help-49

[strong tapir]

(and also tell me why this latex doesn't work damn it)

[tribal temple]

$\cdot$ is a better choice, $a\cdot (b + c) = a\cdot b + a \cdot c$

[grand pond]

dp

[strong tapir]

Thanks :D

[midnight plank]

@strong tapir Has your question been resolved?

[strong tapir]

Jump to the original question

[midnight plank]

@strong tapir Has your question been resolved?

[strong tapir]

<@&286206848099549185> 1h ping

[midnight plank]

@strong tapir Has your question been resolved?

[strong tapir]

.close, got help in another channel

.close

[midnight plank]

Channel closed

Closed by @strong tapir

Use .reopen if this was a mistake.

[midnight plank]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[hearty rune]

ill stick to my sunflowers

good luck though

[wind oxide]

my instict suggests this doesn't have an elementary solution...

[midnight plank]

@subtle torrent Has your question been resolved?

[midnight plank]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[midnight plank]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[midnight plank]

@tidal turret Has your question been resolved?

[queen herald]

Isn't it similar to another question you solved?

The one with spaces T and S of equal dim, etc. etc.

[tidal turret]

this u mean?

or which one

@queen herald

[queen herald]

#help-39 message

It has a similar vibe

[tidal turret]

bro thats about subspaces

I already had that midterm last week

https://media.discordapp.net/attachments/268882317391429632/1223598233763319819/1192815796490080286.gif

[queen herald]

This task doesn't really differ too much

to be honest

[queen herald]

You just find S (it's a one-dim subspace) and then construct a proper f
Since S = <v> for some v, you already know that Ker(f) = <v, ...> and Im(f) = <v, ...>
Include additional info that f(1, 0, 1, 0) = (1, 0, 1, 0) - it will help with construction of f

[tidal turret]

S = <(-2,2,-1,1)>

[queen herald]

yep

[tidal turret]

why that vector is inside the kernel

?

[queen herald]

Because we know that $S \subset Ker(f) \cap Im(f)$

[tidal turret]

true

question would be

[grand pond]

EQUENOS

[tidal turret]

how can ker(f) and Im(f) have a non trivial intersection

is that possible?

[queen herald]

Yes, for example when f is nilpotent

[tidal turret]

nil what

[queen herald]

For example, consider $$
\begin{pmatrix}
0 & 1 \
0 & 0
\end{pmatrix}
$$

[grand pond]

EQUENOS

[queen herald]

Ker = <(1, 0)>
Im = <(1, 0)>

[tidal turret]

how did u found the kernel and the image

is this matrix representation a linear transformation?

f(a,b,c,d) = Ax

[queen herald]

Oh, yeah, any linear transformation of a finite-dimensional space can be represented as a matrix

The i-th column of such matrix would be the image of the i-th standard basis vector: (0, ..., 0, 1, 0, ..., 0)

[tidal turret]

what is the domain and codomain

domain is R^4

[queen herald]

yes

[tidal turret]

also, how do I find the kernel and the image for my lineara transformation if the matrix representation is not given

[queen herald]

Generally, you just represent it as a matrix and find the kernel

[tidal turret]

and how to translate a matrix representation of a linear transformation to the usual way of defining linear transformations

by usual I mean R^x -> R^x : f(x,y,z) = (x + y, x -z)

[queen herald]

In order to find the matrix, just apply it to standard basis vectors to get the columns

[queen herald]

Just multiply the matrix and a column (x, y, z)

[tidal turret]

ok

,, \begin{pmatrix} 0 & 1 \ 0 & 0 \end{pmatrix} \cdot \begin{pmatrix} x_1 \ x_2 \end{pmatrix}

[queen herald]

Well, in case of this particular matrix the domain is R^2

Nope, this is R^4

[tidal turret]

oh, domain is R^2 ?

[queen herald]

yes, because we have 2 columns in our matrix

The amount of columns = dimension of domain

The amount of rows = dimension of the codomain

[tidal turret]

so let the matrix representation of the map be A

A in R^mxn

m is rows
n is cols
the domain is R^n

[queen herald]

yes

[grand pond]

938c2cc0dcc05f2b68c4287040cfcf71

[tidal turret]

now what

[queen herald]

Just multiply by definition

[tidal turret]

0 * x1 + 1 * x2

0 * x1 + 0 * x2

[queen herald]

yes

Which is (x2, 0)

Hence f(x1, x2) = (x2, 0)

[tidal turret]

ok now what

how do I do that for my thingy

[queen herald]

Our goal is to invent a proper f

We know that f(-2, 2, -1, 1) = 0 and f(1, 0, 1, 0) = (1, 0, 1, 0)

We also know that there exists such w that f(w) = (-2, 2, -1, 1), because as you remember (-2, 2, -1, 1) belongs to Im(f)

We can choose w1, w2 such that (-2, 2, -1, 1), (1, 0, 1, 0), w1, w2 are linearly independent and define f(w1) = (-2, 2, -1, 1), f(w2) = [whatever] and see what happens

[tidal turret]

f(-2,2,-1,1) = (0,0,0,0)
f(1,0,1,0) = (1,0,1,0)
f(w1) = (-2,2,-1,1)
f(w2) = [whatever]

how do I find the basis for R^4

like maybe we need to extend a basis of <(-2,2,-1,1)> with a basis of (1,0,1,0) , w1, w2

to find the four linearly independent vectors

mmm

because we need a basis of R^4 {{-2,2,-1,1},{1,0,1,0},w1,w2}

for the uniqueness

[grand pond]

938c2cc0dcc05f2b68c4287040cfcf71

[midnight plank]

@tidal turret Has your question been resolved?

[midnight plank]

@tidal turret Has your question been resolved?

[midnight plank]

@tidal turret Has your question been resolved?

[midnight plank]

@tidal turret Has your question been resolved?

[tidal turret]

.close

[midnight plank]

Channel closed

Closed by @tidal turret

Use .reopen if this was a mistake.

