geometry-and-trigonometry

[winter garden]

SAS they told you 90 degrees and 1 side and they share AB

ABC and BAD both have AB

Since all points in a triangle connect to one another

[maiden brook]

It is HL

bruh this problem is very simple why is there so much discussion about it

[winter garden]

What's the hypothenuse

Did they tell you it's the same

AB are the same so yes

...

[maiden brook]

it’s HL

What

[winter garden]

Hypothenuse length

Got it

HL tho it's just SAS but knowing 90 same

[timber cargo]

I remember this old joke and it goes: "What do you call a working teapot on a mountain

highpotinuse

[maiden brook]

its not

its SSA but a non-ambiguous case

[winter garden]

SAS and SSA I am pretty sure it's the same side angle side

[maiden brook]

please review geo

[woeful bluff]

i thought you couldn’t do SSA or ASS

[maiden brook]

this is ssa ambiguous

[maiden brook]

it’s SSA first off all and u generally cannot

[woeful bluff]

oh okay

[maiden brook]

There are some cases where if ur given a bit more information (namely if the triangle is acute/obtuse, measures of altitudes) u can still only have one feasible triangle

This is derived from the Law of Sines

[pseudo nebula]

HL is just SSA

[rotund field]

https://youtu.be/hT_TWLBrHC4?si=kv3iRCWDa887pL1Y

[fickle rose]

i love ambiguous cases

[maiden brook]

SSA is not a congruence theorem

bruh

[foggy jetty]

Hey please anybody send me a short course for basic geometry for olympiad math

[foggy parcel]

use trig ratios?

[feral sable]

Teacher needed to add stickmen?

[queen kindle]

pls help

[vernal pilot]

Might be wrong about this, but (x+5)/(2x+5+x)=(4)/(4+3)

Then solve for x.

[ionic timber]

my question got bumped in help channel, figured id paste here

[vernal pilot]

What are you trying to do?

[ionic timber]

trying to understand how when we use the distance formula for a point x,y and the focus/directrix, we wind up with those parabolas that seem to have vertexs that each represent an x or y value of the directrix/focus.

like i said i dont really know what my question is, it just confuses me that in finding the distance of these points to create an equation of a parabola, we yield these other parabolas along the way

[vernal pilot]

So are you trying to find the distance between a point on the parabola to another point?

[ionic timber]

no, i solved the initial question. but out of curiosity, i plugged all the quadratic equations (that equating the two distance formulas yielded before simplifying) into a graph, and the 4 parabolas shown above were the result. i was just looking for some insight as to why this happens. But i think i have a rough idea now.

[vernal pilot]

I’m too tired to understand this. But what I’m gathering is that it’s the distance each point of a parabola away from its focus? (x2)

[steep pendant]

Angle D

Segments AD and AC

[rich remnant]

Hi, what do you mean by “normal to dipole axis” in physics, do we mean in the same direction/ plane or opposite direction? Please help

[sullen crest]

Solve for X

[vernal pilot]

Interior angles of a hexagon add up to 720 degrees.

[sullen crest]

I just figured it out lmao sry

[vernal pilot]

Oh, okay.

[upper karma]

Tan(42°) × 11 = x

[rugged rover]

I got a 90 on the test

[upper karma]

nice

[upper karma]

can someone explain to me how this doesn't make sense?

also I would've turned them into cot/tan by now but the program wants the proof to be as pedantic as possible

[rugged hearth]

i think it has to be
sinx/(cosx+sinx) + cosx/(sinx+cosx)

[silver stump]

Prove PQXY is cyclic

[obsidian harness]

,rotate

[obsidian harness]

what have you tried?

!status

[lime crown]

What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above

[obsidian harness]

also I feel we are missing information

are those the midpoints of AB and AC?

[silver stump]

Found the answer

Thanks

2019 IMO second question

[vernal pilot]

Anyone got any good textbooks on geometry; specifically geometric proofs, circle theorems, and maybe vector proofs?

I am pretty mediocre at them, and its definitely not the best part of my math.

[obsidian harness]

bro ok

knew it was harder than usual lmao

[tidal blaze]

Using Basic Proportionality Theorem theorem :
BE/BC = BD/AB and you will find x.

[maiden dock]

hey guys how to tolsve for x y and z

[obsidian harness]

what do angle 6/5 x + 10 and angle y add up to?

search up a list of parallel angle properties if you're not sure

[vernal pilot]

$\frac{6}{5}x+10=2x-13$

[somber coyote]

TheLord26

[vernal pilot]

$y=180-(2x-13)$

[somber coyote]

TheLord26

[vernal pilot]

$z=180-y$

[somber coyote]

TheLord26

[vernal pilot]

———OR———

$z=2x-13$

[somber coyote]

TheLord26

[vernal pilot]

You have to use the supplementary and co-interior rules for angles.

[spiral hull]

hello

[vernal pilot]

hello

[spiral hull]

hey

@vernal pilot

[vernal pilot]

yes

[spiral hull]

wanna help me?

sir

[vernal pilot]

!da2a

[lime crown]

No need to ask “Can I ask…?” or “Does anyone know about…?”—it’s faster for everyone if you just ask your question! See https://dontasktoask.com/

[spiral hull]

sheesh bro flexing the commands on me

[vernal pilot]

ofc ofc

[spiral hull]

i @ u

in the help

[vernal pilot]

can you link the channel? i left and i cant reenter it cuz discord.

[turbid lodge]

🪑

[crystal sinew]

guys please: for a tri ABC, the maximum of (sinAcosB+sinBcosC+sinCcosA)^2

[vernal pilot]

Think about it logically. Firstly consider creating a range of the variables, 0<a,b,c<2pi (do you can always add 2npi for all possible solutions).

Next, remember the quadrants of when each trig function is positive and negative.

If you are trying to find the maximum then you will only be using the first quadrant.

As that’s the only quadrant where both cos and sin are positive.

From there it should be pretty easy to see what would produce the highest result. Consider looking at the exact value triangles for a hint, or letting cos=sin, or graphing sin*cos.

||also consider which quadrant has both sin and cos as negative||

[spiral hull]

Thanks bro I got a 92 in my final exam

You’d be disappointed on the one I got wrong it was hella easy 😂

[vernal pilot]

Nah man, it was all you.

[vernal pilot]

Dw I’ve gotten some questions very wrong for very dumb reasons.

[spiral hull]

I forgot to convert a radish to angle

[floral cairn]

am i tripping rn?

