#Does anyone know why when I type 'no' the while loop still equals true?

1 messages · Page 1 of 1 (latest)

cursive otter
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because "no" has a different address, this is not PHP, Perl, Python

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in C, C++, Java, the above is not true

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in Java if both string are intern() then it could be true

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while(play == true) {

for(int i = 0; i < 3; ++i) {

                ++userTurn;

                System.out.println("Would you like to roll?");

                String userInput = scnr.next();

                if ("no".equals(userInput) || (theDice.countNumOnes() == 2)  || theDice.countNumOnes() == 3 || userTurn == 3 ) {

                    play = false;

            }
        }
        }
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you might as well use "no".equalsIgnoreCase(userInput)

sand bramble
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thank you \

cursive otter
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also yoda style to avoid NPE, by putting the constant on the LEFT

sand bramble
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how do u get ur code in that box

cursive otter
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triple back tick

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String.equals() checks for intern() then equality

sand bramble
cursive otter
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same pointer ? or intern? yes

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otherwise is it String?