#integral
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or multiply both sides by sec²x
then I = ∫ (sec²x / (sec²x + 3)) dx
u = tanx
⇒ I = ∫ (1/(u²+4)) du
⇒ I = 1/2 arctan(u/2) + C
⇒ I = 1/2 arctan((tanx)/2) + C
i think u learn arctangent standard result in fm
cp2 methods in calc
however using t=tan(x/2) is technically fp1
yes