geometry-and-trigonometry

[silent plank]

right angle isn't needed for what's being asked and shouldn't be assumed

[smoky jetty]

ohh interesting, do u think the problem is doable?

[silent plank]

using a reasonable assumption, yes

[smoky jetty]

what could a reasonable assumption be?

[silent plank]

assume which sides are corresponding based on which sides look longer

[smoky jetty]

but are the two triangles' angle values supposed to be similar? I've never heard of similar pair of triangles before

[silent plank]

you've never heard of similar triangles before?

[smoky jetty]

yeah

whats its basic concept?

[silent plank]

all angles the same
corresponding sides in same ratio

[smoky jetty]

corresponding sides? only learned that in geometry a week ago, but it wasnt about triangles. googling it a bit

oh i get it

pretty much the same with parallel line cut by transversal thingy, in terms of concept

do u know how to work it out?

[silent plank]

yes

[smoky jetty]

can u show how? like the not so exact explanation of steps only

[silent plank]

corresponding sides in same ratio

[smoky jetty]

might try this tomorrow, thx

[errant pulsar]

hello, this was asked by someone else but i’ve been wondering how to go about solving it.

it is given that DA is parallel to BC and EA parallel to DB and N, M midpoints of ED and DC, then show that the red area is equal to the blue area

[upper karma]

https://forumgeom.fau.edu/FG2012volume12/FG201220.pdf

^ Sherman Line (A triangle having 4 sides? nah! well, actually yes!!!)

[brittle rivet]

Anyone have some ideas or tricks to memorize the unit circle? I have to be able to fill this out from a blank circle. Thanks.

[still dagger]

To remember the first quarter you have three values to remember. The sine will be increasing will the cosine will be decreasing

[sly raptor]

The way I remember the unit circle is that sqrt(3)/2 is larger than 1/2 and then I can always deduce that, because pi/3 has a larger y than x, it has to have (1/2, sqrt(3)/2) as its coordinates.

And just remember any pi/4 is sqrt(2)/2

Also keep in mind quadrants

[brittle rivet]

Yes I understand that. Where I get messed up on is how they get from say pi/6 to 5pi/6. I forget where they are counting from

[sly raptor]

Ah

[brittle rivet]

Oh wait it's a 30 degree angle so it's every 30 degrees right?

[sly raptor]

I like to change it to degrees and then find the quadrant, and then specify the angle for myself

So 30*5 = 150

Yep

So I know it's 30 below 180, which means lower y than x

[brittle rivet]

Light bulb moment 💡

[sly raptor]

Nice!

[brittle rivet]

Right that totally makes sense

Ty ty

I made a ton of copies and I'm trying to fill it out from blank haha

[sly raptor]

Np, good luck with your unit circle adventures

Not a bad idea

[brittle rivet]

I'm getting better. Thank you for the sage advice sir

[smoky jetty]

wow thats so interesting, actually, u dont necessarily need to remember everything, there are formulas to find those values

[heavy mango]

I have a question: How do I solve a trigonometric function with a constant inside it? I'm referring to this. f(x)=2tan(4x-32)

If I plug in pi/4, for example, how would I solve 2tan(pi-32)?

[smoky jetty]

in the first quadrant, there are 3 angle values that are part of a special right triangle case, so the sine values of those can be found using the Pythagorean theorem. Then on the 2nd quadrant, find the sine function of angles between 0 degrees to 360 degrees. First, you'll get their reference angles (wherein in Q2, Theta _R = 180 - theta, Q3 Theta_R = theta - 180, Q4 Theta_R = 360 - theta) and from there on, you'd have special angles again, which are part of a special triangle case, thus giving u identical values ( TAKE NOTE of the negative values). Then for those sine values lying at the quadrants, you'll be finding quadrantal angles, where r = 1. Find those using the Pythagorean theorem. For the radian measurement, u can just convert degrees measure using theta*(pi/180)

so in conclusion, I'm pretty sure u can find those sine values using formulas to find reference angles (for angles between 0-360 degrees which in your case, for angles in Q2-Q4), quadrantal angles, and the Pythagorean theorem.

[errant pulsar]

i’m sorry if i’m mistaken, but is this something related to my post? if so i wonder how, if not ignore me

[austere hearth]

g(x) = 2 − 6 · cos2
(x) − 2 · cos(x) · tan(x)
someone help please

[dark sparrow]

bad copypaste + no problem statement

[austere hearth]

sowy me dum

solve for x g(x) = 2 − 6 · cos2
(x) − 2 · cos(x) · tan(x)

and about the coypaste nothing can be done

[dark sparrow]

yeah it can

you can post a screenshot instead

be sure to include all instructions to go with this

[austere hearth]

too lazy need to do other work . forgive ?

[dark sparrow]

well sure but if you're too lazy to post your problem here you won't get any help for it

so if youre ok with that then ¯_(ツ)_/¯

[austere hearth]

booo

At which points do the functions intersect the coordinate axes?

@dark sparrow good 🙂

[dark sparrow]

so, do you want to get help with this problem or do you just want someone to do it for you

[austere hearth]

help or step by step solutions

[dark sparrow]

it's just that "too lazy need to do other work" makes me think you wouldn't want to cooperate on being taken through this problem...

anyway

you want to find the intersections of the (graph of) this function with the coordinate axes.

i.e. you want to find its x-intercept(s) and y-intercept.

do you understand what this means?

[austere hearth]

yes ik

[dark sparrow]

ok

do you understand what you need to do to find the y-intercept?

[austere hearth]

x=0

[dark sparrow]

"I need to set x to 0, or in other words I need to evaluate g(0) to get the coordinate of the y-intercept."

ok

are you able to do this on your own?

[austere hearth]

yeah

[dark sparrow]

alright

do you understand what you need to do to find the x-intercept?

[austere hearth]

yeah

but aint workin

[dark sparrow]

in what way is it not working exactly?

is it:
(a) you tried to solve the equation g(x)=0 but got stuck along the way,
(b) you solved the equation g(x)=0 but couldn't figure out how to write down the answer, or
(c) you solved the equation g(x)=0 and got an answer, but your homework system rejects it?

[austere hearth]

b

[dark sparrow]

ok, show your work so we can take a look.

[austere hearth]

nevermind me dum

i forget the minus

https://tenor.com/view/shy-anime-embarassed-girl-gif-15974488

thx u though appreciate ur help sorry for waisting time

@dark sparrow

but then when i solve i only get the t=1 and t =-2/3

so pi/2 and -pi/2 plus 2kpi

but for the t=-2/3 idk

its -41,40

not matching the answer

[dark sparrow]

,w 3sin^2(x) - sin(x) - 2 = 0

[somber coyote]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Ann#0413

[austere hearth]

yes but he got 5,55 for answer 1 and 3,87

and we dont have a interval so i put nr in it for k or n in this example

[dark sparrow]

who's "he"

[austere hearth]

he teacher

[dark sparrow]

can you show the teacher's answer

[austere hearth]

its only the answer without the method

[dark sparrow]

i think it might be some sort of radian vs degree issue

[viscid trellis]

Hello

[dark sparrow]

,calc sin(5.55)

[somber coyote]

Result:

-0.66923985727626

[dark sparrow]

ok yeah your teacher just put things in radians

[austere hearth]

ok me very dumm

thank u

thank u very kind of u

wish u a lovely day

[zealous pivot]

How is this not a contradiction? The perimeter is 700+223+400+282=1605, while XY=953 ??

