#geometry-and-trigonometry

1 messages · Page 47 of 1

faint comet
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Yes I was, thank you

dark sparrow
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fair but you also didn't edit your msg as i asked

granite mortar
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who is gone, seems they joined just for this ???

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weird but wtv

dark sparrow
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yeah idk

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their discord account was 5 days old

finite basin
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Y’all what is geometry about

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Taking it next year

dark sparrow
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very loosely

empty yew
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How to represent $y > x^2$ in graph?
I don't know where to begin!

somber coyoteBOT
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KingDanger

empty yew
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Anyone pls help

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<@&286206848099549185> please anyone help me

upper karma
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graph x^2 as broken lines and then shade the upper part

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Everything above the graph is greater and everything below is less than.

empty yew
empty yew
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Is it like graphing y = x²?

upper karma
empty yew
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And shading the above region

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@upper karma is it correct?

upper karma
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yes

empty yew
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The every area other than this is y < x²

upper karma
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less than or equal to

empty yew
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Ohh thank you @upper karma

upper karma
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np

zinc reef
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@tiny finch

tiny finch
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@zinc reef

zinc reef
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Yes

tiny finch
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why did yu ping me?

zinc reef
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Did you need help with the Ramunjan Serie 1+2+3+4 etc = - 1 over Infinity

tiny finch
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No, i need help with vectors

zinc reef
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Oh

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Well

tiny finch
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...

zinc reef
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I can help you

tiny finch
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Ok

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Thx

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Hve u read the question

zinc reef
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I'm a thirteen year old prodigy in highschool, so I can help you

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No, I didn't read the question

tiny finch
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Its a geometry question so i think you can

zinc reef
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Yeah, I study pre university math

tiny finch
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Given a plane in space, the steepest directiom on the plane is the vector that makes the largest angle with x-y plane.

zinc reef
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Okay

tiny finch
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exoress this vector in terms of the normal n to the plane P

zinc reef
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Okay

tiny finch
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??

zinc reef
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Pressure

tiny finch
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Ok bye

zinc reef
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What do you mean

tiny finch
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i am going to find help on reddit

zinc reef
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Why

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Fine

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I'll help you for real

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I

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I'm sorry

tiny finch
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Ok

zinc reef
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So, basically Write the vector, parametric, and symmetric equations of a line through a given point in a given direction, and a line through two given points.
Find the distance from a point to a given line.
Write the vector and scalar equations of a plane through a given point with a given normal.
Find the distance from a point to a given plane.
Find the angle between two planes.

tiny finch
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Do you know about cross products?

zinc reef
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Yes

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@tiny finch

tiny finch
zinc reef
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Okay, but I gave you a different solution

dark sparrow
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you didn't

tiny finch
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if w points in the steepest direction, it perpendicular to some vector, hence you can find w using cross product.

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Hi @dark sparrow

dark sparrow
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actually wait

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can you restate the problem

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cause i'm a little confused from this convo

tiny finch
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Problem 3
For any plane P which is not parallel to the x-y plane, define the steepest direction
on P to be the direction of any vector which lies in P and which makes the largest
(acute) angle with the x-y plane.
a) Let P be the plane through the origin with normal vector n. Derive a formula, in
terms of n, for a vector w which points in the steepest direction on P

dark sparrow
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ok, and your progress if any?

tiny finch
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if w points in the steepest direction, it perpendicular to some vector, w is also perpendicular to n because it is in the plane. hence you can find w using cross product. w = n × v

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i cant find v

dark sparrow
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ok right so you have the right idea

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the intermediate vector you called v needs to:

  • lie in the xy plane
  • lie in P
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i.e. it needs to be perp to both n (the normal of P) and the normal of the xy plane

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can you say what the normal of the xy plane is?

tiny finch
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because w is also perpendicular to n

tiny finch
dark sparrow
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yes

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heres my idea

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n is shown in red, and your target w is shown in blue

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the intermediate vector in the calculation, which you called v (or so i thought), is green

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blue and green are perpendicular to each other and lie in P

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and green is also in the xy plane bc it is horizontal

tiny finch
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i can see v

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but i dont know what it is

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can you generate another image

dark sparrow
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well, as i said, it needs to satisfy two properties:

  • v lies in P (grey plane) <=> v is perp to n (red)
  • v lies in the xy plane <=> v is perp to k
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here is the same setup from a different angle if you want, but i don't see much of a point.

dark sparrow
tiny finch
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ok

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i think i know

empty yew
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<@&286206848099549185> Does the line for the equation 3x-4y=12 correct?

Anyone ensure is this correct or not?(If not could you please explain?)

primal ibex
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Yeah it’s correct

devout raft
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ABC is a triangle, |AE|=5 cm, |AC|=8 cm, m(CAD)=50° and m(BDE) given as 25°.
According to those info how tall is |BE| in cm?

dark sparrow
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is anything else given except what's marked on the picture?

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@devout raft

regal phoenix
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assuming AD is the height of the triangle, it should make an angle of 90° on point D. you can find m(ADE) by subtracting both 25 and 90 from 180, and because it’s an isosceles triangle, it has the same value of m(AED)

devout raft
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No its all given

dark sparrow
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so then, we don't know that angle ADC is 90°?

devout raft
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Yeah we dont know if it is or not totaly

dark sparrow
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then i think there isnt enough info.

