#Logarithms & non linear data
4 messages · Page 1 of 1 (latest)
my calculations
log(f)=log(AR^b)
log(f)=logA+logR^b
log(f)=blogR+logA
y=mX+c
m=b
c=logA
b=-0.75 / -0.8 (to 1 d.p)
4 messages · Page 1 of 1 (latest)
Is the gradient for 6c wrong on the ms? i'm doing this...
my calculations
log(f)=log(AR^b)
log(f)=logA+logR^b
log(f)=blogR+logA
y=mX+c
m=b
c=logA
b=-0.75 / -0.8 (to 1 d.p)