#hyperbolic
1 messages · Page 1 of 1 (latest)
coshxcoshy=9
sinhxsinhy=8
get y=f(x)
so I did 9-8 for cosh(x-y) = 1 => x=y
but then someone said 'well cosh is even so there is another solution' which we found from doing
9+8=cosh(x+y) so y = arccosh17-x
I have two questions:
- why are there two solutions, like, evenness sounds intelligent to me, i get what evenness is, but i dont nderstand, why its not just one solution
- is there a solution method such that both answers pop up? rather than needing to do both 9-8 and 9+8 which makes no sense to me.
When i think ab the exponentials, I dont see how a +- would arise
<@&791435371564892232>
,w plot y=coshx
It’s a many-to-one function
,w arcosh3
,w (arcosh17)/2
After getting x=y u can sub back in to get cosh^2(x) = 9 and u get the same solns
,w arsinh(sqrt8)
Or similarly with the other eqn
ok so the algebra works
but im still not
convincedd
like
im used to sim equs where, u sub it back in, u get THE solutionm
i suppose theres no reason it mus tbe that way
idk
anyone have an intelligent way i can understand better?
the question seems a bit weird, it would make more sense if it said to solve the equation, rather than finding y in terms of x
U do get both at once if u do +-
wdym
like x-->-x via evennes?
cosh(-x)cosh(y)-sinh(-x)sinhy
coshxcoshy+sinhxsinhy
cosh(x+y)=1?
x=-y
wait
what is this dark magic
oh its bcs x-->-x
im stopeed dont midn me
wdym
Like when u wrote down coshx = +-3
Then x = y = +-arcosh3
Or is it arcosh+-3
rej. coshx=-3 => coshx=3
coshx=3
e^x+e^-x=6
let U=e^x
U^2+1=6U
U^2-6U+1=0
discrim. = 32 => two solutions for x => two solutions where y=x
Ye
But i think whenever u solve an equation like coshx = … u should do +-arcosh… like with x^2 = … u take +-root
or u can do +- within the ln
ya
icl I think the textbook mentions when there is 2 like coshx = k and k > 1?
something like that
if you wanna know the reasoning behind it then yeah idk 😭
maybe to do with the graph like if you want coshx = 3 3 intersects at 2 points but cosh x = 1 intersects 1 and anything below is undefined?
Bean
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