geometry-and-trigonometry

[upper karma]

otherwise you have done it correctly 👍

[nocturne remnant]

are you given that the tension in the rope is 800N?

not sure what else couldve gone wrong

[proven marsh]

understand thanks

[upper karma]

most probably yes cos he have used it

[nocturne remnant]

yes its just cuz its not given in the picture so idk

[upper karma]

yup

[solar sigil]

Yes, sorry

[upper karma]

bro most probably the answer mentioned is wrong

[solar sigil]

The cables AB, AC have a max force of 800N

This is given

[nocturne remnant]

...

[solar sigil]

OK thanks, I'm glad I'm not going crazy then

[upper karma]

Is the mass of the load given?

[solar sigil]

Negative, I have to calculate the max load

[upper karma]

It is not necessary that 800 N will be used

it could be less depending on the mass of the load

[nocturne remnant]

you probably have to balance the horizontal components as well

[upper karma]

I dont think that is imp

[solar sigil]

Well I could, but thats not really associated with the given problem right?

[nocturne remnant]

why not?

[solar sigil]

All the information needed is working in the Y axis

[upper karma]

Horizontal components have nthing to do with the load

[solar sigil]

That

[upper karma]

What i would suggest is leave it, you have done everything correctly

[solar sigil]

Sorry, English isn't my first language so I can be weird in my phrasing sometimes

[upper karma]

so why worry

[upper karma]

same

process is more important than getting the answer

and you have done that well

[solar sigil]

Normally yes, but since covid they have introduced this new program which only checks your main answer. If that one isnt correct, you get a follow up question which gives 70% of the points

The follow up question does involve the first question, but just some numbers changed or a diff approach

[upper karma]

sad

[nocturne remnant]

funny thing

i reached the official answer by considering horizontal components

[upper karma]

how come?

[nocturne remnant]

i.e. the tension in the two cables are different

and i equated the horizontal components to be F

[solar sigil]

Yeah this is fairly new theory for me so this goes over my head

[upper karma]

I understood what you did, but I can't understand why this?

[nocturne remnant]

Basically because the horizontal components have to be equal, the tensions in the two cables need to be in some certain proportion. And only one of them can reach the maximum tension of 800 (the tension in the other cable is below 800)

[solar sigil]

I thought this was not the case because it's in balance.. But the way you phrase it does sound logical

[nocturne remnant]

Also the 3-4-5 triangle in the given diagram was horribly out of scale so that threw me off for a bit too xd

[solar sigil]

So what does the v2F mean? F is force obviously, but the V2?

[nocturne remnant]

Square root of 2

Which is just 1 / cos 45

[solar sigil]

Which equals sin45?

Oh wait cos yea

[nocturne remnant]

Not exactly; that would be 1/sqrt(2)

Well cos 45 and sin 45 are equal anyways

[solar sigil]

Oh

I did not know that

[upper karma]

That's insanely good approach

Thanks

I learnt something new

Now my mechanics will become better by 1%

[solar sigil]

I G2g now unfortunately, but this helped a lot. I still do not fully understand your method, but i will definitely look into it more. Thanks @upper karma and @nocturne remnant!

[upper karma]

is tanh (x) inverse tan ?

[obtuse yew]

https://en.wikipedia.org/wiki/Circumscribed_circle

[limpid flint]

<@&286206848099549185>

[nocturne remnant]

solve for tan(θ_2) by expanding tan(θ_1+θ_2) = 1

[lusty needle]

Its hyperbolic tangent fn

I don't think it even gets used

[silver thistle]

arctan(x) is the inverse tangent function

[upper quarry]

Law of sines indicator is 2 <A

Law of cosines is 2 S

And there's two triangles if 2 angles add up to over 180 degree

But what degrees get transferred over

[silver thistle]

@limpid flint

Let me know if anything is unclear or if you have any questions.

[limpid flint]

Makes sense thanks

[silver thistle]

Anytime.

[pulsar garden]

Hi to everyone

Can i put an intersection point for building in euclidean geometry?

Basically i added that F point because of the intersection of CC' and AB

[pulsar garden]

Basically its the only thing i need to know to proof something since i can't proof in any other way that CC' is bisector of angle ACB and angle AC'B

[dawn dirge]

guys how to solve this?

[silver thistle]

Let me explain.

[pulsar garden]

thank you

[silver thistle]

In deltoids, only one of the diagonal lines bisector the other, let's assume that CC' bisectors AB

Then

The triangle C'FA and the triangle CFB would be the same triangle, since they have the same sidelenghts.

In that case, the angles AC'F and BC'F would be equal to each other.

Also.

The triangle ACF is the same triangle as CFB.

Which means

[pulsar garden]

opposite vertex?

opposite vertex angles

[silver thistle]

I am not sure, no comment.

[silver thistle]

The angle ACF is equal to the angle BCF.

Let me know if you think something about the proof is wrong, or if you have any questions.

[pulsar garden]

you can't do that since you don't know that since its not been still proven that AF = FB

[silver thistle]

I said we're doing an assumption since that isn't given.

[silver thistle]

^^

[pulsar garden]

i mean i already proved that AF = FB by using the first consistency criterion

having the CC' bisector isn't in the hypotesis

its on the thesis

[silver thistle]

Well... I am not sure then?

[pulsar garden]

its just my fault that i didn't gave you all the info

[silver thistle]

Oh-

[pulsar garden]

but i didn't because i wanted just to know if i could put an intersection point

in euclidean geometry

just to know if its legal

and i still don't know if it is a legal move to make

because the original draw is this

sorry

wrong draw

now better

[silver thistle]

Hmm.

[pulsar garden]

basically they are two isosceles triangle upside down

and i can only prove everything if i can put a point of intersection on AB interesection CC'

[desert trout]

Hello, I have some questions about radians and degrees. I have to calculate this sin(alpha) with the formula 2pi/360*(amount of degrees). I checked the answers (see excel below) but still couldnt make any sense of it on how to calculate it. Can someone help me?

[silver thistle]

Yeah, I mean without being completely sure, I don't think you can just say a line bisectors some other line out of nowhere?

[pulsar garden]

yeah that's\ the point

[pulsar garden]

use the proportions

[desert trout]

What are proportions?

[pulsar garden]

to convert degrees to radiants just xrad = xdeg*2pi/360

[pulsar garden]

idk if its the right translation, im italian

but basically its an equality of two ratios

[silver thistle]

Yeah he basically means you're doing cross multiplication in the formula: x/180 = rad/pi

[pulsar garden]

yeah

[desert trout]

If I try to just calculate it: 2pi/360*cos(0). I get the answer 0.17... while it should be 1 according to the answersheet

[pulsar garden]

or x/360 = rad/2pi its just the same thing

[silver thistle]

Mate 2pi radians is equal to 360 degrees.