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or maybe... hold on

devout raft
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I m trying to search for its video resolving on the net

kind cairn
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can anyone recommend any books on conics in euclidean geometry?

devout raft
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Guys i solved the question

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Wait a sec

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For who wonders

dark sparrow
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wait, how do we know AB = AC?

rose raven
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yo gang

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nevermind

lucid shuttle
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Hello! Given two points, let's say A(2,1,-1) and B(-3,0,2), how can i determine the equation of the bundle of planes passing through these two points?

proud nest
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how do i simplify this so that there is no sqrt symbol in the denominator

rugged shuttle
proud nest
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ngl idk but I figured it out somehow 😂

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you multiply the sqrt to both sides

trail tendon
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sqrt(1) = 1 lol

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and

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1/2 / 1 = 1/2

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anything divided by 1 is itself

proud nest
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yep lol

proud nest
trail tendon
proud nest
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I had already gotten the question wrong at that point so I was just trying to figure it out for the future

random dawn
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can i express tan²x as sin²x/cos²x

upper karma
random dawn
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awesome thanks

upper karma
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Only when cos(x) isn’t equal to 0 though

random dawn
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that’s information i don’t rly have but im just gonna assume it isn’t and deal w the consequences later

random dawn
# upper karma Yes

if i have (sin²x-4)/cosx can i express it as two separate fractions?
sin²x/cosx - 4/cosx

then can i express that as
tanx • sinx - 4/cosx
?

random dawn
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ok yeah im lost on this problem LMAO im gonna go open a help channel i think 💀

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this is the first time i see them all occupied 😭😭😭😭

cunning lion
upper karma
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Oh yeah

maiden brook
cunning lion
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like any trig identity, it's true as long as both sides are defined

maiden brook
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it is seen more as a definition but it’s wrong

pliant brook
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Triangle woke

cunning lion
empty yew
somber coyoteBOT
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KingDanger

empty yew
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<@&286206848099549185> anyone help me

empty yew
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Anyone help me 😭

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@dark sparrow sorry for the ping!!!😔 could you please check my answer correct or not?

dark sparrow
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in your question you should replace the word "does" with "is"

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otherwise seems approximately correct

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idk why it passes through (-1, -2) though

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,calc sqrt(2) * (-1) - sqrt(3) * (-2)

somber coyoteBOT
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Result:

2.0498880527647
dark sparrow
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not far off i guess

neon wagon
dark sparrow
neon wagon
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This is exam practice for next Thursday

neon wagon
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How would i check an inverse functions answer by composing the original model with the inverse i found

ruby compass
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Hi there, I'm studying Birkhoff axioms for plane geometry and I can't really wrap my mind around the measurement axiom... In particular, I don't understand how should I interpret negative angles according to this description (or what it means for two angles to be the negative of one another)

ruby compass
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nah there's no way Im this dumb

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sorry for wasting your time

zealous pike
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How can I draw the translation of a line segment?

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This way?

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HELP

obtuse geode
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hi everyone, can you help me? how use the rule "Horse" in trigonometry?

dark sparrow
dark sparrow
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ok then my earlier feedback stands

dark sparrow
obtuse geode
dark sparrow
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да ну?

obtuse geode
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ты из россии?

dark sparrow
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я и по-русски такого правила не знаю...

dark sparrow
obtuse geode
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ахахахах

dark sparrow
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так что это за правило

obtuse geode
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а тут спамить сообщениями можно?

dark sparrow
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в смысле спамить?

obtuse geode
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ну общаться

dark sparrow
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если длиннопост, то пожалуйста

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а спамить при этом зачем?

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brb

obtuse geode
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ну короче, я ща в колледже, скоро экзы и как-то надо готовиться постепенно, а я тригонометрию не знаю вообще, если кратко то там типа лошадь чет делает и кос на син меняется, что скажешь?

dark sparrow
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хоспаде

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вот это конечно напридумывают люди

obtuse geode
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да я сам вахуе

dark sparrow
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ну и не еби себе мозг тогда непонятными мнемониками, а вникай в суть. на том же ютубе сто пудов есть видео, объясняющие, что такое тригонометрическая окружность, как ею пользоваться и т.д.

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выучи разве что формулы $\cos(x+y) = \cos(x)\cos(y) - \sin(x)\sin(y)$ и $\sin(x+y) = \sin(x)\cos(y) + \cos(x)\sin(y)$

somber coyoteBOT
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|Ann⟩

dark sparrow
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я тебе, конечно, прямо так вообще всю тригонометрию не объясню

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могу тебе скинуть список тригонометрических формул собственного сочинения. я правда его сделала несколько лет назад и на английском. и еще я туда несколько совсем выпендрежных формул туда впихнула (параграф 6)

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и там еще нет таблицы значений тригонометрических функций

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если ты, как сказал ты сам, совсем не знаешь тригонометрию, то такая таблица мб хоть немного да поможет

dark sparrow
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pay it no mind

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it is a very stupid mnemonic

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that i think would take more effort to remember than the thing it's supposed to help you with. lmao

upper karma
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Lol

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Nah i guess this might be interesting though, right?

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Like there is literally a horse.

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And a graph is drawn on it

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Imma look into this

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The function doesn't change sides?

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Interesting.

upper karma
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Nvm.... This actually isn't interesting.

obtuse geode
# upper karma The function doesn't change sides?

The rule of the horse in trigonometry says:

If you postpone the angle from the vertical axis, the horse says "yes" and nods, moving his head along the vertical axis. Then the value of the original function changes to a cofunction — a function opposite to this one. For example, for a sine, the cosine is a cofunction.

