,w rotate
#Circles chapter 6 question
broken vale
loud laurelBOT
unborn glen
im gonna go insane
broken vale
🤦‍♂️
unborn glen
screw you
broken vale
,w rotate
loud laurelBOT
unborn glen
dyk the angles subtended by a semicircle theorem
velvet zealot
dyk the angles subtended by a semicircle theorem
not really there’s no example of this question in my book
broken vale
u got that
cedar oracle
question 4
show that the lengths OB OA and AB satisfy a^2 + b^2 = c^2
This will only be true if they are the side lengths of a right angle triangle
limber hearth
use pythag then use 1/2ab
cedar oracle
the largest value of those lengths will be c^2
limber hearth
quick sketch will help
velvet zealot
do u have to sketch it though
limber hearth
do u have to sketch it though
no requirement to
or else they would've asked
it is just general good advice to sketch stuff
velvet zealot
show that the lengths OB OA and AB satisfy a^2 + b^2 = c^2
This will only be tru...
i still didn’t get the right answer
when u mean by lengths do u mean find the distance or the gradient of OB for this example
limber hearth
distance
cedar oracle
oh i’ve already done that didn’t get right answer
AO^2 = 2^2 + 3^2 = 13
AB^2 = 3^2 + 2^2 = 13
OB^2 = 1^2 + 5^2 = 26
AO^2 + AB^2 = 26
OB^2 = 26
So AO^2 + AB^2 = OB^2, meaning OB is the hypotenuse of a right angle triangle
if you do a sketch then youre less likely to make a mistake with your side lengths
cedar oracle
i will don’t understand