[sour mortar]

i have the analysis from a long time ago online from when i solved this problem if you’d like it

idrk the rules on photos here

[vernal pilot]

Ahhh ofc. Radishes, the hardest part of math. (Jkjk)

[safe swift]

can someone help me with this

[fickle rose]

i dont know if joyti bisected the whole shape so i wont comment on that but for kavita's way, she divided it into a square (15x15) and a triangle that is 15m tall and the base/length is 15m

[safe swift]

jyoti bisected only the pentagon. and thankyou for kavitas way

[fast pasture]

Find m ∠ A and m ∠ E

[obsidian harness]

angles in the same segment are equal

so angle A = angle E

[fast pasture]

ahh so i guess i have to turn it into an equation

alr thanks

[upper karma]

hllo

[trail trellis]

hllo

[upper karma]

hllo

[mental carbon]

circle theorems🙂

[stuck sleet]

Why 1/6 is the answer?

[stone socket]

Solve triangle ABC, given a = 322, c = 212, and
𝐵 = 110°50′

[pseudo nebula]

I guess since pyramids are 1/3 the volume of their containers since the base of this pyramid is gonna be 1/2 the base of the parallelogram bc that's how triangles work ig, 1/3 * 1/2 = 1/6, that's my intuition anyways

[fickle rose]

wait

[fickle rose]

use law of cosines

thought i was tripping for a sec

since u have SAS

[stuck sleet]

thanks!

[stuck sleet]

1/6 is also the answer here

is it the same reason?

[upper karma]

Can someone help me

Pls

Pls

like I need this

In the next minute

I’ve asked too many times

And no one is a help

Not responding

Dm Me or like ping me crazy

Or like help me in the channel I created

Like rn

<@&286206848099549185>

Something

Someone

Plssoslpsplspslpss

[winter garden]

.

someone got anything problems to post

me bored

[floral cairn]

help

[grave pond]

How about: since opposing angles in a parallellogram are equal, and angles DAB and CDA are equal by assumption, all four angles are equal. And the angle sum of a quadrilateral is ...

[floral cairn]

we cant assume in deltamath

lol

[grave pond]

You could also say that angles A and D are supplementary (because AB and DC are parallel); if they are equal they must be right.

[floral cairn]

ok

[grave pond]

I see the assumption that triangle ABD = triangle DCA right there in yore screenshot.

[floral cairn]

That's the given and deltamath only has triangle congruency statements

[grave pond]

Huh. How do you distinguish between "given" and "assumption"?

[floral cairn]

given is true

assumption is not

[grave pond]

Wat.

[floral cairn]

here

[winter garden]

I saw statement in you last post BD = Ad

That proves it's a rectangle

Since in a normal parallelogram the 2 line inside are not Equal

BD = AD

Are Ac

[floral cairn]

its not sufficient

they said

[winter garden]

...

Heh what website is this

[floral cairn]

wait why BD cong to AD

shouldnt it be

BD cong to AC

[winter garden]

BD = AC

I wrote wrong

[floral cairn]

deltamath

the worst fucking site

in the planet

[winter garden]

Is BD = AC only a rectangle inside line the same

Why would it not be right

In a normal parallelogram BD ≠ AD

[winter garden]

...

Whyyy

How could you draw a parallelogram with same diagonal with out it being rectangle

[floral cairn]

fr

[pseudo nebula]

I think so yea, cuz the shape formed will be a triangular pyramid

[grave pond]

A quadrilateral with equal diagonals doesn't have to be a rectangle, though.

[winter garden]

Know it also states is a parallelogram

So a parallelogram have 2 short smaw side and 2 long same side

[floral cairn]

it could also be a squatre

thats why

[grave pond]

But that (i.e. "parallellogram" rather than "quadrilateral") doesn't seem to be the world CACA selected in the dropdown.

[winter garden]

A square huh

Didn't see that one

You can change the statement

...

[floral cairn]

ohhh

nvm

[winter garden]

Did it work

[floral cairn]

nah

[winter garden]

Is there an option where you can state BC ≠ AB or something

Then BC = AD

[floral cairn]

no

[winter garden]

And is a parallelogram

Damn

[floral cairn]

its a level 1 proof

deltamath says

so u cant do anything

liek that

[winter garden]

Is there a link

To this place

I don't know where it is on the web

[floral cairn]

u cant access it

u need to pay

[winter garden]

Oof

[floral cairn]

deltamath rectangles

i can screenshot the statements

[winter garden]

XY bisects X proves that is 90 and that XY and WZ is the same

Try that

[floral cairn]

AC bisects angles BAD

[winter garden]

Yeah some thing like that

[floral cairn]

cant do it

[winter garden]

...

Then what's that option doing there

[floral cairn]

they give u the options for every proof

[winter garden]

How about for the first state ment the XY is right angle to WZ

That symbol

How do we differentiate it from a square

[floral cairn]

i did

diagonols are congruent

opposite sidess are cong

but i cant say

that

i can only choose one

its so stupid

[winter garden]

No even both is true a square is still that to prove it that side that are not opposite are not the same

...

Just prove the 2 diagonal are congruent

The site is weird

I think they set it to one proof only

Imma go to bed now bye

[stone socket]

hello

can someone help me on this?

The radius of a circle circumscribing an isosceles triangle is 25cm. If one of the equal interior angles of this isosceles triangle measures 70°, what is the area of the triangle?

[tame urchin]

its also a kite, a trapizoid, and other shapes

well im not sure kite but ik trapizoid

[maiden brook]

trapezoid part is iffy

imo trapezoids have exactly one pair

[hard coral]

How do I find a equation for X, Y and C in this problem? I have atan2(x,y) but that's a piecewise function. So then, how do I even solve this?

[mint nexus]

does this look right? logically speaking if one side of an isosceles trapezoid is 59, then the other side has to be 59 too. so then i did 90+59 and got 149, then did 180-149 and got 31 as my final answer

[tame urchin]

yea your right

unless it specifically tells you its not the same then its right to assume the angle M is equal to Angle P, making your answer correct 💯

[mint nexus]

yep! thank you :)

[ionic river]

can anyone help me out with this problem i got it wrong and idk

[real mural]

hi, i'm confused by this. it's due in just a few hours. i know you're not supossed to give the answer, but i really need it. the question cut off, but it said "solve for angle theta"

[upper karma]

i have 5 problems that i need help on

can someone dm me

and help me?

