geometry-and-trigonometry

[craggy glen]

Does anyone know how to prove this using vectors ?

[lime dune]

just assign appropriate coordinates and this is trivial

[upper karma]

When dividing by an expression we need to check whether that expression is 0 or not

[obsidian harness]

The centroid has both the x coordinates and y coordinates of (A + B + C)/3

Hence OX = (OA + OB + OC)/3

If X is the centroid and O is the origin

[inner vapor]

Yeah

[nocturne remnant]

You don’t need equilateral…

[inner vapor]

Why kpi/2 tho?

I understand pi/3 + 2kpi aswell as 5pi/3 + 2kpi where k is integer number

But i dont understand kpi/2 tho wtf

Not divide substract sin2x then factorize

Then factorize sin2x

And check when its 0

But i dont get why kpi/2

[dark sparrow]

sin(2x) = 0

at precisely those points

[inner vapor]

what??

,w sin(pi)

[somber coyote]

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[dark sparrow]

yes

pi radians is 180°

[inner vapor]

why kpi/2 doe

mmm

[dark sparrow]

sin(t)=0 <=> t = kπ

[inner vapor]

what about it

I agree.

[dark sparrow]

sin(2x)=0 <=> 2x = kπ

[inner vapor]

x = kpi/2

mmm

weird

[dark sparrow]

what's weird about it

[inner vapor]

nothing

I agree

its just hard to visualize

its hard to know if you are capturing all solutions or not

specifically this trigonometric equation we needed to find all x \in R

[dark sparrow]

imagine a sinusoid

like let's go back to the raw sine function

you know what it looks like right

[inner vapor]

what about it, usually oscillates over. 1 and -1

I know how it looks like

,w sin(x)

[dark sparrow]

look where it crosses the x-axis

first at x=0, then at x=pi, then again at x=2pi, and it continues like that bc it's periodic

[inner vapor]

pik

[obsidian harness]

How would you figure out that DA = DC?

[dark sparrow]

they are chords of equal arcs in the same circle

[obsidian harness]

Right let me go look that up

[dark sparrow]

#bots exists btw

[obsidian harness]

This is kind of magic to me

I can figure out the proof: if you mark the centre

Then AOC = 2x

[dark sparrow]

nope

[obsidian harness]

Oh right

Ok it comes from the inscribed angle theorem

[inner vapor]

I dont get why 5pi/3

[dark sparrow]

where

youre gonna have to bring us up to speed on the problem you're doing, sorry

[inner vapor]

basically

sin(2x) = 2sin(2x)cos(x)
0 = 2sin(2x)cos(x) - sin(2x)
0 = sin(2x)(2cos(x) - 1)

sin(2x) = 0
2x_1 = kpi
x_1 = kpi/2

(2cos(x) - 1) = 0
2cos(x) = 1
cos(x) = 1/2

this is cos

mmm

what to do ...

xd

x = 2kpi?

k is an integer

[lime dune]

no

[inner vapor]

its cos(pi/6) = 1/2

but which else?

[lime dune]

$x=\frac{\pi}{3}+2\pi k, \frac{5\pi}{3}+2\pi k$

[somber coyote]

elrichardo1337

[inner vapor]

I get the first

pi/3 + 2pik

but the second one how?

[dark sparrow]

cos(2pi - x) = cos(x)

[inner vapor]

I concluded., to the same formula

but shoudnt it be pi - x?

first solution is pi/3

my question is

why do we jump from the 1st quadrant to the 4th quadrant

[lime dune]

because... that's how cosine works?

the bottom half of the picture that seems to be cut out here should make it obvious

[inner vapor]

why 2pi - pi/3

so strange

no I get it now

may I ask another question?

[dark sparrow]

!da2a

[lime crown]

No need to ask “Can I ask…?” or “Does anyone know about…?”—it’s faster for everyone if you just ask your question! See https://dontasktoask.com/

[inner vapor]

cos(x + pi/4) = (sqrt(2)/2)(cosx - sinx)

how to find all x \in R

[dark sparrow]

do you mean "How do I prove that cos(x + π/4) = sqrt(2)/2 (cos(x) - sin(x)) for all real x?" @inner vapor

if so: angle sum formula for cosine.

[inner vapor]

prove?

I need to find all x \in R

which satisfy the equation

[dark sparrow]

my hint still stands

[inner vapor]

solution set is all reals

I think this might be my first proof

No idea what just happened

Why am I getting same stuff both sides

[dark sparrow]

cause it's true always lmfao

[inner vapor]

Why?

Thats weird

[dark sparrow]

what's weird about it

you applied the angle sum formula for cos

[novel scaffold]

how do you find period of tan(cos(x/2)/2)

the period of cos(x/2) would be 4pi

but now what

[dark sparrow]

well, the composition of anything with cos(x/2) would then have period 4pi or a unit fraction thereof.

[novel scaffold]

then what do you do with the /2 inside tan

[dark sparrow]

1/2 * cos(x/2) ranges between -1/2 and +1/2

tan is one to one on the interval [-1/2, 1/2]

so we won't get any smaller period

[tawny prawn]

A circle with the center lying on the hypotenuse of a rectangular triangle ABC touches the legs AC and BC at the points D and E, respectively, so that AD=3 cm and BE = 1cm Find the magnitude of the angle BAC.

Answer is 30

Degrees

How do we get to it any help?

I think this is how it looks

[obsidian harness]

Isn't this situation impossible

Hold on it is possible except C obviously can't be directly above the centre

[tawny prawn]

I figured it out

[obsidian harness]

Ah great

Btw how did you do it?

[upper karma]

Would this be the way to answer this?