[queen herald]

Exactly

(Sorry I will be available in like 5 hours or so)

[midnight plank]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lofty beacon]

I find all primes p and q
such that pq | 5^p + 5^q. What I got: if p=q easy analysis p=q=5; now p≠q p=2: only (2,3); (2,5); p=3: only (3;2) it was before ; p=5 (2,5 it was before) and (5,313). Now p ≠ 5 and q ≠ 5. 5^p+5^q = 0 mod p => 5+5^q=0 mod p=> 5^(q-1) = -1 mod p Symmetrical for mod q 5^(p-1) = -1 mod q. 5^(p-1) = 1 mod p => 5^(q-p) = -1 mod p; symmetrical for mod q: 5^(p-q) = -1 mod q => 1/5^(q-p) = -1 mod q => -1 = 5^(q-p) mod q (that is same mod p) . maybe we can use orders here.

[midnight plank]

@lofty beacon Has your question been resolved?

[midnight plank]

@lofty beacon Has your question been resolved?

[regal lance]

is there someone here?

to help

pls explain this

[lofty beacon]

This is my channel

.close

[midnight plank]

Channel closed

Closed by @lofty beacon

Use .reopen if this was a mistake.

[midnight plank]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[blissful prairie]

Hi

[blissful prairie]

So can anyone explain what are Determinants

[tepid field]

refer to youtube

[glass zenith]

https://www.youtube.com/watch?v=Ip3X9LOh2dk&list=PLZHQObOWTQDPD3MizzM2xVFitgF8hE_ab&index=6 great video

[soft pewter]

really great video fr

[blissful prairie]

Thankk you

.close

[midnight plank]

Channel closed

Closed by @blissful prairie

Use .reopen if this was a mistake.

[blissful prairie]

.reopen

[midnight plank]

✅

[blissful prairie]

Actually can anyone actually put it in words i find the video a bit complex

[midnight plank]

@blissful prairie Has your question been resolved?

[blissful prairie]

No

[midnight plank]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[midnight plank]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[deep vine]

what does U+W mean?

[sinful topaz]

the sum of vector spaces

[twilit field]

$U+W ={x+y \mid x \in U , y \in W}$. But at the same time we know that $W+U = {y+x \mid x \in U, y \in W}$. However, $U,W \subseteq V$. so $x+y=y+x$ So U+W=W+U

[grand pond]

Veni, vidi, perii is $\R - \Q$

[sinful topaz]

arent you using the fact that addition is commutative to show that U + W = W + U

but they are asking you if the addition is commutative and then telling you if that is the case then U + W = W + U

[twilit field]

They're asking if $+$, where + is the operation that adds subspaces is commutative

[grand pond]

Veni, vidi, perii is $\R - \Q$

[visual tiger]

the first question is equivalent to the second question

"in other words,..."

[sinful topaz]

yes, but didnt you just assume that in whatever this is

[sinful topaz]

yes ik that

[visual tiger]

they assumed commutativity of addition of vectors

not subspaces

it's not well formulated

I would have gone with:

[sinful topaz]

oh so youre allowed to assume commutativity in V for this question?

[visual tiger]

do you know your vector space axioms?

[sinful topaz]

theres like 10 of them, so not off by heart

i can get around 5 of them from the fact that the vector space is an abelian group under addition

[visual tiger]

because you just asked if you can assume the definition 😂

[visual tiger]

that's the definition tho

[sinful topaz]

oh was that an axiom?

whoops

i thought it was just something easily provable by the axioms

oh wait yeah, its one of the things of an abelian group

lol

[visual tiger]

abelian

literally

what distinguishes a group from an abelian group

[sinful topaz]

yeah lol, it just went over my head, even when i was writing the word

[visual tiger]

just to rephrase it a bit

$U+W ={x+y \mid x \in U , y \in W}$. Thus $U+W ={y+x\mid x \in U , y \in W}$ because addition is commutative on vectors of $V$. Thus $U+W =W+U$

[grand pond]

rafilou is not not born in 2003

[twilit field]

got it

thanks

.close

[midnight plank]

Channel closed

Closed by @twilit field

Use .reopen if this was a mistake.

[twilit field]

.close

[midnight plank]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lofty beacon]

find all primes p and q such that pq | 5^p + 5^q. What I got: if p=q => p^2 |25^p=> p=5=q; now p≠q p=2: 2q | 25+5^q => 2q | 5(5+5^(q-1)) => 2q | 5(5+1) => q = 3 or 5; p=3: 3q | 5^3 + 5^q => For it to be divided by 3, 3 and q must have different parity => q = 2 ; p=5: 5q | 5(5^4 + 5^(q-1) => q | 625 +1 => (626 = 3132) q = 2 or 313. Now p ≠ 5 and q ≠ 5. 5^p+5^q = 0 mod p => 5+5^q=0 mod p=> 5^(q-1) = -1 mod p Symmetrical for mod q 5^(p-1) = -1 mod q. 5^(p-1) = 1 mod p => 5^(q-p) = -1 mod p; symmetrical for mod q: 5^(p-q) = -1 mod q => 1/5^(q-p) = -1 mod q => -1 = 5^(q-p) mod q (that is same mod p) . maybe we can use orders here.

[midnight plank]

@lofty beacon Has your question been resolved?

[lofty beacon]

<@&286206848099549185>

[midnight plank]

@lofty beacon Has your question been resolved?

[last slate]

people would try answering if the question was sent in a much more understandable way

try taking a pic of what you want to asl and send it

[midnight plank]

@lofty beacon Has your question been resolved?

[midnight plank]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[midnight plank]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[jolly roost]

would the equation be

10242 < -0.15n^5 +3n^4 + 5560 < 25325

[fallow scarab]

Yes

[midnight plank]

@jolly roost Has your question been resolved?