I'm suspecting the circles ought to be centered at the midpoints of AD and BC, respectively. But the statement does not indicate that.

[dark sparrow]

these circles need to have diameters AD and BC as in those actual segments need to be their diameters

[zealous pivot]

yeah makes sense

[zealous pivot]

This is not too worrying, but is there a keyboard shorcut to start writing on the input bar of geogebra (instead of having to move the mouse and click on the input bar)? I tried searching but didn't find anything, idk if anyone knows.

[smoky beacon]

What does orthogonal unit vector mean

[flat ivy]

At right angles

[pliant roost]

if I remember correctly, orthogonal unit vectors are the vectors that satisfy the following properties:

1. They are all linearly independent
2. They are perpendicular to each other in the respective planes
3. They have unit length (obviously)

[flat ivy]

Yep

[pallid quest]

Does anyone have any tricks for tangent inverses? Because im struggling to recognize which points fit

[zealous pivot]

Let ABC be a triangle, let N lie on the side BC such that AN is twice as long as CM, where M is the midpoint of AB. We also have that the angle ANC is 45 degrees. Prove that AN is perpendicular to CM.

Couldn't solve this 😦 Help is appreciated

[vestal stag]

but what is L in ALC

[zealous pivot]

oh lmao

I write that wrong

[zealous pivot]

L was N, sorry I wrote it wrong (I edited the message)

[teal oriole]

when it comes to trig functions, if you have like
cos beinf 6/10 do u write it as 6/10 or simplify it to 3/5?

[polar path]

as 6/10 🙂

[teal oriole]

thank u!!

[upper karma]

doies anyone here use geogebra? please ping me i need help asap figuring out how to do area

[upper karma]

oh, sorry for my the late response. No, actually that is not related to your post above.

It was just a fun paper I found.

[zealous pivot]

Could eventually solve it xd

[slate mauve]

how do i prove this using a column proof (statement and reasoning)

[pliant roost]

you just write out the sum of the angles of a triangle

w + x + a = 180° and z + y + a = 180°, then the proof easily follows

[sullen kettle]

There’s a pair of parallel lines in there, and x=z and w=y because these two pairs of angles are corresponding angles. https://en.wikipedia.org/wiki/Transversal_(geometry)#Corresponding_angles

[sullen kettle]

This is also a very good argument. The two triangles share an angle, therefore the other two angle sums should be the same.

[pliant roost]

you weren't given that the lines actually are parellel, I mean it's only visual

[sullen kettle]

Ah I see, then your argument is correct and mine isn’t

[sullen kettle]

Provide the details

[hollow gazelle]

need help with this

[heavy shale]

you can see the direction of opening in the graph

[hollow gazelle]

i dont know anything about this lesson

[heavy shale]

Axis of symmetry is the line which divides the parabola symmetrically

[heavy shale]

just use english

where is the first one opening

up or down

coordinate of vertex is the point where the graph turns

[wet sapphire]

ILL HELP YOU BRO

sry caps

[heavy shale]

y-intercept is point where parabola intersects y-axis

and x-intercept is the same thing as y-intercept but for x axis

idk about domain and range

[hollow gazelle]

really

it depends on this whether i take summer class or nah

lmao

[wet sapphire]

isnt that algebra tho?

the work that your doing

[hollow gazelle]

uhm idk yep thats how bad i am at math

[wet sapphire]

lol

you can add me and ask anytime if you need help

[past phoenix]

hey anyone need help in finding area of triangle

[red jetty]

i do not know what you mean by this lol

[heavy vigil]

what is the question

if its general, just use Herons formula

[copper spade]

how can i prove this one?

[heavy mango]

Hi, how do I solve 2tan(pi-32)? What do I do if there's a constant inside tan(x), like the number 32 in this case?

Can someone help?

[grave pond]

What an utterly, totally inane problem.

It makes no sense, but the best you can do is pattern-match the wording and replace the so-defined word sequences by "p" and "q".

[simple swift]

I think the last one

[upper karma]

Well, they are corresponding angles I believe.

[proper bridge]

could somebody pls help me with this problem?

[craggy monolith]

help its literally 12am and this is due literally at 3am and my brain stopped working

[proper bridge]

sin(x)=8/10=4/5

[upper karma]

what was the name of this shape?

i remember faintly from years ago

that the small base

equals the big base over 2

so AB = 2CD = 6

forgot the rule of AD tho

oh a trapezoid

[loud talon]

y=22

x=26.5?

[tribal ore]

Already solved it a bit ago that isn't the right answer but thank you anyways

[loud talon]

I know, just solving for fun. Also, I am in a geometry class

so practice

[dark sparrow]

@loud talon don't give out answers in the future

[loud talon]

ok, sorry. Did not know that I shouldn't give out answers. Should I use /spoiler next time, or just don't give out at all?

[dark sparrow]

just don't give out at all

[ruby fulcrum]

wait wrong place

[upper karma]

Well, basic example of transversal

[upper karma]

Funny to say that as the answer... was not even an answer as it was wrong.

But I understand what you are saying. And @loud talon What method did you use to obtain those answers?

[young otter]

Do any of y’all know how to do this

[foggy crypt]

Draw a diagram.

[foggy crypt]

You will need to understand the definition of vertical angles.

[loud talon]

I solved for x and y.

[terse meteor]

Is this right

[glacial mural]

Hi is anyone available to help me with a project regarding geometry? I really need help and would mean alot ty

Please dm if you can.

[grave pond]

Please read https://dontasktoask.com/

[glacial mural]

Sorry

Mb

[grave pond]

Do you really read that fast?

[glacial mural]

Yes

Im doing a project to show how geometry can be applied irl and i chose architecture

What i have done so far and im not sure whether its relevant and my math is not very good 😔

[grave pond]

I doubt that. It makes your "sorry" sound rather insincere when it comes only a few seconds after I send you a link to a long text that explain what you're doing wrong.

[glacial mural]

I apologise to all as it may sound like im questioning your mathematical ability which i have no intention of. I sincerely am sorry if I have insulted anyone

I dont really socialise much so please forgive me.

[glacial mural]

Im new to forums and i didnt know how I should be asking 😅

[grave pond]

Well, it's just advice.

If you would really rather not get any help than reveal what you're planning to ask until someone commits to answering your question sight unseen, then go right ahead

[glacial mural]

I understand, thank you.

[olive hatch]

I have an object that has the height of 30cm and a diameter of 50cm. Using this information, how can I work out what the length and width of the item is?

[grave pond]

Is your object a cylinder? Otherwise it is not clear exactly what "diameter" means.