If you postpone the angle from the horizontal axis, the horse says "no" and shakes his head, leading along the horizontal axis. Then the function does not change.

Applying the horse rule, it is necessary to determine the sign of the new function from X. Its sign coincides with the sign of the original function.

obtuse geode
upper karma
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Not very polite.

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I didn't like this math

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2/10.

obtuse geode
dark sparrow
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конкретнее не скажу

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но заканчивала я матмех

obtuse geode
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а, ну понял, ты сейчас на высшей ступени образовании?

dark sparrow
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магистратура

obtuse geode
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капец, удачи тебе

dark sparrow
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спасибо

surreal escarp
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Is the arc length equal to the angle opposite of it?

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Cuz then maybe 16) is 34, idk I need help with this

dark sparrow
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no

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inscribed angle theorem

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an angle inscribed in a circle equals half of its arc

surreal escarp
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So would 15) be half of 190 and 16) be half of 34?

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Or actually double 34 sorry for 16

dark sparrow
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double 34 that's right

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and yes you are correct for 15)

dull pilot
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whats this process called

upper karma
exotic gorge
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I made my math teacher into a t sh8rt

maiden brook
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nvm

maiden brook
dull pilot
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3d to 2d projection

fierce magnet
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Greetings

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I am a sci-fi writer and I am trying to calculate/estimate the size of the Virgo Supercluster if it was a sphere that consisted of equidistant Hexagons of 400 thousand kilometers for each side and an area of 415.692 billion square kilometers.

trail tendon
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you sound like you're from another planet

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🤣

fierce magnet
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The main problem I have got is that square roots do not convince me

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Shouldn´t I use "a root of 6" to search for the area of a sphere that consists of hexagons?

fierce magnet
fierce magnet
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The Virgo Supercluster is about 110 million light years in diameter, while its radius is of 55 million

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And I could get with that information, the circumference of the Supercluster

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The problem is that this is not a circle, but a sphere

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And not any sphere; A hollowed sphere

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I want to get the scale of the "surface" of this sphere

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And I thought that by doing the square root of its circumference I managed to do it.

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But I realized that I cannot do that because it consists of standarized Hexagons

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Anyways, a light year consists of 9.461E+12 kilometers

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I could divide that by 400000 and get the amount of planets that would fit in straight line and then calculate its square root

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But oh

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The same problem reappears

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Square root has not the shape of a Hexagon

trail tendon
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but the hexagons are equidistant (so the same size)?

trail tendon
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and you want the maximum amount of hexagons i'm assuming?

fierce magnet
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Yep

trail tendon
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hmm

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there's probably an area of a hexagon

fierce magnet
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Yeah i got it

trail tendon
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if you have the side length you could probably calculate the area of one

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i kind of see an optimization problem coming

fierce magnet
fierce magnet
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Or at least what the power of two gives me

trail tendon
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my only problem is i don't know the behavior at the edges when it gets close to the edge of the circle

fierce magnet
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Oh that is not the problem

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The problem is that the area is determined number by the SQUARE

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And it´s a hexagon

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I don´t know if I am breaking math, but I don´t think Squares is what I am searching for

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What if I want to make a Hexagon out of Hexagons?

trail tendon
#

what "volume" formula did you use for the hexagon?

fierce magnet
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There is no volume

trail tendon
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i mean

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area in three dimension is basically volume

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it's not like you're looking for surface area

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rihgt

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OH

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u mean theres no volume formula for a hexagon?

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3d hexagon i mean

fierce magnet
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I AM looking for surface area

trail tendon
fierce magnet
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The Sphere is hollow

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No volume therefore

trail tendon
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oh

fierce magnet
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There are no inner hexagons inside it

trail tendon
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you want the surface area size

fierce magnet
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They would be Truncated Icosahedrons

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And they suck because they also add Pentagons

fierce magnet
trail tendon
#

then uh

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its the area of a 2d hexagon times 6 right?

fierce magnet
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Uh

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Times 6?

trail tendon
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because your 3d hexagon would have 6 sides, wouldn't it?

fierce magnet
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Uh

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No

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I don´t even want a 3d hexagon, but a sphere

fierce magnet
trail tendon
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...

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you add the area of the surfaces

fierce magnet
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To calculate the area i did the perimeter multiplied by the apotema

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And then divided it by 2

fierce magnet
fierce magnet
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I would require that for the 3d Sphere

trail tendon
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are you using a 3d hexagon to estimate the surface area of a sphere?

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i'm confused lol

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what's your big goal

fierce magnet
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Like a cube with 6 squares except it is big enough to fill a universe

trail tendon
trail tendon
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in 3d

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lol

fierce magnet
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I don´t know him

trail tendon
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oh ok

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but uh

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hmm

fierce magnet
trail tendon
fierce magnet
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The side powered by the square

trail tendon
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what do you mean

fierce magnet
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For the individual Hexagons that is ok, it just allows to give me the Area in square kilometers

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But if i want to form a higher structure with those Hexagons

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Shouldn´t I be doing it by the Hex?

