#proof

96 messages · Page 1 of 1 (latest)

uncut fulcrum
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whats the generic form of an odd number

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like how would you represent an odd number

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e.g any even number can be written as 2n correct?

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similarly, how would you write an odd number

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yes correct

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let that be n

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and create another odd number such as 2m+1 and let that be m

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nice

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we need to prove m^2 + n^2

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yes

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yep

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im gonna trust that you've expanded correctly

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now how do you think we can show divsibility by 2 and not 4 here

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close

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you need to factor out the 2

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and show that you have no remainder

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yes but you cant just divide by 2 because then it wouldnt be showing it

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yep

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do the same for 4

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but you'll be left with remainder 2

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thus it is not divisible by 4

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but it is divisible by 2

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you cant write 2/4

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you need to leave the 2 outside the bracket

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to show there is a remainder of 2

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correct

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yep

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do you understand why

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yep

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yes

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it's purely the fact that there is a remainder

winter galleon
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send

uncut fulcrum
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so

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so you have a curve

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and you've got a point on it

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and you're told there is a tangent at this point

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and you need to find the eq of the tangent

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you understand what a tangent is?

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@hollow burrow

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at one point

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so

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a tangent would be perpendicular to the normal

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but we dont need that here

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we need to find the gradient of the trangent

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at that point

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it would be the same as the gradient of the curve at that point

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so differentiate the eq of the curve

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mhm

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you need to account for the sqrt2 remember

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that’s when it’s a constant on its own

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here sqrt2 is a coefficient of x^-2

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you need to go back over differentiation basics

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and understand that concept properly

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mate

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def go watch a youtube vid

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you multiply by -2 to sqrt 2

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and reduce the power by 1

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?

waxen rapids
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😭

uncut fulcrum
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yes

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because you’re differentiating

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no

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this is what the derivative is

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how do you differentiate y

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try do that first

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why are there 2 terms

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my best suggestion to you is watch a. vid on differentiation

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this is basic differentiation

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what we’re doing this
(-2)sqrt2x^(-3)

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you sub in the x coordinate into it

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to find rhe gradient of tangent

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then you set up y= mx + c

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you know what m is

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so then put that in

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sub in the given coordinates into y=mx + c

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rearrange for c

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then you’ll have an rq for y=mx + c

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mhm

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thats your grad of rang

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tang*

uncut fulcrum
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gradient

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what you just worked out

next kernel
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did you differentiate it

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okay

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now sub in x value given

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okay thats the gradient

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now do

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y-(y1)=m(x-x1)

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for the point they have given you

uncut fulcrum
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good luck

onyx moss
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Bro how is this A level?

mild crystal
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proof questions are like the worst answered

severe pulsar
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these q's are gcse further maths level

waxen rapids