#geometry-and-trigonometry

1 messages · Page 230 of 1

idle bloom
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No just the key ones pls XD

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Now that hand trick sounds interesting, I'll research into it, thank you ann 🙂

dark sparrow
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idk if it's the actual name

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might be easier if i just say it

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like

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describe it

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so here's a hand

idle bloom
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Ok. 🙂

dark sparrow
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the pinky is 0

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the ring finger is 1

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middle is 2, index is 3 and thumb is 4

idle bloom
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Yeah, i get that.

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🙂

dark sparrow
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the angles are, in degrees: 0, 30, 45, 60, 90

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the sines are: sqrt(0)/2, sqrt(1)/2, sqrt(2)/2, sqrt(3)/2 and sqrt(4)/2

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the cosines are: sqrt(4)/2, sqrt(3)/2, sqrt(2)/2, sqrt(1)/2 and sqrt(0)/2

idle bloom
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Woah: see this is why you're such a cool person 🙂 thanks so much.

small raptor
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Imagine if you tatt'd that on your skin. I wonder what the school would do to prevent cheating.

idle bloom
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mandatory glove wearing

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I'd feel sorry for people with sweaty hands XD

granite mortar
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that's why you should allow students to take notes to the exam

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so they don't tattoo their skin to pass a random class

idle bloom
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takes in a laptop

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or phone!

upper karma
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Hey, @gusty drum please remain on topic in this channel

upbeat crow
peak locust
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the height of the bar is 2 + 2sin(60)
the width of the bar is 2 + 2cos(60)
use pythagoras to find the length

upbeat crow
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thanks!

sudden mica
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I need to find all the variables

limpid dome
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you know that f is going to be 58

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because of vertical angles

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then since the sum of angles on a line is 180 degrees, 64 + 90 + e = 180

sudden mica
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I got that

limpid dome
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then you can get the angle in between 78 and f

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and from that get the angle at the other end of the triangle from 64 degrees

sudden mica
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K

limpid dome
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actually that doesn't matter nvm

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just use parallel lines property to see that b has to equal 78 degrees

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and then a = 102 degrees

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similarly, c = f

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and then d = 180-f

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gottem

sudden mica
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Ok

limpid dome
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i bet you just forgot abt the parallel lines

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they kinda blended in

sudden mica
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Yea

radiant nimbus
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so I understand this right... sinh(4x) can be rewritten as (e^4x-e^-4x)/2?

limpid dome
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yeah that's the equation for hyperbolic sine

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if that's what you're asking

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just replace the "x" with "4x" as you've done and you're good

unborn jacinth
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@limpid dome you play hollow knight!!

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im at the mantis lords part

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its hard

limpid dome
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it's not too bad once you realize the attack patterns

unborn jacinth
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yeah

limpid dome
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try on attuned or radiant in the godshome

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jesus that took a while

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also try to improve your nail if you're not getting enough hits in before you make a mistake

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go to the nailsmith

unborn jacinth
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ok

limpid dome
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find pale ore etc.

unborn jacinth
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did you beat the game

limpid dome
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112%

unborn jacinth
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oo

limpid dome
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still not all the hunter's journal entries lmao

radiant nimbus
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sweet, just finished my Cal 2 HW... this hyperbolic trig isn't as bad as I thought it'd be

unborn jacinth
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also I have a math question now

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u know the remainder theorem

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the one that states

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that

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if u divide f(x)

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by (x-a)

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the remainder is f(a)

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what if u don't divide by x-a but like 3x^2-3

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what is the remainder now

limpid dome
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i don't remember anything about that lmao

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what class is this

unborn jacinth
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or does remainder theorem not apply

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trigh

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alg2

limpid dome
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tf

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never learned that

radiant nimbus
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sounds like hocus pocus

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lol

limpid dome
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yeah

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i'd just look it up tbh

unborn jacinth
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:(

radiant nimbus
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haven't taken alg 2 in like 8 years tho

unborn jacinth
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jk

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lol

limpid dome
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you never use it ever

unborn jacinth
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yeah

tawdry pivot
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some notation issues. also you might not find it useful

upper karma
frosty marten
flint pelican
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Guys for this one organic says that cosine normally starts low but I thought co started high and then went downwards

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Is it because it has a negative amplitude right?

tawdry nova
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@flint pelican yes

frosty marten
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Audio

bright nexus
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help 😦

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idk how to start

silent plank
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special angles/triangle

bright nexus
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oh

flint pelican
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Ok

dark sparrow
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:?

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"potty"?

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:?

hard lotus
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anyone up?

worthy root
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🤔

unborn jacinth
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question

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so

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if you have a polynomial which is like x^7

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it means it has AT MOST 7 zeros

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but EXACTLY 7 factors

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right

peak locust
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what is the difference between a zero and a factor

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for each factor, you have a zero

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so you have exactly 7 zeros and 7 factors

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although all of them may not be real

unborn jacinth
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ok

sharp gust
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Would anyone be willing to check these answers and tell me if I'm wrong, and potentially help me out with the third one?

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Might I add that I have the intelligence of a stick of celery

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hElp

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I gotta turn this in in less than 10 minutes

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<@&286206848099549185> yeet

upper karma
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?