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Because there are 6 sides, not 4

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And therefore the Area of a bigger structure wouldn´t have (?) by the square

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That is the problem that is making my mind go insane

trail tendon
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i'm not sure i understand what you mean lol

fierce magnet
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Squares are not Hexagons right?

trail tendon
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right

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this doesnt have anything to do with sqrt(6) or s^2, does it

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from the pictur

fierce magnet
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Oh no not at all

trail tendon
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ok

fierce magnet
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Hold on lemme search something

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You see this?

trail tendon
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yes

fierce magnet
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That´s basically how the sphere consists of

trail tendon
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at some point it ends though right

fierce magnet
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Multiple Hexagons together

trail tendon
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and then there are small gaps

fierce magnet
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What do you mean by gaps?

fierce magnet
trail tendon
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sorry for my poor drawing but uh

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if the hexagons were inscribed in a circle

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there would be gaps

trail tendon
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i thought they were inside a circle

fierce magnet
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It is a Sphere

trail tendon
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well a sphere

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but the same thing still applies, just in 3 dimensin

fierce magnet
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Ah

trail tendon
#

there would be gaps

fierce magnet
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I never thought about it

trail tendon
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because no matter how many hexagons you have you're never gonna get exactly a circle

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oh lol

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you can get smaller hexagons though to get even closer to the area of a circle

fierce magnet
trail tendon
#

thats kinda what reimann sum about, except with rectangles

trail tendon
#

i thought you were trying to find when the farthest out points hit the circle

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sphere sorry

fierce magnet
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I thought i would avoid it because Hexagons are the best polygons to fill spaces

trail tendon
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oh XD

fierce magnet
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They just have the best structure

trail tendon
#

really?

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i mean i would say wouldnt it depend

fierce magnet
#

Why do you think it is common in nature?

trail tendon
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on the space that you're trying to fill

trail tendon
#

nah but uhh

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i guess yeah

fierce magnet
#

Saturn´s storm is literally a Hexagon

trail tendon
trail tendon
fierce magnet
trail tendon
#

thats like how the fibbinacci sequences is randomly in pine cones or smthn

trail tendon
fierce magnet
#

Which is also the reason why the planets are exactly 400 thousand kilometers from each other

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So that their forces do not make them crush

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Equidistant, forming regular Hexagons

trail tendon
#

i would bet that circles would even be more common but they're also kind of irrational so its hard to use them sometimes 💀

trail tendon
#

why hexagons though

fierce magnet
trail tendon
#

why not, say, octogons

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lol

fierce magnet
trail tendon
fierce magnet
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I could have used squares, but they are not as good

trail tendon
#

i mean if you inscribe an octogon in a circle it would leave less space than if you inscribe a hexagon into a circle

fierce magnet
trail tendon
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i see

fierce magnet
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But we´re leaving by the branches

trail tendon
#

wdym

fierce magnet
#

We went far from the original topic

trail tendon
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oh yeah 😭 🤣

fierce magnet
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About the Area of the Sphere

trail tendon
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why don't you just calculate the area of a sphere without estimating?

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like

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the volume

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or surface area, whichever you need

fierce magnet
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Because the problem is inside the formula of Area

trail tendon
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huh?

fierce magnet
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Area basically consists of multiple little squares inside a bigger structure

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And that´s not what i want

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I want Hexagons

trail tendon
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oh

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i mean

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i guess you could just see it as an optimization problem

fierce magnet
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And there are even more problems because if I do it by 6 I am basically making a Sphere of 6 dimensions

trail tendon
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i don't know how to explain what i mean

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let me try to draw

fierce magnet
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And yes, the first option

trail tendon
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oh ok

fierce magnet
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But not in volume

trail tendon
#

it seems that you could use either volume or surface area to do that

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why not?

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it doesn't have to actually have mass for you to calculate it in that way

fierce magnet
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Because i would have to put planets inside it

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Where there is a black hole

trail tendon
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lol but like

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the volume of an empty cube container can be calculated with the length of a side

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it doesn't have to be full to be a volume

fierce magnet
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What matters is the "side" of the circle, the "Crust" of the sphere

trail tendon
#

and you're only using the volume to compare to the volume of the circle

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surface area would be way more complicated than volume

fierce magnet
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I am basically searching for its perimeter

trail tendon
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and i think you could just use volume to compare to the volume of the circle to find the maximum amount of hexagons

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whether you have stuff in the hexagons or not

fierce magnet
trail tendon
#

basically perimeter but in 3 dimensions

fierce magnet
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Nice

trail tendon
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like where you take the area of all the surfaces and add them

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nah but like

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how long was the side of each hexagon did you say?

fierce magnet
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400 thousand kilometers

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I have its area

trail tendon
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ooh just realized i don't know how to find the volume

fierce magnet
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In SQUARE kilometers

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I hate squares so much dude

trail tendon
#

wait

trail tendon
fierce magnet
trail tendon
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wait my bad

fierce magnet
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Not a Truncated Icosahedron

trail tendon
#

you're doing surface area

trail tendon
fierce magnet
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For the Sphere

fierce magnet
trail tendon
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wait

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but in 3d

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hold up

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yeah

fierce magnet
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3d does not matter

trail tendon
#

you only have to worry about the outer half of the hexagon

trail tendon
fierce magnet
#

They are 2d hexagons forming a 3d Sphere

trail tendon
#

so 3 2d hexagons per 3d hexagon

fierce magnet
trail tendon
fierce magnet
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Yeah

trail tendon
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ok

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so

fierce magnet
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I want to make a hexagon the size of a light year

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Made of other hexagons

trail tendon
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this is the surface of each 2d hexagon, there would be 3 2d hexagons for each 3d hexagon.
lets just say n is the number of hexagons
so n * 3 * this < surface area of circle