[midnight plank]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[midnight plank]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

Channel closed

Channel closed due to the original message being deleted.
If you did not intend to do this, please open a new help channel,
as this action is irreversible, and this channel may abruptly lock.

[prime hornet]

[solid verge]

Nvm!

[prime hornet]

[midnight plank]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[formal pebble]

I need some help with geometric foundations, constructions and proofs

[formal pebble]

I don't really have anything specific I just need help with the whole unit

[fallow scarab]

Khan academy

[formal pebble]

I completely forgot about that

Thanks man

[midnight plank]

@formal pebble Has your question been resolved?

Channel closed

Closed by @formal pebble

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[thorny delta]

i don't understand b part can someone explain with logic

[thorny delta]

also if we wanna find fifth term we do n(n-1)(n-2)(n-3)/4! ?

[midnight plank]

@thorny delta Has your question been resolved?

[thorny delta]

<@&286206848099549185>

[fallow scarab]

find the interval of convergence for the series you found in part a)

[thorny delta]

i dont understand sorry 😅 actually this question (b) appears repeatedly and i dont know how to do it since we only just learned the formula in class

for negative binomial

so i dont understand what they mean set of values

[fallow scarab]

https://tutorial.math.lamar.edu/Classes/CalcII/PowerSeries.aspx

[midnight plank]

@thorny delta Has your question been resolved?

[thorny delta]

its too complicated 😅 do you have any other resources? if you do, could you kindly share :- )

[plucky lark]

is this binomial theorem?

wait are you trying to calculate pi?

[thorny delta]

yes

[thorny delta]

no i just wanna know how the formula continues if i wanna find the fifth term

[plucky lark]

oh

thats also the formula newton used to calculate pi

alright ngl i dont know a lot about binomial therom

but i know a video that does

so want me to send the vid?

[plucky lark]

Yea u forgot the x^4 power tho

so $x^4 = (-1(-1-1)(-1-2)(-1-3)x^4)/4!$

[grand pond]

Ryxo

[plucky lark]

for (a) I think u just hafta do
$(1/(2-x^2))^2$

[grand pond]

Ryxo

[midnight plank]

@thorny delta Has your question been resolved?

[thorny delta]

x^3 or x^4?

[plucky lark]

x^4

that was by accident
sorry

[midnight plank]

@thorny delta Has your question been resolved?

[thorny delta]

.close

[midnight plank]

Channel closed

Closed by @thorny delta

Use .reopen if this was a mistake.

[midnight plank]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[pliant mauve]

how did they derive the last formula with the upper 2 i dont get it

[pliant mauve]

and this

like where do they get e_ perpendicular

[pliant mauve]

is it because the absolute value of the 2nd formula would end up being v/p * e_parallel * sin alpha and e_parallel * sin alpha = e perpendicular

[dawn dagger]

Gibts da mehr Kontext?

[midnight plank]

@pliant mauve Has your question been resolved?

[midnight plank]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[midnight plank]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[twilit field]

$W ={(0,0,r,s,t) \mid t ,r \in \R}$

[steep hinge]

hint: $\dim U=2\implies \dim W=3$

[grand pond]

everg

[steep hinge]

this still has dimension smaller than 3

[twilit field]

how's dim(U)=2

[steep hinge]

beacuse it uses just two variable x and y to define it

[twilit field]

I see

[grand pond]

Veni, vidi, perii is $\R - \Q$

[twilit field]

Thanks!

.close

[midnight plank]

Channel closed

Closed by @twilit field

Use .reopen if this was a mistake.

[midnight plank]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lapis ridge]

Topic: Permutations and Combinations

(a) Under what condition is nP1 greater than nP(n-r)?

(b) Given that nPr times nP(n-r) is equal to k times nPn, find an expression for 'k' in terms of 'n' and 'r'

[midnight plank]

Please don't occupy multiple help channels.

[lapis ridge]

Please ping me once someone solves it

[lapis ridge]

Ive done similar before but dis iz hard

[steep hinge]

if you don't even try it, then you can risk a serious ban

[lapis ridge]

I did try it

Ughhhh

Grrr

[steep hinge]

show your work

[steep hinge]

hope you haven't just written

[lapis ridge]

The answer that i found says 'r' is greater than 'n-1' but the book says i should get the answer 'r is greater than n/2'

[keen saddle]

Why are you writing in right alignment?

[lapis ridge]

I did write before i just needed to take the pic

[lapis ridge]

Because i first thought ill do like a brainstorm and that was the brainstorm but i just went for solving it all lmao

[keen saddle]

Lol np

[lapis ridge]

Anyway PLEASE EXPLAIN HOW THE ANSWER TO (a) IS r>n/2 I HAVE BEEN CONFUSED SINCE YESTERDAY GRR

Also please explain (b) please, i dont even know how to BEGIN answering it

[mild trellis]

Hi guys, i am new here. Does it matter where to ask a question about tasks, or can I write in any chat?

[keen saddle]

!help

[midnight plank]

To ask for mathematics help on this server, please open your own help channel or help thread. See #❓how-to-get-help for instructions.

[keen saddle]

nPr = whT

What?

[lapis ridge]

n PERMUTATION r

[keen saddle]

I think its n! / r!

But maybe it's been a long time

[lapis ridge]

Wait isnt it n!/(n-r)!

Bruhhhh

[keen saddle]

Oh mb lol

My suggestion is

Don't cancel the n!

Instead expand it like n • (n-1)!

Do the same for RHS

And you will have a better equation

[lapis ridge]

Im so confused STILL

[keen saddle]

if you have (n-1)! < r!

You can't just cancel the factorial

Instead you write some terms out of it

Like (n-1)! = (n-1)(n-2)(n-3).....(r+1)(r!)

[midnight plank]

@lapis ridge Has your question been resolved?

[midnight plank]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[midnight plank]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[glacial valley]

If a>b and c>d
can I directly say
axc>bxd
is there any way to prove it?

[obtuse basin]

What's your definition of >?