[spice cape]

#❓how-to-get-help

[real mural]

please, i desperately need help

[upper karma]

$\theta \approx 48.2$

[somber coyote]

koyomi

[upper karma]

thats your answer

that just means $B \approx 41.8$

[somber coyote]

koyomi

[upper karma]

i would tell you how to get said answer but you in a rush so good luck 🙏

[real mural]

thank you so much koyomi, and if you're religious, god bless you

[upper karma]

yea np :D

[tender phoenix]

Can anyone help me with proofs?

[vernal pilot]

!da2a

[lime crown]

No need to ask “Can I ask…?” or “Does anyone know about…?”—it’s faster for everyone if you just ask your question! See https://dontasktoask.com/

[upper karma]

It's better to just go straight into the question, people will end up answering your question

So what was your proof question

I'll see if I can help ❤️

[upper karma]

Allow me one moment

[tender phoenix]

k

[vernal pilot]

for q1, you know both triangles are congruent to each other, because of SSS congruency

therfor they have the same angles

[upper karma]

^

Thank you for just saying what I was abt to say lol

[vernal pilot]

ha np

[tender phoenix]

but how do i write that out thats what i need to learn my teacher isnt the best at teaching

[vernal pilot]

AB = CB, AD = DC, ect. then you just say ABD = BCD

with the lines on top of the edges

[upper karma]

I never dine these types of question but like Do your given part then proof part

[tender phoenix]

but i need to fill out all 6 of the column or what ever you call it

[upper karma]

So like

[vernal pilot]

just state all of teh side that are equal (as depicted in the shape)

[upper karma]

Write down BD perpendicular AC with reason given

That's how my teacher told me to do it if we ever encounter it

Write down what your given ig

[tender phoenix]

so like what would you use this for when it comes to the real world?

[vernal pilot]

wait, i didnt see that it was you who drew those lines. dammit

first line should be AD = DC

[upper karma]

Wdym?

[vernal pilot]

the ones that indicate that each line is equal

[upper karma]

Oh

[tender phoenix]

so AD=DC is given right?

[vernal pilot]

you have SAS congruency, not SSS congruency because you arent explicitely told AB = BC

[vernal pilot]

yes

[tender phoenix]

k

[upper karma]

Yea first line should be AD = DC

Also I think Angle ADB is congurent to CDB

My reason would be: Definition of Perp. Lines

[tender phoenix]

so what would be the reason for that given?

k

[vernal pilot]

$\overline{AD}=\overline{DC}$, then you say that $\overline{AD}\perp\overline{DC}$, therefor $\angle ADB=\angle BDC$ because of SAS congruency. Therefor $\angle ABD=\angle DBC$.

[upper karma]

For the given you just write given

[somber coyote]

TheLord26

[vernal pilot]

Also mention how they share line BD

for the second question (hold on ill use fancy math text)

[upper karma]

$ (\overline{E G} \cong \overline{L G}$

Oops

[vernal pilot]

L

[upper karma]

It didn't even WORK

[vernal pilot]

haha

[upper karma]

Reported

Blocked and banned

[vernal pilot]

dam

[upper karma]

Ez!!!

[vernal pilot]

what is wrong with your latex bro

[upper karma]

$\overline{EG} \cong \overline{LG}$

[somber coyote]

koyomi

[upper karma]

I am going to fart

[vernal pilot]

bruh

what

[upper karma]

Will it be congurent to the air?

[vernal pilot]

no

[upper karma]

Aw man

[vernal pilot]

anyway im going back to solving the second question

[upper karma]

Me too

Nvm I'm doing thrid

[vernal pilot]

$\overline{EF}=\overline{LH} \newline \angle F = \angle H \newline F|G|H \newline \therefore \overline{FG}=\overline{GH} \therefore \text{Because of SAS congruency } GFE = GHL \newline \therefore \overline{EG} = \overline{LG} \newline \text{QED}$

[somber coyote]

TheLord26

[tender phoenix]

like how do you understand this for me it just looks like a bunch of letters

[vernal pilot]

whenever you see two letters with a line above them that just means a line, then you look at that line on a triangle. I was constantly looking back at the triangle to make sure i was looking at teh correct line.

[vernal pilot]

and whenever two lines are equal i just noted it down

and once you find congruency you write taht down

[tender phoenix]

ik how to do that but how do you map the statement to the reason?

[upper karma]

$\angle ACD \cong \angle BCD$ because def of Angle Biseor$ \newline \triangle ACD \cong \triangle BCD$ because of ASA Congurence

[tender phoenix]

the given is simple

[upper karma]

PLEASE WORK

FUCK

[tender phoenix]

but when its something else i dont understand how you find the statement

[vernal pilot]

\ not /

[vernal pilot]

well first write down everything you are given, then everything you can easily desern, then you see if you can relate it to another proof. like triangle congruency, or check if youve solved it.

[somber coyote]

koyomi

[upper karma]

Question 3 btw

I'm o4aying it right

[vernal pilot]

ill double check

[upper karma]

Ty

Cus I self taught myself geometry so I can't be too confident giving answers here

[vernal pilot]

its correct, just write one last line saying AD=DB. Then QED if you want, not really needed cuz its not a formal proof, its a math discord server.

[upper karma]

*Most of it

I got a teacher to teach me a little

[tender phoenix]

i understand everything about geometry so far besides proofs either the teacher i have is really bad or i just dont understand

[upper karma]

$\angle A \cong \angle B$ and $\overline{AD} \cong \overline{DB}$

[somber coyote]

koyomi

[vernal pilot]

when i was taught vector proofs my teacher said to just keep listing off facts and eventually you would find something that just works. you can apply this to these geometric proofs as well.

[upper karma]

I need to learn more in geometry ngl

I gotta test out in May for AP precancerous next year

[vernal pilot]

geometry sucks

i prefer algebra and calculus

[upper karma]

I said precancerous

Precalc

[vernal pilot]

same thing

[upper karma]

Question 3 btw

Imma ask the geometry teacher for a study guide

5 months to learn the rest of geometry

🙏

[vernal pilot]

luckily i aint have to do geometry again (not thinking about my finals in 9 months)

[upper karma]

Bro I hate how HS requires Geometry points

I just wanna do some fun stuff not shapes n shit

[vernal pilot]

best part of geometry is messing around all lesson and not doing the work.