[olive hatch]

Is this question impossible to answer if you don't know what object it is?

[grave pond]

Yes. We need to know that the object has a shape where the word "diameter" makes sense..

[olive hatch]

No worries, can I post images here?

[grave pond]

If we know that the object is box-shaped, we can get a little further, but still the most we get is that W² + L² = (40 cm)², which has many different solutions.

You should be able to post images, yes.

[olive hatch]

Alright, so the object is a chandelier, but I'm not sure how this object will help 😐

It's a LED chandelier.

[dusky palm]

tan69+tan66-tan69tan66=2k, what is the value of k?

[dusky palm]

pls help

[grave pond]

Okay, that makes it clearer what "diameter" means, but on the other hand I'm now unsure what the "length" and "width" you're asking about mean.

[olive hatch]

The reason why I'm asking is because I'm trying to list these chandelier onto the tiktok marketplace and it's asking me for the height, width and length of the chandelier.

I have a sheet which shows me the dimensions but the dimensions tell me the height and the diameter only.

Furthermore, it won't even let me list this item because it says The volumetric weight must be less than 15.00kg. Volumetric weight = length*width*height/8000. which I don't understand.

[grave pond]

I'd assume they're asking for the dimensions of a box the chandelier fits into, or possibly the box it is shipped in. In the former case the width and length would both equal the diameter -- understood as the outer diameter of the horizontal circle.

"Volumetric weight" sounds very like they're talking about the shipping box.

[olive hatch]

So the dimensions aren't about the product itself, just the box it's shipped in?

Because on the top left, it says "product dimensions"

[grave pond]

That's what I'd expect, but that's not really a mathematical question. My immediate guess would be that the form you show does gets confused by writing "cm" in front of the numbers.

[grave pond]

Punch the expression on the LHS into a calculator to find 2k, then divide by 2?

[young horizon]

Hi please I need help with no4

[heavy vigil]

use distance formula to find the length of the given side

it should be equal to the length of the other 2 sides

[olive hatch]

This object has a diameter of 16CM and a height of 12CM. My question is, what is the width and length?

In this scenario, does diameter just mean width and length?

I might have extremely confused myself

Could I just say that the length is also 16CM and the width is also 16CM? Since the diameter is 16cm?

[dusky palm]

i cant use calculater in exam

there is restricrion in usage of calcuater

[silent plank]

consider 66+69 = 135

@dusky palm

[dusky palm]

ok

[grave pond]

Ah, clever!

[dusky palm]

figured it out

[placid rampart]

does someone

wanna

help me

fill out the work and answers

for my practice test

i dont really need help i just need yo see the work

and ill understand it

[grave pond]

No, we don't do that.

[placid rampart]

ok ig?

[young bough]

Can someone explain how to get the answer without a yx axis chart

[grave pond]

If the answer (or the approach leading to the answer) is not obvious, you should always draw a diagram.

[patent field]

Hey

So I have a point A(4,0) and apparently it's supposed to be on y= -x+6

But that doesn't sound right 😳

[grave pond]

Indeed it doesn't.

[restive mulch]

im sIow

[torn flare]

number 1, the angle would be the same as angle 4

i think its because of the corresponding angles theorem, im not sure

for the second one you would have to subtract angle 4 from 180 to get angle 5

[restive mulch]

👍

?

[river compass]

A line with a line intersecting it

That particular intersection's angles

Add up to 360

Meaning two angles add up to 180

So <7 & <2 add up to 180

Sorry if I explained that horribly lol

[paper blaze]

Using mass point geometry

[obsidian lotus]

indeed

using the linear pair postulate

[upper karma]

i can explain

so angle 2 is congruent to angle 4 due to them being Alternate Interior Angles.

angle 5 is 43.7. So you need to realize that angle 4 and angle 1 are vertical angles so they are congruent to each other.

in order yo find

in order to find the measure of angle 5 you need to realize that angle 1 and angle 5 are known aa Consecutive Interior Angles

and Corresponding Interior Angles always add uo to 180 degrees

so you do 180-136.3 which u will get 43.7

you need to know the following @restive mulch

-Corresponding Angles are Congruent
-Alternate Interior Angles are Congruent
-Alternate Exterior Angles are Congruent
-Consecutive Interior Angles are Supplementary
-Consecutive Exterior Angles are Supplementary
-Vertical Angles are Congruent
-Linear Pair are Supplementary (And Also Adjacent)

[smoky vector]

What should I do when geo makes no sense

Like any resources

To check that can explain things

[upper karma]

Like High School Geo or like Geometrical Topology or Differential Geometery and etc?

[sinful belfry]

I just started trigonometry, is there anything I should know that is useful?

[wise pawn]

the special angles on the unit circle is a big one

[sinful belfry]

should I study that more often?

[sly raptor]

Yes

Ideally you have them all memorized

[upper karma]

my brain is not braining

no

[agile elm]

anyone down ?

[placid sandal]

would the area of the fabric of space bent by a black hole count as geometry?

like is there a theoretic studies channel?

[grave pond]

The relevant portion of mathematics is called differential geometry. There's a #diff-geo-diff-top channel in the advanced section.
(However, "area/volume of space" in general relativity is not a particularly useful concept since it is not Lorentz invariant; instead you can measure a region of spacetime and get a value in units m³·s).

[smoky jetty]

one thing i found very useful is visualizing the problems i.e making representations

it would help u know why this and that are congruent etc

from personal experience, the theorems in parallel lines cut by transversal seemed really complicated to me at first, as I thought I'd be forced to remember the angles' relationships. But the representation of the problem significantly gave birth to the sort of logic behind them.

[cosmic smelt]

i have this exercise, just look to the squeare, is an 40x40 square and pq ans sr are 8

is asking to find the area of the shadow region

i tried to take the 40 as the large of the rectangle and the 8 as the width

used area formulm of rectangle and multiply with 2 bc there are two rectangles but it didnt, idk why

[unkempt scroll]

when you subtracted the area of 2 rectangles from the area of whole square, you subtracted the center square of 8x8 twice!

since these two rectangles are overlapping at one square, we have to add the area of small square once after subtraction of 2 rectangles

[cosmic smelt]

aaaaaa

thanks dude

u really helped me

[placid sandal]

does it work for white-holes?

[grave pond]

There's no relevant difference at this level of abstraction.

[jade heath]

if we just prove the (1) inequetion didnt we prove the theorem ? why we need to do all these with l, l', l'' ?

[lofty rune]

Guys

Im solving for my early calculus math

I need help on an equation

y^(3)-ty=0

[heavy vigil]

what exactly is the question??

finding the value of t or y?

or do you have to differentiate or integrate

[copper sail]

Help, please! : ( (Ping me if you're able to help)

[grave pond]

Much of that information seems to be red herrings. You need only "GC bisects angle BGD" and "angle CGF is (4x+3)°".

[copper sail]

I still don't understand, sorry 😭

Thank you for trying to help tho!

[grave pond]

Think about what "GC bisects angle BGD" means.