Since 360/360 is equal to 1

and since

[pulsar garden]

because the cosine is giving you the abscissa

[silver thistle]

cos(0) is 1

1 x 1 = 1

[pulsar garden]

ur converting from radiants to deg or deg to radiants?

[desert trout]

From degrees to radii and then I need to calculate the sin(a) cos(a) tan(a)

[silver thistle]

Yes but we need a to know what their values would be.

[desert trout]

Im going to type over the entire thing in english and maybe then we can make sense of it.

[pulsar garden]

0/360 = xrad/2pi

it just gives you 0 radiants

because its 0*2pi basically

unfortunately things works differently in ohio

[desert trout]

This is the assignment

Its all I know and all that been given me.

[silver thistle]

Alright so.

I'll explain how you could do this.

[desert trout]

Top row are the answers

[pulsar garden]

im gonna leave it to you i guess

[lusty needle]

Yes

[silver thistle]

You can take over if you want, I wouldn't mind.

[pulsar garden]

basically you take any degrees you want

you multiply it for PI and then divide it for 180

now you got from deg to radiants

example: 5*PI/180

and then you got radiant

or, same thing (1/36)*PI

[desert trout]

Okee, so then I have the radiants.

But then I need to calculate then sin cos tan

Or is that bs?

Ok, Im fucking stupid

I need to convert to radii and then fill in the amount of degrees in cos sin tan

So just put in cos(10)=0.984

simply filling in the number in Sin Cos Tan

Thanks anyways! @pulsar garden and @silver thistle

[pulsar garden]

no problem

[silver thistle]

Anytime.

[storm loom]

i was wondering if anybody could help me with my geometry homework

[dreamy cave]

Anyone recall a rule saying (x and y are angles)

cos y = cos (pi/2 - x)

[pliant roost]

there is a rule that says cos x = sin(π/2 - x)

[timber cargo]

It's cos θ = sin (90-θ)

But that works too

Using theta is easier to operate with

[lusty needle]

↓↓

[somber coyote]

anand

[hollow sphinx]

How does one find the trig ratios for any given real number not just special angles or the ones that can be solved using Sum & Diff formulas n its derivations. Without usin a calculator.

[dark sparrow]

you cannot.

[lusty needle]

💀

[hollow sphinx]

Like sin(167pi/900)

[hollow sphinx]

How computers/calcs do it?

[dark sparrow]

taylor series, probably

it gives an approximate result (but with precision that can go as high as you want) and is too laborious to carry out by hand

[upper karma]

Not my question, but what exactly are the limitations of Taylor series?

I have never fully finished learning about it, but other than the radius of convergence, is there anything that dictates if a function can be Taylor'd or not?

As long as you can find a power series representation of that function?

[dark sparrow]

well to be taylorable your function needs to be infinitely differentiable

and yeah the power series itself needs to converge

[upper karma]

I see. But isn't that restrictive? Since a lot of functions have a small radius of convergence

[dark sparrow]

dunno what you mean by this. have you run up against such a limitation for a practical problem?

[upper karma]

Not really. Just generally confused about Taylor series since I rushed learning about Taylor series because I wanted to start Parameterization as soon as possible

I know how to Taylor, just not really most of the technicalities

[dark sparrow]

parameterization?

of what

[upper karma]

I guess I should relearn

[dark sparrow]

i think you should hold off on trying to pry into technicalities until you get at least one instance of them blowing up in your face

[upper karma]

Just the general concept of parametric curves and their calculus usages

[upper karma]

The "blow up in your face" Seems... Ominous

[pliant roost]

in real computation lookup tables and linear interpolation are used extensivelyyyy

[hasty karma]

can division by cos^2 x used to solve trig equations?

[shy blade]

someone pls teach me long division I am 13 in 8 grade and forgot

[hasty karma]

[dry current]

Help

[rancid heart]

can someone help with this

[winter grail]

if 65 + x = 180, what is the value of x

[upper karma]

Why, I think you've already solved it angle ABC = 48+18=66

[upper karma]

it's already solved ...

[upper karma]

what does the "5" written in red mean ?

[scarlet bear]

can someone help me with my maths homework im struggling as i recently battled leukemia and missed out on a lot of school... it is due tommorow and need someone to blitz this piece of work dm me please

[timber cargo]

Angle B is the sum of the interior angles C and H

[upper karma]

Pls help me

@timber cargo

[upper karma]

@upper karma I don't see x

Nevermind

[upper karma]

QA=16, because diagonals in rectangle bisect each other and moreover the diagonals are equal in rectangle

So win win situation, DP=AP=UP=QP=8cm

QA = QP + AP = 8+8 = 16

[upper karma]

And in the second part we can say by the properties of triangle in triangle APU

AP=UP = 8

Hence Angle 2 = Angle 3

=> 4x - 1 = 3x + 10
=> 4x - 3x = 10+1
=> x = 11

[upper karma]

If the sides of a triangles are equal , then the angle opposite to it will also be equal. Hence if two sides are equal , then the two angles opposite to the equal sides will also be equal. Q.

[coral tusk]

Random question

[upper karma]

@upper karma could u help with this

Is a 9 and b 11

Is anything mentioned about the type of quadrilateral it is?

if it is a parallelogram

[upper karma]

then its true

I figured it out

I got a 9/12

On the score

My other attempts I got 5/12

Big step up

Now I gotta tell my teacher tomorrow that I got it up

And hope my grade goes up

Good Luck and Keep practising!

help idk how 2 do proofs

Struggling in the same boat @upper karma

[hollow gazelle]

Can someone give me the answer for 3 4 5

[cedar smelt]

Can someone give me the answer to this?

[upper karma]

easy

i show u ok

let me do the work and i show

um sorry bus i have to leave now

<@&286206848099549185> somebody please help him as i cannot now

[modern zenith]

<@&286206848099549185> Help!

[tired tiger]

how

come

[pliant roost]

use the $\cos(\alpha+\beta)=\cos(\alpha)\cos(\beta)-\sin(\alpha)\sin(\beta)$ identity

[somber coyote]

DV Game

[crimson crescent]

Can someone tell me how to do this

[crimson crescent]

If shown, line AB and line CD are straight lines. Find x in each case.

Please @ me

[crimson crescent]

nvm

[lofty girder]

angle EOF is 60

[crimson pawn]

x=90-30 cuz they’re complimentary i think

y is the same

[digital nest]

How would you do this?

Find BC.