[clear sierra]

Hello

I need help

[fickle rose]

dont say you need help just ask the question man

so much easier for everyone else

[vernal pilot]

!da2a

[lime crown]

No need to ask “Can I ask…?” or “Does anyone know about…?”—it’s faster for everyone if you just ask your question! See https://dontasktoask.com/

[bitter snow]

can anyone help me? i already have y

[grand hawk]

X and 76 are supplementary so 180-76 =x

[grand hawk]

U could also just plug y into 6y-88 because it’s opposite of x which means they 6y-88 is equal to x

[bitter snow]

ya i got the answers

i saw what i did wrong

thank you though

🙂

[grand hawk]

Np

[maiden brook]

what fun stuff

[loud night]

yo guys

im struglling with geometry

were currently learning how to solve for altitudes using pythagorean therorem

i just want to know what type of method we would use to find H?

thanks

[loud night]

yo is anyone there?

!help

[lime crown]

To ask for mathematics help on this server, please open your own help channel or help thread. See #❓how-to-get-help for instructions.

[potent yacht]

Someone can answer it and how?

[maiden brook]

similarity

[maiden brook]

los

[potent yacht]

Can you give me the answer and the formula?

[maiden brook]

u dont know law of sines?

[potent yacht]

Yeah

[maiden brook]

In any nondegenerate triangle:

[potent yacht]

Still dont know, my bad😔

[maiden brook]

wdym

[potent yacht]

Can you answer directly, if you don't mind, kinda difficult to me

[maiden brook]

i dont think its advised to answer directly, and u just have to plug in numbers to a formula

[potent yacht]

I need the example to see how formula run😩

[potent yacht]

I have choices in my question but idk where's the correct answer

[maiden brook]

random thing i came up with

[maiden brook]

i trust u to plug numbers into a formula

[potent yacht]

Too hard to understand

[maiden brook]

its not at all hard to understand

this must be some unit quiz/test

[potent yacht]

@maiden brook could you give me the answer of this one and the formula?

Which is the correct answer?

[maiden brook]

the formula is los and i told u how to plug it in

[potent yacht]

I'm so bad at this, I can't figure the correct answer

[upper karma]

wdym by nondegenrate

[maiden brook]

the three vertices of the triangle are not collinear

[upper karma]

ok

[dark sparrow]

!noans

[lime crown]

The purpose of this server is to help you learn, not to hand out answers. Do not ask someone to give you the answer directly.

[upper karma]

damn alright

[upper karma]

This does not apply to people that you have already tried explaining the answer to in 12 thousand ways

Or explaing steps to get to the ans*

[narrow condor]

since you have the angles and a side length, you could apply sine law to the question

[potent yacht]

Where did you get the given?

[narrow condor]

wdym

[potent yacht]

Can you answer this one? I need some idea, if you don't mind

[narrow condor]

homie i just did

[vernal pilot]

e=2.72

jkjk

actually what the dude earlier said about another problem, you can use the sin law to figure it out lol

$\frac{a}{\sin(A)}=\frac{b}{\sin(B)}$

[somber coyote]

TheLord26

[vernal pilot]

$\frac{e}{\sin(105)}=\frac{4.2}{\sin(29)}$

[somber coyote]

TheLord26

[vernal pilot]

$e=\frac{4.2\cdot\sin(105)}{\sin(29)}$

[somber coyote]

TheLord26

[vernal pilot]

$e\approx8.368$

[somber coyote]

TheLord26

[weak mauve]

euler's number isnt that

oh wait

nvmd

[vernal pilot]

i made a joke about the question using e as the variable

i think its absolutely stupid to use e as a variable.

engineers be like $\pi = e$

[weak mauve]

in my school exams, all variables that are italicised are irrational numbers or mathematical constants. Like, Euler's number, Pi, C (speed of light) etc

[somber coyote]

TheLord26

[vernal pilot]

i just dont use e or pi as variables

as for c, if im doing physics i will avoid it, but in math i dont really mind using it.

[weak mauve]

I'm learning trig rn and its hurting my brain as to how to graph sin and cos functions from equation

I've watched khan academy

but

💀

[vernal pilot]

eh, i just got used to them.

[weak mauve]

Im trying to study for a scholarship that won't be available to me in 2 years time 😂

i will probably just forget the shit

[vernal pilot]

nah trig is very important

if you are going for a scholaship based on your math skills it will be VITAL

[weak mauve]

the scholarship I'm taking is everything

Calc, Stats, Trig, Complex no., etc

[vernal pilot]

trig is important in algebra and calculus

amd geometry

[weak mauve]

theres also Linear Programming, systems of equations, and some others I cant remember

[weak mauve]

tbh I really like doing geometry proof

[vernal pilot]

so just algebra and calculus.

[mint nexus]

geometry proofs are hell

[vernal pilot]

i hate them

[weak mauve]

some days ago I proved the formula for the area of a trapezium, and for some reason I was too proud of it

[mint nexus]

i only like the ones where they assert algebraic expressions

cuz im an algebra fan till i die

[weak mauve]

I guess thats because Im doing super easy geometry proof 😂

[weak mauve]

yeah for real algebra on top

[mint nexus]

oops

[vernal pilot]

NO

[mint nexus]

algebra just is more understandable as compared to geometry

[vernal pilot]

calculus is superior in every way

linear algebra scares me

[mint nexus]

calculus sounds insane but it is what it is

[weak mauve]

thats just more complicated algebra

[mint nexus]

math is the answer to the universe🤓

[weak mauve]

physics nerds: 😡

[vernal pilot]

you guys will not understand the fear i felt when doin linear algebra for the first time in my test.

[weak mauve]

does this mean if I show a matrix, I will jump scare you?

[mint nexus]

QUANTUM... physics... i am breaking the comfort limit of issac newton and albert einstein

[vernal pilot]

matrices are easy af

[mint nexus]

https://tenor.com/view/convolution-math-tables-gif-17225536

[weak mauve]

but it is still related to linear programming 🤷

[vernal pilot]

idk man, couldnt find a scared emoji

[mint nexus]

i have a big proofs exam tmr for geometry so im kinda screqws

screwed

[weak mauve]

oh so mentions of matrices wont scare yoi

[mint nexus]

how 2 memorize the rules real quick for rhombuses and trapezoids

[vernal pilot]

just memorise every proof in existance

ez

[mint nexus]

these questions in partixular will be the dearh of me

[weak mauve]

for real

[weak mauve]

what the fuck does the triangle with the curve across it mean

I know congruent symbol but thats it

[mint nexus]

i got a 35 on the last exam because the proofs took 40 points off my exam

[vernal pilot]

bruh

[weak mauve]

waiittt what does congruent mean again?

