math-help

[dire holly]

Well, sure.

I just can't really imagine solving trigonometric equations in degrees right away.

Feels kinda wrong...

Not that there's anything wrong with that, of course.

It's just too unusual.

[bleak ingot]

Where do I even start? This is SAT prep by the way

It's a free response

[heady ruin]

Q. Find the value of x . Idk if this used wavy curve method or inequality question?

[daring spruce]

We need to first remove the denominators

[heady ruin]

I am from grade 11th

[heady ruin]

How?

[daring spruce]

take the lcm and simply fy

[heady ruin]

Just show me your work so that I can understand

[heady ruin]

I did that

[daring spruce]

what did you get?

[heady ruin]

Wait

[daring spruce]

also add two to both sides

[heady ruin]

Something like this tbh mate

[daring spruce]

no, when solving qyadractic inequalities we cannot multiply the other side with denominators

[heady ruin]

Ok

[daring spruce]

after the first step, taking the lcm, add two to both sides

[heady ruin]

Ok

[crisp vale]

So the thing is it’s known enough that a + 1/a has minima and maxima at a = 1 and a = -1, where the expression becomes 2 and -2

So you can js

Plug it in probably

[heady ruin]

Hi there, I am actually a grade 11th student so I don't get maxima

[daring spruce]

no, dont just plug it yet

maxima is in quadactic

[heady ruin]

Ah ok

[crisp vale]

I am also a grade 11 student. Basically, it’s a point that looks like a maximum in that area

[daring spruce]

did you add two to both sides/?

[heady ruin]

Doing that right now

[crisp vale]

Here’s a graph of x + 1/x

The point (-1,-2) is a local maximum

[daring spruce]

true, thats another way

but in india we dont get to use desmos

[crisp vale]

I never needed desmos in my explanation initially

[heady ruin]

Fr

[crisp vale]

And we don’t use desmos either

[heady ruin]

Like this?

[daring spruce]

show me your work

yes

now again take the lcm

[heady ruin]

Right

[daring spruce]

did you do it?

[heady ruin]

Yes

Then can I use the number line

[daring spruce]

okay simply the numerator

[heady ruin]

Ok

[daring spruce]

not yet

[daring spruce]

,rotate

[daring spruce]

again fully simplify the numerator

[heady ruin]

How??

I did that but simplfy more

[daring spruce]

expand x^2-1

whole square

[heady ruin]

Ok

[crisp vale]

This is a lot of work icl

[heady ruin]

,rotate

[heady ruin]

Look my answer should be like X belongs to ( } U {. )

[grim timber]

think about what it means if a cubic polynomial (g(x)) only has 2 unique roots

[crisp vale]

Yea I got smth similar

What is the curly bracket in the middle supposed to be

[heady ruin]

Show me the work then?

[daring spruce]

one sec

[heady ruin]

Oh boy, It's really complicated to explain here

[crisp vale]

No it really isn’t

() means not equal to

[] means equal to

{} is discrete set

[heady ruin]

My bad, I got confused with the wavy curve brackets

[crisp vale]

So how can you mix it with the continuous set brackets

[daring spruce]

hi

[crisp vale]

Oh it can’t be equal in the middle

[heady ruin]

Wassup

[crisp vale]

I got () u ()

[heady ruin]

Yes

That one

[crisp vale]

Okok

[daring spruce]

your expression should become x+1 whole square divided by x greater than equal to 0

[heady ruin]

Just show me your work

[crisp vale]

let $y = \frac{x^2 - 1}{x}$

[terse arch]

ActualDumBatcha

[heady ruin]

A pic if possible

[crisp vale]

Thas how I did it

[heady ruin]

Oh ok

[daring spruce]

y>=0

[heady ruin]

I didn't realise that before

[crisp vale]

Just <

[daring spruce]

now multiply both sides by x^2

[daring spruce]

ah yes my bad

[crisp vale]

Or sketch, Thas how I did it

[daring spruce]

btw y is x+1 whole square

[heady ruin]

Let multiply both sides by two

[daring spruce]

by x

[heady ruin]

Ok I got it

By x

[daring spruce]

yes x+1 whole square by x

now multiply both sides by x square

[heady ruin]

Right 👍

[daring spruce]

if we need to remove the denomitor in quadractic inequaalities we multiply both sides by the square of the denominator

[crisp vale]

What?

[heady ruin]

Look guys, just please 🙏 show the screenshot of the whole answer

Sometimes I miss the steps you said tbh

[daring spruce]

uh

[heady ruin]

No problem then

Screenshot is not possible here

Ah yes

I got the answer

,rotate

[heady ruin]

This ks the answer

Right?

[daring spruce]

yes good

[heady ruin]

Thanks alot @worn marlin and @crisp vale

For helping out

And my big apologies for asking the screenshot of the answer

Something like this

But I got the answer

Thanks a lot 🙏😊

[olive delta]

bros

desmos notebook js dropped

[fluid ore]

I would set the (x²+bx+c)(x+a) equal to (x²+bx+b²/m)(x+a) first and see how that goes

[grim timber]

wat

[olive delta]

https://www.desmos.com/notebook

[dire holly]

Notice that since there are only two distinct zeroes, the quadratic factor must be a perfect square.

If you notice that, the value of m is immediately obvious.

[grim timber]

ah

[tepid skiff]

Check out the https://discord.com/channels/876189935382704210/1407642474159280158 thread on how to use LaTeX and TeXiT!

-# this is an automated system message

[fluid ore]

wait this is so tuff

[autumn elbow]

,rotate

[autumn elbow]

Can someone help me with this