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Oh rip the 10 minutes passed.

sharp gust
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I'm still looking for help regardless, I want to know this stuff before I move onto the quiz

upper karma
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K.

silent plank
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6B, what is a segment bisector?

upper karma
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Oh okay ramonov will help ig.

sharp gust
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A line that bisects a segment down the middle of it

silent plank
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does the question give you such a line?

sharp gust
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Yes, line l

silent plank
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and what is it bisecting?

sharp gust
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lines TR and NS

silent plank
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it doesn't actually say its bisecting NS

sharp gust
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But its still bisecting down the middle of it

silent plank
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although it is, that information isn't immediately available without proving congruency

sharp gust
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Would it be A instead of D, since NQ and QS are congruent and are cut in half by line l?

silent plank
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you don't actually if NQ and QS are equal yet
specifically use the information from statement 3

sharp gust
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Oh okay, so B then?

silent plank
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yeh

sharp gust
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Thanks ^^ Is 5A correct?

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6a*

silent plank
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yes

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you should be able to do 6c now

sudden mica
silent plank
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where are you stuck?

sudden mica
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I need to find 1

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@silent plank

silent plank
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hint: ||tan||

quiet mason
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he said

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1

silent plank
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and try use your knowledge of that to determine the relative sizes of 2 and 3 w/o a calculator

quiet mason
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do you knpw the properties of an isosceles triangle @sudden mica

sudden mica
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Yes

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A triangle with 2 equal sides

quiet mason
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did you know the triangle has equal base angles

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or the angles adjacent to the equal sides

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@sudden mica

sudden mica
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Yes

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Oh i get it now

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Thanks

quiet mason
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👍

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can you solve for 2 and 3

sly gulch
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Hello, i want to ask about trigonometry in real life for my presentation and i seems stuck for 2 days now because the task cant be same as everyone can someone gave me an idea?

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Especially in infinity incolving trigono metry

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*involving

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Can someone help me? Thanks

sly marlin
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hmm

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you can probably use electronics or architecture

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or any simple harmonic motion

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@sly gulch

median crown
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infinity?

sly marlin
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not sure what that is about

median crown
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infinity isn't a real thing

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its a concept

sly gulch
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I mean in like lim In real life like how
x->∞.
to count distance from earth to sun

median crown
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thats not infinity

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wtf

sly gulch
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I mean it like something that have too many number so it called infinity or limitless

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Sorry my english is not that good

median crown
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92.96 million mi

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i mean

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what trig thing goes to infinity?

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even if you had infinity, how will you relate that to trig?

quiet mason
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ye you can assume the distance to be infinity

sly gulch
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Sorry but what do you call this formula in english lim
x->∞.

quiet mason
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its notation

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not formula

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its called a limit

median crown
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oooo

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you could use a taylor series for sin

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you could have infinite terms

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or you could explain pi as an infinite algorithm

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using

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Li Hui's method

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google that one

sly gulch
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Sorry what do you call lim In english?
x->∞

median crown
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its called

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limit

sly gulch
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Because in my language it called as infinity limit :( so im confused

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Lim (Example its called limit function
x-> 1

median crown
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same thing

sly marlin
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We just call it a limit

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Maybe an infinite limit

dark sparrow
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limit at infinity

sly gulch
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Right

sudden locust
dark sparrow
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6 minutes to prove a theorem that can be proved in 2 lines, nice

sly marlin
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10 seconds title
12 seconds splash screen
11 seconds to state the theorem
77 seconds to show an example
47 seconds for angle of a straight line
31 seconds for first line of proof
35 seconds for second line of proof
64 seconds for last line of proof
19 seconds for conclusion
44 seconds shameless plug
21 second outro
more than 6 minutes of my time taken

dark sparrow
sly marlin
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nah I was playing it on 5 times speed

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and I started after you put that

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at least I found the timing entertaining

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took me at most 9 minutes to time it

sudden locust
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I guess the video is targeted for people that is trying to grasp it for the first time... So I always try to be as clear as possible.

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Thanks alot for watching guys 😊 🙏

queen python
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Hey there pal

sudden locust
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Whats up Bongo!

queen python
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How is life

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Are you trying to be a YouTube tutor?

sudden locust
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Ouff, its actually great. Im in a good place right now!

queen python
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very good

sudden locust
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Yeeah im actually studying economics, but I really enjoy math so I work quite alot on a math YouTube channel...

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Really enjoying the process of making videos aswell

queen python
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well if you would listen to my advice I'd recommend not aiming to be big at the start

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try getting a community

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math is one of those topics that people will never stop watching

sudden locust
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Yeeah. Its a marathon not a sprint

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Indeed

queen python
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Also you should maybe do some economics videos

sudden locust
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I will, in the future! Man I have SO many videos planned to do...

queen python
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Is it a ap class?

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there aren't many ap economic videos with the course

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If you could go by unit courses for it that would be nice

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I'm self studying economics and couldn't find many in debt videos on it

sudden locust
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Oww awesome!

queen python
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I might start a tuturing channel soon also

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I'm doing us history and us government this year so I might tutor those so I have my notes digitalized

sudden locust
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Hey thats awesome!

nocturne hill
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Whats tan ( \alpha × X )

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Is equal to ?

