#A level integration (year 13)
4 messages · Page 1 of 1 (latest)
tanθ × cos²θ = sinθ/cosθ × cos²θ = sinθcosθ = ½sin2θ
do u have an answer for this
||½∫sin(x)dx
½[-cosx]
½[-(-1)-(-1)] = 1||
4 messages · Page 1 of 1 (latest)
How do I integrate this? I’ve tried doing parts but doesn’t seem to work
tanθ × cos²θ = sinθ/cosθ × cos²θ = sinθcosθ = ½sin2θ
do u have an answer for this
||½∫sin(x)dx
½[-cosx]
½[-(-1)-(-1)] = 1||