#I beg ,i donno how to do this sequence question-the help would be much appreciated !
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Write the number tiles for each of the patterns below, what do you notice?
1,7,19 - quadratic sequence??
first change 6 then 8 diffrent between then both 2
im not sure
yes very well
do you know how to find the formula for quadratic sequences
i didnt realise there was a formulae - atleast not one i needed to know for gcse?
i know like n^2 + n+ c so likee
an^2 + bn + c
U could sub in the different values of n u have to get three eqns and then find a,b and c
i found this online but i dont understand itt
can you explain whats been shown above?
i dont understand the 3a + b part
for example
yes i was referring to the 2a, 3a + b stuff
ohh okay
okay so the 2nd difference (in this 6) is always equal to some number 2a
the a is the same value as your a in an^2 + bn + c
i seee
for your first difference (in this case 6 again) then it is equal to 3a + b
and then your first term (in this case 1) is equal to a + b + c
so u always have to find a and then b and then c
okay slightly lost as how does it change from 2a to 3a?
i don’t know because i haven’t ever watched a proof for this
it just is this way
2a is for the second difference
3a + b is for your first difference
yes ofc
Free online GCSE video tutorials, notes, exam style questions, worksheets, answers for all topics in Foundation and Higher GCSE. The content is suitable for the Edexcel, OCR and AQA exam boards.
Maths revision video and notes on the topic of finding the nth term for a quadratic sequence.
watch the 2nd vid
oki doki ill give it a try - thanks!
np come back if u need any help
f(n) = an²+bn+c
f(1) = a(1)²+b(1)+c=a+b+c
f(2) = 4a+2b+c
f(3) = 9a+3b+c
f(2)-f(1) = (4-1)a + (3-2)b + (1-1)c = 3a+b
f(3)-f(2) = 5a+b
[f(3)-f(2)]-[f(2)-f(1)] = 5a+b - (3a+b) = 2a
In terms of T₁, T₂, T₃ this reads as
T₁ = a+b+c
T₂-T₁ = 3a+b (first difference)
(T₃-T₂)-(T₂-T₁) = 2a (second difference)
oh ! thanks for that too - i dont fully understand this just yet - but yk practice makes perfect so ill go over the links and hopefully i will be better versed over this topic
appreciate all the help!
this is so pretty ty wifibad ur awesome