#Help on gcse
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It tells you that in the interval of 0≤t≤3 h=0
So from t=0 to t=3 draw a horizontal line at h=0
For 3≤t≤10 you can see that when you expand your brackets you get a negative quadratic with roots at t=3 and t=13
But we don't go past t=10 so the second root won't be plotted
Anyway we can find the maximum height of the quadratic by completing the square
(13-t)(t-3)=-t²+16t-39
-(t²-16t+39)
-((t-8)²-64+39)
-(t-8)²+25
So we know the maximum will be at t=8, and h=25