help

[lucid nimbus]

Rewrite tan(3θ) in terms of sin and cos
2sin3θ/cos3θ + 5sin3θ = 0
Factorise out sin3θ:
(sin3θ)(2/cos3θ + 5)=0
By inspection this will be 0 when sin3θ=0, and 2/cos3θ + 5 = 0

Whenever you have trig equations/identities you want to write in terms of sin and cos

[shell oak]

True

It’s 2sin30/cos30 +5sin30 bc of tan30=sin30/Cos30

Idk how to get theta symbol on phone

@lucid nimbus lemme cook

[lucid nimbus]

please never use 0 as theta ever again

thanks

[shell oak]

Bro idk how to get theta symbol on phone

[lucid nimbus]

just write theta or use x

[shell oak]

Ok

[lucid nimbus]

if you have samsung then you can get theta

or just get greek keyboard to switch to

[shell oak]

I’m outside rn

I can’t

[lucid nimbus]

From the last line:
||sin3θ=0 → θ=0, 60, 120, 180
2/cos3θ + 5 = 0
2+5cos3θ=0
cos3θ=-⅖ → θ≈37.9, 82.1, 157.9||

[peak latch]

how did u change it from dividing by 2 to then adding 2

[lucid nimbus]

multiply both sides by cos3θ

[gritty yoke]

@peak latch

Don’t know if that helps