#can someone explain their steps on this question (proof a level)

51 messages · Page 1 of 1 (latest)

vernal fiber
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a = m * b, where m is some integer
b = n * c , where n is some integer

We want to check whether a/c is an integer

mb / (b/n) = mn, so a/c is the product of two integers hence a is divisible by c

dense vortex
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THAT SHOULD SAY M is part of z but yeah

vernal fiber
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why positive integers only

dense vortex
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Proof by induction hammered that into me

vernal fiber
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gg

dense vortex
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The amended proof is as follows.

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Is this enough for a nobel prize gng

vernal fiber
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😭

dense vortex
vernal fiber
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its the same thing

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np.

dense vortex
vernal fiber
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its cuz ur saying

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a = n c

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and a/c = n

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same thing

dense vortex
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Fr

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I was just wondering like mark scheme wise

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Or whatever whatever

vernal fiber
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for those questions i think theres multipel alt points

dense vortex
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LIKE PROOF BY INDUCTION

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My stupid fricking exam board

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Apparently its not sufficient to just state the summands are all multiples of whatever (for divisibility proofs)

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So i had to invent a way that prevents this.

vernal fiber
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scammed

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u can say it in words

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u dont need the notation

vernal fiber
dense vortex
vernal fiber
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cooked

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its actually better than edexcel ngl

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id rather do ocr cuz in edexcel i have to basically get full marks

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to get A*

dense vortex
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How much stats / mech do u do

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For me stats will only be 16.6 recurring% of the a level 🥀

vernal fiber
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stats and mechs combined is

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33%

vernal fiber
dense vortex
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50% CP and 50% stats and mech

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Mech is 33.3333333333% and stats 16.66666667%

vernal fiber
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huh

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they worked it out

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like
we are assuming both m and n are positive integers so obviousl (m+n)>(m-n) and (m+n)>0

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and they found solutions which satisfied

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that condition

dense vortex
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You can make 6 from two factors with either or 6 and 1 or 3 and 2

vernal fiber
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(m+n)(m-n) = 6
but (m+n) > 0
try m+n = 6
that means m-n = 1 , that satisfies the conditions
or
try m+n = 3 and m-n = 2
m+n is still > m-n

vernal fiber