#quadratics
84 messages · Page 1 of 1 (latest)
expand the right hand side and compare coefficients
ok lemme do that rq
i got x^2 - ax - ax + a + b
for the right hand side
ok so u have -2ax if u simplify it
yes
u see on the left the number in front of the x is -10
yes
so a is 5
yes
what about the extra + a
ohh yh mb
@spice wasp but what do i do w that?
So now we compare terms without x in them
So a^2 + b = 18
we know what a is so we can sub it in and solve for b
look at the left hand side
yes
the only term without x in front is 18
ok
now on the right hand side the only bits without x in front are a^2 + b
so we make them equal
np
are the roots at -3 and 5
yes
ok so what u do is expand (x+3)(x-5)
ill do that rq
yes
how do you always know what to do
basically if u have a quadratic with roots a and b u can write it as (x-a)(x-b) so i did (x-(-3)(x-5) and i got (x+3)(x-5) btw this method only works if there isnt a number infront of the x^2
hmmm okokk
tyy
im ashamed to ask but could you please give me a little push towards the right direction?
@spice wasp i think its something to do with the 3 timestable
the top can be factorised into (x-3)(x+3) and the bottom can be factorised into x(x+3) so u can cancel the (x+3)s
you make it look so ez
ty once again
the top is what is known as a difference of two squares
u should watch vids/read about it
and and the bottom u notice that both terms have an x u should tried to factor it out
complete the square
ty but i some1 alreayd helped me out with that
BUT
could you hlp[e me out wit this pls @vale thicket
Typing or?
i write the answers in my book
because I want to do past papers without printing or rewriting the question.
this is homework not a past paper ðŸ˜
Ok
if you find a way can you tell me too
I just use my iPad.
I ain’t even revised circle theorems. I’m revising quadratic simultaneous equations rn,
im pretty sure this is quadratic simultaneous
idk