[last slate]

you can say that for positive numbers

[carmine sigil]

a = 0, b = -1, c = 0, d = -2
ac < bd

[glacial valley]

greater than

[carmine sigil]

Got it backwards whoops

[glacial valley]

so a,b,c,d must belong to N?

[carmine sigil]

R+

[visual tiger]

N is too restrictive

[obtuse basin]

They don't have to, but N is sufficient

[visual tiger]

positive real numbers is enough, even non-negative

[glacial valley]

oh

and how do I prove that

[visual tiger]

ac > bc > bd when everyone is positive

transitivity

[glacial valley]

how BC>bd

[carmine sigil]

(Remember that whenever you multiply an inequality by a negative number on both sides you have to swap the direction of the inequality. This is why the proof doesn't work for negative numbers.)

[obtuse basin]

By c > d

[visual tiger]

c > d, multiply by b

[glacial valley]

ohhh

thanks for ur valueable time

[glacial valley]

Ok sir

.close

[midnight plank]

Channel closed

Closed by @glacial valley

Use .reopen if this was a mistake.

[visual tiger]

oh and when one of them is 0 slightly different approach

[glacial valley]

?

[visual tiger]

you can prove the same thing with a,b,c,d non-negative instead

[visual tiger]

in any case you would have a and c positive

if one of them were 0 it would be b or d

in that case bd = 0

and ac > 0

edit

[glacial valley]

condition : a,b,c,d not equal zero and positive rational number

[visual tiger]

you don't need such strict conditions

[glacial valley]

what should be then?

[visual tiger]

condition : a,b,c,d not equal zero and positive rational real numbers or zero

[glacial valley]

if one equals zero the inequality holds?

[visual tiger]

If a>b and c>d

then the only numbers that can be 0 are b and/or d

if one of them is 0, then bd = 0

and ac > 0 = bd

[glacial valley]

ohh

thanks

[midnight plank]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[livid girder]

i need help figuring out how to do these

[kind zealot]

$f^{-1}(a)$ is the value $b$ such that $f(b) = a$. For the first one, which value $b$ gives you $f(b) = 1$?

[modern shore]

it is a linear function

of the form ax+by=c

for first point we know of

oh shi mb

[livid girder]

lol, ur good
im a little confused of how to do it because in my textbook its got

f^-1(y)=x f(x)=y
i think I just dont understand what im looking for first?

for the first one in the pic, would I look for x of 1??
im having trouble thinking very sorry

nvm guys i think i got it tyvm

.close

[midnight plank]

Channel closed

Closed by @livid girder

Use .reopen if this was a mistake.

[midnight plank]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[worthy knoll]

how do you differentiate e^(xy)?

[worthy knoll]

i did get the ans to this question , but didnt require its differentiation

just wanna know how to differentiate this

[frail edge]

$e^{xy}\prime = e^{xy} \times (1+\frac{dy}{dx})$

[grand pond]

xd_senBugha

[frail edge]

you just apply the chain rule then product to xy

[worthy knoll]

thats it?

[frail edge]

yup

[worthy knoll]

did u apple the product rule to xy?

but shouldnt it be y + x.dy/dx

[worthy knoll]

mann

[frail edge]

yeah

mb

[worthy knoll]

.close

[midnight plank]

Channel closed

Closed by @worthy knoll

Use .reopen if this was a mistake.

[midnight plank]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[last slate]

How do I solve this question?

[last slate]

I reached $6\int\frac{t\cdot\cos^2{x}}{\cos{2x}}dt$

[grand pond]

forMaths

[last slate]

but I couldn't proceed from there

[lavish venture]

did you try rewriting cos(2x)

[last slate]

i thought maybe $\cos{2x}=2\cos^2{x}-1$

[grand pond]

forMaths

[last slate]

but i have no idea where to go from there

[frail edge]

$\int t \times\frac{1}{2}\times\left( \frac{2\cos^2x-1}{2cos^2x-1} +\frac{1}{2cos^2x-1}\right)dt$

[sick sleet]

If t = tanx, then you can find the derivative, which is dt = sec²x dx

[last slate]

how does that help?

[grand pond]

xd_senBugha

[last slate]

oh

[frail edge]

now do you understand how to go from here?

[last slate]

i think

let me try

[last slate]

wait no wouldnt this be

$\int t \times\left(\frac{1}{2}\times \frac{2\cos^2x-1}{2cos^2x-1} +\frac{1}{2cos^2x-1}\right)dt$

[grand pond]

forMaths

[last slate]

not 1/2 the whole thing because we didnt manipulate the other fraction

[frail edge]

ill go step by step to crosscheck

hold on

uh no

so you first multiply and divide cos^2x by 2

then you add and subtract 1 from 2cos2x

so itll be from the whole thing

[last slate]

oh right

yeh

okay got it, thanks

lemme try from here

nope, dont get how this helps

[frail edge]

ok hold on

[last slate]

$6\int t\cdot\frac{1}{2}\left(1+\frac{1}{2\cos^2{x}}\right)dt$

[grand pond]

forMaths

[last slate]

how do i even get rid of the x in this case? considering we are integrating wrt to t

[frail edge]

$6\int t\cdot\frac{1}{2}\left(1+\sec2 x\right)dt$

[last slate]

how come?

[grand pond]

xd_senBugha

[last slate]

oh right

[frail edge]

now $\sec2x = \frac{1+\tan^2x}{1-\tan^2x}$

[last slate]

oh

ok i know where to go from there

[grand pond]

xd_senBugha

[last slate]

$x=\arctan{t}$

whoops

[frail edge]

no you dont do that

[grand pond]

forMaths

[last slate]

what? why not?

[frail edge]

turn this

youve already set tanx = t

[last slate]

ah right

OH

omg

🤦‍♂️

so annoying how i consistently get the wrong ideas throughout

math is so cruel

[frail edge]

so your integral transforms to $3\int t\times \left(\frac{1+t^2}{1-t^2}\right)dt$

[grand pond]

xd_senBugha

[frail edge]

you know how to solve this?

