Radians

[worldly berry]

How do you know that to find the area of the big triangle, you need to use bxh instead of 0.5absinc as ive seen some qs use the second formula for right angled triangles

[covert spindle]

im pretty sure you cant use 1/2absinc when considering radians

[hearty flint]

Says WHO

Just set your calc to radians 🙏

[covert spindle]

the area of sector considers 1/2r^2 theta

since the line is tangent

this makes the triangle right angled

[hearty flint]

Ya

Can find CA or CO

1/2bh is just a case of 1/2absinC when sinC = 1

[covert spindle]

im saying there isnt even a need of using 1/2absinc

[covert spindle]

@worldly berry

[naive ledge]

why wouldn't you

[covert spindle]

i mean u can

but why would u

its like using sine rule on a right angled triangle

[naive ledge]

yeah for any right angle triangle js use 1/2bh

i guess he could prolly derive that formula with 1/2absinc maybe??

[covert spindle]

gang did u say derive the formula 1/2 bh from 1/2 absinC 😭

[naive ledge]

yeah bro 😭

[covert spindle]

bro 😭

[naive ledge]

1/2absin(pi/2)--->1/2ab(1)

1/2ab

shi peak

[covert spindle]

twin

that was the most counter intuitive thing ive ever seen 😭

[naive ledge]

if he uses and remembers 1/2absinc

it could be helpful

[fringe parcel]

You can but why make ur life harder when it says AC is a tangent to the circle so it’s a right angle triangle