velocity time graph

[edgy sigil]

bump

[rotund cliff]

Yo so

What part of the graph IS the distance?

And is it a nice form that you can use a formula on

[nocturne bridge]

so basically algebraically we need to find this point

so if we call this X

the acceleration is the gradient of the line so

v-x/t=a

v-x=at

v-at=x

now bc it wants distance we need to find the area under the curve

which is in shape of a trapezium

so 1/2(v+(v-at)) x T

so (v-1/2at) x T

so D = TV -1/2aT^2

@edgy sigil

[edgy sigil]

thank u

[nocturne bridge]

np

that is a good q