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I need to solve this but i guess first i have to transfer 200pi/3 to something that is included in ]-pi/2 , pi/2 [ right ?

flint pelican
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Guys

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I have been working on shifting trig functions for like almost an hour

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And I’m still getting every question wrong

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And I feel like I kind of know what I’m doing but at the same time I absolutely have no idea

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Someone help

flint pelican
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This is too hard

nocturne hill
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@flint pelican same , ive been working for 3hours now and i think everything i did is wrong i hate trig soo much

quiet mason
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@nocturne hill

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arctan is the inverse function of tan

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so $\tan^{-1}(\tan(x))$=$x$

somber coyoteBOT
quiet mason
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and in your case x=200pi/3

dark sparrow
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no

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arctan(tan(x)) isn't always equal to x

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arctan isn't the true inverse of tan

nocturne hill
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@dark sparrow u have any more info about that ? Bcuz from my class its the inverse of tan

dark sparrow
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it's the inverse of a RESTRICTION of tan.

nocturne hill
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Oh yeah u right

dark sparrow
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but arctan(tan(pi)) = arctan(0) = 0

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and 0 isn't pi

nocturne hill
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]-pi/2 , pi/2 [

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Also @quiet mason i know that but arctan(tan(x)) = x only if x is included in ] -pi/2 , pi/2 [

dark sparrow
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je parle fr

nocturne hill
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Ah super ca

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Jai du mal a trouvé les notations en anglais lol

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Sinon c'est correcte ce que jai fait ?

dark sparrow
nocturne hill
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X ici cest pi/3

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Non ?

dark sparrow
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il n'y a aucun x nulle part dans ce que t'as écrit

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à part le quantifieur

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ça le rend redondant

nocturne hill
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Mais 200 pi/3 nappartient pas a -pi/2 pi/2

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Comme puis je résoudre ca ?

dark sparrow
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t'as écrit tan(200pi/3) = tan(pi/3)

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écris en addition que pi/3 appartient à ]-pi/2, +pi/2[

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et voilà

nocturne hill
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Aaaah booon ouais

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Jai lidee a la tete ms g tjr des problems de rédaction

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Meerci :)

formal bolt
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tan(200pi/3) = tan(-pi/3)

dark sparrow
formal bolt
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lol

nocturne hill
dark sparrow
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hey j'ai jamais dit que tu aies raison en écrivant tan(200pi/3) = tan(pi/3)

nocturne hill
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Nan ms chuii vraiment nul en trigo 😭 😭

dark sparrow
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ms ?

formal bolt
hard gale
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mais

formal bolt
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That bit doesn't strictly have to do with trigonometry though, so you're safe!

nocturne hill
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Mais ?

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@formal bolt can u please explain why tan 200pi/3 is -pi/3 ?

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Isnt it 2K × pi/3

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K in this case is 100

formal bolt
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Oh but you need it in the form $\alpha + k \pi$, where $\alpha \in ]-\frac{\pi}{2}, \frac{\pi}{2}[$

somber coyoteBOT
nocturne hill
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Oh yeah right

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Whats k in this case ?

formal bolt
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Any integer

nocturne hill
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But k should be an impair number in this case for it to be -alpha

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Right ?

dark sparrow
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impair ?

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oh en anglais on dit "odd" pour impair et "even" pour pair

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et non il n'a pas à être pair ou impair

nocturne hill
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🤦‍♂️ rightt odd*

formal bolt
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Parity of k doesn't count because tangent is pi periodic

dark sparrow
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tan est périodique de période pi

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pas 2pi

nocturne hill
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Aaaaah gotcha 👍👍

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I skipped my trig lessons and now im having problems

formal bolt
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Keep well in mind the graphs and the unit circle I'd say, as a compass

nocturne hill
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Yes it helped me in many cases but i really need to review the whole lesson

flint pelican
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Four hours and I still don’t understand this

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I hate math

upper karma
full ruin
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hello

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can someone help me in here

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can i just like send it to you? it’s geometry

full ruin
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anyone?

nocturne hill
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@full ruin just send ur question right away u dont have to ask to ask as the rules says lol

full ruin
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those three pls

nocturne hill
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For 31 have u tried pethagors ?

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| MN | =( 2x + 5)/2

full ruin
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oh

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all i need is 31 now

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i did the rest

nocturne hill
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For 30 too just use pethagors

full ruin
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well i “did” the rest

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is that the theorem thingy?

nocturne hill
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Use pethagors for 31

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A^2 + b^2 = c^2

full ruin
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OH

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Which ones a

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and b

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and c

nocturne hill
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MP is c

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OP is either a or b and the other is NM/2 which is QM

full ruin
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48? pls

nocturne hill
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Ugh i kinda forget about these 😂

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Gimme a sec

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Ughh idk tbh

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I studied this like 4 years ago 😂 i completly forget it

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Mb someone else can help

full ruin
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ok

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thts why math is useless

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cause you forget it

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EVERYONE DOES

umbral snow
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It's not clear what the numbers are referring to. Are those angles? Lengths?

gleaming yarrow
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i would think that 4x+10 is CDB, and 12x-8 is BCD

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but maybe not

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if that was the case then you'd have the equation 12x-8 + 4x + 10 + 34 = 180

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16x+36 = 180 => x = 9

nocturne hill
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If those are equations of the angles then @gleaming yarrow is right

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I tought they were lenghts

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I guess they should be angles afaik length is useless in this case to find x

unreal nest
silent plank
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where are you stuck?
do you understand the steps invovled?

unreal nest
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I’m unsure what the steps are

silent plank
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@unreal nest do you still need help?

unreal nest
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yes

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I do

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@silent plank

silent plank
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in Q1
do you understand how they got from
5x = 3(2x-4) to
5x = 6x - 12?

idle bloom
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@full ruin you can't say math is useless because you forget it

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That's like saying reading Shakespeare is useless because you'll forget the stories eventually

upper karma
#

Except math is used much more than Shakespeare irl.

idle bloom
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That too

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But he was saying it was useless because people forget it

spark stag
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I never got why math, specifically, was the focus of "this subject is useless" complaints

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Is it a cultural thing? Just students being bitter?