[timber cargo]

Y and 30 are complementary angles, meaning that they add up to 90 degrees. There-go Y would be 60 degrees. Angle O and angle Y are supplementary angles, meaning that their sum is 180 degrees. Angle O is also the sum of the two 30 degree angles and x. After doing some basic algebra, Angle O is 120 and angle EOF is 60

[timber cargo]

Is that an isosceles triangle?

If so, since BA and CA are congruent, 3x+5 is the same as 25. Find x and then multiply it by 2 to get the length of BC

[valid crypt]

How to do proofs

for triangles

they suck

[lusty needle]

Which type of proof?

Triangle similarity?

Triangle congruent?

Is a given shape a triangle?

The given triangle is of what type, like iso, right, equi etc

Which one ya mean?

[timber cargo]

Solve for their sides

[delicate roost]

Hi, I would like to ask a geometry question

segment rs is congruent to segment ts; segment ru is congruent to segment tu is given. prove measurement of angle rsu is 90. The shape shown is a triangle

[upper karma]

what's your general approach to something like this?

they solve it by squaring the first two equations. to me, that isn't obvious. is there a way to deal with these "trick" problems?

[sonic stone]

Say you have a point (a,b) and you want to rotate it 90/180/270 degrees

Do you have to change the point like this?

90° = (-b, a)
180° = (-a, -b)
270° = (a, -b)

[smoky jetty]

I'd say that's an isosceles triangle, where 2 angles with the same measures should have congruent opposite sides. So, from that illustration, b = c. Hopefully, my answer made sense and you could work it out!

[smoky jetty]

Angle AOE & DOF are right angles (90deg), thus Angle DOB + BOF = 90, in other words, DOB & BOF are basically equal to 90 degrees, but segment OB cut the sort of "wholeness" of the 90 degrees into two angles which in turn sums up to 90 degrees. Therefore, they're complimentary angles where angle_1 + angle_2 = 90 degrees. Now, applying the same concept based from the diagram, the "wholeness" of right angle DOB is cut into two smaller angles, namely angle y and angle BOF. Since DOB is a right angle, we conclude that angle y and angle 30 are complimentary angles, wherein the sum of their anglesis equal to 90 degrees. i.e 30deg + y = 90deg hopefully this helps

for angle x, there are multiple ways that I can think of that may certainly help you to understand how to get it. But just tell it here if u haven't solved it yet, and i may try to help again later... hopefully nerdier folks would find the sense of my explanations, lol

[upper karma]

Is it worth going back and revisiting highschool geometry? I have forgotten all about it and I probably won't touch any geometry until I reach differential geometry later

[upper karma]

don't go back for synthetic geometry. go straight to analytic (coordinate) geometry

[pliant roost]

diff geometry doesn't require synthetic geometry almost at all

[upper karma]

Is there resources on it besides basic calculus stuff?

[upper karma]

wow

[pliant roost]

well you can try solving some synthetic geometry tasks using analytic geometry tools

some tasks really need synthetic geometry but some may be solved with analytic tools

it's just that synthetic geometry tasks are not really need in reality and in many cases are just made up

because in the real world you often just stumble upon a curve in geometry (and that's where analytic geometry comes in!)

[upper karma]

prerequisites? linear algebra and multivariable calc.

for geo look:
https://mphitchman.com/geometry/GCTscreen.pdf
or
Geometry From a Differentiable Viewpoint by McCleary

[outer junco]

Bruh someone explain to me because I'm confused

[hasty karma]

there is
1/sinx^2 + 3/sinx + 2 = 0
can i solve it two ways?
first is to turn 1/sinx^2 into t:
t^2 + 3t + 2 = 0
and solve as quadratic equation
or multiply both sides by sin^2x, sin^2 x is not 0 because it would led to division by zero
1+3sinx+2sin^2x = 0?

if they are not equal, then why

in second case i can multiply it, right?

[nocturne remnant]

the two ways are pretty similar

[hasty karma]

they are right, ye?

no missing roots and other things

[hasty karma]

@next mantle

[hidden crypt]

sinx = 0 is not a root of 1+3sinx+2sin^2x = 0, so you won't get any bad roots and won't miss any

[hasty karma]

thx

[bright rover]

How do I do ii)

[upper karma]

I have a lot of questions that I don’t understand cause I was never taught geometry, starting with this.

[lapis moon]

length of a circular arc = radius × central angle

[upper karma]

tyvm

[thorn nest]

I just started a geometry unit, (grade 9) what should I know and not know?

[hasty karma]

know trigonometry

know everything else because it can be useful

[brittle lotus]

trig is a function. Geoemtry+algebra

aside from the idk 60 formulas, how geometry works on complex plane, some vector stuff, and coordinate geometry

quaternion is a bonus if ur bored

@thorn nest

[upper karma]

hypercomplex number

hehe

[wind shell]

I need help calculating the area of projection on a surface. (The green circle is area of projection). How can I calculate area of projection if I have the angle and height (second illustration). from which the beam is projected?

[late gust]

How do you reflect y=-x

[mortal night]

I assume you meant y = -x^2, which in parabolas, means that the usual 'U' shape becomes reflected around the x-axis

Here's the difference between positive and negative x^2;

https://www.google.com/search?q=y+%3D+x^2&ei=U1d4Y4eGHNmx4-EPhuWc2Ac&ved=0ahUKEwjH-_STsLn7AhXZ2DgGHYYyB3sQ4dUDCA8&uact=5&oq=y+%3D+x^2&gs_lcp=Cgxnd3Mtd2l6LXNlcnAQAzIFCAAQkQIyBggAEAcQHjIGCAAQBxAeMgYIABAHEB4yBggAEAcQHjIGCAAQBxAeMgYIABAHEB4yCAgAEAcQHhAKMgYIABAHEB4yBggAEAcQHjoKCAAQRxDWBBCwA0oECEEYAEoECEYYAFClBFilBGCHB2gBcAF4AIAB2gGIAdoBkgEDMi0xmAEAoAEByAEIwAEB&sclient=gws-wiz-serp&safe=active&ssui=on

https://www.google.com/search?q=y+%3D+-x^2&source=lmns&bih=601&biw=1280&hl=en&sa=X&ved=2ahUKEwje87mVsLn7AhU0k9gFHaFGDPYQ_AUoAHoECAEQAA&safe=active&ssui=on

[hearty plover]

Hey I need to help proving this

[upper karma]

Hello guys. May somebody please help me on this question. What does it mention below 360 for the indicated marking?

It looks like "ex" + alpha but I am not sure. Thanks.

[nocturne remnant]

ext ∠

.

took me a while to figure out

[dim gulch]

exterior angle

the value of exterior angle not #

[upper karma]

Thanks guys.