[tawny prawn]

@dark sparrow helped me

Beo and ado are similar triangles

[upper karma]

I'm considering it would be BC ≈ EF

[obsidian harness]

Ahhhhh that's so much clearer

Yeah then it's easy if you realise that lol

[tawny prawn]

My bad bro

[obsidian harness]

No worries I totally missed it

[upper karma]

But it's also ASA and my friend told me that The side visually has to be between two angles

,rotate

[upper karma]

There

[obsidian harness]

Okok

Yes it is ASA

[upper karma]

I'm still new to geometry lmao

[upper karma]

Of course but I need the side that makes it ASA congurent

Congruent*

[obsidian harness]

Cause actually you just need another side for congruence
If you know two of the angles, then the other one is also determined (180 - x - y)

So options A, B, and D would all make the two triangles congruent

But they wouldn't be ASA congruent apart from D

[upper karma]

Yaya I got it right

[obsidian harness]

Haha no worries

[upper karma]

Now what the hell is this?

Would $\overline{EF} \cong \overline{FG}$

[somber coyote]

koyomi

[upper karma]

If so then $3n - 4 = n + 8$

[somber coyote]

koyomi

[upper karma]

But I'm not sure if that's how it would work and if EF is congruent to FG

[obsidian harness]

Yes EF and FG are equal

The two triangles are angle angle side congruent

angle (EDF = FDG), angle (DEF and FGD are both right angles), side (they both share DF)

[upper karma]

So then u can solve for n, plug it in to FG and solve, yes?

[obsidian harness]

Yes

[obsidian harness]

RHS (right angle, hypotenuse, and side) is a special version of angle angle side

Wait actually no

[upper karma]

That's awfully complicated

[obsidian harness]

It's based on SSS cause Pythagoras tells you the other side

[upper karma]

Well I got it, n=6, answer is D

[still apex]

There is a right angle that is 90 degrees

[obsidian harness]

Basically yeah I'm just telling you random facts that happen to be related

For this question you just need to understand that EF = FG
Then it's just algebra

[upper karma]

Should be the same for this other problem I got

Making it look so complicated for no reason lol

And I lose once again 😭

If triangle ADB is an is coles trainabgle, then I can treat ADC was one triangle, and try to solve for AD.

[obsidian harness]

btw it should be D = perpendicular bisector

A median of a triangle is a line that cuts a side in half

So DB cuts AC in half

That means AB = BC also

(The median of a set of data is the number that is halfway in between, you get the idea)

[uncut umbra]

DF is 86 right?

Half of 172

[silent plank]

no

[upper karma]

Oh I thought the angle from the top so I crossed out perpendicular bisected because it wasn't 90 degrees

Wasn't paying attention there was a right angle there

[uncut umbra]

What is it

[silent plank]

look up and apply
outside angles theorem for circle

[uncut umbra]

Wdym

I do 172 squared plus 44 squared?

[silent plank]

no

did you look up outside angles theorem for circle

there shouldn't be any squaring at all in anywhere of what you're looking up

[uncut umbra]

You need that to find ARC DF?

[silent plank]

yes

hence why i asked you to look it up/apply it

[inner vapor]

I wanted to ask

How to find inverse of a trig identity when its not restricted

[dark sparrow]

inverse of a trig identity?

[inner vapor]

Sorry

Trigonometric function

The thing is most videos I see talk about just one angle as an answer to sin^-1

[dark sparrow]

sin^-1 is a misnomer

[inner vapor]

They trick saying its restricted

[dark sparrow]

sin : R -> R is not injective thus not invertible

it does not have a true inverse

[inner vapor]

I know

But

[dark sparrow]

so there is no question of finding it

[inner vapor]

But

Recall this solution

[dark sparrow]

yeah

thats a countably infinite set of points

not one point as you would need to have for an inverse

[inner vapor]

Consider this problem

Sinx = 0

We do not need to find inverse but x in R

Which is infinitely many points

[dark sparrow]

yes

[inner vapor]

Oh

Its a different task

Sorry

Sin x = 0 is not sin^1(0) =x

Unless you only need one solution

[dark sparrow]

^-1

and as i said earlier

sin^-1 is a misnomer

you should be calling it arcsin and writing it like that

[inner vapor]

True

But if I do arcsin in calculator only one output doe

Not parametric

[dark sparrow]

yes, bc arcsin is the inverse of a restriction of sin.

[inner vapor]

How to calculate sin(x)= 1/2?

Its pi/6 and 5pi/6

But thats using unit circle

[dark sparrow]

yes

[inner vapor]

Xd is it possible without

[dark sparrow]

arcsin(1/2) and pi - arcsin(1/2)

[inner vapor]

Si get that

[dark sparrow]

those + 2k*pi generally

[inner vapor]

Yeah 360 spinning is the same

[dark sparrow]

any equation of the form sin(x)=a is solved in this manner

for a between -1 and 1

[inner vapor]

i mean you kinda need to know unit circle

[empty yew]

Sorry for the interruption!!!\
(A)What is the minimum and maximum values of $\sin\theta$ ?\(B)What is the minimum and maximum values of $\sin\theta$ ?

Someone please help what is the question is asking me!!!

[somber coyote]

KingDanger

[inner vapor]

Is it possible using soh cah toa?

[dark sparrow]

soh cah toa is for right triangle shit

[inner vapor]

Min of sin is -1 and max is 1

No?

For 2sinx max is 2 min is -2?

[empty yew]

Idk that's why I am asking

[inner vapor]

Sin oscillates between -1 and 1

. . .

,w plot sinx

[somber coyote]

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[empty yew]

For any values of degrees?

[inner vapor]

Yeah

It would change if 2sinx

Look thats -2 and 2

,w plot 2sinx

[somber coyote]

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[empty yew]

What is the range of the degrees for the sine and cosine?

[inner vapor]

[empty yew]

What's the answer how can we find it?

[inner vapor]

What?

[empty yew]

What is the information that is telling to us and what do you asked it?

