Welp | Pycord | Page 1

storm escarp Mar 4, 2024, 9:46 AM

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?tag requests

rustic stirrupBOT Mar 4, 2024, 9:46 AM

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Why you should not use the requests library for your bot
requests is a popular HTTP library for Python. It is however not a good option for Discord bots, since it is not async and blocking.

This essentially means that your bot will not be able to execute any code at all while a request is happening. Since requests usually take a few seconds to complete, this can have a detrimental effect on your bot's performance. E.g if a user executes a command that performs a request taking 5 seconds to complete, no one else will be able to use your bot for those 5 seconds.

Please look at using a HTTP library that has async support, such as aiohttp or httpx

storm escarp Mar 4, 2024, 10:35 AM

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What do you mean with %7D?

lost geyser Mar 4, 2024, 1:59 PM

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https://stackoverflow.com/questions/22510329/what-do-the-chars-7d-mean-in-an-url-query

Stack Overflow

What do the chars %7D mean in an url query?

If I access my webapp with the url
/vi/5907399890173952.html
then it works but when I look in the log files then googlebot is trying to access a similar url which generates an exception:
/vi/

split bridge Mar 5, 2024, 5:33 AM

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.close

fiery spadeBOT Mar 5, 2024, 5:33 AM

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Done with your help thread?

Please close your own help thread by using </close:1009144375709814897> with @slate scaffold.

Backup bot: </solved:1109625445990793246> (or .solved) with @fiery spade.

lone jewel Mar 5, 2024, 6:35 AM

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you should use a library and just decode the url

analog tiger Mar 5, 2024, 5:57 PM

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@bot.slash_command(name="test", description="test")
async def get(ctx):
API_KEY = 'X'
API_URL = 'X'
ENDPOINT = 'X'

headers = {
    'Authorization': API_KEY,
    'Accept': 'application/json',
    'Content-Type': 'application/json',
}

url = f'{API_URL}/{ENDPOINT}'  # Make sure there is a '/' between API_URL and ENDPOINT

response = requests.get(url, headers=headers)

if response.status_code < 200 or response.status_code >= 300:
    raise Exception(f'Request failed: {response.text}')
else:
    result = response.json()
    data = [{'id': item['id'], 'promoImageUrl': item['promoImageUrl']} for item in result]
    await ctx.respond(data)

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check this

storm escarp Mar 5, 2024, 5:57 PM

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analog tiger @bot.slash_command(name="test", description="test") async def get(ctx): API_...

dont use requests

#

?tag requests

rustic stirrupBOT Mar 5, 2024, 5:57 PM

#

Why you should not use the requests library for your bot
requests is a popular HTTP library for Python. It is however not a good option for Discord bots, since it is not async and blocking.

This essentially means that your bot will not be able to execute any code at all while a request is happening. Since requests usually take a few seconds to complete, this can have a detrimental effect on your bot's performance. E.g if a user executes a command that performs a request taking 5 seconds to complete, no one else will be able to use your bot for those 5 seconds.

Please look at using a HTTP library that has async support, such as aiohttp or httpx

analog tiger Mar 5, 2024, 5:58 PM

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ok

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@bot.slash_command(name="test", description="test")
async def get(ctx):
    API_KEY = 'X'
    API_URL = 'X'
    ENDPOINT = 'X'

    headers = {
        'Authorization': API_KEY,
        'Accept': 'application/json',
        'Content-Type': 'application/json',
    }

    url = f'{API_URL}/{ENDPOINT}'

    async with aiohttp.ClientSession() as session:
        async with session.get(url, headers=headers) as response:
            if response.status < 200 or response.status >= 300:
                raise Exception(f'Request failed: {await response.text()}')
            else:
                result = await response.json()
                data = [{'id': item['id'], 'promoImageUrl': item['promoImageUrl']} for item in result]
                await ctx.respond(data)

#

ya

#Welp