#

so you could divide the surface area of your circle by 3 * this

#

to get the number of hexagons

fierce magnet
#

Oh yeah that is the Area i got

trail tendon
#

so you have to multiply by 3 for each hexagon

#

then by n (the number of hexagons)

#

WAIT

#

no

#

thats LESS than the surface area

#

and you're looking for the biggest integer n

#

right?

fierce magnet
#

Right

trail tendon
#

so i would say

fierce magnet
#

But why would you have to multiply it by 3 if you already found the Area?

trail tendon
trail tendon
#

yeah

#

so

#

s = surface area of sphere(known)
n = number of hexagons (unknown)
x = surface area of hexagon with length 400,000
n < s/3x

#

you could solve the surface area of your circle

trail tendon
trail tendon
#

then you get n, the number of hexagons right?

#

like

#

3d hexagons

fierce magnet
#

Would s work for the surface area of a sphere?

trail tendon
#

i meant sphere btw

fierce magnet
#

At this point that is what i thought so

trail tendon
#

yeah XD

fierce magnet
#

Anyways, i think i have got everything needed to do the math

#

Thanks, i appreciate it

trail tendon
#

cool man

#

that was fun

#

XD

fierce magnet
#

Indeed

trail tendon
#

good luck crunching the numbers

#

XD

fierce magnet
#

Thank you

trail tendon
#

wait i forgot

fierce magnet
#

?

trail tendon
#

its an inequality

#

and n is an integer

#

but yes

#

so you'd have to round down

fierce magnet
#

Oh yeah i do that all the time

#

I can´t make it perfect no matter what

trail tendon
#

yeah ok cool XD

trail tendon
fierce magnet
#

Hmm?

trail tendon
#

the surface area of the 3d hexagon being less than the surface area of the circle doesnt mean the hexagon is inscribed in the circle

#

what if the very tip is coming out of the circle, yet the surface area of the hexagon is still less than the circle

#

😭

fierce magnet
#

Um

#

What if i just simply fix it with the power of imagination?

trail tendon
#

like imagine the tips are a little bit out

trail tendon
#

i mean if complete accuracy isn't too important

#

than u can just do that method ^^^ XD

fierce magnet
#

It´s just lore for a TTRPG

trail tendon
#

LOL alr XD

#

like if we were launching a rocket this might kill someone

fierce magnet
#

Also, i doubt that it might make a huge difference even if it was real

trail tendon
#

but if its just really deep lore then its fine XD

trail tendon
#

you might be off a few million miles...

#

🤷‍♂️

#

😂

fierce magnet
fierce magnet
#

Alright, there might have been a few mistakes

fierce magnet
#

It gave me only less than 31 thousand Hexagons

trail tendon
#

whats the radius of the sphere?/

fierce magnet
#

55 million

#

light years

trail tendon
#

um

#

does the units matter or can i just put in 55 million into the calculations

#

wait yeah they should matter

fierce magnet
#

Oh crap i forgot

trail tendon
#

lol

fierce magnet
#

Considering 9,461E+12 kilometers is equal to a single light year

#

The surface area of a hexagon is insignificant

trail tendon
#

wdym

fierce magnet
#

Considering it has only 415 billion kilometers

#

While a Light year has 9 trillion

trail tendon
#

the surface area should multiply/divide numbers, so it should be significant

#

wait

fierce magnet
trail tendon
fierce magnet
#

Oh

trail tendon
#

i just searched up "surface area of sphere"

#

or soryr

fierce magnet
#

a

trail tendon
#

hexagon

fierce magnet
#

It does not appear with interactive stuff for me

trail tendon
#

huh

#

thats weird

fierce magnet
#

Wait

#

The surface area

#

Does it have in count the lenght of the sides?

trail tendon
#

yes, i believe it inputs the side length and outputs the 2d surface area

fierce magnet
#

Wdym?

trail tendon
#

is the formula

#

a is the input

#

and thats the side of the hexagon

fierce magnet
#

Hm

trail tendon
#

is that not what u were asking

fierce magnet
#

I honestly don´t know

trail tendon
#

lol

fierce magnet
#

But i should try it

#

I mean

#

That was the result i got last time

#

And still it gave me only 31 thousand hexagons

trail tendon
fierce magnet
#

Perhaps there is something wrong with the sphere surface area

fierce magnet
trail tendon
#

ok

fierce magnet
#

It is still a lot

trail tendon
#

that look about right?

fierce magnet
#

9 trillion kilometers

#

Holy

#

And that has to be powered by the square

trail tendon
#

not as the answer

#

thats just uhh

#

the surface area of the sphere

fierce magnet
#

Hold on, lemme do it

trail tendon
#

in kilometers squared

#

wait

#

i'm dumb

#

💀

#

what did i even do

#

lol

#

oh no

fierce magnet
#

It looked real for a sec

trail tendon
#

thats the radius of the sphere

#

in kilometers

fierce magnet
#

Yeah

trail tendon
#

yeah

#

then i can plug it in to the sphere

#

ect

#

liek that

fierce magnet
#

HOLY MOLY

trail tendon
#

so the area of the sphere should be 3.4 * 10^42

#

ri

trail tendon
fierce magnet
#

That´s a lot

trail tendon
#

it is a lot

#

i know powers get weird and stuff

#

but isn't it like

#

theres 10^80 ish atoms in the universe

#

and yet we're dealing with kilometers XD

#

still 10^42 is so far off from 10^80 so yeah

fierce magnet
#

Every planet is an atom in this big structure

trail tendon
#

fr

#

lol

#

anyway

trail tendon
fierce magnet
#

Thanks for helping me once more

trail tendon
#

now we gotta find...