The questions should be reversed(the second question is the first question)

Sorry for the inconveniences

[inner vapor]

What inconvenience?

[empty yew]

This

[inner vapor]

i just asked wolfram to plot 2sin(x)

[empty yew]

Is it y = 2sin(x)?

[inner vapor]

Yeah

Exactly

[empty yew]

What is the difference between the sinx and 2sinx?

In the graph

[inner vapor]

You asked minimum maximum

[empty yew]

Yes

[inner vapor]

Sin x oscillates between -1 and 1

2sinx between -2 and 2

[empty yew]

Oh I understood

[inner vapor]

,w plot f(x) = sinx

[somber coyote]

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[inner vapor]

No idea what happened there

Xdd

[empty yew]

This

[inner vapor]

Mmm

I believe between 0 and 360?

[empty yew]

Is it between 0° and 90°?

[inner vapor]

Not sure

[inner vapor]

Thats 0 and pi/2 maybe, not sure

[empty yew]

An right triangle can only have 0 and 90 as the utmost value.am i correct?

[inner vapor]

I mean

Right triangle mean one of the angles is 90

[empty yew]

Yes

The remaining angles is always between 0° and 90°.

If one of the angles is 0° or 90° it can't be a triangle anymore!!!

It's a straight line

What do we do?

[inner vapor]

No idea about that

Mmm

I will solve more problems

I have nothing to do

[empty yew]

Can't understand

[inner vapor]

Mmm

Im not sure whether you are talking about interior angles or angles of the arc

But

[empty yew]

Interior angles

[inner vapor]

Eitherway I only knew how to answer the minimum and maximum of sin

The other crap I am saying is bullcrap probably

[empty yew]

With this the degree limit is between 0° and 90°(not calculus)

[inner vapor]

Yeah

Because interior is 180, the sum of interio5t amgles

[empty yew]

Yes

[empty yew]

For sure is this right?

[inner vapor]

Yeah 90 and 45 45

i am not sure bro

[empty yew]

Mmm

[inner vapor]

Good luck with that

[empty yew]

,w plot cosx

[somber coyote]

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[empty yew]

Tysm

For your time

[inner vapor]

If maximum is referring to x coordinate there isnt a maximum

It goes up to infinity

[empty yew]

,w plot cos\infty

[somber coyote]

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[empty yew]

,w sin\infty

[somber coyote]

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[empty yew]

This is the limit(again not calculus)

Thank you

[inner vapor]

no idea wtf is going on

Imma go back studying analysis

[empty yew]

Mmm

[inner vapor]

Maximum and minimum is present in my test

But i havent studied

[empty yew]

You researched it here

🤣

[inner vapor]

I mean

,w maximum sin(x)

[somber coyote]

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[inner vapor]

Its saying

At 90 degrees maximum is 1

[empty yew]

Is didn't understand advanced stuff

Mm

[inner vapor]

2pin is the same as summing 360 or 0 or -360

Its spinning 360 you get same place

[inner vapor]

180/2 = 90

,w pi in degrees

[somber coyote]

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[inner vapor]

Its says n is integer

Pi/2 + 2npi

Replace n with -1, 0, 1, 2

Pi / 2 + 0 = pi/2
Pi/2 + 2pi = 180/2 +2*180 = 90 + 360

[empty yew]

Mmm

👍

[golden trout]

any idea on how to approach this problem?

[lime dune]

this is just pythagorean theorem

draw it

[golden trout]

oh my god

that's true

[lime dune]

yea

the general case involves law of cosines/law of sines

but when they're perpendicular it's super easy

[golden trout]

wait, hold on

if it's the pythagorean theorem

[golden trout]

are both things they ask me the same?

[lime dune]

yea

draw it out and the two resultants should have the same length

[golden trout]

yeah they do

the sum goes to the right and the substraction goes to the left

but in both cases the module should be the same

thanks

[lime dune]

npnp

[autumn pelican]

Can someone help me with this ferris wheel problem?

So I have watched a few videos, specifically on these problems, and this is my current attempt at it

A = 22-2/2 = 10
B = 2pi/b = 12- = pi/60
D = 22+2/2 = 12
And since it starts at the bottom, I reverse A

Answer: y = -10cos(pi/60 t) + 12

This seems like the answer to me and on the graph it seems to make sense, so what am I doing wrong?

Turns out I was right... except I converted 2m to 120seconds and I wasn't meant to

[loud yarrow]

someone pls tell me how to solve this

<@&286206848099549185>

PLsssssss

i have a exam 3 days later

im begging

[inner vapor]

!noping

[lime crown]

Please do not ping individual helpers unprompted.

[inner vapor]

!15mim

[lime crown]

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

[loud yarrow]

<@&286206848099549185>

[jagged wyvern]

Can someone tell me why √1 or 1 is incorrect for the radius? (I checked my answer earlier twice for √1 and 1, forgot to take a snapshot before big ideas math reloaded)

I did it both mathematically and visually from the graph. I only have 1 more try to check my answer on this, pls help

Nvm i got 3 i dont understand why it's 3 considering how short when i make a line

[trail tendon]

look at the units of the graph

the side of each unit square represents 3 units

(because two of them represent 6 units)

and this is for the x and y axis so yeh

[trail tendon]

you could zoom in and make a longer line 😂

its just that the units are smaller

[jagged wyvern]

Oh

Forget you saw any of this 😅

[lucid path]

HOW DO YOU GET THE PI BUTTON IM LITERALLY GOING INSANE

AND NO IM NOT DOING 3.14

[trail tendon]

done

[trail tendon]

bro i just remembered i saw all this

💀

[cunning lion]

for things in blue you press 2nd, then the button it's on. so in this case 2nd then ^

[jagged wyvern]

