Hyperbolics

[rich gale]

How do you do part c of this

[rotund folio]

probably whatever the coordinate of C is

from a quick glance at the q

[bright skiff]

@bright skiff

[rich gale]

That’s what I put but it is wrong

[rotund folio]

Send mark scheme and I'll try the q later

[rich gale]

The mark scheme doesn’t have any method it just has the answer which is (4,3)

[rotund folio]

ok well all u do is literally just go onto ur calculator write down both equations and find intersect

ofc its not C the whole idea of the question is to see how C is different using different models

[rich gale]

is there no logical way to solve it?

[rotund folio]

off the top of my head i dont think so but there probably is

oh yeah there is

symmetry

both meet at point (0,3) and both have the turning point at (2,0)

therefore if we go 2 more accross they should both have y = 3

hence (4,3)

pretty sure that logic works

@rich gale