And note that angle CGF is the same as angle CGD.

[copper sail]

OH

Alright! Thank you

[tulip temple]

Hey guys

What exactly is preuniversity maths

Im from India in grade 11 so I'm not very familiar with the standards used in other countries for my academic level

Is grade 11 pre University?

[spring vault]

Hi guys
Geometry is the thing that i loved but i couldn't completely learn it
So is there anything special that i have to know??

[grave pond]

"Geometry" is many things. (Especially, one of the things it is is a horrible parody of formal reasoning that some school systems teach for unknown reasons). You'll have to be more specific about what it is you couldn't learn but wish you had.

[oak mural]

Anyone know how to do these im lost... with the first one

[unkempt scroll]

do you know when sin function is minimum and maximum?

your main job is to make H(t) = min possible value and so think what value of t will give you that?

[cloud niche]

Hello guys, I am a math teacher who is teaching Geometry this year.I am creating video lessons for my students.Is it against the rules to place the link to my channel here? I think this group might find it useful.

I will be uploading more lessons as the school year continues

[silent plank]

no self promoting

[cloud niche]

Sounds good, I wanted to know the rules before posting anything

[sacred trench]

I need help with this please

[uncut raft]

i'm not sure, i thnik that y its 14 and x 8

think*

[sacred trench]

thanks

@uncut raft one more can you help me with

[uncut raft]

yes, but was it correct?

[sacred trench]

Let me check

[uncut raft]

ok

[sacred trench]

I have to check after I answer this one I send you to help me with

or else I could get this one wrong

[uncut raft]

ok

[sacred trench]

My first answer I put JB but I got it wrong

[uncut raft]

hmmm

u think thats i b

i*

[sacred trench]

yeah

[uncut raft]

socwhat was the question?

so what* sorry the corrector

[sacred trench]

I got it right

all good

[uncut raft]

cool

[sacred trench]

.yeah thanks for your help

[uncut raft]

your welcome

[outer wave]

my mistake, this is not the channel, sorry

[smoky vector]

Hey does anyone know what resources I could use when geo makes no sense to me

Like to explain things

For example YouTube

[lime yoke]

can anyone help me with this??

[dark sparrow]

@lime yoke have you made any progress so far?

[lime yoke]

no

my teahcer gave it and i wasnt to get tutoring so i dont understand

[dark sparrow]

have you worked with angles made by 2 parallel lines and a third line intersecting them before?

[lime yoke]

only on thrusday

[dark sparrow]

the two angles marked here are in a position known as corresponding angles, and because the two parallel-looking lines are actually parallel (i.e. marked as such), the two marked angles are equal

[lime yoke]

i have to find x

oo

ty

so

[dark sparrow]

this lets you write down an equation

[lime yoke]

3x + 23 = 4x

[dark sparrow]

yes

[lime yoke]

ty

[somber coyote]

what7todo

[ocean escarp]

Can anyone help me understand why $z= \pm C \sqrt{x^2 + y^2}$?

[somber coyote]

what7todo

[ocean escarp]

I have solved it. I was confused about the axis. The vertical one is Z.

[olive hatch]

https://i0.wp.com/www.ecobriteled.com/wp-content/uploads/2020/02/Screenshot-2020-02-18-at-12.33.52.png?zoom=2&resize=266%2C266 This object has a Diameter of 95mm and a Length 150mm, using this information, how can I calculate what the height is?

[low moat]

I've been doing Khanacademy, and I'm currently on sine and cosine graphs with phase shift, and I have a question. How can I tell whether a graph is a cosine or sine graph?

[pliant roost]

you don't

sine FUNCTION passes through (0; 0), cosine FUNCTION passes through (0; 1)

when either is shifted naming it strictly sine or cosine doesn't make much sense

[jaunty crystal]

can someone explain to me what radians are?

and how they work?

kinda confused

[low moat]

So, if it is shifted, they can be both sine and cosine?

[pliant roost]

it is pointless to say sine or cosine when they are shifted, so you can say them interchangeably in this case

[pliant roost]

radian is such an angle measure, that if you passed x radians on a unit circle you passed a distance of x on a unit circle

[low moat]

So, a shifted graph like this can be expressed with sin and cosine?

[pliant roost]

technically yes

sin(x)=cos(pi/2 - x)

[low moat]

Ah, okay. Thanks

[pliant roost]

@jaunty crystal

[jaunty crystal]

ohh

wait so

how do u

measure radians?

like what is considered as 1 radian?

[pliant jasper]

1 radian is about 57.3 degrees. There are exactly $2\pi$ radians in a circle.

[somber coyote]

FLORIDA MAN

[jaunty crystal]

so just one pi radian = 180 degrees?

[pliant jasper]

Yep

[neon raven]

could anyone try helping me with my trig hw? its on law of sin and cos

[trim breach]

If you post the problem you are having trouble with, someone will be able to help.

[thick hound]

Anybody help ?

[dawn swallow]

A little help

[last trout]

i am not sure but if this question is of congruency then
angle a = angle e (both 90)
ac = ce (mid point)
angle dce = angle bca (vertically opposite angles )

triangle acb = triangle ecd

cd = cb (cpct)

i am not sure because of some symobls which i have yet not seen in my mathematics i am from india but hope this helps

[runic beacon]

4rth line should be AC=CE

[last trout]

sry my bad and thankyou

[spiral bough]

(b) follows from (a), and (a) can be proven by observing that an inscribed trapezoid has two equal sides (the ones that are not parallel, I don’t remember what they were called)

[worn dust]

Hey, does anyone know what the theorem is for stating that
m∠BOA = m∠BOC + m∠COA?

assuming you don't know it's a bisector (although in the image it is)

[slate geode]

who's here familiar with fanos geometry?

i just don't understand what the Ax 3 means

Oooooh wait

4th point not 4 point

[worn dust]

Just found out, it's called "Angle Addition Theorem/Postulate" for anyone interested

[upper karma]

whats the area of a regular pentagon?

[grave pond]

$\dfrac{5(\sqrt5 + 1)}{4\sqrt{10-2\sqrt5}} \approx 1.72$ times the square of the side length.

[somber coyote]

Troposphere

[unique egret]

any clue on how to solve this?

[neat steeple]

lemme see I'm learning this in geometry rn i might be able to help

[neat steeple]

oh ok thanks for the info 🙂

thought it might be addition wasn't sure though

could anybody help me with this?

I have to find the reasoning/proof for each step

1.Given

I think 3 might be subtraction property

-bc on both side would get AB=CD

[worn dust]

a bit late but

1. Given
2. Segment Addition Postulate
3. Substitution or Transitive Property (both work)
4. Subtraction property of equality

[smoky vector]

Hey does anyone know what resources I could use when geometry makes no sense to me
Like to explain things
For example YouTube

[upper karma]

inscribed angle theorem?

[worn dust]

pretty sure it's called angle addition theorem

[upper karma]

Yeah sorry i was thinking of something else. you are right

[sacred trench]

@worn dust you think you can help me out with this

[dark sparrow]

do you want help from them and them only?

if not, then can you show how you got 13?