Oh someone already responded

My bad

[short monolith]

hello

I can't find my help thread is it gone? i never received any help

[trail tendon]

if u have a problem u can post it here prolly

[short monolith]

part B on this

[cunning lion]

#help-40 #help-25

[short monolith]

I have a feeling it's something simple I just don't know

[cunning lion]

you are currently occupying 2 help channels

[short monolith]

sorry about that it disappeared after I clicked away from it

[trail tendon]

am i trippin or is this calculus optimization

or am i trippin

prob im trippin lemme think 💀

[short monolith]

I haven't done trig in 20 years and my friend sent me this question trying to get help and it's bugging me that I can't figure it out

the first part wasn't that hard

[trail tendon]

oh wait

[short monolith]

it must be like a trick question right? 45 degree angle, seems like something obvious but i don't know

[trail tendon]

idk why i said optimization its not optimizing its just finding when the angle is 45 💀

i think you need a formula

hmm

[upper karma]

can someone help me with a simple problem i’m stuck

[short monolith]

arctangent(1.3/d) + arctangent(0.2/d) = 45° is all i could think but i don't know how to solve

[trail tendon]

yeah...

uhh

hmm

[short monolith]

I'm very much out of practice and I don't have her textbook so I can't see the lessons that go with it

[short monolith]

yeah I'm clueless, it supposed to be a high school equivalent question too

[trail tendon]

nah man idrk either 💀

[short monolith]

well...

[muted moat]

https://www.tiktok.com/t/ZPRwr3q12/

[inner vapor]

!redir

[lime crown]

This channel is only for on-topic discussion. Please take casual conversation to #discussion or #chill.

[swift light]

is this correct

[trail tendon]

what kind of math is that

isnt that calc 2

also if ur taking a test then idk

[swift light]

trig

parametric equation

[swift light]

not a test just teacher taking too long to asnwer

[trail tendon]

oh wait i'm dumb

yeah i think thats right

actually i havent had that in a while so im not 100% sure but

im pretty sure

[bronze wind]

can someone link an online calculator thats specifically made for trig functions?

[upper karma]

These first 2 questions are confusing

And yes I already know the bottom one

[dark sparrow]

what part confuses you?

[upper karma]

I have no idea where to even begin, I'm testing out of geometry and I got 2 packets, first one was easy, and now this one is difficult because all I remember from my self study was postulates

Like the ASA shit

And it tells me something about ratios

[dark sparrow]

https://youtu.be/YiFwvAFk-xs

[south gulch]

How do you do this

Help

[upper karma]

nice

[south gulch]

Howto do

[dark sparrow]

... the question seems not to be clearly stated

[south gulch]

I need

[upper karma]

I mean I got the bottom part down, cus of the vid some1 sent, but it hasn't mentioned anything about Trinangle similarities

,rotate

[abstract hatch]

the answer for the second question would be s = r√π yards

i guess they just want the most simplified answer

[finite nest]

Hey i have a question

This task

Translated its: A right-angled triangle, you know that: The length of the shortest side is 20. The difference between the lengths of the other two sides is 2. How long is the longest side in this triangle??

@somber coyote

,help

[somber coyote]

A brief description and guide on how to use me was sent to your DMs!
Please use ,list to see a list of all my commands, and ,help cmd to get detailed help on a command!

[finite nest]

,list

[somber coyote]

My commands!

Use ,ls to obtain a briefer listing, and use ,help <cmd>to view detailed help for a particular command, or ,help to view general help.

If you still have questions, talk to our friendly support team here.

Info

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Page 2/4

[abstract hatch]

is the answer 101?

[cloud yarrow]

a = 20, c - b = 2, a² + b² = c², try rewriting all variables in terms of one other variable and solving

[abstract hatch]

@finite nest whats the answer??

[subtle bramble]

PLEASE HELP ANYBODY

[subtle bramble]

can u help me

anybdoy

[abstract hatch]

yea one sec

im tryna read the question

[subtle bramble]

okay ty

[abstract hatch]

is it possible for a clearer image, im really sorry tho

[subtle bramble]

can we dm?

[abstract hatch]

yea sure

[tame flame]

Hi, there is any geometric figure with a finite amount of points?

[dark sparrow]

define "geometric figure"

[tame flame]

Mm a set of a points arranged in a determinated way?

[dark sparrow]

what does "arranged" and "determined way" mean?

i could give you this

which is a scattering of ten points

certainly 10 is a finite number

[tame flame]

Mm so, the points have to be through by lines, but it have to be a closed figure, isn't it?

[dark sparrow]

i don't understand what "through by lines" is supposed to mean.

!xy

[lime crown]

Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

[subtle bramble]

can anybody tell me the surface area

[dark sparrow]

!noans

[lime crown]

The purpose of this server is to help you learn, not to hand out answers. Do not ask someone to give you the answer directly.

[dark sparrow]

you've selected the net correctly. it is conveniently broken up into 5 faces, so you can (and should) calculate the area of each face and then add them all together @subtle bramble

[tame flame]

sorry, english is no my first language :(

[dark sparrow]

then what is your first language?

[tame flame]

spanish

[dark sparrow]

ok

can i see the problem in the original spanish

[subtle bramble]

im just looking for anwsers i dont understand how to use it

[dark sparrow]

!noans

[lime crown]

The purpose of this server is to help you learn, not to hand out answers. Do not ask someone to give you the answer directly.

[dark sparrow]

we do not give out answers here @subtle bramble

[dark sparrow]

...that says "no geometric figure has a finite number of points"?

oh alguna means some?

ok, but this still leaves open the question of

what is a "geometric figure" for our purposes

the question of "what counts as a geometric figure" is crucial

cause whatever definition we're going with, we could check my scattering of 10 points against it

[inner vapor]

OP should clarify the larger context of the problem

!xy

[lime crown]

Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

[junior condor]

Scenario: Writing a paper about math in nature, trying to research stuff about tessellations. What do I search in order to get some good info, and is there anything I should know before stepping into this?