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Because yeah, sure, some jobs don't need math

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But most jobs don't need biology, or chemistry, or literary analysis

idle bloom
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It's a cultural thing

spark stag
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And if your job needs physics, it definitely also needs math

idle bloom
#

It's because unlike alot of other subjects, it's very foundational

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Like in an English class, I can completely not understand one book, but then when the next book comes around it's like a clean slate

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But in math it builds off of itself

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So people who fall behind are hurt the most

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And then it's really hard to catch up

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And then bam, you aren't so doing well in class so you don't like the subject

upper karma
#

Mathemetician's Lament.

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You start off, and it's pretty easy.

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As things accumulate it eventually gets to the point where it's incomprehensible.

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Like I'm in 10th grade HS rn, taking Precalc H.

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And there's only 4 people that can do these challenge problems my teacher puts up.

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This kid from China, me, and these 2 twins.

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And it's like, not that hard, but people doesn't see it.

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People only tries to use patterns to get them through, which is why everyone gets a b or lower on tests, since my teacher's tests has conceptual problems.

idle bloom
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^^

upper karma
#

it's not really the culture, but rather, excuses to something people sees as hard.

idle bloom
#

Concept vs pattern is something that's not taught

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In calculus that falls apart even more

upper karma
#

^

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We're learning logs ffs and people are struggling.

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Like we learned it last year.

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And like some of us learned it the year before.

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Smh.

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People are trying to do the same thing for every test.

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They learn the subject, and once the test is over, they drop it.

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Because it's just a pattern, not something they deeply understand.

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If they deeply understood it, there's no way in hell they'd just forget it after a test.

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After all, math is just logic.

idle bloom
#

Math is about logic not numbers

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Just like how history is about connections not dates

quiet mason
#

then why do i have to fucking learn up dates for my exams

fringe dirge
#

partially for the same reason that you have to memorize a multiplication table

dark sparrow
#

history class has been nothing but a bunch of names and dates ime

idle bloom
#

2x2 is 2^2 right, so 8x8 is 2^6 or am I missing something?

dark sparrow
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if by x you mean *, then yes

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8 * 8 = 64 = 2^6

idle bloom
#

Thank you. I've today spent a bit of my lunch at school trying to show my classmate why that happens and they just didn't get how indices worked, to the point i thought i was going mad XD

brisk rock
#

Okay I got issues so I used to be able to do this stuff and I kind of understood but now I don't at all 😂
If anyone could walk me through solving this I'd be so grateful

trim pulsar
#

Do you start by factoring

idle bloom
#

Wait do you assume it equals 0?

somber coyoteBOT
trim pulsar
#

I'm pretty sure you just factor and that's the max simplification

coral sapphire
#

why is it not max simplified?

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You know the denominator /= 0, but no terms cancel

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I can't see anything to do

brisk rock
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Yeah I'm totally lost hahah

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Cause I'm barely capable of factoring

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I would but I just end up getting super confused

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I've been going over factoring in class for about, 4 years?

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I'm a junior in high school, started going over factoring in at least 8th grade

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Pre algebra, algebra 1, algebra 2, now I'm in aglebra 3/trig

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Ooo

trim pulsar
#

Alg 3 is a thing?

brisk rock
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It's Trigonometry, but in my school they also use Algebra III as a name for it

trim pulsar
#

Unenlightened NYC gang

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Wait a second

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Nvm

knotty glade
#

@upper karma Y'know there's no reason to be rude about it, seriously
Or, accuse anyone of lying

eager shell
#

Hi. I just had a quick question, if a circle is split into three equal sectors, would the angle of each sector be 360/3? I missed the class with this subject 😅

quiet mason
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define equal sector

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you mean sectors with equal angles

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?

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either way

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even if the arc lengths are equal

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yes the angles are 360/3

eager shell
#

The task i'm trying to solve says it's a circle that's split into three equal sectors. And that each sector is to be folded in a way that makes it a ("side face"?) in a cone.

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only other information i've been given is the radius of the circle.

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And i need to find the volume of the cone. And i figured i could do that by getting the surface of the cone and then getting the height through S = SquareRoot(r^2 + h^2)

quiet mason
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lateral height

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yeah

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but r is radius of base of cone

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that is not equal to radius of circle

eager shell
#

hmm

knotty glade
#

@upper karma Yes.

eager shell
#

This is extremely confusing.

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So if the circle is split into three sectors

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and each sector makes a surface for a cone.

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then i have three equal cones

eager shell
#

Ok so this is what i've got. I find the area of the sector by ```c
r1 = 12
(Pi12^2120) / 360 = 150,8

// Then i get the circumference of the base of the cone by doing

b = (2Pi12120) / 360 = 25,13

// From there i can get the diameter of the base by doing

25,13/Pi = 8

// This solves my first task which is to get the diameter of the base. Task B is to get the volume of the cone. I start of like this

r2 = d/2 = 4
s = r1 = 12

// I then use Pythagoras to get the height

h^2 = 12^2+4^2
h = SquareRoot(12^2 + 4^2) = 12,65
V = (Pi4^212.65) / 3 = 212cm^3

eager shell
#

Wait

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i messed up

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cause h is not the hyp

upper karma
#

My teacher is not willing to tell me how to do this so can someone explain me how do I get those blue areas?

umbral snow
#

What a weird question

upper karma
#

Equilateral triangles

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(it's a project Kaynex)

#

Those triangles are the same size as the dotted ones

#

The one that have 2 equal sides

#

Right!