[pliant roost]

multiply both the numerator and denominator by the conjugate of cos x - sin x (which is just cos x + sin x), then simplify the denominator to cos 2x and the numerator to 1 + 2sin(2x), and then just get your result

[upper karma]

@nocturne remnant @dim gulch and one more thing, for the picture, i think my teacher made a mistake. The Interior Angle Measure of a Regular Polygon is:
S = [(n - 2) * 180]/n but he put S/n = [(n - 2) * 180]/n. Am I correct or is the teacher correct?

[nocturne remnant]

s is the sum of the interior angles

i think the teacher is correct here

[upper karma]

ohhh

oh i get it

so i am wrong

ok thank

you

[lusty needle]

Bro there's a direct formula for this

Wait ya can't apply that here nvm 💀

[nocturne remnant]

…without a calculator?

That seems crazy

[lusty needle]

Ikr

I used a calculator (thinking I would be able to understand how to do it)

But damnnn I'm out

[winter copper]

thanx bro vo hogya

[lusty needle]

How tf? 💀

Slide me the solution in dms

[lusty needle]

Oh that's it?

No simplification?

[winter copper]

hm

[lusty needle]

[nocturne remnant]

Wow 🤓

[smoky jetty]

why are the functions divided to 2?

[winter copper]

bro identity h

[smoky jetty]

i forgot, but can u elaborate?

[winter copper]

SIN C + SIN D = 2sin (C+D)/2 cos(C-D)/2

[smoky jetty]

been months since i've learned (not great, from school) those, but they seem to make sense. thx!

wait im quite getting it now, suddenly intrigued😳 lmao

[toxic reef]

does AP equal BQ

[main quail]

i dont know

[half perch]

how do you solve this question

[smoky jetty]

I'd suggest putting your initial understanding of those problems, then asking how to fill in the analyzed gaps.

[hasty karma]

need to find some origin offset for point-zoom

help

theese two transformations are beyond my understanding idk

so vector camera+mouse will have same world coordinates before and after scaling applied

you can see two marked triangles

they have some ratio

[hasty karma]

ok if i scale from 2 to 1 it changes 2 times

so purple will be larger than green 2 times

[hearty plover]

Ah okay thank you

[hasty karma]

i found one

but looks like it doesnt work

some weird shit happens here

it is just combination of two transformations

but i cant do this

Noone knows?

fuck

[upper karma]

i only know about the vector

ok

[hasty karma]

so what is the solution for problem?

[upper karma]

umm, idk

i just know that there is a vector lol

sorry bro

[hasty karma]

damn

[upper karma]

how do I find the base of a triangle within a triangle but the base is shifted up by some H-a

[nocturne remnant]

similar triangles?

[carmine ore]

what does two triangles are inversely congruent mean?

[crimson crescent]

I need help with doing statement reason for this problem

[upper karma]

I think this ties to knowing Statement, Converse, Inverse, and Contrapositive

https://www.varsitytutors.com/hotmath/hotmath_help/topics/converse-inverse-contrapositive

[cerulean bay]

is there anyway I could get help with this question?

[carmine ore]

Yo! Were basically doing the same thing. Is this for class? If you have notes for this, I'd love to have them.

[cerulean bay]

mhm its for a class

im kinda struggling rn

I believe i have some notes i could share with you though

[carmine ore]

This is asking you to proge triangle ABC is congruent with triangle CDA right?

[carmine ore]

Appreciate it bro

What class is it?

[cerulean bay]

highschool geometry lol!

[carmine ore]

:0

[cerulean bay]

yeah

nothing crazy

[carmine ore]

https://www.amazon.com/Math-Proofs-Demystified-Stan-Gibilisco-ebook/dp/B0012OYBW6/ref=mp_s_a_1_3?crid=14P0Y3FHQ3SY0&keywords=proofs+demystified&qid=1668999193&sprefix=proofs+demistif%2Caps%2C519&sr=8-3
I honestly don't remember doing proofs in geometry. But this is the book I'm using

So for the first one, you have to reason that the line BC is congruent with line DA right?

[cerulean bay]

yup

[carmine ore]

#help-28 message

I had a similar problem. This dude gave me a good template to follow.

Maybe you already know this, idk

[cerulean bay]

im trying to find the notes for ya

[carmine ore]

Sorry I can't be of more help

[cerulean bay]

no worries 😄

[carmine ore]

Ty bro

[cerulean bay]

I mean do u want anything specifically

or

cuz this is pretty simple stuff we are learning

[carmine ore]

Um

I'm trying to get my heard around how to solve proving something with what is givenm

If there are definitions, templates, or whatever

Like the format you showed looks exactly like my book. With the statement and reasoning.

[cerulean bay]

hmm alright!

[carmine ore]

Sorry, idk what else to say

[cerulean bay]

no worries

[carmine ore]

Like rn, are struggling with that problem cause you don't know where to start? Or you just don't know how to reason the statement with what is given or?

[cerulean bay]

rn im sturggling with the reasons

[carmine ore]

Cause that would probably help me find out what I want

[cerulean bay]

I know where to start

[carmine ore]

Okay

[cerulean bay]

for the most part

[carmine ore]

Oh bet

Okay

[cerulean bay]

I think

[carmine ore]

Maybe when you figure it out, you could tell me haha

[cerulean bay]

yeah im going to visit my teacher

and ask him about it

[carmine ore]

I'll also ask someone I know. Cause that will benefit us both

[lapis shadow]

anyone know the proof for appollonius' definition of a circle using the square sum of 2 foci?

I figure the center is the midpoint of the foci and the radius is the length of the median of the triangle formed

[rancid heart]

anybody someone got a video that could help me with geometric proofs, (segment proofs and postulate/theorms)

or a document

please

[lofty girder]

probably oc tutor has some vid on it

just look him up on youtube

[hasty karma]

why quaternions > trig

trig is same thing, as i see

and so far imaginary axis looks like fancy name for y

[pliant roost]

quartenions are 4-dimensional

[hasty karma]

sin^4 x

[smoky jetty]

theorems regarding parallelograms?

and that whole file itself. seems like some of the answer is there already

[candid path]

IM here

[upper karma]

Organic Chemistry Tutor

[upper karma]

1. Given
2. Given
3. Definition of Angle Bisector
4. Reflexive Property
5. SAS (Side - Angle - Side)

[civic sable]

Could i get help with this please?

