Roots of Polynomials | Revision Server | Page 1

gray lotus Nov 14, 2024, 3:59 PM

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Oo this is nice actually

First note that the square of any REAL number is non-negative so

(α-β)² + (γ-α)² + (β-γ)² ≥ 0

2α² + 2β² + 2γ² - 2αβ - 2βγ - 2γα ≥ 0

2((α+β+γ)² - 2αβ - 2βγ - 2γα) - 2αβ - 2βγ - 2γα ≥ 0

2(α+β+γ)² ≥ 6(αβ + βγ + γα)

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And then the final step is to use m = α+β+γ and n = αβ + βγ + γα

gray lotus Nov 14, 2024, 6:22 PM

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A level questions don't really get much harder

pseudo wyvern Nov 15, 2024, 8:44 PM

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got the interview?

gray lotus Nov 17, 2024, 2:31 PM

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Not yet

pseudo wyvern Nov 17, 2024, 2:37 PM

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still?

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ur college taking mad long swr

gray lotus Nov 17, 2024, 4:07 PM

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Most colleges haven't yet

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The only one i've heard about its King's for maths

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I haven't heard anyone else talk about trinity interviews for maths yet

pseudo wyvern Nov 17, 2024, 4:10 PM

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Yeah same

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I also saw one of kings for cs

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And Selwyn for math

#Roots of Polynomials