#

They are isosceles triangles

umbral snow
#

If you tried to fit the dotted triangles into the box, what would happen?

upper karma
#

Boi... The square is made out of the one side of the triangles that's not the same side

#

They would be 1/4

#

Of the square

#

The area of the big one is 110,000 cm^2

#

One quarter would be 110,00 ÷4?

#

???

#

sadcat hello?

#

I need to find the area of the blue area everytime it gets small, an amount of 30 times so ;_;

#

I don't even know how the get a new square

#

<@&286206848099549185> pandaOhNo

umbral snow
#

@upper karma
The blue square is halved every day

upper karma
#

Uhmm

#

I can kinda see it

#

But is my hypothesis of dividing 110,000 into 4 to get the quarters is correct?

#

Then I just need add them all

#

And that would be my new area

#

It's wrong

#

That just gives the area of the first square catSad

idle bloom
#

Right let's start from the beginning right, what is the area of the first square.

upper karma
#

110,000

#

Cm^2

idle bloom
#

Now, for a second while I explain this forget about that number ok

#

What do you do to a number if you want half of it

upper karma
#

Divide it into 2

idle bloom
#

Yeah ok, now what happens if we divide by 2, twice

upper karma
#

A quarter (?

idle bloom
#

Yeah also known as 1/( 2^2)

upper karma
#

Yeah...

idle bloom
#

so if on the 3rd day we've divided by 2 3 times

#

what will you do?

upper karma
#

Divide by 2^3?

idle bloom
#

Exactly

#

Now if you notice that you raise the number to the power of how many days you divide by 2 by.

#

So If I divide by 2 for 15 days:

#

It'd be

#

The amount /(2^15)

upper karma
#

Yeah!

idle bloom
#

Woops not 1 XD

#

so by day 30.

#

it'd be?

upper karma
#

I see how the square is halfed, but I don't know how to explain it

#

/2^30

idle bloom
#

yes you would do that/

#

But if you don't know why you half it I can explain that as well 🙂

upper karma
#

Please!!!

idle bloom
#

It involves Pythagoras have you done that?

upper karma
#

I'm living from school right now, I'm going to be offline for aprox 45

idle bloom
#

Ok, I'll do this quick then

upper karma
#

Listening/reading you

idle bloom
#

if you have a side on a square and it is length: 4

#

Just let it be that for a moment

#

The midpoint would be halfway between 4, or 2

#

now if we know that these 2 midpoints we drew on the square are each 2cm across

#

We should find that (sqrt of (2^2 add 2^2) is 2 sqrt 2

#

or a length of our inner square.

#

Now the area of our larger square in this example is 4x4 or 16

#

and because we know the length of the inner square is 2 sqrt 2 we just square 2sqrt2 to get 8cm

#

8 is 1/2 of 16

#

so our inner square is 1/2 the bigger squares area

#

That might be a bit hard in the way i've put it so sorry @upper karma

upper karma
#

Reading it right now

#

Oofthonkg

#

So it's because of the midpoints

idle bloom
#

Yeah I wrote that badly, even I'm lost reading it back XD

#

Yeah, because of the midpoints, to understand that, I'd recommend just drawing it out and labelling one of the sides a letter and using that to work out the formula for your first square.

upper karma
#

holothink uhmm

idle bloom
#

anyway XD

#

you do 110,000 / 2^30 and voila your answer to the area of the square after 30 days.

upper karma
#

Nice nice

idle bloom
#

I wish my school set us projects like that XD, (I'm a little bit of a nerd )

upper karma
#

They are fine... I guess

#

I'm new to this school so the stuff I know doesn't match with my classmates knowing

#

In a negative way, most of the times I don't know what's happening

#

Like this problem, I don't remember doing this type of stuff in my previous school

#

I think my teacher think am not as good

#

This is something I was supposed to know alreadycatSad

idle bloom
#

Yeah, in my classes in Britian, our teacher doesn't fully know how much people know their mathematical knowledge and just goes straight through topics expecting people to know. So I often end up helping people sitting next to and around me. I find it quite relaxing and fun to do, especially when people go from that "What, i don't get it, to the OH!!, i get it now" 🙂 Tbh just look up on the internet for maybe a hour or 2 a week some maths problems at your level and just above , then have a go at them and if you don't get it look up the reasoning behind them. That's what I did when I was struggling for a bit. But that's what I do, it might not work for you. Anyway good luck with you education 🙂

upper karma
#

Guys i need help

coral sapphire
#

Sure what

upper karma
#

help

#

how

#

Did you survived the question

novel flax
#

ok so

#

you manipulate the sides

#

and you will get a right triangle with legs 7 and 23

#

the hypotenuse of the right triangle is the diagonal of the square

#

which is 17 radical 2

#

since 17 radical 2 is the diagonal of the square, then x (the side of the square) is 17

#

did i help @upper karma

upper karma
#

thanks

#

mow i know

#

hmm

mellow flicker
#

approved @novel flax 👌

#

btw @upper karma idk if this is how orange905 did it but it helps to rotate those lines thus making a rectangle with sides 23 and 7 to find the diagnoal

upper karma
#

i am still trying to start with it

#

just says find x

upper karma
#

Does it looks like a correct answer?

olive solar
#

where's your question?

unborn jacinth
#

question

#

horizontal asymptotes can be crossed right

#

but vertical ones can't

upper karma
#

Yes.

unborn jacinth
#

so then @upper karma what do horizontal asymptotes tell us

#

what is their significance

#

and also do they only cross when x-> infinity or x-> -infinity

upper karma
#

It's easiest shown by a graph.