[mint nexus]

equal

[vernal pilot]

the same

[mint nexus]

yes

[vernal pilot]

but might be flipped or rotated

[weak mauve]

how tf does HR is congruent to NT

[vernal pilot]

is that supposed to be the angle symbol?

[mint nexus]

[weak mauve]

oh wait

I read it wrong

[mint nexus]

yes

[weak mauve]

sorry mb

[vernal pilot]

just a really weird way of writing it ig

$\angle$

[somber coyote]

TheLord26

[weak mauve]

yeah isnt the angle symbol mean to be triangle

[weak mauve]

that

[mint nexus]

idk why its done that way

screw it im majoring in polisci i dont wanna do math

[weak mauve]

I dont know, but im just gonna spitball here:

Since HR and NT are equal, you can say the shape is symmetrical, and thats it cos I have no idea how to proceed

[vernal pilot]

best course of action

[weak mauve]

yes drop out of math and embrace being a snake

[vernal pilot]

nope cant say symmetrical

[mint nexus]

no idea

rn is like

a shared segment

idk

[vernal pilot]

you can say its symmetrical because it is a rectangle tho

[mint nexus]

reflextive postulate

something

[weak mauve]

oh then that

what grade are you guys in?

[mint nexus]

stupid rectangle

10

it only gets worse from here lol

[vernal pilot]

you can just prove it is true for if the lines went to the corners.

[weak mauve]

are you in america?

[mint nexus]

yea

nextyear i gotta take like 4 diff aps ☹️

[weak mauve]

im in new Zealand and Im year 11, which is probs equivalent to grade 9 in america

[mint nexus]

ohhh

[weak mauve]

or grade 8

[mint nexus]

WHAT

[weak mauve]

the education system here is so bad

[mint nexus]

wait so how old are you

[weak mauve]

but my area of expertise is algebra soooo

[weak mauve]

14

[mint nexus]

yea you'd be a freshman here

[weak mauve]

what does that mean

[mint nexus]

grade 9

[weak mauve]

oh I see

[mint nexus]

starting year of hs

yes

[weak mauve]

but I actually skipped 2 years here in New Zealand

so in new Zealand I should be in year 9

[mint nexus]

ohh

[weak mauve]

which is probs equivalent to grade 6 or 7

idk the scaling is weird

[mint nexus]

well god damn

go to canada or somethin man

[weak mauve]

here in New Zealand, we do fuck all until year 10, where we actually start to do real shit because it will affect our univeristy grades

literally everything I did from year 3 to 6 was the same

[mint nexus]

get the hell outta new zealand and pursue a decent education someplace better when you get older

[weak mauve]

eh Im studying computer science

[mint nexus]

atleast a temporary fix until your educational career is over

[weak mauve]

I go to univeristy when im 16

[mint nexus]

you would make good money in america if you major in compsci

super wanted major

[vernal pilot]

such a backwater country, thats why Australia on top

🇦🇺 🇦🇺 🇦🇺 🇦🇺

[weak mauve]

yeah ik, but I dont really like migrating

[weak mauve]

for real, has better universities and everything

but I dont like the fires though

and wildlife

sorry 😔

[vernal pilot]

bro

aint no way bros dissing out wildlife

[weak mauve]

no I meant like the dangerous

[mint nexus]

i can understand that but then again prioritize in your studies and sometimes for that its necessary to travel to foreign countries or places out of your country

[weak mauve]

snakes, spiders etc

I am crazy scared of them two

[vernal pilot]

no

[weak mauve]

ik ik, but I'll see

[vernal pilot]

because things can kill spiders

[mint nexus]

absolutely not

spiders are horrible but good for ecosystem

[weak mauve]

plus, univeristy fees in America are ⤴️

[mint nexus]

agreed

its why i plan on studying abroad in canada

[weak mauve]

its like 40k usd to study at MIT

[mint nexus]

it might be pricy but the education there is strict and good

[weak mauve]

and thats just tuition fees

[mint nexus]

yea with intl fees its worse

might not even consider you either

[weak mauve]

im studying uni here in new zealand then idk

find work

[mint nexus]

even with a solid gpa they prioritize in their residents then move to intl students

[mint nexus]

just rack up a solid gpa, do whatevers necessary to gain a decent role in your school

here in america we take college level courses to rack up our GPA, or we take extracurriculars such as clubs, sports, etc to make our background more interesting

additionally, if you are a person of color or a person with non american ethnic backgrounds, you're more prone to get into your desired college. this is usually aimed at first-gen individuals though

[weak mauve]

oh yeah thats right, uni scholarships are always targeted at "specific ethnic groups"

[vernal pilot]

'Merica

[mint nexus]

yea, it is somewhat beneficial though if you work to the best of your ability. my half-brother got accepted into harvard med school just for his ethnic background consisting of persian immigrant parents lol

well, not entirely

he did have amazing credentials and was top of his class, but his background increased his chances

[vernal pilot]

but like, is it even worth moving to america? like you get worse food, the gun control is pretty bad, no free healthcare

[mint nexus]

btw we should probs move to general discussion🥲

[vernal pilot]

ye

[mint nexus]

^ reason why im moving to europe fr

[weak mauve]

bro healthcare in america has been made into a joke

[restive pumice]

Can I ask geometry question in here?

[vernal pilot]

!da2a

[lime crown]

No need to ask “Can I ask…?” or “Does anyone know about…?”—it’s faster for everyone if you just ask your question! See https://dontasktoask.com/

[vernal pilot]

also this is the #geometry-and-trigonometry channel....

[restive pumice]

Oh

[bronze wind]

Can someone tell me how I would find e

[fickle rose]

the triangle that has angle e in it is an isoscles triangle

with that info you should easily be able to solve

[bronze wind]

oh I didnt even notice that

[restive pumice]

Each of the 3 angles in an isoscles triangle is less than 90° and there are 2 angles with the same value. Am I right?

[fickle rose]

no

[restive pumice]

What

[fickle rose]

isosceles right triangles exist

45 45 90

[restive pumice]

Oh

[restive pumice]

Wait thats an isosceles acute triangle

[ocean wing]

Isoscles triangles have two equal sides right?

[fickle rose]

yes

[ocean wing]

Thanks

[fickle rose]

2 equal angles too btw

[restive pumice]

Given the ABCD tetrahedron. Call I, J, K in turn is the midpoint of the edges AC, CD, BD.
a) find the intersection of two planes (ABC) and (AKJ).
B) Find E is the intersection of the BI and plane line (AKJ).
C) find G is the intersection of the line Ek and the plane (ACD).
d) prove that AB / / (CDE).

