you can do when $cos(\theta)$ is given and $\sin^2(\theta)+\cos^2(\theta)) = 1$?
somber coyoteBOT
Researcher in Pre-algebra
deft blaze
how'd one explain this even, isn't it just too obvious
ashen rain
The answer is B
I solved it logically
However I want to know the actual way to do it?
Can anyone guide me?
jagged sapphire
ashen rain
@jagged sapphire
Just add all the x coordinates and y coordinates and divide each sum by 4
U Will get the centroid
jagged sapphire
@ashen rain Like what do you mean by adding
jagged sapphire
i figured it
ashen rain
Yeh
ashen rain
Lol
ashen rain
Ur welcome
ashen rain
Sure
earnest echo
Is that a test??
coarse crag
This is why i hated geometry, always have to remember the stupid names. While it has a correlation to if you actually know the answer, its not testing that, its testing if you can remember a level of abstraction of the reason.
jagged sapphire
jagged sapphire
Is that a test??
no practice homework
limpid gust
so the angle is 120?
earnest echo
Yeah
deft blaze
limpid gust
@earnest echo why??
earnest echo
Because it's bannable offense to ask for help on tests
limpid gust
its not a test
steep temple
how many types of triangles do you know
steep temple
are you sure that is a right triangle
steep temple
so why are you talking about hypotenuses
umbral snow
Did you get that last one?
steep temple
are you just posting your homework here
jagged sapphire
@umbral snow yeah by myself
without help
i watched a video
i need help not awnsers
steep temple
#geometry-and-trigonometry message
#geometry-and-trigonometry message
#geometry-and-trigonometry message
#geometry-and-trigonometry message
#geometry-and-trigonometry message
#geometry-and-trigonometry message
#geometry-and-trigonometry message
in 2 hours you've posted 7 questions without even saying what youve attempted
umbral snow
Maybe try watching the videos first, and post if you're struggling
solemn axle
A reference angle is the angle between a point and the x axis.
So take 0 and 180 and do +- 89
One of them is already 89 so just find the other three
@thorny lintel
thorny lintel
why would you use 180? @solemn axle
upper karma
For any angle b, there are rules as to how you find the reference angle(a):
Quadrant 1: a = b
Quadrant 2: a = 180 - b
Quadrant 3: a = b - 180
Quadrant 4: a = 360 - b
@thorny lintel
tender prawn
i haven't got the faintest idea how to do this
thorny lintel
wait isn’t the reference angle 89° already? @upper karma
tender prawn
im guessing i should use tan = sin/cos but i dont feel like i have enough info
upper karma
what problem you're trying to solve? @thorny lintel
thorny lintel
question 2 @upper karma
upper karma
yeah it is 89
silk patio
You should be able to rearrange it chicken and use cosine formula
cos(C)=1/2
tan(C)=rt(3)
silk patio
Use intuition
upper karma
I've tried so many things, 45-45-90, tried using sin, cos, tan. none of it worked my answer was still wrong. One thing I have learned is that there must be a ratio between the big circle's radius and small circle's radius. I just need to find the ratio
green tree
silk patio
Join the centres of the two circles
green tree
help me please
green tree
@silk patio
tender prawn
how do I find the radius of the inner circle?
or like draw a square around the two circles
silk patio
Don’t at me
green tree
im asking for help mr famous
tender prawn
btw wdym by cos(C)=1/2
tan(C)=rt(3) sorry
like
oh
if cos(C) = 1/2, tan(C) = sqrt3?
silk patio
Yeah probably
jagged magnet
can i get some help on this
silk patio
But to get that you rearrange it
jagged magnet
i dont quite understand the concept
tender prawn
angle chasing
just label a bunch of angles and use sum of angles in triangle is 180
also altitude forms a right angle with the base
silk patio
Guys I’m struggling with my triangle, can you help me
jagged magnet
we re in the same class
silk patio
Help each other dummy
jagged magnet
all we asked for was help
tender prawn
green tree
this guy keeps harassing me
jagged magnet
and u ignored