#

No.

unborn jacinth
#

it can be either?

upper karma
#

For horizontal asymptotes it never crosses at infin/-inf.

#

At most, it would touch it but never cross.

#

Horizontal Asymptotes helps us graph.

unborn jacinth
#

ohk

#

wait

#

so if the horizontal asymptote of a function is like y=2

#

it can either go from like y val 100 to y val 2.000000009

#

etc

upper karma
#

Yes.

unborn jacinth
#

but does it ever reach 2

#

yes right

upper karma
#

Horizontal asymptote can be intercepted, but not vertical.

unborn jacinth
#

wait wdym by not vertical

#

isn't that what horizontal

#

is

upper karma
#

Horizontal is left to right. Vertical is up to down.

#

Vertical is not intercepted.

unborn jacinth
#

ohhh

upper karma
#

Since if you plug in x=2 or x=-2, you get an undefined y value.

unborn jacinth
#

thats what u mean

#

ok

#

sorry

#

last question

upper karma
#

No need to be sorry.

unborn jacinth
#

im drawing something

#

one sec

#

lol

#

@upper karma

#

Ok so if the green line is the horizontal asymptote and the red lines are the graph, is this possible

#

like can the graph go through it

#

not just touch it

umbral snow
#

"Asymptote" only matters as you go very far in either direction

upper karma
#

It can depending on the graph.

#

^

umbral snow
#

A graph can definitely cross it, then go back to it

upper karma
#

Yep.

umbral snow
#

It just has to end approaching it

unborn jacinth
#

ohk

#

thanks!

#

@umbral snow Assuming the blue line is the horizontal asymptote, the graph would have to look more like the green one rather than red

#

am i correct?

#

because the red one doesn't end approching it

umbral snow
#

Yes

unborn jacinth
#

ok

upper karma
#

oh nm sorry

tulip flare
#

can somebody help

upper karma
#

how to do

dark sparrow
#

what have you tried, where are you stuck, and most importantly why are you posting this algebra question in #geometry-and-trigonometry?

upper karma
#

It said a cube

#

but ok

vague pagoda
#

"it said a cube"

upper karma
#

Hi i need help with a question

fallow thunder
#

,rotate

somber coyoteBOT
upper karma
#

Yes

upper karma
#

yes?? XD

#

geo-trig

#

is it?

#

im taking trig and i was given this

#

LOL aight

#

ok ok

#

algebra 2 is trig???????????\

#

or ur taking about the question

#

um

#

sure

#

it relates

#

🙂

#

....

#

sure

ruby slate
#

This is not related to geometry or trig at all

upper karma
#

lol i just want this problem solved! Not to argue

tall dagger
#

alright i need some help

#

with this

full ruin
#

LMAOO

#

this easy asf

#

even i can do it

tall dagger
#

then teach

#

I don't feel like trying to learn it from the videos

#

because they're ass

#

and I don't wanna skip the question because ima have to restart

full ruin
#

it’s 40

#

you are welcome

#

ly2

#

yes ik i’m smart

#

yes ik i’m sexy

#

yes ik- woah that’s a bit inappropriate sir

tall dagger
#

jajajaja

#

i already got 40

#

but h o w to get

long sapphire
#

you have one square with dimensions 4 by 4 and 4 triangles with dimensions 4 by 3

tall dagger
#

ahh I see

#

what about for this one?

wary turtle
#

In the same way Jiramide said: you have rectangles with dimensions 3 by 5 and an equilateral triangle with dimension 3 by 3.

#

Knowing the base of the triangle, you can calculate the area of the floor.

tall dagger
#

mhm 15 correct?

upper karma
#

You have 3 rectangles and 2 triangles. Find the area of those and add it.

tall dagger
#

15 + 15 + 15.. + 1.95 + 1.95...??

wary turtle
#

Yes, if 1.95 is indeed the area of the triangle.

tall dagger
#

1.5 * 2.6 * .5 correct?

#

to find area of the triangle

upper karma
#

What the fuck.

#

Umm.

#

The base is 1.5+1.5?

#

Which is 3?!??

tall dagger
#

LMAO

#

I was just doing thye base of one half

#

of the side

upper karma
#

Don't lmao my ass.

#

Multiplying 2 lengths OF THE SAME LENGTH.

#

Won't get you anywhere.

#

Furthermore, that is simply not the area of a triangle.

tall dagger
#

3 * 2.6 * 1/2

#

?

upper karma
#

Good.

tall dagger
#

ahaha

#

3.9

upper karma
#

K good.

#

And you have 2 of those triangles right?

tall dagger
#

15 + 15 + 15 + 3.9 + 3.9??

upper karma
#

Yes.

#

That's it.

tall dagger
#

thank you wise master

#

I am now a pro at calculating area of triangular prisms

upper karma
#

Note that if you did 1.5 * 2.6 * 0.5, you would have only solved half of 1 triangle.

