#Q4
173 messages · Page 1 of 1 (latest)
point A being on the circle x^2+y^2=25
r^2=25 ofc
so r=+ or -5 where we’re in the 2nd quadrant so it must be +ve
r=+5
this must be a 3,4,5 pythagoras triangle
So what’s the answer
Both 👍
okay, then try to follow what im saying
this is what the circle would look like rn
as you can see there’s a triangle in there, this is because we have a radius, value along the x axis and value along the y axis
this combines to give us a right-angle triangle
should i explain a bit more or does that make sense?
Explain more
But they want area
look here
we need to work step by step
we can’t just jump into such a big thing like that
First we need to find the coordinates of (3,p)
To do that we’d have to make this sort of triangle
How do you think we can find the height of this triangle first of all
did u get the answer 50/3
OAB is not right angled
Guys I’m sorry but I need a mentor
I know
But he needs to do a right angle triangle to find the coordinates (3,4)
what step u on
as it’s a pythagorean triplet
?
struggling with explaining step 1
just plug it into the equation
yh u plug 3 into the circle equation
A (3,4)
O (0,0)
B (0,5)
no
oops (0,-5)
no
its not
i did it and i even sent it to chat gpt and i got my answer
ill send u my working
alright
im not really sure of the need of using a pythag triple
OHHH
surely it's just
THE LINE CROSSES THE X AXIS AT B
i used it to find A
I haven't done it
whats eqol”
I just know the method
I’ll send u my working and u verify
aight
Same just want to check numbers
yhyh
is A (3,4)
Yh
How do you actually do this?
I’m so confused
Look at my working If u can read it
ive done this question a lot and i checked chatgpt asw
i asked tom he said it looked fine
@hallow spindle
-
sub x coord into circle eq to find p
-
use (0,0) and point A to find equation of tangent, which is L
-
let y = 0 for L to find point B
-
find area with 1/2bh
@acoustic timber call a mentor here for a sec please
aight
it is probs better cuz its more legible if u do it lmao
dude 😭
tom is a y13 student
Bro there’s no harm in checking
im sure he could do y11 transition maths work
x²+y²=25
let x = 3
y²=16
y=4
A : (3,4)
(0,0) and (3,4)
y-y1=m(x-x1)
gradient is 4/3
y-4=4/3(x-3)
3y-12=4x-12
3y=4x+24
y=4/3x + 8
let y=0
0=4/3x+8
-8=4/3x
x = -6
B : (-6,0)
points: (0,0), (3,4), (-6,0)
Then you guys can explain to me or the mentor can
gradient of L is -3/4 right
How did you even do it Tom?
I need a mentor who can actually explain the maths
I’m a slow learner
it doesn't actually say it's perpendicular
oh wait I'm stupid
yh it's -3/4 as m
@hallow spindle
I did this
yh
Lol!!!
Get a mentor here!!!
what we've learnt is don't let a y11 do a y11 question 🤪
sub 0 into the x val
Tom, please mentor!!!!
Just one thing
yh thats correct
with ur equation u have
sub y = 0
in
and find the x coord
then u have point B
What’s point B?
(25/3,0)
<@&791435371564892232> guys I need help we’re all stuck
Isn’t it 3/25
na 25/3
sub 0 into the line dude
it cant be 3/25 or itd be inside the circle
and it’s not inside the circle otherwise would be positive gradient
Then what would you do after that
y=0 when line intercepts x axis
draw it out
yk the height is 4
and the base is 25/3
then use 1/2 bh
and u get 100/6 or 50/3
Can you draw it out and show me please?
i did
this is the full working out for B if you dont understand
Thanks so much guys!
@hallow spindle
np
no problem
if this is solved and you have no further questions, run command /solved
should you have any questions, im available for dms or pings!
Wait and how you found area?