[worn dust]

I got 117

117 for a and 10.8166538264 for the distance itself

[worn dust]

but yea @sacred trench it's asking you to square the distance between the two points provided

[sacred trench]

Oh I see

Thanks wonk

[novel vale]

it is like this by replacing the strings given points

[fair harbor]

In the acute angle triangle ABC there is a height BH. It turns out that CH = AB
How many degrees is the angle BAC if ABC = 84 ?

please

i know, it is very simple, but i am struggling with this one

[versed kernel]

You are building a rectangular planter box. The designer gave you the following instructions:
a) The top of the box should have sides parallel to 2x+3y=6. Since it is a rectangle, you know
that the other sides should be perpendicular to the given line
b) 2 of the vertices are given as C(7,0) and E(3,7)
c) The rectangular box has a height = 3 feet.
d) Each side is made of concrete with thickness of 2 inches
e) All length measurements are in feet
f) The volume of a rectangle =lengthwidththickness

Find the perimeter of the top rectangle
Find the volume of the concrete in each side of the rectangle
If concrete costs $5.25 per 6 cubic feet, how much does the box cost?
Write an equation to represent the measure of the angle formed by
the diagonal with the longer side.
If the angle formed by the longer side and the diagonal is 52 degrees, find x

[arctic basalt]

Can someone explain to me why the coordinates of point b are as they are? This is a visualization of the law of cosines

[dark sparrow]

are you familiar with polar coords

or the unit circle in the trigonometric usage thereof

[arctic basalt]

Oh I got it thanks

I didn’t realize they were the polar coords

[cobalt chasm]

d = sqrt(a) = sqrt((x2 - x1)^2 + (y2 - y1)^2)
a = d^2 = (x2-x1)^2 + (y2-y1)^2 = (11-5)^2 + (-7-2)^2 = 6^2 + 9^2 = 36 + 81 = 117.

[upper karma]

hello

[upper karma]

sigh <@&268886789983436800>

[sturdy kite]

how would i approach solving this

so far i have this information

1 period is 4 seconds
and potentially there is a shift of +2200ml vertically
the graph also begins before inhaling so i assume it starts from the mid point of a sinusoidal fuction

[wide dragon]

can someone explain the working out after sinx = 1/root2

i dont understand where the pi's come into play in row 3, 4 and 5

[arctic basalt]

sinx = 1/root2 is just the same as asking the question “for what angles on the unit circle the y coordinate will be equal to 1/root2 ” in this case because sin is positive we only consider the angles above the x axis

Can someone give me a hint?

[alpine peak]

Trig is the spawn of satan himself

every time i look at this goddamn circle i cry

[sterile bolt]

Can someone tell me what I’m doing wrong? I’ve done this type of problem twice and have gotten it wrong both times. The blue box are the values I’m supposed to get but i don’t know how. Any advice?

[opaque panther]

@sterile bolt You're using the right equation but you're simplifying it incorrectly

[sterile bolt]

yeah i figured it out sorry about that

thank you tho

[opaque panther]

Didn't do anything, thanks and good luck though 😂

[sacred hamlet]

From the figure, the parabola passes through points (-5,2) and (-1,2) with point A(-3,4) as its vertex. If this parabola intersects a line y=5 at points B and C, then triangle ABC. How many square units are there?

[opaque panther]

@sacred hamlet Well, you need the equation of the parabola to find points B and C, so consider this:

K and H are givens (just the vertex), so if it starts at point (-3, 4) and goes to (-5,2) & (-1,2)
What that's saying is F(2) = 2, so the equation has to agree with that

[burnt wasp]

completely confused on as to what I need to do to solve this question

[heavy shale]

u need to find all the possible values where sin(2x)+sinx = 0

[burnt wasp]

yeah I understand that part at least, I tried graphing sin(2x)+sinx=0 on desmos and stuff and got a bunch of solutions but I'm not getting all the solutions from 0 to 2pi apparently

so im just baffled

[heavy shale]

u can use formula for sin(2x)

[opaque panther]

@burnt wasp So you can write out the sin double angle formula to get 2sin(x)cos(x)

0 = 2sin(x)cos(x) + sin(x)

Factor out the like term which is sin(x), solve the equation. You should get 2 answers this way

Then you can write the equation another way:

• sin(x) = 2sin(x)cos(x)

Divide both sides by 2sin(x), simplify, then solve for cos(x), should get 2 more answers

I can't really explain why this process works or how I know this solves all possible values of x without looking at the graph though

[thick hound]

Anybody ?

[cunning crest]

Whats the difference between coordinate and analytic geometry?

[manic lance]

i got 24

but ithink thats wrong

for sure

yea

whatever lmao

[ripe narwhal]

anyone? I could not understand this question

[upper karma]

Which part of it? I’m happy to talk you through it

[ripe narwhal]

part d and e

[upper karma]

Have you drawn the curve yet? What does items when they say the value of the inequality must be > 0? Like, what does that look like on the graph?

[green knoll]

Can anyone help with my trigonometry assignment?

[heavy shale]

[lyric belfry]

Alr so

[lyric belfry]

it’s find the measure of the missing angle, ik it’s basic geometry but I can’t think rn

My grades r about to come in

[green knoll]

I'm so struggling rn and it's due on monday. Our assignment was handed yesterday Friday

[lyric belfry]

when does trigonometry get taught?

College?

[heavy shale]

10th grade

[green knoll]

Corresponding angle (F shape, meaning the question mark should be 67 degrees as well, I could be wrong but it should be the same)

[heavy shale]

Ok you can use the property of parallel lines

[lyric belfry]

oh alright let me try

Ik correspding angles, alternate interior etc.

I just don’t understand the measuring part

[green knoll]

oki

[heavy shale]

ok so these angle are corresponding and using property of parallel lines the are equal

[heavy shale]

So Part A u first need to draw a line perpendicular to a cuz thats what height is

[lyric belfry]

How does this work

14x - 6 = 120 right

all I do is solve for x

[heavy shale]

Yes

[lyric belfry]

Ok thanks

[green knoll]

okay but if I have to find the height of the triangle how will that help me find it after drawing a perpindular line to a when there are no other numbers?

[heavy shale]

lets suppose that perpendicualar is Called AD

now what would sin theta be?

[green knoll]

i find that by dividing the perpindular by the hypotenuse right?

[heavy shale]

yes

[green knoll]

alright! tysm! let me do that now

[heavy shale]

ok

[undone moat]

Depends

In WJEC GCSE you are sometimes taught trigonomtry in Year 9

Or 9th if you are american

[lyric belfry]

What would this be

[heavy shale]

Use Co-interior angle property

[undone moat]

If corresponding angles are the same, then you just have to use the property to find the angle

Therefore

[green knoll]

wait, would that mean that the perpendicular is 90 degrees divided by b cm? how would I show this in a mathematical procedure?

[undone moat]

Wdym?