#

i was gonna check XD

fierce magnet
#

Don´t worry, i already have the hexagon area

trail tendon
#

oh alr

#

XD

fierce magnet
#

I have to multiply it by 3 right?

trail tendon
#

um

#

divide the sphere by 3 * hexagon area

#

yeah

#

wait

#

yeah

fierce magnet
#

Alr

#

Thanks a lot

trail tendon
#

yeah bro XD

thorny juniper
#

anybody know where i can find a lot of hard trig questions? in looking primarily for identities

thorny juniper
#

uhhh

#

whatever you think is hard

#

im looking for relatively hard

tired oracle
#

im in 11th grade does that work or is it too easy?

thorny juniper
#

like they take say 30 minutes each ig

thorny juniper
#

just send what you have ill check it

#

dm me like a pic

tired oracle
#

ohk

light dock
thorny juniper
#

i wanted to include one but i dont think it let me send

upper karma
#

Send it as a link then

light dock
#

you can type it out

upper karma
#

You should be able to upload files though

thorny juniper
#

this type of question

#

b4 i think it didnt let me send bc i was in main discussion

#

sry about that

upper karma
#

@thorny juniper Something like this?

thorny juniper
#

yes this is perfect

#

where can i find these?

thorny juniper
#

thanks fam

#

👍

upper karma
#

Were you revoked of your rank?

#

?

#

I believe you used to have a role

#

Maybe not

#

I don’t think so, I just joined recently

#

Ahh maybe it was some other catgod then

vivid plinth
upper karma
serene blaze
#

i need to approximate the angles, but all the calculus i did, it was wrong

#

i did the a²=b²+c².2bc.cos

#

but it gave me a big number

#

i think i'm not using the right formula, or i'm miscalculating something

vivid plinth
#

Do u know SOHCAHTOA?

regal phoenix
#

he did the cosine rule

#

so ig yes

vivid plinth
#

Wait does he have to approximate or can he use a calculator?

vivid plinth
#

So sounds like u need to approximate

ripe bison
#

Cosine rule honestly sounds like the only thing that's needed there

vivid plinth
#

I dont think he used it correctly tho

ripe bison
#

Could also be a mistake in radians/degrees

#

That's usually pretty common, lol

vivid plinth
#

Mhm

ripe bison
#

I need to brush up on geometry again sometime

#

I'm currently just working through calculus

serene blaze
serene blaze
little anvil
ionic timber
# little anvil help?

is this high school geometry? there does not seem to be questions this difficult for high school geometry on khan acedemy. anyone have any idea what i could search to find geometry lessons/problems that are as difficult as this?

trail tendon
# little anvil help?

it's a matter of writing down what you know, and discovering more things until you have found what they're asking for lol

#

what progress have you made

lime dune
#

thank you for the completely noninformative answer

#

this is from aops introduction to geometry

#

whose problems tend to be more difficult than those in a standard HS geometry textbook

trail tendon
lime dune
#

anyway as a hint for a

#

how can you relate angle DCB to angle COB?

sour cosmos
#

probably not in your best interest to use an aops book or solve aops problems to study for a class

trail tendon
sour cosmos
#

theyre hard if you dont read their books

#

sure they have some typical and practical information but the books arent exactly the best to compare to a school curriculum

#

since its mainly meant for olympiads

trail tendon
#

naw like i remember i tried some problems recently from like idk maybe algebra or something?

sour cosmos
#

a lot of information they supply you with wont really help you in regards to school

trail tendon
#

did not know how to do a lot of the problems 💀

#

but i KNOW common algebra 💀

sour cosmos
#

i have their intermediate algebra book

#

i realized the book wasnt for me cause it strayed far from our school curriculum and didnt really contain any useful information imo

sour cosmos
#

cause they use a lot of tricks from previous books

trail tendon
#

it was kinda long time ago so i don't remember much of it besides the actual algebra that i use in actual math 💀

#

from my perspective aops is just working on an entirely different level 💀

sour cosmos
#

idk

#

next time just getting the pdf bro

#

be serios

trail tendon
#

lol

sour cosmos
#

idrk any good geometry books

#

i think u can just learn it all online through youtube

#

and like khan academy or smthing

trail tendon
#

i mean i already passed them or "learned" the main material

#

but i may go through the aops like u said because

#

the aops problems are exponentially harder than the khan academy ones lol

sour cosmos
#

geometry is substantially harder than algebra for me

#

maybe ill take a look at it idk

#

i just dont read the aops books because they take a long time to teach the most niche techniques for solving the most niche problems

#

and im not an olympiad

#

so

upper karma
#

Hello guys

#

I noticed my photomath app always provides me with unified solutions of trig equation

#

Should i also try to unify my solution or it's not mistake if i dont do so

dark sparrow
#

"unified"?

#

can you show an example of a solution from photomath

upper karma
#

I mean instead of x=pi/2 +2pik and x=3pi/2 + 2pik, it shows just one solution x=pi/2 + pik

#

Where k is an integer

#

It unified those two solution into one

dark sparrow
#

that specifically?

#

right

#

so that looks like it's specifically for the equations sin(x)=0 or cos(x)=0.

upper karma
#

It was for cos

dark sparrow
#

i mean the unification you're talking about generally.