[civic sable]

<@&286206848099549185>

[carmine ore]

Lmk if you find some

[rich wraith]

Hello do you help me for Trigonometry

[zinc zealot]

im trying to figure out how to solve this and i need to find the angles and the value of x and y

[low spade]

m<1 + m<2 = 90

set that equation up

at least

if im doing this right lol

that'll help u find x and then input that into m<1 and m<2 in order to find out the measures

i think u do the same for m<3 and m<4

if im right, i rlly hope this helps 😁

5x+11y+7x-13y = 90

12x-19y+6x+10y = 90

[zinc zealot]

can you explain the equation if you would

math was never my strong suit and combined with my ADHD i tend to wander off during lessons

@low spade

[low spade]

yes ofc

complementary means 90 degrees btw

[zinc zealot]

ik its just the xy in one equation is what confuses me

[low spade]

ohh i see

well

u need to add like terms

so

the equation would then be

[zinc zealot]

12x-7y=90?

[low spade]

12x - 2y = 90

WAIT

I THINK IM DOING THIS WRONG

[zinc zealot]

oh ok i asked for help earlier and they said that but thanks for showing the actual one

wym?

[low spade]

uhh

bc

theres like

no regular num without a variable

what math are u in ?

[zinc zealot]

geometry honors

[low spade]

oh so am i

[zinc zealot]

idk why the put me on honors i cant handle too much work at once

im trying to find the angle

[low spade]

okok

ill add u

once i find the time, ill see if i can solve it

and then walk u thru it

is that okay ?

[zinc zealot]

yea

[rich wraith]

Help

[timber cargo]

Тебе нужно сложное понимание того, что представляют собой значения триггерных функций при 0, 30, 45, 60, 90 градусах, и вам необходимо ознакомиться с единичным кругом, прежде чем решать эти задачи

[pliant roost]

он серб и может не знать русский (тут вообще английский сервер), а так да, ты прав, такого рода значения надо просто запомнить.
speaking about the second image: you also have to know some trigonometric sum/other identities like product-to-sum formula

[rich wraith]

Я знаю основные тригонометрические функции, но мне непонятно, как я могу это решить, у меня есть это, чтобы сдать завтра, если я не сдам, я получаю 1

[upper karma]

why are you equating this to 90?

12x - 19y is angle 3 which is said to be half of angle 4 which happens to be 6x+10y.

so I am just curious why you are equating this to 90.

[low spade]

omg

ur right

😭😭

tbh im not rlly sure but i did just finish a unit in my own geoH class kind of similar to it and i guess i tried to solve it like that ???

but i did end up realizing it made no sense

thank u 🙏

[trail lance]

Really need help, been stuck here since last night..

[onyx cloud]

do you know how to calculate the volume of a cube and a cone?

[upper karma]

yeah then you subtract one from the other

[timber cargo]

Yeah, I agree

[steep basin]

I don't see a cone, that's a cube and a cylinder. You find the volume of the cube and subtract the volume of the cylinder.

[rich wraith]

I know the basic trigonometric functions but it's not clear to me how I can solve this, I have this to pass tomorrow, if I don't pass I get 1

Plis me help

[steep basin]

Solve what? Trig functions are very powerful but part of the math is learning what they're useful for.

[rich wraith]

I need help to solve these tasks because I haven't been to school for 2 weeks

[steep basin]

Triangles have 3 sides and 3 angles. The trig functions help you take a certain number of sides/angles and use them to evaluate the value of another angle or side. Trig functions are ratios

If you give me side A and side B then I can give you side C. That's basically what they do. But I can't see your problems.

[rich wraith]

Can you calculate this task for me?

[smoky jetty]

whats tg and ctg?

[rich wraith]

Contages

[smoky jetty]

tangent and cotangent?

if it is, then I'm certain you're dealing with special triangle case (for the first image)

so, you're gonna solve for it?

[rich wraith]

I don't know how to solve it

[steep basin]

I can't tell what it wants either.

[rich wraith]

Can you at least help me with this task

[rich wraith]

.

[steep basin]

That's actually beyond my knowledge, sorry. I never learned the algebra tricks behind trig identities. I think if you were gone for 2 weeks then you might have to talk to your teacher about catching up.

[rich wraith]

Here in Serbia, professors are very strict and crazy

[smoky jetty]

i can try to help you with the first image

but first, state here what you know about those stuff, currently

specifically about special right triangle cases, (45° - 45° - 90° ) & (30° - 60° - 90°)

[rich wraith]

Thanks you

Can you write me on paper and draw the solution

[smoky jetty]

uhh

sorry but i cant atm, though maybe u could be the one doing it? i'll try, just reviewing for exams atm

first, here's the (30-60-90) case

those values can be obtained using Pythagorean theorem (as long as there are 2 given values from either of the 3 sides)

now, from that, u have all the values for the trig ratios

[tame ocean]

Hello

Could anyone in this group chat help me with trigonometry revision

[smoky jetty]

now, you'll just input the ratios of each trigo functions for the 30 deg

[smoky jetty]

may I know what lesson it's in?

seems familiar (but idk)

[upper karma]

Describe the set of points whose distance from x-axis equals the distance from the yz plane

[upper karma]

I know you are from Serbia, but here is a joke.

Where do Russians get their milk from?
Ans: mosCOW

lol

[crimson crescent]

I need help with doing statement reason for this problem

[rich wraith]

🐄

[onyx dock]

please PLEASE tell me how the fuck we get pi/12 from pi/4 and 11pi/6

[onyx dock]

OH MY GOD IM STUPID

[earnest stratus]

Hi i need help in geometry where do i go

[storm portal]

Just ask

[civic sable]

moving my problem from #math-discussion

[timber cargo]

If two shapes are similar, then their areas is square of linear ratios

Just find x

[upper karma]

ask Divive Life

[real oar]

Are things like sin=Opposite/hypo, cos=adjacent/hypo etc a part of a unit circle?

Because iirc
The identities like
sin² + cos² = 1 are a part of unit circle, right?

[nocturne remnant]

what exactly do you mean by "part of a unit circle"?

[real oar]

Someone suggested me a website related to that, lemme, bring it up.

This site.

[real oar]

Are they related to a unit circle?

Just like how identities like 'sin² + cos² = 1' are related to unit circles.

[upper karma]

what do i do after this??

[upper karma]

why not try to represent sec and tan in a standard sin cos form?

it should simplify a bit
to make it a less stressful fraction

[heavy vigil]

sec^2x is the derivative of tan x

use substitution

[upper karma]

this is calc

[gleaming coyote]

Hello^^ Im really sorry but can someone help me on this pls

[timber cargo]

Pythagorean therom

[gleaming coyote]

BC^2=AB^2 +AC^2 right?

[timber cargo]

AC^2 = AB^2 + BC^2

Ac is your hypotenuse

[gleaming coyote]

okok tyy^^ ill try to punch in the numbers

[timber cargo]

Bc and Ab are your side lengths

[gleaming coyote]

Is 109 the answer?