[lyric belfry]

So 103

thanks

[undone moat]

Yes

[lyric belfry]

I think I’m getting it now

co interior = 180

[undone moat]

I wouldn't put it that way

But if you want to

Then

[lyric belfry]

oh

what other way would I put it

[undone moat]

So the cointerior angles sum up to 180

[green knoll]

to find the height from the first pic i showed, I have to divide the perpendicular by hypotenuse. but like would the perpendicular be 90 degrees?

im so confused because i have to show mathematical reasoning

[undone moat]

You just show why you used the specific trigonemtric function to find it

If you want to show mathematical reasoning you have to justify why you used the method and how you did it

[undone moat]

Pythagoras' Theorem

[dreamy spear]

i would suggest distance formula

[undone moat]

I mean, if we know the the length of the other sides if the line segment is the hypotenuse, we can work it out using Pythagoras' Theorem.

You can implement it in this question

It is just asking for the length of the line segment, and so long the method used is sensible and correct there is no point arguing about how to find the length.

[cosmic fulcrum]

how do I solve for the length of ac. radius is 2 and angle θ is 60◦

[upper karma]

The angle <bac is 90 degree

do you know that ?

the angle on the diameter is 90 degree

thats a theorem

[cosmic smelt]

how do i know wich milepost is closer?

[opaque panther]

9^2 + 7^2 = c^2
c is the line segment.. Was there any doubt?

[smoky jetty]

we were taught plane trigo at 8th grade, sucked it badly, though ig i recovered, lmao

[smoky jetty]

First of all, what's your initial understanding of the problem? i.e how do you think it should be solved

or your idea of the theorems regarding it

[glass ivy]

can anyone help me with this problem?

find the equation of the plane that passes through the point (2, 5, 1), is perpendicular to the plane 3x-y+2z=1 and parallel to the lines 4x+5y-z=7 and 2x+3y+4z=1

[undone moat]

@upper karma

[undone moat]

Is this on a 3d plane?

[glass ivy]

yes

[smoky jetty]

from the x axis i think

[cosmic fulcrum]

no it doesnt say

[near haven]

Ive been struggling with this for a while

[grave pond]

,rccw

[grave pond]

The trick for making this simple is to notice that ABO is similar to HAO where H(6,0) is the foot of the altitude from A.

So you can ask for the tangent of angle HAO instead.

[near haven]

Hao?

Where did u get h from

[grave pond]

I gave a name to the point where the dashed vertical line meets the x-axis.

[near haven]

Ahh the one beside a at 6,0 as u said got it

Ill try that

[grave pond]

It's a very useful fact about right triangles: the altitude splits a right triangle into two smaller right triangles that are each similar to the original.

[near haven]

Yh got it man thx so tan abo = tan hao = .5 thx man

[grave pond]

No, you divided OH and AH in the wrong order.

[near haven]

Wdym

U mean its 2 not .5?

[grave pond]

Yeah. Or perhaps I'm wrong. Better double-check your work in any case.

[near haven]

Tan = the opposite side / the adjacent side so if we are talking about hao then it would be tan a = ho/ha = 3/6 = .5 got it?

Which as u pointed out = to abo which is the question

[grave pond]

How is HO/HA = 3/6?

[near haven]

No i think i did smth wrong one sec

Ohhh i misplaced h i placed it at 0,6 not 6,0 so i calculated it 3/6 instead of 6/ab

But still how do i get ab

6/3*

I still dont get how do i connect tan abo and tan hao like how do i proof it

[near haven]

@grave pond are u there bro?

[undone moat]

Indeed

[undone moat]

Are we solving for x in this problem?

[undone moat]

I am sorry I can't help with these types of problems

'rccw

,rccw

[smoky jetty]

interesting. welp, I've not encountered such parallel lines cut by a deformed transversal (pun). But I'm certain that the vertical angle theorem is applicable to that problem

[whole heron]

It is

[smoky jetty]

alright then

[undone moat]

Bruh.

[smoky jetty]

yeah, the transversal is pretty unique for me atleast

[grave pond]

The two angles are the same: each of them is 180° - 90­° - angle AOB.

[zinc trout]

Need help with this

[feral orbit]

Hey

Can somebody help me?

please

#help-0

[half iron]

Hw assignment help

[heady plume]

Im guessing bcfg?

Bc that plane is parallel is to adhe

[fair pendant]

Don't post irrelevant videos in channels, i'm giving you a day mute

[keen leaf]

is your ans is 22 for 1st ques?

[cosmic fulcrum]

anyone know how to solve for lenght of ac

and area of the shades region?

bc goes through the middle

[silent plank]

consider the theorem concerning angle subtended by the diameter (aka thales theorem)

[solid jackal]

BC =4cm
ABC is a right angle triangle cos hypo is through diameter
sin60= AC/4
AC= 3.46

[cosmic fulcrum]

yeah i guess its about proving that

else it would be easy

[near haven]

(Cos 5x/sin x) = 1 (where 5x is the measure of an acute angle) find the value of sin 2x

[cedar python]

does anyone know why?

[royal osprey]

Bottom one uses SSA

[cedar python]

i thought it can be sas 💀

[royal osprey]

The upper one is SAS, the bottom triangle is SSA

[cedar python]

OHHHHHHH

THX

[royal osprey]

Ye

[royal osprey]

Yes your right

[cedar python]

wait so its still still be congruent even if the angles r not the same @royal osprey ?

[royal osprey]

As long as both of them use the same congruency shortcut

[solid yacht]

isnt SSA not enough to prove congruence

Like its the "ambiguous case"

[royal osprey]

Yes.. I’ll be specific. If it’s AAA or SSA, you can’t prove congruency.

[upper karma]

my head is literally

gonna explode

[solid yacht]

you move the x over to the right and reflect over the x axis

4 units to the right'

[upper karma]

which point is the x

[solid yacht]

all the points

you add 4 to the x of all of the points

that will move the whole graph to the right 4 units

[upper karma]

that’s wt their asking for

[solid yacht]

translation

translation is when you move a graph by x amount of units

reflection is like a mirror

its a mirrored image of the graph on the other side of a axis

[upper karma]

ok

and does it reflect

[solid yacht]

and rotation is the graph rotated by however many degrees

yes

[upper karma]

on the x axis

[solid yacht]

at the end

yes

[little patio]

I always remind myself that ASS is not a word that should appear on a mathematics paper therefore ASS is not a reason to prove for congruent

[cedar python]

tu

ty

[real oar]

Do the identities like
"sin² + cos² = 1"
always end up as 1?

And how was it derived?

[opaque panther]

Think about the Pythagorean theorem @real oar

Side a^2 plus side b^2 = side c^2

This is the same thing just with a unit circle, who's radius is one.

Take an angle and try it for yourself, it'll make sense. I bet that's also a good question better explained by YouTube

[upper karma]

Late to the party, but draw another parallel line at the tip...

[drifting pulsar]

any clue how to prove this?

