#Summation
21 messages · Page 1 of 1 (latest)
discriminant
er how would that work
i'd try complete the square on f(n) probs
it tells you f(n) is a square for all values of n so it can be written as m^2 for some integer m right?
so f(n) = (n-k)^2 - k^2 + k + 12
you know the -k^2 + k + 12 must be 0 otherwise we don't have a square
is that because
k^2-k-12 requires to have infinitely many factor pairs
f(n) = (n-k)^2 -k^2+k+12 = m^2, m∈Z
(n-k)^2 - m^2 = k^2-k-12 = C (C=k^2-k-12)
(n-k+m)(n-k-m) = C, where C is a fixed constant which has a finite number of factor pairs.
since it works for all n, there are infinitely many factor pairs which means C=0
This is how i woulda thought ab it
larping
ik yo dumbass cant think of that
mb king ur the smartest here
if you couldn't think of that then obviously someone like me couldn't have
I don’t understand this bit sorry
Why does it have to equal 0?
because (n-k)^2 is already a perfect square - adding -k^2 + k + 12 stops this from happening
if you have (n-k)^2 - m^2 is also a perfect square (where m^2 = k^2 - k - 12)
you can do some number theory to show the only solution is when m=0 but it's kinda overkill for tmua
working in mod 4 probably ?
Ohh okay I see I understood the first half but not the second half 😭😭 but yeah I’ll keep this in mind if this was to ever come up thank you marhs goat
No clue tbh, I think algebra and functions
I’m working through tyler tutoring and it’s just a worksheet on the first section
So possibly module 1?
Not too sure sorry