#

And np.

tall dagger
#

Yes, I see where I made my first mistake at lmao

stray merlin
#

oωo

upper karma
#

Hey! Anybody got any suggestions on learning proofs in geo better?

unkempt jay
#

@upper karma are you in college?

upper karma
#

@unkempt jay no in 9th

unkempt jay
#

oh

upper karma
#

any suggestions?

silent plank
#

parallel lines, similarity and congruency?

upper karma
#

@silent plank yup D:

silent plank
#

they aren't on the same interior

#

you're looking for another word starting with C

upper karma
#

congruent?

silent plank
#

not that one

upper karma
#

thats what it said on the answer key

silent plank
#

they are congruent but why are they congruent

upper karma
#

they are on the same position of the transversal?

#

the top line and the middle like are parralel, and the vertical like all the way to the left is the transversal

silent plank
#

their is a word that describes their positions

upper karma
#

idk what it is if its not congruent

#

complementary?

silent plank
#

complementary means they add up to 90 degrees

upper karma
#

yea i dont think thats it

#

what is the word?

silent plank
#

are you familiar with all the follow terms:
vertical, corresponding, alternate interior, alternate exterior, consecutive, complementary, supplementary (angles) and possible more

upper karma
#

yes I am

silent plank
#

and which is the term that describes 8 and 11

upper karma
#

corresponding

#

omg i feel so stupid

#

i mixed up corresponding with congruent

#

🤦

exotic meteor
#

Any tip how I can calculate all angles with this cheat sheet?

weary drift
#

Look up how to determine “reference angles”

exotic meteor
#

I think I understood it

#

I just need to check if it will be positive or negative

#

Sin is positive from 0 to pi and cos is positive from -pi/2 to pi/2

wet ice
#

Emergency 🚨

silent plank
#

where are you stuck?

dark sparrow
#

@wet ice why is this an emergency

wet ice
#

Because it’s due in hour and I don’t have time to do it in other class

quiet mason
#

what do you have to do in these problems

#

tho

silent plank
#

best to state the issue you're having asap then

wet ice
#

#asap

quiet mason
#

uhm

wet ice
#

I couldn’t really pay attention well the other day that’s why I’m unsure what to do

#

And I am a good student

quiet mason
#

read the instrutions

wet ice
#

It’s sohcahtoa but

quiet mason
#

lol "good boy"

wet ice
#

I did I’m not good with understanding

quiet mason
#

ok wtf is sohcahtoa

#

leave that

wet ice
#

How we suppose to change it and -

#

..

quiet mason
#

do you know what are sines and cosines

wet ice
#

Oh idk people say it

#

Yes

#

Idk what’s on top thou like y/x or

quiet mason
#

in the first problem

wet ice
#

I’m bout to go my first period now

quiet mason
#

sine(angle)=opposite side / hypotenuse

#

got this?

#

ok come later then bye

wet ice
#

Yes

#

Sin is opp over hype? Ok

#

@quiet mason

quiet mason
#

yes

#

opposite mind you

#

cosine is adjacent side /hypotenuse

wet ice
#

Which letter are we trying to find on first one

#

@quiet mason

quiet mason
#

sin(36°20')=a/964 @wet ice

#

a=964*sin(36°20')

wet ice
#

We finding small a?

quiet mason
#

,w calculate sin(36°20')

#

yes

somber coyoteBOT
wet ice
quiet mason
#

big A is alread shown

#

as 36 deg 20 min

wet ice
#

Big A is 36 20

quiet mason
#

yea

wet ice
#

But how do we turn it or do we have to turn it to decimal

quiet mason
#

no

#

keep it as it is

#

36°20'

wet ice
#

Oh

quiet mason
#

so you undwdstood what i meant right

white cradle
#

also 60 minutes makes a degree

wet ice
#

It would be much easier if it was written out, texts seem to separate it

#

I know that

white cradle
#

ah kk

wet ice
#

60 min = 1 degree

#

;-;

white cradle
wet ice
#

Lol

#

Okay so big A is 36 20 and we keep it like that

quiet mason
#

yea

#

and pull up a calculator

wet ice
#

Is C 964

#

I have no calculator

#

But I have my phone

quiet mason
#

yes

#

phone calculator

white cradle
#

basically a calculator and so much more

wet ice
#

Lmao

quiet mason
#

and C cannot be 964

#

lol

wet ice
#

Oh

quiet mason
#

its an angle

wet ice
#

But it’s across it

#

.

#

Ok math is confusing

quiet mason
#

no

white cradle
#

oof no it's not

wet ice
#

Not for smart people like u guy

quiet mason
#

lol

#

stop

silent plank
#

capital letters generally represent angles
lowercase represent sides

wet ice
#

Sigh class start

quiet mason
#

and To talk about side with 964 m specify its bounds

#

like AB=964M

#

964m

#

got me?

#

yee ok after class ping

wet ice
#

AB??

quiet mason
#

see the diagram

silent plank
#

or lowercase c = 964m

wet ice
#

After class I’ll have trig

quiet mason
#

ok ping in class?

#

thats easy

wet ice
#

Ping?

#

Wym

quiet mason
#

@wet ice

white cradle
#

that's a ping

wet ice
#

Oh

#

Uh

#

But I can’t touch my phone

white cradle
#

cause when you do that, if notifs are on you get a ping

wet ice
#

I’m in English class rn

white cradle
#

rip then

wet ice
#

:((.