I solved a) but now stuck at B and C

The intersection for a) would be the line d which passes through the common point A and parallel with BC, JK right?

[restive pumice]

Is this how I find E in problem b)? I think since d is the intersection of (AJK) and (ABC) so it would be on same surface with those 2

Oh wait no

It feels a bit off

[vernal pilot]

e=180-2(36)

Because isosceles

[bronze wind]

I already solved it but thanks

[upper karma]

uhm this might be a stupid question but i thought it was simple (maybe it is) but i need help with using the number line

Not really the number line but using the Ruler Postulate

what's the distance between √3 and -√5

i came up first with √8 (its stupid i know) 😓😓

Would it be √3+√5

[balmy carbon]

any1 can help with geometry angles ?

my problem is like I can do step A B but can't figure out what to do with the step C 💀

[lime crown]

No need to ask “Can I ask…?” or “Does anyone know about…?”—it’s faster for everyone if you just ask your question! See https://dontasktoask.com/

[vernal pilot]

$s=|p_{1}|+|p_{2}|$

[somber coyote]

TheLord26

[vernal pilot]

Where s is distance and p_1 and p_2 are two points on the number line.

$\text{Alternatively: } s=|p_{1}-p_{2}|$

[somber coyote]

TheLord26

[vernal pilot]

But I prefer the first method because it’s easier to understand.

[balmy carbon]

no

[balmy carbon]

anyone #help-7｜zen1thxyz

[upper karma]

Ping the helpers role

[tame urchin]

What does it mean by altitude in a triangle?

[keen turtle]

How to find ratio

[livid kraken]

Similarities of triangles I think

[hallow kayak]

Is anyone really good at trig? If you are please dm me

[lapis moon]

❌

similar triangles are taught in junior secondary geometry, while vectors are taught in high school

[lapis moon]

Use the convex can combination of vectors: https://youtu.be/qy9jB5ydxGo?si=Aso-FywI_YTevY_W

[livid kraken]

Thanks for correcting me
Tbh I didn't notice vectors

I saw triangle and ratio and figured it was similarity 😂😂

[bitter snow]

anyone help pls?

[hallow kayak]

129

75+54

[bitter snow]

Thank you, i hope its correct

[lapis moon]

tbh i know there's an elementary way (the area method) that doesn't use vectors at all, but it doesn't involves similar triangles

the 2nd fig features the circumcenter, which is sth reli classic

there shld b tons of info abt that

to answer that question you just need to retain some keywords in mind, draw some additional line segments, and observe a few congruences of triangles

for the 1st figure, you're given the side lengths of two triangles, so you can alr solve those triangles

[craggy tiger]

I am stuck on a problem where you need to write a formula for calculating the combined mass of a half-sphere and a cone. The height of the cone is r⋅4 and both shapes have the same radius. Their density is 3.51g/cm³. I wrote:
(r³⋅π⋅4/2/3+r²⋅π⋅4r/3)⋅3.51=m
The right answer was: 7,02⋅π⋅r³
These answers are equal. What I wonder is how someone got that formula.

[paper olive]

How do I move forward here, lol

AED is 60 yes or no I'm just skeptical

Because in the example the product of the formula was for the angles inside the chords

[craggy tiger]

It can't be 60 since its obtuse

[paper olive]

Yeah

Idk where to move on from there

[craggy tiger]

Can someone please answer my question?

[craggy tiger]

60+60=120
360-120=240
240/2=120

[paper olive]

I did that and doubted myself

Thanks

[vernal pilot]

!da2a

[lime crown]

No need to ask “Can I ask…?” or “Does anyone know about…?”—it’s faster for everyone if you just ask your question! See https://dontasktoask.com/

[astral stratus]

Can someone help me please I’m not sure on how to find x

[fickle rose]

30 60 90 and 45 45 90 triangles

all of them are one of the 2

or if u wanna take the longer route just use pythagorean theorem

[astral stratus]

Ik what to do but idk how to set up the problem to find x for number 23

Can u help me by doing that

[fickle rose]

u could always just use trigonometric ratios

since it seems you already found one side

but if u wanna use pythagorean theorem u can do 11^2 + x^2 = 51^2 (i think u wrote 51)

then isolate for x

[stuck sleet]

Just wondering

The solution is saying that these 2 triangles are similar:

the red and blue

Why????

[lapis moon]

@astral stratus

1. plz improve ur handwriting. i can't read the circled part
2. what's on the right is wrong. "11" is a rational number while 4√6 is an irrational number. be careful when you use '=' sign. if you're making an approximation, you need to state the number of decimal places/significant figures
3. the calculations are wrong, and i've marked them with ❌

[lapis moon]

angle chasing

[stuck sleet]

can you explain further? Thanks!

[lapis moon]

https://artofproblemsolving.com/wiki/index.php/Angle

[astral stratus]

No it’s not an 11 my teacher makes me say ll which stands for long leg

And sl for short leg

[lapis moon]

it's the 1st time that i've heard of such practices. new vocab learnt. thx 4 edu. looking forward to using this in my future life
unluckily, ll written on paper can be mixed up with 11

your marker has tons of questions to correct, so write the least possible

• to reduce her/his workload
• to gain more time for proofreading
• to allow him/her to give your marks quicker

don't make him/her guess what you mean. instead, state things clearly.

you can simply continue by re-doing what you've done for the larger triangle to the smaller triangle

[sick kraken]

Im so stuck on this one

It was on my test and i got it wrong

I know its easier than it seems but i cant seem to get it

Cylinder A has a volume of 20, if Cylinder B has half the radius of Cylinder B, What is the volume of Cylinder B?

[floral shale]

Are we assuming that they have the same height?

Let $πr^2h = 20$

[somber coyote]

Umbraleviathan

[floral shale]

Then for cylinder B, replace r with r/2

Then you're gonna solve for πr^2 h

Well

Lemme clarify

You're given that $V_a = \pi r^2 h = 20$. You know that Cylinder B has half the radius of A, so:

$$V_b = \pi \parens{\frac{r}{2}}^2 h$$

[somber coyote]

Umbraleviathan

[floral shale]

Isolate πr^2 h, do a substitution, then isolate Vb

[tame urchin]

$\adjacent$

[somber coyote]

Steve7108
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[tame urchin]

Ok so a symbol don't exist

For adjacent

[pine arch]

Hi can somebody help me rq

So far i know this

let me write it down

ik triangles acb and acd are equal

i proved it with asa

and then i know that triangles abo and ado are equal

because of sas

[grave pond]

That sounds like it should work.

