#Elecetrical engineering related question
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Using the DC circuit above calculate:
a)Potential difference across each resistor
b) the power dissipated by the 10 ohms resistor
The values on the circuit are on the left side branch 5 ohm resistor above 10 ohm resistor , besides them are 2 ohm resistor above 4 ohm resistor above an 8 ohm resistor and they all have a battery giving 10 voltage
This is just a btec engineering L3 starter question but im confused so I could use help
well the entire left side (5 and 10) is in parallel
and so is the entire right side (2,4 and 8)
so u basically make each side into its equivalent resistance so left "resistor" is 10/3 ohm
and right "resistor" is 8/7 ohms
and those two new "resistors" are in series with eachother so total resistance in circuit is 8/7 + 10/3
then you find the potential difference across each of the two new "resistors" AND recall that the potential difference is the same across each branch
then use P = V^2 / R