What’s your andeee to a
#HELP
hot night
Answer
I cba to do it
Ok well every term after the “2” is negative
And if the full expansion to ∞ tends to the answer
Then your answer is going to get smaller and smaller by a little bit for each expansion
So it must be an overestimate
hot night
Like if the answer is 1.73
Then let’s say the term is expanded to second order
So just first 2 terms
Then you might get like 1.81
For first 3 terms might be like 1.76
4th: 1.74 etc….
Well the answer is sqrt3 =1.732 and so on
So for every additional term, the number you have gets slightly smaller towards √3
Because all the terms are bagtige
Negative after the first
Well you can but that’s not you giving an explanation like the q wants
solid blaze
it says " the student uses this expansion with x=1/9! so i assumed we substitue 1/9
hot night
It’ll make it clear it’s an overestimate tho
solid blaze
why would they give me 1/9
hot night
Well I’ve not done part a tho I’d assume you’d get something in the form of a(1+bx)^½ where substituting 1/9 in gives √3 or smthn
Gimme a sec
upbeat stag
because it says without doing any calculations
so you're meant to tell based on the expansion
upbeat stag
Like if the answer is 1.73
so basically how thingy explained up here
hot night
Ye you just get √3 when you sub it in the a(1+bx)^n form
So subbing in 1/9
If you expanded until you had infinite terms for this q
It would give √3
hot night
So you’ve seen this right?
hot night
If x = 1/9
I just subbed it in
And you’ll get the fraction = √3
Well sqrt(4 - 9 (1/9)) does give just √ 3
hot night
But the main thing is that
If you expanded 2(1-9x/4)^½ to ∞ where x = 1/9
So all these terms
The sum of all these infinite terms will be = √3
Do you get that
After all, that’s like the entire point of the binomial expansion
solid blaze
But the main thing is that
i understood it thank you