[covert cape]

what should i do if i dont really know anything about geometry proofs and i have a test tomorrow

[grave pond]

Get a good night's sleep since that doesn't sound like a salvageable situation anyway.

[covert cape]

damn i don’t understand why i just don’t get oroods

proofs

i was in honors algebra

geometry is just a lot harder

[grave pond]

Hmm, they shouldn't be particularly harder than algebra proofs. But some countries have a tradition of teaching and testing geometry proofs in particular with a particular "two-column" format which is barely readable for no really good reason.

[maiden brook]

then how can u show ABD is isosceles? how would that help?

[fading raven]

i need help with this

[maiden brook]

definition of incenter

[fading raven]

its the point where all the angles cross

that middle part

[misty tusk]

yep

and what do we know about the lines there

[grave pond]

The givens are not completely consistent -- if the lengths 11, 4, and 20 are exact, the angles would be about 11.3099° and 19.9831° rather than 11° and 20°.

(The key to this is that if G is the incenter then AG, BG, CG must be angle bisectors).

[maiden brook]

yeah then why give the side lengths at all

[upper karma]

my geo teacher is making every group in the class make a song and music video about transformations, it needs to be dual language and at least 2:30 long. It's cringey as hell so I'm editing it to be cringey to the max

[fickle rose]

incenter is where all angle bisectors

intersect

and its equidistant from the sides

using that info u can get all the angles

[heady sedge]

can anyone solve this

[upper karma]

try converting everything in sin and cos

and simplify?

[heady sedge]

i did try that

@upper karma

[bronze wind]

how would I solve both of these?

[fickle rose]

for the top one, setup an equation in which u the sum of all those expressions that represent the angle values add up to 180

[bronze wind]

I did that and it didnt all add up to 180

[fickle rose]

thats not possible

2x+11+2x+11+x-2 = 180

[bronze wind]

I set it up like that

[fickle rose]

u are literally forced to get the solution for x that would make this equation true if you did it pro[erly

isolate for x

simple algebra

[bronze wind]

when I plugged what I got for x, it got like 37.2

I cant check rn since im multitasking

[fickle rose]

32.2

[bronze wind]

yeah

[fickle rose]

wait no

u get 32

i cant do math rn

its 32

x=32

5x+20 = 180

simplify u get 32

[bronze wind]

oh wait I see what I did

mb

[fickle rose]

and regardless it can be a decimal value too

[bronze wind]

I know but when plugged in, it should add up to 180

[fickle rose]

oh yeah

but anyways thats how u solve

same one for the second one

except 180-exterior angle = interior angle

or if u just have to solve for x then u can do 45+5x=9x+9

[bronze wind]

ok

[stuck sleet]

what is a seam???

[tired rain]

Hello can someone help me with this I need to find the cosinus and sinus of -7pi/6 I found the right sinus I think but I found racine of 3/2 as the cosinus but it's - racine of 3/2 if anyone could tell me where I did wrong 😅

[vernal pilot]

Think about what $\frac{-7\pi}{6}$ is if $0<\theta<2\pi$.

[somber coyote]

TheLord26

[vernal pilot]

You could draw a diagram where you go -7pi/6 radians around a circle, then you can check what quadrant it’s in.

And that will tell you if it’s positive or negative.

Tldr find 5pi/6 which is in the second quadrant, which is where sin is + and cos is -.

And then finding sin(5pi/6) should be relatively easy.

After all it’s just $\arcsin(\frac{5\pi}{6})$\newline which equals $\arcsin(\frac{\pi}{6})$.

[somber coyote]

TheLord26

[vernal pilot]

While $\arccos(\frac{5\pi}{6})=-\arcsin(\frac{\pi}{6})$

[somber coyote]

TheLord26

[tired rain]

Thank you sm!!

[tame urchin]

Someone left their geometr7 hw on the floor

Snatched that shit so fast 💯

[jaunty shard]

when the net of the lamp shade is curved into the shape of a lamp shade, it will need to be extended a bit, creating an overlap, so that the 2 ends can be sewn together. so, you will need to add the area of a trapezoid to the frustum lateral surface area.

[jaunty cradle]

Need to find the area of the circle

[maiden brook]

it’s a trapezoid?

[tidal blaze]

-7pi/6 = 2pi - 5pi/6 = -5pi/6
So sin(-7pi/6) = sin(-5pi/6) = sin(-pi + pi/6) = -sin(pi/6) = -0.5

[tidal blaze]

I think you should research on the internet about the** properties of a circle inscribed in a trapezoid** and you will probably find the answer.

[tidal canyon]

can someone help me understand proofs and reasons and help with this questions

Given: AB > BD ∠ADB = ∠C
Prove: AD > DC
4 proofs 4 reasons

[lament tree]

what's a "diameter" of a parabola?

found out

[lapis moon]

treat parabola as the subset S in ℝ², and use the usual (i.e. Euclidean) distance ρ, it's easy to see that {ρ(x, y) | (x, y) ∈ S²} isn't bounded above, so the "diameter of a parabola" can be written formally as +∞.
reference: https://people.math.osu.edu/costin.10/H161/supremum copy.pdf

[lament tree]

that wasn't what I was asking

I was asking what it is not the number

but ty ig

[lament tree]

I mean, the size

[grave pond]

For some purposes you could use the length of the latus rectum as a rough analogy to "diameter" in the sense of a well-defined length scale for the parabola.

(Oh, and this is actually also twice the radius of curvature at the vertex of the parabola, which is another way it generalizes the diameter of a circle ...)

[lament tree]

yeah ig

but I was asking cus I was reading a text by archimedes and he tells you to draw a segment paralel to the parabola's diameter

I then found out what he was talking about was the line that cuts it in half

[grave pond]

Oh.

[thick slate]

need help with questin 3

from a previous year

[slender marsh]

Need help with this question

[grave pond]

What can you say about the two angles labeled as 2c+51 and 8c-24 if the lines are parallel?