[spark stag]

[ping dealt with]

[tribal raven]

https://media.discordapp.net/attachments/789276083907592222/1233199718696226846/IMG_2758.jpg?ex=662c3a3c&is=662ae8bc&hm=4bb145a72f100c097e3199102e1f90960af538f063927144faeb43859d08a18a&=&format=webp&width=895&height=671

i need help with 14 and 15 im cooked plezser

[past geyser]

I can help you with 15

first off, calculate the length of the square

secondly, calculate the area of the sector

third, calculate the area of one of the right angle triangles

[tribal raven]

THANK YOU SO MUCH

[past geyser]

np lil dawg

did you read what I wrote?

[tribal raven]

yes im working on it rn

[tribal raven]

how do i do this?

[past geyser]

well

it's a quarter of a circle

what's the area of a circle?

[tribal raven]

pi r^2?

[past geyser]

yes

so what's a quarter of a circle

[tribal raven]

the are divided by 4?

[past geyser]

what is "they"

tell me with a formula

[tribal raven]

pi r^2 divided by 4?

[past geyser]

yes

[trail tendon]

bro says lil every second you know hes like 13 💀

[past geyser]

I’m 13?

I call everyone lil dawg or lil bro

[trail tendon]

14....
you know that you have a kite. angle OBT is 90 degrees, angle OAT is 90 degrees, so angle T is 60 degrees. does that help at all?

[trail tendon]

why 😂

[past geyser]

It’s just goofy and silly

[trail tendon]

you bet 🤣

[tribal raven]

nono i got 14 thank you though

[trail tendon]

o alr 💀

[safe vault]

Hey could anyone help me with my 10th grade geometry?

I have a really weird request

[trail tendon]

no idea, post it and prob someone can

[safe vault]

Well I was hoping someone could sign into my Aleks account and do it for me

I don’t want help so much as I want it done or I’m in a serious amount of trouble

[trail tendon]

um

help is basically ur only option 💀

ppl arent gonna do it for u and giving ppl ur account to anything is bad idea...

i know u prob know but yeh

whats the problems though

[safe vault]

Honestly I don’t care anymore man. I just want it done 😦

[trail tendon]

ok

then whats the problems

gotta power thru 👍 😂

[safe vault]

All this stuff

I only need to get like 4 though before I can move on and hopefully get some easier problems for AI to do

[trail tendon]

what's your first problem

[trail tendon]

i don't mean to be that guy, but not actually learning the homework is probably a really bad idea in general 💀

[safe vault]

It’s fine. I understand

[trail tendon]

yeh

[safe vault]

I just don’t care anymore. I don’t want to do this

[trail tendon]

I know the feeling ☠️

[safe vault]

We can do this I guess

[trail tendon]

thats the spirit 😂

[safe vault]

If you’re gonna do it just do it. I don’t want an explanation. It’s just a waste of your time

And sorry if I seem angry or upset. These past few days have been absolutely awful.

[trail tendon]

😔

[trail tendon]

it's not actually that hard tho

i know ur probably burnt out

but

[safe vault]

:/

[trail tendon]

wait do you have a calculator

[safe vault]

Yea

Desmos

[trail tendon]

do you know the length of JK?

ye or nah

xD

[safe vault]

Nah

I’m sorry bro I don’t have all night

[trail tendon]

😔

JK is 17.16 because its the distance from J to K

does that make sense :l

[safe vault]

Oh

Yea

I’m stupid but not that stupid

[trail tendon]

XD yeh

so whats JL

[safe vault]

I’m trying to pull someone’s IP so I’m kinda focused on other stuff

[trail tendon]

ik ur prob just burnt out lol

[safe vault]

Mhm

[trail tendon]

LOL

[safe vault]

I wish my AI thing would work but it keeps getting it wrong

[trail tendon]

but u know JL?

[safe vault]

Mhm

[trail tendon]

so do u know how to do (a) XD

[safe vault]

I’m sorry bro I get you’re trying to help but I don’t need explanations man. I appreciate you but if you’re gonna solve it just solve it and tell what I need to know

I’m sorry man

[dark sparrow]

!noans

[lime crown]

The purpose of this server is to help you learn, not to hand out answers. Do not ask someone to give you the answer directly.

[dark sparrow]

!nogpt

[lime crown]

Please do not trust ChatGPT or similar AI tools for mathematical tasks, as they often generate output which "sounds correct" but has numerous factual or logical errors. Use of these AI tools to answer other people's help questions is strictly against server rules (see #rules).

[dark sparrow]

don't ping everyone.

it's disabled, but it is rude anyway.

anyway, i see you have the net of this thing in front of you (on the right)

do you see that the net is broken up into 5 shapes (3 rectangles, 2 triangles)? Y/N

@left fossil ?

oh

you have the N word in your bio.

[granite mortar]

im deleting the mod ping bcs the image is unnecessary now

[dark sparrow]

ok

[merry mulch]

What is the angle between pair of lines $x^2-2xycot\theta-y^2=0$ ?

is it 90?

[dark sparrow]

did you miss a 0 there

[merry mulch]

where?

[dark sparrow]

like did you mean x^2 - 2xy cot(θ) - y^2 = 0?

or did you drop the zero on purpose?

[merry mulch]

I missed it

[dark sparrow]

ok

[somber coyote]

Nischal

[dark sparrow]

factorize that quadratic into something of the form (x - ay)(x - by)

from that, get the slopes of the two lines in question

from that, find the angle between them

[merry mulch]

lemme try

[merry mulch]

How do I factorize?

I have done this in another way. Can you verify whether it is right or not?