[last slate]

i will try lol

[last slate]

wait no, how?

where did the 1+ go

[frail edge]

oh wait

yeah

mb

[last slate]

is it not supposed to be $3\int t\cdot\left(1+\frac{1+\tan^2{x}}{1-\tan^2{x}}\right)dt$

[grand pond]

forMaths

[last slate]

gotcha

[frail edge]

dumb mistake

[last slate]

@frail edge I got it. Thank you very much!

.close

[midnight plank]

Channel closed

Closed by @proper dune

Use .reopen if this was a mistake.

[frail edge]

youre welcome man

[midnight plank]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[twilit field]

let $span(v_1,v_2, \dots, v_n)=V$, with ${v_1,v_2,\dots, v_n}$ being linearly independent, in which case we're done

[runic hamlet]

span(v1,...,vn)=V always because they span V

[mint dragon]

what seperates a spanning list from a basis

[twilit field]

oops

yeah

[grand pond]

Veni, vidi, perii is $\R - \Q$

[twilit field]

if $span(v_1,v_2,\dots, v_n) = V$, and they aren't $LI$,we remove a random vector and check for Linear independence and if the remaining vectors span V, if its achieved, we're done, if not, we remove another random vector and continue this until we get a linearly independent. If the span of the vectors obtained on removing an arbitary vector is not $V$, we replace that vector and repeat the process , until we get a LI list spanning V

[grand pond]

Veni, vidi, perii is $\R - \Q$

[twilit field]

Is this fine?

I suppose this is a smarter way of doing the same thing

.close

[midnight plank]

Channel closed

Closed by @twilit field

Use .reopen if this was a mistake.

[hard umbra]

yours is not quite doing the same thing

[twilit field]

Wdym

[hard umbra]

#help-48 message

why does your described process terminate

if it does not terminate, then your process does not provide a proof of the theorem

[twilit field]

.reoepn

.reopen

[midnight plank]

✅

[keen saddle]

Ahh you closed the other one

Lol

[twilit field]

wait, so is this proof incomplete or is that proof incomplete

[hard umbra]

well both suffer from the same problem

why do the described processes terminate?

[twilit field]

there a finite number of elements in the list

[hard umbra]

okay so what happens when you go through all the elements in the list and you hit case 2 every single time

[twilit field]

I don't follow

oh

[hard umbra]

in your case 2, you don't remove any vectors from the list, you just put it back and try again

okay so, what if you try every vector and you hit case 2 every time

[twilit field]

we repeat that process in every possible order

[hard umbra]

your algorithm currently dictates that you should keep trying

[twilit field]

I guess talking about span is a better way to say that

[hard umbra]

well the way you described it doesnt really make it clear that the algorithm will work

why does trying things in every possible order help?

if you hit case 2 immediately for every vector you try, then you cant do anything

you could keep trying and trying forever without making any progress

[twilit field]

which is why I edited it to say every possible order

[hard umbra]

that doesnt help though

you still hit case 2 immediately

the process you described is essentially memoryless

[twilit field]

hmm

yeah

span is a better way

got it. Thanks!

.close

[midnight plank]

Channel closed

Closed by @twilit field

Use .reopen if this was a mistake.

[hard umbra]

bruh internet died

[hard umbra]

i was about to say

to prove that your process works, you need to show that you cant get linearly dependent lists spanning V where if you remove a vector it no longer spans

[twilit field]

ah, okay

I'll think about this tomorrow, forgot I have some NT HW to do

[hard umbra]

this is impossible for vector spaces, but i think its possible for modules

[midnight plank]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[stuck scaffold]

I’ve done part a but I don’t know how to do part b

[junior flower]

hint: subtraction

[flat veldt]

Sniped

And just substitution that's all

[stuck scaffold]

Oh ok

[flat veldt]

!done

[midnight plank]

If you are done with this channel, please mark your problem as solved by typing .close

[stuck scaffold]

.close

[midnight plank]

Channel closed

Closed by @stuck scaffold

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[royal grove]

hey i was looking for ways to improve in math especially the reasonings/proof giving part. im on my first year of uni and i find it pretty hard to do those things

[lavish venture]

just read proofs and solve more problems

[royal grove]

how am i supposed to make my own proofs then ?

[lavish venture]

by writing them

you may take inspiration from the proofs of professionals

[glad compass]

There are many unsolved problems that need proof!

Like the rienmann hypothesis and p vs np

Or if you want something easier you can try to prove flt!

[versed mesa]

Does anyone here know how to solve a kenken problem? (I tried studying it but no luck, I also tried to use a kenken solver but it cannot solve my problem please help ong)

[carmine sigil]

!occupied

[midnight plank]

Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).

[royal grove]

they seem interesting but i have a low level id say

[carmine sigil]

@royal grove I would suggest just doing proofs and having others double check them. That's really the only way to get better.

[lavish venture]

lol those problems are unsolved problems that mathematicians have slammed their heads against the wall for centuries trying to solve, he’s probably a troll

[glad compass]

Try writing corollaries to the proofs in your books

[carmine sigil]

If you have a particular subject you'd like to study, why not start just doing proofs.

[glad compass]

Yeah lmao

[royal grove]

during lessons theres some things that need proof but each time it seems impossible to get starded on those

[lavish venture]

it’s always a good idea to work backwards

[carmine sigil]

it only seems impossible because you're unaccostomed to it

[lavish venture]

proofs require creativity that wasn’t required in standard algebra or calculus classes which were purely computational

[royal grove]

id like to know if theres like a path to follow to make those maybe how to find a lead or smt

[glad compass]

Instead of seeing the proof, try to discover ot yourself, even if it takes days or weeks try it. The knowledge you will get on your way to the proof is invaluable.