#

no, it's not a mistake not to do it. but usually it is nicer to make your answer shorter.

upper karma
#

Sometimes i just dont understand how to unify some solutions

#

Thats why i asked, but thanks

inner vapor
#

how to I sketch cos(x)?

proven summit
inner vapor
#

I am still wondering

#

I think I might need an unit circle for this

#

cant believe they are asking for that without actually having taught us tho

dark sparrow
#

they didnt teach you what a sine wave looks like?

inner vapor
#

unit circle I meant

#

but fair, I wasnt being precise enough with my wording

upper karma
#

Is topology a part of geo?

#

Can someone enlighten me to topology?

regal phoenix
upper karma
amber hollow
#

could anyone help me with this?

solid needle
#

are you able to do that?

amber hollow
#

i got as far as 1/sin(t) * 1/cos(t) - 1/(sin(t)/cos(t) and then im confused

#

can i get rid of the ones by just flipping everything?

solid needle
#

what do you mean flipping everything

amber hollow
#

instead of 1/sin(t) i make it sin(t)/1 which just means it's sin(t) and i do that for everythin?

solid needle
#

you cant just arbitrarily flip fractions

#

what youre trying to do is similar to a student going:

#

ok i need to do 1/2 + 1/3

#

im just gonna flip the fractions

#

2/1 + 3/1

amber hollow
#

oh

solid needle
#

ok the answer is 5

amber hollow
#

uh

#

i swear i can do algebra but when it comes to trigonemetry i get so confused

solid needle
#

so a tip

#

what you need to think about is that the trig functions are still just functions

#

if you can interpret something like

#

1/x

#

then imagine 1/sin t the same way

#

sin t represents some value, like any other expression

#

you can imagine that value to be x if you want

#

so for now, if you want, do the following substitution:

#

y = sin t
x = cos t

#

and see if that helps

#

(note that i specifically set y to be sin t, i know the substitution is arbitrary but there is good reason to get in the habit of associating y with sin and x with cos, so i would use the substitution i have as written)

amber hollow
#

so if sin is y and cos is x. i end up getting 1/yx - 1/(y/x). the latter half can be simplified by multiplying the nominator by the reciprocal of the denominnator, so x/y meaning im now at 1/yx - x/y. then i tried to get a common denominator by multiplying x/y by x but i dont think im on the right track rn

solid needle
#

you are

#

multiply the top and bottom of x/y by x, keeping the fraction value the same

#

now you have a common denominator

#

you will end up with:

#

(1-x^2)/yx

#

at this point it feels like youre stuck

#

the point of the substitution wasnt to get you all the way to the answer, it was to help you think about how these expressions can be manipulated

#

substitute your sin and cos stuff back

#

look for other properties you can apply

#

@amber hollow

amber hollow
#

oh yeah thats pretty much where i ended up and thought i was wrong lol

solid needle
#

its right, sub the trig functions back

#

see if you can identify what to do with the numerator now

#

remember, this x y sub isnt something you have to do, and it will rarely get you all the way to the answer

#

it is only to help you organize your expressions so they are easier and more familiar to deal with

amber hollow
#

bc i noticed 1-cos^2(t) = sin^2

#

how do i memorize all this stuff. do i just try to remember the base stuff and how i get all the basic identities like that from them?

#

thx though

solid needle
#

so all of the basic trig identities

#

so everything before law of sines/law of cosines/sum formulas

#

they are all either basic conceptual understanding of trig functions

#

or they are very simple, basically trivial algebraic manipulations of them

#

if you build a strong foundational proficiency with trig functions, their properties and behaviors, none of those trig identities ever need to be memorized

#

i have never memorized them and can pull them out any time i need to and can prove any of them easily

#

that might sound intimidating, but given the right instruction, its really not that bad at all

#

the question is simply do you have the resources and the time to work it out

amber hollow
#

i see. im only taking this class rn bc when i tried to do advanced calculus i noticed that they actually use a bunch of trigonoometry and while im good at calculus, i struggle alot with trig so im trying to build a foundation for it. its so weird and intimidating though, its like i dont get it at all

solid needle
#

your last resort should be hard memorization

#

if you want

#

i can help give you that foundation here

#

it only takes about 30 min to go over some basics probably?

#

and the rest should follow if you just use my notes and practice

amber hollow
#

i do have a book thats supposed to be teaching it to me but i honestly feel like it doesnt cover everthing because i still dont understand hyp/opp/adj stuff except for like the very very bare minimum and every time i ask my professor for help its like im actually supposed to have a grasp of it already so

#

if you dont mind id like someone to go over basics with me and some notes to look at so i have a better understanding

#

also like how im supposed to know the unit circle without memorizing half of it x)

trail tendon
#

hm?

solid needle
#

ok let's do it

#

let's start from square one

#

you said you don't quite get opposite/adjacent/hypotenuse

#

let's begin there

#

so start with a RIGHT triangle

#

now we are going to label one of the non-right angles our "reference angle"

#

i mark theta on the image, but to make it easier to type, i will type it as "t"

#

now ill label the sides

#

question: which side is opposite to t? adjacent to t? which one is the hypotenuse?

amber hollow
#

hypotenuse is the long one...opposite is, a because its opposite the angle? and b is adjacent cause its touching the angle but not the hypotenuse

solid needle
#

correct

#

that's really it

#

so now we can define all of our trig functions:

