Integration

[native osprey]

I'm not sure how to do 5b and 9.

[distant bone]

So you need to find the area in this case. When integrating between bounds, you work out the area underneath the curve to the x-axis. So in this case it would be ∫₀¹ (4x³ + 2x - 10) dx, where you do f(1) - f(0).

now for area if get negtive answer you just take postive

$$\left| \int_0^1 (4x^3 + 2x - 10) , dx \right| = 8 \quad \text{(Area)}
$$

[fresh sky]

HM

[distant bone]

for challange it is thhe same thing plug in numbers you get qurdatic and get 2 soultions

[native osprey]

ohh alr alr tysm