#functions
414 messages · Page 1 of 1 (latest)
take the limit of f as x approaches 3
in other words try plugging 3.2, then 3.1 and numbers that are even closer to 3 into the function
and see what happens
idk u tell me
is take the limit of f as x goes to inf
okay so how do i do that
basically see what happens as u plug in larger numbers for x
wait sorry let me rephrase from earlier
if we add in big values
such as 10
itll go smaller and tend to 0
if we add smaller values
it goes further away from 0
tends to 0
wait
what form of f are you taking limits of
the one from the q or the one from part a
one from a
right
this is correct
not this
that’s why
i said
let me rephrase
okay but now what do i do with this q
so as x is increasing f is decreasing isnt it
yeah
yeah so as x goes away from 3
f goes to zero
as x gets closer to 3
f gets larger
if that makes sense
yeha so 0 is one
range
but
to 1/4 idk how u attain this number
why is it 1/4
when x needs to be greater than 3
so 1/5
surely
you can just plug in x = 3 here to find the limit
yes the function isnt defined at x = 3
but we know its going to approach 1/4 as we get closer to x = 3
ok plug in x = 5, x = 4, x = 3.5, x = 3.25 , x = 3.0000015
tell me what you get for each sub
alright sure, you've plugged in x = 4 here but f is defined for any real number greater than 3
so what about 3.5 or 3.2 or 3.0000000000000000000000000000000000000000001
x=5 -> 0.1667 , x=4 ->0.2 , x=3.5 ->0.222 ., x=3.25 -->0.23 x=3.0000015->0.2499999
leans to 0.25
this is the whole idea behind limits
do u think u can give me one to try?
nah
but it'll get infinitely close
might help to graph it and see for urself
another eg of what we just went through yeah
ye
this is a trick question btw
why u tricking me
bit devious
so 0 is wrong
theres no limits w this one
i dont understand
cant be -2 bc its undefined
mb i had to go
i had another goose being dopey moment
but the range is
f(x) >= 0
or
f(x) < -1
so you did get it you just had to write it as an inequality
well done
the trick part
was in the domain, i wanted to see if youd spot the domain is wrong
wait why is it bigger than -1 and or equal to 0?
should it not be bigger than 0
i dont understand
it is
see
there's two parts to the range instead of one like in ur question
wym
yeah
i know
but
why is it equal to 0
should it not be >0
what about the -1?
yeah
f isnt defined at x = -2 remember
hang on im so lost now
yeah it isnt definef at -2
but what has it got to do with -1
what does the range tell you
i meant what does the range of a function tell you
but anyway it tells you what all the y values are
so if u sub in x = -2 into f you'd get -1
since f isnt defined at x = 2
then you know that for values around x = 2 you get values around -1
u get it
okay i understand , so why the inequality <-1
sub some values in that are either side of -2
and see what u notice
hint: ||might help to notice that you can simplify f into 1/(x+1) where x != -1||
lmk what ur confused about
did you do this
idk what u mean tbh
-2
the number -2
sub in values which are either side of -2
so for example -3 and -2.5
-1.8 and -1
have you graphed this
it will help
ibr idk how to graph it
im genuinely so bad
like how would i graph this idk
all i know
is that
it will look like this
yeah u got it
yeah but no the values tho
ohhh
yeah thanks for reminding
okay
so
now what tho
bc im still not understanding thi s -1 business
yeah we do
alr
so as x gets further away from -2 you can see that the graph shoots downwards (before it starts shooting upwards again)
its just gonna get smaller and smaller
and go off to negative infinity
so our range of values are from -1 all the way off to negative infinity
not including -1 btw
why not including -1
which is why we have f(x) < -1
-1 is the output from inputting -2
if f is not defined at -2
how can you input it
ohh so because were getting -1 when we input -2 it is baso not defined
if you cant input -2 into the function then you cant get an output
which would be -1 here IF the function was defined at x = -2
perfect
these domain and range qs throw a lot of people off
yh ngl im not stuck on another one💀
😂
so what would be the answer for this
part c is it
yeah
its only 1 mark
because of the relationship between domains + ranges of a function and the domains + ranges of its inverse
how is the domain of f linked to the range of f^-1
hang on not part c
wait yeah part c
omds idek anymore man
i clearly dont understand this topic
u should know that the domain of a function f
is the range of its inverse f^-1
and the range of f is the domain of f^-1
yeah ik its vice versa lol
yh so its just that
so its x>1/2?
no
read this again
no
youve been doing this for a while
take a break
and come back
i havent tho
the E thing means 'element of' and R means 'the set of all real numbers'
yeahh i know this
so what is the domain
and what is the range
you want the domain of f^-1
and you know that its the same as the range of f
so what do you need to find
not a trick question this time 😭
what i understand is
lets say we have f(x) domain and range
for f(x)^-1 the domain is the range
and the range is the domain
theyre swapped right
ye
both x E R and x > -1/2
okay so whats the range
simply means x is a real number which is greater than 1/2
thats what u gotta work out
no
yeah
it doesnt touch 0
yes
and it shoots upwards
it goes off to infinity
this is why its said to be undefined
so with 1/2x-1 the same thing happens when plugging in 1/2
what you wanna do now is consider large values of x
upto you
okay lets go with 2
im not feeling that wild
0.33333
0.11111
0.0526
1.539x10^-11
yeah
going towards 0
you dont need to input every single number
you already know where the function is heading
as x deviates from 1/2 and gets larger and larger f goes to zero
and as x gets closer and closer to 1/2
so does it have to be bigger than 1/2
why is it smaller than 0
why am i strugglign with something like this 😭
look yh
just remember two questions when finding the range
what happens as x gets stupidly large or stupidly small
what happens as x gets close to x = k
in this case k is 1/2
as the domain was x > 1/2
anyway now u got the range you have ur answer for part c
unfourtanetly this is going to be one of the silliest topics i get stuck on
i still dont understand it well💀
i have a headache man
what part dont you get
do you know why im doing what im doing
right
what im doing is looking at the extremes
if my domain is x > 5
then im only interested in how the function behaves at values that are super close to 5
and at values that are very large
i could look at x = 6,7,8,9 but thats not really gonna help much
but if i look at x = 10 billion for instance
Why not 10 gazillion
How do you know it's not walking
what about 10 googol
okay so ur studying the values that r bigger than x
to see how they behave
as they tend to 0
almost
yes
yes
not necessarily
ur interested in ridiculously large numbers because they give you information which actually helps
what is that information
how the function is behaving at these large numbers
wtf 2 he’s
hrs
on this
my head hurts
i don’t understand
anyrbing
i think
im gonna go do smth else
i’ll come back to this
@hollow tangle thank you for being patient w me
ofc man no worries but damn has it really been 2 hours