#stats
171 messages · Page 1 of 1 (latest)
which part
a
so the sd (standard deviation i cba to type) is 9
an outlier is 2 sd from the mean
so in this case it would be 18 away from the mean
so in total a range of +- 18 from the mean
this means the range of the data would be 36
since its 50 there are values that are outliers
as they don’t fit the range of non outlying data (36)
if there was no outliers the range would be 36
if that makes sense
ok wait i read what you said in the other server too do you want me to just give the answer or is the way i explained before fone
if not then
calculate the mean
what
fine
ok cool
so you’d calculate the mean first cause by definition an outlier is 2sd away from the mean
so in this case the mean is (frequency times by x)
/ total frequency
yeah
so 0p+30q/p+q
which is just 30q/p+q
if 30 is an outlier then 30 is greater then the mean + 2sd
so 30> 2(9) + 30p/p+q
then just rearrange it to make p the subject
i see
it looks fine
so 30 will be an outlier if p>4q
kk
ok there we go
i accidentally did 30p not 1
q
okay then p is in that inequality and the one given (p>4q)
so we know that p>4q>3q/2 is true
so 30 must follow p>4q
does that make sense m?
not really
yeah
yh
you can combine them to make it p>4q>3q/2
how do you know which order to put it in btw
we just worked out that if 30 is an outlier then p>3q/2
4q is bigger than 3q/2
my bad lol
so anyways
we worked out that if 30 is an inequality for that set of data then p>3q/2
mhm
hmm
i don’t get this link sorry
do you get how to get here
yeah
it’s just that
do we just say p>4q because they gave it then?
i think so?
fairs
sure
Average stats experience
nah ocr
ok part c it tell you to use q=3
why are you here
so since p>4q
p>12
Doesn't ocr ebook have worked solutions
not for all questions
so if we calculate the mean it’s 30(3)/p+3
which is 90/p+3
since p>12
ok i cba to scroll up more
okay so an outlier is 2 sd from the mean
yea
so the range here is 30
if the range is > then the mean+2sd
then there are outliers
if you understood from part a
so 30> 90/(p+3) + 18
12>90/(p+3)
so in part b we worked out p>4q
p>12
let’s use 13 i guess since that’s higher then 12
sub that in
12>90/16
ohh
yeah so the range is higher then the mean +2sd
so it’s possible for there to be outliers
12>5.625
great
for counter example do you only need 1 example?
i’m confused the data they give you has a standard deviation of 12.25
yeah idk how to do part d sorry
it don’t make sense to me
yes it will benefit you
Ew
when you get 100% in a year you’ll be happy
Do i need previous parts
i don’t think so
you won’t
well just the top part that an outlier is 2sd from the mean
wifibad is cooking
it’s been 21 mins i think it’s a glitch surely 🤣🤣
i’ve been checking every minute
I think I'm being way too general
Out here finding integer solutions to an equation with 3 unknowns
can we see your solution anyways
I mean i need to find 3 integers that satisfy the equation first
Yeah I'm overcomplicating it
come on stats man
stats sucks
I rewrote it up nicely which took like another 10 minutes
I didn't spent that whole time doing it ok
Also i started off with the assuming that mean(x) could be any number between 12-18 as all the data would still be within 2 standard devs of the mean
Which made things unnecessarily complicated when just trying to find one counterexample rather than a general one