OH WAIT NO I FORGOT TO SQUARE HOLD ON

[timber cargo]

Nope

108

Square root of 108 in the simplest form is 6 radical 3

[gleaming coyote]

ohh okay tysmm^^

i think I calculated it wrong tysmm^^

[gleaming coyote]

excuse me but can someone help me on this cause my answer reached the thousands and it just looks wrong

oh wait no i think i got it now

[pliant roost]

it's just the AB² = BC * BD

[lusty needle]

Is this a theorem ?

[upper karma]

hello, i have a problem that should be solved with the pythagoras theorem but i have no idea how to solve it: Leon wants to fit a piece of furniture into his new apartment. He measured the distance between the floor and the ceiling: 221 cm. He will have to pass his piece of furniture through the door, setting it down. Its cabinet is 212 cm high and 80 cm wide. He is reassured, because 212 <221. What do you think ? Justify.

[little plank]

this is literally just AC^2 = AB^2 + BC^2

and from there you take AB^2

so that would be:

AB^2 = AC^2 - BC^2

or

AB = sqrt(AC^2 - BC^2)

sqrt means square root (i dont know how else to represent this)

[gleaming coyote]

It’s fine tyy^^

I’ll try to punch in the numbers again the one I did was wrong 😭

[little plank]

gl and if you get it wrong just send your calculation here

[pliant roost]

yep

a length relation between a tangent, a circle and a secant

works for two secants or two tangents (in the second case they're just equal lol) too

[lusty needle]

O

[upper karma]

If the angle between 2 lines is 0 it means they're collinear right?

I know that it means they're collinear if they're 180degrees apart. I just wanted to make this sure

[pliant roost]

yes, but if they're vectors then they're opposite when 180 degrees apart

[upper karma]

Yeah thanks. But then they're still collinear right?

[pliant roost]

yes

[upper karma]

Lovely, thanks

[pliant roost]

collinear is lying on the same line

[upper karma]

Direction can be ±180° and magnitude wouldnt matter then

[crisp sandal]

Hi, why is (sinx)^2 = sin^2x and not sin^2x^2?

[pliant roost]

because mathematical notation commonly just says $\sin^2 x=(\sin x)^2$ by definition

it's just the notation

[somber coyote]

DV Game

[pliant roost]

also remember that $\sin x = \sin(x)$, it's just a function

[somber coyote]

DV Game

[upper karma]

i think it is because sin is a function

x is not a function but rather a variable.

and by definition, variables are subject to change.

[proven tusk]

anyone know how to solve this?

like i understand that you're supposed to put how you got to that answer but I have no idea what I'm supposed to be put as an answer

[opal storm]

yes

[opal storm]

1. given 2. substitution 3. combining like terms 4. subtraction property 5. division property

"...property of equality"

for 4 and 5

[proven tusk]

thanks

[storm portal]

What have you tried?

[proven tusk]

so far what i have is 2y + 120 = 180 and then 4x + 4 + 2y = 180 to figure out the values

[zinc zealot]

how can i solve this question?

[proven tusk]

solved

[storm portal]

Start by drawing the picture

[zinc zealot]

got that part

how do i solve the equation tho

[storm portal]

You’ll need to rely on your picture to help with that

[zinc zealot]

i did 6m+17 + 4m+3
10m+20 hwta do i do next?

[timber cargo]

4x +4 is also equal to 120

[rich wraith]

Hi does anyone know how to solve this

[silent plank]

there doesnt seem to be an actual question there

[timber cargo]

nor is that eligible to read

other than that trig identity

[tawdry cloud]

Given the line is tangent to the circle and the triangle is isosceles and inscribed, how can I solve for x? f(x) is some linear function.

[muted iron]

let tanx = t
sec²x dx will be replaced by dt

integrate

[muted iron]

basic geometry.
vertically opposite angles are equal, hence, 4x + 4 = 120. find x.

then, use 4x + 4 + 2y = 180 to find y

[hushed tendon]

Hey guys I need some help here

Does anyone know how to do this method?

[hushed tendon]

Thanks

[rose turtle]

Need some help here , Thanks

Same with this please

[heavy vigil]

since its a rectangle, every angle is 90 degrees

[heavy vigil]

use similarity of triangles to find y

[lunar tartan]

Does anybody know how you're supposed to prove this?

[timber cargo]

Can you rewrite that in better hand writing that way it's eligible to read

[lunar tartan]

Yes no problem

Is this better?

[timber cargo]

Yes, much better

[timber cargo]

So, start by drawing an equilateral triangle

Each angle would be 60 degrees

And Tangent of 60 degrees is the square root of 3

And since you're adding the square root of three three times, you can note the sum of that as 3 times the square root of 3

@lunar tartan Does that make sense so far?

[lunar tartan]

Yes it's very clear thank u

[timber cargo]

Okay, but I'm not done yet

So, we've proved that the left hand side of the equation is equal to 3 times radical 3

Now, over to the right hand side, we are taking the product of radical three three times

@lunar tartan How you studied the product laws with exponents?

and square roots

[lunar tartan]

English is not my first language but I'm trying my best wait

[timber cargo]

Have you learned these notations yet

[lunar tartan]

Yes I have

[timber cargo]

Okay, that's good

So do you know how to multiply the square root of 3 three times?

[lunar tartan]

Yes it's square root 27

Or square root 9 times 3

[timber cargo]

Yes

correct

[lunar tartan]

And that becomes 3 times Square root 3

[timber cargo]

Yes

beautiful

[lunar tartan]

So that is the answer than

[timber cargo]

Yeah

[lunar tartan]

Thank you so much

[timber cargo]

You're very welcome

[violet shadow]

This question says

Cos(theta)=root3/2

And it says ‘find tan theta’

I got tan theta =(4root3)/7

But the answer page seems to be in the wrong place is this right?

Because I first got tan(theta/2)=the 4root3/7

But idk if it’s a 4 or an 8

[timber cargo]

Can you write out the question on a piece of paper?

@violet shadow

[timber cargo]

Right so, do you know what theta has to be in order for the cos of theta to be root 3 over 2

[violet shadow]

Ye

Inverse cos

Never mind I got this

I think u just use SOHCAHTOA lol

[upper karma]

SOHCAHTOA

yep

[weary moat]

https://tenor.com/view/spongebob-squidward-krakatoa-volcano-erupting-gif-4580897

[pliant roost]

what a weird acronym actually

[wispy sapphire]

I joined this server because I despise geometry

[upper karma]

geo is easy

[upper karma]

yeah

it is just weird

[upper karma]

muhahahhahahahahaha so funny heheheheh mmamamammamamas papapapappapa i am crying hehehehhehe

actually tho

i am laughing

[white mesa]

Useful tho

[ashen shuttle]

wait the pytagorian theorem is like a^2+b^2=c^2?

right? just making sure

[stiff dock]

Yup, that's it

[ashen shuttle]

thank you

[stiff dock]

np

[sick gulch]

Hello i have a question hehe

Whats the best tip in order to solve trigo. Identities easier?