[carmine sigil]

it gets easier as you learn how to approach proof type problems, but obviously there is not single answer or algorithm to generate a proof

[lavish venture]

there is no concrete method of proof

you just have to get better at problem solving

it isn’t like differentiating a function

you get better by doing

[royal grove]

so to get better at problem solving i have to solve problems ;-;

[lavish venture]

are you reading a book

[lavish venture]

crazy how that works right

[royal grove]

im taking classes

[lavish venture]

you should read some books

as a supplement

independently

[royal grove]

many things in my classes revolve around problem solving

[lavish venture]

peter eccles mathematical reasoning book is good

[royal grove]

imma give it a look

[lavish venture]

so is "a transition to advanced mathematics" by smith

[royal grove]

also the thing im worried about is what if i dont learn to solve but just to copy

[lavish venture]

just don’t copy?

[royal grove]

yk not actually understanding but when given the solution it seems easy

[lavish venture]

i only refer to the solutions after solving it

[royal grove]

its hard to explain lol

[lavish venture]

if you’re doing the exercises how is it copying?

unless you’re just looking at the back of the book

if you’re doing it on your own it’s not copying

[royal grove]

sometimes when i im stuck i look at the solution

but i dont feel like i learned something

[lavish venture]

it’s ok to look at the solution when your stuck

but don’t do it immediately

wait

try to figure it out even if you can’t think of it quickly

[royal grove]

okok

still

sometimes its just impossible to get a start

i feel like the property is already proved

but then it is not

[lavish venture]

math isn’t a spectator sport i don’t know what to tell you

other than just do it

at this point it seems like you’re making excuses

for why you can’t do it

it’s like you’re trying to convince yourself you aren’t capable or something

just go do math

[royal grove]

real

it hit me where it needed

its hard to swallow but youre right omg

thank you dude

[lavish venture]

mhm you’re welcome

[royal grove]

.close

[midnight plank]

Channel closed

Closed by @royal grove

Use .reopen if this was a mistake.

[midnight plank]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

Channel closed

Channel closed due to the original message being deleted.
If you did not intend to do this, please open a new help channel,
as this action is irreversible, and this channel may abruptly lock.

[flat veldt]

.

[keen saddle]

Occupy a new channel

@raven apex

[raven apex]

ok

[midnight plank]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[zenith kettle]

How do I do the question I only got part a correct

[twin forge]

What did you try

[zenith kettle]

i tried making the bracket zero

for part b

and for c i put n=4

[zenith kettle]

apparently its wrong

[twin forge]

What did you get for n

[zenith kettle]

20

for part b i did n= 20

[twin forge]

That's correct though let me re read

Oh

It's basically how much was mined each year

You need to find the total mass mined

Nvm

Did you write 20 as the answer or 1200?

[zenith kettle]

yh i wrote part b wrong mb

how about part c

[twin forge]

That's the total mass mined in all the years upto 23

You need to find mined in just 23

[zenith kettle]

ohhh

so it want it in that year only

tyy

/close

.close

[midnight plank]

Channel closed

Closed by @zenith kettle

Use .reopen if this was a mistake.

[midnight plank]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[stable halo]

im confused

which one could it possibly be

like bruh non of these represent integrating factor?

[tribal temple]

Assuming y1 and y2 are solutions to the original?

[midnight plank]

@stable halo Has your question been resolved?

[stable halo]

yes

two seperate solutions

independant solutions i should say

[tribal temple]

Cool cool, I guess “try each of them out” then(?)

[stable halo]

??

how am i meant to try each of them

like physically differnetiate it and plug it in?

[tribal temple]

Yeah substitute each option into the original diffeq and see if it works out or not

[stable halo]

how

my derivites would just be dy1/dx

and dy2/dx

[tribal temple]

You know e.g. that dy1/dx = -(py1 + q) and ditto for y2, by being solutions to the diffeq themselves

[stable halo]

thx

.close

[midnight plank]

Channel closed

Closed by @stable halo

Use .reopen if this was a mistake.

[midnight plank]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vocal steeple]

Can i get help?

[lethal owl]

Translation

[vocal steeple]

determine the limit for lim x->infinity f(x) and lim x->-infinity f(x) if they exist

[lethal owl]

So what are you stuck at

[vocal steeple]

I dont know how to do the task

I dont know what lim x-> infinity e^-x+1 becomes

[lethal owl]

Simplify it first

[vocal steeple]

e^(1-x)

[lethal owl]

Like
$\lim_{x\to\infty}=\frac{1}{e^x}(e)$

[grand pond]

Sherif Player

[lethal owl]

So now what do you think will happen as x gets bigger and bigger

@vocal steeple ?

[vocal steeple]

you divide by a larger number

or?

which becomes so small it becomes 0?

but i dont know how to simplify

[lethal owl]

Yeah e^x gets bigger and bigger thus
1/e^x gets smaller and smaller till it reaches 0

[vocal steeple]

yeah but it is e^x not x alone

[lethal owl]

So that limit would be 0

[lethal owl]

As long as the base of the exponent is a positive number larger than 1
Then it to the power of x would increase to infinity as x approaches infinity

That's the same as 2^x
The larger x get the larger 2^x is

[vocal steeple]

but why

e is not defined

[lethal owl]

e is Euler's number that equals 2.71828

It is a famous constant all over the field of science and math

[vocal steeple]

why is e^1=0

[lethal owl]

What?

[vocal steeple]

wait

[lethal owl]

e^1 = e

[vocal steeple]

i mean e^0

why is that 1

maybe a bit irrelevant

[lethal owl]

For any number a ≠ 0
a^0 = 1

[vocal steeple]

hmm so how do i go to solve this

[lethal owl]

...

