#Differentiation

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snow rampart
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How would I do this question

vital hornet
vital hornet
# snow rampart How would I do this question

a)
||Let f(x)=xe^(x²)
Equation of tangent to f(x) at x=1:
y=f'(1)(x-1)+f(1)
f(1)=e
f'(x) = 2x²e^(x²) + e^(x²)
f'(1)=2e+e=3e
→ tangent equation:
y=3e(x-1)+e
y=3ex-2e||

b)
||y=3ex-2e → B=-2e, A=⅔
½×⅔×2e=2e/3||

sterile quest
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for part A: use product rule v du/ dx + u dv/dx

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where u could be x and v could be e^x

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get an expression for dy/dx

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and then sub in x = 1 to find the gradient at that point

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to find y coordinates sub x = 1 into y = xe^x

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use formula: y-y1 = m(x-x1) to find equation of line where m is the gradient at x = 1, x = 1 and y = e

snow rampart
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What I am confused what to do with e^x^2

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I differentiated it and got x^2 e^x+e^x2