[royal osprey]

Yeah that’s why it’s wrong

[sacred trench]

@royal osprey could you help me with this

@everyone

[mental ridge]

@sacred trench reason 2 is vertical angle
Reason 3 is transitive property of congruence
Reason 4 is converse of isosceles triangle theorem

[mental ridge]

Try this site out https://www.mathsisfun.com/algebra/trigonometry.html
Trigonometric identities are just the length of two lines in a triangle inside a unit circle (A circle with a radius of 1). This works in all triangles because of fundamental theorem of similarity.

[sacred trench]

@mental ridge is that for the first image I sent you or the second one ?

[mental ridge]

Its for the osai guy

[sacred trench]

@mental ridge could you just help me real quick with these though please

there the last problems in my HW

and cant seem to figure it our

out*

[mental ridge]

Sure let's go to vc channel mathematics

[sacred trench]

okay

[real oar]

Oh thank you!

[nova pelican]

they not the same corner

[cosmic mountain]

could you explain it.

[lavish quail]

can someone explain to me how this is incorrect before i blow my brains out

[trim breach]

You can use the Isosceles Triangle Theorem and the fact there are 180 degrees in a triangle to solve for x.

[trim breach]

Maybe a syntax thing? (x + 3, y + 1) maybe?

[sullen kettle]

like @trim breach said, you wrote the differences in x and y but instead you need to write how the new coordinates depend on the old ones

[foggy nova]

d

[sleek lava]

How would i do this?

I'm completely lost and our teacher left us with just an answer key with no explanation to them

[naive cipher]

Lets name the vertices a , b, c

[naive cipher]

Now in a right traingle hypotenuse is the biggest side

So

Ac>ab ,,ac>bc

[heavy shale]

name the vertices A(-1,2); B(-10,5); C(-4,k)

Now using distance formula find all the sides

In a right angled triangle, (largest side)^2 = sum of square of other 2 side

[upper karma]

Hi everyone! I made my first yt movie in manim. It lasts only 2 and a half minutes. Maybe you’ll enjoy if you watch it 🙂 Link: https://youtu.be/QtVImcr4g0U

[real oar]

I have a question,
Suppose a hexagon ABCDEF where all angles are equal, AD and BE intersect at O, would the triangles created (Triangle AOB and EOD) be equilateral?

Can one mathematically prove this?

Btw all sides are equal too.

[real oar]

Wait my dumbass lemme try it again.

[real oar]

This is my second attempt 🙂.

Lemme just

Now it doesn't look too overwhelming.

Btw those triangles are similar by AA test of similarity.

[real oar]

(Prove: AOB and EOD are equilateral)

[real oar]

I think it's better to consider 1/1 = AO/DO
1/1 = BO/EO than what I just did.

This can also be be done

$\frac {1}{1} = \frac {AO}{DO} = \frac {1}{1} = \frac {BO}{EO}$

and just crossmultiply.

[somber coyote]

OSAI(OverSentientAI)

[real oar]

Y'all get the drill right?

[real oar]

I also had a bigger question..

Suppose in hexagon PQRSTU there's midpoint for PQ called V and a centre to the hexagon is called O will 6(VO * PQ) = A(PQRSTU)?

If a hexagon is made of 6 equilateral triangles then is

$A(PQRSTU) = 6\left( \frac {\sqrt {\frac {PO² + OQ² - 2(VP²)}{2}} \cdot PQ}{2}\right)$

correct?

[somber coyote]

OSAI(OverSentientAI)

[real oar]

I mean, the height of the equilateral triangle is the median as well, right?

So the median will equal to
PO² + OQ² = 2(VP²) + 2(OV²)
PO² + OQ² - 2(VP²) = 2(OV²)
(PO² + OQ² - 2(VP²))/2 = OV²
√(PO² + OQ² - 2(VP²))/2 = OV
Right?

And yes I used appolonius theorem.

[fierce shadow]

,w sin^4x+cos^4x=3/4

[somber coyote]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Аппроксимат#6705

[somber coyote]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by ghost#6572

[lethal fable]

since 1 and 2 are a linear pair they equal 180 so 180-123 and you would get 2

[upper karma]

basics of trigonometry help pls ?

a 1.5 m tall boy is standing at some distance form a 30 m tall building . the angle of elevation form his eyes to the top of the building increases form 30 to 60 degree as he walks towards the building . find the distance he walked towards the building ?

[grave pond]

Hmm, if the boy is 1.5 m tall, then his eyes are probably something like 135 cm above the ground, but there's some uncertainty there.

But other than that, you should be able to find the distance to the building at the beginning and end of the walk, and subtract.

[woven light]

https://media.discordapp.net/attachments/979534947780001852/1034992390974480465/image0.jpg

https://media.discordapp.net/attachments/979534947780001852/1034992391649755147/image1.jpg

[serene monolith]

grog

[signal ibex]

just look for a fixpoint on P and try to go through every answer and ask urself what it does to P

[heavy shale]

thats Pythagoras theorem

since hypotneuse is largest

[rotund vigil]

Somebody please solve this for x and y...

[undone moat]

It is like a normal equation but with trigonemtric functions.

First ask yourself, on what axis sine is projected and from then on you can work out the question yourself.

I can only say this concerning the question.

The sine function is projected on the y and cosine on the x.

It is simplified to c^2=a^2+b^2

[rotund vigil]

can you pls provide a solution ?

[heavy shale]

U can use linear pair property to find m5

and then go from there to the closest angle(i.e. 8) and use properties of parallel lines and triangle to find the angles

[jagged coyote]

Ty

[upper karma]

Hi guys

You have a triangle defined by the 3D points P1,P2 and P3, and another separate point P4. You do not have access to the normal of the triangle. How do you determine on which side of the triangle point P4 is? (Point traversal order is from 1 to 3)

Any ideas?

[trim breach]

Thank you for your contribution.

[atomic nebula]

can someone help me rq

[grave pond]

Certainly not unless you describe what it is you want help with.

[atomic nebula]

probably really dumb but idk if i did my equation right

[brazen gust]

convert it into y=mx+b form

[atomic nebula]

i did that

i got a huge number i cant graph

[brazen gust]

what'd u get

[atomic nebula]

it was like -14

[brazen gust]

yeah

but follow along the graph until u get to the numbers u can graph

[atomic nebula]

so this is right

[timber cargo]

Yes, that's right.

And your x intercept would be at (3.5,0)

and your y intercept is at (0,-14)

[atomic nebula]

how would i plot that though

or am i just dumb

[timber cargo]

Okay, so, you know that one of the points that lies on the linear line is at the point (3.5,0), so using y=4x-14, pick some other x value, preferably an integer, and you'll get some y value. Graph that point and use a straight-edge to align with the point you just plotted with the x intercept of the graph and just draw a continuous line

[atomic nebula]

okay

thanks

[timber cargo]

So, it should look something like this

@atomic nebula ^

[atomic nebula]

okay

[timber cargo]

K, 👍

[atomic nebula]

thank you!!!

[twin ember]

Trying to think though some stuff conceptually for trig

Would I be correct in saying this?