[vocal steeple]

e^(-1x+1) => e^(1-x)

[lethal owl]

Ok

[vocal steeple]

i dont understand

[lethal owl]

You don't understand this

I think the problem you have is that you got into culculus while you are lacking the basics of algebra

$$a^{b+c} = a^b \times a^c$$

[grand pond]

Sherif Player

[vocal steeple]

oh yeah true

[lethal owl]

Also $a^{-b}=\frac{1}{a^b}$

[grand pond]

Sherif Player

[vocal steeple]

i know that

[lethal owl]

So using both of those you can simplify the question to this

[vocal steeple]

e* (1/e^x)

[lethal owl]

Yeah

[vocal steeple]

now what

dont we want to get rid of the e?

do we cancel out the e's

[lethal owl]

Just apply the limit already

[vocal steeple]

or does that not work in this case

[lethal owl]

And no you can't cancel them

[midnight plank]

@vocal steeple Has your question been resolved?

Channel closed

Closed by @vocal steeple

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[copper kayak]

hi

[copper kayak]

for example 5 I am just confused as to why you need to find the zeros of the function

plz @ me when responding. Thanks

also for this part. Isnt this the same tangent line?

[midnight plank]

@copper kayak Has your question been resolved?

[midnight plank]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[sacred fable]

whats the error in my equation's logic? i cant seem to figure it out ive tried many times

[fallow scarab]

,calc 1743 * 1.2 * 1.3

[grand pond]

Result:

2719.08

[fallow scarab]

looks fine. why do you think it's wrong

[sacred fable]

the answer listed up there on the right is by the website my prof gave us

is the site just wrong?

[midnight plank]

@sacred fable Has your question been resolved?

Channel closed

Closed by @sacred fable

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[winter ravine]

someone help me with functions

[winter ravine]

Determine the domain and range of each of the following function

if you could help me understand it/explain it to me that would be great

[sacred fable]

Do you know about the rules of a denominator in a fraction

[winter ravine]

no 😬

[sacred fable]

Basically the denominator of any fraction cant be 0

Do u know why?

[winter ravine]

ohh

yeah

[sacred fable]

Ye its undefined

[winter ravine]

its undefined

thought you were talking about something else

[sacred fable]

So when looking for the domain of a function what you're doing is looking for any x values that can exist in a given function

[winter ravine]

yeah

[sacred fable]

Keeping in mind a denominator =/= 0

Do you think you can figure out what values cannot exist in the function you gave?

Or do u need a bit more nudge to the right direction

[winter ravine]

yeah i still need help

i know the denominator cant be 0

but for domain and range i think you're supposed to find values that make the function =0

so you cna put it into domain and range

like 1/x-3

3 would be the value

x cannot eqaul 3

[sacred fable]

Think of domain as this definition: all possible x values that are allowed to exist in the function
Range: all possible y values allowed to exist in a function

[sacred fable]

Yeah exactly :)

So in a rational function's domain ur looking for what x values arent allowed

[winter ravine]

yeah but as equations get more complicated i just cant anymore

[winter ravine]

yeah

[sacred fable]

In your function theres two denominators

[winter ravine]

yeah

[sacred fable]

U already found one of em which is x - 3

[winter ravine]

x-3

[sacred fable]

And you figured out x =/= 3

[winter ravine]

yes

[sacred fable]

Now do the same with the other denominator: 1 - (1 /(x-3))

[winter ravine]

yeah uhmm

[sacred fable]

It also cant be equal to 0

In a rational function
You take every denominator that has a variable and then set it to =/= 0

Solve for all of them, and you'll find all the values that x isnt allowed to exist as

[winter ravine]

wait what?

which all of them?

[sacred fable]

Hold on let me draw it

[winter ravine]

i have no idea how to do 1-1/x-3

[sacred fable]

You already found out x =/= 3
So now solve for the other denominator =/= 0

[winter ravine]

how tho

[sacred fable]

You wanna isolate the x
Do you know how to isolate x in a rational comparison like this?

[winter ravine]

ahem

i can do it when its simple

ill try and draw it

[winter ravine]

ahem

yeah i cant

i dont know what im doing 😭

[sacred fable]

you have 2 numbers that dont have the same denominator which makes calculating annoying

You can make it easier by making all the denominators the same

Think of 1 as 1/1

And then try to make the denominator of your two fractions the same

[winter ravine]

yeah i remember that

[winter ravine]

i forgot how you do that

i dont know how the rules and stuff wokr

im guessing you just do x-3

so it becomes x-3/x-3

[sacred fable]

Yeah! Cuz x - 3 / x - 3 = 1

[winter ravine]

how

[sacred fable]

a / is just dividing, so dividing a number or whole equation by itself equals one

[sacred fable]

Which makes that = 1

[winter ravine]

ahh i see

[sacred fable]

So now you have
(x-3)/(x-3) - 1/(x-3) =/= 0

Since everything has the same denominator you can just multiply both sides by the denominator to remove it

[winter ravine]

to remove what?

[sacred fable]

The denominator

The bottom part

[winter ravine]

yeah

the 0 side aswell?

[sacred fable]

Yep

[winter ravine]

like this?

[sacred fable]

Whatever new thing you do to one side you have to do to the other

[sacred fable]

Yes

[winter ravine]

yeah

[sacred fable]

Now you have x - 3 - 1 =/= 0

And you pre much have it from here i think

[winter ravine]

i dont know tho

yeah i dont know what to do

[winter ravine]

this is how it looks right?

[sacred fable]

Nono u got the side on the right wrong
You had 0 right? So it was 0 × (x-3)

And everything × 0 = 0

[winter ravine]

ohhh

i see

[sacred fable]

Ye

[winter ravine]

this right?

[sacred fable]

Yes

[winter ravine]

can u check if this is right rq?

[sacred fable]

What is this part for?

[winter ravine]

domain and range

same

just another question

[winter ravine]

?

.close

[midnight plank]

Channel closed

Closed by @winter ravine

Use .reopen if this was a mistake.

[midnight plank]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[flat geyser]

3-95a ii and iii

[flat geyser]

Dont know where to start, reallyy

Better quality image

[midnight plank]

@flat geyser Has your question been resolved?