I was correct. The answer is 90. I found the exact question on the web. Thank you

[shadow hedge]

Can someone explain to me a couple of things in trigonometry

for example what is x scale? I’ve asked something related to it to this server but everyone gave different answers. Someone said its period/4 while other person denied it. How do i find it?

Secondly, i asked another question here i dont exactly remember what the question was but the guy in the video had some equations in sine function and he made them equal to zero and found something but i dont know what he found or where he used that number like why did he do that

is this channel busy? I can ask it to available channels

[dark sparrow]

good question, what does "x scale" mean? where did you see that phrase?

[shadow hedge]

someone on this server told me they use this

[dark sparrow]

show the full context

[shadow hedge]

they divided the graph based on that

i cant bc it was a while ago

i am doing a review and everything is more complicated now idk

[dark sparrow]

well, your half-remembered conversation isn't much to go off of.

[shadow hedge]

okay the thing is i asked how to graph something

Then they told me to use x scale way

[dark sparrow]

"x scale way"??

[shadow hedge]

idk they said it

do u know whats an x scale method way or thing

[dark sparrow]

well we need to see exactly what was said to make sense of that

[shadow hedge]

They divided the graph with the number they found

[dark sparrow]

i personally am confused by the wording and i think there is something lost in transmission

[shadow hedge]

They said it helps graphing

but idk like whether i have to do that but like whats that in general

[dark sparrow]

are you really unable to send a screenshot of the conversation exactly as it went

cause again, this imprecision makes it impossible to make sense of anything

[shadow hedge]

this happened 2-3 weeks ago so unfortunately no

do u know whats x scale in general

[dark sparrow]

the only thing that this evokes for me is "x-axis scale", i.e. the ratio of units on the x-axis to the lengths that represent them on paper

and that is not specifically a trigonometric concept.

for example if you are drawing on graph paper then the most common scale would be 1 unit = 1 grid square on both axes.

when graphing trigonometric functions, it might make sense to run the x-axis with a different scale, such as making 1 grid square represent some fraction of pi

which fraction depends on both what function(s) you're graphing and how big physically you want the graph to be

[shadow hedge]

Alr uhm i asked 2 questions do u know the other one?

lets say sin (2x-3) dude tried making 2x-3 = 0

[dark sparrow]

your second question is even more vague than the first, so i can't answer

[shadow hedge]

okay

i dont think its this much complicated though anyways

i was just asking what do you do with the value of x when you make sin(3x+9) -> 3x+9 = 0 so x=-3. I saw someone do this but i did not understand where they used x=3 at

anyways never mind

[dark sparrow]

3x+9=0 does not become x=3, it becomes x=-3

[shadow hedge]

My mistake

[dark sparrow]

also it is not about complexity

it is about having the right context so i can give you an explanation that makes sense and meshes with said context

[shadow hedge]

okay anyways

[dark sparrow]

it sounds like you might be talking about finding x-intercepts

[shadow hedge]

I think i have the picture for the second question

Hold on

[dark sparrow]

mmm

[shadow hedge]

Do u see how he wrote x=-pi/2

whats that for

[dark sparrow]

dubious

[shadow hedge]

he then added it to other numbers

he added it to period i suppose

[past crown]

Can anyone help?

[dark sparrow]

!status

[lime crown]

What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above

[alpine star]

Anyone help? I cant find right angle triangle to find MF😕

[fallen vector]

hello, my friend needs help with their work

[alpine star]

!15mins

[lime crown]

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

[alpine star]

<@&286206848099549185>

[tawny bramble]

yes

[alpine star]

This how do i solve for MF

[tawny bramble]

Trignometry Question? can be soplved by ,me

[alpine star]

Ye im trying to find it length by finding its right angle im new to this topic

[surreal jewel]

Power of a point. Have u learned that

[fallen vector]

No

[surreal jewel]

For #1

9x = 18 * 10

U can prove this with similar triangles

[fallen vector]

Ah ok

[fallen vector]

For 2#, would it be 6x = 4 * 9 ?

[surreal jewel]

Yes

Lmk if u find out how to prove it

Its called PoP

Power of a point

[fallen vector]

Ahh thank youu

[fallen vector]

What about for q5?

[digital knot]

https://www.youtube.com/watch?v=KFV70dj5OMw&ab_channel=TheOrganicChemistryTutor

Maybe you should watch this

[surreal jewel]

Hmm the intersection point in outside

Take a guess

[alpine star]

Anyone help

[fallen vector]

Would it become a negative?

[surreal jewel]

Nope

[surreal jewel]

Watch this

Proly a better explanation

[fallen vector]

Thank you

[digital knot]

Connect FA

@alpine star and FAM is a right-angle triangle

[alpine star]

Ah thanks.Saved my life 🙏🙏

[upper karma]

What is a similarity statement

Like "These triangles are congruent through AA (Angle-Angle)"

Well nvm I got it

May someone tell me a way to do this? I thought this was in like full on trig!?

,rotate

[past geyser]

@upper karma do you know the formula for length of an arc?

and area of a sector?

[dark sparrow]

no, it's like "Triangles ABC and DEF are similar" only you have to keep careful track of the order in which you list each one's vertices

[past geyser]

ann in a rap battle between you and me who would win

sorry

nvm

[upper karma]

I do know arc is like S = r(theta)

But for my first answering got S = 22.340

(Approx)

[past geyser]

$\text{arc length} = \frac{\theta}{360^\circ}} \cdot 2\pi r$

i dunno how to do degrees in latex

[dark sparrow]

that's specifically the one for angles in degrees btw

[past geyser]

sorry no pi r^2

[dark sparrow]

^\circ

[past geyser]

2pi r

[dark sparrow]

idk, i am shit at rap of any kind

anyway

[upper karma]

Why's that?