[stiff dock]

maybe converting everything to cosine and sine, but i'm not really sure

that only works most of the time, though

[nocturne remnant]

there's no "best" tip for trig identities especially if they involve using compound angle (/ sum-to-product) formulas; there are just so many ways to do them

[upper karma]

yes

with c being the hypotenuse and a,b being the two legs

Pythagorean theorem only applies for right triangles

and then you get into stuff like Pythagorean Triplets

fun

now imagine Pythagorean theorem in 3d, 4d, and mixed with p - acidic numbers, hyper complex numbers, matrices, non linear partial differential equations, polar coordinates, and etc.

hehehhehe

[upper karma]

u know what is funny

your pfp has Pythagorean theorem

[ashen shuttle]

thank you guys

this server is so good

[upper karma]

Your Welcome

[stiff dock]

that's exactly what i thought answering that

[timber cargo]

O, I like that a lot

[upper karma]

Does anyone know if this is right?

[vestal ore]

Soit H l'hexagone du plan d'Argand-Gauss dont les sommets sont les racines du polynôme p(x) = (x- √3)^6 +64. Déterminer z ∈ C sachant que l'ensemble M ={zx ∈ C : x ∈ H} est l'hexagone qui a v1 = –1 + √3i, v2 = 1 – √3i et v3 = 5 – √3i comme trois sommets consécutifs.

[sonic willow]

my epic physics teacher is saying that we will add 14 vectors of force and calculate acceleration from that

(Im at beggining of 1st grade of high school by the way)

Is this hard?

[upper karma]

Are you trying to find area or perimeter?

[upper karma]

Perimeter

[severe orbit]

Hey can someone help me with a proofs question (geometry)

[ripe linden]

2+2=5

[crimson crescent]

I need help with finishing this statement reason

I already put the given

The rest of my statements are AD=BD, m<ACD=m<BCD, m<CDA=m<CDB

I need help with finishing it and the reasons for those statements

[upper karma]

hahaha

lol

[upper karma]

You are incorrect my friend. (you are trying to find the perimeter)

[upper karma]

Could you help me out then?

[upper karma]

Yes, I am doing that

just remember that the formula for perimeter is 2l + 2w (l for length and w for width)

[upper karma]

Thank you

[upper karma]

yw

[flint ravine]

preaty simple and probably over thinking it but x=3/4y and x+4 is 12 its for a basic midpoint thing and agen I'm prbably overr thinking it but this unit is rlly stumping me so can anyone help also is doesnt say round so its to the fist decimal or less

[hasty karma]

how to understand trig(a+b) and trig(a)+trig(b)?

all i know is that there are some fancy formulas ill never manage to learn exactly so i need some way to workaround it

so far i came with idea of shifting curve for sin/cos/tg of (+- x + n*pi/2), where n is some integer (Z)

i noticed shift when sin and cos added, so sin(x+1) = k(a sin(x)+ b cos(x))

there is also some unit circle way described in textbook, but any attepments of understanding it as book says had no success

||sin(x+1) = (a sinx + b cosx)/c, a ~ 2.5, b ~ -3.9, c ~ 3.2758*sqrt(2) dont ask||

i guess this way isnt the right one, because original formula looks like sin a cos b - sin b cos a

damn

[brave quiver]

i prefer this over the circle way of doing it

[flint ravine]

sorry nvm I figured it out

[acoustic ibex]

What are some ways to figure out if a quadrilateral is cyclic

also can someone give me a breif idea about what barycentric coordinates are?

[red hollow]

im in 8th and this makes ZERO SENSE TO ME

[brave quiver]

do you know anything about trigonometry?

[sonic willow]

cool

[cedar venture]

i have a question: how to work out sin cos tan and inverse sin cos tan by hand? like for example how do i work out sin90 by hand without calculator?

and what happens if you sin cos tan something?

thanks

[timber cargo]

Practice with a Unit Cricle

Really understand the mechanics behind it

[cedar venture]

thanks

[halcyon spindle]

you can use ptolmey's theorem or just add the opposite angles to verify if the sum equals 180

[jade valley]

can someone send me a link to a resource on trig

[upper karma]

Search up Arihant Trig pdf, AoPS precalculus and etc

[copper lava]

valid

[copper lava]

Given:

[copper lava]

Given: <A=<B and CD bisects AB

[copper lava]

CD=CD is deffinition of bisect

[copper lava]

AD=DB reflexive

[copper lava]

CB=CA also reflexive i think

[twin seal]

please help

[vague rapids]

dog i was about to ask the same shit proving triangles sucks so hard

its useless too when are you ever going to have to prove a triangle ina 9-5

[timber cargo]

Since those two smaller triangles are similar, then length DB and length BF are similar

[upper karma]

yay

[spice condor]

Can someone remind me what bisect means

[heavy vigil]

divide into two parts

[spice condor]

Do they have to be equal?

[graceful axle]

can someone help me with my practise test

[analog plank]

Someone help me with my practice test?

[graceful axle]

in Vc

[analog plank]

in Vc

Please We’re desperate.

[devout umbra]

Dammn

[upper karma]

yes

[upper karma]

prove that using the first principles of differentiation

[rich wraith]

I have a test tomorrow and I don't know anything about acute angle trigonometry

If you can show me everything from the beginning so I can understand

[upper karma]

How would this be solved?

[hoary ether]

This is part of a larger physics problem involving lattices etc. Can somebody tell me what the component of i is here. I’ve already messed up and done a lot of working with the incorrect vector

Solving for the vector b

Current best guess is sqrt(3)a i

[zenith quiver]

Big ideas math

[lofty hawk]

how can i tell whether 2 triangles are AAS SAS ASA SSS or HL

[flint ravine]

did you get a good answer/do you still need help

[calm tangle]

How would I do this? Help would be much appreciated

[flint ravine]

wait I doent remember doest that mean congruent or simalar

[timber cargo]

Congruent

[flint ravine]

ok thanks

[timber cargo]

Seems that side length MS is proportional to side length DT

[flint ravine]

well what I would do to solve it is that is said sm=td so that would give you 3x+4=4x-3 and y=hopefully you can solve that

[timber cargo]

So just set them equal to each other and solve for x

@calm tangle

[calm tangle]

Would it be 7

If 3x+4=4x-3

[timber cargo]

Yeah

[calm tangle]

Thank you

[fierce vigil]

how would I do this? any help is appreciatd

[upper karma]

I got@it@ty

[smoky jetty]

draw it?

i think it's something like this , I really hope I understood that angle of elevation correctly (ignore the square)

then use Pythagorean theorem (solution of a right triangle)

where sin 37deg = x/ 120 (correct me if im wrong)

[kindred sand]

prove that FA = FE knowing that BC is perpendicular to AC, AD = 1/3 of AB and CE = BE

[upper karma]

hi ik this is really dumb to ask bt i overthink questions lots so
5. Calculate:

(a) cos120˚, cos135˚, cos150˚;

does ths mean i just calculate the value of each

[rotund raft]

hi, sorry if this is the wrong place for this, but what's the difference between these two

in the context of wallpaper group notation

[timber cargo]

Yeah.

