Two responses to the button interaction | Pycord | Page 1

sudden zenith Jul 3, 2024, 2:21 PM

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Can I make 2 responses to 1 interaction?
Code:

@button(label="Отклонить", emoji="🛃", style=discord.ButtonStyle.red, custom_id="tudabat")
    async def callback(self, button: discord.ui.Button, interaction: discord.Interaction):
        self.disable_all_items()
        await interaction.response.edit_message(view=self)
        await interaction.response.send_modal(PrichModal(user_id=self.user_id))```

Error:
```py
Ignoring exception in view <ButtonReaction timeout=None children=2> for item <Button style=<ButtonStyle.danger: 4> url=None disabled=True label='Отклонить' emoji=<PartialEmoji animated=False name='🛃' id=None> row=None>:
Traceback (most recent call last):
  File "C:\Users\Tarasov\AppData\Local\Programs\Python\Python311\Lib\site-packages\discord\ui\view.py", line 426, in _scheduled_task
    await item.callback(interaction)
  File "C:\Users\Tarasov\Desktop\Боты\Bot DS\Прочее\Helper.py", line 72, in callback
    await interaction.response.send_modal(PrichModal(user_id=self.user_id))
  File "C:\Users\Tarasov\AppData\Local\Programs\Python\Python311\Lib\site-packages\discord\interactions.py", line 1171, in send_modal
    raise InteractionResponded(self._parent)
discord.errors.InteractionResponded: This interaction has already been responded to before

raven trench Jul 3, 2024, 2:21 PM

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Modals have to be the only response

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I don't think you can respond twice the way you want

sudden zenith Jul 3, 2024, 2:23 PM

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raven trench Modals have to be the only response

And then how do I make the buttons deactivate (there are 2 of them) and the modal window go?

raven trench Jul 3, 2024, 2:23 PM

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send the modal first

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should work

sudden zenith Jul 3, 2024, 2:25 PM

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raven trench should work

If you meant just swapping them, then it didn't help?

Ignoring exception in view <ButtonReaction timeout=None children=2> for item <Button style=<ButtonStyle.danger: 4> url=None disabled=True label='Отклонить' emoji=<PartialEmoji animated=False name='🛃' id=None> row=None>:
Traceback (most recent call last):
  File "C:\Users\Tarasov\AppData\Local\Programs\Python\Python311\Lib\site-packages\discord\ui\view.py", line 426, in _scheduled_task
    await item.callback(interaction)
  File "C:\Users\Tarasov\Desktop\Боты\Bot DS\Прочее\Helper.py", line 72, in callback
    await interaction.response.edit_message(view=self)
  File "C:\Users\Tarasov\AppData\Local\Programs\Python\Python311\Lib\site-packages\discord\interactions.py", line 1010, in edit_message
    raise InteractionResponded(self._parent)
discord.errors.InteractionResponded: This interaction has already been responded to before```

plucky sierra Jul 3, 2024, 2:25 PM

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sudden zenith Can I make 2 responses to 1 interaction? Code: ```py @button(label="Отклонить", ...

No you can’t

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You need to use followup

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.rtfm followup

drowsy kayakBOT Jul 3, 2024, 2:25 PM

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5 results

discord.ApplicationContext.followup
discord.ApplicationContext.send_followup
discord.Interaction.followup
discord.ext.bridge.BridgeApplicationContext.followup
discord.ext.bridge.BridgeApplicationContext.send_followup

sudden zenith Jul 3, 2024, 2:29 PM

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plucky sierra You need to use followup

Can you tell me what it should look like in my case?

plucky sierra Jul 3, 2024, 2:29 PM

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sudden zenith Can you tell me what it should look like in my case?

If u have already answer you can just do interaction.message.edit

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And if u want to send another message you do
interaction.followup.send

sudden zenith Jul 3, 2024, 2:31 PM

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plucky sierra If u have already answer you can just do interaction.message.edit

Oh, thanks, I forgot about that possibility.

plucky sierra Jul 3, 2024, 2:35 PM

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With pleasure

magic dew Jul 3, 2024, 2:44 PM

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Modals are special ✨

#Two responses to the button interaction