#

we have

  • sin t = opp/hyp
  • cos t = adj/hyp
  • tan t = opp/adj
  • csc t = hyp/opp
  • sec t = hyp/adj
  • cot t = adj/opp
#

don't worry about the naming conventions of the last 3, we'll get there

#

as usual, hard memorize in the meantime, but once you understand, you will get to release more and more from memory as you'll just "understand" them

#

so what this is saying is that

#

no matter what kind of right triangle you draw

#

as long as the labeled reference angle is, for instance, 30 degrees

#

sin t, the ratio of opp/hyp, is always going to be EXACTLY the same value

#

in this case, 1/2

#

and that's why it's a function

#

as long you give it one particular value, and the output will never change

#

you can never have 1 input give 2 different outputs

#

following so far?

solid needle
amber hollow
#

so by ratio u mean that you're always going to get 1/2 for the sin when you divide the lines for opp/hyp regardless of how long the lines are? as long as it's a right triangle.

solid needle
#

AND as long as the angle t is 30 degrees

#

then yes

empty yew
#

!noans

lime crownBOT
#

The purpose of this server is to help you learn, not to hand out answers. Do not ask someone to give you the answer directly.

amber hollow
solid needle
#

good, the reason why the value never changes is just a simple application of triangle similarity theorems

#

so if you have any doubts about that or want to be more rigorous in your understanding, literally just review similar triangles from geometry

#

ok moving on

#

so in summary trig functions you can think of like this:

solid needle
#

for a given right triangle, and a marked angle t

#

input t into the trig function, output a side length ratio

#

trig functions: input angle measure -> output side length ratio

#

that's the key idea here

empty yew
#

Ask help like how to do that @cerulean turtle

solid needle
#

so now let's talk about to extend the domain of these trig functions

#

as you know, you can input things like 220 degrees into trig functions

#

in the context of the right triangle, this is nonsensical

#

but if we now reframe our definition, we can literally plug in any real number for our angle and have it make sense

#

so now I will present a new definition for specifically sin and cos

#

the previous definition you can think of as a motivation, why we might care about these functions

#

but this next definition i will provide is the one that will clarify literally almost everything

#

ready?

amber hollow
#

yes

solid needle
#

here is the unit circle

#

start on the right side at 0 degrees

#

this is just definitional

#

now if we go counterclockwise, this will positively affect the angle

#

again, this is definitional

#

so now we can label things like:

#

but don't forget, we can label the other way going negative

#

so on this unit circle, we say that 90 deg = -270 deg

#

and there is no reason we need to stay within -360 and 360 either

#

we can say for instance that 0 deg = 360 deg = 720 deg = 360n deg for any integer n

#

again, this is just definitions, there is nothing to understand here except this is how we label a direction with an angle

#

this is really the only thing you will need to "hard memorize"

#

so far so good?

amber hollow
#

yeah im following

solid needle
#

ok now the definition of sin and cos

#

pick an angle t

#

mark the POINT where the ray hits the unit circle

#

of course it has coordinates, as does every point on the plane

#

by definition, we say that:
x = cos t
y = sin t

amber hollow
#

wait so the points on the plane that is the circle are comprised of two ratios based on the right triangle formed by angle t?

#

i dont even understand that question

solid needle
#

you could say that

#

so i think i can clear up what it is you're asking in that question and demonstrate it

#

i mentioned before that

#

being motivated from the original opp/adj/hyp definitions

#

we are now extending these functions so that their domains go beyond the 0-90 deg range

#

but in order to extend it, you first need to make sure you didn't mess up the definition that is already there

#

let's now show that our original first definition matches this new definition

#

otherwise what would be the whole point of this?

#

is that what you're basically asking?

amber hollow
#

i think so yeah

solid needle
#

ok let's do that

#

you can see the right triangle in that diagram i drew

#

what's the side opposite of t? adjacent to t?

amber hollow
#

the side opposite to t is the purple part and the side adjacent is the red part

solid needle
#

good

#

and would you agree that the blue radius is 1?

#

since this is a unit circle?

amber hollow
#

unit circle meaning that the radius is 1?

solid needle
#

yes, that's what unit circle means

amber hollow
#

then yeah

solid needle
#

perfect

#

so now we can see that sin t = purple/blue

#

and since blue = 1, sin t = purple

#

and isn't the purple line just the y coord?

#

can you see how it works for the adjacent side/cos too?

amber hollow
#

so the red line is the x coord. red/blue is red/1 so cos t is just red

solid needle
#

bingo

#

would you now agree that this new definition lines up with the old definition?

amber hollow
#

yeah i understand now

solid needle
#

great

#

now this is where it gets fun

#

armed with just this basic definition

#

you now no longer need to memorize ANY "basic" trig identity

#

like i mentioned previously

#

let's start with a simple example

#

sin^2 t + cos^2 t = 1

#

you know this one already, yeah?

amber hollow
#

yeah

solid needle
#

do you know how it's derived?

amber hollow
#

the pythagorean theorum? a^2 + b^2 = c^2

solid needle
#

yep!

#

now let's try another one

#

sin(-t) = -sin t

#

you know this one?

amber hollow
#

i dont remember it no

#

wait no

#

i do i used that on my quiz i think

#

im not sure

solid needle
#

ok let's go over this one then

#

can you see that the negative of an angle

#

is just the angle reflected over the x axis

#

does that make sense?

amber hollow
#

yes i understand that

solid needle
#

ok now