[dark sparrow]

the point is

[somber coyote]

aguaman
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[dark sparrow]

oh ok so i have to say 2 diff things at once

[upper karma]

The vid I watched did NOT mention this

[dark sparrow]

ok wait

[past geyser]

this is just how I learned it

[upper karma]

It stated: multiply 160 by pi/180

[dark sparrow]

similarity thing first or arc shit first

pick one

[upper karma]

I got the similarity thing

Sorry

[dark sparrow]

ok right

[past geyser]

?

[dark sparrow]

so the vid probably talked about converting the angle into radians

do you know what a radian is

yes/no

[upper karma]

Unit circle stuff

[past geyser]

they don't need radians for this

[dark sparrow]

it is not specifically a "unit circle stuff"

[sick imp]

Yo

[dark sparrow]

the radian is a unit of angle

[upper karma]

Idk how to say it but I remember radian being a eqiv of an angle

[sick imp]

Help plz

[past geyser]

,rotate

[dark sparrow]

the radian is an angle unit.

https://images-ext-1.discordapp.net/external/Fe1CQso2IwAXkZmOc2V_yBIUGSaBNFBBn7DI4d5COXQ/https/upload.wikimedia.org/wikipedia/commons/4/4e/Circle_radians.gif

[sick imp]

I can show more of my working if you want

[dark sparrow]

specifically, there are 2pi radians to a full revolution. @upper karma

[past geyser]

ok first off,

[dark sparrow]

and one consequence of this is that the length of an arc is just L = r*θ if you measure your angles in radians

[past geyser]

you notice how 3 is a common factor of all of those terms?

[dark sparrow]

there is no pesky conversion constant in there

[past geyser]

@sick imp

[sick imp]

I tried that

Let me show all my working

[upper karma]

That's true, but would converting an angle into radian form be multiplying the angle (in this case 160) by pi/180?

[past geyser]

i'm telling you, you don't need to convert to radians to solve this question, it's in degrees so work with degrees

¯_(ツ)_/¯

[sick imp]

@past geyser

[past geyser]

but listen to Ann she's more experienced than me

[dark sparrow]

@upper karma your takeaway for your problem should be that the area and arc length of a circular sector are both proportional to its angle,

and so they make up the same fraction of the full circle's circumference as the angle makes out of 360° (a full turn)

[dark sparrow]

so for the 160° arc, it is equal to 160/360 of the circle's full circumference

etc.

[upper karma]

Well aguaman stated I can work with DEG without turning it into a radian yet I'm not sure what the length of the arc formula would be if we're to be working with a degree

I think one of you put it into latex form somewhere up

[upper karma]

Like this

[dark sparrow]

i just told you.

[upper karma]

I am stupid

[dark sparrow]

so for the 160° arc, it is equal to 160/360 of the circle's full circumference

also talking about turning the arc into "a radian" sounds about as silly as turning a length into "a mile" or "a foot" or "a meter"

[upper karma]

But that would be too easy

No shot it could be that

[dark sparrow]

fym too easy

[past geyser]

Occam's razor is a principle often attributed to. 14th–century friar William of Ockham that says that if you have two competing ideas to explain the same phenomenon, you should prefer the simpler one.

simplest answer is usually the best

[dark sparrow]

if you cut a circle in half what could POSSIBLY happen to each piece's area except for it to be half the whole thing

if you cut a perfectly circular pizza into 10 equal slices how much crust could each slice possibly have except 1/10 of the whole thing's crust?

[past geyser]

[upper karma]

I dunno how to explain but like it can't be that simple when I've struggled on the past couple of pages

[dark sparrow]

do you like actually refuse to believe me here

or is it simply stupefaction

[sick imp]

Did anyone get my question?

[dark sparrow]

sorry, you came at a bad time -- try #precalculus ?

[sick imp]

All good

[upper karma]

Yeah you're right

Well imma do this sector problem and just a recall A = 1/2(Theta)R²

(Find area)

[dark sparrow]

that's for when theta is in radians

yours isn't

it's not like... two utterly different solution paths, my idea vs the conversion-to-radians method. but in your case it is just easier to conceptualize this as "that fraction of the circle's area".

[upper karma]

So I can just divide theta by 360

[dark sparrow]

can you repost your question

so that i can see what angle you had there

and to hammer in the idea rather than an instruction

[upper karma]

You might need to run a ,rotate

,rotate

[upper karma]

145 degrees

[past geyser]

just do 160/360 times the formula for a sector

oh we doing area now

it's the same concept

[upper karma]

Yeah

[past geyser]

so... what's your solution?

[dark sparrow]

the area is 145/360 times the full circle area

[upper karma]

I can just do 145/360 like I did for the arc problem r8ght? (To replace theta

[past geyser]

yes

but you do not multiply by 2pi r

you need to do something else

do you know what?

[upper karma]

Mutiply by half

I think

[past geyser]

what

[upper karma]

I saw it in the equation for radians

[past geyser]

no

[upper karma]

I'm js assuming shit atp

[past geyser]

do not think about radians we are not working in radians here

[upper karma]

Oh

Alright

[past geyser]

you don't need to overcomplicate this

[dark sparrow]

which you are rn

you are overthinking and overcomplicating

[upper karma]

Yeah I can tell

[dark sparrow]

are you on a deadline

[past geyser]

if you want to calculate a quarter of a circle what do you do?

[upper karma]

May 14th

[past geyser]

you have plenty of time lmao

[upper karma]

Multiply the area by 1/4

[past geyser]

yes

if you want to do half a circle what do you want to do?

[upper karma]

I know but all of geometry in less than a month LMAO

[upper karma]

1/2

[past geyser]

yes

but in this case we are doing 145/360 of a circle

[upper karma]

So for this it's 145/360 (or a simple fraction)

[past geyser]

so what do you do?

yes

so what's your formula?

[upper karma]

Times it by pir²

[past geyser]

yes

what is the radius?

