#Solving quadratics by completing the square
44 messages · Page 1 of 1 (latest)
(t+3)^2 - 13 = 0
(t+3)^2 = 13
t+3 = +-sqrt(13)
t = -3 +-sqrt(13)
Be careful with your signs, you should always switch them when u move something from one side to another
Is that u^2 + 8u - 3 = 0
Soz having abit of a hard time decoding if thats an 8 or 6
Again same thing, u want the variable (u) to be alone on one side
Its not wrong
u = -4 +- sqrt(19)
it’s v and it’s a 8
the signs r confusing a bit tbh
Thats fine ur in y11 just pattern this so that u dont lose silly marks in exams
Yep
It’s all of higher
So I’m revising it last minute bc I had English paper 2 on Friday
Yeah just be careful with the signs, u make a negative a positive when u move it over and u make a positive a negative when u move it to the other side as u know
👍
Yh I get u lol
But in real gcses the exams will be more spread out
I still need to do circle thereoms
So you won't have to rush
Yh ofc
Go learn them now, usually they're marks heavy
Esp when u have like 2/3 in one problem
?
I will after I do the quadratics
I’ll do all of algebra
Since I’m nearly done
How is this not square root of 19?
Erm it should be
Everything seems fine
(t+b/2)^2+c - (b/2)^2 use this formula
it's quite literally the formula for completing the square for a quadratic mate.