#factorise
25 messages · Page 1 of 1 (latest)
how to do it?
apparently this is the answer but idk how to get there
@true hazel could u help please or anyone
i think this is the difference of 2 squares
when you have two numbers that are squared, you can factorise them like that
like for example
You're told to factorise x^2 - 4
this can be factorised as (x+2)(x-2)
And i think it goes the same to the question you have
because its 7^2
and since x is a variable you just leave it there, hence why the x is there in the answer
This is just a rule and it only works when the 2 numbers/variables are square numbers and the symbol between them is -
not +
Sorry if this is a bad explaination ðŸ˜
erm well you could set 7^x = y
then you would have y^2 - 121
so its a difference of two squares like the person above pointed out
from index laws
you know that
7^2x = (7^x)^2
so you have [(7^x)^2 - 121]
two square numbers here, 121 and (7^x)^2
diff of 2 squares and it becomes (7^x - 11)(7^x +11)
alr i understand thanks @true hazel @astral girder @dusty scarab