[flat geyser]

<@&286206848099549185>

https://tenor.com/view/lebron-james-crying-hug-cavs-nba-sad-gif-11873768

[flat geyser]

Please

https://tenor.com/view/jawshcord-jamr-jawsh-minion-laugh-bounce-gif-10176095372465015854

.close

[midnight plank]

Channel closed

Closed by @flat geyser

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[winter ravine]

can someone help me get the range for this

[midnight plank]

@winter ravine Has your question been resolved?

[winter ravine]

<@&286206848099549185>

[livid python]

you know asymptotes ?

[midnight plank]

@winter ravine Has your question been resolved?

[midnight plank]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[ornate rose]

I need help with

[ornate rose]

Letter C

I know I need to add my vector from Letter A to the function F using its domain

Is that right?

<@&286206848099549185>

.close

[midnight plank]

Channel closed

Closed by @ornate rose

Use .reopen if this was a mistake.

[midnight plank]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fervent storm]

simplify (2a^2b)(4ab^2)

[fallow scarab]

,tex .exp rules

[grand pond]

riemann

[fervent storm]

would i use product rule?

got it!!

.close

[midnight plank]

Channel closed

Closed by @fervent storm

Use .reopen if this was a mistake.

[midnight plank]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[upbeat plinth]

One message removed from a suspended account.

[last arch]

Do you know basic trig derivatives?

[upbeat plinth]

One message removed from a suspended account.

One message removed from a suspended account.

One message removed from a suspended account.

One message removed from a suspended account.

One message removed from a suspended account.

One message removed from a suspended account.

[last arch]

Yes

So what's the gradient of the tangent line?

[upbeat plinth]

One message removed from a suspended account.

One message removed from a suspended account.

[last arch]

Yea

[upbeat plinth]

One message removed from a suspended account.

One message removed from a suspended account.

One message removed from a suspended account.

[last arch]

Yea

Then from here use point line form

[upbeat plinth]

One message removed from a suspended account.

One message removed from a suspended account.

One message removed from a suspended account.

One message removed from a suspended account.

[midnight plank]

Channel closed

Closed by @upbeat plinth

Use .reopen if this was a mistake.

[midnight plank]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[cold sonnet]

.close

[midnight plank]

Channel closed

Closed by @cold sonnet

Use .reopen if this was a mistake.

[midnight plank]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[odd sonnet]

The sum of three numbers in G.P. is 56. If we subtract 1, 7, 21 from these numbers
in that order, we obtain an arithmetic progression. Find the numbers

[odd sonnet]

what i did: a+b+c=56

and (a-1+c-21)/2 =b-7

got b=16 on solving

after that i did b= sq root(ac) since a b and c are in gp

then solved for a and c using some simple manipulation, but still getting the incorrect asnwer

why?

got a=33, b=16 and c=7

[fallen aurora]

can you show your work?

[odd sonnet]

1 sec

[visual tiger]

ok so that's how you got b and no problem with that

but a and c?

[odd sonnet]

nvm

found my mistake

calculated 256*2 as 412

.close

[midnight plank]

Channel closed

Closed by @odd sonnet

Use .reopen if this was a mistake.

[visual tiger]

by the way

if now you find a = 32 and c = 8 instead

there still is a mistake

[midnight plank]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[last slate]

Hi, i have trouble with systems of equations

Im working on solving 3 equations with 3 variables

[last slate]

The problem is not that I can't find my answer or anything, i just find these methods quite frustrating

The methods in question are elimination method and substitution method

I don't know if im just lack in excercises or fundamentals, but i kept retrying on one question over and over again

Sometimes these would take about hours to answer

Maybe this is normal? Maybe i am meant to struggle on these methods?

I disliked the fact i had to keep retrying on one question it feels very exhausting

For the past 2 hours, i was able to answer 2 questions and 1 in progress

I figured if there's a faster way to identify what steps need to be taken first?

[fallen galleon]

https://www.youtube.com/watch?v=nLar40Dd_Us heres a video i found super helpful back when i was struggling with this also

though it only shows elimination as the method

[last slate]

That's good enough for me, though im still worried if the test going to ask me to answer only in substitution 💀

[fallen galleon]

substitution is the same thing

goal is just to reduce from 3 variables down to 2

[last slate]

ill watch the video tomorrow, my brain is exhausted

Thanks

[fallen galleon]

so you find one equation that you can make one variable as the subject

then sub into the other two

that way you reduce the variables down from 3 to 2

then 2 variables is easy to solve (hopefully)

[last slate]

Idk why, i hate the fact that i have to predict shi

[fallen galleon]

kinda true foresight is quite important

but not absolutely necessary

[last slate]

Well if this question ever got into my test, it would be my last

Maybe

Just to save time

I've went on one question for 3 days

Absolutely exhausting

Maybe im dumb-dumb

[fallen galleon]

nah i used to be the same

[last slate]

Fr?

[fallen galleon]

yea

3 equations used to be difficult but god bless youtube i found some videos and absolutely made it click for me

[last slate]

Oh it's the same guy

Who helped me with my earlier questions

12 mins video...

[fallen galleon]

but really the most important thing is to reduce it from 3 variables down to 2 variables

thats all

[last slate]

I did that, sometimes, the variable aint doin it

Like... 2a + b = .... and 4b + a =...

Mf-

[fallen galleon]

now thats 2 variables

[last slate]

Sometimes i get very wierd results

[fallen galleon]

super simple to solve

[last slate]

ill just do it tomorrow, im tired

[fallen galleon]

maybe you made some obscure mistakes somewhere

i made those mistakes too much

[last slate]

Yea, i can't lie, that happens, ALOT

[last slate]

Damn thanks

That really gives hope

Btw

How long you study a day?

[fallen galleon]

idk depends on my mood

[last slate]

Ah oke

My final exams are in November

And i have 15 days before November

Im cooked

Ahh it's not good to worry

Im just going to rest

Thanks

Tq very muchh

.close