#

8 problems and I got none done

#

I hope I can secretly do it durin this class maybe not but fkk

#

Thanks guys

#

For your time

winter bison
#

What's the difference of co-functions and inverse functions 🤔

dark sparrow
#

"co-functions"?

winter bison
#

Cofunction

#

?

#

Of trigonometric function :3

sly marlin
#

you mean cosecant and cosine and cotangent?

#

Inverse functions are the map from ratio to angles
The other trigonometric functions are more maps from angle to ratio

#

@winter bison

#

If that's what you mean

winter bison
flint pelican
#

Guys how come one second he puts the angle after the line but

#

The next he puts the angle before

#

Is it because with sin you put angle after but with cos you do before or is it something else

sly marlin
#

It's angle between x axis and line

#

@flint pelican

flint pelican
#

🤯💀

#

Ty

nocturne musk
#

hi

#

can someone help me with this?

coral sapphire
#

@nocturne musk move to an unoccupied question channel and i will help you

nocturne musk
#

okay

#

which channel is that?

#

I figured out that one already but I have another one

coral sapphire
#

Look under the Math Help label on the sidebar and join an unoccupied (no one is talking) channel

#

All the channels are question-(some greek symbol)

quiet mason
#

wb k

wind heart
#

I kinda need help

#

How would I find x?

#

It’s a right angle

#

Oh I think the upside down T means perpendicular

somber coyoteBOT
wind heart
#

So 72x=8

#

x=9

#

Wait is it that easy?

#

would that be the answer?

#

oh lol I mean 72=8x*

#

Thanks

#

It was a lot easier than I thought it was

delicate laurel
upper karma
#

what is the difference between posulates and theorums

upper karma
#

Whats the easiest way to solve this

limpid basin
#

plot it on a graph

upper karma
#

what if you don't have a graph

#

like it was on a test

limpid basin
#

uh draw a graph?

#

or you can do it algebraically by finding the side lengths of AB, BC, and AC

upper karma
#

okay

#

thanks

sharp fern
#

does anyone know de moivre's theorem and nth roots

#

im struggling with it

weary drift
#

if there's a homework q related to this, just post it along with how you tried to solve it

sharp fern
#

no question, im just trying to learn it reading it from the textbook, but i cant seem to understand it

weary drift
#

@sharp fern part of learning involves practice, so perhaps find some example q's to try out

pastel lichen
lavish umbra
#

How can I get from AD-CD=CB-CD to AD=CB
Do i just add CD to both sides?

sly marlin
#

but you would get AD=CB

#

@lavish umbra

lavish umbra
#

Nope, just typed it wrong

#

So would that work?

sly marlin
#

yeah

#

probably

#

Are these vectors?

#

then yeah, you can

upper karma
#

assume a square has the side of pi. Will the perimeter be infinite or finite?

fringe dirge
#

What do you think?

upper karma
#

I think it's finite

#

but I have no idea

#

Or it could be fractal-like

fringe dirge
#

Are squares fractal-like?

upper karma
#

well, no, not inheritly

fringe dirge
#

If I give you a square of side length 3, what's the perimeter?

upper karma
#

12

#

right, I think I got the point

#

lol

fringe dirge
#

yeah just because pi is a weird number

#

It's still a finite number

upper karma
#

"A hang glider is observed from a field due East at an angle of elevation of 50degrees. The hang glider is 2km away from the observer at this field. The angle of elevation from a second field is 23 degrees. The second field is 3.5 km away from the first at a bearing of 155degrees. How high is the hang glider?"

#

5 dollars Canadian to whoever can solve this and show their work on paper.

coral sapphire
#

LOL bribing the Mathematics Discord

upper karma
#

it's not even for marks, my teacher couldn't even solve this. It's in the work I'm supposed to do he gave up on it. Another teacher created this math problem.

#

This is just a prize to see if it's able to get solved.

fringe dirge
#

Does the 2km in the second sentence mean actual distance

#

or just horizontal distance

coral sapphire
#

what is a bearing?

upper karma
#

@fringe dirge I just wrote the question as is, my guess is that it's the actual distance between the observer and hang glider, and not the horizontal distance. But I could be wrong.

fringe dirge
#

really either way, you only need the first two sentences, the rest is useless

coral sapphire
#

^, wondering why you need the second part too

upper karma
#

perhaps the question is flawed and can't be solved.

fringe dirge
#

No as in

#

the first part gives you your answer

upper karma
#

i used tan and the answer didn't match what's in the book

fringe dirge
#

It's possible the second part could contradict

#

Because that's not right

upper karma
#

i also used sin

fringe dirge
#

If you assume that it's the actual distance at least

upper karma
#

if you're able to get the answer of what's in the book to the nearest 10th degree ill give you the money

fringe dirge
#

What were the two answers that you got using sin/tan

upper karma
#

1.53 for Sin and 2.38 for Tan

coral sapphire
#

What does the bearing mean?

upper karma
#

bearing is direction

#

bearing north 180 degrees = south

#

180 degrees from north is south

coral sapphire
#

Alright I understand now

fringe dirge
#

Yeah both those answers are right

#

The answers in book are just wrong then

upper karma
#

every goddamn question he made is hard to understand

#

don't waste your time on it then it's not worth the money

#

if it's wrong

#

if you make a word problem for a question it has to be not open to interpretation

#

@fringe dirge if i find out from the teacher the question is wrong in the book ill send you the moneys lol

wind heart
#

Hello

#

Would a be considered a linear pair, and would c be considered neither?