[lapis moon]

instead of having sm1 directly pointed out your mistake, which is sth you won't be able to do in tests/exams, i'm giving you a guide for proofreading your work

you shldn't change the variables. their name and cAsE have to be preserved
when you're doing approximations, you have to state the number of significant figures/decimal places

you can use your scientific calculator's built-in variable

to store your computed answer

type out the target expression in terms of that built-in variable in your scientific calculator

if it's good then you're done, but this bad cuz

,calc x = asin(5/14); cos(x)/sin(2*x)

[somber coyote]

Result:

[1.4]

[lapis moon]

\tikzmath{\ans = 5/7;}
which is NOT $5/7 \approx \ans$

[somber coyote]

vin100

[lapis moon]

you can use a strategy called "bisection method" to find out the topmost "bad" line (i.e. where your solution goes bad)

[stiff flint]

those two equtions should be equal so if we solve for c we get 12.5

[slender marsh]

I need help with the statement and reason question

[misty tusk]

this is fairly straightforward

compare the side lengths using a ratio and compare the angle lengths

if you know what the similarity postulates are you'll answer it easily

hmm okay

so essentially its asking if the triangles are similar

why

thats not how that works

you have a few similarity postulates to say for certain triangles are similar

yeah but that doesnt give you enough information on its own

you also need to say that the sides have a relationship if you dont have enough information about the angles

are you familiar with fractions

there is enough info and they are similar but im not going to just hand out the answer

cool

so we can compare the angles using fractions to see if the triangles are similar by setting them to be equal
so the angles of one are 9 and 15 and the other is 3 and 5

so we can say $\frac{9}{15} = \frac{3}{5}$ and if that's true we can say that the triangles are similar

[somber coyote]

architecture2

[misty tusk]

mmhm

and its true because we know 2 sides and one angle

np

[misty tusk]

okay

geometric proofs are fun

so for 2. its essentially just saying the angle is self-similar so our reason is going to be via the reflexive property

for 3. its the addition property of equality because all its doing is reorganizing things we already know by what we said was congruent above

for 4 it seems like angle addition?

and for 5 you're substituting in from 4

so yeah. i can go more-in depth but thats the basics

[maiden brook]

this one is rlly easy

[misty tusk]

yeah its one of the first ones you cover iirc

i did proofs i think 2 years ago now

[maiden brook]

SAS

[floral cairn]

help please

[floral cairn]

Base angle thereom

Sas

[ocean ledge]

how do the inverse trig functions work? or what are their formulas.

ik the formulas of sin, cos, tan. but how would i get the inverse formulas of them?

[misty tusk]

okay so its unbelievably simple

[ocean ledge]

pls enlighten me

[misty tusk]

$$\csc(x) = \frac{1}{\sin(x)}$$
$$\sec(x) = \frac{1}{\cos(x)}$$
$$\cot(x) = \frac{1}{\tan(x)}$$

[somber coyote]

architecture2

[misty tusk]

there

thats it

csc is cosecant
sec is secant
and cot is cotangent

So say you're trying to find $$\csc(\frac{\pi}{2})$$ Thats essentially the same as saying $$\frac{1}{\sin(\frac{\pi}{2})}$$ which we know is $$1$$

[somber coyote]

architecture2

[ocean ledge]

so to get for example m of angle A of right triangle ABC, where the hypotenuse is 12, and the adjacent in 8, I can do sec(cos(8 / 12))?

[misty tusk]

i mean sort of? thats not necessarily how you'd write it though

[ocean ledge]

What's the correct way?

[misty tusk]

OH you mean like

okay i see i see

so what you mean is smth slightly different

those are arcsin, arccos, and arctan

so like. if you had in your example
$$\cos A = \frac{8}{12}$$
you can say that
$$A = \arccos\frac{8}{12}$$
and solve for A

[somber coyote]

architecture2

[nocturne remnant]

sec is not the inverse function of cosine, it is the reciprocal of cosine

[misty tusk]

and that would give you the angle A

my mistake for mixing the two up

[ocean ledge]

my fault, I dont know a lot abt this stuff lol. so what's the formula for arccos?

[misty tusk]

I don't really know how to find the arccos of a number by hand

I usually use a calculator

esp since it doesnt often give you exact answers

[ocean ledge]

Thank you

[misty tusk]

ofc

sorry for the earlier confusion

[misty tusk]

seems like D yep

[silent plank]

its a poorly worded question

as D is already known from YS being a perpendicular bisector

[sonic mural]

I have two ECEF points on earth A and B. I want to get the relative position from b to a (as if a is 0,0,0). The problem is that it will be rotated.

not sure what the best way to achieve it but I have two ideas:

a tangent plane at point A then point B is projected onto the plane

I dont need height

or calculate the translation of the plane and rotating point B by that

which makes it as if it was at the north pole

A. Will that work the way im expecting it to?
B. how do I actually do that? I already got the translation of the plane I just need to rotate the coordinate. Or if it should be projected how do I do that

[violet rose]

is answer to this a. -cos(x)-sin(x) or did i make a mistake?

[noble quiver]

I think your answer is correct

[spring panther]

hey guys

could somebody please help me

PLEASE

What i need to work on:
Reasoning, Lines, Transformations
Triangles, Polygons, Circles, Three dimensional figures (i just need to review and or learn)

i need videos

[silent plank]

google

[lilac bane]

and youtube

[spring panther]

bro

[spring panther]

bro

i used the "help" channel to...

wait nvm

nvm

[lilac bane]

did you expect us to create videos and send it to you

[vernal pilot]

Lol exactly, we can’t teach you entire topics, we can however go through a question if you’d like if we have the time.

And for the to be the case you have to post a question.

[lilac bane]

exactly

[vernal pilot]

If you really want to learn something I suggest paying attention in class or studying using textbook.

[spring panther]

i do pay attention

but the test reviews focus on the smallest little topics that we spend a day learning and then forget about

[wise grove]

Triangle ABC has sides AB = 51, BC = 119, and AC = 136. Point C is reflected over line AB to create point C′. Next, point B is reflected over line AC′ to create point B′.If [B′C′C] can be expressed in the form of a√b, where b is not divisible by any perfect square besides 1, find a + b.

[misty tusk]

<@&268886789983436800>

[velvet relic]

@vagrant vault

You just have to see the slope of the other ones and then plot M so it has the same slop

[vagrant vault]

OHHHHHHHH

TY

THAT MAKES SO MUCH SENSE

UR AMAZING

AND A GRADE SAVER

[velvet relic]

And it has to go in that spot rather than the upper one because of order of the letters

[vagrant vault]

[velvet relic]

JKLM and the go counterclockwise in that order

[vagrant vault]

ty bro or dude or human TY

[velvet relic]

like M at 0,3 would almost be a parallelogram but that would actually make the lines cross eachother

[vagrant vault]

yeah it wouldnt be parallel