[nocturne remnant]

Yes

[twin ember]

Ok cool. I'm sitting here staring at trig problems and trying to figure out how to deal with squared things and I needed to make this connection lol

[undone moat]

I am sorry if I am posting this in a non-relevant place, however I could not find anything related to it, soo...

I was on a website for mathematics and got this question.

I don't ask you to explain it to me.

Please do explain how this makes any sense.

[deft drum]

When we draw a line, we call it 1d geometry. Now the tip of your pen and pencil would have some thickness. So if you zoom it more there will be some thickness. Is there positibility to have a line w/o thickness at all?

[deft drum]

What is the upper limit?

[undone moat]

There is no upper limit, I am not asking a question.

[nocturne remnant]

[deft drum]

Oh now i got it

So prime number means a number has only two factors 1 and itself lets say 7: 1 and 7 can divide 7 with 0 remainder

If a number is divisible by any other number than that, it is called composite number

So the answer is very easy, I would like you to give answer of both of the questions

[dark sparrow]

in what way does this question not make sense to you?

[undone moat]

How can a prime number be a prime number if it is the multiple of anything other than one and itself?

I said there is one for part a but it was apparently wrong.

[undone moat]

Go on then.

This literally breaks mathematics though.

[deft drum]

5 / 5 = 0 and there no integer that divides 5 therefore answer is 1

8 / 8 = 0 but there are other integers like 2 and 4 also divide 8, therefore answer is 0

Let me know if I am mistaken

[undone moat]

You are correct, but the question is so badly worded.

[deft drum]

May be it was a trick question then

[undone moat]

Idk.

[nocturne remnant]

?

[undone moat]

Look.

How can a prime number remain so if it is a multiple of another number excluding one and itself?

[nocturne remnant]

Yeah duh

What’s the matter?

[undone moat]

Nothing

Just the question I posted in chat

[nocturne remnant]

This one?

What’s wrong w it

[undone moat]

Yes.

Nevermind.

I am fine now

[nocturne remnant]

Ok good

There’s nothing wrong with the question imo tho

[dark sparrow]

5/5 isn't 0...

[deft drum]

Yeah my bad 5%5

[dark sparrow]

@undone moat you do realize that the answer to "how many X are there which are Y" can be zero, yes?

[deft drum]

Can anyone help me here

[dark sparrow]

no, it is not possible to draw a perfectly straight line without any thickness in the real world

[upper karma]

whats Geometry ive never heard of this until today

oue oue ya des meufs de LYON ?

Oue

[ancient kernel]

hey guys is there any good math book for geometry?

[upper karma]

what?

[ancient kernel]

like in the form of a pdf

[languid elm]

I need help with my geometry hw bro

[royal osprey]

Does anyone know how I can better understand special segments and point of concurrencies

[twin ember]

Which one would be correct here?

X is supposed to be theta oops

Also I am trying to prove

If that helps

[timber cargo]

1/cotθ = Tanθ

And Tanθ=sinθ/Cosθ

[dark sparrow]

do you mean correct or do you mean helpful?

[near haven]

Can sm help me with this rq

[mellow sparrow]

Hello I require help in this problem. It's the summation that's bothering me.

[vapid pollen]

Hmm have you tried half-arc?

Bc 5X is 2X+3X. And with half-arc you could get something from X to 2X

And since it is an acute angle

Then you don't need to worry about +-

[undone moat]

,rccw

[undone moat]

This just involves an equation.

,w (cos 5x)/sinx=5

[somber coyote]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Sir Wumpus.#7458

[undone moat]

Therefore...

You can rearragnge the equation so that ,w cos 5x = sin x

[near haven]

Bro im in 10th grade but thx for helping lol

I solved it x = 15 and sin 2x = .5

[torn gazelle]

im struggling with a problem in geometry

[idle thistle]

I'm sure this a pretty basic question and I'm just dumb

This is how far I am

[smoky jetty]

you're almost there

although u dont necessarily need that angle below

[idle thistle]

Yeah Idk, I'm very lost so I started looking for other ways of doing it

[vapid pollen]

How

[near haven]

Angle y (the other acute angle) = 180 - (x +90)
Angle y = (-x + 90 )
Sinx = cosy
Cosx = siny
Cosx=sin(-x+90)
Cos(5x) = sin(-5x+90)
Sin(-5x+90)/sinx=1
Sin(-5x+90)=sinx
-5x+90=x
90=6x
X=15
Sin 2x = sin (15*2) = sin 30 = 1/2 or .5

Got it?

[vapid pollen]

How do go from Cosx= sin(90-x) to Cos(5x)= sin (-5x +90)

[eager bolt]

trig is probably the easiest way]

[timber cargo]

90-48 is 42, so find Cos of 42 degrees, using that, you can then find cos of 48

If you need me to show you it mathematically, I can

Actually, I'll just do it right now, give me a minute or two to jot everything down

[idle thistle]

i tried that but im not sure

[eager bolt]

you can send a pic

of the paper of course

😭

[idle thistle]

oh i dont have the whole thing

just that page

sorry

[idle thistle]

oht hanks

thanks*

[eager bolt]

so where did you try it

oh

[idle thistle]

on a piece of paper

[eager bolt]

he already helped

i guess i'm no longer needed

right?

[idle thistle]

well, kinda

hes gonna write it down

[eager bolt]

ok

bye

[idle thistle]

now i feel guilty

[eager bolt]

dont be

focus on the problem

[idle thistle]

ah thanks man!

[timber cargo]

Yeah, no problen

[idle thistle]

on my first attempt I actually got 4.5 for WX I just assumed it was wrong because the 12cm ZY was shorter (and I know it's not drawn to scale but I thought it was somewhat accurate).

[near haven]

U multiply x by 5

[vapid pollen]

Ye but is that legal?

[near haven]

Yh its legal no one would put u in jail for it lmao jokes aside yh its legal since u multiply x by 5 on both sides so the ratio is still the same so its completely fine

Any more questions?

[vapid pollen]

450-5x , which is 360+90-5x which is equivalent to 90-5x

Oooooh

Right

Thanks

I ended up being the one who had to be helped

[near haven]

Nah its alr we all help each other

[vapid pollen]

Yes

[near haven]

Anyways u got the whole thing right

[vapid pollen]

Yup

The 360 can dissapear since they would have equivalent trigonometric relations

[near haven]

Y 360 tho? This is a triangle the sum of all angles is 180

[vapid pollen]

Because 360 is a full round

Trigonmetric ratios of X equal trigonometric ratios of (X+- 360°)

+- 720 +- 900 +- ...

[vapid pollen]

Sin30° = sin390°

[near haven]

Ahh its essentially the same so its useless just keep things simple

Other than that everything is clear?

[vapid pollen]

Yep yep it is alright

[vapid pollen]

Thanks

[near haven]

Np i got u bro

[vapid pollen]

[upper karma]

Can some explains this to me

[dark sparrow]

,rccw

[distant crypt]

yo who is good with geometry? im in eleventh grade and teacher had some trouble with a problem and was hoping to get some help