#mechanics chapter 10 pulley question
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But you have to break it down
Immediately
5kg is mass
So x 9.8 = weight
And weight is force
Acc I forgot broski
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Once you get to uni and do engineering
Youโll realize a level
Was useless
Fair
Did you get a as 5g/7
Ok
I meant 5g/7
Why did you use 3 for mass
which mass
Where has 3 come from
T = ma
T = 2a
5g - T = 5a
5g - 2a = 5a
5g = 7a
a = 5g/7
Did you do f = ma i teh wrong direction
oh wait
mb sorry yh
theres no gravity acting on the table particle
That wasn't the point I was making
Im ngl
I dont understand your handwriting
What the hell is on the rhs
Oh you used a vertical force for a horizontal f = ma
Very silly
yh mb
so wait T=2a right
,w sqrt( 2( (0.4)( (5*9.8)/7) )
alr alr
ill do the second part and tell u my answer]
ok
Don't look in here until you're done I'm using this channel as a calculator
,w sqrt( (20.45*9.8)/7 + 2(0.6)(9.8))
4.61 to 3sf is my answer ๐
I found the speed at the instant the string snaps and used that as an initial velocity for a free fall suvat
Yeah
then what equation did u use
v^2 = u^2 + 2as
i did that asw
I made a typo
wait i think u made a mistake
I wrote 0.8 not 0.6
oh wait mb nvm i made a mistake
4.17 to 3sf
Nice one
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Did you have you rmocks
i have like tests tommorow
im usually good with the vertical ones