[sick imp]

I’m so confused on how to get help

[upper karma]

Theta/360(pi)(18)²

[past geyser]

i'll try to help you afterwards gimme a moment

[past geyser]

yeah but what is theta???

[upper karma]

145

[past geyser]

ok

so plug it in

that's your answer

[upper karma]

I'm stupid but not dumb 💀

[past geyser]

tf does this mean

[sick imp]

Alr thx I’m in help#9

[past geyser]

@sick imp go to #precalculus

i'll help you there

[upper karma]

I really don't know

I've been staying up learning some geometry shit so I can test out of it this year and skip to AP Precalc

Bit I believe my stupidity is NOT gonna let me pass

[past geyser]

lil dawg you gotta stop talking down to yourself

that ain't helping shit mf

😭

[upper karma]

I'm an honest person

[past geyser]

repeat after me lil shnawg

I am smart, I am not stupid, I am great

[dark sparrow]

there is a difference between honesty and self flagellation

[upper karma]

On a real note I do feel kind of screwed for this geometry test out

I got over semester 1 of geometry in one day buy this semester 2 stuff is like genuinely making me struggle

FYI semester one was all about comm9n sense geometry, no proofs?..

,rotate

[upper karma]

The questions ask us if an alleged segment of a alleged right triangle is tangent to the circle

I think I got it by checking Pythagoras theory stuff on the triangle and know that a triangle is a right triangle if both sides equal each other when a² +b² = c²

So for the first one a²+b²>c²

So that means it is not a right angle so it isn't tangent

But for question 2 I am confused, I am only given 10.2 and 6.8, 6.8 is the distance from the surface of the circle to the end of segment AB

[dark sparrow]

ok so

general tip

when you see a point on a diagram that seems relevant (like it's the intersection point of two objects or some point of tangency or sth like that)

give it a name

in this case, there's two points in need of a name

[upper karma]

I believe my overthinking got to me

[dark sparrow]

the center, which it is a good idea to call O bc that's a common name for the center of a circle

and the intersection point of OB with the circle, which you might call C perhaps

then you can at least talk about the segment OC

[upper karma]

Okay so what I over thaight about was if Segemnt BA was not tangent to the Circle, then would 10.2 be the radius of the circle

I fear that the line AO would be a little longer or shorter but it is not shown the diagram

[dark sparrow]

?

A is still on the circle and we can accept that O is the center, yes?

[upper karma]

Yeah

Would point A be an intersection point?

Well obviously it goes through the circle

[dark sparrow]

??

it sounds like you overthought or didnt read my earlier tip

or perhaps i was not clear enough

[upper karma]

Yeah I did overthink

[dark sparrow]

i intended for that tip to apply to points that don't already have names

the idea i was trying to get across was, better to have too many names than too few.

and if there's a point that looks notable, you should name it.

[upper karma]

So I figured out BC + CO is = 17

If I added the radius of the circle

To 6.8

I get 17, then profe the triangle us right with Pythagoras therom

So I was right

Using Pythagoras theorm, I proved that the triangle is a right triangle, which makes segment AB tangent to the Circle

Yeah now this is rlly ez

Ty for the help Lann? Or Ann, I dunno

[rugged shuttle]

why does this (polar) graph go through (0,0)?

if theta=0 r=-1, if r=0 theta=pi/3

[cunning lion]

r = 0 is the origin regardless of the angle

[rugged shuttle]

oh i see

if a<b or a=b, then the graph touches the pole, if a>b, then theta is undefined and the graph doesnt touch the pole

[upper karma]

I really don't get how to do these 2 problems

I haven't tried anything because I honestly don't know where to start

But I do know RTT and 2TT

[dark sparrow]

care to decipher those acronyms for those unfamiliar?

[upper karma]

I thought they were universesal my fault. Radius Tangent Theorm and Two-Tangent Theorem

Also I noticed that I have quadlatietal

[dark sparrow]

two tangent theorem is the one that states tangent segments from the same point to the same circle are equal, right

[upper karma]

Yup

[dark sparrow]

anyway: what do the angles in a quadrilateral add up to?

[upper karma]

360

[dark sparrow]

right

and you know the angle between a tangent and its corresponding radius is 90°, so...

[upper karma]

So I have 3 known anglez

[dark sparrow]

indeed, and so the fourth is easy

[upper karma]

So 360-(180+128)=?

[dark sparrow]

yes

[upper karma]

Well now the 2nd problems 😭

I could add up the sides but I only have an unknown portion of some sides

I'll list these as x and y

[whole holly]

I am a senior in high school. My math foundation is not bad, I need an online course (udemy etc.) Do you have any advice?

[rugged shuttle]

what do u want to learn

[whole holly]

Algebra

[upper karma]

I believe that I must use my theorems

[whole holly]

I want to go deep

[upper karma]

How deep?

There Algrebra I and II

Which is really important when ur going up higher in math

[whole holly]

at high school level

What is the difference between I and II

[upper karma]

I contains things like simple radicals and exponetials, II contains radicals with variables, absolute value graphs, log and ln functions, exponential and radical forms, etc.

[whole holly]

Both are necessary

[upper karma]

Indeed

[primal jasper]

I’ve always liked practicing with text books

[upper karma]

Well I wish I had a textbook

They seem so useful

[primal jasper]

I do like hard copy’s wayyy better, but you can find online pdfs of them for free

[upper karma]

Would it be safe to assume T is the midpoint between XY

Because TY = 3, then XY = 6

[primal jasper]

Yes it would be the midpoint

[upper karma]

OKay thank uuu

[primal jasper]

I could find some online ones for you if you’d like! Just tell me for which subject

[upper karma]

Honestly geometry stuff

I'm looking to test out of geometry to take AP precancerous next year and boost myself into Calc year after