pls
#guys pls give some lessons on Roblox studio lua.
light lark
heady edge
peak orbit
local cat = "bob"
local function Cat(dog)
print(dog)
return 69
end
print(Cat(cat))
what will this print and why?
heady edge
#include <stdio.h>
int main()
{
int a = 10, b = 0, c = 10;
char* str = "TFy!QJu ROo TNn(ROo)SLq SLq ULo+UHs UJq "
"TNn*RPn/QPbEWS_JSWQAIJO^NBELPeHBFHT}TnALVlBL"
"OFAkHFOuFETpHCStHAUFAgcEAelclcn^r^r\\tZvYxXyT|S~Pn SPm "
"SOn TNn ULo0ULo#ULo-WHq!WFs XDt!";
while (a != 0)
{
a = str[b++];
while (a-- > 64)
{
if (++c == 90)
{
c = 10;
putchar('\n');
}
else
{
if (b % 2 == 0)
putchar('!');
else
putchar(' ');
}
}
}
return 0;
}
what does this do
this is pretty easy
you should get this first try
nova willow
```c
#include <stdio.h>
int main()
{
int a = 10, b = 0, c = 10;
char...
is this java?
heady edge
lua real
nova willow
pls
local wavefunctionMetatable = {
__add = function(wf1, wf2)
assert(#wf1 == #wf2, "Wavefunctions must have the same number of coefficients")
local result = setmetatable({}, wavefunctionMetatable)
for i = 1, #wf1 do
result[i] = wf1[i] + wf2[i]
end
return result
end,
__mul = function(wf1, wf2)
assert(#wf1 == #wf2, "Wavefunctions must have the same number of coefficients")
local innerProduct = 0
for i = 1, #wf1 do
innerProduct = innerProduct + wf1[i] * wf2[i]
end
return innerProduct
end
}
local wf1 = setmetatable({1, 0, 0, 0}, wavefunctionMetatable)
local wf2 = setmetatable({0, 1 / math.sqrt(2), 1 / math.sqrt(2), 0}, wavefunctionMetatable)
local wfSum = wf1 + wf2
local innerProduct = wf1 * wf2
gray zenith
```lua
local cat = "bob"
local function Cat(dog)
print(dog)
return 69
end
...
monkey?
nova willow
```lua
local cat = "bob"
local function Cat(dog)
print(dog)
return 69
end
...
im gonna say bob
because the param is looking for dog
and the argument that you gave was the cat
which is = bob
so it would print bob
gray zenith
hmm, Cat, is the funtion that accepts one variable and calls that variable dog, it then gets passed the variable value defined as cat which equals bob, so inside the Cat function , print(dog) will print the value that was was passed , which is bob. then the Cat function with the return, returns a static value of 69, and then last print then prints what was returned by the function Cat, which is 69. So you would see bob and 69 in the output
torn crypt
```c
#include <stdio.h>
int main()
{
int a = 10, b = 0, c = 10;
char...
This is java
mystic nest
```c
#include <stdio.h>
int main()
{
int a = 10, b = 0, c = 10;
char...
this is binary what u guys talking about?
heady edge
moon runes