Find the value of cos of 2pi/3

etc...

[subtle orchid]

can someone help with geometry question in #help-40 thxxx

[deep vapor]

Good afternoon, how would I do this problem. Please and thank you

[mental cloud]

how would i go about solving this?

[crimson pawn]

measure of <1 is 180- measure of <2

[deft galleon]

@fierce vigil this is late but heres a better picture of what its asking

h is the satellite height B is the buidling

[lime pivot]

can anyone double check my work?

[smoky jetty]

Ohh woww, thats more accurate!!

[pliant roost]

how do I solve sin x = 2cos x + 1? idk why, but I am so stumped

[dark sparrow]

theres a slightly bullshit way to solve this

[heavy shale]

u can try squaring both sides

[dark sparrow]

that doesn't involve squaring both sides.

[heavy shale]

cant u just square both sides and then convert sin^2 x to cos x

and then solve like quadratic?

[dark sparrow]

you will gain extra solutions

[heavy shale]

oh ok

[dark sparrow]

it will be kind of a pain to sift the true ones from the extraneous ones

replace the variable in the original equation with t so that the letter x is free for use. (partly because i don't want to introduce inconvenient notation)
so the equation is sin(t) = 2cos(t) + 1
now let x = cos(t) and y = sin(t)
then you have two equations: x^2 + y^2 = 1; y = 2x+1

this is a system that can be solved by substitution among other methods

you will get two (x,y) pairs as your solutions

each one corresponds to an angle (up to coterminality)

[pliant roost]

smart

thank you

[woven fulcrum]

how did this happen?

[upper karma]

How to do trig identities

[woven fulcrum]

whyis 5pie/3 not used and only -pie/3 and 4pie/3

[amber crater]

I asked 8 ppl but no one can solve it

[royal quest]

Hello 👋

How do I solve this it’s the correct answer but I do not know how

[woven fulcrum]

oh okok thank you

[onyx cloud]

do you know what FU, FV, and UV are?

[crimson pawn]

Wouldn’t they be like segments on a line or sum

[severe orbit]

Hello can someone help me with this geometry fill out proofs question?

Number 7

[latent flame]

Anyone able to come up with a slick way to get the purple point? Both intersections of the line with the circle are known, but if you know of a way to get the point without the northern intersection, that would be more ideal.

That shorter line drawn is the tangent line to the circle at the first point of intersection.

[latent flame]

The line that goes to the bottom of the page intersects this circle at two points. Those intersections are known. The tangent line at each of those intersections is known, one of them is drawn. The question is how to get the point on the tangent line, where a line that is both perpendicular to the first tangent, and also tangent to the circle would intersect it.

Now I'm thinking it might work to find the points on the circle where the slope of the tangent line on the circle is perpendicular to the slope of that first tangent

[latent flame]

im like 80% sure this would work, and it would narrow it down to two points on the circle

its the tangent at the southern point of intersection

[neat sparrow]

could anyone hop in a call and help me with segment and angle proofs?

[neat sparrow]

?

[opaque gull]

How would you do sin x = -4.5 in interval 0 to 360

[pliant roost]

there is no such x

-1 ≤ sin x ≤ 1 for all x

[opaque gull]

Thank you

So undefined?

[celest crow]

where can i get year 9 questions on angles in circles(Geometry)

[green fern]

helppp T.T

[pliant roost]

no such x

[crimson pawn]

you would need to break it into a rectangle and a triangle

then find the areas seperate and add

2x is 4 meaning x is 2

1/2 * bh
1/2 *2/1=1 *2sqrt3=2sqrt3 as the area for the triangle

[heavy shale]

^

But u can also use trapezium formula

[somber coyote]

NotMyself

[crimson pawn]

then find the area of rectangle: lw=a
82sqrt3 is 16sqrt3 +2sqrt3

=18sqrt3 answer is C

@green fern

[smoky jetty]

refer to its theorems prob

ably

[snow falcon]

anyone know this?

i need help

@viral merlin do you know this?

[viral merlin]

maybe I do

maybe I don't

[snow falcon]

Can you help?

I've been stuck for the past hour

or no

@viral merlin

[viral merlin]

what does ABCD~QSRP mean

[snow falcon]

idk that's the thing

its these

its the sides

of the shapes

[viral merlin]

idk what it means either

I never did geometry

[snow falcon]

aghhhh

[crimson pawn]

it means that the first shape is similar to the second shape

[snow falcon]

idk how to get the answer

[crimson pawn]

magic

you know what similar means in terms of shapes right

[snow falcon]

no..

not rlly

[crimson pawn]

Essentially means that the sides are proportional

like one side on the first shape is proportional to the one on the second

also all the angles are alsways the same

[upper karma]

should be y = 32, x = 63

[upper karma]

Let ABC be a triangle such that AB = 40, BC = 30, CA = 14. If H is the orthocenter of ABC, then find the radius of a circumcircle of the triangle AHB.

https://tenor.com/view/help-kermit-frog-halo-alo-gif-20777482

[eternal slate]

Hey guys can you pls help, Which formula (name of formula) can be used to make a straight line from E to the circle?

[green fern]

Thank you so much

[timber cargo]

I don't understand the question

[eternal slate]

all good

i was being stupid

[crimson pawn]

if a banana is taken off a tree and it is browning, is it fresh?

[eternal slate]

i found a solution

[crimson pawn]

that’s what he meant

[eternal slate]

yes

[hasty karma]

~ means they have same ratio?

like AB=PQ*k, where k is some coefficient

same for other sides and all angles are same

if so, it isnt quite hard to solve as i see

i could help

[heavy shale]

This ~ means ABCD is similar to PQRS

and one property of similar shapes is their corresponding angles are equal

And since ABCD~QSRP

angle d = angle p

and u can calculate x and y like that